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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36701. |
What is time period of a simple pendulum in a freely falling lift ? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/oscillation-1139998" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATION">OSCILLATION</a> of simple pendulum in freely <a href="https://interviewquestions.tuteehub.com/tag/falling-983241" style="font-weight:bold;" target="_blank" title="Click to know more about FALLING">FALLING</a> lift <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> stop due to the period becomes <a href="https://interviewquestions.tuteehub.com/tag/infinite-515764" style="font-weight:bold;" target="_blank" title="Click to know more about INFINITE">INFINITE</a>. Because in freely falling lift. The effective acceleration `g-g= 0` and period of oscillation <br/> `T= 2pi sqrt((<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(0))` <br/> T = infinite.</body></html> | |
| 36702. |
(A) : If barometer is accelerated upwards, the level of mercury in the tube of barometer will decrease. (R ) : The effective value of 'g' increases while the barometer is accelerated up. |
| Answer» <html><body><p>Both (A) and (R ) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R ) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>Both (A) and (R ) are false </p>Answer :B</body></html> | |
| 36703. |
Assertion :The amplitude of an oscillating pendulum decreases gradually with time. Reason : The frequency of the pendulum decreases with time. |
| Answer» <html><body><p>Both are ture and the <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of the <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a>.<br/>Both are ture and the reason is not correct explanation of the assertion.<br/>Assertion is true, but the reason is false.<br/>Both assertion and reason are false.</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36704. |
How many watt are there in 1 horse-power? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> horse-power = 746 <a href="https://interviewquestions.tuteehub.com/tag/watt-1450279" style="font-weight:bold;" target="_blank" title="Click to know more about WATT">WATT</a>.</body></html> | |
| 36705. |
A vehicle moving in a straight road has its speed changed from 5m//s to 8m//s in 2 sec. What is the average acceleration? |
| Answer» <html><body><p>`1m//s^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`1.5`<br/>`2m//s^(2)`<br/>zero</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36706. |
In Ohm's law potential difference between two end of a resistor are 15V, 14V, 10V, 12V and 13V. Find average absolute error, fractional (relative) error and pecentage error. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/absolute-11456" style="font-weight:bold;" target="_blank" title="Click to know more about ABSOLUTE">ABSOLUTE</a> <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> =1.44 <br/> <a href="https://interviewquestions.tuteehub.com/tag/least-7256596" style="font-weight:bold;" target="_blank" title="Click to know more about LEAST">LEAST</a> error `=0.1125` <a href="https://interviewquestions.tuteehub.com/tag/percentage-13406" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENTAGE">PERCENTAGE</a> error =`11.25%`</body></html> | |
| 36707. |
What is the minimum force that needs to be applied on a body of mass 100 g, kept on a horizontal surface, to set the body in motion? Given, coefficient of friction between the surface and the body is 0.4 and the force acts parallel to the surface. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :39200 <a href="https://interviewquestions.tuteehub.com/tag/dyn-2596635" style="font-weight:bold;" target="_blank" title="Click to know more about DYN">DYN</a></body></html> | |
| 36708. |
A wire of length '1' meters, made of a material of specific gravity 8 is floating horizontally on the surface of water. If it is not wet by water, the maximum diameter of the wire (in milli-meters) upto which it can continue to float is (surface tension of water is T=70xx10^(-3)Nm^(-1)) |
| Answer» <html><body><p>`1.5`<br/>`1.1`<br/>`0.75`<br/>`0.55`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36709. |
