InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4051. |
Find the radius of the circle escribed to the triangle ABC (Shown in the figure below) on the side BC ifangleNAB=30^(@), angleBAC=30^(@), AB=AC=5. |
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Answer» `((10sqrt(2)+5sqrt(3)-5)(2-SQRT(3)))/(2sqrt(2))` |
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| 4052. |
Using determinants find equation of line passess from point (1,2) and (3,6) |
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| 4053. |
Find int (1)/( sin x cos^(3) x) dx |
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| 4054. |
If a,b,c ge 4are integers, not all equal, and 4abc = (a + 3) (b + 3) (c + 3), then what is the value of a + b + c ? |
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| 4055. |
If f(x) =(sin [x])/([x])" at "[x] ne 0 and f(x)=0" at "then " underset(x to 0)"Lt" f(x)= |
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Answer» 0 |
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| 4056. |
IfA =({:( 1,1,1),( 1,omega ^(2) , omega ),( 1 ,omega , omega ^(2)) :})where omega is a complex cube root of unity then adj -Aequals |
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Answer» `(OMEGA ^(2) -omega ) VEC A ` |
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| 4057. |
Find the equation of normal to the parabola y^(2) = 4x and whose slopeis 2. |
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| 4058. |
The projections of a line segment on x, y and z axes are respectively 3, 4 and 12. The length of the line segment is |
| Answer» Answer :D | |
| 4059. |
Let n be a positive integer. Find the maximum number of non congruent triangles whose side lengths are integers less than or equal to n. |
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| 4060. |
A fair die is tossed twice. The probability of getting 4, 5 or 6 on the first toss and 1,2,3 or 4 on the second toss is |
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Answer» `7//36` |
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| 4061. |
Evaluate the following improper integrals with infinite limits on the basis of their definition : (a) int_(2)^(oo)(xdx)/(sqrt((x^(2)-3)^(3))), (b) int_(1)^(oo)(dx)/(x+x^(3)), (c ) int_(0)^(oo)(xdx)/(sqrt((4x^2+1)^(3))), (d) int_(1)^(oo)(dx)/(x^(2)(1+x)), (e) int_(-oo)^(oo)(dx)/(x^(2)-6x+10), (f) int_(0)^(oo)e^(-x)sinxdx |
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Answer» (C ) `1;` (d) `1-1n2;` (e ) `pi;(F)(1)/(2)`. |
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| 4062. |
If the coordinate axes are the bisectors of the angle between the pairs of lines ax^(2) + 2hxy + by^(2) = 0 , where h^(2) gt ab anda ne b, then |
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Answer» `a + B = 0` |
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| 4063. |
If 4 fair coins are tossed find the probability of getting 2 heads and 2 talls. |
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| 4064. |
""^20C_0 + ""^20C_1 + ""^20C_2+…….+""^20C_10 = |
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Answer» `[2^19 - 1/2. ""^18C_10]` |
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| 4065. |
Does the graph below represent a function or a relation? (##CEN_GRA_C01_S01_002_Q01.png" width="80%"> |
| Answer» Solution :Vertical LINE X = 2 meets the above graph at (2, 1) and (2, 2). Hence the graph does not represent a FUNCTION. | |
| 4066. |
A company produces two types of leather belts A and B on which the profits are Rs. 40 and Rs. 30 per belt respectively. Each belt of type A requires twice as much time as required by a belt to type B.If all belts were of type B the company could produce 1000 belts per day. But the supply of leather is sufficient only for 800 belts per day. Belt A requires a fancy buckle and only 400 fancy buckles are available per day. For belt of type B only 700 buckles are available per day. How should the company manufacture the two types of belts in order to have maximum overall profit? |
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| 4067. |
Let R be the relation in the set N given byR = {(a,b) : a = b -2, b gt 6}. Choose the correct answer. |
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Answer» `(2, 4) in R` |
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| 4068. |
