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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
Sin60.cos30+Sin30.cos60 |
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Answer» Wrong hai 3/4+1/4= 4/4=1 √3/2×√3/2+1/2×1/2 Step-by-step explanation:Given :\xa0Expression To find :\xa0The solution of the given expression?Solution :Applying property,We know,\xa0 |
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| 852. |
In the series 2^1/2 , 8^1/2 , 16^1/2 , 32^1/2 eighth term is |
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| 853. |
I have 20 apples I eat 4 apples and 3 give to old woman how many apples i have |
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Answer» 13 13 29-9+3-10 13 13 |
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| 854. |
Why did not uploaded cbse 2020 board exam question paper? |
| Answer» It will be on internet in some time | |
| 855. |
The least number that is divisible by all the numbers from 1 to 10 |
| Answer» The least number divisible by all the numbers from 1 to 10 will be the LCM of these numbers.We have,1 = 12 = 2 × 13 = 3 × 14 = 2 × 25 = 5 × 16 = 2 × 37 = 7 × 18 = 2 × 2 × 29 = 3 × 310 = 2 × 5So, LCM of these numbers = 1 × 2 × 2 × 2 × 3 × 3 × 5 × 7 = 2520Hence, least number divisible by all the numbers from 1 to 10 is 2520 | |
| 856. |
3.1 Kay 1 qution |
| Answer» | |
| 857. |
Find p and q such that 2p,2p,q, p+4q,35 are in A. P |
| Answer» Find the lcm of 67 to 48 | |
| 858. |
if diameter of semicircle protractor 14cm.than find perimeter. |
| Answer» Diameter of semicircular protractor = 14 cmRadius = 7 cmPerimeter = 2πr/2 + 2r = πr + 2r= π (7) + 2 (7)= 22x 7/7 + 14=\xa022 + 14= 36 cm | |
| 859. |
(-5-7) (-3-2) |
| Answer» 875 | |
| 860. |
Prove that -x2+x-1=0 has no real roots |
| Answer» b^2 - 4ac = 1 - 4× -2×-1= -7 not equal to 0 so has no real roots | |
| 861. |
Which exercises are deleted for 10th CBSE |
| Answer» There r many topics which r deleted from cbse syllabusU can check it by using the revised syllabus of mathematicsThnku | |
| 862. |
Find the altitude of an equilateral triangle when each of its side is \'a\' |
| Answer» Here ABC is an equilateral triangle with each side as \'a\'.therefore AD Is the altitude which bisects the base BC into 2 equal halves.therefore in triangle ABDAD^2+BD^2=AB^2 ( Pythagoras theorem)=>AD=√a^2-a^2/4=>AD=√3a/2.therefore altitude of the triangle is √3a/2. | |
| 863. |
If p is a prime number and p dividesk^2 thwn p divides: |
| Answer» K | |
| 864. |
Is "sample space" of probability related to our current syllabus 2020? |
| Answer» Because it is not mentioned in the NCERT Book class10 But there is 1 question in this CBSE guide related to the calculations of sample space | |
| 865. |
Exercise 4.2 ques.no.6 ncert |
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Answer» 6. A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If, the total cost of production on that day was Rs. 90, find the number of articles produced and the cost of each article.Ans.\xa0Let cost of production of each article be Rs xWe are given total cost of production on that particular day = Rs 90Therefore, total number of articles produced that day = 90/xAccording to the given conditions,⇒⇒⇒⇒⇒⇒x\xa0(x\xa0− 15) + 12 (x\xa0− 15) = 0⇒(x\xa0− 15) (x\xa0+ 12) = 0⇒x\xa0= 15, −12Cost cannot be in negative, therefore, we discard\xa0x\xa0= −12Therefore,\xa0x\xa0=\xa0Rs\xa015 which is the cost of production of each article.Number of articles produced on that particular day =\xa0= 6 Hi |
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| 866. |
Write first 5 terms of an AP whose first term is 99 and d=–9 |
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Answer» Bro you answer was it from internet?? You know that an A.P is in the form a,a plus d, a plus 2d, a plus 3d , a plus 4d...where a is the first term and d is the common difference.Here it is given a-99 & d - (-9)Therefore A.P is- 99 ,99 plus -9 , 99 plus 2(-9);99 plus 3(-9); 99 plus 4(-9)Ans:- 99; 90;81; 72 & 63....HOPE IT HELPED YOU..... |
