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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36501. |
Calculate rate of flow of glycerin of density 1.25xx10^(3) kg//m^(3)? through the conical section of a horizontal pipe, if the radii of its ends are 0.1m and 0.04m and pressure drop across its length is 10 N//m^(2) |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to continuity equation <br/>`(V_(2))/(V_(1))=(A_(1))/(A_(2))=(r_(1)^(2))/(r_(2)^(2))=((0.1)^(2))/((0.04)^(2))=(25)/(4)` <br/>and, according to Bernoulli.s equation for a horizontal tube, `P_(1)+(1)/(2)rhoV_(1)^(2)=P_(2)+(1)/(2)rhoV_(2)^(2)` <br/>`V_(2)^(2)-V_(1)^(2)=2((P_(1)-P_(2)))/(2)=<a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a>(10N//m^(2))/((1.25xx10^(3)kg//m^(3)))=16xx10^(-3)m^(2)//s^(2)` <br/>but `V_(2)=(25)/(4)V(1)=6.25V+_(1)therefore [(6.25)^(2)-1^(2)]V_(1)^(2)=16xx10^(-3)m^(2)//s^(2)` or `V_(1)~~0.0205 m//s` <br/> the <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of volume flow=`A_(1)V_(1)=pi(0.1)^(2)xx(0.02)=6.28xx10^(-4)m^(3)//s` <br/>And the rate of mass flow is `(dm)/(dt)=rhoA.V.=(1.25xx10^(3) kg//m^(3))xx(6.28xx10^(-4)m^(3)//s)=0.785 kg//s`</body></html> | |
| 36502. |
One cubic metre of an ideal gas is at a pressure of 10^5 N//m^2and temperature 300K. The gas isallowed to expand at constant pressure to twice its volume by supplying heat. If the change in internal energy in this process is 10^4 J, then the heat supplied is |
| Answer» <html><body><p>`10^5J` <br/>`10^4J`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a> xx10^4 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`2.2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^5 J`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36503. |
Two non-mixing liquids of densities rho and n rho ( n gt 1) are put in a container. The height of each liquid is h. A solid cylinder of length L and density d is put in this container. The cylinder floats with its axis vertical and length PL ( P lt 1) in the denser liquid. The density dis equal to |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`{<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> + ( n+1) p} <a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>`<br/>`{ <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> + ( n+1) p } rho`<br/>`{ 2 + ( n-1)p} rho`<br/>`{1 - ( n-1)p} rho`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36504. |
If f is the number of degrees of freedon of a gas, show that gamma =1 + (2)/(f). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :We know `C _(p) - C _(v) = <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> and (C _(p))/( C_(v)) = gamma ` <br/> <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> `C _(v) = (f R)/( 2) i.e., (R)/(C _(v)) = (2)/(f)` <br/> `therefore C _(p) = R + C _(v)` <br/> `(C _(p))/( C _(v)) = (R)/( C _(v) + 1 i.e., gamma = (2)/(f) + 1` <br/> `gamma = 1 + (2)/(f)`</body></html> | |
| 36505. |
Show that Reynold's number R=(rhov_(0)d)/(eta)is dimensionless. (rho is density of the fluid, v_(0) is the critical velocity, d is diameter through which the fluid is flowing and eta is the coefficient of viscosity of the fluid). |
| Answer» <html><body><p></p>Solution :`R=([ML^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)][<a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a>^(-1)][L])/([ML^(-1)T^(-1)])=[(ML^(-1)T^(-1))/(ML^(-1)T^(-1))]=[M^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)L^(0)T^(0)]` <br/> `therefore R` is dimensionless.</body></html> | |
| 36506. |
Define angular acceleration. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of change of angular <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> is called angular <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a>. The angular acceleration is also a vector quantity .<br/>` <a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(alpha) = (d vec(omega))/(dt)`</body></html> | |
| 36507. |
In the Ingen hauz's method to compare the thermal conductivities of different substances, the length upto which wax melted in copper and zinc rods are 9.3 cm and 5 cm respectively. Compare their thermal conductivities. |
