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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40151. |
Two vertices of a triangle are at (-3,1)& (0,2) and centroid is at origin , find its third vertex |
| Answer» Let the coordinates of the third vertex be (x, y). Then by centroid formula, coordinates of centroid of given triangle are,{tex}\\left( \\frac { x - 3 + 0 } { 3 } , \\frac { y + 1 - 2 } { 3 } \\right) = \\left( \\frac { x - 3 } { 2 } , \\frac { y - 1 } { 3 } \\right){/tex}We have centorid is at origin (0, 0){tex}\\therefore \\frac { x - 3 } { 3 } = 0 \\quad \\text { and } \\frac { y - 1 } { 3 } = 0{/tex}{tex}\\Rightarrow{/tex}x - 3 = 0\xa0{tex}\\Rightarrow{/tex}y - 1 = 0{tex}\\Rightarrow{/tex}x = 3{tex}\\Rightarrow{/tex}y = 1Hence, the coordinates of the third vertex are (3, 1). | |
| 40152. |
Find the volume of the two cuboids of dimensions 22×2×5+22×8×3 |
| Answer» | |
| 40153. |
If A and B are coprimes then the HCF of a and b |
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Answer» 1 Dont suck HCF-1 |
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| 40154. |
(sin^4A-cos^4A+1)^2cosec^2A=2 |
| Answer» Multiplying both sides by 0.0=0 h/p | |
| 40155. |
is 0.3 a root of Q.E x2-0.9=o?justify. |
| Answer» X2-0.9=0X2=0.9X=0.3Hence justified ? | |
| 40156. |
From when case class 10 board exam going to be started |
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Answer» I think from last week of February And ithink it should be started on end of the february Final exam will be start 5 march to 13 april In February we have computer exam and in March we have other subjects exam. February- computer March- other languages I think from February |
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| 40157. |
By using BODMAS ,solve that 9+6÷3×5-8+3÷4 |
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Answer» 10.25 9+2×5-8+0.75=9+10-8+0.75=19.75-8=11.75 9+6÷3×5-8+3÷4 = 9+2×5-8+0.75 = 9+10-8+0.75 = 19-8.75 = 10.25. 15÷15-11÷4=1-2.75=-1.75 answer |
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| 40158. |
Find the area whose perimeter is 34cm and length is 12 |
| Answer» 264 | |
| 40159. |
(1+cotA+tanA)(sinA-cosA)=secA/cosec2A-cosecA/sec2A |
| Answer» L.H.S\xa0= (1 + cotA + tanA) (sinA - cosA)= sinA - cosA + cotA sinA - cotA cosA + sinA tanA - tanA cosA{tex}= \\sin A - \\cos A + \\frac{{\\cos A}}{{\\sin A}} \\times \\sin A - \\cot A\\cos A + \\sin A\\;\\tan A - \\frac{{\\sin A}}{{\\cos A}} \\times \\cos A{/tex}= sinA - cosA + cosA - cotA cosA + sinA tanA - sinA= sinA tanA - cotA cosA........(1)Now taking ;{tex}\\quad \\frac{{\\sec A}}{{\\cos e{c^2}A}} - \\frac{{\\cos ecA}}{{{{\\sec }^2}A}}{/tex}{tex} = \\frac{{\\frac{1}{{\\cos A}}}}{{\\frac{1}{{{{\\sin }^2}A}}}} - \\frac{{\\frac{1}{{\\sin A}}}}{{\\frac{1}{{{{\\cos }^2}A}}}}{/tex}{tex} = \\frac{{{{\\sin }^2}A}}{{\\cos A}} - \\frac{{{{\\cos }^2}A}}{{\\sin A}}{/tex}{tex} = \\sin A \\times \\frac{{\\sin A}}{{\\cos A}} - \\cos A \\times \\frac{{\\cos A}}{{\\sin A}}{/tex}{tex} = \\sin A \\times \\tan A - \\cos A \\times \\cot A{/tex}.......(2)From (1) & (2),(1 + cotA + tanA) (sinA - cosA) =\xa0{tex}\\frac { \\sec A } { cosec ^ { 2 } A } - \\frac { cosec A } { \\sec ^ { 2 } A }{/tex}\xa0= sinA.tanA - cosA.cotA\xa0Hence, Proved. | |
| 40160. |
3 qual circle of radius |
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| 40161. |
Express 0.6 as a rational number in the simplest form |
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Answer» gwiwdg hlo 3/5 bro Here is your questions answer....0.6 = 6/10 = 3/5. (Ans). |
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| 40162. |
Describe the structure and function s of Nephron . Draw the diagram also |