The sequence 9, 18, 27, 36, 45, 54,….. consists of successive mutiple of 9. This sequence is then altered by multiplying every other term by -1, starting with the first term, to prduce the new sequence -9, 18, -27,36,-45, 54,…….. If the sum of the first n terms of this new sequence is 180, determine n. |
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| 4069. |
A line passes through two points A(2,-3,-1) and B(8,-1,2). The coordinates of a point on this lie at distance of 14 units from a are |
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Answer» `(14,-1,5)` |
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| 4070. |
Let PQ be a focal chord of the parabola y^2=4ax. The tangents to the parabola at P and Q meet at a point lying on the line y=2x +a, a gt0. Length of chord PQ is: |
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Answer» 7a |
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| 4071. |
The value of I= int_(0)^(pi) (xdx)/( 4 cos^(2) x +9 sin^(2) x ) is |
| Answer» Answer :A | |
| 4072. |
Write the general solution of the differential equations : dy/dx=cosx-x |
| Answer» SOLUTION :`dy/DX=cosx-xrArry=int(cosx-x)dx` | |
| 4073. |
Letf(x)={{:(-1+sinK_(1)pix",", "x is rational."), (1+cosK_(2)pix",", x):} If f(x) is a periodic function, then |
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Answer» EITHER `K_(1),K_(2) in` RATIONAL or `K_(1),K_(2) in` IRRATIONAL |
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| 4074. |
Transform each of the following equations into ones in which the coefficients of the third highest power of x is zero . x^3+2x^2+x+1=0 |
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| 4075. |
At what points, the function f(x)=sinx-cosx,0ltxlt2pi, attains local maxima and minima. |
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Answer» Manumum value=`-sqrt2` |
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| 4077. |
inttan^5theta sec^4theta d theta |
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Answer» SOLUTION :`inttan^5theta sec^4theta d THETA` =`inttan^5theta.(1+tan^2theta).sec^2thetad theta` [PUT `tantheta=1` Then `sec^2thetad theta=DT`] =`intt^5.(1+t^2).dt=int(t^5+t^7)dt` =`1/6t^6+1/8t^8+C=1/6tan^6theta+1/8tan^8theta+C` |
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| 4078. |
For the following probability distribution determine standard deviation of the random variable X. |
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| 4079. |
The solution of y = x(dy)/(dx) + a sqrt(1+((dy)/(dx))^(2)) is |
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Answer» y = MX + C |
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| 4080. |
If only one common tangent can be drawn to the circles x^2+y^2-2x-4y-20=0 and (x+3)^(2)+(y+1)^(2)=p^(2)," then p=" |
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Answer» 20 |
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| 4081. |
The value of int_(0)^([x]) (2^t)/( 2^([t]) ) dt |
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Answer» `[X] LOG 2` |
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| 4082. |
Prove that if the function f(x)=sin x+cos a x is a periodic, than a is a rational number. |
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| 4083. |
If (3hati+4hatj+9hatk) and (a hati-3hatj+1hatk) are perpendicualr to each other then a = ……………… |
| Answer» ANSWER :A | |
| 4084. |
Let pi_(1) be the plane passing through the points (0,1,2), (1,0,-2), (-2, 1,0) and p_(2) be the plane passing through the point (1, 2,3) and perpendicular to the planes x + y + z =1 and 2x-3y + z =5. If theta is the acute angle between the planes pi_(1) and pi_(2) then cos theta= |
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Answer» `(sqrt14)/(9)` |
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| 4085. |
If f(x) = {:{ ( (1- sqrt2e sinx)/(pi-4x) ,if x ne pi/4), ( a , if x = pi/4) :} is continous atpi/4 thana is equal to |
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Answer» 4 |
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| 4086. |
If the limiting points of the system of circles x ^(2) + y ^(2) + 2gx+ lamda (x ^(2) + y ^(2) + 2fy +k) =0, where lamdais a parameter, subtend a right angle at the origin, then klf ^(2)= |
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Answer» `-1` |
