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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36801. |
Tube A has both ends open, while tube B has one end closed , otherwise they are indentical. The raito of fundamental ferquency of tubes A & B is |
| Answer» <html><body><p>1:2<br/>1:4<br/>2:1<br/>4:1</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36802. |
State and explain Wien's displacement law. |
| Answer» <html><body><p></p>Solution :Thermal radiation <a href="https://interviewquestions.tuteehub.com/tag/emitted-7679123" style="font-weight:bold;" target="_blank" title="Click to know more about EMITTED">EMITTED</a> by a body consists of electromagnetic waves of different wavelengths and wavelengths of these waves <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> a continuous spectrum, but amount of electromagnetic waves of certain definite frequencies is more. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C11_E01_045_S01.png" width="80%"/> <br/> For example, in black radiation at room temperature (300 K) majority of the radiation consists of electromagnetic waves of wavelength `95,500" A"^(@)` (called infrared waves). <br/> On increasing its temperature, the amount of waves of smaller wavelength increases. <br/> At about 1100 K, as the waves of wavelength corresponding to red colour is more, the body appears red. <br/> Figure shows the graph of spectral emissive power `W_(lamda)` versus wavelengths `(lamda_(m))` at different temperatures. <br/> From the graph it is clear that with increase in temperature, wavelength `(lamda_(m))` corresponding to the maximum value of `W_(lamda)` decreases. <br/> Wien.s displacement law : ..The wavelength `(lamda_(m))` of a emitted radiation from the surface of any body is <a href="https://interviewquestions.tuteehub.com/tag/inversely-7688775" style="font-weight:bold;" target="_blank" title="Click to know more about INVERSELY">INVERSELY</a> <a href="https://interviewquestions.tuteehub.com/tag/proportional-1170279" style="font-weight:bold;" target="_blank" title="Click to know more about PROPORTIONAL">PROPORTIONAL</a> to the <a href="https://interviewquestions.tuteehub.com/tag/absolute-11456" style="font-weight:bold;" target="_blank" title="Click to know more about ABSOLUTE">ABSOLUTE</a> temperature of the emitting surface... <br/> `:." "lamda_(m)T=` constant <br/> The above equation is called the Wien.s displacement law. <br/> The constant in above equation is called Wien.s constant and its value is `2.9xx10^(-3)" mK"` <br/> Remember : Here `lamda_(m)` is not maximum wavelength but radiation energy is maximum Value of Wien.s constant is `2.9xx10^(-3)" mK"` and 0.290 cm K in CGS system and dimensional formula is `[M^(0)L^(1)T^(0)K^(1)]`. <br/> This rule explains that by heating iron piece why it becomes first reddish, then greenish yellow and white at last. <br/> Wien.s law is useful to estimate temperature of surface of space objects like Sun, Moon and Star. <br/> Intensity of light is maximum for `14mum` wavelength from Moon and temperature of Moon is approximated as 200 K is as below, <br/> Here, `lamda_(m)=14mum=14xx10^(-6)m` <br/> Now from Wien.s law, <br/> `lamda_(m)T=` constant <br/> `:." T = "("constant")/(lamda_(m))=(2.9xx10^(-3))/(14xx10^(-6))` <br/> `T=207K` <br/> `:.T~~200K` <br/> Intensity of light is maximum for `lamda_(m)=4753Å` wavelength from Sun. Hence,according to Wien.s law, <br/> `lamda_(m)" T = constant"` <br/> `:.T=("constant")/(lamda_(m))` <br/> `:.T=(2.9xx10^(-3))/(4753xx10^(-10))` <br/> `=0.00061014xx10^(7)` <br/> `~~6101K` <br/> `~~6060` K (Value of textbook) <br/> This is temperature of surface of Sun not of inner side. <br/> The meaningful of surface of Sun not of inner side. <br/> The meaningful characteristic of curves of radiation from black body is they at universal and only depends on temperature but not on dimension, shape or matter.</body></html> | |
| 36803. |
Springs are usually made of steel but not of copper why? |
| Answer» <html><body><p></p>Solution :Elasticity of steel is more than that of coppper. It means that the elastic limit of limit is <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a>. Let us consider two springs of the same size, one of steel and another of copper.An equal <a href="https://interviewquestions.tuteehub.com/tag/tensile-1241684" style="font-weight:bold;" target="_blank" title="Click to know more about TENSILE">TENSILE</a> force is applied on both springs. On slowly increasing the magnitude of the applied force on the two springs it seen that,at a certain stage the steel spring still behaves like an elastic body but the copper spring undergoes a permanent <a href="https://interviewquestions.tuteehub.com/tag/deformation-947276" style="font-weight:bold;" target="_blank" title="Click to know more about DEFORMATION">DEFORMATION</a> . For this reason, springs are usually made of steel but not of copper. More-over , copper is <a href="https://interviewquestions.tuteehub.com/tag/costlier-2037861" style="font-weight:bold;" target="_blank" title="Click to know more about COSTLIER">COSTLIER</a> than steel. However, copper springs <a href="https://interviewquestions.tuteehub.com/tag/may-557248" style="font-weight:bold;" target="_blank" title="Click to know more about MAY">MAY</a> be used where the applied force is not very high.</body></html> | |