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Answer» You can get diagram in your NCERT book on page no 111. Diagram also please Thanks a nephron is the structural and functional unitof a kidney . it is also known as the filtering unit of kidney.it consists of bowman\'s capsule ,artr.glomerulus,PCT,DCT ,loop of henle,collecting ductetc.a nephron filters blood ,absorbs useful substances from it and collects harmful substances such as CO2,nitrogeneous waste ,urea in the form of urine. |
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| 40163. |
which book is best for surface area and volume |
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Answer» RD Sharma Rs agrwal Rs agrawal RD Sharma |
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| 40164. |
Prove 3+2√5 is irrational |
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Answer» Yes it is irrational no. Let 3+2root 5 be rational and 3+2root5 =r where r is rational.3+2root5=r2root5=r-3Root5=r-3\\2Thereforer-3/2 is rational Root5 is also rationalBut this is a contradiction as we know that root5 orrational.Therefore.3+2root5 is irrational |
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| 40165. |
About distance formula and write the correct formula |
| Answer» Distance formula is used to find the distance between two given points on graph. The exact formula used for finding distance between coordinates of two points is :-√(X2-X1)² + (Y2-Y1)². | |
| 40166. |
Find the zeroes of polynomial ×square+8××15 |
| Answer» x2 + 8x + 15 = 0x2 + 5x + 3x + 15 = 0x(x + 5) + 3(x + 5) = 0(x+ 5) (x + 3) = 0x + 5 = 0, x+ 3 = 0x = -5 or x = -3 | |
| 40167. |
Write the number which when divided by 47 gives 23 as reminber solve |
| Answer» 14 and 13 | |
| 40168. |
X^3+x^2+x-1=0 fin the roots of the eqn |
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| 40169. |
How to find out a very easy steps of any digit of square number I\'m forgot then i will asking u |
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| 40170. |
How many forms of ap 9,17,25 must be taken to give sum of 636 |
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Answer» 12 X= 79 [approx] 12 |
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| 40171. |
Find all the zeroes of 2x4 - 3 x3 -3x2+6x-2 |
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| 40172. |
1235+7891 |
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Answer» 9126 9126 will be the answer 9,126 9126 9,126 |
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| 40173. |
What is the formula of area of minor sector? |
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Answer» Theta/360 × πr^2 {π¤\\360 - sin[¤\\2]cos[¤\\2]}r² |
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| 40174. |
In a family of 3 children, find the probability of having at least one boy |
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Answer» 7/8 1/3 P (boy)=1/3 P(at least one boy) = 7/8. |
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| 40175. |
If m^th term |
| Answer» Let a and d be the first term and common difference respectively of the given A.P. Thenan = a + (n - 1)d{tex}\\frac { 1 } { n } ={/tex}\xa0mth term\xa0{tex}\\Rightarrow \\frac { 1 } { n } {/tex}= a + ( m - 1 ) d\xa0...(i){tex}\\frac { 1 } { m }{/tex}= nth term{tex}\\Rightarrow \\frac { 1 } { m } {/tex}= a + ( n - 1 ) d\xa0...(ii)On subtracting equation (ii) from equation (i), we get{tex}\\frac { 1 } { n } - \\frac { 1 } { m } = {/tex} [a+ (m-1) d] -[ a+ (n -1)d]= a + md - d - a - nd + d{tex}= ( m - n ) d{/tex}{tex} \\Rightarrow \\frac { m - n } { m n } = ( m - n ) d {/tex}{tex}\\Rightarrow d = \\frac { 1 } { m n }{/tex}Putting d = {tex}\\frac { 1 } { m n }{/tex}\xa0in equation (i), we get{tex}\\frac { 1 } { n } = a + \\frac { ( m - 1 ) } { m n } {/tex}{tex}\\Rightarrow \\frac { 1 } { n } = a + \\frac { 1 } { n } - \\frac { 1 } { m n } {/tex}{tex}\\Rightarrow a = \\frac { 1 } { m n }{/tex}{tex}\\therefore{/tex}\xa0(mn)th term = a + (mn - 1) d=\xa0{tex}\\frac { 1 } { m n } + ( m n - 1 ) \\frac { 1 } { m n } {/tex}{tex}\\left[ \\because a = \\frac { 1 } { m n } = d \\right]{/tex}= {tex}\\frac { 1 } { m n } + \\frac { mn } { m n } - \\frac { 1 } { m n }{/tex}= 1 | |
