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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36601. |
A sphere of radius 6 cm weighs 2 kg in air. It is held with its lower half immersed in water. What will be its appent weight? ( Surface tension of water =72.5xx10^(-3) N m^(-1) "and " g=9.81 m s^(-2)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :1.5504 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a></body></html> | |
| 36602. |
A sphere of mass M and radius r shown in figure slips on a rough horizontal plane. At same instant it has translational velocity v_(0) and rotational velocity about the centre v_(0)//2r. Find the translational velocity (in m/s) after the sphere start pure rolling (Take v_(0)=7 m/s) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a></body></html> | |
| 36603. |
The centre of mass of a rigid body ………… the rigid body. |
| Answer» <html><body><p>is <a href="https://interviewquestions.tuteehub.com/tag/inside-1045864" style="font-weight:bold;" target="_blank" title="Click to know more about INSIDE">INSIDE</a><br/>is outside <br/>it can be <a href="https://interviewquestions.tuteehub.com/tag/either-7265046" style="font-weight:bold;" target="_blank" title="Click to know more about EITHER">EITHER</a> inside or outside<br/>is at the <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> of </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36604. |
What should be minimum distance between listener and reflecting surface ? |
| Answer» <html><body><p>28m <br/><a href="https://interviewquestions.tuteehub.com/tag/18m-280488" style="font-weight:bold;" target="_blank" title="Click to know more about 18M">18M</a> <br/>19m <br/>`16.6m` </p>Solution :Is same sound is heard after time `t ge (1)/(10)` s <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to reflection then it is called an <a href="https://interviewquestions.tuteehub.com/tag/echo-11626" style="font-weight:bold;" target="_blank" title="Click to know more about ECHO">ECHO</a> (because sensation of hearing <a href="https://interviewquestions.tuteehub.com/tag/lasts-2782602" style="font-weight:bold;" target="_blank" title="Click to know more about LASTS">LASTS</a> for `(1)/(10)s` in human <a href="https://interviewquestions.tuteehub.com/tag/ears-964179" style="font-weight:bold;" target="_blank" title="Click to know more about EARS">EARS</a>). Thus, `t _(min) = (1)/(10) s=0.1 s` <br/> Now, when sound is reflected from reflector at distance x from its source and echo is heard at the end of t time. <br/> `v = (2x)/(t) implies x = (vt)(2) implies x_(min) = (v)/(2)xx t _(min)` <br/> `therefore x_(min) = (332)/(2) xx 0.1 = 16.6 m`</body></html> | |
| 36605. |
Centre of mass of two particle with masses 2 kg and 1 kg locsted at (1, 0, 1) and (2, 2, 0) has the co - ordinates of |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>),(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(3),(2)/(3)`<br/>`(2)/(3),(4)/(3),(2)/(3)`<br/>`(2)/(3),(2)/(3),(4)/(3)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(3),(2)/(3),(2)/(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36606. |
A solid sphere is rotating with an angular velocity omega. It is of moment is inertia 'I' about its diametrical axis and is of linear expansion coefficient alpha. When temperature is increased by DeltaT, the fractional change in its angular velocity is |
| Answer» <html><body><p>`2alphaDeltaT`<br/>`alphaDeltaT`<br/>`(alphaDeltaT)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(2alphaDeltaT)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36607. |
In an experiment to determine the thermal conductivity of copper with Searle's apparatus, 100 gm of water flowed in 4.2 minutes past the cold end of the copper bar, its initial and final temperatures being 25°C and 52°C respectively. If the temperature difference between two points in the bar 10 cm apart is 23°C and the area of cross-section of the bar is 5 "cm"^2,calculate the coefficient of thermal conductivity of copper. Specific heat capacity of water 4,200 "J kg"^(-1) "K"^(-1) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> gained by water `= Q = "m c d T"` <br/> `= 100 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3) xx 4200 xx (<a href="https://interviewquestions.tuteehub.com/tag/52-324553" style="font-weight:bold;" target="_blank" title="Click to know more about 52">52</a> - 25) = 11340` J <br/> `A = 5 xx 10^(-4) m^(2) , theta_1 - theta_2 = 23^(@) C = 23 "K", d = 0.10 m, t = 4.2 xx 60 = 252 s`, <br/> `K= (Q d)/( A ( theta_1 - theta_2 ) t ) = ( 11340xx 0.10)/( 5 xx 10^(-4) xx 23 xx 252)= 292.3 "Wm"^(-1) "K"^(-1)`</body></html> | |