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| 4087. |
Find the number of 4 letter words that can be formed using the letters of the word MIXTURE which do not contain the letter X |
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| 4088. |
The parameter on which the value of thedeterminant |[1, a, a^2],[cos (p-d) x ,cos p x, cos (p+d) x],[sin (p-d) x, sin p x, sin (p+d) x]|does not depend upon is |
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Answer» a |
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| 4089. |
If (pi)/(2) lt alpha (3pi)/(2) , the modulus argument form of (1 + cos 2 alpha) + isin 2 alpha is |
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Answer» `-2COS ALPHA{COS(alpha-pi)+ISIN(alpha-pi)}` |
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| 4090. |
From the equations which representsthe following Pair of lines x = y , x + 2y + 5 = 0 |
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Answer» Solution :x = y , x + 2y + 5 = 0 `therefore` (x =-y) ( x + 2y + 5 )= 0 or, `x^2 + 2XY + 5x - XY - 2y^2 - 5y = 0 or, `x^2 - 2y^2 + xy + 5x - 5y = 0 which REPRESENTS a PAIR of lines. |
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| 4091. |
A pair of dice is thrown. If the two numbers appearing are different , find the probability thet the sum of points exceeds 8. |
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Answer» SOLUTION :Let B be the event that sum of the POINTS exceeds 8. `THEREFORE` B={ (3,6),(4,5),(5,4),(6,3),(5,6),(6,5),(4,6),(6,4) } `therefore P (B) = absB/absS=8/30` |
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| 4092. |
A pair of dice is thrown. If the two numbers appearing are different , find the probability thet the sum of point is 8. |
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Answer» <P> Solution :A pair of DICE is THROWN as two NUMBERS are differentWe have `absS=30` Let A be the event thet the sum of points on the dice is 8, where the number on the dice are different. `therefore` A={(2,6),(3,5),(5,3),(6,2)} `P(A)=absA/absS=4/30` |
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| 4093. |
If(1 ) /(x ^ 4+x ^ 2+ 1 )= (Ax +B)/(x ^ 2+ x +1 )+ (Cx+D)/( x ^ 2 - x+1 ) ,thenC +Disequal to |
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Answer» ` - 1 ` ` RARR ( Ax +B)( x ^ 2- x+ 1 )+(Cx+ D)(x ^ 2+ x+ 1 )= 1 ` Let, `x ^ 2 +1 =x ` `rArrx ^ 2+ 1 - x=0 ` `0+(Cx + D )(2x )= 1` `rArr2 Cx^ 2+2Dx =1 ` `rArr2C ( x-1 )+ 2Dx= 1` ` rArr2x ( C + D)- 2C = 1` `rArr2x ( C + D)- 2 c =0.x+ 1` `thereforeC + D =0 ` |
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| 4094. |
If tantheta(P)/(q)"where"p,qgt0and if thetain(0,(pi)/(4))then sqrt((q+p)/(q-p))+sqrt((q-p)/(q+p)) is equal to |
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Answer» `(2sintheta)/(sqrt(sin2theta))` `=((1+p//q)+(1-p//q))/(sqrt(1-(p//q)^(2)))=(2)/(sqrt(1-tan^(2)THETA))=(2cos theta)/(sqrt(COS2 theta)).` |
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| 4095. |
int_(0)^(1) (tan^(-1)x)/(x) dx equals |
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Answer» `underset(0)overset(x)INT (x)/(sin x)dx` |
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| 4097. |
Integrate the following function : int(4x+5)/(sqrt(2x^(2)+x-3))dx |
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| 4098. |
If veca=overset(-)i-overset(-)j-overset(-)k and vecb=lambda hati-3hatj+hatk and the orthogonal projection of vecb" on "veca is 4/3 (hati-hatj-hatk), then lambda is equal to |
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Answer» 0 |
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| 4099. |
If the vertices of a feasible region are O(0, 0), A(10, 0), B(0, 20), C(15, 15), then minimum value of a objective function Z = 10x - 20y + 30 is ……… |
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Answer» -120 |
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| 4100. |
A bag contains 2 n + 1 coins. If is known thatn of these coins have a head on both sides, whereas the remaining n + 1 coins are fair. A coin is picked up at random from the bag and tosses. If the probabilitythat the toss resultsin a head is 31/42 , then n= |
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Answer» 10 |
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