| Answer» <html><body><p></p>Solution :Given `l_(C)=9.3cmandl_(Z)=5cm` <br/> `becauseK_(C)/K_(Z)=l_(C)^(2)/l_(Z)^(2)=((9.3cm)/(5cm))^(2)=3.46` <br/> <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, the <a href="https://interviewquestions.tuteehub.com/tag/thermal-706916" style="font-weight:bold;" target="_blank" title="Click to know more about THERMAL">THERMAL</a> conductivity of <a href="https://interviewquestions.tuteehub.com/tag/copper-933790" style="font-weight:bold;" target="_blank" title="Click to know more about COPPER">COPPER</a> is 3.46 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> that of zinc.</body></html> | |
| 36508. |
Find the emissive power from "0.3 cm"^(2) surface of filament of bulb of tungsten at 3000 K temperature. Take e=0.4 for tungsten bulb. |
| Answer» <html><body><p></p>Solution :From Stefan - Boltzmaan law, <br/> `H=AesigmaT^(4)` <br/> `=0.3xx10^(-4)xx0.4xx5.67xx10^(-8)xx(3000)^(4)` <br/> `=55.1124` <br/> `:.` H `~~` <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> (Acc. to textbook <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a>)</body></html> | |
| 36509. |
A rocket is fired vertically with a speed of 5 km s^(-1) from the earth’s surface. How far from the earth does the rocket go before returning to the earth ?Massof the earth = 6.0 × 10^(24) kg, mean radius of the earth = 6.4 xx 10^(6) m , G = 6.67 xx 10^(-11) " N "m^(2) kg^(-2). |
| Answer» <html><body><p></p>Solution :`implies` Suppose, initial speed of rocket is v and at maximum height its final speed will be <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a>. Suppose, mass of rocket is m.<br/> Radius of earth `R_E`and from <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> its height is h.<br/> From conservation of energy,<br/> on surface, `K_(1)+U_(1) = K_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+U_(2)`at maximum height <br/> `:. 1/2 mv^2 +(-(GM_Em)/R_E)=0 + (GM_Em)/((R_E+h))` <br/> `:. 1/2 mv^2= GM_(<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>)m[1/R_E-1/((R_(E)+h))]` <br/> `:. v^2=2GM_E[h/(R_E(R_E+h))]` <br/> `:. v^2 =2gR_E^2[(h)/(R_E(R_E+h))] ""[:. GM_E = gR_E^2]` <br/> `:. v^2 = 2gR_E [h/(h(R_E/h+1))]` <br/> `:. v^2=2 g R_E[1/((R_E)/h+1)]` <br/>`:. R_E/h+1 = (2g R_E)/(v^2)` <br/> `:. R_E/h = (2gR_E)/(v^2) -1` <br/> `:. R_E/h=(2 xx 9.8 xx 6.4 xx 10^6)/(25xx10^6)-1` <br/>`= 5.0176 - 1.0000` <br/> = 4.0176 <br/> `:. h= R_E/(4.0176)` <br/> `:. h = (6.4 xx10^6)/(4.0176)` <br/> `:. h = 1.59 xx10^(6)` <br/> `:. h = 1.6 xx10^(6) m` <br/> `:. h = 1.600 xx10^3 m` <br/> `:. h = 1600 km` <br/> `implies` The distance of rocket from the centre of earth, <br/> `= 6.4 xx10^(6) m + 1.6 xx10^(6) m` <br/> `= 8.0 xx 10^(6) m`</body></html> | |
| 36510. |
Explain Hooke's Law. |
| Answer» <html><body><p></p>Solution :"For small <a href="https://interviewquestions.tuteehub.com/tag/deformations-947281" style="font-weight:bold;" target="_blank" title="Click to know more about DEFORMATIONS">DEFORMATIONS</a> the stress and strain are <a href="https://interviewquestions.tuteehub.com/tag/proportional-1170279" style="font-weight:bold;" target="_blank" title="Click to know more about PROPORTIONAL">PROPORTIONAL</a> to each other". This is known as Hooke.s law.<br/>stress `prop` `therefore` strain stress `= kxx` strain <br/> where k is the proportionality constant and is known as modulus of elasticity. <br/> Hooke.s law is an empirical law and it is <a href="https://interviewquestions.tuteehub.com/tag/valid-723164" style="font-weight:bold;" target="_blank" title="Click to know more about VALID">VALID</a> for most materials.<br/>However, there are some materials which do not exhibit this linear relationship.<br/> SI unit of k is `Nm^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) or Pa`<br/>Dimensional formula is `[M^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) L^(-1) T ^(-2)]`</body></html> | |
| 36511. |
If an object is dropped from the top of a building and it reaches the ground at t = 4s, then the height of the building is (ignoring air resistance)(g=9.8ms^(-2)) |
| Answer» <html><body><p>77.3m<br/>78. <a href="https://interviewquestions.tuteehub.com/tag/4m-318788" style="font-weight:bold;" target="_blank" title="Click to know more about 4M">4M</a> <br/>80.5 m<br/>79.2m</p>Answer :D</body></html> | |
| 36512. |