| 36608. |
In a stationary wave |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> is <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> at nodes<br/>pressure change is maximum at anitnodes<br/>pressure change is minimum at nodes<br/>amplitude is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> at all points</p>Answer :A</body></html> | |
| 36609. |
In the question number 91, if a force Fis applied to 20 kg block, then the tension in the string is |
| Answer» <html><body><p>100N<br/><a href="https://interviewquestions.tuteehub.com/tag/200n-290170" style="font-weight:bold;" target="_blank" title="Click to know more about 200N">200N</a><br/>300N<br/>400N</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_OBJ_FING_PHY_XI_C05_E01_092_S01.png" width="80%"/> <br/> When a force F is applied on 20kg block, then the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> in <a href="https://interviewquestions.tuteehub.com/tag/string-11290" style="font-weight:bold;" target="_blank" title="Click to know more about STRING">STRING</a> is T=m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=(10kg)(20ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))=200N</body></html> | |
| 36610. |
A syring containing water is held horizontally with its nozzle at a height, h = 1.25 m above the ground as shown in Fig. 3.42. The diameter of the piston is 5 times that of the nozzle. The ispushed with a constant speed of 20 cm. s^-1.If g= 10m . s^-2. |
| Answer» <html><body><p>the speed of water emerging from the nozzle is 5m . `s^-1`<br/>the time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> by water to hit the <a href="https://interviewquestions.tuteehub.com/tag/ground-1013213" style="font-weight:bold;" target="_blank" title="Click to know more about GROUND">GROUND</a> is 0.5 s<br/>the horizontal <a href="https://interviewquestions.tuteehub.com/tag/range-1177030" style="font-weight:bold;" target="_blank" title="Click to know more about RANGE">RANGE</a>,R = 2.5 m<br/>the magnitude of the velocity with which the water hits the ground is `5sqrt2 m. s^-1` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U07_C03_E11_006_O01.png" width="30%"/></p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::C::D</body></html> | |
| 36611. |
A gun weighing 25 kg fires a bullet weighing 30 g with the speed of 200 ms^(-1). What is the speed of recoil of the gun? |
| Answer» <html><body><p></p>Solution :Mass of the <a href="https://interviewquestions.tuteehub.com/tag/gun-1014044" style="font-weight:bold;" target="_blank" title="Click to know more about GUN">GUN</a> M = 25 kg <br/>Mass of the bullet `m = 30g = 30 xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) kg` <br/>Speed of bullet `v = 200 ms^(-1)` <br/>Speed of gun V = ? <br/> The motion is in one dimension. As per law of conservation of momentum, <br/> `<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a> = mv = 0` <br/> `V=(-mv)/(M)` <br/> ` V = (-30 xx 10^(-3) xx 200)/(25)= - 240 xx 10^(-3) ms^(-1)` <br/>The negative sign <a href="https://interviewquestions.tuteehub.com/tag/shows-1206590" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWS">SHOWS</a> that the gun moves in the <a href="https://interviewquestions.tuteehub.com/tag/opposite-1137237" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSITE">OPPOSITE</a> direction of the bullet. Further the magnitude of the recoil speed is very small compared to the bullet.s speed.</body></html> | |
| 36612. |
What is meant by free oscillation ? |
| Answer» <html><body><p></p>Solution :When the oscillator is allowed to oscillate by displacing its position from equilibrium position, from equilibrium position, it oscillates with a frequency which is <a href="https://interviewquestions.tuteehub.com/tag/equalto-974074" style="font-weight:bold;" target="_blank" title="Click to know more about EQUALTO">EQUALTO</a> the <a href="https://interviewquestions.tuteehub.com/tag/natural-575613" style="font-weight:bold;" target="_blank" title="Click to know more about NATURAL">NATURAL</a> frequency of the oscillator. Such an <a href="https://interviewquestions.tuteehub.com/tag/oscillation-1139998" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATION">OSCILLATION</a> or vibration is <a href="https://interviewquestions.tuteehub.com/tag/known-534098" style="font-weight:bold;" target="_blank" title="Click to know more about KNOWN">KNOWN</a> as free oscillation or free vibration.</body></html> | |
| 36613. |
