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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1451. |
Escherichia coli is used as an indicator organism to determine pollution of water with:A. Heavy metalsB. Faecal matterC. Industrial effluentsD. Pollen of aquatic plants |
| Answer» Correct Answer - B | |
| 1452. |
Chlorenchyma is known to develop in theA. Cytoplasm of ChlorellaB. Mycelium of a green mould such as AspergillusC. Spore capsule of a mossD. Pollen tube of Pinus |
| Answer» Correct Answer - C | |
| 1453. |
Acetaldehyde reacts with semicarbazide product will beA. `CH_3CH = NNH–CO–NH_2`B. `CH_3CH = NCONHNH_2`C. `CH_3CH = NHNH_2`D. `CH_3-oversetunderset(||)(O)C-NH-CONH_2` |
| Answer» Correct Answer - A | |
| 1454. |
Given below are four matchings of an animal and its kind of respiratory organ. `{:("A. Silver fish - Trachea"),("B. Scorpion - Book lung"),("C. Sea squirt - Pharyngeal gill slits"),("D. Dolphin - Skin"):}` The correct matchings areA. A and DB. A, B and CC. B and DD. C and D |
| Answer» Correct Answer - B | |
| 1455. |
A male human is heterozygous for autosomal genes A and B and is also hemizygous for hemophilic gene h. What proportion of his sperms will be abhA. `1//32`B. `1//16`C. `1//4`D. `1//8` |
| Answer» Correct Answer - D | |
| 1456. |
Industrial melanism as observed in peppered moth proves thatA. Melanism is a pollution-generated featureB. The true black melanic forms arise by a recurring random mutationC. The melanic form of the moth has no selective advantage over lighter form in industrial areaD. The lighter-form the moth has no selective advantage either in polluted industrial area or non-polluted area |
| Answer» Correct Answer - A | |
| 1457. |
If an electron in a hydrogen atom jumps from the `3rd` orbit to the `2nd` orbit, it emits a photon of wavelength `lambda`. When it jumps form the `4th` orbit to the `3dr` orbit, the corresponding wavelength of the photon will beA. `(16)/(25)lamda`B. `(9)/(16)lamda`C. `(20)/(7)lamda`D. `(20)/(13)lamda` |
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Answer» Correct Answer - C `(1)/(lamda)=R(1)^(2)((1)/(2^(2))-(1)/(3^(3)))` `(1)/(lamda_(2))=R(1)^(2)((1)/(3^(2))-(1)/(4^(2)))` `((1)/(lamda))/((1)/(lamda_(2)))=((1)/(4)-(1)/(9))/((1)/(9)-(1)/(16))=((5)/(4xx9))/((16-9)/(9xx16))` `(lamda_(2))/(lamda)=(5)/(4xx9)xx(9xx16)/(7)=(20)/(7)` `lamda_(2)=(20)/(7)lamda` |
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| 1458. |
The energy required to charge a parallel plate condenser of plate separtion `d` and plate area of cross-section `A` such that the unifom field between the plates is `E` isA. `epsilon_(0)E^(2)Ad`B. `(1)/(2)epsilon_(0)E^(2)Ad`C. `(1)/(2)epsilon_(0)E^(2)//Ad`D. `epsilon_(0)E^(2)//Ad` |
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Answer» Correct Answer - A Energy stored in capacitor for field `E=(1)/(2)CV^(2)` `=(1)/(2)((epsilon_(0)A)/(d))(E.d)^(2)` `=(1)/(2)epsilon_(0)AE^(2)d` Energy stored in capacitor `+` Energy loss in the process of charging = Energy given by cell. `=(Aepsilon_(0))/(d)V^(2)` `=2xx" Energy stored in capacitor"` Since energy stored in capacitor = Energy loss in the process of storing the charge in capacitor. |
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| 1459. |
Two radioactive substance `A` and `B` have decay constants `5 lambda` and `lambda` respectively. At `t=0` they have the same number of nuclei. The ratio of number of nuclei of nuclei of `A` to those of `B` will be `(1/e)^(2)` after a time intervalA. `(1)/(2 lambda)`B. `(1)/(4 lambda )`C. `4 lambda `D. `2 lambda ` |
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Answer» Correct Answer - A `(N_(A))/(N_(B))=(N_(0)e^(-lambda_(A)t))/(N_(0)e^(-lambda_(B)t))=(e^(-5lambdat))/(e^(-lambdat))` `implies (1)/(e^(4lambdat))=(1)/(e^(2))impliest=(1)/(2 lambda)` |
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| 1460. |
