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1501.

What is far point of a normal human eye ?

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Solution :The FAR POINT of a normal HUMAN EYE is at INFINITY.
1502.

What happens if a 5 A fuse is connected to a wire carrying 15 A current ?

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SOLUTION :The fuse melts and BREAKS the circuit preventing all the appliances from working .
1503.

Use your brain power! M=(h_(2))/(h_(1))"…..(i)" M=(v)/(u)" …..(ii)" From equations (i) and (ii) what is the relation between h_(1), h_(2), u and v ?

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Solution :From the given equations, we can SAY that,
`(h_(2))/(h_(1))=(v)/(u)`
According to Cartesian SIGN convention, for concave lens, `h_(2) and h_(1)` are always positive while v and u are always negative.
`therefore" "(+h_(2))/(+h_(1))=(-v)/(-u)`
SIMILARLY, for convex lens, when object is placed within the focal length, `h_(2) and h_(1)` are positive while v and u are negative.
`therefore" "(+h_(2))/(+h_(1))=(-v)/(-u)`
For all other positions of object, `h_(2) and u` are negative while, `h_(1) and v` are positive.
`therefore" "(-h_(2))/(+h_(1))=(+v)/(-u)`
1504.

If there were only one type of charge in the universe, then

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`oint_(S) vec(E) .vec(ds) = 0` if the CHARGE is outside the surface
`oint_(S) vec(E) .vec(ds) = (Q)/(in_(0))` if charges of MAGNITUDE `q` were inside the surface
`oint_(S) vec(E) .vec(ds)` could not be defined
Both A and B

Answer :D
1505.

Why are the traffic light-signals [or danger signals] of red colour ?

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Solution :In te VISIBLE spectrum, the red colour has the largest wavelength and it least SCATTERED by fog or DUST particles. Hence, it can be observed EASILY even in foggy and dusty CONDITIONS.
1506.

The resultant force acting on a body is equal to zero then the body will be in ………………………

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SOLUTION :EQUILIBRIUM
1507.

If the temperature of water is decreased from 4^(@)Cto 0^(@)C , then its……………

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VOLUME DECEASES and DENSITY increases
volume increases and density decreases
volume and density decrease
volume and density increase

Answer :B
1508.

Find the focal length of the lenses used in spectacles of a person if the power of the spectacles is 0.5D.

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Solution :Focal LENGTH of the lenses used in her spectacles
` = 1/(" POWER of the LENS") = 1/( 0.5 D) = 2m`
1509.

The change in focal length of an eye lens is caused by the action of the.

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pupil
retina
iris
ciliary muscles

Solution :The ACTION of ciliary muscles holding the eye lens CHANGE the focal length of eye lens ENABLING the eye to focus the IMAGE of objects at VARYING distances. Choose (iv) is correct.
1510.

The direction of current is taken opposite to the direction of flow of______________.

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SOLUTION :ELECTRONS
1511.

Find the centre of mass of a uniform triangula lamina.

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ANSWER :At its CENTROID
1512.

The values of current I flowing in for the corresponding values of potential difference V across the resistor are given below : Plot a graph between V and I and calculate the resistance of that resistor.

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Solution :The graph between V and I PLOTTED by using the given DATA is shown below:

CALCULATION of the resistance of given RESISTOR:
1513.

Find out, the meidum having highest optical density. Also find the medium with lowest optical density.

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SOLUTION :DIAMOND has highest optical density (n = 2.42). MEDIUM with lowest optical density is AIR (n = 1.0003).
1514.

What are the different types of nuclear reactions?

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Solution :There are TWO type of nuclear reactions:
(i) Nuclear FISSION (II) Nuclear FUSION.
1515.

Decrease in leucocytes is…..........

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Leucopenia
Leukemia
Anaemia
None of the above

Answer :a
1516.

Try this. i. Try to read a book keeping it very far from your eyes. ii. Try to read a book keeping it very close to your eyes. iii. Try to read a book keeping it at a distance of 25 cm from your eyes. At which time you see the alphabets clearly? Why?

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SOLUTION :The alphabets can be read clearly by keeping the book at a distance of approximately 25 cm from the eyes. This is because for a normal eye, minimum distance at which an object can be seen most DIS!inctly without strain is about 25 cm in front of the eye. The object placed at a distance LESS or more than 25 cm APPEARS blur.
1517.

