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4051.

Find the radius of the circle escribed to the triangle ABC (Shown in the figure below) on the side BC ifangleNAB=30^(@), angleBAC=30^(@), AB=AC=5.

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`((10sqrt(2)+5sqrt(3)-5)(2-SQRT(3)))/(2sqrt(2))`
`((10sqrt(2)+5sqrt(3)+5))/(2sqrt(2))(2-sqrt(3))`
`((10sqrt(2)+5sqrt(3)-5))/(2sqrt(2))(2+sqrt(3))`
`((10sqrt(2)+5sqrt(2)+1))/(2sqrt(3))(sqrt(3)-1)`

Answer :A
4052.

Using determinants find equation of line passess from point (1,2) and (3,6)

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ANSWER :`thereforey=2x`
4053.

Find int (1)/( sin x cos^(3) x) dx

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ANSWER :`I = log_(e) ( TAN X) + ( tan^(2) x )/(2) + C`
4054.

If a,b,c ge 4are integers, not all equal, and 4abc = (a + 3) (b + 3) (c + 3), then what is the value of a + b + c ?

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ANSWER :16
4055.

If f(x) =(sin [x])/([x])" at "[x] ne 0 and f(x)=0" at "then " underset(x to 0)"Lt" f(x)=

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0
1
`-1`
does not exist

Answer :D
4056.

IfA =({:( 1,1,1),( 1,omega ^(2) , omega ),( 1 ,omega , omega ^(2)) :})where omega is a complex cube root of unity then adj -Aequals

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`(OMEGA ^(2) -omega ) VEC A `
` (omega -omega ^(2) ) oversetto A `
` -oversetto A `
` oversetto A `

ANSWER :B
4057.

Find the equation of normal to the parabola y^(2) = 4x and whose slopeis 2.

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ANSWER :`RARR 2x-y -12=0`
4058.

The projections of a line segment on x, y and z axes are respectively 3, 4 and 12. The length of the line segment is

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5
`4sqrt(10)`
`3sqrt(17)`
13

Answer :D
4059.

Let n be a positive integer. Find the maximum number of non congruent triangles whose side lengths are integers less than or equal to n.

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ANSWER :`{((N(n+2)(2n+5))/(24),"n is EVE"),(((n+1)(n+3)(2n+1))/(24),"n is ODD"):}`
4060.

A fair die is tossed twice. The probability of getting 4, 5 or 6 on the first toss and 1,2,3 or 4 on the second toss is

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`7//36`
`5//36`
`1//3`
`35//36`

ANSWER :C
4061.

Evaluate the following improper integrals with infinite limits on the basis of their definition : (a) int_(2)^(oo)(xdx)/(sqrt((x^(2)-3)^(3))), (b) int_(1)^(oo)(dx)/(x+x^(3)), (c ) int_(0)^(oo)(xdx)/(sqrt((4x^2+1)^(3))), (d) int_(1)^(oo)(dx)/(x^(2)(1+x)), (e) int_(-oo)^(oo)(dx)/(x^(2)-6x+10), (f) int_(0)^(oo)e^(-x)sinxdx

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Answer :(b) `(1)/(2)1n2;`
(C ) `1;`
(d) `1-1n2;` (e ) `pi;(F)(1)/(2)`.
4062.

If the coordinate axes are the bisectors of the angle between the pairs of lines ax^(2) + 2hxy + by^(2) = 0 , where h^(2) gt ab anda ne b, then

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`a + B = 0`
`H = 0`
`h NE 0 , a + b = 0`
` a + b ne 0`

ANSWER :B
4063.

If 4 fair coins are tossed find the probability of getting 2 heads and 2 talls.

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ANSWER :`(3)/(8)`
4064.

""^20C_0 + ""^20C_1 + ""^20C_2+…….+""^20C_10 =

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`[2^19 - 1/2. ""^18C_10]`
`[2^19 +1/2.""^20C_10]`
`2^19-1/4. ""^18C_10]`
`[2^19 - 1/4 . ""^6C_3]`

ANSWER :B
4065.