V_(x) and V_(y) are the horizontal and vertical compounds of velocity with x and y as the corresponding displacements along horizontal and vertical at any time t in a projectile motion in XY co-ordinate system, where g is the acceleration due to gravity. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In projectile motion <a href="https://interviewquestions.tuteehub.com/tag/horizontal-1029056" style="font-weight:bold;" target="_blank" title="Click to know more about HORIZONTAL">HORIZONTAL</a> component of velocity remains constant. Hence tis will be straight line II to time <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a>. <br/> y-t <a href="https://interviewquestions.tuteehub.com/tag/graph-17327" style="font-weight:bold;" target="_blank" title="Click to know more about GRAPH">GRAPH</a> is <a href="https://interviewquestions.tuteehub.com/tag/parabolic-2912016" style="font-weight:bold;" target="_blank" title="Click to know more about PARABOLIC">PARABOLIC</a>.</body></html> | |
| 36710. |
Weight of a body mass 'm' decreases by 1% when it is raised to a height 'h' above the earth's surface. If the body is taken to a depth 'h' in a mine, the change in its weight is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> by `<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>%`<br/>decreases by `0.5%`<br/><a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> by `1%`<br/><a href="https://interviewquestions.tuteehub.com/tag/increses-2126589" style="font-weight:bold;" target="_blank" title="Click to know more about INCRESES">INCRESES</a> by `0.5%`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 36711. |
Ten particles are moving at the speed of of 2,3,4,5,5,5,6,6,7 and 9 and ms^(-1). Calculate rms speed , average speed and most probable speed . |
| Answer» <html><body><p></p>Solution :The average speed `<a href="https://interviewquestions.tuteehub.com/tag/bar-892478" style="font-weight:bold;" target="_blank" title="Click to know more about BAR">BAR</a> nu=(2+3+4+5+5+5+6+6+7+9)/10=5.2"<a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>"^(-1)` <br/>To find the rms speed, first calculate the mean square speed `<a href="https://interviewquestions.tuteehub.com/tag/barv-2461077" style="font-weight:bold;" target="_blank" title="Click to know more about BARV">BARV</a>^(2)` <br/> `bar(nu^(2))=(2^(2)+3^(2)+4^(2)+5^(2)+5^(2)+5^(2)+6^(2)+6^(2)+7^(2)+9^(2))/10=30.6 m^(2)s^(-2)` <br/> The rms speed `nu_(rms)=sqrt(nu^bar(2))=sqrt(30.6)=5.53ms^(-1)` <br/> The most probable speed is `5ms^(-1)` because <a href="https://interviewquestions.tuteehub.com/tag/three-708969" style="font-weight:bold;" target="_blank" title="Click to know more about THREE">THREE</a> of the pearticles have that speed.</body></html> | |
| 36712. |
Figure shows a concave mirror with its pole at (0,0) and principal axis along x axis. There is a point object at (-40 cm, 1cm) Then the position of image (-40,1) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to <a href="https://interviewquestions.tuteehub.com/tag/sign-1207134" style="font-weight:bold;" target="_blank" title="Click to know more about SIGN">SIGN</a> convention, <br/> `u=-40cm implies h_1=1cm implies f=-5cm` <br/> `implies 1/v+1/u=1/f implies 1/v+1/(-40)=1/(-5) implies V=(-40)/7 cm`, <br/> `h_2/h_1=(-v)/u, h_2=(-v)/u times <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>= (-(-40/7) times 1)/(-40)=-1/7 cm` <br/>`therefore` The <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> of <a href="https://interviewquestions.tuteehub.com/tag/image-11684" style="font-weight:bold;" target="_blank" title="Click to know more about IMAGE">IMAGE</a> is `((-40)/7 cm,-1/7 cm)`</body></html> | |
| 36713. |
The mass and diameter of a planet are two times those of earth. If a seconds pendulum is taken to it, the time period of the pendulum in seconds is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`(1)/(2)`<br/>`2sqrt(2)`<br/>`sqrt(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36714. |
On what does the reaction time depend ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> depends on the <a href="https://interviewquestions.tuteehub.com/tag/situation-1210683" style="font-weight:bold;" target="_blank" title="Click to know more about SITUATION">SITUATION</a> and the person.</body></html> | |
| 36715. |