Which of the following combinations of properties would be most desirable for a cooking pot ? |
| Answer» <html><body><p>High specific <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> and <a href="https://interviewquestions.tuteehub.com/tag/low-537644" style="font-weight:bold;" target="_blank" title="Click to know more about LOW">LOW</a> thermal conductivity <br/>Low specific heat and high thermal conductivity <br/>High specific heat and high thermal conductivity <br/>Low specific heat and low thermal conductivity </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36513. |
What is the pressure on a swimmer 10 m below, the surface of a lake ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Here, `h = 10 m, <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> = 9.8 ms^(-2) , rho_w = 1000 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> m^(-3)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> on a swimmer10 m below the surface of the lake. <br/> `P = P_(a) + h rho g = (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> xx 10^5) + (10 xx 9.8 xx 10^3)` <br/> `=10 xx 10^4 + 9.8 xx 10^4 = 19.8 xx 10^4` <br/> `P = 1.98 xx 10^5 ~~ 2 atm`.</body></html> | |
| 36514. |
A pendulum clock of an iron rod is connected to a small, heavy bob. If it shows correct time at 20^(0)C, how fast or slow will itgo in one day at 40^(0)C ? (Coefficient of linear expansion for steel is 12 xx 10^(-6)//^(0)C . ) |
| Answer» <html><body><p></p>Solution :We known `(<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> T)/(T) = (1)/(2) alpha Delta t` <br/> `rArr (T_(2) - T_(1))/(T_(1)) = (1)/(2) alpha (t_(2) - t_(1))` <br/> Which is the fractional <a href="https://interviewquestions.tuteehub.com/tag/loss-1079380" style="font-weight:bold;" target="_blank" title="Click to know more about LOSS">LOSS</a> of time . As the temperature period increases and the clock loses time or goes slow. <br/> The time lost in one day (or in <a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a> <a href="https://interviewquestions.tuteehub.com/tag/hours-1030090" style="font-weight:bold;" target="_blank" title="Click to know more about HOURS">HOURS</a>) <br/> `((1)/(2) alpha (t_(2) - t_(1)) ) = (86400 s) (1)/(2) alpha (t_(2) - t_(1))` <br/> = 43200 `alpha (t_(2) - t_(1)) s ` <br/> In this problem, `alpha = 12 xx 10^(-6)//^(0)C`, <br/> `t_(1) = 20^(0)C , t_(2) = 40^(0)C ` <br/> The time lost in one day = 43200 `xx 12 xx 10^(-6) (40 - 20)` = 10.368 s.</body></html> | |
| 36515. |
Define angular frequency. Giveits S.I. unit. |
| Answer» <html><body><p></p>Solution :It is the angel <a href="https://interviewquestions.tuteehub.com/tag/covered-2552266" style="font-weight:bold;" target="_blank" title="Click to know more about COVERED">COVERED</a> per unit time or it is the <a href="https://interviewquestions.tuteehub.com/tag/quantity-1174212" style="font-weight:bold;" target="_blank" title="Click to know more about QUANTITY">QUANTITY</a> <a href="https://interviewquestions.tuteehub.com/tag/obtained-7273275" style="font-weight:bold;" target="_blank" title="Click to know more about OBTAINED">OBTAINED</a> by multiplying frequency by a factor of `2pi`. `omega = 2pin`, S.I. Unit is <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a>`s-^1`</body></html> | |
| 36516. |
The escape velocity for a body projected vertically upwards from the surface of Earth is 11"kms"^(-1)If the body is projected at an angle of45^(@) with verical, the escape velocity will be ........ |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`11sqrt(2)`<br/>22<br/>11</p>Solution :Escape velocity does not depends upon the <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of projection</body></html> | |
| 36517. |
The displacement of particle is represented by the equation y=3cos((pi)/4-2omegat). The motion of the particle is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> harmonic with particle is `(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>)` <br/>simple harmonic with period `(<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(omega)`<br/>periodic but not simple harmonic<br/>non periodic</p>Answer :B</body></html> | |
| 36518. |