| 36804. |
A person of mass 60 kg wants to lose 5 kg by goingup and down a 10 m high stairs. Assume he burns twice as much fat while going up than coming down. If 1 kg of fat is burnt on expending 7000 kilocalories, how many times must he go up and down to reduce his weight by 5 kg? Work done in moving up = mgh Work done in moving down =(mgh)/(2) Total work done =(3)/(2) mgh = (3)/(2) xx 60xx 10xx10 N number of trips |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`5xx7000 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) xx4.2J = 60xx15 xx 10 xx N` <br/> `N =(21xx 7xx10^(6))/( 9000)= (147)/(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)xx 10^(3) =16.3 xx 10^(3)` times</body></html> | |
| 36805. |
If stress is numerically equal to young's modulus the elongation will be |
| Answer» <html><body><p>1/4 the <a href="https://interviewquestions.tuteehub.com/tag/original-1139424" style="font-weight:bold;" target="_blank" title="Click to know more about ORIGINAL">ORIGINAL</a> <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a><br/>1/2 the original length<br/> <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the original length<br/>Twice the original length </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36806. |
A disc of mass 5 kg is kept floatinghorizontally in mid air by firing 10 bullets per second vertically up. If the mass of each bullet is 50 gm and bullets rebound with same speed, the speed of each bullet is, (g = 10 ms^(-2)) |
| Answer» <html><body><p> `100 ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a> ms^(-1)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> ms^(-1)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 36807. |
A circular disc is rotating about its natural axis with angular velocity of 10 rads^(-1). A second disc of same mass is joined to it coaxially. If the radius of disc is half of the radius of the first, then they together rotate with an angular velocity of |
| Answer» <html><body><p>`2.<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> rads^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`5 rads^(-1)`<br/>`8 rads^(-1)`<br/>`6 rads^(-1)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 36808. |
Mention the dimensional formula of spring constant . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`M^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)T^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`</body></html> | |
| 36809. |
A 100cm long stretched string is struck at a point 25 cm from one of its ends. Which of the overtones would be absent in the emitted notes ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :Atthe striking point, an amtinode would be formed. So, the overtones having a node at the point of 25 cm would not be formed . As 25 cm` = (100 cm)/(4) = (l)/(4) `( l = length of the <a href="https://interviewquestions.tuteehub.com/tag/stretched-7711564" style="font-weight:bold;" target="_blank" title="Click to know more about STRETCHED">STRETCHED</a> string,) the absent overtones would be the <a href="https://interviewquestions.tuteehub.com/tag/4th-319068" style="font-weight:bold;" target="_blank" title="Click to know more about 4TH">4TH</a> , 8th , <a href="https://interviewquestions.tuteehub.com/tag/12th-12928" style="font-weight:bold;" target="_blank" title="Click to know more about 12TH">12TH</a> , ..... harmonics .</body></html> | |
| 36810. |
For a particle acceleration is defined as veca=(-5xhati)/(|xx|) for X ne 0 "and" veca =0 "for" X=0. If the particle is initially at rest (a,0) what is period of of motion of the particle. |
| Answer» <html><body><p>`4sqrt(2a//5)<a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>.`<br/>`8sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(a//5))sec.`<br/>`2sqrt(2a//5) sec.`<br/>cannot be <a href="https://interviewquestions.tuteehub.com/tag/determined-949906" style="font-weight:bold;" target="_blank" title="Click to know more about DETERMINED">DETERMINED</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a></body></html> | |