Velocity-time graph for the motion of a certain body is shown in Fig. Explain the nature of this motion. Find the initial velocity and acceleration and write the equation for the variation of displacement with time. What happens to the moving body at point B? How does the body moves after this moment? |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C03_SLV_022_S01.png" width="80%"/> <br/> The <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> - time graph is a straight <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a> with-ve slope. The motion is uniformly retarding up to point B and there after uniformly accelerated up to <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>. <br/> At point B the body stops and then its direction of velocity <a href="https://interviewquestions.tuteehub.com/tag/reversed-7265159" style="font-weight:bold;" target="_blank" title="Click to know more about REVERSED">REVERSED</a>. <br/> The initial velocity at point A is `v_(0)=7ms^(-1)`. <br/> `therefore a=(v_(f)-v_(o))/(Deltat)=(0-7ms^(-1))/(11s)=(-7)/(11)ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> `=0.64ms^(2)` <br/> The equation of motion for this body which gives variation of displacement with time is <br/> `S=7t-(1)/(2)0.64t^(2)=7t-0.32t^(2)`.</body></html> | |
| 36716. |
A massless rod S having length 2l has point masses attached to its two each as shown in Fig. The rod is rotating about an axis passing through its centre and making angle alpha with the axis. The magnitude of rate of change of momentum of rod i.e. |(dL)/(dt)| equals |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(3) omega^(2) sin <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>. <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> alpha`<br/>`ml^(2)omega^(2) sin 2 alpha`<br/>`ml^(2) sin 2 alpha`<br/>`m^(1//2)l^(1//2) omega sin alpha. cos alpha`</p>Solution :Refer to Fig. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XI_V01_C05_E01_173_S01.png" width="80%"/> <br/> The radius `r` of the circle traced by the masses is `r = l sin alpha` <br/> Angular momentum `overset rarr(L) = overset rarr(r ) xx m overset rarr(v)` <br/> `|overset rarr(L)| = r xx m omega r = m omega r^(2)` <br/> `= momega (l sin alpha)^(2) = m omegal^(2) sin^(2)alpha` <br/> `(dL)/(dt) = m omegal^(2) sin alpha cos alpha(d alpha)/(dt)` <br/> `= m omegal^(2) (sin 2 alpha) omega = m omega^(2)l^(2) sin 2 alpha`</body></html> | |
| 36717. |
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 ms^(-1). A plumb bob is suspended from the roof of the car by a string of length 1m. The angle made by the string with vertical is (g=10 ms^(-2)) |
| Answer» <html><body><p>`0^(@)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36718. |
If the escape velocity on the earth is 11.2km-s^-1, its value for a planet having double the radius and 8 times the mass of earth is |
| Answer» <html><body><p>`10.2 <a href="https://interviewquestions.tuteehub.com/tag/kms-1064571" style="font-weight:bold;" target="_blank" title="Click to know more about KMS">KMS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`22.4 kms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10kms-267108" style="font-weight:bold;" target="_blank" title="Click to know more about 10KMS">10KMS</a>^(-1)`<br/>0</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36719. |
Calculate the value of g in the following two cases: (a) If a mango of mass 1/2 kg falls from a tree from a height of 15 metres, what is the acceleration due to gravity when it beigns to fall? (b) Consider a satellite orbiting the Earth in a circular orbit of radius 1600 km above the surface of the Earth. What is the acceleration experienced by the satellite due to Earth's gravitational force? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`g^(.)=g(1-(2h)/(Re))` <br/> `=g(1-(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 1600 xx 10^(3))/(<a href="https://interviewquestions.tuteehub.com/tag/6400-330890" style="font-weight:bold;" target="_blank" title="Click to know more about 6400">6400</a> xx 10^(3)))=g(1-(2)/(4))` <br/> `g^(.)=g(1-(1)/(2))=(g)/(2)` <br/> `g^(.)=(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)/(2)` (or) `g^(.)=(9.8)/(2)=4.9 ms^(-2)`</body></html> | |
| 36720. |
A particle is acted upon by constant magnitude force perpendicular to ot which is always perpendicular to velocity of particle. The motion is taking place in a plane it follows that : |
| Answer» <html><body><p>Velocity is constant<br/>acceleration is constant<br/>kinetic energy is constant<br/>it <a href="https://interviewquestions.tuteehub.com/tag/moves-1104598" style="font-weight:bold;" target="_blank" title="Click to know more about MOVES">MOVES</a> in <a href="https://interviewquestions.tuteehub.com/tag/circular-916697" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCULAR">CIRCULAR</a> path</p>Answer :c,d</body></html> | |