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| 867. |
234 is rational no.? |
| Answer» Ya | |
| 868. |
Sum of zeroes________. |
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Answer» Alpha + Beta = sum of zeroes . Its formula is =-b/a. -(coeff of x)/ coeff of x2 |
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| 869. |
Prove that 3 + root 2 is irrational |
| Answer» Let\'s assume to the contrary that 3+root 2 is rational.Therefore converting it in the form a/b where a and b are co primes.therefore a/b =3+root2a/b-3=root2 Now since a and b are integers so a/b-3 is rational.Thus root 2 is rational.But it contradicts the fact that root 2 is irrational.This contradiction arouse due to incorrect assumption that 3+root 2 is rational.Thus 3+root 2 is irrational. | |
| 870. |
Excersice 4.1 second qustion. |
| Answer» Let breadth of rectangular plot be x metersLength is one more than twice its breadthSo, length is (2x+1)meters Area of rec. =l*b 528= x(2x+1) 528= 2x^2 +x 2x^2+x-528=0 | |
| 871. |
cosA-sinA +1/cosA+sinA -1=1/cosecA-cotA |
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Answer» Ismein only aap jo left sude par h unka rationalising kardo Hi |
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| 872. |
X+Y=14 and X-y =4 |
| Answer» Given=> x + y = 14. .... equation 1x - y = 4. ...... equation 2Now, we will solve it by substitution method;Let\'s take equation 1 =>x + y = 14x = 14 - yPut the value of x in equation 2=>x - y = 4=> 14 - y - y = 4=> 2y = 14 - 4=> y = 10/2=> y = 5Now, put the value of y in equation 1 =>x + y = 14=> x + 5 = 14=> x = 9Therefore the value of x = 9 and y = 5 | |
| 873. |
Kiska kitna Science me chapter hua hai? |
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Answer» 5 Hi @Abhinav If everybody will focus in studies then how anybody will be enjoy live life. 3 Please focus on studies |
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| 874. |
1/2× +1/3y=2 and 1/3x +1/2y=13/6 solve the equation by elimination and substitution method |
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Answer» Expert Answer:\xa0X/2 + Y/3 = 2 → 3X + 2Y = 12.....(i)X/3 + Y/2 = 13/6 → 2X + 3Y = 13....(ii)Adding (i) and (ii) we get X = 2\xa0Subtracting (ii) from (i) we get Y = 31/x = 2 and 1/y = 3x = 1/2 and y = 1/3 Give me the answer |
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| 875. |
Find the ratio in which the line segment joining the points (-3,10)and (6,-8)is divided by (-1,6) |
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Answer» Here x₁ = -3, y₁ = 10, x₂ = 6, y₂ = -8 ...... [m(6) + n (-3)]/(m+n) ,\xa0[m (-8) + n (10)]/(m+n) = (-1,6)\xa0....... (6m - 3n)/(m+n), (-8m+10n)/(m+n) = (-1,6) .......\xa0equating the coefficients of x and y....... (6m-3n)/(m+n) = -1 ....... (-8m+10n)/(m+n) = 6........... 6m - 3n = -1 (m+n)............ 6m - 3n = -1 (m+n).......... 6m-3n=-m-n.......... 6m+m=-n+3n......... 7m=2n.. ......... m/n= 2/7......... m:n = 2:7..........So the point (-1,6) is dividing the line segment in the ratio 2:7. Let P(-1, 6) divides the line segment joining the points A(-3, 10) and B(6, -8) in the ratio K : 1.Then the co-ordinates of P are given byHere, we havex1\xa0= -3, y1\xa0= 10x2\xa0= 6, y2\xa0= -8and m1\xa0= K, m2\xa0= 1So, the co-ordinates of P areBut the co-ordinates of P are given as P(-1, 6)Hence, required ratio = 2 : 7. |
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| 876. |
It is immediately ok. |
| Answer» Ok | |
| 877. |
Which YouTube channel explain statistics in the best way plz tell. Imigiately. |
| Answer» | |
| 878. |
In case of even number find the sum of 1n term |
| Answer» Let n = 2Then sun of first 2 term of even number equal to even, 2 + 4 = 6This shows that sum of nth term of even number is always even | |
