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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3251. |
When a system is taken from state A to state B along the path ACB, 80 k cal of heat flows into the system and 30 k cal of work is done. How much heat flows into the system along path ADB if the work done is 10 k cal ? When the system is returned from B to A along the curved path the work done is 20 k cal. Does the system absorb or liberate heat. |
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Answer» Solution :`dw_(BA)=-20 K cal ` `du_(BA)=-du_(ADB)` `du_(BA)=-du_(ADB)` `dQ_(BA)=du_(BA)+dw_(BA)` `=-50-20 = -70 ` k cal |
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| 3252. |
When a system is taken from state A to state B along the path ACB, 80 k cal of heat flows into the system and 30 k cal of work is done. How much heat flows into the system along path ADB if the work done is 10 k cal ? |
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Answer» Solution :`dw_(ADB)=+10kcal ` INTERNAL ENERGY is path independent `du_(ADB)=du_(ADB)=50 K cal ` `dQ_(ADB)=50+10=60 k cal ` |
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| 3253. |
When a system is taken from state A to state B along the path ACB, 80 k cal of heat flows into the system and 30 k cal of work is done. If U_A = 0 and U_D = 40k cal, find the heat absorbed in the process AD |
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Answer» Solution :`U_A=0, U_D = 40 K CAL ` `du_(AD)=40 k cal ` `dw_(ADB)=10K cal ` `dw_(DB)=0 "since" dV = 0 ` `dQ_(AD)=40+10=50` k cal |
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| 3255. |
A straight currrent- carryingconductor is placed ina magneticfield such that itslength is perpendicular to thefield .Nameand state the rule used to the findthedirection of the forceactingon the conductor . |
Answer» Solution :In this caseFleming.slefthand ruleis used to findthe directionof theforceactingon the conductor . Stretch the THUMB , FOREFINGER and middle finger of your LEFT hand such that they are mutually PERPENDICULAR (figure 13.22). If the first (force) finger points in the direction of magnetif fieldand second (middle ) finger pointsin the direction of current,thenthumb will pointin thedirectionof motionor the forceactingon the conductor . |
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| 3256. |
The orbit of a planet is an ellipse with the Sun at one of the ___________. |
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Answer» a) FOCI |
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| 3257. |
The sky appears reddish at the sunset due to the fact, that |
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Answer» blue-violet light has been scattered least. |
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| 3258. |
What is cubical expansion ? |
| Answer» Solution :If there is an increase in the VOLUME of a SOLID BODY due to HEATING, then the expansion is CALLED cubical or columetric expansion. | |
| 3259. |
PQ is a cwrent carrying conductor in the plane of the paper as shown in the fig. Mention the direction of magnetic fields produced by it at points A and B. Given : r_(1) lt r_(2r) ,where will the strength of the magnetic field be larger ? Justify your answer in each case. |
Answer» SOLUTION :STRENGTH of magnetic field will be larger at A as the strength of magnetic field decreases when the distance is increased direction of MAGNETICFIELD lines at A as well as B is anticlockwise because field lines are concentric circles and direction is determined by Right HAND thumb rule. 