| 40176. |
Any tips and tricks for preparation of board exam? I want to get science stream ? |
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Answer» First do board exams and then see medical stream. Dont take much stress and sit for studies 24 hrs Do hardwork as much as you can do . And be prepare yourself for science stream.and let me tell you one thing ,if you are thinking about science stream so don\'t change your mind at that time because the same thing has been happened to me. eat your teachers **** |
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| 40177. |
A cistern. Internally measure 159cm×120cm×110cm has 129600cm^3of water |
| Answer» Bhghh | |
| 40178. |
The sum of first 4 of an AP is 1/2. The sum of next 4 terms |
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Answer» Where is the sum of next four terms Your question is incomplete rashid |
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| 40179. |
It is true that there will two question paper for maths.. |
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Answer» If I have take PCB so which Question paper I should choose OH | really. .....................? Yes it is true you can opt any one of them but let me tell you one thing always choose tuff question paper that will help in your studies It is true but not for the year 2018 _ 19 . CBSE just planned for it . It is not for our board exams. |
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| 40180. |
If ax^2+bx+6 does not have two distinct real roots then find the value of 3a+b |
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| 40181. |
Prove thatsin theta(1+tantheta)+costheta(1+cottheta)=sectheta + cosectheta |
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Answer» LHS=sin theta (1+sin theta /cos theta) +cos theta (1+cos theta /sin theta)=sin theta /cos theta (sin theta +cos theta) +cos theta /sin theta (sin theta +costheta)=( sin theta +costheta) (sin theta /cos theta +cos theta /sin theta)=sin theta +costheta /sin theta *costheta)=1/cos theta +1/sin theta=sec theta+cosec theta=RHS(proved)Hope this will help you ☺️ Brain is the part of our body inside our head that controls our thoughts feelings and movements.??? What is brain |
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| 40182. |
Find all the zeros of the polynomial(2x^4-9x^3+5x^2+3x-1) if two of its zeros are(2+√3)and(2-√3) |
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| 40183. |
If areas of two similar triangles are equal.prove that they are congruent. |
| Answer» Given :\xa0{tex}\\triangle \\mathrm{ABC}{\\sim} \\triangle \\mathrm{PQR}{/tex}\xa0&ar\xa0{tex}\\triangle \\mathrm{ABC}{/tex}\xa0= ar\xa0{tex}\\Delta \\mathrm{PQR}{/tex}{tex}{/tex}To prove:\xa0{tex}\\triangle \\mathrm{ABC} \\cong \\triangle \\mathrm{PQR}{/tex}Since,\xa0{tex}\\triangle \\mathrm{ABC}{\\sim} \\Delta \\mathrm{PQR}{/tex}ar\xa0{tex}\\triangle A B C=\\text { ar } \\triangle P Q R{/tex}\xa0(given){tex}\\frac{{\\Delta ABC}}{{ar\\Delta PQR}} = 1{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{{A{B^2}}}{{P{Q^2}}} = \\frac{{B{C^2}}}{{Q{R^2}}} = \\frac{{C{A^2}}}{{P{R^2}}} = 1{/tex}[Using Theorem of area of similar Triangles]{tex}\\Rightarrow{/tex}\xa0AB = PQ, BC = QR & CA = PRThus,\xa0{tex}\\triangle \\mathrm{ABC} \\cong \\triangle \\mathrm{PQR}{/tex} | |
| 40184. |
Find the roots.(x-5)(x-6)=25/24² |