Does the graph below represent a function or a relation? (##CEN_GRA_C01_S01_002_Q01.png" width="80%">

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Solution :Vertical LINE X = 2 meets the above graph at (2, 1) and (2, 2). Hence the graph does not represent a FUNCTION.
4066.

A company produces two types of leather belts A and B on which the profits are Rs. 40 and Rs. 30 per belt respectively. Each belt of type A requires twice as much time as required by a belt to type B.If all belts were of type B the company could produce 1000 belts per day. But the supply of leather is sufficient only for 800 belts per day. Belt A requires a fancy buckle and only 400 fancy buckles are available per day. For belt of type B only 700 buckles are available per day. How should the company manufacture the two types of belts in order to have maximum overall profit?

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SOLUTION :NA
4067.

Let R be the relation in the set N given byR = {(a,b) : a = b -2, b gt 6}. Choose the correct answer.

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`(2, 4) in R`
`(3, 8) in R`
`(6, 8) inR`
`(8, 7) in R`

Answer :C
4068.

The sequence 9, 18, 27, 36, 45, 54,….. consists of successive mutiple of 9. This sequence is then altered by multiplying every other term by -1, starting with the first term, to prduce the new sequence -9, 18, -27,36,-45, 54,…….. If the sum of the first n terms of this new sequence is 180, determine n.

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ANSWER :40
4069.

A line passes through two points A(2,-3,-1) and B(8,-1,2). The coordinates of a point on this lie at distance of 14 units from a are

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`(14,-1,5)`
`(-10,-7,-7)`
`(10,7,7)`
`(-4,-1,-5)`

Answer :B
4070.

Let PQ be a focal chord of the parabola y^2=4ax. The tangents to the parabola at P and Q meet at a point lying on the line y=2x +a, a gt0. Length of chord PQ is:

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7a
5a
2a
3a

Answer :B
4071.

The value of I= int_(0)^(pi) (xdx)/( 4 cos^(2) x +9 sin^(2) x ) is

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`PI^(2) //12`
`pi^(2)//4`
`pi^(2) //6`
`pi^(2) //3`

Answer :A
4072.

Write the general solution of the differential equations : dy/dx=cosx-x

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SOLUTION :`dy/DX=cosx-xrArry=int(cosx-x)dx`
4073.

Letf(x)={{:(-1+sinK_(1)pix",", "x is rational."), (1+cosK_(2)pix",", x):} If f(x) is a periodic function, then

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EITHER `K_(1),K_(2) in` RATIONAL or `K_(1),K_(2) in` IRRATIONAL
`K_(1),K_(2) in " rational only "`
`K_(1),K_(2) in " irrational only "`
`K_(1),K_(2) in " irrational such that " K_(1)/K_(2)` is rational

ANSWER :B
4074.

Transform each of the following equations into ones in which the coefficients of the third highest power of x is zero . x^3+2x^2+x+1=0

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ANSWER :`x^3-x^2 +1=0 , 27 x^3 +27 x^2 +23=0`
4075.

At what points, the function f(x)=sinx-cosx,0ltxlt2pi, attains local maxima and minima.

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ANSWER :MAXIMUM VALUE=`-SQRT2`
Manumum value=`-sqrt2`
4076.

Matrices of different order can not be subtracted .

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ANSWER :1
4077.

inttan^5theta sec^4theta d theta

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SOLUTION :`inttan^5theta sec^4theta d THETA`
=`inttan^5theta.(1+tan^2theta).sec^2thetad theta`
[PUT `tantheta=1`
Then `sec^2thetad theta=DT`]
=`intt^5.(1+t^2).dt=int(t^5+t^7)dt`
=`1/6t^6+1/8t^8+C=1/6tan^6theta+1/8tan^8theta+C`
4078.