| 879. |
Exercise 12.3 |
| Answer» available on this app.. | |
| 880. |
HCF of 867 and 255 |
| Answer» By using Euclid division Lemmaa=bq+rwhere a is > bso a = 867 and b =255867=255×3+102here r≠ 0 so a = 255 and b = 102255 = 102 × 2 + 51here r ≠ 0 so a = 102 and b = 51102 = 51 × 2 + 0here r = 0so, Hcf of (867,255) is = 51 | |
| 881. |
Which one of the following salts will dissolve in water to form an alkaline solution? |
| Answer» On dissolving in water, which of the following salt give an alkaline solution?A. Ammonium ChlorideB. Sodium CarbonateC. Sodium AcetateD. Sodium ChlorideAns. BExplanation:\xa0On dissolving in water, Sodium Carbonate salt gives an alkaline solution. | |
| 882. |
Is the triangle with sides 25cm,5cm and 24cm a right triangle? Give reasons |
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Answer» Let a = 25 cm, b = 5 cm and c =24 cmNow, b2 + c2 = (5)2 + (24)2= 25+ 576 = 601 ≠ (25)2Hence, given sides do not make a right triangle because it does not satisfy the property of Pythagoras theorem. Hence,given sides do not make a right angle triangle because it doesn\'t satisfy the property of pythagoras theorem Hence, given sides do not make a right triangle because it does not satisfy the property of Pythagoras theorem. |
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| 883. |
9÷3×3=9 CAN ANYONE TELL ME HOW IT IS POSSIBLE |
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Answer» 9÷3×3=3×3=9 Please follow BODMAS in these type of questions... Is now my answer is correct or not ??? Question is 9÷3×3=9:- So let,9÷3=3 then 3 is left so we can multiply the 3×3 so we get 9 Yes, because according to BODMAS first we have to divide and then multiply. |
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| 884. |
Find the product of 3√4×√2 |
| Answer» √4=2 so ,the value is 3×2×√2=6√2 | |
| 885. |
7cm,24cm,25cm, in triangle they are the length of its hypotenuse |
| Answer» Yes , sides 7cm,24cm,25cm form a right angle triangleStep-by-step explanation:In right triangle, the square of the hypotenuse length is equal to the sum the squares of base and perpendicular length .Hypotenuse² = Perpendicular² + Base²As givenDo sides 7cm ,24cm ,25cm form a right angle triangle .As hypotenuse sides is always greater length side i.e 25 cm .625 = 576 + 49625 = 625Thus the square of the hypotenuse length is equal to the sum the squares of base and perpendicular length .Therefore sides 7cm,24cm,25cm form a right angle triangle | |
| 886. |
Explain how 2+2=5 ? |
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Answer» TELL ME HOW 4+4=10 Sorry the third line was written by mistake The second step is not there in the solution No, it was not by mistake I can prove this....By this method—We can take20–20=25–25And we can write it also as(5×5)–(5×5)=(5×5)–(5×5)Now by taking out the common factor we get4(5–5)=5(5–5)Canceling (5–5) from both sides Gives us. 4=5So it is now clear that 2 + 2 can also be 5Mujhe aaj hi Pata Chala ye method Vo galti se ho gya hai aap se 2+2= 4 hota hai 2+2=4 |
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| 887. |
What is 20+5 |
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Answer» 25 It\'s 25 25 25 bro 25 |
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| 888. |
Sir, new syllabus CBSE ma nahi dekha raha ha |
| Answer» Click on the given link for revised\xa0syllabus :http://cbseacademic.nic.in/Revisedcurriculum_2021.htmlRevised Curriculum for the Academic Year 2020-21 | |
| 889. |
Multiple of 54 |
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Answer» 54,108,162,...... 54,108,162,216,270,324,378,432,486,540,594,648,702,756,810,864,918,972,1026,1080,1134,1188,1242,1296,1350,1404,1458,1512,1566,1620,1674,1728,1782,1836,1890,1944,1998,2052,2106,2160,2214,2268,2322,2376,2430,2484,2538,2592,2646, 54,108,162,216,270,324,378,432,486,540,594,648,702,756,810,864,918,972,1026,1080,1134,1188,1242,1296,1350,1404,1458,1512,1566,1620,1674,1728,1782,1836,1890,1944,1998,2052,2106,2160,2214,2268,2322,2376,2430,2484,2538,2592,2646 |