| Answer» According to the question,{tex}(x - 5)(x - 6) = \\frac{{25}}{{{{\\left( {24} \\right)}^2}}}{/tex}{tex}\\Rightarrow x(x - 6) - 5(x - 6) = \\frac{{25}}{{{{(24)}^2}}}{/tex}{tex}\\Rightarrow {x^2} - 6x - 5x + 30 - \\frac{{25}}{{{{(24)}^2}}} = 0{/tex}{tex}\\Rightarrow {x^2} - 11x + 30 - \\frac{{25}}{{{{(24)}^2}}} = 0{/tex}{tex}\\Rightarrow {x^2} - 11x + \\frac{{30 \\times {{24}^2} - 25}}{{{{(24)}^2}}} = 0{/tex}{tex} \\Rightarrow {x^2} - 11x + \\frac{{30 \\times 576 - 25}}{{{{(24)}^2}}} = 0{/tex}{tex} \\Rightarrow {x^2} - 11x + \\frac{{17280 - 25}}{{{{(24)}^2}}} = 0{/tex}{tex}\\Rightarrow {x^2} - \\frac{{264x}}{{24}} + \\frac{{145}}{{24}} \\times \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow {x^2} - \\left( {\\frac{{145}}{{24}} + \\frac{{119}}{{24}}} \\right)x + \\frac{{145}}{{24}} \\times \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow {x^2} - \\frac{{145}}{{24}}x - \\frac{{119}}{{24}}x + \\frac{{145}}{{24}} \\times \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow x\\left( {x - \\frac{{145}}{{24}}} \\right) - \\frac{{119}}{{24}}\\left( {x - \\frac{{145}}{{24}}} \\right) = 0{/tex}{tex}\\Rightarrow \\left( {x - \\frac{{145}}{{24}}} \\right)\\left( {x - \\frac{{119}}{{24}}} \\right) = 0{/tex}{tex}\\Rightarrow x - \\frac{{145}}{{24}} = 0{/tex} or {tex}x - \\frac{{119}}{{24}} = 0{/tex}{tex}\\Rightarrow x = \\frac{{145}}{{24}}{/tex} or {tex}x = \\frac{{119}}{{24}}{/tex} | |
| 40185. |
(M/3+3/n)^2-2mn |
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| 40186. |
A coin is tossed once.what is the probability of getting tail? |
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Answer» 1/2 1 |
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| 40187. |
NCERT examplar math guide important question of chapter 6th. |
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| 40188. |
Volume of cone height 13 radius 4 |
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Answer» It is wrong By the help of1/3×22/7 ×16 ×13=217.90 |
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| 40189. |
If 9 is Pythagoras |
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| 40190. |
Find the 7th term the end of the AP:7, 10,13......,154. |
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Answer» Seventh term from the last will be 136 7th term of the AP will be 25 |
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| 40191. |
If an ap consists 5terms2,4,6,8,______10find nth terma |
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Answer» n= 3 An = n × d. |
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| 40192. |
Can you add a workbook solution for class 110th? |
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| 40193. |
Step-deviation |
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| 40194. |
Multiples of 2 |
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Answer» The number which is end with even number are multiples of 2 . Ex.2,4,6,8 ,0 and so on 2,4,6,8,10,12and so on |
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| 40195. |
can the number 6n, n being a natural number, end with the digit 5? Give reason |
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Answer» 6n = (2×3)n and we know that the no. which end with 5 it must have 5 as its factor .So it does not end with 5 If any number ends with 5, then it will be divisible by 5 . Here 6 is not divisible by 5 .so, that 6n can not end with 5 |
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| 40196. |
Ch 10 ncert solution |
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Answer» Circles Bhai google pe seach karle?? Just sel up Gobar |
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| 40197. |
Whate is sin cos |
| Answer» Trignometric ratios signs | |
| 40198. |
SinA cosC +cosA sinC |
| Answer» What is the question ? What we have to prove? | |
| 40199. |
Find a,band c such that the following numbers are in the AP a,7,b,23 and c |
| Answer» a+d=7a+3d=23Solving these we get,a=-1 d=8Hence b=15 c=31 | |
| 40200. |
The nth term of the pattern is given by 3n+2.find the.(a) 12th term |
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Answer» N12 =3 (12)+2N12 =36+2N12 =38 12 th term = 3×12+2=38 Find the n term |
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