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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 37501. |
Find the ratio of 4:3 |
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| 37502. |
Verify that 3,-1,_1\\3 are zeros of cubic polynomial |
| Answer» where is polynomial for which you are asking | |
| 37503. |
Cbse can make rule for basic and standerd maths |
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Answer» Thanks Yes yes |
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| 37504. |
144 198 find the hcf and lcm |
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Answer» Xh v hubbub conceptual and basic thing |
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| 37505. |
Rs aggarawal solution of exercise 4A |
| Answer» U can get solution from offliine RS Aggarawal solution app | |
| 37506. |
Substitution metod |
| Answer» find value of any variable from eqation1 and put it into eqn 2 | |
| 37507. |
Some important thing about trignometry for boards |
| Answer» Prepare the trigonometric ratios perfectly,the values of degrees and formulas Then you are able to solve any problem | |
| 37508. |
1 divided by sec Theta - 1 + 1 / sec theta + 1 is equals to 2 cos x cot theta |
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| 37509. |
(1+tanA+secA)(1+cotA-cosecA)=? |
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| 37510. |
3075 ÷1 |
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Answer» 3075 3075 3075 3075 1 |
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| 37511. |
If sec 4A =cosec(A-20°) where 4A is an acute angle find the value of A |
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Answer» Thanks Sec 4A=sec(90°-(A-20°))4A=90°-A+204A=110-A5A=110A=110/5A=22° |
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| 37512. |
Prove that 7-√5 is irrational |
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Answer» then -√5 is irrational no. and you have to rise contradiction. then you take another rational 7 and substract by 7-√5 then√5 will remain . You have to let rational firstly |
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| 37513. |
Divide 32 into two parts such that their product is 175? |
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Answer» Let the four parts be (a - 3d), (a - d), (a + d) and (a + 3d). Then,Sum of the numbers = 32 {tex}\\Rightarrow{/tex}(a - 3d) + (a - d) + (a + d) + (a + 3d) = 32\xa0{tex}\\Rightarrow{/tex} 4a = 32\xa0{tex}\\Rightarrow{/tex} a = 8It is given that{tex}\\frac { ( a - 3 d ) ( a + 3 d ) } { ( a - d ) ( a + d ) } = \\frac { 7 } { 15 }{/tex}{tex}\\Rightarrow \\quad \\frac { a ^ { 2 } - 9 d ^ { 2 } } { a ^ { 2 } - d ^ { 2 } } = \\frac { 7 } { 15 }{/tex}{tex}\\Rightarrow \\quad \\frac { 64 - 9 d ^ { 2 } } { 64 - d ^ { 2 } } = \\frac { 7 } { 15 } \\Rightarrow{/tex}128d2 = 512\xa0{tex}\\Rightarrow{/tex} d2 = 4\xa0{tex}\\Rightarrow{/tex}d = ± 2Thus, the four parts are a - 3d, a - d, a + d and a + 3d i.e., 2,6,10,14. 25 and 7 its product = 175 But it said to divide it into two parts... |
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| 37514. |
Solve for \'x\' and \'y\'7(y+3)-2(x+2)=144(y-2)+3(x-3)=2 |
| Answer» The given equations are:7(y + 3) - 2(x + 2) = 144(y - 2) + 3(x - 3) = 2So, 7(y + 3) - 2(x + 2) = 14⇒ 7y + 21 - 2x - 4 = 14⇒ 7y - 2x = 14 + 4 - 21⇒ - 2x + 7y = -3 ........ (i)And 4(y - 2) + 3(x - 3) = 2⇒ 4y - x + 3x - 9 = 2⇒ 4y + 3x = 2 + 8 + 9⇒ 3x + 4y = 19 .............(ii)Multiplying (i) by 4 and (ii) by 7, we get-8x + 28y = -12........(iii)21x + 28y = 133......(iv)Subtracting (iii) and (iv),we get29x = 145x = 5Substituting x = 5 in (i),we get7y = -3 + 10⇒ 7y = 7⇒ y = 1{tex}\\therefore{/tex}\xa0Solution is x = 5, y = 1 | |
| 37515. |
b cos thita = a , then prove that cosec thita + cot thita = √b+a÷√b-a |
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| 37516. |
Find two consecutive multiples of 3 whose product is 648 |
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Answer» Let the\xa0consecutive multiples of 3 be 3x and 3(x + 1).Then, we have\xa0{tex}3x\\times3(x + 1) = 648{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}9x^2\xa0+ 9x - 648 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2\xa0+ x - 72 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2\xa0+ 9x - 8x - 72 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x(x + 9) - 8(x + 9) = 0{/tex}{tex}\\Rightarrow{/tex}\xa0x + 9\xa0= 0 or x - 8 = o{tex}\\Rightarrow{/tex}\xa0x = -9 or x = 8Since x is a positive number, x\xa0{tex}\\neq{/tex}\xa0-9{tex}\\Rightarrow{/tex}\xa0x = 8{tex}\\Rightarrow{/tex}\xa03x = 3(8) = 24 and 3(x + 1) = 3(9) = 27Hence, the required consecutive multiples of 3 are 24 and 27. Language is strange of Sia so I am not understanding please use simple language |