A screen is placed at a distance of 90 cm from an object. The image of this object is formed on the screen by a convex lens at two different location separated by 20cm. The focal length of the lens is |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :By the displacement method <br/> `f=(d^2-x^2)/(<a href="https://interviewquestions.tuteehub.com/tag/4d-318718" style="font-weight:bold;" target="_blank" title="Click to know more about 4D">4D</a>)= f=(90^2-20^2)/( 4 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> 90)= 21.4 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`</body></html> | |
| 36519. |
A metal sphere is electrically charged to Q_(0) and hangs on an insulting cord. The sphere slowly loses it charge because the air has a non zero resistivity rho. The potential of sphere of radius r_(0) is to be calculated with reference to infinity. Assume that resistivity of air is every where the same. Mass the correct statements |
| Answer» <html><body><p>Capacitance of sphere is `<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> pi epsilon_(0)r_(0)`<br/><a href="https://interviewquestions.tuteehub.com/tag/electrical-968148" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRICAL">ELECTRICAL</a> resistance of air is `R = (rho)/(4 pi r_(0))`<br/>Initial current is `(Q_(0))/(rho epsilon_(0))`<br/>Time in which charge gets <a href="https://interviewquestions.tuteehub.com/tag/halved-2104643" style="font-weight:bold;" target="_blank" title="Click to know more about HALVED">HALVED</a> is `rho epsilon_(0) ln 2`</p>Answer :A::B::C::D</body></html> | |
| 36520. |
Two soap bubbles of radii in the ratio of 2 : 1. What is the ratio of excess pressure inside them? |
| Answer» <html><body><p>`1:2` <br/>`1:<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>` <br/>`2:1 ` <br/>`4:1` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> P_1)/(Delta P_2) = ( (4 <a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>)/(r_1))/( (4sigma)/(r_2) ) = r_2/r_1 = 1/2`</body></html> | |
| 36521. |
The linear momentum of a particle varies with time as p=a_(0)+at+bt^(2). Which of the following graph represents force and time relation ? |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C05_E03_020_O01.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C05_E03_020_O02.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C05_E03_020_O03.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C05_E03_020_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36522. |
A particle falls towards the earth from infinity. The velocity with which it reaches earth's surface (g rarr acceleration due to gravity on earth's surface and R is the radius of the earth) |
| Answer» <html><body><p>2gR<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2gR)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/gr-1010452" style="font-weight:bold;" target="_blank" title="Click to know more about GR">GR</a>)`<br/>R/g</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36523. |
A fully loaded boeing aircraft has a mass of 3.3xx10^(5)kg . Its total wing area is 500m^(2) .It is in level flight with a speed of 96.km//h. (a)Estimate the pressure difference between the lower and upper surfaces of the wings . (b) Estimate the fractional increase in thespeed of the air on the upper surface of the wing relative to the lower surface. (The density of air is rho=1.2kgm^(-3))(g=9.8ms^(-2)) |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :The weight of the boeing aircraft is balanced by the upward force <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to the pressure difference `=DeltaPxxA`<br/>`mg=DeltaPxxA`<br/>`thereforeDeltaP=(mg)/(A)`<br/>`=(3.3xx10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)xx9.8)/(500)`<br/>`0.06468xx10^(5)`<br/> `therefore` Pressure difference `=6468Nm^(-2)`<br/>(b)From Bernoulli.s equation,<br/>`P_(1)-P_(2)=(1)/(2)rho(v_(2)^(2)-v_(1)^(2))+rhog(h_(2)-h_(1))`<br/>Neglecting `h_(2)-h_(1)` for its small value,<br/>`thereforeP_(1)-P_(2)=(1)/(2)(rho(v_(2)^(2)-v_(1)^(2))`<br/>`therefore(2DeltaP)/(rho)=(v_(2)-v_(1))(v_(2)+v_(1))`<br/>`thereforev_(2)-v_(1)=(2DeltaP)/(rho(v_(2)+v_(1))=(DeltaP)/(rho((v_(2)+v_(1))/(2)))`...(1)<br/>Now average speed`ltvgt=(v_(1)+v_(2))/(2)`<br/>`=(960xx1000)/(<a href="https://interviewquestions.tuteehub.com/tag/3600-1859327" style="font-weight:bold;" target="_blank" title="Click to know more about 3600">3600</a>)`<br/>`=266.6ms^(-1)`<br/>`thereforev_(2)-v_(1)=(DeltaP)/(rholtvgt)=(6468)/(1.2xx266.6)`<br/> `=20.21ms^(-1)`<br/>`therefore(v_(2)-v_(1))/(ltvgt)=(20.21)/(267)"" (because` From equation (1))<br/> `=0.0756`<br/> `=0.8`<br/>Hence , speed above the wing needs to be only `8%` higher than that below.</body></html> | |
