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62001.

After 15 years, Mary's age will be four times of her present age. Find her present age.

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Her present age is 5 years

62002.

After 15 years , Mary's age will be four times of her present age. Find her present age.

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62003.

4 years hence the mother will be twice of his son, the sum of present age is 46, find present age

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Let the present age of mother and her son be x and y years respectively.It is given that , sum of their present age is 46.=>x+y=46----------(1)Four years hence,Mother's age=x+4Son's age=y+4

It is given that 4 years hence, mother's age will be twice that of son's age.=>(x+4)=2(y+4)==>x-2y=4------------(2)

eqn(1)×2=>2x+2y=92eqn(2)×1=>x - 2y=4------------------------------------------------ 3x=96=>x=32=>y=46-x=46-32=14

∴Mother's present age=32Son's present age=14

Thnks ji

62004.

16. Present age of father is 42 years and that of his son is 14years. Find the ratio of(a) Present age of father to the present age of son.

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62005.

14. What must be subtracted from &r4+ 14x-2r+ 7x-8 so that the resulting polynomial isexactly divisible by 4x2 3x -2

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solve after diviend-remainder=quotient ×divisor

62006.

ll nliensIรณn 46 cm by 30 em. Finduiunig the photograph.The length and breadth of a rectangular park are in the ratio 8:5. A path 2 m wide, unng all armund outridnthe park has an area of 640 m2 Find tho d

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let the length and breadth be 8x and 5x

total length including path = 8x+4

total breadth including Path = 5x+4

area of path = total area - area of park

640 = (8x+4)*(5x+4) - 8x*5x

640=40x²+32x+20x+16-4x²

640=52x+16

-52x=16-640

-52x=624

x=12

length = 8*12=96m

breadth = 5*12= 60m

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62007.

The difference between CompoundInterest and Simple Interest on a certainsum for 2 years at 15% per annum isR180. Find the sum.9.

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62008.

The difference between the compound interest and the simple interest on a certain sum for3 years at 10% per annum is 93 . Find the sum.

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62009.

Fig. 6.15An Fig. 6.16.ifyz. then prove that AOB1803 bis a line

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62010.

x + x + 26 + x / 3 = 180

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3x+26/3 = 180

3x+26 = 540

3x = 540-26

3x = 514

x = 514/3

x = 171.33

62011.

750 watts water pump raises 1200 litres of waterfrom the ground to a water tank in a given time.How many watts water pump is needed to raise1800 litres of water from the ground in the sameamount of time?

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750 pumps 1200 in time tTo pump 1800 we need (750/1200)*1800=1125 watts.

62012.

The area of trapezium is 960 cm2. If the parallel sidesare 34 cm and 46 cm, find the distance between them.

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62013.

( 3 ^ { - 7 } \div 3 ^ { - 10 } ) \times 3 ^ { - 5 }

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62014.

ot be uue 101cumple is Find AB ir A-Cand BC)

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A*B=zero. .........

AB= 0.

62015.

LEVEL-212. What must be added to the polynomial f(x) = x+ + 2x3 - 2x² + x - 1 so that theresulting polynomial is exactly divisible by x² + 2x - 3?

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62016.

The ratio of age of a&b is 7:9 after 4 year the sum of their ages is 104 find present age of a and b

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Suppose their ages are7xand 9xnow7x+9x+8= 10416x= 96x= 6

their ages will be7*6= 42 yearsand 9*7= 63 years

Thnks ji

62017.

49. What must be subtracted from the polynomial pix) = x + 2resulting polynomial is exactly divisible by - 4x +32(CBSE-13-A9EU82]- 13 - 12x + 2. Soma(CBSE-13-DSGZHOX)

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62018.

9. At a certain rate of simple interest, a certainsum of money amounts to 5440 in3 years and 6400 in 5 years. Find theprincipal and the rate of interest.

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62019.

11 - ( - 5 ) ^ { 2 } \div ( - 2 )

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11-(-5)²+(-2)=11-25-2=11-27=-16

62020.

If the difference of compound interest and simple interest on certainamount invested for 2 years at the rate of 2 % per annum is Re. 1, thenlo interest, on certain sumfind the principal.

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Let principle be pSI = Px5/2x2/100SI = P/20 =.05P

CI = Amount after two years - P= P(1 + 5/200)^2 - P= P(1 + 1/40)^2 - P= P(41/40)x(41/40) - P= 1.0506P - P=.0506P

According to given condition

CI - SI = 1.0506P -.05P = 1.0006P = 1P = 10000/6P = 1666.7 ans

62021.

4. The compound interest, calculaleua certain sum of money for the secondyear is * 1,089 and for the third year it is71,197.90. Calculate the rate of interest andthe sum of money.7oars at a certain

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your answer is wr6

62022.