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| 37517. |
Find two consecutive multiples of 3 whose products is 648. |
| Answer» Let two consecutive multiples of 3 be x and (x+3)As per given conditionx (x+3) = 648⇒ x² + 3x = 648⇒ x² + 3x -648 = 0⇒ x² + 27x - 24x -648 = 0⇒ x ( x + 27 ) -24 ( x +27)⇒ ( x - 24) ( x + 27)⇒ x = 24 and x = -27so, we take x = 24.Required multiples of 3⇒ x = 24⇒ x +3 = 24+3 = 27.\xa0 | |
| 37518. |
How to prove the pythagoras theorem? |
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Answer» By similarity of triangle The formula of pythagoras theorem is : H²=P²+B² By practicing |
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| 37519. |
Find the HCF of 8954553 |
| Answer» 676806467649464383455857668523424386876867822734556438349 | |
| 37520. |
Co ordinate geometry |
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| 37521. |
(a+b) (x+y) a²+b² |
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| 37522. |
What is BPT theoram |
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Answer» If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio. This is called Thales Theorem or BPT. Basic Proportionality Theorem |
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| 37523. |
The following distribution gives the daily in come of 50 workers if a factory |
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| 37524. |
Why are there 28 days in feb |
| Answer» Because of the days in a year is 365 and a 1/4 days.This 1/4 day was consider at the every 4th year that we call as a leap year. | |
| 37525. |
What may be the basic questions could be asked in the first terminal of exam |
| Answer» May be related to speed of anything from ch. 3or4From ch. 2 alpha and bita.From ch. 1 related to vriables power | |
| 37526. |
Rs aggarwal mcq chp1 solutions |
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| 37527. |
If the polonomial x⁴+7x³+7x²+px+q is actually divisible by x²+7x+12 find p and q? |
| Answer» Factors of x2 + 7x + 12 :x2 + 7x + 12 = 0{tex}\\Rightarrow{/tex}\xa0x2 + 4x + 3x + 12 = 0{tex}\u200b\u200b\\Rightarrow{/tex}\xa0x(x + 4) + 3(x + 4) = 0{tex}\u200b\u200b\\Rightarrow{/tex}(x + 4) (x + 3) = 0{tex}\u200b\u200b\\Rightarrow{/tex}\xa0x = - 4, -3 ...(i)Since p(x) = x4 + 7x3 + 7x2 + px + qIf p(x) is exactly divisible by x2+ 7x + 12, then x = - 4 and x = - 3 are its zeroes. So putting x = - 4 and x = - 3.p(- 4) = (- 4)4 + 7(- 4)3 + 7(- 4)2 + p(- 4) + qbut p(- 4) = 0{tex}\\therefore{/tex}\xa00 = 256 - 448 + 112 - 4p + q0 = - 4p + q - 80{tex}\\Rightarrow{/tex}4p - q = - 80 ...(i)and p(-3) = (-3)4 + 7(-3)3 + 7(-3)2 + p(-3) + qbut p(-3) = 0{tex}\\Rightarrow{/tex}0 = 81-189 + 63 - 3p + q{tex}\\Rightarrow{/tex}0 = -3p + q -45{tex}\\Rightarrow{/tex}3p -q = -45 ..........(ii)On putting the value of p in eq. (i),we get,{tex}4(-35) - q = - 80{/tex}{tex}\\Rightarrow{/tex}{tex}-140 - q = - 80{/tex}{tex}\\Rightarrow\\ {/tex}{tex}-q = 140 - 80{/tex}{tex}\\Rightarrow\\ {/tex}\xa0{tex}-q = 60{/tex}{tex}\\therefore{/tex}\xa0{tex}q = -60{/tex}Hence, p = -35, q = -60 | |
| 37528. |
Prove that sqrt 5 is irrational |
| Answer» Let take √5 as a rational numberIf a and b are two co-prime number and b is not equal to 0.We can write √5 = a/bMultiply by b both side we getb√5 = aTo remove root, Squaring on both sides, we get5b2 = a2 ……………(1)Therefore, 5 divides a2 and according to a theorem of rational number, for any prime number p which is divided \'a2\' then it will divide \'a\' also.That means 5 will divide \'a\'. So we can writea = 5cand putting the value of a in equation (1) we get5b2 = (5c)25b2 = 25c2Divide by 25 we getb2/5 = c2again using the same theorem we get that b will divide by 5and we have already get that a is divided by 5but a and b are co-prime number. so it is contradicting.Hence √5 is an irrational number | |
| 37529. |
The sum of n term of an AP is n^2+3n. Find its 20 th term |
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| 37530. |
Explain why a number of the form 4q+2, can never a perfect square |
| Answer» No number of the form 4q + 2 is a perfect square because,If q is a prime factor of aperfect square, then q^2 must also be the factor of a perfect square.4q + 2 = 2 (2q + 2), here 2 is a factor of (2q + 2), but 2^2 = 4 is not the factor of (4q + 2) as (4q + 2) = 2(2q + 1), which is odd and we know that all the odd numbers are not divisible by 2.So, we can say that 4q + 2 is not divisible by 4Hence, 4q + 2 is not a perfect\xa0 | |