For the following probability distribution determine standard deviation of the random variable X.

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ANSWER :0.7
4079.

The solution of y = x(dy)/(dx) + a sqrt(1+((dy)/(dx))^(2)) is

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y = MX + C
`y = mx + asqrt(1+m^(2))`
y = mx
`y = asqrt(1+m^(2))`

ANSWER :B
4080.

If only one common tangent can be drawn to the circles x^2+y^2-2x-4y-20=0 and (x+3)^(2)+(y+1)^(2)=p^(2)," then p="

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20
16
49
10

Answer :D
4081.

The value of int_(0)^([x]) (2^t)/( 2^([t]) ) dt

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`[X] LOG 2`
`([x])/(log 2)`
`(1)/(2) ([x])/(log 2)`
`(1)/( 4) ([x])/( log 2)`

ANSWER :B
4082.

Prove that if the function f(x)=sin x+cos a x is a periodic, than a is a rational number.

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ANSWER :`(2N)/(K)`
4083.

If (3hati+4hatj+9hatk) and (a hati-3hatj+1hatk) are perpendicualr to each other then a = ………………

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1
`-1`
7
`-7`

ANSWER :A
4084.

Let pi_(1) be the plane passing through the points (0,1,2), (1,0,-2), (-2, 1,0) and p_(2) be the plane passing through the point (1, 2,3) and perpendicular to the planes x + y + z =1 and 2x-3y + z =5. If theta is the acute angle between the planes pi_(1) and pi_(2) then cos theta=

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`(sqrt14)/(9)`
`(PI)/(3)`
`(13)/(3 sqrt22)`
`(pi)/(4)`

ANSWER :A
4085.

If f(x) = {:{ ( (1- sqrt2e sinx)/(pi-4x) ,if x ne pi/4), ( a , if x = pi/4) :} is continous atpi/4 thana is equal to

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4
2
1
`1//4`

ANSWER :D
4086.

If the limiting points of the system of circles x ^(2) + y ^(2) + 2gx+ lamda (x ^(2) + y ^(2) + 2fy +k) =0, where lamdais a parameter, subtend a right angle at the origin, then klf ^(2)=

Answer»

`-1`
1
2
none of these

ANSWER :C
4087.

Find the number of 4 letter words that can be formed using the letters of the word MIXTURE which do not contain the letter X

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ANSWER :360
4088.

The parameter on which the value of thedeterminant |[1, a, a^2],[cos (p-d) x ,cos p x, cos (p+d) x],[sin (p-d) x, sin p x, sin (p+d) x]|does not depend upon is

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a
p
d
x

Answer :B
4089.

If (pi)/(2) lt alpha (3pi)/(2) , the modulus argument form of (1 + cos 2 alpha) + isin 2 alpha is

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`-2COS ALPHA{COS(alpha-pi)+ISIN(alpha-pi)}`
`2cos alpha{cos(alpha)+isinalpha)`
`2cos alpha{cos(-alpha)+isin(-alpha)}`
`-2cos alpha{cos(pi-alpha)+isin(pi-alpha)}`

ANSWER :A
4090.

From the equations which representsthe following Pair of lines x = y , x + 2y + 5 = 0

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Solution :x = y , x + 2y + 5 = 0
`therefore` (x =-y) ( x + 2y + 5 )= 0
or, `x^2 + 2XY + 5x - XY - 2y^2 - 5y = 0
or, `x^2 - 2y^2 + xy + 5x - 5y = 0
which REPRESENTS a PAIR of lines.
4091.

A pair of dice is thrown. If the two numbers appearing are different , find the probability thet the sum of points exceeds 8.

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SOLUTION :Let B be the event that sum of the POINTS exceeds 8.
`THEREFORE` B={ (3,6),(4,5),(5,4),(6,3),(5,6),(6,5),(4,6),(6,4) }
`therefore P (B) = absB/absS=8/30`
4092.