A cylinder of radius R made of material of thermal conductivity K_1 is surrounded by a cylindrical shell of inner radius R and outer radius 3R made of material of thermal conductivity K_2. The two ends of the combined system are maintained at two different temperatures. There is no loss of heat across the cylindrical surfaceand the system is in steady state. The effective thermal conductivity of the system is |
| Answer» <html><body><p>`K_1 + K_2`<br/>`( K_2 K_1)/( K_1 + K_2)`<br/>`( 8K_1 + K_1)/( <a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)`<br/>`( K_1 + 8K_2)/(9)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36614. |
State and prove Pascal's law in fluids. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E01_049_S01.png" width="80%"/> <br/>Pascal's law states that if the effect of <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> can be generated then the pressure in a fluid in equilibrium is the same <a href="https://interviewquestions.tuteehub.com/tag/everywhere-2065767" style="font-weight:bold;" target="_blank" title="Click to know more about EVERYWHERE">EVERYWHERE</a>.<br/> Let us consider any two points A and B inside the fluid imagined. A cylinder is such that points A and B lie at the centre of the <a href="https://interviewquestions.tuteehub.com/tag/circular-916697" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCULAR">CIRCULAR</a> surface at the top and bottom of the cylinder. Let the fluid inside this cylinder be in equilibrium under the action of <a href="https://interviewquestions.tuteehub.com/tag/forces-16875" style="font-weight:bold;" target="_blank" title="Click to know more about FORCES">FORCES</a> from <a href="https://interviewquestions.tuteehub.com/tag/outside-1143075" style="font-weight:bold;" target="_blank" title="Click to know more about OUTSIDE">OUTSIDE</a> the fluid. The forces acting on the circular, top and bottom surfaces are perpendicular to the forces acting on the cylindrical surface. Therefore the forces acting on the faces at A and B are equal and opposite and hence add to zero.<br/>As the areas of these two faces are equal, pressure at A = pressure at B.<br/>This is the proof of Pasccal's law when the effect of gravity is not taken into account.</body></html> | |
| 36615. |
How do insects run on the surface of water? |
| Answer» <html><body><p></p>Solution :Water has a tendency to reduce its <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a>. Surface of water <a href="https://interviewquestions.tuteehub.com/tag/behaves-894569" style="font-weight:bold;" target="_blank" title="Click to know more about BEHAVES">BEHAVES</a> <a href="https://interviewquestions.tuteehub.com/tag/like-1073845" style="font-weight:bold;" target="_blank" title="Click to know more about LIKE">LIKE</a> a <a href="https://interviewquestions.tuteehub.com/tag/stretched-7711564" style="font-weight:bold;" target="_blank" title="Click to know more about STRETCHED">STRETCHED</a> membrane. So, when insects touch water, it can easily run over it. It can run even with greater speed due to less aggressive force between water and insects.</body></html> | |
| 36616. |
A gardener is watering plants at the rate 0.1 litre/sec using a pipe of cross - section 1 cm^(2). What additional force he has to exert if he desires to increasethe rate of watering two times ? |
| Answer» <html><body><p></p>Solution :`F=Adv^(2)=((Av)^(2)d)/(A)` If rate of watering plant (Av) is doubled, it means amount of water poured / sec is doubled which is possible only if velocity is doubled. Hence force is to be made 4 <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a>.<br/>`<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` additional force = 3 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> initial force<br/>`= 3Adv^(2)=3((Av)^(2))/(A)d`<br/>`= (3xx0.1xx0.1xx10^(3))/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-4))=3xx10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)N`</body></html> | |
| 36617. |
"A solid sphere of copper of radius R and a hollow sphere of the same material of inner radius r and outer radius R are heated to the same temperature and allowed to cool in the same environment. Which of them starts cooling faster ?'' |
| Answer» <html><body><p></p>Solution :Rate of loss of <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> = mass x <a href="https://interviewquestions.tuteehub.com/tag/specific-1220917" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIFIC">SPECIFIC</a> heat x rate of cooling. The surface <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a> of <a href="https://interviewquestions.tuteehub.com/tag/hollow-1028416" style="font-weight:bold;" target="_blank" title="Click to know more about HOLLOW">HOLLOW</a> and solid sphere are equal. But mass is <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> for hollow sphere. So rate of cooling of holow sphere is faster.</body></html> | |