A common emitter amplifier has a voltage gain of `50`, an input impedence of `100 Omega` and an output impedence of `200 Omega`. The power gain of the of the amplifier isA. 100B. 500C. 1000D. 1250 |
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Answer» Correct Answer - D Voltage gain `=(beta)((R_(0))/(R_(i)))=50` `implies beta=((50)(100))/((200))=25` Power gain `=(beta^(2))((R_(0))/(R_(i)))=(25)^(2)((200)(100))` `=625xx2 =1250` |
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| 1461. |
Curie temperature is the temperature above whichA. paramagnetic material becomes ferromagnetic materialB. ferromagnetic material becomes diamagnetic materialC. ferromagnetic material becomes paramagnetic materialD. paramagnetic material becomes diamagnetic material |
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Answer» Correct Answer - C Curie temperature is that temperature above which a ferromagnet becomes paramagnet. |
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| 1462. |
The voltage gain of an amplifier with `9%` negative feedback is `10`. The voltage gain without feedback will beA. 1.25B. 100C. 90D. 10 |
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Answer» Correct Answer - B `"Voltage gain"=(A_(V))/(1+beta.A_(V)),` where `beta=(9)/(100)=0.09`, voltage gain = 10 `rArr" "10=(A_(V))/(1+(9)/(100).A_(V))` `rArr A_(V)=(10)/(0.1)=100` |
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| 1463. |
The total energy of eletcron in the ground state of hydrogen atom is `-13.6 eV`. The kinetic enegry of an electron in the first excited state isA. 1.7 evB. 3.4 eVC. 6.8 eVD. 13.6 eV |
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Answer» Correct Answer - B Total energy in first excited state `=-(13.4)/(4)=-3.4 eV` K.E. in first excited state =- total energy in that state =- (-3.4)=3.4eV |
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| 1464. |
The groud state energy of hydrogen atom is `-13.6 eV`. When its electron is in first excited state, its exciation energy isA. 10.2 eVB. zeroC. 3.4 eVD. 6.8 eV |
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Answer» Correct Answer - A Since `E_(0)=-13.6eV`, Energy in the excited state `=(-13.6)/(4)=-3.4eV` `DeltaE`= excitation energy =Energy needed to raise the electron from ground state to higher level `=-3.4+13.6=10.2eV` |
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| 1465. |
A dipole of moment `vecp` is placed in a uniform electric field `vecE`. The force on the dipole is `vecF` and the torque is `vec(tau)`A. `vectau=vecp.vecE`B. `vectau=vecpxxvecE`C. `vectau=vecp+vecE`D. `vectau=vecp-vecE` |
| Answer» Correct Answer - B | |
| 1466. |
A student measued the diameter of a small steel ball using a screw gauge of least count `1.001 cm`. The main scale reading is `5 mm` and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero erroof `-0.004 cm`, the correct diameter of the ball isA. 0.053 cmB. 0.525 cmC. 0.521 cmD. 0.529 cm |
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Answer» Correct Answer - D Diameter of the ball =MSR + CSR`xx` (Least count)-zero error `=0.5 cm+25xx0.001-(-0.004)` `=0.5 + 0.025 +0.004` `=0.529 cm` |
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| 1467. |
If kinetic energy of a body is increased by 300%, then percentage change in momentum will beA. `100%`B. `150%`C. `265%`D. `73.2%` |
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Answer» Correct Answer - A `P_1=sqrt(2mE_1) , P_2=sqrt(2mE_2)` `=sqrt(2m(E_1+300/100E_1))=sqrt(2m(4E_1))=2P_1` % change `=(P_2-P_1)/P_1xx100=(2P_2-P_1)/P_1xx100=100%` |
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| 1468. |
The specific resistance of a conductor increases with:A. Increase in temperatureB. Increase in cross section areaC. Increase in cross section and decrease in lengthD. Decrease in cross section area |
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Answer» Correct Answer - A The value of `rho` doesnot depends on geometry but increases with increase in temperature |