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| 3260. |
The laws of reflection of light are valid for |
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Answer» PLANE MIRRORS only |
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| 3261. |
Which type of mirror produces an image that is always erect, always the same height as the object, and always virtual. |
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Answer» CONVEX |
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| 3262. |
Name the phenomenon responsible for (i) advance of sunrise (ii) colour of water in deep sea (iii) twinkling of stars and (iv) reddish appearance of the sun at the time of sunrise and sunset. |
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Answer» SOLUTION :(i) ATMOSPHERIC refraction (II) Scattering of light. (III) Atmospheric refraction (iv) Scattering of light. |
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| 3263. |
Identify the diagram and label it . |
Answer» Solution :This is the DIAGRAM SHOWING STEM cell THERAPY : 
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| 3264. |
An electric iron draws a current of 4 A when connected to a 220 V mains. Its resistance must |
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Answer» `1000 OMEGA` |
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| 3265. |
Solve the equation for alpha decay and beta decay. alpha decay ._(88)Ra^(226) rarr Rn + ........................ beta decay ._(27)Co^(60) rarr Ni + ....................... |
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Answer» SOLUTION :`alpha` decay `._(88) Ra^(226) rarr RN + ._(2)He^(4)` `beta` decay ._(27)Co^(60) rarr ._(28)Ni^(60) + ._(-1)e^(0)` |
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| 3266. |
(a) Which phenomenon accounts for advanced sunrise and delayed sunset ? (b) Which phenomenon accounts for blue colour of clear sky ? |
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Answer» Solution :(a) Atmospheric REFRACTION is responsible for ADVANCED SUNRISE and deleyed sunset. (b) Blue coloue of CLEAR SKY is on account of scattering of sunlight. |
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| 3267. |
What is the use of telescope? |
| Answer» Solution :TELESCOPE is an optical instrument to see the distant OBJECTS like STARS, planaets etc. in space. | |
| 3268. |
Distinguish between Oviparous and Viviparous animals . |
| Answer» Solution :The animals which GIVE BIRTH to YOUNG ONES are CALLED viviparous animals | |
| 3269. |
Name a common nutrient that is absorbed in the small intestine and then reabsorbed by the kidney tubules. |
| Answer» SOLUTION :This NUTRIENT is GLUCOSE | |
| 3270. |
List measures that can be taken to conserve forests . |
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Answer» Solution :Measures need to be taken to CONSERVE FORESTS : (i)Reforestation of the DEFORESTED areas as soon as possible. (ii)Ban on the indiscriminate cutting of trees. (iii)Felling of trees for fueland wood should be avoided. (IV)OVERGRAZING in forestsashould be discouraged. |
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| 3271. |
Extensive planting of trees to increase forest cover is called : |
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Answer» AFFORESTATION |
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| 3272. |
What do you mean by lateral inversion of the image in mirrors? |
| Answer» SOLUTION :If we look into the mirror to see the IMAGE , we see that the image in inverted SIDEWAYS, i.e. if we MOVE our left hand the image APPEAR to move its right hand. | |
| 3273. |
A student while doing the experiment on tracing the path of a ray of light passing through a rectangular glass slab measured the three angles marked as theta_(1), theta_(2) " and " theta_(3) in the figure. His measurements could be correct if he were to find : |
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Answer» `theta_(1) lt theta_(2) lt theta_(3)` |
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| 3274. |
According to Newton's law of gravitation, earth's gravitational force is higher on an object of larger mass. Why doesn't that obejct fall down with higher velocity as compared to an object with lower mass? |
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Answer» Solution :i. The ACCELERATION DUE to gravity g on an OBJECT only depends on mas (M) and RADIUS (R) of the earth `g=(GM)/(R^(2))` (ii). It does not depend on mass (m) of the object. III. The acceleration produced at a given point is the same for all objects. iv Hence object of larger mass does not fall down with higher velocity as compared to an object with lower mass. |
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| 3275. |
Define power of a lens and write its SI unit. |
| Answer» Solution :Reciprocal of focal length of a LENS, EXPRESSED in METRE, is called the power of that lens. Its SI UNIT is 1 DIOPTRE (1 D), where 1 D = 1 `m^(-1)`. | |