| 36811. |
Consider a simple pendulum, having a bob attached to a string , that oscillates under the action of the force of gravity. Suppose that the period of oscillation of the simple. Pendulum depends on its length ( l) , mass of the bob ( m ) , and acceleration due to gravity ( g ) . Derive theexpression for is time period using method of dimension . |
| Answer» <html><body><p></p>Solution :(i) Let `theta` be the angle made by the string with vertical. When the bob is at the mean position `theta=0.`<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C10_E15_008_S01.png" width="80%"/><br/> (ii) There are two forces acting on the bob. The tension T along the vertical force due to gravity (=mg).<br/> (iii) The force can be resolved into `mgcostheta` along a circle of <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> L and centre at this support point. <br/> (iv) Its radial <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> `(omega^(2)L)` and also tangential acceleration. So net radial force `= T - mg costheta` , While the tangential acceleration provided by `mg sintheta`the radial force gives zero torque. <br/> (v) So torque providedby the tangential component. <br/> `tau="Lmg"sintheta` <br/> `tau=Ialpha` (by Newton's law of rotational motion) <br/> `Ialpha=mgsinthetaL` <br/> `alphaimplies("mgL")/(I)sintheta` <br/> where I is the <a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a> of inertia , `alpha` is angular acceleration, <br/> (<a href="https://interviewquestions.tuteehub.com/tag/vi-723586" style="font-weight:bold;" target="_blank" title="Click to know more about VI">VI</a>) The `theta` is to small, <br/> `sintheta=theta` <br/> `alpha=(mgL)/(I)theta,omega=sqrt((I)/(mgL))`<br/> [for simple <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a> `a(t) =-omega^(2)txxtheta" is small ]"and T=2pisqrt((I)/(mgL))""[:'omega=(2pi)/(T)]`</body></html> | |
| 36812. |
The equation of a wave is y = 0.1 sin (100 pi t - kx) where x , y are in metres and t in seconds . If the velocity of the wave is 100 m/s , then the value of k is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> m^(-1)`<br/>`2 m^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> m^(-1)`<br/>`2 pi m^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`v = (omega)/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>) implies k = (omega)/(v) = (100 pi)/(100) = pi m^(-1)`</body></html> | |
| 36813. |
Pieces of glass and copper are heated to the same temperature. Why does the piece of copper feel hotter on touching? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/copper-933790" style="font-weight:bold;" target="_blank" title="Click to know more about COPPER">COPPER</a> is a good conductor of heat whereas glass is a bad conductor. So when copper is touched heat <a href="https://interviewquestions.tuteehub.com/tag/flows-993448" style="font-weight:bold;" target="_blank" title="Click to know more about FLOWS">FLOWS</a> from copper to the hand quickly. But heat conduction from glass to <a href="https://interviewquestions.tuteehub.com/tag/human-1032714" style="font-weight:bold;" target="_blank" title="Click to know more about HUMAN">HUMAN</a> <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> is slow. So the piece of copper feels hotter.</body></html> | |
| 36814. |
A heavy steel ball of mass greater than 1kg moving with a speed of 2 m/s collides head on with a stationary ping-pong ball of mass less than 0.1 gm. The collision is elactic. After the collision the ping pong ball moves approximately with speed of |
| Answer» <html><body><p>2 m/s<br/><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> m/s<br/>`2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(4)` m/s<br/>`2 xx 10^(3)` m/s</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36815. |
Three equal masses of m kg each are fixed at the vetrices of an equilateral triangle ABC (a) What is the force acting on a mass 2m placed at the centriod G of the triangle. (b) What is the force if the mass at the vertex A is doubled ? Take AG = BG = 1m |
| Answer» <html><body><p></p>Solution :The individual forces in vector notation are <br/> `F_(GA)=(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>(m)(<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>))/1hatj` <br/> `F_(GB)=(G(m)(2m))/1 (-hat1 cos 30^@- hatj <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> 30^@)` <br/> `F_(GC)=(G(m)(2m))/1 (hat1 cos 30^@ -hatj sin 30^@)` <br/> From the principle of superposition and the law of vector addition the resultant gravitational force `F_R` on(2m) is <br/> `F_R=F_(GA)+F_(GB)+F_(GC)` <br/> `F_R=2Gm^2hatj + 2Gm^2 (-hati cos 30^@ - hatj sin 30^@) + 2Gm^2 (hati cos 30^@ - hatj sin 30^@) =0` <br/> (b) By symmetry, the X-component of the force cancels out. The Y-component survives. <br/> `therefore F_R=4Gm^2 hatj - 2Gm^2 hatj =2Gm^2 hatj`</body></html> | |