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| 1469. |
For a transistor `(I_(C))/(I_(E))=0.96`, then current gain for common emitter configurationA. 12B. 6C. 48D. 24 |
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Answer» Correct Answer - D `beta=alpha/(1-alpha)=24` |
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| 1470. |
A small object of uniform density rolls up a curved surface with an initial velocity v. it reaches up to a maximum height of `(3v^2)/(4g) with respect to the initial position. The object isA. RingB. Solid sphereC. Hollow sphereD. Disc |
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Answer» Correct Answer - D Using mechanical energy conservation `(1)/(2)mv^(2)(1+(k^(2))/(R^(2)))=mg((3v^(2))/(4g))` `1+(k^(2))/(R^(2))=(3)/(2)` `(k^(2))/(R^(2))=(1)/(2)` So, body is disc or solid cylinder. |
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| 1471. |
An ideal gas heat engine operates in Carnot cycle between `227^(@)C` and `127^(@)C`. It absorbs `6 x 10^(4) cals` of heat at higher temperature. Amount of heat converted to work isA. `4.8 xx 10^(4)` calsB. `2.4 xx 10^(4)` calsC. `1.2 xx 10^(4) ` calsD. `6xx10^(4)` cals |
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Answer» Correct Answer - B `eta=(W)/(Q)=1 -(T_(2))/(T_(1))impliesW=Q(1-(T_(2))/(T_(1)))` `=1.2xx10^(4) cals ` |
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| 1472. |
The translocation of organic solutes in sleve tube membres is supportted byA. Root pressure and transpiration pullB. P-proteinsC. Mass flow involving a carrier and ATPD. Cytoplasmic streaming |
| Answer» Correct Answer - C | |
| 1473. |
Deficiency of oxygen affects most theA. BrainB. SkinC. KidneyD. Intestine |
| Answer» Correct Answer - A | |
| 1474. |
What shall be the water potential of a root hair cell absorbing water from the soilA. ZeroB. Less than zeroC. More than zeroD. Infinite |
| Answer» Correct Answer - B | |
| 1475. |
Vexillary aestivation is characteristic of the familyA. SolanaceaeB. BrassicaceaeC. FabaceaeD. Asteraceae |
| Answer» Correct Answer - C | |
| 1476. |
During the electrolysis of molten sodium chloride, the time required to produce `0.10 mol` of chlorine gas using a current of `3` amperes isA. 55 minutesB. 110 minutesC. 220 minutesD. 330 minutes |
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Answer» Correct Answer - B `2Cl^(-)tounderset("0.1 mol 0.2F")(Cl_(2)+2e^(-))` `Q=1t` `0.2xx96500=3xxt` `t=(0.2xx96500)/(3xx60)"min"=107.22"min`. |
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| 1477. |
A galvanometer having a coil resistance of `60 Omega` shows full scale defection when a current of `1.0 A` passes thoguth it. It can vbe convered into an ammeter to read currents up to `5.0 A` byA. Putting in parallel a resistance of 15 `Omega`B. Putting in parallel a resistance of 240 `Omega`C. Putting in series a resistance of 15 `Omega `D. Putting in series a resistance of 240 `Omega ` |
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Answer» Correct Answer - A `Ig=1.0A, G=60q, I=5.0A` `S=(I_(g))/(I-I_(g))G` `G=(1.0)/(5.0-1.0)=60` `=15 Omega ` in parallel |
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| 1478. |
Telemere repetitive DNA sequences control the function of eukarote chromosomes because theyA. Prevent chromosome lossB. Act as repliconsC. Are RNA transcription initiatorD. Help chromosome pairing |
| Answer» Correct Answer - A | |
| 1479. |
The length of DNA molecile greatly exceeds the dimensions of the nucleus in eukaryotic cell. How is this DNA accommodatedA. Through elimination of repetitive DNAB. Deletion of non-essential genesC. Super-coiling in nucleosomesD. Super-coiling in nucleosomes |
| Answer» Correct Answer - C | |
| 1480. |
The most likely reason for the development of resistence against pesticides in insects damaging a crop isA. Genetic recombinationB. Directed mutationsC. Acquired heritable changesD. Random mutations |
| Answer» Correct Answer - D | |
| 1481. |
The following ratio is generally constant for a given speciesA. T + C / G +AB. G + C /A+ TC. A + C / T+ GD. A + G / C +T |
| Answer» Correct Answer - B | |
| 1482. |
Which one of the following pairs of solution is not an acidic buffer?A. `H_(2)CO_(3) and Na_(2)CO_(3)`B. `H_(3)PO_(4) and Na_(3)PO_(4)`C. `HClO_(4) and NaClO_(4)`D. `CH_(3)COOH and CH_(3)COONa` |
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Answer» Correct Answer - C Weak acid and its conjugate salt with strong base is an acidic buffer but according to option Ans is (3), `HClO_(4)` is a strong acid `thereforeHClO_(4)+NaClO_(4)` is not an acidic buffer |
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| 1483. |
`CH_3-CH_2-undersetunderset(Cl)|CH CH_3` obtained by chlorination of n butane, will be : -A. Meso formB. Racemic mixtureC. d-formD. l-form |
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Answer» Correct Answer - B `CH_3-CH_2-CH_2-CH_3 to CH_3-CH_2CH-CH_3` intermediate `Sp^2` hybrid planar shape `overset"Cl"to` recemic mix planr shape reagent |
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| 1484. |
Mechanism of a hypothetical reaction `X_(2) + Y_(2) rarr 2XY` is given below: (i) `X_(2) rarr X + X` (fast) (ii) `X+Y_(2) hArr XY+Y` (slow) (iii) `X + Y rarr XY` (fast) The overall order of the reaction will be :A. 1B. 2C. 0D. 1.5 |
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Answer» Correct Answer - D The solution of this question is given by assuming step (i) to be reversible which is not given in question Overall rate = Rate of slowest step (ii) `=k[X][Y_(2)]`......(1) k=rate constant of step (ii) Assuming step (i) to be reversible, its equilibrium constant, `k_(eq)=([X]^(2))/([X_(2)]) implies [X]=k_(eq)^(1/2)[X_(2)]^((1)/(2))`.....(2) Put (2) in (1) Rate `=kk_(eq)^((1)/(2))[X_(2)]^((1)/(2))[Y_(2)]` Overall order `=(1)/(2)+1=(3)/(2)` |
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| 1485. |
What is true about Nereis, scorpion, cockroah and silver fish?A. They all belong to the same phylumB. They all belong to the same phylumC. They all possess dorsal heartD. None of them is |
| Answer» Correct Answer - C | |
| 1486. |
A long solenoid has `500` turns. When a current of `2A` is passed through it, the resulting magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb` . The self-inductance of the solenoid isA. 1.0 henryB. 4.0 henryC. 2.5 henryD. 2.0 henry |
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Answer» Correct Answer - A `"Flux linkage "="Flux through each turn"xx"number of turn"` `phi=500xx4xx10^(-3)=2Wb` since `phi=Li` `rArr L=(phi)/(i)=(2)/(2)=1H` |
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| 1487. |
A particle of mass m, charge q and kinetic energy T enters in a transverse uniform magnetic field of induction B. After the 3 s, the kinetic energy of the particle will beA. TB. 4 TC. 3 TD. 2 T |
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Answer» Correct Answer - A `vecF=q(vec vxxvecB)`, i.e. magnetic force is perpendicular to both velocity and magnetic field. A force `_|__(r)`, to `vecV` does no work or no power delivered by force which is `_|__(r), vecVA` hence no kinetic energy or speed will change since `P=vecF.vecV=0` As `vecF _|__(r),vecV_|__(r),vec(dr)` or `dW=vecF.vec(dr)=0` |
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| 1488. |
The distance travelled by a particle starting from rest and moving with an acceleration `(4)/(3) ms^-2`, in the third second is.A. `(10)/(3)m`B. `(19)/(3)m`C. 6mD. 4m |
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Answer» Correct Answer - A Distance covered in `n^(th)` second. `S_(n)=u+(1)/(2)a(2n-1),` `=0+(1)/(2)xx(4)/(3)(2xx3-1)` `=(1)/(2)xx(4)/(3)xx5=(10)/(3)m` |
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| 1489. |
Which of the following is the most important for animals and plants being driven to extinctionA. Alien species invasionB. Habitat loss and fragmentationC. Drought and floodsD. Economic exploitation |
| Answer» Correct Answer - B | |
| 1490. |
Consider the following statements: (A) Coenzyme or metal ion that is tightly bound to enzyme protein is called prosthetic group, (B) A complete catalytic active cnzyme with its bound prosthetic group is called apoenzyme. Select the correct optionA. (A) is false but (B) is true.B. Both (A) and (B) are true.C. A) is true but (B) is false.D. Both (A) and (B) are false. |
| Answer» Correct Answer - D | |
| 1491. |
Two astronauts are floating in gravitational free space after having lost contanct with their spaceship. The two will:A. Keep floating at the same distance between themB. Move towards each otherC. Move away from each otherD. Will become stationary |
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Answer» Correct Answer - B Both the astronauts are in the condition of weightness. Gravitational force between them pulls towards each other. |
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| 1492. |
Two rotating bodies `A` and `B` of masses `m` and `2m` with moments of inertia `I_(A)` and `I_(B) (I_(B) gt I_(A))` have equal kinetic energy of rotation. If `L_(A)` and `L_(B)` be their angular momenta respectively, thenA. `L_(A)=(L_(B))/(2)`B. `L_(A)=2L_(B)`C. `L_(B) gt L_(A)`D. `L_(A) gt L_(B)` |
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Answer» Correct Answer - C `K.E_(A)=K.E_(B)` `(1)/(2)I_(A)omega_(A)^(2)=(1)/(2)I_(B)omega_(B)^(2)` `(omega_(A))/(omega_(B))=sqrt((I_(B))/(I_(A)))` . . . (i) `{I_(B) gt I_(A)implies(I_(A))/(I_(B)) lt 1}` `L_(A)=I_(A)omega_(A)" "L_(B)=I_(B)omega_(B)` `(L_(A))/(L_(B))=(I_(A))/(I_(B))xx(omega_(A))/(omega_(B))=(I_(A))/(I_(B))xxsqrt((I_(A))/(I_(B)))` `=sqrt((I_(A))/(I_(B))) lt 1` `[L_(A) lt L_(B)]` |
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| 1493. |
Concentrated aqueous sulphuric acid is `98% H_(2)SO_(4)` by mass and has a density of `1.80 g mL^(-1)`. Volume of acid required to make one litre of `0.1 MH_(2)SO_(4)` solution is:A. 5.55 mLB. 11.10 mLC. 16.65 mLD. 22.20 mL |
| Answer» Correct Answer - A | |
| 1494. |
If Avogadro number `N_(A)` is changed from `6.022xx10^(23) mol^(-1)` to 6`.022xx10^(23) mol^(-1)`, this would change:A. the ratio of chemical species to each other in a balanced equationB. the ratio of elements to each other in a compoundC. the definition of mass in units of gramsD. the mass of one mole of carbon |
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Answer» Correct Answer - C 1 amu=`(1)/(12)xx`mass of 1 atom of C-12 isotope 1 amu=`(1)/(6.023)gm=1.66xx10^(-24)gm` If Avogadro number of change then the definition of mass in unit of gm is changed. |
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| 1495. |
Acetamide is treated separately with the following reagents. Which one of these would give methyl amine ?A. `NaOH-Br_(2)`B. SodalimeC. Hot conc.` H_(2)SO_(4)`D. ` PCl_(5 )` |
| Answer» Correct Answer - A | |
| 1496. |
Most stable pesticidesA. OrganophosphatesB. OrganochlorinesC. Bordeaux mixtureD. Azaderectnin |
| Answer» Correct Answer - B | |
| 1497. |
Best economic method to harvest the solar energy:-A. Solar cellB. Energy plantationC. Cultivation of sugar cane then energy obtain by burning itD. Solar cooke |
| Answer» Correct Answer - B | |
| 1498. |
Main reason of disturbance of biological diversityA. Green house effectB. HuntingC. Soil erosionD. Destruction of natural habitats |
| Answer» Correct Answer - D | |
| 1499. |
Best method to preserve the wild relatives of plants:-A. By growing them in natural habitatsB. Gene libraryC. By storing seedsD. Cryopreservation |
| Answer» Correct Answer - A | |
| 1500. |
Amount of cellular DNA increases duringA. CytokinesisB. FertilisationC. MutationD. Respiration |
| Answer» Correct Answer - B | |