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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
When a monoatomic gas expands at constant pressure, the percentage of heat supplied that increases temperature of the gas and in doing external work in expansion at constant pressure is |
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Answer» 100%,0 |
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| 2. |
A ship is moving due east with a velocity of 12 m/sec, a truck is moving across on the ship with velocity 4 m/sec. A monkey is climbing the vertical pole mounted on the truck with a velocity of 3m/sec. Find the velocity of the monkey as observed by the man on the shore |
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Answer» 10 m/sec |
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| 3. |
An earth satellite is movewd from one stable circular orbit to another larger and stable circular orbit. The following quantities increase for the satellite a result of this change |
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Answer» gravitational potential energy `v= sqrt((GM)/(r )), a_(1) = r omega^(2)` so only option (A) is CORRECT. |
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| 4. |
A machine gun fires a bullet of mass 40 g with a velocity 1200 ms^(-1). The man holding it, can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ? |
| Answer» Answer :D | |
| 5. |
If a vector vec(A) makes anangle alpha , betaand gammawith X,Y and Z axis respectively then sin ^(2) alpha +sin^(2) beta +sin ^(2)gamma =.... |
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Answer» 0 |
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| 6. |
Same torque is applied on a solid cylinder and solid sphere with same mass and radius Cylinder rotates about its axis and sphere about its diameter. Then in a given time, the angular velocity acquired is |
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Answer» is more for sphere |
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| 7. |
Which of the following is not a scalar ? |
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Answer» Volume |
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| 8. |
1cc of water at 100°C is given 540 cal of heat and the steam formed occupies 1671cc. at 1 atm pressure. Then workdone against atmospheric pressure in this process is nearly(in Cal) |
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Answer» 540 |
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| 9. |
When a body is projected into air with certain initial velocity making an angle with the horizontal, it will travel in a parabolic path. A ball is dropped through the window of a train travelling with high velocity, to a man standing near the track. The ball------- |
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Answer» FALLS down vertically |
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| 10. |
When a body is projected into air with certain initial velocity making an angle with the horizontal, it will travel in a parabolic path . What are the vertical and horizontal components of velocity? |
| Answer» SOLUTION :`u_x=ucostheta` and `u_y=usintheta` | |
| 11. |
A particle moves on a straight line with a uniform velocity. About its angular momentum incorrect statement is |
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Answer» is ALWAYS ZERO |
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| 12. |
The following four wires are made of same material and same tensiom is applied to them . Which one will have maximum increase in length ? |
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Answer» LENGTH L =0.5 MM and diameter D = 0.5mm |
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| 13. |
a. What can you say about velocity in each of the following position-time graphs? . . . . . . . . b. The slope of the velocity-time graph is equal to acceleration. (True//False) c. What does the area under acceleration-time graph represents? d. Can velocity-time graph be parallel to the velocity axis? (Yes//No) e. What isthe slope of the v-t fraph in uniform motion? . |
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Answer» Solution : a. We KNOW that the slope of the position-time graph is equal to veloctiy. So i. as the slope is ZERO it is zero velocity. ii. As the slope is positive and constant, it is constant POSITVE velocity . iii. As the slope is infinite, it is infinite velocity. iv. as the slope is negative and constant, it is constant negative increasing velocity . vi as the slope is positive and decreasing, it is positive increasing velocity. vii. as the slope is positive and increasing, it is positive increasing velocity. viii. as the slope is positive and decteasing, it is positive decreasing veovity. b. TRUE, as `dv//dt=`acceleration. c. Chagein velocity d. No because it will indicate infinite acceleration, which is not poasible E. Zero, becoause acceleration will be zero inuniform motion. |