Assertion: A voltmeter must be connected in parallel and should have a high resistance. Reason: The introduction of the voltmeter in the circuit must not affect the potential difference.

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if both the assertion and the REASON are trueand the reason is the correct EXPLANATION of the assertion.
if both theassertion and the reason are TRUE , but the reason is not the correct explanation of the assertion.
if the assertion is true, but Reason is FALSE.
if assertion is false, but the reason is true.

Solution :both the assertion and the reason are trueand the reason is the correct explanation of the assertion.
1518.

A star sometimes brighter and at other times fainter. What is this effect called ? State the reason.

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Solution :This defect is called twinkling of stars. Reasons: The light from the stars will be passing through the atmosphere WHOSE refractive index KEEPS changing constantly due to wind and varying air density. THUS, there will be CHANGES in the density of light from the star REACHING our eyes causing twinkling effect.
1519.

Mention one difference between refraction in a prism and a glass slab.

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Solution :In PRISM, during REFRACTION, the INCIDENT ray is not PARALLEL to the emerget ray as in a glass slab.
1520.

Images formed by convex lenses for different position of the object. Object between focus F_(1) and optical centre O Image formation - (a) On the same side of the lens as the object (b) Virtual, erect and magnified

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SOLUTION :
1521.

A ________ microscope works based on the principle of vernier.

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SOLUTION :TRAVELLING MICROSCOPE
1522.

If the angle between the vectors vecA and vecB is theta, the value of the product (vecB xx vecA) * vecA is equal to

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`BA^(2) COS THETA`
`BA^(2) sin theta `
`BA^(2) sin theta cos theta `
Zero

Solution :ANGLE between `vecB xx vecA and vecA ` is `90^(@)`
`(vecB xx vecA). vecA=|vecB xx vecA||vecA| cos 90^(@)`
`=0`
1523.

Classify the following into levers as class I, class II or class III: (a) a door (b) a catapult (c) claw hammer (d) a wheel barrow (e) a fishing rod. (f) sugar tongs.

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ANSWER :(a) CLASS II,
(b) class I,
(c) class I,
(d) class II,
(E) class III,
(f) class III.
1524.

What type of carbon - carbonbondsare present invanaspatighee ?

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Singlebonds
Doublebonds
triplebonds
NONE of these

Answer :B
1525.

1 joule equals

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`AV s^(-1)`
`AV^(-1) S`
`AV s`
`A^(-1) VS`

ANSWER :C
1526.

A straight wire carrying electric current is moving out of plane of paper and is perpendicular to it What is the direction and type of induced magnetic field?

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Solution :Induced MAGNETIC field will be in the FORM of CONCENTRIC circles in the plane of PAPER.
1527.

_________ act in oppositedirections.

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SOLUTION :Unlikeparallel FORCES
1528.

Keeping the potential difference constant, the resistance of a circuit is halved. How does the current change?

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SOLUTION :The CURRENT BECOMES DOUBLE the initialcurrent.
1529.

A player completes a circular path of radius r in 40 s. At the end of 2 minutes 20 seconds, displacement will be

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2R
`2pir`
`7pir`
zero

Answer :A
1530.

Kajal who jas just begun to learn swimming is in the pool suddenly she finds her gold earring falling into the water she feels that the earrings has not gone too deep and the goes into the water to retrieve it. Her trainer observing this pulls her out. Why the earrings looked that is has not gone deep?

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Solution :It is due to the REFRACTION of light, the EARRING in POND SEEMS to be RAISED up.
1531.

Kajal who jas just begun to learn swimming is in the pool suddenly she finds her gold earring falling into the water she feels that the earrings has not gone too deep and the goes into the water to retrieve it. Her trainer observing this pulls her out. what value does the trainer show?

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Solution :Trainer CONCERNED about the safety of the students
(b) Presence of MIND of the trainer, TIMELY action.
1532.

Are they longitudinal or transverse?

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SOLUTION :SOUND WAVES in AIR are LONGITUDINAL.
1533.

To study the dependence of current (I) on the potential difference (V) across a resistor R, two students used the two set ups shown in Figures A and B respectively. They kept the contact point J in four different positions, marked (a), (b), (c) and (d) in the two figures. For the two students, the ammeter and voltmeter readings will be maximum when the contact J is in the position :

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(d) in both the SET UPS
(a) in both the set ups
(d) in set up A and (a) in set up B
(a) in set up A and (d) in set up B

Solution :NA
1534.