| 36816. |
The mean free path of gas molecules varies with the diameter d of the molecules as |
| Answer» <html><body><p>`d^-1`<br/>`d^-2`<br/>`d^2`<br/>`d^-3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::D</body></html> | |
| 36817. |
Two mettalic strips each of length l_(0) and thickness d, temperature T_(0) are riveted together so that their ends coincide. One strip is maxe of a metal of coeficient of expansioin alpha_(1) and the other of a metal with a coefficient alpha_(2), where alpha_(2)gtalpha_(1). When this bimetallic strip is heated to a temperature T_(0)+DeltaT, find the radius of curvature R of the strip. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a></body></html> | |
| 36818. |
An ant moves on the floor of a room making two displacement. One of magnitude 3m and another of magnitude 4m. If the angle between the two displacements is 120^(@) what will be the magnitude of the resultant displacement ? |
| Answer» <html><body><p>6.082m<br/>5.2m<br/>4.8m<br/>3.606m</p>Answer :D</body></html> | |
| 36819. |
State Archimedes principle. |
| Answer» <html><body><p></p>Solution :When a <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> is partially or wholly <a href="https://interviewquestions.tuteehub.com/tag/immersed-1037461" style="font-weight:bold;" target="_blank" title="Click to know more about IMMERSED">IMMERSED</a> in a fluid, it experiences an upward thrust equal to the weight of the fluid displaced by it and its upthrust acts through the <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> of gravity of the liquid displaced. <br/> Upthrust or <a href="https://interviewquestions.tuteehub.com/tag/buoyant-391416" style="font-weight:bold;" target="_blank" title="Click to know more about BUOYANT">BUOYANT</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> = weight of liquid displaced.</body></html> | |
| 36820. |
A system is taken along different path in the graph of Pto V from its initial state to final state. Which of following quantity does not depend on the path of the system ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/exchange-454713" style="font-weight:bold;" target="_blank" title="Click to know more about EXCHANGE">EXCHANGE</a> of <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> Q<br/>Work done <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a><br/>Depend on Q but not on W<br/>(Q - W)</p>Answer :D</body></html> | |
| 36821. |
Two satellites of masses 100kg and 200kg are revolving the earth at attitudes 6400 km and 44800km. The ratio of orbital velocity of the satellites is: |
| Answer» <html><body><p>`1:2`<br/>`2:1`<br/>`1:4`<br/>`4:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36822. |
The average kinetic energy associated with the x component of the motion of a molecule is |
| Answer» <html><body><p>`(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)k_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)T`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(2)k_(B)T`<br/>`k_(B)T`<br/>`(2)/(3)k_(B)T`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36823. |
Draw and explain thevariations of force of friction vs applied force graphically |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/thevariation-1412876" style="font-weight:bold;" target="_blank" title="Click to know more about THEVARIATION">THEVARIATION</a> of bothstaticand kineticfrictionalforces with exertnalappliedforceis graphicallyshown in the <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a><br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E02_144_S01.png" width="80%"/></body></html> | |
| 36824. |
A solid metal sphere and a solid wooden sphere are having the same mass. If they are spinning with same angular velocity, then |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> sphere <a href="https://interviewquestions.tuteehub.com/tag/possesses-1160374" style="font-weight:bold;" target="_blank" title="Click to know more about POSSESSES">POSSESSES</a> more <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> momentum <br/>wooden sphere will have more angular momentum <br/>both will have same angular momentum <br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of the above </p>Answer :B</body></html> | |
| 36825. |
A thin equiconvex lens is made of glass of refrative index 1.5 and its focal length is 0.2m. If it acts as a concove lens of 0.5m focal length when dipped in a liquid, the refractive index of liquid is |