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| 14. |
Which of the following measurements is most precise? |
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Answer» 5.00 km |
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| 15. |
Block A of mass 1 kg is placed on the rough surface of block B of mas 3 kg. Block B is placed on smooth horizontal surface. Blocks are given the velocities as shown. Find net work done by the frictional force.[in -ve] |
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Answer» |
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| 16. |
The photograph of a house occupies an area of 1.75 cm^(2) on a 35 mm side. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m^(2). What is the linear magnification of the projector-screen arrangement. |
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Answer» Solution :AREA of object `=1.75 MC^(2)` `=1.75xx10^(-4)` Areaof image `=1.55 m^(2)` Area magnification, `m=("Area of image")/("Area of object")=("Area on screen")/("Area on SLIDE")` `m=(1.55)/(1.75xx10^(-4))` `m=0.8857xx10^(4)` LINEAR magnification `=sqrt("Areal magnification")` `=sqrt(0.8857xx10^(4))` `=0.941xx10^(2)=94.1` |
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| 17. |
A uniform spherical shell gradually shrinks maintaining its shape. The gravitational potential at the centre |
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Answer» increases |
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| 18. |
A steel wire of length 2 m and cross sectional area 2 mm^2is fixed at one end and stretched by suspending a block of mass 2 kg on the surface of the moon. If the Young's modulus of steel is 2 xx 10^11 N m^(-2)find the increase in the length of the steel wire. (g on the moon = 1/6 of the g on the earth) |
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Answer» Solution :`L= 2 m, A= 2 mm^2 = 2 XX 10^(-6) m^2`, M = 2 kg: g on the MOON =`g/6 = (9.8)/(6) ms^(-2)` `Y = 2 xx 10^11 (N)/(m^2) , e = ?` The increase in length ` e = (FL)/(AY) = (MgL)/(AY) = (2 xx 9.8 xx 2)/(6 xx 2 xx 10^(-6) xx 2 xx 10^11)` ` = 1.633 xx 10^(-5) m` |
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| 19. |
The triple points of neon and carbon dioxide are 24.57 K " and " 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales. |
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Answer» Solution :Neon : - `248.58 ^(@) C = - 415.44 ^(@) F , CO_(2) : - 56.60 ^(@) C = - 69.88 ^(@) F` `("USE " t_(F) = 9/5 t_(c) + 32)` |
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| 20. |
The loaded bucket of a craneachievers a maximum velocity 5 m//s in some time at a uniform rate and thentakes half of this time to stop at a uniform rate after the application of brake. The time differnce between the instants when half of the maximum velocity is achieved is t (sec). Find the displacement of the bucket. |
Answer»  . `a_(1)=(v_(m))/(t_(1)) rArr t_(1)=v_(m)/(a_(1))` (i) DISPLACEMENT =`(1//2) v_(m)` `(t_(1)+t_(2)//2)` But velocity `(v_(m)//2)` is observed at `C` and `D`. `CD=Delta=Delta t=1 s` (given) `C` and `D` are mid-points of `OA` and `OB` . From similar TRIANGLES, `OB =(t_(1)_t_(2)//2) =2CD =2Delta t` Displacement=`((1)/(2)) v_(m) (2 Delta t)=v_(m) Delta t =5 xx1=5 m`, |
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| 21. |
The length and breadth of a rectangle are 6.01 m and 12 m. Taking the significant figure into account the area of the rectangle is : |
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Answer» `72.00m^(2)` |
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| 22. |
A person swims at 135^(0) to currect of river, to meet target on reaching opposite point. The ratio of person.s velocity to river water velocity is |
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Answer» `sqrt(3) :1` |
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| 23. |
A passenger arriving in a new town wishes to go from the station to a hotellocated 10 km away on a straight road from the station . A dishonest cabman takes him along a circuitous path 23 km long and reaches the hotel in 28 min . Whatis (a)the average speed of the taxt , (b) the magnitude of average velocity ? Are the two equal ? |
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Answer» |
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| 24. |
Add 38.8+-0.4 and 29.7+-0.3. |
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Answer» `Deltaa_(2)=1.51-1.53=-0.02, Deltaa_(3)=1.51-1.44=+0.07,Deltaa_(4)=1.51-1.54=-0.03` `Deltaa_(5)=1.51-1.56=-0.06, Deltaa_(6)=1.51-1.46=+0.06` (iii) `BAR(Deltaa_(i))=(0.03+0.02+0.07+0.03+0.06+0.06)//6)=0.04` (iv) `bar(Delta a)//bara=0.04//1.51=0.03` (v) % error `=(bar(Deltaa)//bara)XX100%=3%` |