| 3276. |
Body of annelidan animals is long, cylindrical and ……….. ,segmented. |
| Answer» Solution :BODY of ANNELIDAN animals is LONG , CYLINDRICAL and metaemerically segmented. | |
| 3277. |
___________is a smooth curve, tangent to which at any point gives the direction of magnetic field at that point. |
| Answer» SOLUTION :A MAGNETIC FIELD LINE | |
| 3278. |
Electromagnetic induction was discovered by …………. . |
| Answer» SOLUTION :ELECTROMAGNETIC induction was discovered by `ul(Michael Faraday and independently by JOSEPH Henry")` . | |
| 3279. |
In which of the following devicel process is solar energy converted into chemical energy? |
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Answer» SOLAR EVAPORATION |
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| 3280. |
The P-V diagram of a gas undergoing a cyclic process ABCDA is shown in (figure). Where P is in N//m^(2) and V is in cm^(3). Identify the incorrect statement |
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Answer» 0.4 J of work is DONE by the GAS from A to B `:. dW = p. dV = 0` |
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| 3281. |
On what basis and how are the orbits of artificial stellites classified? |
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Answer» Solution :Depending on the height of the satellite 's orbit above the earth's surface , the satellite orbits are classified as below : (a) If the height of the stellite 's orbit above the earth's surface is GREATERTHAN or equal to 35780 km , the orbit is called high earth orbit. (b) A satellite is revolving in such orbits takes around 24 hours to complete one revolution, almost same as duration of one rotation of the earth. (c) If the satellite is revolving in a high earth orbit parallel to the equator, then its time for one revolution around the earth is same as that of rotation of earth . As a result , the satellite APPEARS to be stationary with respect to the earth. Therefore , these satellites are called geosynchronous satellites. (d) Being geosychronous ,these satellites can OBSERVE a specific region on the earth continuously . Hence , they can be used for carrying SIGNALS for telephone , television etc. and also in the applications like meteorology . |
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| 3282. |
Assertion : A parallel beam of light passing through the concave lens , is diverged or spread out Reason : A convex lens is also called as diverging lens. |
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Answer» If both assertion and reason are true and reason is the CORRECT explanation of assertion. |
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| 3283. |
The magnification produced by a plane mirror is +1. What does this mean ? |
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Answer» Solution :We know that MAGNIFICATION prodcued by a mirror is given by `m = (h.)/(h) = -(v)/(u)` As magnification produced by a plane mirror m = + 1, HENCE we have `+1 = (h.)/(h) = - (v)/(u) rArr h. = h` and v = -u Thus the size of image is exactly equal to the size of the OBJECT placed in FRONT of it. Moreover, the image is formed as MUCH behind the mirror as the object is in front of it. |
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| 3284. |
How is energy formed from oxidation of carbohydrates, fats and proteins? |
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Answer» Solution : (1) First of all the dietary carbohydrates are digested in the digestive system with the help of various enzymes and converted into glucose. SIMILARLY, proteins are converted into amino acids and fats are broken down into fatty aid and glycerol (alcohol). (2) Oxidation of carbohydrates takes place during cellular respiration. Glucose is oxidized by three steps during aerobic respiration, viz. glycolysis, tricarboxylic acid cycle or Krebs cycle and electron transfer chain. (3) From one molecule of glucose two molecules of each pyruvic acid ATP NADH and water are formed during glycolysis. Pyruvic acid ' ' 2 which is formed in this process is converted into Acetyl-Coenzyme-Aalong with release of two molecules each of `NADH_2" and "CO_2` . (4) In the next step, i.e. in TCA cycle, molecules of Acetyl-Co-A ENTER the mitochondria and a cyclic chain of REACTIONS take place. Acetyl part of Acetyl-Co-A is completely oxidized through this cyclical Process The molecules `CO_2, H_2O, NADH_2, FADH_2` are released in this . 2' 2 ' 2' 2 process. (5) In THIRD step, i.e. in ETC reaction, `NADH_2" and "FADH_2` formed during first two steps are used for obtaining ATP molecules. 3 molecules of ATP are obtained from each `NADH_2` molecule and 2 molecules of ATP from each `FADH_2`. (6) Thus, one molecule of glucose upon complete oxidation in presence of oxygen yields 38 molecules of ATP. This is how from carbohydrates, energy is obtained. (7) If carbohydrates are insufficient in diet, then proteins or lipids are used for energy production. Fatty acids derived from fats and amino acids derived from proteins are converted into Acetyl-Co-A. Acetyl-Co-A once again can yield energy through TCA cycle. |