| 36721. |
the displacement in metres of a body varies with time t in second as y = t2 – t – 2. The displacement is zero for a positive of t equal to |
| Answer» <html><body><p>1s<br/>2s<br/>3s<br/>4s</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36722. |
Two bodies start moving in the same straight line at the same instant of time from the same origin. The first body moves with a constant velocity of 40 m/s, and the second starts from rest with a constant acceleration of 4m/s""^2. Find the time that elapses before the second catehes the firs body. Find also the greatest distance between der prior to ir and the time at which this occurs. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :When the second body catches the first, the <a href="https://interviewquestions.tuteehub.com/tag/ditance-2588434" style="font-weight:bold;" target="_blank" title="Click to know more about DITANCE">DITANCE</a> <a href="https://interviewquestions.tuteehub.com/tag/travelled-7256865" style="font-weight:bold;" target="_blank" title="Click to know more about TRAVELLED">TRAVELLED</a> by each is the same. <br/> `40t=1/2(4)t^(2) or t=20S` <br/> Now, the distance s between the two bodies at any time t is <br/> `s=ut-1/2at^(2)` <br/> For s to be maximum. <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/ds-960390" style="font-weight:bold;" target="_blank" title="Click to know more about DS">DS</a>)/(dt)=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> or u-at=0` <br/> `or t=u/a=(40)/(4)=10s` <br/> Maximum Distance `=40 xx 10-1/2 xx 4 xx (10)^(2)=400-200=200m`</body></html> | |
| 36723. |
Define projectile motion . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : A projectile moves under the combined effect of two velocities. <br/> (i) A <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> velocity in the horizontal direction, which will not change provided there isno air resistance. <br/> (ii) A uniformly changing velocity (i.e., increasing or decreasing) in the vertical direction. <br/> There are two types of projectile motion: (i) Projectile given an <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> velocity in the horizontal direction (horizontal projection) <br/> (ii) Projectile given an initial velocity at an angle to the horizontal (<a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> projection) To <a href="https://interviewquestions.tuteehub.com/tag/study-1230645" style="font-weight:bold;" target="_blank" title="Click to know more about STUDY">STUDY</a> the motion of a projectile, let us Projectile given an initial velocity at an angle to the horizontal (angular projection) To study the motion of a projectile, let us Projectile given an initial velocity at an angle to the horizontal (angular projection) To study the motion of a projectile, let us assume that, <br/> (i)Air resistance is neglected. <br/> (ii) The effect due to rotation of Earth and curvature of Earth is negligible. <br/> (iii) The acceleration due to gravity is constant in magnitude and direction at all points of the motion of the neglected.</body></html> | |
| 36724. |
From a circular disc of radius R and mass 9 M , a small disc of mass M and radius (R)/(3) is removed concentrically . The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>)/(9) MR^(2)`<br/>`MR^(2)`<br/>` 4 MR^(2)`<br/>`(4)/(9) MR^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass of the <a href="https://interviewquestions.tuteehub.com/tag/disc-955290" style="font-weight:bold;" target="_blank" title="Click to know more about DISC">DISC</a> = 9 M <br/> Mass of removed portion of disc = M <br/> The moment of inertia of the complete disc about an axis passing through its centre O and <a href="https://interviewquestions.tuteehub.com/tag/perpendicular-598789" style="font-weight:bold;" target="_blank" title="Click to know more about PERPENDICULAR">PERPENDICULAR</a> to its plane is <br/> `I_(1) = (9)/(2) MR^(2)` <br/> Now, the moment of inertia of the disc with removed portion <br/> `I_(2) = (1)/(2) M ((R)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))^(2) = (1)/(18) MR^(2)` <br/> Therefore , moment of inertia of theremaining portion of disc about O is `I = I_(1) - I_(2) = (9 MR^(2))/(2) = (MR^(2))/(18) = (40 MR^(2))/(9)`</body></html> | |
| 36725. |
Which of the following quantities is expressed as force per unit area? |