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| 25. |
What quantities are conserved in this collision? |
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Answer» LINEAR and angular MOMENTUM, but not KINETIC energy |
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| 26. |
The resultant of two vectors A and B is perpendicular to vector A and its magnitude is equal to half of the magnitude of vector B. Then the angle between A and B is |
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Answer» SOLUTION :Given :`theta = 90^(@) , r = (b)/(2)` Formula :`r^(2) = (a^(2) +b^(2) + 2ab cos PHI) "". . . (1)` `tan theta = (b sin phi)/(a + b cos phi)"" . . . (20` Since,`theta = 90^(@) , tan 90^(@) = infty` i.e., `a + b cos phi = 0 (or) a = - b cos phi "". . . (3)` (3) in (1) ` r^(2) = (( - b cos phi)^(2) + b^(2) + 2 (-b cos phi) b cos phi )` `= b^(2) - b^(2) cos^(2) phi` `= b^(2) (1 - cos^(2) phi)` `r^(2) = b^(2) sin^(2) phi` `sin phi = pm (r)/(b) = pm (b)/(2b) = pm (1)/(2)` `phi = 30^(@) (or) 150^(@)` `phi`cannot be`30^(@)` as, resultant MAKES an angle `90^(@) `with a . `:. a and b is 150^(@)` `:. Ans: (C)150^(@)` |
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| 27. |
A persons is spinning with his hands outstretched at th rate of 4 rad s^(-1). When he brings his hands close to the body, he spins at the rate of 16 rad s^(-1). The ratio of M.I. in the two cases susccessively is |
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Answer» `4:1` |
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| 28. |
If the length of metal rod is doubled its radius of cross section is halved, how does the coeffcient of thermal conducitivity of that rod change ? |
| Answer» SOLUTION :REMAINS UNCHANGED. The value of K depends only on nature of MATERIAL. | |
| 29. |
A 1 kg ball is rotated in a vertical circle by using a string of length 0.1 m. If the tension in the string at the lowest point is 29.4N, its angular velocity at that position is |
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Answer» `7 "rads"^(-1)` |
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| 30. |
State newton's second law |
| Answer» SOLUTION :The FORCE acting on an object is EQUAL to the rate of CHANGE of its momentum ` vecF = (d vecp)/(dt)` | |
| 31. |
Two moles of hydrogen is heated through 10kunder constant pressure. If R = 83 J/mole K the external work done in Joule is |
| Answer» ANSWER :D | |
| 32. |
Express 1 light year in terms of metre. |
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Answer» `0.946 xx10^(-16) m` |
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| 33. |
A person weighing 60 kg in a small boat of mass 140 kg which is at rest, throws a 5 kg stone in the horizontal direction with a velocity of 14 ms^(-1). The velocity of the boat immediately after the throw is ( in m//s) |
| Answer» Solution :`m_(1)u_(1)+m_(2)u_(2)=m_(1)v_(1)+m_(2)v_(2)` | |
| 34. |
Draw force - displacement graph for a spring and find an expression for the potential energy of an elastic spring. |
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Answer» Solution :(i) According to Hooke's law the restoring spring force and displacement are linearly related as `F=-k x`, and are opposite in direction, the graph between F and x is a straight LINE with dwelling only in the second and fourth quadrant as shown in Figure. (ii) The ELASTIC potential ENERGY can be easily calculated by drawing a F - x graph. The shaded area (triangle) is the work done by the spring force. (III) Area (base) (height) `=(1)/(2)xx (x)xx (kx)`. `=(1)/(2)kx^(2)`  (iv) Work done is stored as the potential energy of the spring. `therefore U = (1)/(2) kx^(2)` |
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| 35. |
Aliquid is flowing through a narrow tube. The coefficient of viscosity of liquid is 0.1308 poise. The length and inner radius of tube are 50 cm and I mm respectively. The rate of flow of liquid is 36 min. Find the pressure difference between ends of tube. |
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Answer» `10^(6) "DYNE"//cm^(2)` |
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| 36. |
A man in a lift feels an apparent weight W when the lift is moving up with a uniform acceleration of 1/3 rd of the acceleration due to gravity. If the same man were in the same lift now moving down with a uniform acceleration that is 1/2 of the acceleration due to gravity, then his apparent weight is |
| Answer» Answer :A | |
| 37. |
A uniform chain of length 2 m is kept on a table such that a length of 60 cm hangs freely from the edge of the tale. The total mass of the chain is 4 kg. What is the work done in pulling the entire chain on to the tabl? (g=10m//s^(2)) |
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Answer» 7.2J |
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| 38. |