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| 3285. |
Which of the following is formed under the earth by the decomposition of plant matter by anaerobic bacteria lying under water? |
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Answer» COAL gas |
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| 3286. |
What is dispersion? What happens when light is passed through a glass prism. |
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Answer» SOLUTION :The process of splitting up of white light into its constituent colour as it passes through a refracting medium is KNOWN as DISPERSION of light. It bends towards the base of the prism after PASSING through it. |
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| 3287. |
One circular ring and one circular disc both having same mass and radius. The ratio of their moment of inertia about the axis passing through their centres and perpendicular to their planes will be |
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Answer» `1:1` |
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| 3288. |
Which one of the following statements is correct about the human circular system ? |
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Answer» Blood TRANSPORTS only OXYGENS and not carbon dioxide. |
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| 3289. |
A student is observing a permanent slide showing swquentially the different Stages of asexual reproduction taking place in yeast. Name this process and draw diagrams of what he observes in a proper sequence. |
Answer» SOLUTION :The PROCESS of REPRODUTION in YEAST is BUDDING. 
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| 3290. |
Identify the parts A,B,C and D. |
| Answer» SOLUTION :A-Exine, B-Intine, C-Generative CELL, D-Vegetative NUCLEUS. | |
| 3291. |
Nature of disaster management. |
| Answer» Solution :(1) DISASTER management involves either PREVENTION of disasters or creating preparedness to face them. Disaster management is DONE in two modes, viz. pre-disaster management and post-disaster management. (2) For disaster management, the action plans are preapred. This is done after STUDYING the different aspects such as preventive measures, rehabilitation and reconstruction plans. (4) The disasters are tackled in the following steps : Preparation, redemption, preparedness, action during actual disaster, response, resurgence and restoration. At every level there are other voluntary organizations and Government meteorological for their help in disaster management. | |
| 3292. |
Seeds have some food stored in the cotyledons that is helpful during the process of germination. A small seed can grow into a giant tree when allowed to grow in the right conditions/environment. Answer the following questions based on above passage: (i) How is the food stored in the cotyledons helpful during the process of germination? (ii) List four values acquired by a student in the early stages of his/her growth which can enable him/her to achieve great heights in life. (iii) Write any two environmental conditions to be provided by the parents/family to help the chilli's personality grow in the right direction. |
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Answer» Solution :(i) Cotyledons contains FOOD in the form of bio-chemical energy which is USED in the process of germination. (ii) Hard WORK, passion for learning and KNOWLEDGE, similarity, thinking skills and origin ability. (iii) Providing opportunities for variety of learning experiences, motivation and FREEDOM to experiment. |
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| 3293. |
Study the following electric circuit and calculate the potential difference across5 Omegaresistor. |
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Answer» Solution :V=IR R = 3+4+5 `=12 Omega` `3=Ixx12` `I = (3)/(12) =(1)/(4)` Ampere , Potential difference across `5 Omega` RESISTOR . V=IR `V= (1)/(4) XX5` `= (5)/(4) V ` or 1.25 V |
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| 3294. |
Two resistances x and y are connected i] in parallel and, ii] in series. In which case the resultant resistance will be the less than either of the individual resistance? |
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Answer» SOLUTION :In parallel COMBINATION, the RESULTANT resistance will be less than either resistance. In series combination, the resultant combination will be LARGER than both resistances. |
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| 3295. |
Draw a neat labelled diagram of the human eye and explain the working of each part of it. |