| 36524. |
In which process (isothermal or adiabatic) there is a greater change in internal energy? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a></body></html> | |
| 36525. |
If 300 ml of a gas at 27^(@)C is cooled to 7^(@)Catconstant pressure, then its final volume will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/540-325109" style="font-weight:bold;" target="_blank" title="Click to know more about 540">540</a> ml <br/><a href="https://interviewquestions.tuteehub.com/tag/350-308849" style="font-weight:bold;" target="_blank" title="Click to know more about 350">350</a> ml <br/>280 ml <br/>135 ml </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36526. |
Two plane mirrors are arranged at right angles to each other as shown in figure. A ray of light is incident on the horizontal mirror at an angle theta For what value of theta the ray emerges parallel to the incoming ray after reflection from the vertical mirror? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^@`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^@`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^@`<br/>All of these</p>Answer :D</body></html> | |
| 36527. |
Find the minimum radius of a planet of mean density 5500kgm^(-3) and temperature 400^(@)C which has retained oxygen in its atmosphere. Density of oxygen at STP =1.424kgm^(-3). G=6.6xx10^(-11)Nm^(2)kg^(-2) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`4.15xx10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)m`</body></html> | |
| 36528. |
In the question number 55, the ratio of elongation of steel to the copper wires is |
| Answer» <html><body><p>`(5)/(2)`<br/>`(2)/(5)`<br/>`(3)/(2)`<br/>`(2)/(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :From Eq.(i), of <a href="https://interviewquestions.tuteehub.com/tag/theabovesolution-3192085" style="font-weight:bold;" target="_blank" title="Click to know more about THEABOVESOLUTION">THEABOVESOLUTION</a>,we get`(DeltaL_(S))/(DeltaL_(C)) = (L_(S))/(L_(C)) xx (Y_(C))/(Y_(S))` <br/>Substitution the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> values,we get<br/>`(DeltaL_(S))/(DeltaL_(C)) = (1.6 m)/(2.4 m)xx (1.2 xx 10^(11) N m^(-2))/(2 xx 10^(11) N m^(-2)) = (2)/(5)`</body></html> | |
| 36529. |
The radius of the Earth is 6400 km and g = 10 in order that a body of 5 kg weights zero at the equator, the angular speed of the Earth is ............ rad |
| Answer» <html><body><p>`1/80`<br/>`1/400`<br/>`1/800`<br/>`1/600`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For condition of <a href="https://interviewquestions.tuteehub.com/tag/weightlessness-1451441" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHTLESSNESS">WEIGHTLESSNESS</a> at <a href="https://interviewquestions.tuteehub.com/tag/equator-974243" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATOR">EQUATOR</a> `omega = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(g/R) = 1/800 ` rad/sec</body></html> | |
| 36530. |
A particle is executing a simple harmonic motion. Its maximum acceleration is alpha and maximum velocity is beta. Then, its time period of vibration will be……… |
| Answer» <html><body><p>`(2pi <a href="https://interviewquestions.tuteehub.com/tag/beta-2557" style="font-weight:bold;" target="_blank" title="Click to know more about BETA">BETA</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>)`<br/>`(beta^2)/(alpha^2)`<br/>`(alpha)/(beta)`<br/>`(beta^2)/(alpha)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> acceleration in <a href="https://interviewquestions.tuteehub.com/tag/shm-630759" style="font-weight:bold;" target="_blank" title="Click to know more about SHM">SHM</a> <br/> `a_("max")= A omega^(2)` <br/> `therefore alpha = A omega^(2)` and <br/> Maximum velocity `v_("max")= A omega` <br/> `therefore beta = A omega` <br/> `therefore (a_("max"))/(v_("max"))= (A omega^(2))/(A omega)` <br/> `(alpha)/(beta)= omega` <br/> `therefore (alpha)/(beta)= (2pi)/(T)` <br/> `therefore T= 2pi (beta)/(alpha)`.</body></html> | |
