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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If tanA+sinA=m and tanA-sinA=N then prove that M*M-N*N=4Гmn |
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| 2. |
2-2 |
| Answer» 0 | |
| 3. |
How to draw graph in statistics |
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| 4. |
4powerx-3power(x-1/2)= 3power(x+1/2)-2power(2x-1) |
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| 5. |
Angle ABC is right angles at B,BC=7cm and AC-AB= 1cm. Find the value of cosA+sinA |
| Answer» If ac-ab=1 then,AC=1+AB-----(1)IN TRI ABC BY PYTHAGORAS TH.(1+AB)^2=(7)^2+(AB)^2OPENING IDENTITY....1+(AB)^2+2AB=49+AB^22AB=48AB=24HENCE, AC=24+1=25cmcosA+sinA=24/25+7/25=31/25 | |
| 6. |
1/x+2+2/x+2=4/x+4 find roots |
| Answer» No real roots because this is not a quadratic equation | |
| 7. |
Solve:(x-1) ²⁴(2x+3)¹³(4x+5)¹²>0 |
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| 8. |
Maths board papers question no 15 Delhi set 1 |
| Answer» Listen, firstly reverse the half diagram (lower part). So, it will become a circle.Now,find the area of larger circle and subtract it from area of smaller circle . You will get your answer. Ok? | |
| 9. |
Define BPT thales theorem |
| Answer» BPT mean Basic proportional theoram EG.= if we draw a triangle ABC by construction we draw a line EF which is parallel to BC then it will be AE÷EB=AF÷FC | |
| 10. |
TRIGNOMENTRY |
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| 11. |
Square of 2789.2789 |
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| 12. |
If sinx+ sin²x= 1 then prove that cos²x+ cost x= 1 |
| Answer» sinx=1-sin^2x1-sin^2x=cos^2x=>sinx=cos^2xsin^2x=cos^4x=> 1-cos^x=cos^4x | |
| 13. |
Find the value of Cos70/sin26+cosec20/sec70-2tan30tan60 |
| Answer» It is not cos70 if sin is26 it is cos64 if sin is 26Plz check the question repeat | |
| 14. |
Find tanp-cotr |
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| 15. |
Sin A+cosA =1 why? |
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Answer» Sin^2 +cos^2=1 That\'s is rule |
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| 16. |
1+ cos theta+sin theta/1+cos theta- sin theta =1+ sin theta/cos theta |
| Answer» LHS\xa0{tex} \\frac{{1 + \\cos \\theta + \\sin \\theta }}{{1 + \\cos \\theta - \\sin \\theta }}{/tex}Dividing numerator and denominator by cos{tex} \\theta {/tex}{tex}= \\frac{{\\frac{1}{{\\cos \\theta }} + \\frac{{\\cos \\theta }}{{\\cos \\theta }} + \\frac{{\\sin \\theta }}{{\\cos \\theta }}}}{{\\frac{1}{{\\cos \\theta }} + \\frac{{\\cos \\theta }}{{\\cos \\theta }} - \\frac{{\\sin \\theta }}{{\\cos \\theta }}}}{/tex}{tex}= \\frac{{\\sec \\theta + 1 + \\tan \\theta }}{{\\sec \\theta + 1 - \\tan \\theta }}{/tex}Multiplying and dividing by\xa0{tex} \\sec \\theta + 1 + \\tan \\theta {/tex}{tex}= \\frac{{\\sec \\theta + 1 + \\tan \\theta }}{{\\sec \\theta + 1 - \\tan \\theta }} \\times \\frac{{\\sec \\theta + 1 + \\tan \\theta }}{{\\sec \\theta + 1 + \\tan \\theta }}{/tex}{tex}= \\frac{{{{(\\sec \\theta + 1 + \\tan \\theta )}^2}}}{{{{(\\sec \\theta + 1)}^2} - {{\\tan }^2}\\theta }}{/tex}{tex}= \\frac{{{{\\sec }^2}\\theta + 1 + {{\\tan }^2}\\theta + 2\\sec \\theta + 2\\tan \\theta + 2\\sec \\theta \\tan \\theta }}{{1 + {{\\sec }^2}\\theta + 2\\sec \\theta - {{\\tan }^2}\\theta }}{/tex}Now,\xa0{tex} 1 + {\\tan ^2}\\theta = {\\sec ^2}\\theta {/tex}{tex}= \\frac{{2{{\\sec }^2}\\theta + 2\\sec \\theta + 2\\tan \\theta + 2\\sec \\theta \\tan \\theta }}{{2 + 2\\sec \\theta }}{/tex}{tex} = \\frac{{2\\left[ {\\sec \\theta (\\sec \\theta + 1) + \\tan \\theta (1 + \\sec \\theta } \\right]}}{{2(1 + \\sec \\theta )}}{/tex}{tex} = \\frac{{(\\sec + \\tan \\theta )(\\sec \\theta + 1)}}{{(1 + \\sec \\theta )}}{/tex}{tex} = \\sec \\theta + \\tan \\theta = \\frac{1}{{\\cos \\theta }} + \\frac{{\\sin \\theta }}{{\\cos \\theta }}{/tex}{tex}= \\frac{{1 + \\sin \\theta }}{{\\cos \\theta }} = RHS{/tex} | |
| 17. |
For what value of p are the roots of th eq are real and equal 4x\'2+Px+3 |
| Answer» We have the following equation,4x2\xa0+ px + 3 = 0This is the form of ax2\xa0+ bx + c = 0, wherea = 4, b = p and c = 3For real and equal roots, we must haveD = 0{tex}\\Rightarrow{/tex}\xa0b2\xa0- 4ac = 0{tex}\\Rightarrow{/tex}\xa0p2\xa0- 4(4) (3) = 0{tex}\\Rightarrow{/tex}\xa0p2\xa0- 48 = 0{tex}\\Rightarrow{/tex}\xa0p2\xa0= 48{tex}\\Rightarrow{/tex}\xa0p =\xa0{tex}\\pm 4 \\sqrt { 3 }{/tex} | |
| 18. |
What is the value of since |
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| 19. |
(a+b)3 |
| Answer» 3a+3b or (a+b)³=(a+b)³ = a³ + 3a²b + 3ab² + b³ | |
| 20. |
How much sleep is enough to score maximum?Give me advice. |
| Answer» 8 hrs | |
| 21. |
