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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 601. |
23/⅔⁵ |
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| 602. |
Can anyone explain the 1st question of 3rd section from exercise 1.3 |
| Answer» \xa0(i)\xa0We can prove\xa0irrational by contradiction.Let us suppose that\xa0\xa0is rational.It means we have some co-prime integers\xa0a\xa0and\xa0b\xa0(b\xa0≠ 0) such that=ab⇒\xa0\xa0…\xa0(1)R.H.S\xa0of\xa0(1)\xa0is rational but we know that\xa0\xa0is irrational.It is not possible which means our supposition is wrong.Therefore,\xa0\xa0cannot be rational.Hence, it is irrational. | |
| 603. |
The area of a square is 36metre if breadth is 4times of length . Then find side of square |
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| 604. |
X2- |
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| 605. |
8.2 1 question 3 part |
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| 606. |
underoot of 9293 |
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| 607. |
ques related from division algorithm is dlted or not?? |
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Answer» It \'s deleted from syllabus sister Division algorithm is deducted from syllabus |
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| 608. |
hey guys exempler is important.and which topic is dlted |
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Answer» 10 dafny Which class? HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.CBSE stated in its notification that the deleted portions of the CBSE syllabus should not be considered for internal assessments or for the year-end board exams.Deleted syllabus of CBSE Class 10 Mathematics\xa0 You could easily know which question is in syllabus if you are through with the syllabus Exampler has mixed questions so we need to aware which topics have been deleted. It is not possible to tell like this |
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| 609. |
Syallbus of standard maths and basic maths |
| Answer» Syallbus of standard maths and basic maths is same\xa0HRD Minister Ramesh Nishank announced a major CBSE syllabus reduction for the new academic year 2020-21 on July 7 which was soon followed by an official notification by CBSE on the same.Considering the loss of classroom teaching time due to the Covid-19 pandemic and lockdown, CBSE reduced the syllabus of classes 9 to 12 with the help of suggestions from NCERT.The CBSE syllabus has been rationalized keeping intact the learning outcomes so that the core concepts of students can be retained.CBSE stated in its notification that the deleted portions of the CBSE syllabus should not be considered for internal assessments or for the year-end board exams.Deleted syllabus of CBSE Class 10 Mathematics\xa0 | |
| 610. |
2x⁶- 3x+5=0 some one solve this question please ?????? |
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| 611. |
X²+3x+1 and x²-3x-1 |
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| 612. |
Which of the following are irrationali)2√5 |
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| 613. |
The common difference of an A.P is 3 than a20-a15 is |
| Answer» We know that,an=a+(n-1)dSo,a20=a+(20-1)(3)a20=a+19(3)a20=a+57Similarly, a15=a+14da15=a+14(3)a15=a+42Now,a20-a15=(a+57)-(a+42)=a+57-a-42=57-42=15 | |
| 614. |
If 2 is a root of x^2+bx+q=0 has equal roots the. find q |
| Answer» x2 + bx +12=0.2 is a root of the equation.Then, 4+2b+12=0.Then, 2b+16=0.So, 2b=\xa0-16.Therefore, b= -8.x2+bx+q=0.x2-8k+q=0.Equal roots, so b2 =4ac.64=4 × 1×qq=16. | |
| 615. |
What is the value of cos\'90 |
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Answer» 0 Sorry ,By mistake l sent this answer for three times. 0 0 0 |
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| 616. |
X by 3 + y by 4 equal to 45 X by 6 minus y by 8 equal to 4 |
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| 617. |
140 lcm |
| Answer» 2*2*5*7 | |
| 618. |
In an ap an=3n+2 then find 10th term |
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Answer» 10th term =3(10)+2 =30+2 =32 a10=3×10+2a10=32 F |
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| 619. |
How to solve word problems of quadratic equation chapter 4 |
| Answer» Make your concept strong and read the question carefully and solve it . | |
| 620. |
(3x+4y) ^3+(3x-4y) ^3 solve |
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Answer» This is like a question of Binomial Theorem?? 54x³ + 128y³ |
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| 621. |
The degree of polynomial (x+1) (x^2-x-x^4+1) is |
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Answer» It\'s degree is 5 =(x+1)(x^2-x-x^4+1)=0= x(x^2-x-x^4+1)+1(x^2-x-x^4+1) =0=x^3 - x^2 -x^5 +x + x^2 -x - x^4 + 1 =0= -x^5- x^4 - x^3 + 1Therefore,the degree of the given poly. Is 5 |
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| 622. |
Area of semi circle is ..... |
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Answer» 1/2πr² 1/2πr² Area of cirle=πr^2Area of semi circle=1/2 πr^2 ½πr² 1/2(πr2\xa0) |
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| 623. |
Use Euclid\'s division algorithm to find HCF of 870and225 |
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Answer» That\'s out of the syllabus. 870=225×3+195,, 225=195×1+30,, 195=30×6+15 ,, 30=15×2+0 HCF=15 15 |
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| 624. |
For decimal no. 0.6 bar on 6 the rational no. is |
| Answer» Let p= 0.666.....(1)Multiplying eq.(1) by 10,we get10p=6.666.....(2)Subtracting eq(1) from eq(2), we get= 10p - p = 6.666 - 0.666= 9p=6=. p=6/9=. p=2/3 | |
| 625. |
indicate the place value of digit 4 in 5467 |
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Answer» On hundredth place place value of 4 is 400 Place value of 4 is 400 400(hundredths) Hundredth |
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| 626. |
Divide (2x^2-x-20) by (x+3) and verify division algorithm |
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Answer» It\'s 2x^2 - x-20 Quotient = 2x - 5, remainder = -5Verification:It can be seen that:(x + 3) (2x - 5) - 5 = 2x2\xa0+ 6x - 5x - 15 - 5 = 2x2\xa0+ x - 20Dividend= Divisor x Quotient + RemainderHence, the division algorithm is verified. |
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| 627. |
In an ap if a is equals to minus 15 a N is equal to 1 is equals to -63 then n is |
| Answer» Answer | |
| 628. |
If d=HCF (48, 72) the value of d is |
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Answer» We have,48= 2 × 2 × 2 × 2 × 3 = 2^4 × 372 = 2 × 2 × 2 ×b3 × 3 =2^3 × 3^2d = HCF(48,72) = 2^3 × 3 =2×2×2×3 =24Therefore, the value of d=24 d=24 If d is the hcf of 48 and 72 so the value of d will be the hcf of laterfactor of 48 is2,3,4,6,8,12,24 and 48factor of 72 is2,3,4,6,8,9,12,24,36 and 72so the hcf is 24 and d= 24 |
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| 629. |
The (HCF*LCM) for the number 50 and 80 is |
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Answer» Exact ans. is 4000 HCF of no. × LCM of no. =Product of the given no.Thus,HCF ×LCM = 50 × 80 HCF × LCM = 4000 Exactly ans kya hoga The least common multiple of 50 and 80 can be computed by using the greatest common factor aka gcf of 50 and 80. This is the easiest approach:\xa0\xa0lcm (50,80) =50×80gcf(50,80)=400010\xa050×80gcf(50,80)=400010= 400\xa0Alternatively, the lcm of 50 and 80 can be found using the prime factorization of 50 and 80:•The prime factorization of 50 is: 2 x 5 x 5•The prime factorization of 80 is: 2 x 2 x 2 x 2 x 5•Eliminate the duplicate factors of the two lists, then multiply them once with the remaining factors of the lists to get lcm(50,50) = 400\xa0AND HCF=5 |
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| 630. |
The decimal expansion of 33/2 ^2 *5 will terminate |
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Answer» 33---------------- 2^2 × 5 33 × 5. 165--------------- = --------2^2 × 5^2 (2×5)^2 = 165 ---------- (10)^2 = 165 -------- 100 = 1.65Therefore,1.65 is the decimal expansion of the given value The decimal expansion of the rational number will terminate after 2 places.Step-by-step explanation:To find :\xa0The decimal expansion of the rational number will terminate after?\u200bSolution :The rational number is\xa0Multiply and divide by 5,Therefore, the decimal expansion of the rational number will terminate after 2 places. |
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| 631. |
find the sum of series 1+(1+2)+(1+2+3+4)+........+(1+2+3+4+.....+20) |
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Answer» 1540 h 224 |
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| 632. |
gud afternooon everyone |
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Answer» ohh sry☹️☹️ Here you can only ask questions u are not allowed to chat |
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| 633. |
Please solve this two anyone fast |
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Answer» Where is the question first put question My question is below Where is the question? First Send your problem |
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| 634. |
(v) (k - 12) x2 + 2 (k - 12) x ·+ 2 = 0 . ( vz) x2 - 4kx + k = 0 |
| Answer» Here, a = k – 12, b = 2 (k – 12), c = 2∴ D = b2\xa0– 4ac = [2(k– 12)]2– 4(k – 12) x 2= 4 (k – 12)2\xa0– 8 (k– 12)Roots are equal, if D = 0⇒ 4 (k – 12) 2 – 8 (k – 12) = 0⇒ 4(k – 12)(k – 12 – 2) = 0⇒ (k – 12) (k – 14) = 0⇒ k = 12 or 14But k = 12 does not satisfy the eqn.k = 14\xa0Ans. | |
| 635. |
t²-15 Que. From polynomials |
| Answer» By comparing the given poly. with ax^2 + bx + c =0,we geta = 1, b=0, c=-15We have, t^2-15=0 t=+_√15Therefore, the zeroes of the polynomial t^2-√15 are √15,-√15Now, sum of zeroes=-b/a √15 - √15= -0/1 0=0 Also, product of zeroes=c/a√15 × (-√15) = 15/1 15 = 15 Hence, Verified | |
| 636. |
Express each number as product of its prime factors 7429 |
| Answer» 7429 = 17 x 19 x 23 | |
| 637. |
Ex 6.2 |
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| 638. |
Proof that√5, is irrational number |
| Answer» Let us assume that √5 is a rational number.Sp it t can be expressed in the form p/q where p,q are co-prime integers and q≠0⇒√5=p/qOn squaring both the sides we get,⇒5=p²/q²⇒5q²=p² —————–(i)p²/5= q²So 5 divides pp is a multiple of 5⇒p=5m⇒p²=25m² ————-(ii)From equations (i) and (ii), we get,5q²=25m²⇒q²=5m²⇒q² is a multiple of 5⇒q is a multiple of 5Hence, p,q have a common factor 5. This contradicts our assumption that they are co-primes. Therefore, p/q is not a rational number√5 is an irrational number | |
| 639. |
How many number of termsrequired for an arithmetic series10+8+6+……………., to get the sum is-126. |
| Answer» 18 | |
| 640. |
Definition of allotropes |
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Answer» The version physical form in which elements can be exist Yes Exist in two or three different forms in the same physical state is known as an allotropes |
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| 641. |
The quadratic polynomial p(x) with-81 and 9 as product are one of the zeroes repeatingly |
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| 642. |
If alpha and beta are the zeroes of x^2+7x+12 then find the value of 1/alpha+1/beta +2 alpha beta |
| Answer» - 295/12 | |
| 643. |
Sin theta + cos theta |
| Answer» P/H + B/H | |
| 644. |
5 tan² A – 5 sec² A + 1 is equal to |
| Answer» 10 | |
| 645. |
X2+5x+10=0 |
| Answer» Using quadratic formula X= -b±√b²-4acX= -5± √(5) ²-4*1*10X= -5±√25-40X= -5± √15X= -5±3.8 By taking (+) X= -5+3.8X= -1. 2 By taking (-) X= -5-3.8 X= -8. 8 | |
| 646. |
Find the area of a quadarant of a Circle whose circumference 22cm |
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Answer» ????????????? = ???? ?π? = ?? 2 x 22/7 x r = 22 r = 22 x 7/2 x 22 ? = ?/?In quadrant, angle of sector, = 90°Area of the quadrant = 90°/360° × πr^2 = 40 × 22/7 × 7/2 × 7/2 = 1540 cm^2ᎻᎾᏢᎬ ᎷᎽ ᎯᏁᏕᏯᎬᏒ ᏯᎨᏝᏝ ᏰᎬ ᎻᎬᏝᏢƒυℓℓ Circumference= 2×22/7×r22=2×22/7×rr=22×7/2×22r=7/2=3.5 cmArea of quadrant= 1/4×22/7×7/2×7/2 =77/8cm² Formulas used =\xa01. Circumference = 2 pie r2. Area of Quadrant = 1/4 Pie r²Circumference = 2 Pie r 22 = 2 * 22/7 r r = 22 * 7 / 22 * 2r = 7/2 or 3.5 cmArea Of Quadrant = 1/4 Pie r² = (1/4) * (22/7 ) * 3.5 * 3.5 = 1 * 22 * 35 * 35 / 4 * 7 * 10 * 10 = 1 * 11 * 35 / 4 * 10= 9.625 cm²\xa0 |
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| 647. |
Qutratic polynomial 1/3 and 1/4 |
| Answer» P(x)=x²-(Sum of zeroes)x+(product of zeroes). Put these values in the bracket as given by question and you will get the correct quadratic equation. | |
| 648. |
X square - 9 /x power 4 + x power 3 - 23x square - 3x + 60 |
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| 649. |
What is quadratic polynomial? |
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Answer» Polynomial in the form of ax*2+bx+c Polynomial having the power 2 The equation in the form of x2-ax-b A polynomial in which the power is 2 |
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| 650. |
Example 6 of chapter 9 |
| Answer» In ∆ PBDTan30°=PD/BD1/√3=PD/BDBD=PD√3____________by eq .1In∆PACTan45°=PC/AC1=PC/ACPC=PD+ACPD+DC=AC | |