| 36618. |
The dimensional formula of (1)/(2) in_(0)E^(2)is (in_(0) is permittivity of free space and E is electric field ) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) T^(-2)`<br/>`MLT^(-2)`<br/>`ML^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) T^(-2)`<br/>`ML^(-2) T^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 36619. |
There are two incline planes AO and OB inclined at 45^(@) and60^(@) respectively with the horizontal as shown in the figure. When a man moves on the incline plane AO with speed 10 m/s. he oberves that the rain drops are falling45^(@) with the vertical. When the man moves on the inclined plane OB with speed 20 m/s. he observes that the raindrops are falling vertically downward. Then actual speed of rain is |
| Answer» <html><body><p>`5sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)m//s`<br/>`20 sqrt(2)m//s`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> sqrt(2)m//s`<br/>None of these</p>Answer :C</body></html> | |
| 36620. |
A man walking briskly in rain with speed v must slant his umbrella forward making an angle theta with the vertical. A student derives the following relation between theta and v: tantheta = v and checks that the relation has a correct limit : as vtoo, thetato0, as expected , (we are assuming there is no strong wind and that the rain falls vertically for a stationary man.) Do you think this relation can be correct ? If you, guess the correct relation. |
| Answer» <html><body><p></p>Solution :tan `<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>` must be dimensionless . The <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> formula is tan`theta = v//v.` where v. is the <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of <a href="https://interviewquestions.tuteehub.com/tag/rainfall-1176708" style="font-weight:bold;" target="_blank" title="Click to know more about RAINFALL">RAINFALL</a>.</body></html> | |
| 36621. |
A particle of mass 10 g is kept of the surface of a uniform sphere of mass 100 kg and radius 10 cm. Find the work to be done against the gravitational force between them to take the particle far away from the sphere. (Take G = 6.67 xx 10^(-11) Nm^(2)//kg^(2) ? |
| Answer» <html><body><p>`6.67 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-9) J` <br/>`6.67 xx 10^(10) J` <br/>`13.34 xx 10^(-10) J` <br/>`3.33xx 10^(-10) J` </p>Solution :`implies` Work = Change in <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy `= U_2 - U , ` <br/> `W- (GMm)/(oo) - (-(GMm)/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>+(6.67 xx 10^(-11) xx 100 xx 10 xx 10^3 )/(10 xx 10^(-2))` <br/> ` [ :. (GMm)/(oo) = 0]` <br/> `:. W = 6.67 xx 10 ^(-10) J`</body></html> | |
| 36622. |
A steel wire of length 20 cm is stretched to increase its length by 0.2 cm. Find the lateral strain in the wire if the Poissin's ratio for steel is 0.19. |
| Answer» <html><body><p>0.0019<br/>0.0008<br/>0.019<br/>0.008</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a></body></html> | |
| 36623. |
A simple pendulum is swinging in vertical plane. The ratio of its potential energies when it is making angles 45^(@) and 90^(@) with the vertical is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> : 1`<br/>`1 : (<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) + 1)`<br/>`sqrt(2) : 1`<br/>`(sqrt(2) - 1) : sqrt(2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36624. |
The relation between time t and distance x is t=ax^(2)+bx where a and b are constants. The acceleration and velocity relation is acceleration = - k av^(3). The value of 'k' is |
| Answer» <html><body><p> <br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 36625. |
Two cylinders A and B of equal capacity areconnected to each other via a stop cock. A contains a gas at standard temperature T and pressure P.B is completely evacuated. The entire system is thermally insulated. The stop cock is thermally insulted. The stop cock is suddenly opened. The find pressure of the gas in A and B is |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>P <br/>`P//2` <br/>`P//4` <br/><a href="https://interviewquestions.tuteehub.com/tag/2p-300467" style="font-weight:bold;" target="_blank" title="Click to know more about 2P">2P</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36626. |
If three vectors along coordinate axes represent the adjacent sides of a cubie of length b, then the unit vector alongits diagonal passing through the origin will be |