| 36531. |
What are the different types of longtitudinal strain? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Longitudinal strain can be classified into two types:(i) Tensile strain:If the length is incrases from its <a href="https://interviewquestions.tuteehub.com/tag/natural-575613" style="font-weight:bold;" target="_blank" title="Click to know more about NATURAL">NATURAL</a> length then it is knownas tensile strain.<br/>(ii) Compressive strain:If the length is decreased from its natural length then it is <a href="https://interviewquestions.tuteehub.com/tag/known-534098" style="font-weight:bold;" target="_blank" title="Click to know more about KNOWN">KNOWN</a> as compressive strain.</body></html> | |
| 36532. |
During damped vibration, the quantity which gradually decrease is |
| Answer» <html><body><p>velocity<br/>phase<br/>frequency<br/>amplitude</p>Answer :D</body></html> | |
| 36533. |
Four moels of a perfect gas is heated to increase its temperature by 2^(0)C absorbsheat of 40 cal at constant volume. If the same gas is heated at constant pressure find the amount of heat supplied. (R = 2 cal/molK). |
| Answer» <html><body><p></p>Solution :Number of moles n = 4 <br/> Change in <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>`Deltat=2` <br/> Heat <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> absorbed `dQ=40` cal. <br/> <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> constant `R = 2` cal/mole <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> <br/> Heat energy absorbed at constant pressure <br/> `dQ = dU +dW` per mole per kelvin. <br/> But `dU = C_(v)<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a> and dW = P dV` <br/> `C_(p)=C_(v) +R`Multiply with n.dT <br/> `nC_(p)dT=nC_(v)dT +nRdT` <br/> `nC_(p)dT =` Heat energyabsorbed at constant pressure by n moles of gas. <br/> `nC_(v)dT=dU =`Heat energy absorbed at constant volume. <br/> `:.dQ=dU+nRdT =40+4xx2xx2=56`cal <br/> Heat energy absorbed at constant presure when 4 moles of air is heated through `2^(0)=56`cal.</body></html> | |
| 36534. |
A particle revolves round a circular path. The acceleration of the particle is inversely proportional to |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of particle <br/>radius<br/>velocity<br/>both (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) and (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 36535. |
Arrange the following colours is increasing order of their critical angles with respect to glass (A) red (B) yellow ( C) blue (D) violet |
| Answer» <html><body><p>a,b,<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>,d<br/>a,c,b,d<br/>d,c,b,a<br/>a,d,b,c</p>Answer :C</body></html> | |
| 36536. |
Mention the clockwise moment of a force. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> <a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a></body></html> | |
| 36537. |
Two blocks A and B of mass m and 2m respectively are moving towards a massive ("mass" gt gt 2m) cliff with velocities 2v and v respectively. The cliff moves with a velocity v. If the coefficient of restitution of collision at the surface of the cliff is e = 1//2, find the: a. velocity of the block B just after colliding with the cliff. b. work done by the cliff during collision. c. maximum compression of the spring of stiffness k which is fitted with the block B. |
| Answer» <html><body><p><br/></p>Solution :As the cliff is very heafy so its velocity <a href="https://interviewquestions.tuteehub.com/tag/almost-373246" style="font-weight:bold;" target="_blank" title="Click to know more about ALMOST">ALMOST</a> remains same after collision. <br/> Let velocilty of <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> `B` just after Collision be `v_(1)` <br/> `v_(2)-v_(1)=<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>[u_(1)u_(2)]` <br/> `impliesv-v_(1)=1/2[2-v]impliesv_(1)=v/2` b. work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> by clif =change in `<a href="https://interviewquestions.tuteehub.com/tag/ke-527890" style="font-weight:bold;" target="_blank" title="Click to know more about KE">KE</a>` of `m` <br/> `1/2m[(v/2)^(2)-(2)^(2)]a=-15/8mv^(2)` <br/> c. Just after collision with cliff <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VOL2_C01_E01_085_S01.png" width="80%"/> <br/> At maximum compression <br/> `COLM: 2mv_(0)+mv_(0)=2mv+(mv)/2impliesv_(0)=5/6v` <br/> COME:` 1/2kx_(m)^(2)+1/2(3m)v_(0)^(2)=1/2(2m)v^(2)+1/2m(v/2)^(2)` <br/> `implies x_(m)=(sqrt(m/(6k)))v`</body></html> | |
| 36538. |
When a satellite moves around the earth in a certain orbit, the quantity which remains constant is : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a><br/>kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a><br/>aerial velocity<br/>potential energy </p>Solution :From <a href="https://interviewquestions.tuteehub.com/tag/kepler-531882" style="font-weight:bold;" target="_blank" title="Click to know more about KEPLER">KEPLER</a>'s law velocity remains instant</body></html> | |
| 36539. |
Velocity of a wave y = 10 ^(-4) sin (100 t - (x)/(10)) m is …...m/s |
| Answer» <html><body><p>100<br/>4<br/><a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a><br/>10</p>Solution :Comparing <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> equation with <br/> `y = a sin (<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a> t - <a href="https://interviewquestions.tuteehub.com/tag/kx-1064991" style="font-weight:bold;" target="_blank" title="Click to know more about KX">KX</a>) ` we get, <br/> `v = (omega )/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>) = (100)/(1//10) = 1000 (m)/(s)`</body></html> | |
| 36540. |
(A) : Collision between two particles is not necessarily associated with physical contact between them (R): Only in physical contact, momentum transfer takes place |
| Answer» <html><body><p> Both .A. and .<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>. are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and .R. is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of .A. <br/> Both .A. and .R. are true and .R. is not the correct explanation of .A. <br/>A. is true and .R. is false <br/>A. is false and .R. is true</p>Answer :C</body></html> | |
| 36541. |
velocity of ground with respect to B |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Velocity of ground with respect to <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> <br/> `=0-v_B-v_A=0-(-<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>)=25m//s` <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> north</body></html> | |
| 36542. |
Two particles of masses in the ratio 1: 2 you're moving in circles of radii in the ratio 2:3 with time periods in the ratio 3: 4. The ratio of their centripetal forces is |
| Answer» <html><body><p> 9:4<br/> 1:4<br/> 9:16<br/> 16:27</p>Answer :D</body></html> | |
| 36543. |
10 grams of ice at -20^(@)C is added to 10 grams of water at 50^(@)C. The amount of ice and water that are present at equilibrium respectively |
| Answer» <html><body><p>0,20g<br/>5g, 15g<br/>5g, 10g<br/>10g, 10g</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36544. |
The average translational kinetic energy of O_2, molecules at a particular temperature is 0.048 eV. The average translational kinetic energy of equal number of N, molecules at the same temperature is (in eV) |
| Answer» <html><body><p>0.016<br/>0.032<br/>0.048<br/>0.768</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36545. |
For which of the following does the centre of mass lie outside the body? |
| Answer» <html><body><p>A <a href="https://interviewquestions.tuteehub.com/tag/pencil-590779" style="font-weight:bold;" target="_blank" title="Click to know more about PENCIL">PENCIL</a> <br/>A shotput<br/>A <a href="https://interviewquestions.tuteehub.com/tag/dice-951060" style="font-weight:bold;" target="_blank" title="Click to know more about DICE">DICE</a> <br/>A <a href="https://interviewquestions.tuteehub.com/tag/bangle-389355" style="font-weight:bold;" target="_blank" title="Click to know more about BANGLE">BANGLE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36546. |
What do you understand by the word speculaar reflection ? |
| Answer» <html><body><p></p>Solution :Specular <a href="https://interviewquestions.tuteehub.com/tag/reflection-13747" style="font-weight:bold;" target="_blank" title="Click to know more about REFLECTION">REFLECTION</a> is <a href="https://interviewquestions.tuteehub.com/tag/observed-582965" style="font-weight:bold;" target="_blank" title="Click to know more about OBSERVED">OBSERVED</a> only when the <a href="https://interviewquestions.tuteehub.com/tag/wavelength-1450414" style="font-weight:bold;" target="_blank" title="Click to know more about WAVELENGTH">WAVELENGTH</a> of the source is smaller than <a href="https://interviewquestions.tuteehub.com/tag/dimensions-439808" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONS">DIMENSIONS</a> of the reflecting surface, as well as smaller than surface irregularities.</body></html> | |
| 36547. |
A circular disc rolls on a horizontal floor without slipping and the centre of the disc moves with a uniform velocity v. Which of the following values the velocity at a point on the rim of the disc can have? |
| Answer» <html><body><p>v<br/>`-v`<br/>2v<br/>zero<br/></p>Solution :Velocity of the point of <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> of the circular <a href="https://interviewquestions.tuteehub.com/tag/disc-955290" style="font-weight:bold;" target="_blank" title="Click to know more about DISC">DISC</a> with respect to the horizontal <a href="https://interviewquestions.tuteehub.com/tag/floor-993091" style="font-weight:bold;" target="_blank" title="Click to know more about FLOOR">FLOOR</a> = v - v = 0 <br/> Velocity of the farthest point = v + v = 2v <br/> Horizontal velocity of the left or right end point <br/> = velocity of the <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> of the disc <br/> = v <br/> The option A, C and D is correct.</body></html> | |
| 36548. |
A 5 kg collar is attached to a spring of spring constant 500 N m^(-1). It slides without friction over a horizontal rod. The collar is displaced from its equilibrium position by 10.0 cm and released. Calculate (a) the period of oscillation, (b) the maximum speed and (c) maximum acceleration of the collar. |
| Answer» <html><body><p></p>Solution :(a) The period of <a href="https://interviewquestions.tuteehub.com/tag/oscillation-1139998" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATION">OSCILLATION</a> as given by Eq. (14.21) is, <br/> `T=2pisqrt(m/k)=2pisqrt((5.0kg)/(500Nm^(-1)))` <br/> `=(2pi//10)s` <br/> `=0.63s` <br/> (b) The <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of the collar executing SHM is given by, <br/> `v(t)=Aomega` <br/> `=0.1xxsqrt(k/m)` <br/> `=0.1xxsqrt((500Nm^(-1))/(<a href="https://interviewquestions.tuteehub.com/tag/5kg-326499" style="font-weight:bold;" target="_blank" title="Click to know more about 5KG">5KG</a>))` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/1ms-1803776" style="font-weight:bold;" target="_blank" title="Click to know more about 1MS">1MS</a>^(-1)` <br/> and it occurs at x = 0 <br/> (c) The acceleration of the collar at thedisplacement x (t ) from the equilibrium is given by, <br/> `a(t)=-omega^(2)xt` <br/> `=-k/mx(t)` <br/> Therefore, the maximum acceleration is, <br/> `a_("max")=omega^(2)A` <br/> `(500Nm^(-1))/(5kg)xx0.1m` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/10ms-267176" style="font-weight:bold;" target="_blank" title="Click to know more about 10MS">10MS</a>^(-2)` <br/> and it occurs at the extremities.</body></html> | |
| 36549. |
Two balls of equal masses movin with velocities 10m/s and -7m/s respectively collide elatically. There velocities after collision with be |
| Answer» <html><body><p>`7 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1) and 17ms^(-1)`<br/>`-7ms^(-1) and 10ms^(-1)`<br/>`10ms^(-1) and -7ms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3ms-1863586" style="font-weight:bold;" target="_blank" title="Click to know more about 3MS">3MS</a>^(-1) and -<a href="https://interviewquestions.tuteehub.com/tag/70ms-334138" style="font-weight:bold;" target="_blank" title="Click to know more about 70MS">70MS</a>^(-1)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36550. |
The circular motion of a particle with constant speed is………. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> but not <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a> <br/>simple harmonic but not periodic<br/>periodic and simple harmonic<br/>none of these</p>Solution :Simple harmonic but not periodic.</body></html> | |