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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 951. |
Khushi are you here |
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Answer» ...,................. No |
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| 952. |
हमसे जलने वाले भी कमाल के होते हैं, महफिले तो खुद की होती है, पर चर्चे हमारे होते हैं!✌✌ |
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Answer» ? Thik kaha bro ??? |
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| 953. |
what is ratio theorm |
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Answer» The ratio theorm . This theorm is very useful for finding the coordination of a point that divided a line into a certain ratio. If P is any point on a line AB,and if ,a,b and p are the position vectors of A,B and P respectively,then If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. |
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| 954. |
Solve this################## |
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Answer» #(#+#)=### . Learn with us by sending your whatsapp no . |
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| 955. |
4x+3y=11, 3y-4x=19 solve elimination method |
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Answer» if one zero of the polynomial FX equal to (k square + 4 )x square + 13 x + 4 k is reciprocal of the other than k= 4x+3y=11........(i)3y-4x=19-4x + 3y = 19 ........(ii)adding (i) and (ii)6y = 30y = 30/6 = 5Put y = 5 in (i)4x + 3(5) = 11\xa04x + 15 = 114x = 11 - 15\xa04x = -4\xa0x = -1\xa0\xa0\xa0 |
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| 956. |
Where I able to see my board copies. |
| Answer» Learn with us by sending your whatsapp no. | |
| 957. |
Exercise 9.1. Question 6 |
| Answer» A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from\xa0\xa0to\xa0\xa0as he walks towards the building. Find the distance he walked towards the building.Ans.\xa0AB = 30 m and PR = 1.5 mAC = AB – BC= AB – PR= 30 – 1.5= 28.5 mIn right triangle ACQ,\xa0\xa0QC =\xa0\xa0mIn right triangle ACP,\xa0\xa0\xa0\xa0\xa0\xa0PQ =\xa0\xa0PQ =\xa0\xa0=\xa0\xa0mHence, the walked towards the building is\xa0\xa0m. | |
| 958. |
Find the H C F of 40824000000 |
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Answer» It\'s not possible Ek no. Ka HCF? |
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| 959. |
Hi,shivani |
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Answer» Hi suno new post kro us pr reply krti hu Hi ashish J To add in cbse homework help group.send your whatsapp no. Fastly |
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| 960. |
Hi shivani |
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Answer» There every body will see On vedantu How Send me your photo Hi |
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| 961. |
Show that 5-root3 is irrational |
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Answer» What about nt to worry Ok don\'t worry Yes I have posted a que see Hi bushra |
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| 962. |
X^2+2x-1=0 find factor |
| Answer» It can done by completing the square method X^2+2X-1=0{X^2+2X +1}-1-1=0 (adding and subtracting1)(X+1)^2-2=0(X+1)^2=2Squareroot both sidesX+1=2^(1/2) or X+1=-2^(1/2)X=-1+2^(1/2) or X=-1-2^(1/2) | |
| 963. |
. A quadratic polynomial, the sum and product of whose zeros are -3 and 2 respectively is:\xa0* |
| Answer» We know that a quadratic polynomial when the sum and product of its zeroes are given byp(x) = K {x2\xa0– (sum of the zeroes) x\xa0+ Product of zeroes},where K is a constant.Therefore, required quadratic polynomial p(x) is given byp(x) K[x2–(-3x)+(1)] = K (x2 +3x +2). | |
| 964. |
Find value of K such that equation has real and equal roots. x^2 -2 (1+3k)x +7 (3+2k) = 0 |
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| 965. |
find the value of x and y in ABCD rectangle,AB=x+y,BC=14,CD=30,AD=x-y |
| Answer» x+y = 30 ( opp sides of rectangle are equal) -------1x-y = 14 (opp sides of rectangle)Therefore x= y +14 (putting this in eq 1)2y+14 =302y= 16y=8 (putting this in eq 1)x= 22 | |
| 966. |
Team SouL |
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Answer» Mu m le mera Anshu . I am in team |
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| 967. |