In order todetermine the equivalent resistance of two resistors R_(1) and R_(2) connected in series, a student made this circuit for his experiment. The only statement which is true for this circuit is that it gives :

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INCORRECT readings for current I as well as for potential DIFFERENCE V
correct READING for current I but incorrect reading for potential difference V
incorrect reading for current I but correct reading for potential difference V
correct readings for both current I and potential difference V.

Solution :NA
1535.

How will you create an artifical aquatic ecosystem, which is self - sustaninable ?

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Solution :A natural ecosystem is self-sustainable because it has all the key role players like the producers, the consumers and the DECOMPOSERS. While creating an ARTIFICAL ecosystem, we will have to add all the important components. For examples :
(i) In a large jar filled with WATER, add source of oxygen and light.
(ii) Add aquatic plants.
(iii) Add zooplanktons which feed on these plants.
(iv)Add SMALL fish which feed on these zooplanktons.
(v) We may add larger fish which feed on these smaller fishes.
(vi) Lastly add some aquatic bacteria which feed on the dead and decaying matter so that the system remains CLEAN.
1536.

Study the given ray diagrams and select the correct statement from the following :

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Device X is a concave MIRROR and device Y is a convex lens, whose focal lengths are `20 cm` and `25 cm` respectively.
Device X is a convex lens and device Y is a concave mirror, whose focal lengths are `10 cm` and `25 cm` respectively.
Device X is a concave lens and device Y is a convex mirror, whose focal lengths are `20 cm` and `25 cm` respectively.
Device X is a convex lens and device Y is a concave mirror, whose focal lengths are `20 cm` and `25 cm` respectively.

Solution :(d) The device X is a convex lens of focal LENGTH 20 cm. Parallel RAYS FALLING on convex lens are focussed on the screen at 20 cm from the lens. The device Y is a concave mirror of focal length 25 cm. Parallel rays falling on the concave mirror are focussed on the screen at 25 cm from the concave mirror.
1537.

State in brief the meaning of a variable resistoL Draw a circuit diagram to illustrate its function specially in the study of variation in current with the potential difference across a resistor.

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Solution :A device to regulate CURRENT without changing the voltage SOURCE in an electric circuit is CALLED a variable RESISTOR or a rheostat.
1538.

In regions with cold climate, the aquatic plants and animals can survive even when the atmospheric temperature goes below 0^@C

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Solution :1.The existence offish and other aquatic life is possible due to anomalous expansion of water.
2. In regions of cold climate, the atmospheric temperature falls below `0^@C`.
3. As the atmospheric temperature falls, the water at the surface of ponds and lakes starts contracting. Its volume decreases and density increases.
4. The water with higher density moves downward and thewater with lower density moves UPWARD. This continues till the temperature of water becomes `4^@C`.
5. When the temperature of water starts decreasing below `4^@C`, water starts expanding instead of contracting. Its volume increases, density decreases and it remains at thesurface.
6. Soon, the surface water gets converted into sheet of ice. This sheet of ice ACTS as an insulator and does not ALLOW the transfer of HEAT from water to the atmosphere.
7. Therefore, the water below the sheet of ice remains at `4^@C`.
8. Hence, due to the anomalous expansion of water, aquatic life (plants and animals)is PRESERVED in regions of cold climate.
1539.

In V-T diagram shown in fig., what is the relation between P_1 and P_2 ?

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`P_2 and P_1`
`P_2 gt P_1`
`P_1 gt P_2`
Cannot say

Solution :In an isobaric process P = constant and
`V PROP T " or " V ((NR)/P)^T`
V-T graph is a straight line with slope`prop 1/P`
`(slope)_2gt (slope)_1 :. P_2 lt P_1`
1540.

Define linear magnification of an object. Write the expression for the same.

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Solution :Linear magnification of an object specifies how large or small the image of the object FORMED in a spherical mirror or lens is when COMPARED to the size of the object. Linear magnification (m) is the RATIO of the height of the image (h.) to the height of the object (h) :
`m=(h.)/(h)`
Linear magnification can also be expressed as the ratio of the image DISTANCE (v) to object distance (U) :
`m=(v)/(u)`.
1541.

The speed of light in diamond is 125,000" km "s^(-1) what is its refractive index ? (Speed of light in air =3xx10^(8)ms^(-1)).

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ANSWER :`2*4`
1542.

(ATP, mitochondria, external, internal, inhalation, alveolar, breathing, respiration exhalation is called …………………………. When ……………………….. Is done, air enters the lungs. The oxygen from this air enters the blood while carbon dioxide from the blood exits from the blood. Through exhalation, CO_(2) is given out. This gaseous exchange occurs through ........................ membrane. This is called ........................ respiration. The RBCs carry oxygen to every cell. Here inside the ....................... tissue respiration or ..................... respiration takes place. The oxygen is used for production of energy. By oxidation of food nutrients energy is released in the form of ....................... .

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Solution :Release of energy from the ASSIMILATED food is called respiration. Inhalation and exhalation is called breathing. When inhalation is done, air enters the lungs. The oxygen from this air enters the blood while CARBON DIOXIDE from the blood exits from the blood. Through exhalation, `CO_(2)` is given out. This gaseous exchange occurs through alveolar membrane. This is called external respiration. The RBCs carry oxygen to every cell. Here inside the mitochondria TISSUE respiration or internal respiration takes place. The oxygen is USED for production of energy. By oxidation of food nutrients, energy is released in the form of ATP.
1543.

An object of height 6 cm is placed perpendicular to the principal axis of a concave lens of focal length5 cm. Use lens formula to determine the position, size and nature of the image if the distance of the object from the lens is 10 cm.

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Solution :A CONCAVE lens always form a virtual and erect IMAGE on the same side of the OBJECT.
Image distance v=?
Focal length f=-5 cm
Object distance u=-10 cm
`1/f=1/v-1/u`
`1/v=1/f+1/u`
`=1/(-5)+1/(-10)`
`=1/(-5)+1/(-10)`
`=1/(-5)-1/10=(-1-2)/10`
`=(-3)/10=3.3cm`
`v=-3.3cm`
`("Size of the image")/("Size of tbe object")=+v/u`
`(h.)/h=(-3.3)/(-10)`
`h/6=3.3/10`
`h.=(6xx3.3)/10`
`=(19.8)/10=1.98 cm`
Size of the image is 1.98 cm
1544.

Which phenomenon is responsible for making the path of light visible ?

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Solution :TYNDALL EFFECT is RESPONSIBLE for making the path of light VISIBLE.
1545.

Name and state the rule used for determination of direction of induced current produced in a conductor due to a changing magnetic field and give one practical application of this phenomenon in everyday life.

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Solution :Rule: Fleming.s right-HAND rule.
It states that if we stretch the thumb, forelinger and middle finger of our right hand such that they are mutually perpendicular to each other. If forefinger indicates direction of magnetic FIELD and the thumb shows the direction of motion of conductor, then middle finger will SHOW direction of inducedcurrent.
Application: Electrical generator.
1546.

Draw the electron dot structure and line structure of methane molecule

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SOLUTION :
1547.

When a ray of light from air enters a denser medium, it :

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BENDS AWAY from the normal
bends TOWARDS the normal
goes undeviated
is REFLECTED back

Answer :B
1548.

A body goes from A to b with a velocity of 20m/s and comes back from B to A with a velocity of 30m/s. The average velocity of the body during he whole journey is

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zero
25m/s
24m/s
none of these

SOLUTION :AVERAGE velocity
`=("Total DISPLACEMENT covered")/("Total time taken")`As the body comes BACK to the starting point, total displacement is zero
1549.

Explain with the help of a diagram, how we are able to observe the sunrise about two minutes before the sun gets above the horizon. Hence, explain why does apparent duration of a day from sunrise to sunset is 4 minutes more than its actual duration.

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Solution :The air becomes rarer as its height above the earth increases. Its refractive INDEX decreases. A ray of LIGHT from the Sun when it enters the atmosphere at the horizon gets refracted from a rarer to a DENSER medium. The rays, therefore gradually bend towards the normal and the Sun appears to be raised. As a result, the Sun is visible to an observer nearly two minutes before actual sunrise at the horizon. Similarly, even after actual sunset, Sun is seen by us for about 2 minutes. Thus, in EFFECT Sun is seen for 4 minutes more. It means that apparent duration of day (from sunrise to sunset) has increased by 4 minutes than its actual duration.
1550.

Observe. Check your conclusions and observations in the previous activity with those given in the table given on page 83 of your textbook.

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Solution :[STUDENTS are expected to COMPARE the above GIVEN information with the table given in the TEXTBOOK on their own]