Find the cartesian coordinates of the points (2, 180-), 3,

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62023.

( 2 ^ { - 9 } \div 2 ^ { - 11 } ) ^ { 3 }

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62024.

) length46 cm and breadth = 25 cm

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thanks

62025.

7 m 11 cm \div 3

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62026.

Write the equation of ellipse 20x^2 +9y^2 =180 in standard form.

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62027.

1. Divide the Polynomial P(x)=x4–3x2+4x+5 by the Polynomial g(x)=x2-x+1 andfind the quotient and the remainder.

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X²-x+1 ) x⁴-3x²+4x+5 (x²+x-3.............. x⁴+1x² -x³...............- -. +.............. x³-4x²+4x............. x³-1x²+ 1x.............. - + -.............. -3x²+3x+5.....................-3x²+3x-3.....................+ - +..................... 8Hence Remainder is 8Quotient is x² + x - 3

62028.

104 TOJ TUTUuue9. If 1 and -1 are zeroes of the polynomial ax 4 -bx3 + cx + dx + e = 0, show thata+c+e= b + d = 0

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62029.

e 2c roes the polunoverify the relations between the 6 Coew、lendand the zeyoesciendS-. Sol

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Given polynomialx^2 + x/6 - 2 = 06x^2 + x - 12 = 06x^2 + 9x - 8x - 12 = 03x(2x + 3) - 4(2x + 3) = 0(3x - 4)(2x + 3) = 0x = 4/3, - 3/2

For polynomial of formax^2 + bx + c = 0

Sum of zeroes = 4/3 - 3/2 = (8-9)/6 = - 1/6- b/a = - 1/6

Product of zeroes= 4/3*-3/2 = - 2c/a = - 12/6 = - 2

62030.

What must be added to polynomialp(x) 6x5+5x4+1t-3x2 +x 1, so that theresulting polynomial is exactly divisible by3x2 -2x + 4? (Hint: add-r(x) in p(x))

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62031.

I + 71 =(

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PLEASE HIT THE LIKE BUTTON

62032.

what will the SI and amount when:Principal=₹1500Rate=₹12/p.a.Time=3years3months

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62033.

71÷7

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71÷7=10.14 your answer is 10.14

62034.

In Fig. 6.37, if ∆ABE~∆ ACD, show that∆ADE~∆ABC.

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1

2

62035.

Fig.3110. In Fig. 32, ABCD is a rectangle of length AB- 40 cm and breadth BC 25 cm. If P, Q, R. Sbethe mid-points of the sides AB, BC, CD and DA respectively, find the area of the shadedregion.:0nswer Book For Wrting an answer.(indluding Heading)UseFig. 322 cm

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62036.

54 \div 11

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11)54(4 44 -------- 10

54/11 = 4(10/11)

It is right solution

R u shore, it is right solution

62037.

\frac{54+3 \times 16+2}{180+5 \times 6 \div 3}=?

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62038.

f a and b are two vectors such that a | 5, b | 4 and a.b 10 find theanglebetween a and b and hence find ax b

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mere questions ka ye value nhi h

|a×b| bhi find Karna h

62039.

8000 for 9 months at 20% per annum compoundedFind the compound interest onquarterly8.

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62040.

Find the amount of15625 for 9 months as 16% per annum, when the interest is compounded quarterly.

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62041.

Q. 11 Find compound interest when P= Rs. 10,000, R= 16% PaT-9months interest compounded quarterly

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62042.

nd2x5+b,whendevdedby(xt4)polynomial bx3 3x2-2eaves the remainder 7i and r spectively. find the valse of b 2

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thanks for answer

62043.

11Prove that the altitude from vertex of an isosceles triangle bisects the base.

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By RHS rule both triangle are congurent so by CPCT BD=DC

62044.

5 Prove that the circle drawn on any one of theequal sides of an isosceles triangle as diameterbisects the base.

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62045.

7 475 o के

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62046.

Find the CI for.(a)28000, time-6 months, rate12% per annum with interest being compoundedquarterly

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62047.

475/71

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is sawaal ka answer 6.69 hai

6.6901 is the correct answer

475 ÷ 71 = 6.6901408451 =6.69so 6.69 is the answer of the following question

475÷71= 6.6901....... is the ans of this question

correct answer is 6.69014085

correct answer=6.6901408451

6.69 is the correct answer

6•6901 is the right answer.

correct answer is 6.690140845070422

please like my answer

62048.

(2 . 475 ol ा...

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62049.

312 \div 54

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312÷54=5.78 is the value

It is right solution

I'm not getting correct solutions, how it will got it, If u show me in detail

Pls

62050.

3.Ifa = S and b = 25, verify a-bb-a.

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