| Answer» <html><body><p>Pressure<br/>Stress <br/>Both (a) and (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) <br/>None</p>Solution :Both (a) and (b)</body></html> | |
| 36726. |
Select the correct reason for the uplift of a jet plane A jet plane moves up in air because |
| Answer» <html><body><p>the gravity does not <a href="https://interviewquestions.tuteehub.com/tag/act-1106" style="font-weight:bold;" target="_blank" title="Click to know more about ACT">ACT</a> on bodies moving with <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> speeds <br/>the thrust of the jet <a href="https://interviewquestions.tuteehub.com/tag/compensates-925498" style="font-weight:bold;" target="_blank" title="Click to know more about COMPENSATES">COMPENSATES</a> for the force of gravity <br/>the flow of air around the wings causesan <a href="https://interviewquestions.tuteehub.com/tag/upward-721781" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARD">UPWARD</a> force4 whcihc compensates for the force of gravity <br/>the weightof air whose volume is equal to the volume of the plane is more than the weight of the plane </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :b</body></html> | |
| 36727. |
Obtain the differential equation of forced oscillation. |
| Answer» <html><body><p></p>Solution :The force act on <a href="https://interviewquestions.tuteehub.com/tag/oscillator-1140010" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATOR">OSCILLATOR</a> to sustain the oscillations external periodic force <br/> `F(t)= F_(0) cos omega_(d) t` <br/> Here, F(t) is the amplitude `F_(0)` of external periodic force dependently on time. <br/> Three forces act on oscillator <br/> (1) Restoring force `""F(x) = -<a href="https://interviewquestions.tuteehub.com/tag/kx-1064991" style="font-weight:bold;" target="_blank" title="Click to know more about KX">KX</a>(t)` <br/> (2) Resistive force `""F_(S) = -bv(t)` <br/> External periodic force `F_(d) = F_(0) cos omega_(d)t` <br/> Where `F_(0) cos omega_(d) t` is external periodic force and `omega_(d)= (2pi)/(T) implies T= (2pi)/(omega_d)` <br/> Period of external periodic force depends on the <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> frequency of drivingforce. <br/> From Newton.s second law of motion, if the net force is `F(t)= ma(t)` then <br/> `F(t) = F(x) +F_(S)+F_(d)"""......."(1)` <br/> `ma(t) = -kx(t) -bv(t) +F_(0)cos omega_(d)t` <br/> but `a(t) = (d^(2)x(t))/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>^2), v(t) = (dx(t))/(dt)` <br/> From equation (1) <br/> `m(d^(2)x(t))/(dt^2)= -b(dx(t))/(dt) -kx(t) -bv(t) +F_(0)cos omega_(d)t` <br/> `therefore m(d^(2)x(t))/(dt^2)+ b(dx(t))/(dt) +kx(t) = F_(0)cos omega_(d)t` <br/> `therefore (d^(2)x(t))/(dt^2)+(b)/(m)*(dx(t))/(dt) +(k)/(m) x(t)= (F_0)/(m) cos omega_(d)t` <br/> is the <a href="https://interviewquestions.tuteehub.com/tag/differential-953008" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENTIAL">DIFFERENTIAL</a> equation of forced oscillation. <br/> m is the mass of oscillator. <br/> This oscillator initially oscillates with its natural frequency `omega`. When we apply the external periodic force, the oscillations with the natural frequency die out, and then the body oscillates with the angular frequency of the external force. <br/> Its displacement, after the natural oscillations die out, is given by `x(t) = A cos (omega_(d)t + phi)` where t is the time measured from the moment when the periodic force is applied. <br/> The amplitude of forced oscillation, `A= (F_0)/([m^(2)(omega^(2)-omega_(d)^(2))^(2)+(omega_(d)^(2)b^(2))^(1/2)])` and phase `phi = tan^(-1) ((v_0)/(omega_(d)x_(0)))` <br/> Where `v_(0)` is the velocity of the particle at time `t=0" and "x_(0)` is the displacement of the particle at time t=0.</body></html> | |
| 36728. |
A small planet revolving around a large starting a circulation orbit of radius R with a period of revolution T. The gravitaional force of attraction between the star and the planet is proportional to R^(3/2) then T is proportional to |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/>`R^(7//2)` <br/>`R^(5//4)` <br/>`R^(5//2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36729. |
A body of 200g begines to fall from a height where is potential energy is 80 j. Its velocity at a point where kinetic and potential energies are equal is |