| Answer» <html><body><p>`(hati+hatj+hatk)/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`(hati+hatj+hatk)/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)b)`<br/>`hati+hatj+hatk`<br/>`(hati+hatj+hatk)/(sqrt(3))`<br/></p>Solution :(d) <a href="https://interviewquestions.tuteehub.com/tag/diagonal-950665" style="font-weight:bold;" target="_blank" title="Click to know more about DIAGONAL">DIAGONAL</a> <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> `A=bhati+bhatj+bhatk` <br/> or `A=sqrt(b^(2)+b^(2)+b^(2))=sqrt(3)b` ltbrrgt `:. hatA=A/A=(hati+hatj+hatk)/(sqrt(3))`</body></html> | |
| 36627. |
Obtained an expression for efflux velocity of a liquid through a small hole in a vessel |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to Bernoulli.s theorem <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> v =`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2gh)`</body></html> | |
| 36628. |
Explain this statement clearly : "To call a dimensional quantity 'large' or 'small' is meaningless without specifying a standard for comparison". In view of this, reframe the following statements wherever necessary: (a) atoms are very small objects (b) a jet plane moves with great speed (c) the mass of jupiter is very large (d) the air inside this room contains a large number of molecules (e) a proton is much more massive than an electron (f) the speed of sound is much smaller than the speed of light. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) Compared to size of tip of pin, atoms are very small. <br/> (b) <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of jet plane is <a href="https://interviewquestions.tuteehub.com/tag/much-2164829" style="font-weight:bold;" target="_blank" title="Click to know more about MUCH">MUCH</a> more than a speed of superfast train. <br/> (c) Mass of jupiter is very large compared to mass of the earth. <br/> (d) No. of <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> in <a href="https://interviewquestions.tuteehub.com/tag/air-852233" style="font-weight:bold;" target="_blank" title="Click to know more about AIR">AIR</a> contained in room is very large compared to no. of molecules in one mole air. <br/> (e) This statement is correct. <br/>(f)This statement is correct</body></html> | |
| 36629. |
(A) : Sudden fall of pressure at a place indicates storm. (R ) : Air flows from higher pressure to lower pressure. |
| Answer» <html><body><p>Both (A) and (R ) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>Both (A) and (R ) are false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36630. |
When a steel rod of length 2m is compressed its length decreases by 0.1cm. Find the work done per unit volume against the compressive stress. |
| Answer» <html><body><p>`2.5xx10^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)<a href="https://interviewquestions.tuteehub.com/tag/jm-525388" style="font-weight:bold;" target="_blank" title="Click to know more about JM">JM</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.25xx10^(4)Jm^(-3)`<br/>`5.0xx10^(4)Jm^(-3)` <br/>`7.5xx10^(4)Jm^(-3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :1</body></html> | |
| 36631. |
A sealed tank containing a liquid of density rho moves with a horizontal acceleration a, as shown in the figure. The difference in pressure between the points A and B is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> <a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a> <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> rho a`<br/>`h rho g -l rho a`<br/>`h rho g+l rho a `</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36632. |
A heavy mass is attached to a thin wire and is whirled in a vertical circle. The wire is most likely to break |
| Answer» <html><body><p>When the mass is at the lowest <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> <br/>When mass is at the highest point <br/> When <a href="https://interviewquestions.tuteehub.com/tag/wire-1457703" style="font-weight:bold;" target="_blank" title="Click to know more about WIRE">WIRE</a> is horizontal<br/>When mass is at an <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of `<a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a>^(-1) ((1)/(sqrt2))`from upward vertical</p>Answer :A</body></html> | |
| 36633. |
(A): Increasing the number of observations minimizes random errors (R ): positive and negative random errors occur with equal probability |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and ( R) are true and (R ) is not the correct explanation of (A)<br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>(A) is false but (R ) is true</p>Answer :A</body></html> | |
| 36634. |