Calculate the volume of water in litres content in glass consider glass to be a cylinder |
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| 968. |
X-3/x+3-x+3/x-3=48/7 |
| Answer» Answer :- x=0 | |
| 969. |
Section formula explain in hindi |
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| 970. |
Express tan A, sec A and cos A in terms of sin A |
| Answer» Rddxghc | |
| 971. |
Prove angle bisector theoram |
| Answer» This\xa0theorem\xa0states that an\xa0angle bisector\xa0divides the opposite side of a triangle into two segments that are proportional to the triangle\'s other two sides. In the triangle below, that\'s AB/BD = AC/CD. We then used the\xa0theorem\xa0to find the missing length in a triangle with an\xa0angle bisector.\xa0An\xa0angle bisector\xa0is a line or ray that divides an\xa0angle\xa0into two congruent\xa0angles\xa0. ... Some textbooks call this\xa0Angle Bisector\xa0Theorem , but this name is usually used for another theorem about\xa0angle bisectors\xa0in a triangle.\xa0Example\xa0: In the figure, →BD is an\xa0angle bisector. | |
| 972. |
Find the 12th term from the end of the AP -2, -4, -6, -------, -100 |
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Answer» Yes, Pranali u r right. ? let the first term be -100 and d = 2 .........a₁₂ = {a + (n-1)d}..........= {100 + (12-1)2}............= (-100 + 11 × 2)..........= -100 + 22.........= - 78..........So, the 12th term of the AP from the end will be -78............ |
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| 973. |
If the zeros of the polynomial ax²+bx+b=0 are in the ratio m:n then find the value of √(m/n)+√(n/m). |
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Answer» Let α and β are two zeroes of the polynomial ax²+bx+b.Sum of zeroes = -(b)/a = α+βProduct of zeroes = c/a = αβ = b/aα/β = m/nNow, √m/n + √n/m =√α/β + √β/α =√α/√β + √β/√α =(α+β)/√αβ =(-b/a)/√b/a =-√b/√a Question : If the zeros of the polynomial ax²+bx+b=0 are in the ratio m:n then find the value of √(m/n)+√(n/m) .Answer :ORlet the zeros of the given polynomial ax^2+bx+c be m"alpha" and n"alpha"\xa0m "alpha " + n"alpha" = -b/a=>"alpha"= -b/a(m+n)------------------(i)\xa0and similarly product of zeros\xa0=> mn"alpha^2"=b/a-------------(ii)\xa0Now,\xa0Putting the value of equation (i) in equation (ii)You would get the desired answer which is\xa0\xa0root m/ root n +root n/root m=>root b/a\xa0 |
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| 974. |
8childrens can sit on a banch ; How many bancha are required for656 children tosit on? |
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Answer» 82 benches are required 62 |
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| 975. |
2x^4+x^3-14x^2-19x-6÷2x^2-5x-3 |
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| 976. |
How to solve ques 7 of exercise 14.1 by assumed mean method and ques 8 by direct method (ncert) |
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| 977. |
Chapter first all questions |
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Answer» ...... It is given in this app?☺ |
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| 978. |
Class 9factorisation |
| Answer» Isss me se konsa question chahiye aapko | |
| 979. |
4.1 |
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Answer» Questions hai kya hoga to dana what does it mean What? |
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| 980. |
Find the sum of all multiple 11 lying between 100 and 700 |
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Answer» Here, the A.P. will be110,121,....,693an=a+(n-1)d693=110+(n-1)*11693-110=(n-1)*11583=(n-1)*11n-1=583/11n-1=53n=54Answer Don\'t know |
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| 981. |
Calculate the distance(2,-5) (3,-4) |
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| 982. |
2x-5y+4 and 2x+y-8=0 what type of lines are formed |
| Answer» We can rewrite the equations as:2x – 5y = - 4& 2x + y = 8For equation, 2x – 5y = - 4First, take x = 0 and find the value of y.Then, take y = 0 and find the value of x.Now similarly solve for equation, 2x + y = 8Plot the values in a graph and find the intersecting point for the solution.Hence, the solution so obtained from the graph is (3,2), which is the intersecting point of the two lines.The vertices of the formed triangle by these lines and the y - axis in the graph are A(3,2), B(0,8) and C(0,0.8).\xa0 | |