A pair of dice is thrown. If the two numbers appearing are different , find the probability thet the sum of point is 8.

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<P>

Solution :A pair of DICE is THROWN as two NUMBERS are different
We have `absS=30`
Let A be the event thet the sum of points on the dice is 8, where the number on the dice are different.
`therefore` A={(2,6),(3,5),(5,3),(6,2)}
`P(A)=absA/absS=4/30`
4093.

If(1 ) /(x ^ 4+x ^ 2+ 1 )= (Ax +B)/(x ^ 2+ x +1 )+ (Cx+D)/( x ^ 2 - x+1 ) ,thenC +Disequal to

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` - 1 `
` 1 `
` 2`
` 0`

SOLUTION : ` ( 1 ) /(X ^4 + x ^ 2+ 1 )= ( Ax + B) /(x ^ 2+ x+ 1 ) + (Cx +D)/(x ^ 2- x+ 1) `
` RARR ( Ax +B)( x ^ 2- x+ 1 )+(Cx+ D)(x ^ 2+ x+ 1 )= 1 `
Let, `x ^ 2 +1 =x `
`rArrx ^ 2+ 1 - x=0 `
`0+(Cx + D )(2x )= 1`
`rArr2 Cx^ 2+2Dx =1 `
`rArr2C ( x-1 )+ 2Dx= 1`
` rArr2x ( C + D)- 2C = 1`
`rArr2x ( C + D)- 2 c =0.x+ 1`
`thereforeC + D =0 `
4094.

If tantheta(P)/(q)"where"p,qgt0and if thetain(0,(pi)/(4))then sqrt((q+p)/(q-p))+sqrt((q-p)/(q+p)) is equal to

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`(2sintheta)/(sqrt(sin2theta))`
`(2sintheta)/(sqrt(COS2THETA))`
`(2costheta)/(sqrt(cos2theta))`
`(2costheta)/(sqrt(cos2theta))`

Solution :`sqrt((q+p)/(q-p))+sqrt((q-p)/(q+p))=sqrt((1+p//q)/(1-p//q))+sqrt((1-p//q)/(1+p//q))`
`=((1+p//q)+(1-p//q))/(sqrt(1-(p//q)^(2)))=(2)/(sqrt(1-tan^(2)THETA))=(2cos theta)/(sqrt(COS2 theta)).`
4095.

int_(0)^(1) (tan^(-1)x)/(x) dx equals

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`underset(0)overset(x)INT (x)/(sin x)dx`
`(1)/(2)underset(0)overset(x)int (x)/(sin x)dx`
`underset(0)overset(pi//2)int (sin x)/(x)dx`
None of the above

Answer :B
4096.

lim_(xto0)"sin"(1)/(x) is

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0
1
`OO`
DOEST not exist

Answer :D
4097.

Integrate the following function : int(4x+5)/(sqrt(2x^(2)+x-3))dx

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Answer :`2sqrt(2x^(2)+X-3)+2sqrt2log|(x+(1)/(4))+SQRT((x+(1)/(4))^(2)-((5)/(4))^(2))|+C`
4098.

If veca=overset(-)i-overset(-)j-overset(-)k and vecb=lambda hati-3hatj+hatk and the orthogonal projection of vecb" on "veca is 4/3 (hati-hatj-hatk), then lambda is equal to

Answer»

0
2
12
`-1`

ANSWER :B
4099.

If the vertices of a feasible region are O(0, 0), A(10, 0), B(0, 20), C(15, 15), then minimum value of a objective function Z = 10x - 20y + 30 is ………

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-120
130
30
-370

Answer :D
4100.

A bag contains 2 n + 1 coins. If is known thatn of these coins have a head on both sides, whereas the remaining n + 1 coins are fair. A coin is picked up at random from the bag and tosses. If the probabilitythat the toss resultsin a head is 31/42 , then n=

Answer»

10
11
12
13

Answer :A