A wooden block is floating on water in a closed vessel. What will happen (i) if the air above the water is compressed, (ii) if all the air above the water is removed from the closed vessel? |
| Answer» <html><body><p></p>Solution :(i) If the air above the water in the closed vessel is compressed, the block will float <a href="https://interviewquestions.tuteehub.com/tag/upwards-2318352" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARDS">UPWARDS</a> some more. <br/> Here, <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of the wooden block = weight of displaced water + weight of displaced air. <br/> If the air is compressed, then its <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> increases and hence the weight of the displaced air increases while the weight of the displaced water decreases. Hence, the block will float upwards some more. <br/> (ii) If all the air above the water is <a href="https://interviewquestions.tuteehub.com/tag/removed-2986295" style="font-weight:bold;" target="_blank" title="Click to know more about REMOVED">REMOVED</a> from the closed vessel, then the wooden block sinks more. This happens because when the air is removed, the buoyancy due to air is absent. Consequently, the apparentweight of the body increases, and the block sinks some more.</body></html> | |
| 36635. |
When the temperature of a liquid is raised by 100^(@)C, 0.01% of the liquid is expelled. Calculate the coefficient of apparent expansion of the liquid. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> mass of the liquid `(m _(1) = <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> gm,` <br/> Mass of the expelled liquid `(m _(1) - m _(2)) = 0.01 gm (0.01%)` <br/> Remaining liquid `= m _(2) =<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>- -0.01 = 99.99 gm , t _(2) -t _(1) = 100^(@)C` <br/> From `gamma _(a) = (m _(1) - m _(2))/( m _(2) (t _(2) -t _(1)) ) = ( 0.01)/(99.99 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 100) = (1)/( 999900) = 0.00001//^(@)C` <br/> `thereore` <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of apparent expansion of the liquid `= 10 xx 10 ^(-) //^(@)C`</body></html> | |
| 36636. |
A body is dropped from a height of 16m. The body strikes the ground and losses 25% of its velocity. The body rebounds to a height of |
| Answer» <html><body><p>12m<br/>9m<br/>4m<br/>8m</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36637. |
A body of mass 10kg is placed on foxed rough horizontal surface. Coefficient of static friction is 0.6 and coefficient of kinetic friction is 0.6 and coefficient of kinetic friction is 0.4. If horizontal force 20Nis applied on the body find out the frictional force (g=10ms^(-2)) |
| Answer» <html><body><p> </p>Solution :Limiting friction <br/> `f_(S)=mu_(S)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>=0.6xx10xx10=60N`<br/> Kinetic friction `=0.4xx10xx10=40N`<br/> The force applied on the body is F=20N. <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> the body remains at <a href="https://interviewquestions.tuteehub.com/tag/rest-11386" style="font-weight:bold;" target="_blank" title="Click to know more about REST">REST</a>, frictional force is static in nature and its value is `f_(s)=20N`.If we extend the discussion and make F=40N. `f_(s)` will be 40 N and the body remains at rest. If F=59N then `f_(s)` will be 59N and the body remains at rest. Static frictional force can take any volue between zero and 60N. Please note that in the formula `f_(s)=mu_(s)N,f_(s)` is maximum static frictional force or limiting friction. Its important to understand that the term static friction and limiting friction are not exactly the same. One should note that limiting friction is static in nature, but every static friction is not limiting friction. If `Fgt60N` the body slides on the surface, Hence the friction force involved will be kinetic frictional force and its magnitude will be `f_(k)=mu_(k)N`.`f_(k)=0.4xx10xx10=40N`<br/> In Fig. 1.4 (a) (b), the <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> is subjected to three forces mg, `P and R^(.) (R^(.)` is the resultant of normal reaction N and frictional force f) and hence they must be concurrent. <br/> `R^(.)=sqrt(f^(2)+N^(2)), tanphi_(s)=f_(max)/N=(mu_(s)N)/N, tanphi_(s)=mu_(s).........(1.2)` <br/> where `phi_(s)` is known as the angle of friction which represents the angle between the resultant `R^(.)` and the normal reaction N. It is to be remembered that as long as `thetaltphi_(s)`, the block is in equilibrium and when `thetaltphi_(s)`, the motion is about to begin. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_B_C01_SLV_001_S01.png" width="80%"/></body></html> | |