| Answer» <html><body><p>`10sqrt(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)m//s`<br/><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> m/s<br/>400 m/s<br/>20 m/s</p>Answer :D</body></html> | |
| 36730. |
An ideal gas undergoes a thermodynamic process as shown in Fig. The process consists of two isobaric and two isothermal steps. Show that the network done during the whole process is W _((Net)) = P _(1) (V _(2) - V _(1)) log _(e)""(P_(2))/( P _(1)) |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> _(nct) =P_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> _(B) -V _(A)) + P _(1) P_(2)<a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> _(e) ( V _(2) // V _(B)) + P _(1) (V _(1) - V _(2)) + P _(1) V _(1) log (V _(A) //V_(1)) , P _(2) V _(B) = P _(1) V _(2), P _(2) V _(A) = P _(1) V _(1) W _(net) = P _(2) V _(B) - P _(2) V _(A) + P _(1) V _(2) log _(e) (P _(2) // P _(1)) + P _(1) V _(1) - P _(1) V _(2) - P _(1) V _(1) log ( P _(1) // P _(1)) = P _(1) (V _(2) - V _(1)) log _(e) ( P _(2) // P _(1))`</body></html> | |
| 36731. |
A rod of length 1 and radius .r. is joined to a rod of length 1/2 and radius r/2 material. The free end of small rod is fixed to a rigid base and the free and of larger rod is given a twist of theta. The twist angle at the joint will be |
| Answer» <html><body><p></p>Solution :`theta_(1)+theta_(2)= theta to (1)` we know that `theta <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> (<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(r^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))` <br/> `:.(theta_(1))/(theta_(2))=(l_(1))/(l_(2))xx(r_(2)^(4))/(r_(1^(4)))=(1//2)/(l)xx(r^(4))/((r//2)^(4))=<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>, (theta_(1))/(theta_(2))=8 to (2)` <br/> After solving equation (1) and (2), we get `theta_(1)=(8)/(9) theta`</body></html> | |
| 36732. |
The velocity at the maximum height of a projectile is half of its initial velocity of projection. The angle of projection is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(0)`<br/>`60^(0)`<br/>`76^(0)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 36733. |
The average resisting force that must act on a 5kg mass to reduce its speed from 65 cms^(-2) to 15 cms^(-1) in 0.2s is |
| Answer» <html><body><p>12.5N<br/>25N<br/>50N<br/>100N</p>Answer :A</body></html> | |
| 36734. |
A copper cube 0.30m on a side is subjected to a shearing force of F = 6.0xx10^6N . Assuming that the shear modulus for copper is 4.2xx10^10 N//m^2 . The angle through which the cube shear is (approximately) |
| Answer» <html><body><p>`0.09^@` <br/>`0.15^@` <br/>`0.21^@` <br/>`0.32^@` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36735. |
Derive an expression for the acceleartion of the bodysliding down a frictionless surface |
| Answer» <html><body><p></p>Solution :Whenan objectof massmslideson africtionalsurfaceinclinedat anangle `theta` as shownin the figurethe forcesactingonitdecides theaccelerationof <a href="https://interviewquestions.tuteehub.com/tag/theobject-1409990" style="font-weight:bold;" target="_blank" title="Click to know more about THEOBJECT">THEOBJECT</a>(b)speedof theobject when it reachesthe bottom .<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E02_147_S01.png" width="80%"/> <br/>The forceactingon theobject is<br/> (i)Downwardgravitational force (mg) <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) Normalforceperpendicularto inclinedsurface (N)<br/> theblockis assumedto be apointmass[Inorder to drawthe freebodydiagram in figure(a)].Sincethe motionis on theinclinedsurfacethecoordinatesystemparallelto tehinclinedsurfaceis chosenas shown in thefigure (b)It isnotedthat theanglemadebythe gravitationalforcewith theperpendicularto the surfacesi <a href="https://interviewquestions.tuteehub.com/tag/equalto-974074" style="font-weight:bold;" target="_blank" title="Click to know more about EQUALTO">EQUALTO</a> theangleof inclination `theta` as shown inin figure<br/> `-mg cos theta hat(j)+ N hat(j) = 0`(No acceleration ) <br/> Bycomparingthecomponentson bothsidesN- mg cos `theta = 0` <br/> `N= mg cos theta`<br/> Themagnitude of normalforce(N)exertedby tghesurfaceis <a href="https://interviewquestions.tuteehub.com/tag/equivalentto-974754" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENTTO">EQUIVALENTTO</a> mgcos `theta` . Theobjectslidesalongthe x direction . <br/> Bycomparingthe componentson bothsideswe canequate <br/> `mg sin theta= ma ` <br/> Theaccelerationof theslindingobjectis<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E02_147_S02.png" width="80%"/> <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E02_147_S03.png" width="80%"/> <br/> Notethat theacceleratindependson theangleinclination `theta`</body></html> | |
