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Side of square plot = 80mwidth of path = 4marea of the road= 80*80-(80-4)*(80-4)6400-5776624m^2

Radius of circular field = 20m

As, we know area of circle is given by the formula → πr²

So, Area of circle = (22/7) (20)²

= (22/7)(400)

= 1257.14 m²

If the width of path is 5m then the radius of circle when we remove the path = (20-5)m= 15m

Area of circle without path

= (22/7)(15)²

=( 22/7)(225)

=707.14 m²

So, The area of path will be →

Area of whole circle​ - Area of circle without the path

= 1257.14 - 707.14

= 550 m²

(0,3) (8,6) distance

by expanding the options we get option 1 as 7/4.

Given: Δ ABC ~Δ PQR

To Prove: ar(ΔABC) / ar(ΔPQR) = (AB/PQ)2= (BC/QR)2= (CA/RP)2

Construction: Draw AM⊥ BC, PN ⊥ QR

ar(ΔABC) / ar(ΔPQR) = (½× BC× AM) /(½ ×QR × PN)

= BC/QR× AM/PN ... [i]

In Δ ABM and Δ PQN,

∠B = ∠Q (Δ ABC ~ Δ PQR)

∠M = ∠N (each 90°)

So,Δ ABM ~ Δ PQN (AA similarity criterion)

Therefore, AM/PN = AB/PQ ... [ii]

But, AB/PQ = BC/QR = CA/RP (ΔABC ~ Δ PQR) ... [iii]

Hence, from (i)

ar(ΔABC) / ar(ΔPQR) = BC/QR× AM/PN

= AB/PQ× AB/PQ [From (ii) and (iii)]

= (AB/PQ)2

Using (iii)

ar(ΔABC) / ar(ΔPQR) = (AB/PQ)2= (BC/QR)2= (CA/RP)2

Salary is 60000 75% is expense so expense=45000now salary increased by 25% so new salary=60000*1.25=75000expense is increased by 15% so new expense=45000*1.15=51750so saving=75000-51750=23250

Area of the room= length×breadth=8×5=40 sq.mLength of the room including verandah=8+2+2=12mBreadth of the room including verandah=5+2+2=9mHence,Area of the room including verandah=12×9=108 sq.m∴,the area of the verandah is=(area of the room including verandah-area of the room)=108-40 =68sq.m

1

Here PQ = PR ( Isosceles triangle ) , so from base angle theorem we get∠PQR =∠PRQ , So

∠TQR =∠SRQ------- ( 1 ) ( As∠PQR =∠TQR and∠PRQ =∠SRQ )And

∠TRQ =∠SQR -------- ( 2 ) ( Given QS and RT are bisectors of∠PQR and∠PRQ respectively )In ,∆TQR and∆SRQ

∠TQR =∠SRQ ( From equation 1 )QR = QR( Common side )And∠TRQ =∠SQR ( From equation 2 )So,∆TQR≅∆SRQ( By ASA rule )

Therefore ,

QS = RT ( By CPCT ) ( Hence proved )

LHS = (sinA-cosA+1)/(sinA+cos-1) = (1 + sinA) (1 - sinA)/cos A(1 - sinA) = 1 - sin2A/cos A(1 - sinA) = cos2A/cos A(1 - sinA) = cosA/(1 - sinA) = 1/ (1/cosA - sinA/cosA) = 1/(secA - tanA) = RHS Hence Proved

Thanks Bhaiya

Let the outer rectangle be ABCD and the inner rectangle be abcd.

Length and Breadth of the outer rectangle = 120 meter and 85 meter.Area of outer reactangle Ao = 120*85 = 10200 m^2

The uniform width of the inside path is 3.5 meter,So, the length of the inner rectangle = 120 - 7 = 113 mand the breadth of the inner rectangle = 85 - 7 = 78 mThe area of the inner rectangle Ai = 113× 78 = 8814 m^2

The area of path= Ao - Ai= 10200 - 8814= 1386 m^2

Remaining area = area of inner rectangle = 8814 m^2

smallest number=7

The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 9135 = 5 x 756 = 2 x 2 x 2 x 791 = 7 x 13LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.2)

148×320=47360 320 boxes will cost 47360

= 320×cost of one chocolate box= 320×148= 47360

29and73

Let the two digit number be xy

x + y = 8

Right away I can logically see that, since the value

increases if the digits are reversed, our choices are:

17

26

35

If I reverse 17 I get 71 .. This is more than an 18 increase

If I reverse 26 I get 62 ... This is more than an 18 increase

If I reverse 35 I get 53... 35 + 18 = 53 so this is my answer

*************************************

Now algebraically:

x + y = 8 {equation 1}

The value of xy is 10x + y

The value of yx is 10y + x

10y + x = 10x + y + 18

9y - 9x = 18

9(y - x) = 18

y - x = 2

From equation 1: y = 8-x

8 - x - x = 2

8 - 2x = 2

-2x = -6

x = 3

y - x = 2

y - 3 = 2

y = 5

Originalnumber xy = 35

Radha read 1/6 part of book in. Morning

Radha read 3/6 part of book in evening

Therefore,Part of book she read in a day= 1/6 + 3/6= 4/6= 2/3

there is no answer

0 has no reciprocal

0 is the number which has no reciprocal

1) (1/2)^-6 = (2)^6 = 2*2*2*2*2*2 = 64

2) 15 km distance covered by 30 ltr gas1 km distance covered by 30/15 ltr gas

Then,20 km distance get covered by (30/15)*20 = 40 ltr gas

Area of path with be 3m*perimeter of plothence3*2(l+b)=6(100)=600m^2

115 is the answer as we move according to table of 11...

Ans. 115Explanation: 93-82 = 11192-148=44247-192 = 55

the difference is increasing in multiples of 11.

Let the no. be X. therefore X-93 = 22=> X = 115

Also we can verify the answer by considering, 148-X = 33=> X = 115

879÷2=439.5is the best answer.

3/5*100= 60 percentage7/10*100= 70 Percentage

60% 70% is the correct answer of the given question

(i) 3/5 = 0.6.(ii) 7/10 = 0.7.

(1) 3/5= 0.6 (ii) 7/10=0.7

60% and 70% is the right answers

60% and 70% is the right answer

1st is 60persent2nd is 70 persent

125%

125%

thànks

16 ÷ 4= 74First add 1+6=7then 16÷4 = 4, Together the number will be now 74.Similarly, 21÷ 7= 33add 2+ 1= 3Then 21÷7=3 , together 33Likewise, 81÷ 9= 99add 8+1=9, 81÷9=9, together it is 99. Next 55÷ 5= ?First add 5+5=10next 55÷5=11, together it is 111 answer.