Which of the following laws of thermodynamics forms the basis for the definition of temperature? |
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Answer» FIRST law |
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| 39. |
The principle of 'parallax' in section 2.3.1 is used in the determination of distances of very distant starts. The baseline AB is the line joining the Earth's two locations six months apart in its orbit around the Sun. That is, the baseline is about the diameter of the Earth's orbit =3xx10^(11)m. However, even the nearest stars are so distant that with such a long baseline, they show parallax only of the order of 1" (second) of arc or so. A parsec is a conventent unit of length on the astronomical scale. It is the distance of an object that will show a parallax of 1" (second of arc) fromopposite ends of a baseline equal to the distance from the Earth to the Sun. How much is a parsecin terms of metres ? |
| Answer» Solution :`~= 3XX10^(16)`m, as a UNIT of LENGTH 1 phrase is defined to be equal to `3.084xx10^(16)`m. | |
| 40. |
Rain drops are falling vertically down wards at5sqrt(2) m/s. A man runs horizontally in the rain at 5sqrt(2). The magnitude and direction of relative velocity of the rain drops with respect to the person is |
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Answer» `5 m//s , 45^(@)` with vertical |
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| 41. |
6 gm of steam at 100^(@)C is mixed with 6 gm of ice at 0^(@)C.The mass of steam left uncondensed is |
| Answer» Answer :B | |
| 42. |
A steel cable with a radius of 1.5 cm supports a chairlift at a ski area. If the maximum stress is not to exceed 10^(8)" N m"^(-2), what is the maximum load the cable can support ? |
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Answer» |
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| 43. |
A ball is hanging vertically by a light inextensible string of length L from fixed point O. The ball of mass m is given a speed u at the lowest position such that it completes a vertical circle with centre at O as shown. Let AB be a diameter of circular path of ball making an angle theta with vertical as shown. (g is acceleration due to gravity) a) Let T_A and T_B be tension in string when ball is at A and B respectively, then find T_A – T_B.(b) Let vec(a)_(A) and vec(a)_(B) be acceleration of ball when it is at A and B respectively, then find the value of |vec(a)_(A)+vec(a)_(B)| |
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Answer» `(B) gsqrt(4+12 cos^(2) theta)` |
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| 44. |
An ideal gas hea engine operates in a Carnot cycle between 227^(@)C and 127^(@)C. It absorbs 6 kcal of heat at higher temperature. The amount of heat in kcal rejected to sink is |
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Answer» 4.8 `T_(2) = 127^(@)C = 127 + 273 = 400 K, Q_(1) = 6 KCAL` As `(Q_(2))/(Q_(1)) = (T_(2))/(T_(1)) :. (Q_(2)) = (T_(2))/(T_(1))Q_(1) = (400 K)/(500 K) XX 6 kcal = 4.8 kcal` |
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| 45. |
Which of the following example does not constitute a couple? |
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Answer» STEERING a car |
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| 46. |
An aluminium wire 1 m in length and radius 1 mm is loaded with a mass of 40 kg hanging vertically. Young’s modulus of Al is 7.0 xx 10^(10) N//m^(2). Calculate (a) tensile stress (b) change in length (c) tensile strain and (d) the force constant of such a wire. |
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Answer» Solution :(a) Stress = `(F)/(A)=(mg)/(PIR^(2))=(40xx10)/(pixx(1xx10^(-3))^(2))=1.27xx10^(8)N/m^(2)` (b) `DeltaL=(FL)/(AY)=(40xx10xx1)/(pixx(1xx10^(-3))^(2)xx7xx10^(10))=1.8xx10^(-3)` m (c) Strain `=(DeltaL)/(L)=(1.8xx10^(-3))/(1)=1.8xx10^(-3)` (d) F=Kx=K`Delta`L,K = Force CONSTANT `K=(DeltaF)/(L)=(40xx10)/(1.8xx10^(-3)=2.2xx10^(5)N/m` |
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| 47. |
Out of the following the most plastic material is |
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Answer» Â iron |
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| 48. |
If a particle is moving on an parallel path given by r=b cos omegat hati+asinomegat hatj, then find its radial acceleration along r |
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Answer» `omega r` `(d^(2)r)/(dt^(2))=-BOMEGA^(2) sin omegat hati+aomega^(2) cos omegat hatj` `(d^(2)r)/(dt^(2))=-omega^(2) [b cos omegat hati+a sin omegat hatj]=-omega^(2)r` |
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| 49. |
The volume of a mass of gas at 37^(@)C and a pressure of 75 cm of mercury is 620 c.c. Find the volume at N.T.P. |
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Answer» 5000 CC |
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