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Equal implies that discrimanat is 0So,(-2k)² - 4 × k × 6 = 04k² - 24 k = 0k² - 6k = 0k ( k - 6) = 0So, k = 0 or 6k = 0 not satisfied so, k = 6

5x^2 + 3x - 14 = 05x^2 + 10x - 7x - 14 = 05x(x + 2) - 7(x + 2) = 0(5x - 7)(x + 2) = 0x = 7/5, - 2

For One shirt cloth required will.be 49/2*1/35=7/2*5=7/10=0.7m

531 is correct answer.

Forty Four crore Thirty Eight Lakh Seventy One Thousand Two Hundred and Three.

Take the unknown number to be x1/3 x +1 =15x/3 = 15 - 1x/3 = 14x = 14 × 3x = 42

Hence the number is 42 .Hence proved.

let the number be x sox/3 + 4 = 16x/3 = 16-4x/3 = 12x = 36

4x^2 + 13x + 6 = 0

Discriminant = b^2 - 4ac = (13)^2 - 4(4)(6) = 169 - 96 = 73Root D = Root 73

x = [-b + Root D]/2a or [-b - Root D]/2ax = [-13 + root 73] / 8 or [-13 - root 73] / 8

the 4 digit number is aabb

now for a no. to be divisible by 11, the difference of off odd place number and even place number is multiple of 11

here it is (a+b) -(a+b) = 0

which is a multiple of 11 , so the number aabb is always divisible by 11

so 11 = 2k+1 => 2k = 10 or k = 10/2 = 5

there is hundred digit word

The four digit number is in decimal 9×10×10×10=9000

9×10×10×10=9000 is the answer

9000 is the correct answer of your question

the correct answer isthere are hundred digit words

The answer is 9999-999=9000

9×10×10×10=9000is The answer

there is 9000 four digit number.

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x²-2ax+a² -b² =0so(x-a)² - b² = 0(x-a-b)(x-a+b) = 0sox = a+b and a-b

1/x + 1/ x -2 =3;; x-2-x/x(x-2)=3; -2/ x^2-2x; =3; -2=3x^2-6x+2;

1/x-1/x-2=3x-2-x/x^2-2x=33x^2-6x= -23x^2-6x+2=0according to shridhar acharya x = -b+-√b^2-4ac/2a a= 3, b= -6, C= 2x= 6+-√36-4×3×2/2×3 = 6+-√36-24/6= 6+-√12/6= 6+-2√3/6x= +6+2√3/6=2(3+√3)/6=3+√3/3x= 6-2√3/6=2(3-√3)/6=3-√3/2

(x/3) + 5 = 8 (x/3) = 3 x = 9

let the number be x(x/3) +5 =8(x/3)=8-5(x/3)=3x=3*3x=9

your answer is x= 9

3 added to 5 gives the number =8

Volume of bottle Vb= length*breadth*height

Given length = 5 cm, breadth = 3 cm, height = 10 cm

Then,Vb = 5*3*10 = 150 cm^31 cm^3 = 1mlVb = 150 ml

Girl has to take medicine 5 ml three times a day, in a day she will take = 5*3 = 15 ml

Therefore, medicine last for number of days = 150/15= 10 days

unable to understand

equation 1 and 2 so equal krrne ke liyee *2 kiye haii??

Quadratic formula is X= -b √b^2-4ac/2ax^2 - 5x = 0a = 1 b = -5 c = 0x = (5 ± √(25 - 0))/2x = (5 ± 5)/2x = 0x = 5

Thanks sir ji

3 injection in a day OR 3 injection per dar 1 injection = 5ml medicine3 injection = 5×3 = 15 ml medicine15ml medicine will she need for one day.

15 mL is the best answer

3 injection per day ,medicine per injection is 5ml so, 5*3=15 my medicine is the answer

neetu takes 3 injection in a dayeach injection = 5ml3injection = 5×3= 15ml in a day

for 5 day injection= 3×5=15total = 15×5= 75ml

1 injection=5ml of medicinein one day she take 3 injectiontherefore3 injection=3x5ml in one day =15ml of medicine in one day

5×3=1515ml is the answer

6¹=66²=366³=216.........for any value of 6 raised to n will have unit digit 6

10! +1 +1 = 10! +2 10! +1 + 3 = 10! + 410! +1 + 6 = 10! +710! +1 +7 = 10! +8

we can factorise all the numbers so there are two factor therefore, none one is prime.

Answer: B)104Solution:let a=52 b=53(a+b)+(a-b)= (52+53)+(52-53)=105+(-1)=104

Year is represented by y axis as we 0bserve there is difference of 4 years between each unit

1 unit length represent 4 years

It is AP starting at 100 ending at 995 and common difference is 5995 = 100 + (n-1)*5895/5 = n-1n = 179 + 1 = 180

thanks

Since, H.C.F. of the two natural numbers = 59, so we can write -

A = 59x and B = 59y

Using H.C.F× L.C.M. = Product of two numbers

59x× 59y = 59× 590

⇒ xy = 10

So, sets of possible numbers are = (1, 10,)(10, 1) and (2, 5)(5, 2)

Hence, 4 numbers sets of possible numbers are (59, 590), (590, 59), (118, 295) and (295, 118)

35 X 98 is equal to 35 30

-35×98. =3530.

tan^x-sec^x=-1hencetan^2(75)-sec^2(75)=-1

Nature of rootsD=b^2-4acD=144-4*4*5=144-80=64As discriminant is greater than 0 hence roots are distinct and real

we can use the identity a³+b³ = (a+b)(a²+b²-ab)

here a = sinx , b=cosx so sin³x+ cos³x = (sinx+cosx)*(sin²x+cos²x-sinxcosx).but sin²x + cos²x = 1 so, sin³x+ cos³x = (sinx+cosx)*(1-sinxcosx).

x = -(-5) whole root of {(-5)² -4 ×3×2 } upon 3×2

x = {5 + or - √(25-24)}/6x = {5 + or - 1}/6x = 6/6 and 4/6x = 1 and 2/3