| Answer» <html><body><p>`17//8`<br/>`15//8`<br/>`13//8`<br/>`9//8`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36826. |
If the distance between the centres of the atoms of potassium and bromine in KBr molecule is 0.282 xx 10^(-9) m, the centre of mass of this two particle system from potassium is (mass of bromine = 80 u and of potassium = 39 u). |
| Answer» <html><body><p>`9.3xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a>`<br/>`18.96 xx10^(-2)nm`<br/>`27.9xx10^(-2)nm`<br/>`3.3xx10^(-2)nm`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36827. |
A column of Hg of 10 cm length is contained in the middle of a narrow horizontal 1 m long tube which is closed at both ends. Both the halves of the tube contain air at a pressure 76 cm of Hg. By what distance will the column of Hg be displaced if the tube is held vertical? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a></body></html> | |
| 36828. |
A uniform tube of length 60 cm stands vertically with its lower end dipping into water . First two air column lengths above water are 15 cm, when the tube resonds to a vibrating fork of frequency 500 H_(Z) . Find the lowest frequency to the tube will respond when it is open at both ends. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(lambda)/(2) = (45 - 15) cm` <br/> `:. lambda = <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> cm` <br/> `nu = f lambda = (500) (0.6)` <br/> `= <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> m//s` <br/> Lowest frequency when <a href="https://interviewquestions.tuteehub.com/tag/open-586655" style="font-weight:bold;" target="_blank" title="Click to know more about OPEN">OPEN</a> from both ends is `(nu)/(<a href="https://interviewquestions.tuteehub.com/tag/2l-300409" style="font-weight:bold;" target="_blank" title="Click to know more about 2L">2L</a>)` . <br/> `= (300)/(2 xx0.6) = 250 H_(Z)`</body></html> | |
| 36829. |
A solid sphere of radius R is resting on a smooth horizontal surface. A constant force F is applied at a height h from the bottom. Vhoose the correct alternative. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/sphere-1222094" style="font-weight:bold;" target="_blank" title="Click to know more about SPHERE">SPHERE</a> will <a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a> slide whatever be the <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> of h<br/>Sphere will roll without sliding when `hge104R`<br/>Sphere will roll without sliding if h=1.4R<br/>None of the above</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36830. |
The weight of liquid column in a capillary tube is 11xx10^(-4)N. If the radius of tube is 7 mm, calculate the surface tension of liquid. |
| Answer» <html><body><p></p>Solution :Weight of liquid column `W=11xx10^(-4)N` <br/> Radius of <a href="https://interviewquestions.tuteehub.com/tag/capillary-908628" style="font-weight:bold;" target="_blank" title="Click to know more about CAPILLARY">CAPILLARY</a> <a href="https://interviewquestions.tuteehub.com/tag/tube-1428592" style="font-weight:bold;" target="_blank" title="Click to know more about TUBE">TUBE</a> `r=7mm=7xx10^(-3)m` <br/> Weight of liquid column `W=2pirS` <br/> Surface tension <br/> `S=(W)/(2pir)=(11xx10^(-4))/(2xx(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)xx7xx10^(-3))impliesS=0.025N//m`</body></html> | |
| 36831. |
A particle is projected at 60^(@) to the horizontal with a kinetic energy K. The kinetic energy at the highest point is: |
| Answer» <html><body><p>K<br/>Zero<br/>K/4<br/>K/2</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36832. |
Bernoulli's theorem is applicable to …………….. . |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/flow-993213" style="font-weight:bold;" target="_blank" title="Click to know more about FLOW">FLOW</a> of liquids <br/>viscosity <br/>surface <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> <br/>static <a href="https://interviewquestions.tuteehub.com/tag/fluid-993483" style="font-weight:bold;" target="_blank" title="Click to know more about FLUID">FLUID</a> pressure </p>Answer :A</body></html> | |
| 36833. |