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| 890. |
what number comes between 2and 4? If you know the answer then tell me |
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Answer» 3 2.1,2.2,2.3,2.4,2.5,2.6,2.7,2.8,2.9,3.0,3.1,3.2,3.3,3.4,3.5,3.6,3.7,3.8,3.9 Infinite 3 https://youtu.be/1xKSSckSA0Q |
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| 891. |
Difference between Zero of the Polynomial and Root of the Polynomial |
| Answer» https://youtu.be/1xKSSckSA0Q | |
| 892. |
Anybody give me a hard math question without ch-7,14,15 |
| Answer» https://youtu.be/1xKSSckSA0Q | |
| 893. |
Maths exercise number 14.1, question number 5 |
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Answer» available on this app also.. https://youtu.be/1xKSSckSA0Q 5. In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number mangoes. The following was the distribution of mangoes according to the number of boxes.Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?Ans.\xa0Since value of number of mangoes and number of boxes are large numerically. So we use step-deviation method.From given data, Assume mean\xa0\xa0= 57, Width of the class\xa0\xa0= 3\xa0\xa0=\xa0\xa0(approx.)Using formula, Mean\xa0\xa0= 57 + 3 (0.0625) = 57 + 0.1875 = 57.1875 = 57.19 (approx.)Hence mean number of mangoes kept in a packing box is 57.19. |
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| 894. |
Maths exercise number 14.1, question number 5 solution |
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Answer» https://youtu.be/1xKSSckSA0Q 5. In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number mangoes. The following was the distribution of mangoes according to the number of boxes.Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?Ans.\xa0Since value of number of mangoes and number of boxes are large numerically. So we use step-deviation method.From given data, Assume mean\xa0\xa0= 57, Width of the class\xa0\xa0= 3\xa0\xa0=\xa0\xa0(approx.)Using formula, Mean\xa0\xa0= 57 + 3 (0.0625) = 57 + 0.1875 = 57.1875 = 57.19 (approx.)Hence mean number of mangoes kept in a packing box is 57.19. |
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| 895. |
Exercise no.14.1, question number 5 |
| Answer» 5. In a retail market, fruit vendors were selling mangoes kept in packing boxes. These boxes contained varying number mangoes. The following was the distribution of mangoes according to the number of boxes.Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?Ans.\xa0Since value of number of mangoes and number of boxes are large numerically. So we use step-deviation method.From given data, Assume mean\xa0\xa0= 57, Width of the class\xa0\xa0= 3\xa0\xa0=\xa0\xa0(approx.)Using formula, Mean\xa0\xa0= 57 + 3 (0.0625) = 57 + 0.1875 = 57.1875 = 57.19 (approx.)Hence mean number of mangoes kept in a packing box is 57.19. | |
| 896. |
Proof of theorem 6.3 |
| Answer» | |
| 897. |
Find the area of sector of a circle with radius 6 cm if angle of the sector is 60° |
| Answer» Area of sector =Φ/360°*πr²WhereΦ=angle of sectorarea =6*6*22/6*7=792/42=18.85area of sector =18.85cm² | |
| 898. |
Find the value of p in eq. 3x square + 11x + p |
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| 899. |
Factorise it: 4x²-80x+400 |
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Answer» Hello Hii sanket 4x²-80x+400 = 0x2 - 20x + 100 = 0\xa0x2 - 10x - 10x + 100 =0x ( x - 10) - 10\xa0(x - 10) =0(x -10) (x - 10) = 0\xa0x - 10 = 0, x - 10 = 0x = 10 and x = 10 |
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| 900. |
The value of the sphere of radius is |
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