| 36736. |
Match the column I with columnII |
| Answer» <html><body><p>(A)-(s),(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)-(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ),(C )-(q),(D)-(p)<br/>(A)-(p),(B)-(s),(C )-(r ),(D)-(q)<br/>(A)-(q),(B)-(r ),(C )-(p),(D)-(s)<br/>(A)-(r ),(B)-(p ),(C )-(q),(D)-(s)</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_OBJ_FING_PHY_XI_C12_E01_027_S01.png" width="80%"/></body></html> | |
| 36737. |
The sum of the given two numbers with regard to significant figures is (5.0 xx 10^(-8) ) + (4.5 xx 10^(-6) )= |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>.55 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)`<br/>`4.5 xx 10^(-6)`<br/>`4.6 xx 10^(-6)`<br/>`4 xx 10^(-6)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 36738. |
A string of neglisible mass going over a clamped pulley of mass m supports a block of mass M as shown in figure. Find the force on the pulley by the clamp. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>([( M + m)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) + m^(2) ]<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)`</body></html> | |
| 36739. |
Let y=1/(1+x^(2)) at t=0 s be the amplitude of the wave propogating in the positive x-direction. At t=2 s, the amplitude of the wave propogating becomes y=1/(1+(x-2)^(2)). Assume that the shape of the wave does not change during propogation. The velocity of the wave is |
| Answer» <html><body><p>`0.5 ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`1.0 ms^(-1)`<br/>`1.5 ms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.0 ms^(-1)`</p>Solution :`1.0 ms^(-1)` <br/> The general <a href="https://interviewquestions.tuteehub.com/tag/expression-980856" style="font-weight:bold;" target="_blank" title="Click to know more about EXPRESSION">EXPRESSION</a> y in terms of x <br/> `y = (1)/(1 + (x - vt)^(2))` <br/> The shape of the wave does not change: <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> wave move in 2 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>, 2m in positive .x. direction. So, wave moves 2m in 2 sec.<br/> `therefore`The velocity of the wave =`("displacement")/("time") = (2)/(2) : v = 1 ms^(-1)`</body></html> | |
| 36740. |
Earth orbiting satellite will escape if |
| Answer» <html><body><p>its speed is increased by 41 %<br/>its KE is doubled <br/>Both (a) and (b) are correct<br/>Both (a) and (b) are wrong</p>Solution :Escape velocity, `v_(e)=sqrt(2)v_(o)=1414v_(o)` or <a href="https://interviewquestions.tuteehub.com/tag/orbital-1138169" style="font-weight:bold;" target="_blank" title="Click to know more about ORBITAL">ORBITAL</a> speed is to be increased by 41 % <br/> Further speed is to <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> `sqrt(2)` <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> and <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> enegry is to increase two times.</body></html> | |
| 36741. |
Does speed of planet remain constant in an orbit? |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a>` According to equation `v_0=sqrt((GM_e)/r)`, for definiteorbit, r is constant and <a href="https://interviewquestions.tuteehub.com/tag/orbital-1138169" style="font-weight:bold;" target="_blank" title="Click to know more about ORBITAL">ORBITAL</a> <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> `v_0` is constant.</body></html> | |
| 36742. |
The phase difference between two pointsw separated by 1 in a wave of frequency 120 Hz is 90^(@).The wave velocity will be : |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/480-1879936" style="font-weight:bold;" target="_blank" title="Click to know more about 480">480</a> m//s`<br/>`180 m//s`<br/>`720 m//s`<br/>`240 m//s`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Delta <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>= 1 m Delta varphi=90^(@)=(pi)/(2) "rad", gamma =12 Hz` <br/> As `Delta varphi =(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a>)xx Delta x` <br/> (or) `(pi)/(2)=(2pi)/(lambda)xx1` <br/> (or) `lambda=4m` <br/> `v= gamma lambda120xx4= 480 m//s`</body></html> | |
| 36743. |