What is displacement? Explain its general meaning by giving examples. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Displacement : The distance of the oscillator (simple harmonic body means oscillator) at any instant from the equilibrium (fixed or reference point) position is called displacement of the oscillator at that instant. <br/> The displacement is considered positive from one side of equilibrium point and negative from other side. In short, displacement prossess zero, positive and negative values. <br/> Displacement is refers to change with time of any physical property under consideration. Its examples are as follow : <br/> (1) In case of rectilinear motion of a steel ball on a surface, the distance from the starting point as a function of time is its position displacement. The choice of origin is a matter of convenience. <br/> (2) <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C14_E01_010_S01.png" width="80%"/> <br/> Consider a block attached to a spring, the other end of which is fixed to a rigid wall, as shown in figure (a). The block moves on a <a href="https://interviewquestions.tuteehub.com/tag/frictionless-1000488" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTIONLESS">FRICTIONLESS</a> surface. <br/> The motion of the block can be described in terms of its distance or displacement x from the wall. <br/> (3) In figure (b), an <a href="https://interviewquestions.tuteehub.com/tag/oscillating-2900383" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATING">OSCILLATING</a> simple pendulum. its motion can be described in terms of angular displacement `theta` from the vertical. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C14_E01_010_S02.png" width="80%"/> <br/> For an oscillating simple pendulum, the angle from the vertical as a function of time may be regarded as a displacement variable. <br/> (4) The displacement variable may be taken in pressure variations with time in the propagation of sound <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> in air. <br/> (5) The displacement variable may also take in the changing electric and magnetic fields in a <a href="https://interviewquestions.tuteehub.com/tag/electromagnetic-968633" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTROMAGNETIC">ELECTROMAGNETIC</a> waves. <br/> (6) The voltage across a capacitor, changing with time in an a.c. circuit is also a displacement variable. <br/> Hence, it is not so that the displacement variable always taken as in the context of position but above shown displacement variable may be taken.</body></html> | |
| 36834. |
Define Chandraskhar limit. |
| Answer» <html><body><p></p>Solution :It is the largest possible <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> of mass of a <a href="https://interviewquestions.tuteehub.com/tag/white-742716" style="font-weight:bold;" target="_blank" title="Click to know more about WHITE">WHITE</a> dwarf <a href="https://interviewquestions.tuteehub.com/tag/star-1224588" style="font-weight:bold;" target="_blank" title="Click to know more about STAR">STAR</a> which is equal to <a href="https://interviewquestions.tuteehub.com/tag/nearly-1112451" style="font-weight:bold;" target="_blank" title="Click to know more about NEARLY">NEARLY</a> 1.4 times the mass of the sun.</body></html> | |
| 36835. |
Is friction , a conservative or non-conservative force ? |
| Answer» <html><body><p></p>Solution :Non-conservative force. Friction <a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a> <a href="https://interviewquestions.tuteehub.com/tag/opposes-7701987" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSES">OPPOSES</a> the relative <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a>. So the net <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done during <a href="https://interviewquestions.tuteehub.com/tag/forward-464460" style="font-weight:bold;" target="_blank" title="Click to know more about FORWARD">FORWARD</a> and backward motion is zero.</body></html> | |
| 36836. |
Find the torque of a force vecF = 7hati +3hatj -5hatk about the point whose position vector is vecr = hati - hatj + hatk. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`2hati + 12hatj + <a href="https://interviewquestions.tuteehub.com/tag/10hatk-1774400" style="font-weight:bold;" target="_blank" title="Click to know more about 10HATK">10HATK</a>`</body></html> | |
| 36837. |
A pipe 20 cm long is closed at one end. Which harmonic mode of the pipe is resonantly excited by a 430 Hz source ? Will the same source be in resonane with the pipe if both end are open ? (speed of sound in air is 340 m s^(-1)). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a> (<a href="https://interviewquestions.tuteehub.com/tag/fundamental-466867" style="font-weight:bold;" target="_blank" title="Click to know more about FUNDAMENTAL">FUNDAMENTAL</a>), No</body></html> | |
| 36838. |