| 36638. |
A particle is released from a height h. At a certain height, its kinetic energy is two times its potential energy. Height and speed of the particle at that instant are |
| Answer» <html><body><p>`h/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> sqrt((2gh)/(3))`<br/>`h/3 2sqrt((gh)/(3))`<br/>`(2h)/3 sqrt((2gh)/(3))`<br/>`h/3 sqrt(2gh)`</p>Solution :Total <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> energy = mgh <br/>As `(KE)/(PE) = 2/1`<br/>`:. `KE = `2/3 mgh and PE = 1/3 mgh` <br/> Height from the ground at that <a href="https://interviewquestions.tuteehub.com/tag/instant-1046099" style="font-weight:bold;" target="_blank" title="Click to know more about INSTANT">INSTANT</a> is `h. = h/3` <br/> and speed of particle at that instant is <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>(h - h.)) = sqrt(2h((2h)/(3))) = 2sqrt((gh)/(3))`.</body></html> | |
| 36639. |
In the above problem its displacement after 3 seconds is |
| Answer» <html><body><p>78.4m <br/>44.15m <br/>10.57m <br/>Zero</p>Solution :`S=ut+(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)at^(2), a=g(sin theta, mu_(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)<a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta)`</body></html> | |
| 36640. |
A trolley of mass 360 kg is lying on a horizontal frictionless surface. A man of mass 40 kg runs with uniform speed on the trolley by a distance of 2m in 0.5 second. What is the velocity of the trolley relative to earth? |
| Answer» <html><body><p>0.8 m/s<br/>0.4 m/s<br/>1.6 m/s<br/>2.2 m/s </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36641. |
Study of which motion is required to understand many physical phenomena? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/study-1230645" style="font-weight:bold;" target="_blank" title="Click to know more about STUDY">STUDY</a> of <a href="https://interviewquestions.tuteehub.com/tag/oscillatory-2208020" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATORY">OSCILLATORY</a> <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a>.</body></html> | |
| 36642. |
The spring has a force constant k. The pulley is light and smooth while the spring and string are light figure. If the block of mass m slightly displaced vertically and released, find the period of verticall oscillations. |
| Answer» <html><body><p></p>Solution :Let `x_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)` be the extension in the spring in <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> position and `F_(0)` be the tension in the spring. Then <br/> `F_(0)=kx_(0)` <br/> If `T_(0)` is the tension in the string, then <br/> `T_(0)=mf or 2T_(0)=F_(0)=kx_(0)`…(i) <br/> Let mass m be pulled downward through distnace x, then tension in spring and string be F and T respectively. <br/> Now `F=2T=k(x_(0)=x//2)=kx_(0)<a href="https://interviewquestions.tuteehub.com/tag/kx-1064991" style="font-weight:bold;" target="_blank" title="Click to know more about KX">KX</a>//2` <br/> or `2T=2T_(0)+kx//2`[from (i)] <br/> or `T-T_(0)=kx//4` <br/> Restoring force on the mass m is <br/> `f=T-mg=T-T_(0)=kx//4`...(ii) <br/> From (ii) , `fpropx and f` is a restoring force, therefore, if mass m is left <a href="https://interviewquestions.tuteehub.com/tag/free-465311" style="font-weight:bold;" target="_blank" title="Click to know more about FREE">FREE</a>, it will execute SHM. <br/> Here, spring factore`=k//4,` inertia factore `=`m. <br/> <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> period, `T=2pisqrt((m)/(k//4))=4pisqrt((m)/(k))` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XI_V02_C10_S01_413_S01.png" width="80%"/></body></html> | |
| 36643. |
A person in lift which ascents up with acceleration 10ms^(-2) drops a stone from a height 10 m. The time of decent is [g=10ms^(-2)] |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> s<br/>2 s<br/>1.5 s <br/><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> s</p>Answer :A</body></html> | |
| 36644. |
What is acoustics ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :It is the study of the <a href="https://interviewquestions.tuteehub.com/tag/production-14556" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCTION">PRODUCTION</a> and propagation of <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> waves.</body></html> | |
| 36645. |
Iceberg floats in water with part of it submerged .What is the fraction of the volume of inceberg submerged if the density of ice is rho_(i)=0.917g//cm^(3). |
| Answer» <html><body><p></p>Solution :Density of ice `rho_(ice)=0.17g//cm^(3)`<br/> Density of water `rho_(w)=1g//cm^(3)`<br/> Let volume of <a href="https://interviewquestions.tuteehub.com/tag/iceberg-1035401" style="font-weight:bold;" target="_blank" title="Click to know more about ICEBERG">ICEBERG</a> =V<br/> Let volume of water displaced by iceberg =.V.<br/> For body <a href="https://interviewquestions.tuteehub.com/tag/floats-992996" style="font-weight:bold;" target="_blank" title="Click to know more about FLOATS">FLOATS</a> on <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a>, <br/> <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of iceberg = weight of water displaced by the submerged part by ice<br/>`thereforeVrho_(i)thetag=Vrho_(w)g`<br/>`therefore(V)/(V)=(rho_(ice))/(rho_(w))=(0.917)/(1)=0.917`</body></html> | |
| 36646. |
A particle of a small mass m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/2mg-1835961" style="font-weight:bold;" target="_blank" title="Click to know more about 2MG">2MG</a> <br/>4mg <br/>`<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> gt mg` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36647. |
People often say for every action there is an equuivalent opposite reaction here they meant action of a human is it correct to apply newton third lawto human action ?What is meant by action in newton third law given your argument based on newton 's laws |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Newton'sthirdlawis applicableto onlyhuman'sactionswhichinvolve physicalforce. <a href="https://interviewquestions.tuteehub.com/tag/thirdlaw-3209667" style="font-weight:bold;" target="_blank" title="Click to know more about THIRDLAW">THIRDLAW</a> is notapplicbleto humanpsychologicalactionsor <a href="https://interviewquestions.tuteehub.com/tag/thought-1417452" style="font-weight:bold;" target="_blank" title="Click to know more about THOUGHT">THOUGHT</a></body></html> | |
| 36648. |
Which of the following is/are conservation forces(s)? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/vecf-3257300" style="font-weight:bold;" target="_blank" title="Click to know more about VECF">VECF</a>=2r^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)vecr`<br/>`vecF=-5/rhatr`<br/>`vecF=(3(xhati+yhatj))/((x^(2)+y^(2))^(3//2))`<br/>`vecF=(3(yhati+xhatj))/((x^(2)+y^(2))^(3//2))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36649. |
Figures 10.23(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect? Why |
| Answer» <html><body><p></p>Solution :Fig(a) is incorrect [Reason: at a <a href="https://interviewquestions.tuteehub.com/tag/construction-4021" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTRUCTION">CONSTRUCTION</a> (i.e., where the area of cross section of the tube is smaller). Flow <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> is larger due to mass conservation. Consequently <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> there is smaller <a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to Bernoulli.s equation. We assume the fluid to be incompressible].</body></html> | |
| 36650. |
Two equal spheres B and C, each of mass m, are in contact on a smooth horizontal table. A third sphere A of same size as that of B or C but mass m//2 impinges symmetrically on them with a velocity u and is itself brought to rest. The loss of KE during collision is |
| Answer» <html><body><p>`("mu"^(2))/8`<br/>`("mu"^(2))/<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>`<br/>`("mu"^(2))/3`<br/>`("mu"^(2))/2`</p>Solution :`u=`velocity of sphere `A` before impact. As the spheres are identical, the triangle `ABC` formed by joining their centres is equilateral. The spheres `B` and `C` will move in direction `AB` and `AC` after impact making can angle of `<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)` with the origina lines of motion of ball `A`. <br/> Let `v` be the speed ofthe balls `B` and `C` after impact. <br/> <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> conservationgives <br/> `(m/2)u=mvcos30^(@) +mvcos30^(@)` <br/> `u=2sqrt(3)vimpliesv=u/(2sqrt(3))`.......i <br/> From Newton's experimental law, for an oblique collision, we have take components along <a href="https://interviewquestions.tuteehub.com/tag/normal-1123860" style="font-weight:bold;" target="_blank" title="Click to know more about NORMAL">NORMAL</a>, i.<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>. along `AB` for balls `A` and `B`. <br/> `v_(B)-v_(A)=-e(u_(B)-u_(A))` <br/> `v-0=-e(0-ucos30^(@))` <br/> `v=eucos30^(@)`.........ii <br/> Combining eqn i and ii we get `e=1/3` <br/> Loss in `KE =1/2 m/2 u^(2)-2(1/2mv^(2))` <br/> `=1/4mu^(2)-m(u/(2sqrt(3)))^(2)=1/6mu^(2)`</body></html> | |