| 37531. |
Last year paper minmum question same yes ya no |
| Answer» Yes | |
| 37532. |
Find the HCFof 408 and 1032 and expressed it in the form of 1032m-408x5. |
| Answer» 1032 | |
| 37533. |
Find the value of x :5x+2,4x-1 and x-1 are in AP |
| Answer» 0,y | |
| 37534. |
0,y |
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| 37535. |
if x + a is a factor of 3x+6ax + 5x + 8. Find a |
| Answer» a= -1/2 or a=1/3 | |
| 37536. |
5 comes just before |
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Answer» 6 R u sure u r in 10th??????? 6 6 6 |
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| 37537. |
2 x square - 7 x minus 15 is equal Mein zero |
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Answer» x=3 What we have to find in this? |
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| 37538. |
State whether a number 3*5 *13 * 46 + 23 are prime or composite numbers |
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Answer» 3×5×13×46+23=15×13×46+23=195×46+23=8970+23=8993\u200bSince, there are no prime factors of 8993, it is divisible by only 1 and itself.Thus, 8993 is a prime number. 8993 |
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| 37539. |
Prove √5 is an irrational no. |
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Answer» Plzz explain me In ncert tere is an example to prove root 3 instead of 3 you write 5 then it will be prove it is so easy |
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| 37540. |
Is there any change in syaalbus this year for class10???????? |
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Answer» Yes, decrease syllabus with government order. yes |
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| 37541. |
9 6 squared minus 9 10 square barabar hai 9 sec square minus 10 square barabar |
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| 37542. |
Where is test series in home screen |
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Answer» Ten lakh is the correct is right answer Which date of maths test Jb bhi ap ap khologe 1 point test series k h |
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| 37543. |
Online forms 2019 |
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| 37544. |
Sec50 sin40+cos40 cosec50 |
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Answer» Sec(90-40)sin 40+cos50 cosec (90-50) Cosec40 sin 40+cos 50 sec 501+1=2 I think your question is wrongMay be your correct question is, Sec 50 Sin 45 + Cos 45 Cosec 50. |
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| 37545. |
If 1/2 is a root of the equation x^2+kx-5/4=0, then find the value of k. |
| Answer» p(x)=x^2+kx-5/4=0If x=1/2Then p(1/2)= (1/2)^2+k(1/2)-5/4=0 p(1/2)= 1/4+k/2 -5/4=0 => -4/4+k/2=0 => k/2 -1=0 => k/2 =1 => k=2........ans. | |
| 37546. |
Class 10 3 |
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| 37547. |
Tan^2thita -sin^2thita =tan^2thita×sin^2thita |
| Answer» If you mean,\xa0to prove (tan²θ - sin²θ) = tan²θ × sin²θ , then the answer will Be.....\xa0L.H.S = tan²θ - sin²θ\xa0= sin²θ/cos²θ - sin²θ\xa0= sin²θ [ 1/cos²θ - 1]\xa0[ we know, sec x = 1/cos x so, 1/cos²θ = sec²θ]\xa0= sin²θ [ sec²θ - 1]\xa0we also know that, sec² x - tan² x=1so,sec² θ - tan² θ=1or,sec² θ - 1 = tan² θthen, sin² θ [sec²θ - 1] = sin² θ × tan² θ = RHSHence, (tan² θ - sin² θ) = tan² θ × sin² θ. | |
| 37548. |
What do you mean by euclid divisions by lemma |
| Answer» Let a be the positive integer when divided by b then there exists a quotient \'q\' and remainder \'r\' such that a = bq + r , 0 <= r < b. ???????? | |
| 37549. |
If a positive integer p is divided by 3 then find the possible remainder |
| Answer» 0,1 and 2 | |
| 37550. |
Which side book should i perfer for maths class 10th |
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Answer» NCERT and its exempler Glad to have your help aishreet..Thx all for suggestions No RS Agrawal is a bad book and RD Sharma is a quite good but NCERT is the best book and it\'s exampler According to me you must follow RD Sharma if u want to get hundred out of hundred in maths ....as I have given board exam this year that is in the session 2018-19 and you know70% of questions came from RD Sharma this year and 28% of from NCERT in maths board exam.. only their statement was changed and you know what I got 99 in maths..i m very happy...??.. Ncert book or ncert exampler from this book the paper alwsys come RS Agarwal is better than RD Sharma Rd sharma is useful or not for class 10 RS Aggarwal is the best book |
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