What is real bumber |
| Answer» A real number is a value of a continuous quantity that can represent a distance along a line. | |
| 22. |
when we use sn formula |
| Answer» We use it to find the sum of a given AAPIt would be specified in the ques to find the sum of the AP or the term of the AP or even both | |
| 23. |
Which term of the AP : 3,8,13,18,........is 78? |
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Answer» a=3. d=8-3=5an=a+(n-1)d78=3+(n-1)575=(n-1)515=n-116=n 26 th term |
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| 24. |
write the number of solution of the following pair of linear equationx+2y-8=0 , 2x+4y=16 |
| Answer» On comparing with standard equation, we get\xa0{tex}a_1 = 1, b_1 = 2, c_1 = -8\\\\a_2 = 2, b_2 = 4, c_2 = -16{/tex}The equations are consistent and dependent with infinitely many solutions, if and only if\xa0{tex}{a_1\\over a_2} = {b_1\\over b_2} = {c_1\\over c_2}{/tex}{tex}=>{1\\over 2} ={2\\over 4} = {-8\\over -16}\\\\=> {1\\over 2} ={1\\over 2} = {1\\over 2}{/tex}So the given pair of linear equations\xa0have many solutons. | |
| 25. |
FIND THE ROOTS OF root 2+3,root2-3 |
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| 26. |
Find the value of 1+ tan²A |
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Answer» sec²A Sec^2A |
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| 27. |
In triangleABC similar to triangle PQR. |
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| 28. |
Find the value of 1+ tan²A. |
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| 29. |
Under root 2 prove it |
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| 30. |
Theorem 6.6 of NCERT book |
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| 31. |
Sin30° + cos45° = ? |
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| 32. |
did all the question are coming from outdide? |
| Answer» 80% from ncert | |
| 33. |
Find H.C.F of a and b, if a=x square y and b= xy cube |
| Answer» Answer is xy. | |
| 34. |
Tan1*tan2*tan3*_ _ _ _ _ _ _ _ _ _ _ _tan89= |
| Answer» I also don\'t know, sorry | |
| 35. |
Why a^0=1 |
| Answer» If any no. has a power of zero it will be 1. | |
| 36. |
Which game do u play? |
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Answer» Clas of clan Coc Cox |
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| 37. |
Tan2*tan4*tan6*_ _ _ __ _ _ _ _ __ tan88= |
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Answer» 1 Answer will be 1explanation-tan 88 can be written as cot 2 and it will be cancel with tan 2 because cot 2 is reciprocal of tan 2 similarly all will be written in cot form and cancel each other |
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| 38. |
What is basic concpet of trigonometry |
| Answer» Relation between side and angle | |
| 39. |
What is distance formula |
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Answer» Distance = speed x time D=DistanceS=SpeedT=Time D=S•T D=speed Time |
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| 40. |
What iz probability of an eyed face card |
| Answer» 12/36 = 1/3 | |
| 41. |
Find the value of a when the distance between the points (3 ,a)and (4,1) is root10 |
| Answer» DISTANCE= root (3-4)2 + (a-1)2 = root 1+a2+1-2a=root 10 squaring both sides\xa0a2-2a+2=10a2-2a-8=0a2-4a+2a-8=0a(a-4) + 2(a-4)=0a=4 or - 2 | |
| 42. |
Sec4A = Cosec(A-20°) |
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Answer» Sec4A=cosec(A-20°)Cosec(90°-4A)=cosec(A-20°)90°-4A=cosec(A-20°)÷cosec90°-4A=A-20°-4A-A=-20°-90°-5A=-110°5A=110°A=110°÷5A=22 •••A=22(Answer) The value of A is 22°. |
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| 43. |
The maximum value of sin theta is________. |
| Answer» 1 | |
| 44. |
x^3+(1/x^3)-2 |
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| 45. |
prove....2+2=5 |
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| 46. |
Find the value of theta (0° |
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| 47. |
Show that tanthita/tanpahyi=1/2 |
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| 48. |
Sin18°/cos72° |
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Answer» Sin18 /sin(90-72)= 1 answer cos(90-18)/cos72cos72/cos721 |
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| 49. |
Latest pattern of class 10 maths paper |
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| 50. |
Find 100 ia a term of ap 25,28,31 or not |
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Answer» Common difference =28-25=3 First term (a)=25an= a+( n-1) d100=25+ ( n-1)3100=25+3n-3100=22+3n100-22=3n78=3nn = 26Hence 100 is twenty sixth term of this App A=25 ,D=3 A+99d 25+99×3=322 |
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