A particle of mass 4 gm is moving simple harmonically with a period 8 sec and amplitude 8 cm. What is its velocity when the displacement is 8 cm |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> cm/sec<br/>6 cm/sec<br/>4 cm/sec<br/>zero</p>Answer :D</body></html> | |
| 36744. |
Give the ideal gas equation and explain the terms . |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`<a href="https://interviewquestions.tuteehub.com/tag/pv-593601" style="font-weight:bold;" target="_blank" title="Click to know more about PV">PV</a>=(k_BN)/T`<br/>`P=(k_BN)/<a href="https://interviewquestions.tuteehub.com/tag/vt-1448359" style="font-weight:bold;" target="_blank" title="Click to know more about VT">VT</a>`<br/>`PV=k_BNT`<br/>`P=(k_BNV)/T`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36745. |
When the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is measured to be 35.72" of arc. Calculate the diameter of Jupiter. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`1.429xx10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)` <a href="https://interviewquestions.tuteehub.com/tag/km-1064498" style="font-weight:bold;" target="_blank" title="Click to know more about KM">KM</a></body></html> | |
| 36746. |
What is the length of a simple pendulum, which ticks seconds ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :From Eq. (14.29), the time period of a <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> pendulum is given by, <br/> `T=2pisqrt(L/g)` <br/> From this relation one gets, <br/> `L=(gT^(2))/(4pi^(2))` <br/> The time period of a simple pendulum, which ticks seconds, is 2 s. <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, for g = 9.8 m `s^(-2)` and T = 2 s, L is <br/> `=(9.8(<a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2))xx4(s^(2)))/(4pi^(2))` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/1m-283006" style="font-weight:bold;" target="_blank" title="Click to know more about 1M">1M</a>`</body></html> | |
| 36747. |
Two identical water bottles one empty and the other filled with water are allowed to roll down an inclined plane. Which one of them reaches the bottom first ? Explain your answer. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of the <a href="https://interviewquestions.tuteehub.com/tag/empty-2611346" style="font-weight:bold;" target="_blank" title="Click to know more about EMPTY">EMPTY</a> water bottle mostly <a href="https://interviewquestions.tuteehub.com/tag/concentrated-409727" style="font-weight:bold;" target="_blank" title="Click to know more about CONCENTRATED">CONCENTRATED</a> on its <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a>. So moment of inertia of empty water bottle is more than the bottle filled with water. As we know, moment of inertia is inversely proportional to angular velocity. Therefore, the bottle filled with water whirls with greater speed and reaches the ground first</body></html> | |
| 36748. |
When a liquid in a vessel is heated its levela)will increase b) may increase or decreases c) will decrease d) may remains same |
| Answer» <html><body><p> only (a) is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/>only (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) is correct <br/>(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) is correct <br/>(b) & (d) are correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36749. |
A Carnot engine takes 3000 kcal of heat from a reservoir at 627^(@)C. The sink is at 27^(@)C. What is the amount of work done by the engine? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Temperature of the reservoir, <br/> `T_(1) = (627 + 273)<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> = 900K` <br/> Temperature of the sink, <br/> `T_(2) = (27_273)K = 300K` <br/> `:. "<a href="https://interviewquestions.tuteehub.com/tag/efficiency-20674" style="font-weight:bold;" target="_blank" title="Click to know more about EFFICIENCY">EFFICIENCY</a>", eta = 1 -(T_2)/(T_1) = 1 - (300)/(900) = 2/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>` <br/> Again, `eta = W/(Q_1)` <br/> or, `W = etaQ_(1) = 2/3 xx 3000` <br/> `=2000 kcal = 2000 xx 4.2 xx 10^(3)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/> `=8.4 xx 10^(6) J`.</body></html> | |
| 36750. |
For a uniform body, if the shape is kept the same but its size is changed uniformly, will the position of the centre of gravity change ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :no</body></html> | |