Answer» Solution : These parts and their functions are as follows: The human eyeball is approximately spherical in shape and its diameter is about 2.3 cm. (1) Cornea : The front portion of the eye, bulging outwards, is known as the cornea. It is a transparent and thin spherical membrane. Light enters the eye through this membrane. Most of the refraction of light rays entering the eye occurs at the outer SURFACE of the cornea, i.e., cornea refracts the rays of light falling on the eye. (2) Iris : Beyond the cornea, there is a dark coloured muscular diaphragm known as the iris. The iris controls the size of the pupil. It is the colour of the iris that we call as the colour of the eye. (3) Pupil : The small hole in the middle of the iris is called the pupil. Light enters the eye through the pupil. The pupil regulates and controls the amount of light entering into the eye. [The pupil of the eye acts like a variable aperture WHOSE size varies with the help of the iris. When the light is very bright, the iris contracts the pupil to allow less light to enter into the eye. However, in dim light the iris expands the pupil to allow more light to enter into the eye. Thus, the pupil opens completely through relaxation of the iris.] (4) Crystalline lens : Behind the iris there is the eye lens which is a convex lens made of a transparent, soft and flexible material like a jelly made of proteins. The focal length and hence converging power of the eye lens is adjustable, because its curvature can be changed (modified) to some extent by ciliary muscles. It focuses an inverted real image of the object on the RETINA. (5) Ciliary muscles : They hold the eye lens in position and help in changing (modifying) the curvature of the eye lens and hence the focal length of the eye lens. When the ciliary muscles are relaxed, the eye lens becomes thin. Hence, its focal length increases and the converging power decreases. When the ciliary muscles are tense, the eye lens becomes thick. Hence, its focal length decreases and the converging power increases. (6) Retina : Behind the eye lens and at the back SIDE of the eyeball, there is a screen called retina on which an inverted real image of the object is formed. The retina is a delicate membrane / film covering the entire curved back surface of the eye. It has enormous number of light-sensitive cells in the form of rods and cones. The rod-like cells respond to the intensity of light and cone-like cells respond to the colour of light. These cells get activated upon illumination and generate electrical signals (or NERVE impulses) which are sent to the brain via the optic nerve. The brain interprets these signals and finally, processes the information so that we perceive objects as they are. (7) Optic nerve : It transmits visual information from the retina to the brain. ( 8 ) Aqueous humour: The space between the cornea and eye lens is filled with a viscous and transparent liquid called aqueous humour which helps the refracted light to be focussed on the retina. It also maintains intraocular pressure. (9) Vitreous humour : The space between the eye lens and retina contains transparent jelly called the vitreous humour. |
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| 3296. |
What are the functions of the following?(a) Thalamus (b) Hypothalamus (c) Cerebellum (d) Pons |
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Answer» SOLUTION :Thalamus- acts as relay STATION (b) Hypothalamus - Temperature control, thirst, hunger, urination, important linkbetween nervous system and endocrine system. (c) Cerebellum- MAINTENANCE of posture and balance, co-ordinate voluntary muscle ACTIVITY (d) Pons - Role in sleep - awake CYCLE |
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| 3297. |
Three equal resistances when combined in series are equivalent to 90Ω. Their equivalent resistance when combined in parallel will be |
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Answer» 270 Ω |
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| 3298. |
Choose the incorrect statement.1) We are encouraged to plant more trees so as to ensure clean environment andalso provide biomass fuel2)Gobar-gas is produced when crops, vegetablewastes etc.,decompose in the absence ofoxygen3)The main ingredient of biogas is ethane and it gives a lot of smokeand also produces a lot of residual ash4)Bio-mass is a renewable source of energy |
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Answer» We are encouraged to plant more trees so as to ensure CLEAN environment andalso provide biomass fuel The main ingredient of bio-gas is methane. It burns without smoke, leaves no residue like ash in wood, charcoal and coal burning. Bio-mass is living matter or its residues and is a renewable source of energy. Thus, part (c ) is the INCORRECT statement. |
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| 3299. |
Safe limit of receiving the radiation is about ….. |
| Answer» Solution : 250 mR per week | |
| 3300. |
The ............. are costly because, they can be used only once. |
| Answer» SOLUTION :LAUNCH VEHICLES | |