A swimmer's speed in the direction of flow of a river is 12kmh^(-1). Against the direction of flow of the river the swimmer's speed is 6kmh^(-1). Calculate the swimmer's speed in still water and the velocity of the river flow. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let `v_(s)andv_(r)` represent the <a href="https://interviewquestions.tuteehub.com/tag/velocities-1444510" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITIES">VELOCITIES</a> of the swimmer and river respectively with respect to ground. <br/> `v_(s)+v_(r)=12""…..(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> and `v_(s)-v_(r)=6""…..(2)` <br/> Adding the both <a href="https://interviewquestions.tuteehub.com/tag/equations-452536" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATIONS">EQUATIONS</a>(1) and (2) `2v_(s)=12+6=18kmh^(-1)orv_(s)=9kmh^(-1)`. From <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> (1), <br/> `9+v_(r)=12orv_(r)=3kmh^(-1)` <br/> When the river flow and swimmer move in the same direction, the net velocity of swimmer is 12 kmph.</body></html> | |
| 36839. |
A thermally insulated vertical cylinder of cross - section area A contains 3moles of an ideal monatomicgas under a piston of mass M. A heater supplying heat to the gas at constant rate PJ/s, is switched on at t = 0. The velocity of the piston is given by [Take atmospheric pressure as P_0] |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`(2P)/(5p_0A + <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>])` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/3p-311052" style="font-weight:bold;" target="_blank" title="Click to know more about 3P">3P</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>[p_0A + Mg])`<br/>`(3P)/(2[p_0A + Mg])` <br/>`(P)/(p_0A + Mg)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36840. |
In Exercise 9, let us take theposition of mass when the spring is unstretched as x=0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t=0), the mass is at the maximum compressed position. In what way to these functions for SHM differ from each other, in frequency, in amplitude or the initial phase? |
| Answer» <html><body><p></p>Solution :Amplitude from exercise : `14.9, A = 2 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>` <br/> Angular frequency `omega = sqrt((k)/(m)) = sqrt((1200)/(3)) = sqrt(400) = <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> s^(-1)` <br/> Initial phase inthe maximum compressed position `phi = (3pi)/(2) rad` <br/> Displacement of block at time t `x(t) = A <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> (omega t+phi)` <br/> ` = 2sin (2omega t+(3pi)/(2))= -2cos 20 t cm`. <br/> Hence, in all these three <a href="https://interviewquestions.tuteehub.com/tag/cases-910165" style="font-weight:bold;" target="_blank" title="Click to know more about CASES">CASES</a>, amplitude and frequency are same but differ only in initial phase because motions starts from different positions.</body></html> | |
| 36841. |
Explain why it is sometimes safer for a ship while floating on water to load more goods than to get rid of them. |
| Answer» <html><body><p></p>Solution :For stable <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> of a floating body, its centre of gravity should lie below its metacentre. So, if the metacentre <a href="https://interviewquestions.tuteehub.com/tag/lies-1073086" style="font-weight:bold;" target="_blank" title="Click to know more about LIES">LIES</a> below the centre of gravity of a floating <a href="https://interviewquestions.tuteehub.com/tag/ship-1205430" style="font-weight:bold;" target="_blank" title="Click to know more about SHIP">SHIP</a>, then, to <a href="https://interviewquestions.tuteehub.com/tag/lower-1080637" style="font-weight:bold;" target="_blank" title="Click to know more about LOWER">LOWER</a> the position of its centre of gravity below the metacentre, more <a href="https://interviewquestions.tuteehub.com/tag/goods-1009877" style="font-weight:bold;" target="_blank" title="Click to know more about GOODS">GOODS</a> should be loaded in the hold of the ship. In that case, the ship will float under stable equilibrium and hence it is safer for a ship floating on water to be loaded with more goods.</body></html> | |
| 36842. |
The dimensions of (mu_(0)epsi_(0))^((1)/(2)) are |
| Answer» <html><body><p>`[<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)T]`<br/>`[LT^(-1)]`<br/>`[L^((1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))T^(-(1)/(2))]`<br/>`[L^((1)/(2)) T^(-(1)/(2))]`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36843. |
Tabulate , the displacement , velocity and acceleration is SHM. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C10_E14_002_S01.png" width="80%"/></body></html> | |
| 36844. |
Does the damping force remain constant on a system executing shm? |