| 983. |
Prove Root 13 irrational |
| Answer» Let us assume that √13 is rational no and equals to p/q are Co primes√13=p/qsquaring both sides√13*2=p*2/q*213=p*2/q*213q*2=p*213/p*213/pp=3r for some integer rp*2=169r*213q*2=169*2b*2=13r*213/b*213/b13 is a common factor but this is contradiction hence our supposition is wrong √13 is irrational no. | |
| 984. |
Neha tomorrow morning mai massage kar na tik hai bya sister. |
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Answer» Ha thik hai bye Ok thanks for given advice Aur ha apna number aisa kisi bhi aap par mat share kiya karo warna uske karan tumhe pareshani ho sakti hai Sorry message Bhai massage ya message |
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| 985. |
an= - 3n + 7 |
| Answer» Do your it self | |
| 986. |
Yes u are right pranali ....i am from Nagpur Maharashtra |
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Answer» No Do u use insta I am from Amravati Aap kha se ho Oh |
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| 987. |
MH me kha se ho ...Pranali...... |
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Answer» Ok Ya Sumit , i think aap bhi Maharashtra se ho...... I am right Ha , priyanshu aap muze sister bol sakte ho Kya |
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| 988. |
Anyone know there will be 2021 class 10th board exam will taken or not. |
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Answer» Ji bilkul आप मुझे भाई बोल सकती है! Questions kaha hai Priyanshu aapne mere question ka answer nhi diya Not now Till 15 july u will ask me or i will tell you. Board exam will pospoin it . Don\'t know |
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| 989. |
Yaha koi maharastra se hai ky ? |
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Answer» Kha se Kuch nhi Ha ji bolo kya baat hai Mai hu Ha |
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| 990. |
Root-11/4+2root2 |
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| 991. |
Evaluate the followingSin18° cos73° +√3{tan 10° tan30° tan40° tan50° tan 80° |
| Answer» We know that:(i) sin(90 - A) = cosA.(ii) cotA = (1/tanA).(iii) tan(90 - A) = cotANow, Coming to the question.= > 1 + 1= > 2. | |
| 992. |
Chapter 8c question 9 |
| Answer» Exercise ???? | |
| 993. |
Show that (a, a), (-a, -a) and (-√3a,√3a) are the vertices of equilateral triangle |
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| 994. |
All the theorem of triangle |
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Answer» Oh sorry Neha ji he ask theorem not ask about it Theorem book may nhii kya....?...? NCERT BOOK la lo bahi The triangle inequality states that the sum of the lengths of any two sides of a triangle must be greater than or equal to the length of the third side. That sum can equal the length of the third side only in the case of a degenerate triangle, one with collinear vertices.Internal angle (degrees): 60°Edges and vertices: 3Properties: Convex, cyclic, equilateral, isogonal, isotoxalSymmetry group: Dihedral (D3), order 2×3 |
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| 995. |
please give me answer of ch-8 8.4 Q.3 10 sum |
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Answer» thanks pranali In RS agwal book Q3) i) = 1 ii) = 1 |
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| 996. |
Q. 4 ex. 8.4 |
| Answer» It is available on the app... | |
| 997. |
Exercise 1.3 |
| Answer» It is available on the app... | |
| 998. |
Show that there is no natural number 4 ki power n ends with 0 |
| Answer» cannot ends with the digit zero. ... A digit ending with zero must need to have 2 and 5 as factors or the number itself should have ended with the digit zero. The factors of 4 = 2×2. It has only 2 as a factor and 5 is missing. | |
| 999. |
Find quadratic polynomial whose zeroes are - 4 and 1 respectively |
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Answer» 1) therefore, for polynomial.....we have to use.... x²-(sum of zeros)x + product of zeros.2) hence,the required polynomial is.......x² -(-3)x + (-4)hope it helps....... |
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| 1000. |
Show that n square -1 is divisible by 8, if n is of the form 3m or 3m+1 for some integer m |
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