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6801.

What is stellar energy ?

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Solution :Fusion reaction that takes PLACE in the cores of sum and other STARS RESULTS in an enormous AMOUNT of energy, which is CALLED as stellar energy.
Discussion
6802.

A bullet of mass 50 is moving with a velocity of 500 ms^(-1) . It penetrates 10 cm into a still target and comes to rest Calculate (a) the kinetic energy possessed by the bullel and (b) the average retarding force offered by the target.

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SOLUTION :(a)6250J (B)62500 N
Discussion
6803.

Which of the following represents voltage?

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WORK DONE/Current `XX` Time
Work done/CHARGE
Work done `xx` Time/Current
Work done Charge Time

Answer :A
Discussion
6804.

Anaemia can be diagnosed by

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`""_(15)P^(31)`
`""_(15)P^(32)`
`""_(26)FE^(59)`
`""_(11)Na^(24)`

Solution :`""_(26)Fe^(59)`
Discussion
6805.

The machine which converts the kinetic energy of wind to electrical energy

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ANSWER :WIND TURBINE
Discussion
6806.

What will happens to the plate ? Why ?

Answer»

Solution :The plate BREAKS into PIECES, because of the potential ENERGY of the metal ball.
Discussion
6807.

The magnetic field in a given region is uniform. Draw a diagram to represent it.

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SOLUTION :
Discussion
6808.

How is the strength of the magnetic field at a point near a wire related to the strength of the electric current flowing in the wire?

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SOLUTION :The magnitude of MAGNETIC field is directly proportional to the STRENGTH of the electric CURRENT flowing in the WIRE.
Discussion
6809.

Zero Kelvin is the ____________ of the body.

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SOLUTION :ABSOLUTE SCALE of TEMPERATURE
Discussion
6810.

An object placed between the pole and focus of a concave mirror produced a virtual and enlarged image. Explain this using mirror formula.

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Solution :According to the spherical mirror FORMULA
`(1)/(v)+(1)/(U)=(1)/(f)`
`(1)/(v)=(1)/(f)-(1)/(u)`
`(1)/(v)=(u-f)/(uf)`
For a CONCAVE mirror, f = - ve and u = - ve,
It is given that `u lt f` so v is positive.
Since `v gt 0` i.e. positive and `u lt 0` i.e. negative.
Therefore, image FORMED is BEHIND the mirror [virtual].
`m=-(v)/(u)`
`m=-((+v))/((-u))` therefore m is + ve and the image is enlarged.
Discussion
6811.

Two resistors of 30 Omega and 60 Omega are connected in parallel in an electric circuit. How does the current passing through the two resistors compare?

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SOLUTION :CURRENT PASSING through `30 Omega` resistor is double of the current passing through `60 Omega` resistor.
Discussion
6812.

Give anexample ofa community for whom conservation of forest and wildlife has been a religious tenet .

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Solution :For BISHNOI COMMUNITY in Rajasthan , conservation oftorest andwildlife has been a religious TENET.
Discussion
6813.

Suggest a few measures for controlling carbon dioxide levels in the atmosphere.

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Solution :Few measures for controlling carbon dioxide levels in the atmosphere are as follows
(i) Reduce the consumption of petrol in automobiles. USING car-pools and public TRANSPORT helps in REDUCING petrol usage.
(II) Use of alternative fuels such as CNG (clean fuel) instead of coal and petroleum.
(iii) Manure should be prepared out of litter instead of burning it.
(iv) The smoke coming out of the thermal power stations and other industries should be well treated to remove harmful gases, before discharging it into atmosphere.
(v) Planting more and more trees.
Discussion
6814.

The fuse wire is made up of a material whose melting point is relatively high.

Answer»

Solution :Correct Statement : The FUSE WIRE is made up of a material WHOSE MELTING point is RELATIVELY low
Discussion
6815.

Name the rule for finding the direction of magnetic field produced by a straight current-carrying conductor.

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ANSWER :N/a
Discussion
6816.

A cyclist starts form centreO of a circular park of radius1 km and moves along the pathOPRQO as shown Fig. 2 (EP).15. If he maintains constant speed of10 ms^(-1), what is his acceleration at point (R )in magnitude and direction ? .

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Solution :Centripetal ACCELERATION, `a_(C)=(V^(2))/(r)=(10^(2))/(1000)=0.1 m//s^(2)` along RO.
Discussion
6817.

A couple is acting on a two particle system. The resultant motion will be

Answer»

PURELY ROTATIONAL motion
Purely linear motion
Both (a) & (B)
Neither (a) nor (b)

Solution :Net force for a couple is zero.
So, couple produces only rotational motion.
Discussion
6818.

What is aneuploidy?

Answer»

Solution :(i) The rhythmic closure and OPENING of the valves causes heart sounds. The first sound .LUBB. is of LONGER duration and is produced by the closure of the tricuspid and bicuspid valves after the beginning of ventricular systole. The second sound .DUPP. is of a shorter duration and produced by the closure of semilunar valve at the end of ventricular systole.
(ii) Aneuploidy is the loss or gain of ONE or more chromosomes in a SET. It is of three types. Monosomy (2n-1), Trisomy (2n+1 )and Nullisomy (2n-2).
Discussion
6819.

Draw graphs showing the variation of accleeration due to gravity with (a) height above the Earth's surface, (b) depth below the Earth's surface.

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Solution :
`G propto (1)/(R^2)" for " r gt 0` above surface of earth i.e., AB.
Discussion
6820.

Cloning :

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SOLUTION :PRODUCING EXACT replica of any CELL or organ or entire ORGANISM.
Discussion
6821.

During winter, sometimes we see a white trail at the back of a flying aeroplane in a clear sky. Explain why.

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Solution :In winter, air temperature is low.Hence, when ann aeroplane FLIES,the vapour RELEASED by its engine condenses and forms WHITE clouds. If the relative HUMIDITY of theair surrounding the plane is high, we see white trail at the backof the plane for a long time before it disappears.If the relative humidity is low, the white trail is short and disappears quickly. If the relative humidity is very low, there is no formation of the white trail.
Discussion
6822.

The motion of electric charges through a conductor will constitute. . . . . .. . . . .

Answer»

ELECTRIC CURRENT
electric potential
electrical FIELD
NONE

ANSWER :A
Discussion
6823.

Ankit developed an eye defect at the age of 65 yrs and had to wear a lens of power +3D. Answer the following questions: (a) Name the eye defect. (b) State two reasons why this defect is caused? (c) Compute the focal length of his lens

Answer»

SOLUTION :PRESBYOPIA.
Discussion
6824.

Ankit developed an eye defect at the age of 65 yrs and had to wear a lens of power +3D. Find the focal length of the lens

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SOLUTION :The focusing power of the eye lens decreases with AGE. The muscles near the lens LOSE their ability to change the focal length of the lens. The near point of the lens SHIFTS further than the eye.
Discussion
6825.

Name and state the rule to determine the direction of a force experienced by a straight current-carrying conductor placed in a magnetic field whichis perpendicularto it.

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Solution :Fleming.s left hand rule gives the DIRECTION of theforce experiencedby a straightcurrent carrying conductorplaced in a MAGNETIC field . According to this rule, if the thumb, fore-FINGER and middle finger of the left hand are stretchedto beperpendicularto each other as SHOWNIN the figure, and ifthe fore finger represents the direction of magneticfield, themiddle finger represents the direction of current, then the thumb represents the direction of force . Fleming.sleft hand rule is APPLICABLE for motors.
Discussion
6826.

It is not advisable to connect an electric bulb and electric heater in series.

Answer»

SOLUTION :An electric bulb and electric heater have DIFFERENT resistances and the requirement of current for their proper FUNCTIONING is different.
Moreover, sometimes the devices MAY get damaged. If. one of the devices stops and the circuit breaks, the other device cannot be USED.
Discussion
6827.

A charged particle passes through a region of a non-uniform magnetic field and emerges outof if. Then, itsA] speed may change but velocity remains sameB] velocity remains sameC] velocity may change but speed remains same

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Solution :C] Direction of motion ofa charged particle is CHANGED and HENCE, its velocity CHANGES, but SPEED REMAINS the same.
Discussion
6828.

The mirrorformula is (1)/(f) = (1)/(v) + (1)/(u) where symbols have standard meaning. How will focal length of mirror change when u is changed by moving the object towards or away from the mirror?

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Solution :Focal length (f) of a MIRROR does not depend UPON u or v. It cannot be changed by moving the OBJECT towards or away from the mirror. This is because, when we change object distance (u), the image distance (v) changes, KEEPING (f) constant.
Infact, focal lenght of mirror is half the radius of curvatur (R) of the mirror, i.e., `f = R//2`. Focal length will change with change in radius of curvature of the mirror.
Discussion
6829.

To construct a ray diagram we use two rays of light which are so chosen that it is easy to determine their directions after reflection from the mirror. Choose these two rays and state the path of these rays after reflection from a concave mirror. Use these two rays to find the nature and position of the image of an object placed at a distance of 15 cm from a concave mirror of focal length 10 cm.

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SOLUTION :The position of the image formed by a spherical mirror can be found by considering following two rays :
(i) The ray incident PARALLEL to the PRINCIPAL axis, after reflection, passes through the principal focus of a concave mirror.
(ii) A ray passing through the centre of curvature in a concave mirror after reflection, retraces its path.
The image formation is shown in the adjacent figure. Here for every 5 cm distance we have 1 cm in the ray diagram. Here AB is the object and A.B. is the real and inverted image formed on the BASIS of above mentioned two rays.

Actual measurement shows that the image is formed 30 cm in front of the concave mirror i.e., v = 30 cm.
Discussion
6830.

Which of the following are greenhouse gases?

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`N_(2)`
`CO_(2)`
`CH_(4)`
both b & C

Answer :B::C
Discussion
6831.

The________units form the backbone of the DNA.

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5 CARBON sugar
sugar phosphate
nitrogenous base
phosphate

Answer :B
Discussion
6832.

In the electrolysis of water Why is it that the volume of gas collected on one electrode is two times that on the other electrode

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SOLUTION :`2H_(2)O OVERSET("Electrolysis") rarr 2H_(2) + O_(2)`
As per the chemical EQUATION, the VOLUME of `H_(2)`, liberated at the cathode is twice the volume of `O_(2)` liberated at the cathode.
Discussion
6833.

The filament of a bulb should have a high melting point.Why?

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Solution :The intensity of light emitted by the filament of a bulb depends on the temperature of the filament. It increases with the temperature. (2) The melting point of the material used to MAKE the filament of a bulb should be very high so that the filament can be HEATED to a high temperature by passing a current through it, without melting it. This enables US to obtain more light. The melting point of tungsten is very high. Hence, tungsten is used to make a solenoid type coil (filament) in an electric bulb.
Discussion
6834.

________ is located behind a convex mirror

Answer»

The FOCAL point
A RAY
A REAL image
The OBJECT

Answer :A
Discussion
6835.

Arrange in ascending and descending order, on the basis of their biological effect. Alpha (alpha), Gamma (gamma), Beta (beta)

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SOLUTION :ASCENDING ORDER : Alpha (`alpha`), Beta (`beta`), GAMMA (`gamma`)
DESCENDING order : Gamma (`gamma`) , Beta (`beta`), Alpha (`alpha`)
Discussion
6836.

In Q 55 above ,what would the man weigh in terms of absolute SI units ?

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`(Wg)N`
`((W)/(6)G)N`
`(6Wg)N`
zero

Answer :B
Discussion
6837.

The rest positions of the needles in a Milliammeter and Voltmeter when not being used in a circuit are as shown in the figure. The 'zero error' and 'least count' of these two instruments are :

Answer»

(+ 4 mA, - 0.2 V) and (1 mA, 0.1 V) respectively
(+ 4 mA, - 0.2 V) and (2 mA, 0.2 V) respectively
(- 4 mA, + 0.2 V) and (2 mA, 0.2 V) respectively
(- 4 mA, + 0.2 V) and (2 mA, 0.1 V) respectively

Solution :NA
Discussion
6838.

Which muscles help in changing the shape of the eye lens ?

Answer»

SOLUTION :CILIARY MUSCLES.
Discussion
6839.

The frequency, which is audible to the human ear is

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50kHz
20kHz
15000kHz
10000kHz

Solution :Audible frequency hearing the HUMAN ear RANGE between 20 HZ to 20 KHZ
Discussion
6840.

Identify the substances that are oxidised and the substances that arereduced in the following reactions : underset(" Manganese dioxide")(MnO_(2)) + 4HCI to underset("Manganese chloride")(MnCI_(2)) + 2H_(2)O + CI_(2)uarr

Answer»

Solution :
(1)OXIDATION : ` toH_(2)S, H_(2)O and HCI `
(2) REDUCTION ` toSO_(2) , CuO and MnO_(2)`
Discussion
6841.

Identify the substances that are oxidised and the substances that arereduced in the following reactions : (1)2H_(2)S_((g)) + SO_(2(g)) to 3S_((s)) + 2H_(2)O_((l))

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Solution :When oxidation and reduction take PLACE simultaneously in a given CHEMICAL reaction , it is known as a REDOX reaction.

`H_(2)S` is oxidised and ` SO_(2)`is reduced.
Discussion
6842.

In many applications, solar cells are connected to rechargeable batteries. Why is this so ?

Answer»


ANSWER :The electricity made by solar cells during the DAY TIME is stored in rechargeable batteries so that it can be USED LATER on, for example, at night
Discussion
6843.

What is a solar cell?

Answer»

Solution :It converts SOLAR ENERG directy into ELECTRICITY.
Discussion
6844.

Find the resistance of a bulb, on which 60W and 120 V is marked.

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<P>

SOLUTION :P = 60W, V = 120 V
We know P = VI
`rArr(V_(2))/(R)(becauseI=(V)/(R))`
`rArrR=(V_(2))/(R)=(120xxcancel(120))/(CANCEL(60))=240Omega.`
Discussion
6845.

What is the far point and near point of the human eye with normal vision?

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Solution :Far point of the HUMAN EYE with NORMAL vision is infinity and near point is 25 CM.
Discussion
6846.

A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in fron of the convex lens if theimage is equal to the size of the object? Also, find the power of the lens.

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SOLUTION :v=+50 CM (image is REAL)
m=-1 (SIZE of image =size of object and image is inverted)
U=?
`m=v/u` or ` u=v/m=50/(-1)` or u=-50cm `1/f=1/v-1/u`
`=1/50-1/(-50)=1/50+1/50=2/50`
`f=50/2=2.5cm`
Discussion
6847.

Diminished image : Beyond 2F_(1) : : Same size image: ……………… .

Answer»


ANSWER :at `2F_(1)`
Discussion
6848.

Read the passageand answer the following question. Salaam Mumbai Foundation. This organization runs programs in various schools in Mumbai to emprower the children living in slum area in the field of education, sports, arts and business. jThis organization encourages the children to take education by helping them to improve their health and lifestyle. This trust has made some districts in Maharashtra completely tobacco-free through hard work. Since the year 2002 this organisation is working with various school in urban and rural area for making the society tabaccofree. This programme is being implemented with the help of Government in about 200 schools in Mumbai and 14000 schools in the rest of maharashtra. The oath of freedom from tobacco is taken in every school as per the Government letter. What is the greatest achievement of the organization ?

Answer»

Solution :The ACHIEVEMENT of this organization is that it has MADE some DISTRICTS in MAHARASHTRA completely tobacco-free through hard work.
Discussion
6849.

Read the passageand answer the following question. Salaam Mumbai Foundation. This organization runs programs in various schools in Mumbai to emprower the children living in slum area in the field of education, sports, arts and business. jThis organization encourages the children to take education by helping them to improve their health and lifestyle. This trust has made some districts in Maharashtra completely tobacco-free through hard work. Since the year 2002 this organisation is working with various school in urban and rural area for making the society tabaccofree. This programme is being implemented with the help of Government in about 200 schools in Mumbai and 14000 schools in the rest of maharashtra. The oath of freedom from tobacco is taken in every school as per the Government letter. What are the steps being taken by the organization to making the society tobacco free ?

Answer»

Solution :1. Since the year 2002 this ORGANISATION is working with various SCHOOL in urban and rural area for MAKING the society tobacco-free.
2. This programme is being implemented with the help of Government in about 200 schools in Mumbai and 14000 schools in the rest of MAHRASHTRA.
3. The oath of freedom from tobacco is taken in every school as per the Government letter.
Discussion
6850.

Read the passageand answer the following question. Salaam Mumbai Foundation. This organization runs programs in various schools in Mumbai to emprower the children living in slum area in the field of education, sports, arts and business. jThis organization encourages the children to take education by helping them to improve their health and lifestyle. This trust has made some districts in Maharashtra completely tobacco-free through hard work. Since the year 2002 this organisation is working with various school in urban and rural area for making the society tabaccofree. This programme is being implemented with the help of Government in about 200 schools in Mumbai and 14000 schools in the rest of maharashtra. The oath of freedom from tobacco is taken in every school as per the Government letter. What is the objective of thsi organization ?

Answer»

Solution :The objective of this organization is to empowere the children living in SLUM AREA in the field of education, sports, ARTS and business. It ENCOURAGES the children to take educatin by helping them to IMPROVE their health and lifestyle.
Discussion