| Answer» <html><body><p></p>Solution :No. It <a href="https://interviewquestions.tuteehub.com/tag/varies-1443299" style="font-weight:bold;" target="_blank" title="Click to know more about VARIES">VARIES</a> with <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of the oscillator. Damping <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> is maximum when the velocity is <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> and vice versa.</body></html> | |
| 36845. |
The reasons for phenomenal progress of physics in the last few centuries is/are |
| Answer» <html><body><p> The realization that not only qualitative <a href="https://interviewquestions.tuteehub.com/tag/thinking-1414302" style="font-weight:bold;" target="_blank" title="Click to know more about THINKING">THINKING</a> but quantitative measurement is of primeimportance<br/>Observations through complicated manifestation of daily life phenomenon as consequence<br/>But understanding them focusing on essential features to more <a href="https://interviewquestions.tuteehub.com/tag/realistic-2245795" style="font-weight:bold;" target="_blank" title="Click to know more about REALISTIC">REALISTIC</a> situations <br/><a href="https://interviewquestions.tuteehub.com/tag/observed-582965" style="font-weight:bold;" target="_blank" title="Click to know more about OBSERVED">OBSERVED</a> complicated situations translated into mathematical equations. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36846. |
The mass of a unifprm rod is 0.4 kg and its length is 2 m. .Calculate the radius of gyration of the rod about an axis passing through its centre of mass and perpendicular to its length ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/mk-548207" style="font-weight:bold;" target="_blank" title="Click to know more about MK">MK</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = Ml^(2)//<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>, K = l//sqrt(12) = 2sqrt(12) = 0.58 m`</body></html> | |
| 36847. |
In Exercise 9, let us take theposition of mass when the spring is unstretched as x=0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t=0), the mass is at the maximum streatched position. |
| Answer» <html><body><p></p>Solution :Amplitude from exercise : `14.9, A = 2 cm` <br/> <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> frequency `omega = sqrt((k)/(m)) = sqrt((1200)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)) = sqrt(400) = 20 rad s^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> Phase in the maximum stretched position `phi =(pi)/(2)rad` <br/> Displacement of block at time t <br/> `x(t) =A sin (omega t+phi)` putting thevalue ` = <a href="https://interviewquestions.tuteehub.com/tag/2sin-301148" style="font-weight:bold;" target="_blank" title="Click to know more about 2SIN">2SIN</a> (2omega t+(pi)/(2))= 2 cos 20 t cm`.</body></html> | |
| 36848. |
In Exercise 9, let us take theposition of mass when the spring is unstretched as x=0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t=0), the mass is at the mean position. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Amplitude from exercise : `14.9, A = 2 cm` <br/> Angular frequency `omega = sqrt((k)/(m)) = sqrt((1200)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)) = sqrt(400) = 20 <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> s^(-1)` <br/> Initial <a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a> at mean position `phi = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>` <br/> Displacement of block at time t <br/> `x(t) = A sin(omega t+phi)` putting the abovevalues <br/> `= 2 sin(2 omega t +0)` <br/> ` =2 sin 20 t cm""[therefore omega = 20 rad s^(-1)]`</body></html> | |
| 36849. |
The static friction |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> <a href="https://interviewquestions.tuteehub.com/tag/linearly-2157962" style="font-weight:bold;" target="_blank" title="Click to know more about LINEARLY">LINEARLY</a><br/> is <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> <br/>zero<br/>varies <a href="https://interviewquestions.tuteehub.com/tag/parabolically-7383557" style="font-weight:bold;" target="_blank" title="Click to know more about PARABOLICALLY">PARABOLICALLY</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :increases linearly</body></html> | |
| 36850. |
A solid sphere is kept over a smooth surface as shown in figure. It is hit by a cute at height h above the centre C. If the surface is rough, then after hitting the sphere, in which case the force of friction is in forward direction. |
| Answer» <html><body><p>In <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> 1<br/>In case 2<br/>In both the cases<br/>In <a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of the cases</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |