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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36401. |
The motor of an engine is rotating about its axis with angular velocity of 120 r.p.m. it comes to rest in 10s, after being switched off. Assuming constant decleration, calculate the number of revolutions made by it before coming to rest. |
| Answer» <html><body><p></p>Solution :Here, `omega_(0)=120 ` r.p.m. = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> r.p.s. `= 4pi rad s^(-1)`<br/>`omega = 0`and `t=10 s "" omega = omega_(0)+at`<br/>`0=4pi+axx10` or `a=-0.4 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> rad s^(-2)`<br/>Also, the angle covered by the <a href="https://interviewquestions.tuteehub.com/tag/motor-1104203" style="font-weight:bold;" target="_blank" title="Click to know more about MOTOR">MOTOR</a>,<br/>`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> = omega_(0)t+(1)/(2)at^(2)`<br/>`because theta = 4pi xx10+(1)/(2)xx(-0.4 pi)xx10^(2)=40 pi-20pi`<br/>`= 20 pi` rad<br/>Hence, the number of revolutions completed, <br/>`n =(theta)/(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)=(20pi)/(2pi)=10`</body></html> | |
| 36402. |
An electron of mass m is involved in head-on collision with an atom of mass M , initially at rest . As a result of the collision a certain amount of energy E is stored internally in the atom . What is the minimum initial velocity that the electron must have ? [Hint : Since energy is stored in the atom , the collision is essentially inelastic . mv = mv' + Mv'' and (1)/(2) mv^(2) = E + (1)/(2) mv^(2) + (1)/(2) Mv''^(2) . Solve for v' and apply the condition for real values of v'.) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(m + M) <a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a>))`</body></html> | |
| 36403. |
A stone is tied at end of string and whirled in horizontal plane with circular path of radius 20 cm. If its acceleration is 980 cms^(-2), then what will be its angular speed ? |
| Answer» <html><body><p></p>Solution :Centripetalacceleration <br/> `a_(c )= (<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(2))/( r )` <br/> `=r epsilon^(2) ` <br/> `epsilon = sqrt((a)/(r )) = sqrt((960)/( <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>))` <br/> `epsilon = sqrt(<a href="https://interviewquestions.tuteehub.com/tag/49-318440" style="font-weight:bold;" target="_blank" title="Click to know more about 49">49</a>) =7 (rad)/( s )`</body></html> | |
| 36404. |
The angle of inclination of an inclined plane is 60^(@). Coefficient of friction between 10kg body on it and its surface is 0.2, g=10 ms^(-2). The acceleration of the body down the plane in ms^(-2)is |
| Answer» <html><body><p>5.667<br/>6.66<br/>7.66<br/>Zero</p>Solution :`F=ma, a = <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> (<a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>-mu_(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)<a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta)`</body></html> | |
| 36405. |
The volume V of a liquid crossing through a tube is related to the area of cross-section A, velocity v and times t as V alpha A^(a) v^(b) t^(c ) which of the following is correct |
| Answer» <html><body><p>`a <a href="https://interviewquestions.tuteehub.com/tag/ne-1112263" style="font-weight:bold;" target="_blank" title="Click to know more about NE">NE</a> <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> ne <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`a = b = c`<br/>`a ne b = c`<br/>`a= b ne c`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 36406. |
At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the rms speed of a helium gas atom at - 20 ^(@)C ? (atomic mass of Ar = 39.9 u, of He = 4.0 u). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`2.52 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>`</body></html> | |
| 36407. |
A physical quantity Q is found to depend on quantities x,y,z obeying relation Q = (x^(2)y^(3))/(z^(1)) . The percentage errors in x, y, and z are 2%, 3% and 1% respectively. Find the percentage error in Q. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = `(x^(2)y^(3))/(<a href="https://interviewquestions.tuteehub.com/tag/z-750254" style="font-weight:bold;" target="_blank" title="Click to know more about Z">Z</a>)` <br/> It is given, `(Deltax)/(x) = 2%, (Deltay)/(y)= 3%, (Deltaz)/(z) = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>%` <br/> `(DeltaQ)/(Q) = 2((Deltax)/(x)) + 3((Deltay)/(y)) + 1 ((Deltaz)/(z)) = 2(2%) + 3(3%) +1(1%)` <br/> `(DeltaQ)/(Q) = 4% + 9% + 1% = 14%`</body></html> | |
| 36408. |
1000 drops of a liquid each of diameter 4 mm coasesce to form a single large drop. If surface tension of liquid is 35 dyne cm^(-1). Calculate the energy evolvedby the system in the process. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of drops ` n =1000 impliesn^(1//3)=10impliesn^(2//3)=100` <br/> <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> tension of liquid `S=35"dyne"cm^(-1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> of each small drop `r=2mm=0.2cm` <br/> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> evolved in merging <br/> `W=4pir^(2)S[n-n^(2//3)]` <br/> `impliesW=4xx22/7xx(2xx10^(-1))^(2)35[1000-100]` <br/> `impliesW=(88xx35xx4xx10^(-2))/6[900]` <br/> `=15840` ergs `~~1.58xx10^(-3)J`</body></html> | |
| 36409. |
The value of universal gas.Constant is 8.3 J/moK, the mean kinetic energy of 32gm of oxygen at -73^(@)C will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/480-1879936" style="font-weight:bold;" target="_blank" title="Click to know more about 480">480</a> J<br/>4780J<br/>2490J<br/>100J</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36410. |
Find the ratio of escape velocities from the earth and the moon. (Mass of the earth = 6.0 xx 10^(24) kg, Radius of the earth = 6400 km, Mass of the moon = 7.4 xx 10^(22) kg Radius of the moon = 1740 km.) |
| Answer» <html><body><p></p>Solution :`V_(e) prop <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((M)/(R))` <br/> `(V_(e1))/(V_(<a href="https://interviewquestions.tuteehub.com/tag/e2-961697" style="font-weight:bold;" target="_blank" title="Click to know more about E2">E2</a>)) = sqrt(((6.0xx 10^(24))/(7.4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)))((1740)/(6400))) = (4.695)/(1)`</body></html> | |
| 36411. |
Two light trollwys of masses m_(1) and m_(2) (= 3m_(1)) are connected by a spring. The spring is compressed and bound by a cord. The cord is burnt through, the spring expands and the trolleys move off in opposite direction. Assume that the coefficient of friction is the same for both trollwys. |
| Answer» <html><body><p>The relationship between the velocties `v_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` and `v_(2)` of the trolleys is `v_(1)//v_(2) = <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>The relationship between the periods `t_(1)` and `t_(2)` during which the trolleys <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> `t_(1)//t_(2) = 3` <br/>The relationship between the <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> `s_(1)` and `s_(2)` travelled by the trolleys is `s_(1)//s_(2) = 3`<br/>The relationship between the force of friction `f_(1)` and `f_(2)` acting on the two trolleys is `f_(1)//f_(2) = (1)/(3)`</p>Answer :A::B::D</body></html> | |
| 36412. |
A track (ACB) is in the shape of an arc of a circle. It is held fixed in vertical plane with its radius OA horizontal. A small block is released on the inner surface of the track from point A. It slides without friction and leaves the track at B. What should be value of q so that the block travels the largest horizontal distance by the time it returns to the horizontal plane passing through B? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`theta=tan^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)(1/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))`</body></html> | |
| 36413. |
A stone dropped froma cliff the ground in 4 sec. Height of the cliff is |
| Answer» <html><body><p>39.2 m <br/>29.4 m <br/>9.8 m <br/>78.4 m </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36414. |
One gets less hurt when one jumps from a height on sand than on hand floor. Why ? |
| Answer» <html><body><p></p>Solution :When a man jumps on any surface, the surface in contact with the man gets a <a href="https://interviewquestions.tuteehub.com/tag/little-1075899" style="font-weight:bold;" target="_blank" title="Click to know more about LITTLE">LITTLE</a> depressed. This depression is more in the case of a sandy surface than of a hand floor. The initial potential energy of the man is the same in both cases. So the kinetic energy just before <a href="https://interviewquestions.tuteehub.com/tag/hitting-2711575" style="font-weight:bold;" target="_blank" title="Click to know more about HITTING">HITTING</a> the ground is also the same. <br/> Suppose , the mass of the man = m and he jumps from a height h. The average reaction force of the ground on him is <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>. He stops after depressing the ground by x. so his kinetic energy is used up in <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done against the <a href="https://interviewquestions.tuteehub.com/tag/net-5194" style="font-weight:bold;" target="_blank" title="Click to know more about NET">NET</a> reaction force R-mg. As kinetic energy just before hitting the ground = potential energy at height = h =mgh , <br/> `(R -mg )x =mghor, R =(1+ h/x) mg` <br/> As x is more for a sandy surface , R is less and hence, the man is less hurt.</body></html> | |
| 36415. |
The unit vector parallel to the resultant of the vectors A = 4i+3j + 6k and B = -i + 3j-8k is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(7) (3 hat(i) + 6hat(<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>) - 2hat(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>))`<br/>`(1)/(2) (<a href="https://interviewquestions.tuteehub.com/tag/3hat-1863202" style="font-weight:bold;" target="_blank" title="Click to know more about 3HAT">3HAT</a>(i) + 6hat(j) + 2hat(k))`<br/>`(1)/(49) (3 hat(i) + 6hat(j) - 2hat(k))`<br/>`(1)/(49) (3hat(i) - 6hat(j) + 2hat(k))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36416. |
A stone is projected from level ground with speed u and ann at angle theta with horizontal. Somehow the acceleration due to gravity (g) becomes double (that is 2g) immediately after the stone reaches the maximum height and remains same thereafter. Assume direction of acceleration due to gravity always vertically downwards. Q. The horizontal range of particle is |
| Answer» <html><body><p>`(3)/(4)(<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>^(2)sin2theta)/(g)` <br/>`(u^(2)sin 2theta)/(2g) (1+(1)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2)))`<br/>`(u^(2))/(g) sin 2theta` <br/>`(u^(2)sin2theta)/(2g) (2+(1)/(sqrt(2)))`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The time taken to <a href="https://interviewquestions.tuteehub.com/tag/reach-1178062" style="font-weight:bold;" target="_blank" title="Click to know more about REACH">REACH</a> maximum <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> and maximum height are `t=(usintheta)/(g)andH=(u^(2)sin^(2)theta)/(2g)` <br/> For remaining half, the time of flight is <br/> `t'=sqrt((2H)/((2g)))=sqrt((u^(2)sin^(2)theta)/(2g^(2)))=(t)/(sqrt(2))` <br/> `:.` Total time of flight is `t+t',T=t(1+(1)/(sqrt(2)))` <br/> `T=(usintheta)/(g)=(1+(1)/(sqrt(2)))` <br/> So horizontal range is u `costhetaxxT=(u^(2)sin2theta)/(2g)(1+(1)/(sqrt(2)))`</body></html> | |
| 36417. |
A bomb is dropped from an aeroplanewhen it is directly above a target at an height of 1000m .The aeroplane is moving horizontally with a speed of 500 kmh^(-1). By how much distance will the bomb miss the target ? |
| Answer» <html><body><p></p>Solution :As the aeroplane ismoving horizontally , the initial <a href="https://interviewquestions.tuteehub.com/tag/downward-2061463" style="font-weight:bold;" target="_blank" title="Click to know more about DOWNWARD">DOWNWARD</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of the bomb , `u_(y) = 0`<br/>Also, y = 1000 m `g = 9 . 8 ms^(-2) , t = ?`<br/>`:. 1000 = 0 + (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2) xx 9 . 8t^(2)`<br/>` = 4 . 9 t^(2)`<br/>(or)`t = sqrt((1000)/(4 . 9)) = (100)/(7) s`<br/> `{:("Horizontal"),("velocity of the"),("aeroplane"):}} = 500 kmh^(-1)`<br/>`= 500 xx (5)/(18) ms^(-1)`<br/>`= (<a href="https://interviewquestions.tuteehub.com/tag/1250-1782936" style="font-weight:bold;" target="_blank" title="Click to know more about 1250">1250</a>)/(9) ms^(-1)`<br/>`{:("<a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> by"),("Which the bomb"),("misses the target"):}} = {{:("Horizontal distance covered"),("by the bomb before it"),("hits the ground"):}`<br/>= Horizontal velocity `xx`time<br/>`= (1250)/(9) xx (100)/(7) = 1984. 13 m `</body></html> | |
| 36418. |
Explain elasticity using intermolecular forces. |
| Answer» <html><body><p></p>Solution :When a deforming force is applied in a solid, its atoms are pulled apart or <a href="https://interviewquestions.tuteehub.com/tag/bind-897680" style="font-weight:bold;" target="_blank" title="Click to know more about BIND">BIND</a> <a href="https://interviewquestions.tuteehub.com/tag/together-3221943" style="font-weight:bold;" target="_blank" title="Click to know more about TOGETHER">TOGETHER</a>. When the deforming force is removed, interatomic forces of attraction or repulsion restore the atoms to their <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> positions. If a body <a href="https://interviewquestions.tuteehub.com/tag/regains-613784" style="font-weight:bold;" target="_blank" title="Click to know more about REGAINS">REGAINS</a> its original shape and size after theremoval of deforming force, it is said to be elastic and the <a href="https://interviewquestions.tuteehub.com/tag/property-1170155" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTY">PROPERTY</a> is called elasticity.</body></html> | |
| 36419. |
Distinguish between cohesive and adhesive forces. |
| Answer» <html><body><p></p>Solution :The force between the like <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> which holds the liquid <a href="https://interviewquestions.tuteehub.com/tag/together-3221943" style="font-weight:bold;" target="_blank" title="Click to know more about TOGETHER">TOGETHER</a> is called .cohesive force.. When the liquid is in <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> with a solid, the molecules of the these solid and liquid will experience an <a href="https://interviewquestions.tuteehub.com/tag/attractive-887662" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTIVE">ATTRACTIVE</a> force which is called .adhesive force..</body></html> | |
| 36420. |
Express a unit of electrical energy in terms of joule. |
| Answer» <html><body><p></p>Solution :1 <a href="https://interviewquestions.tuteehub.com/tag/electrical-968148" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRICAL">ELECTRICAL</a> unit = 1 kWh <br/> `=1xx(10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)W)xx(3600s)` <br/> 1 electrical unit = `3600xx10^(3)<a href="https://interviewquestions.tuteehub.com/tag/ws-732723" style="font-weight:bold;" target="_blank" title="Click to know more about WS">WS</a>` <br/> 1 electrical unit = `3.6xx10^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)J` <br/> `1kWh=3.6xx10^(6)J`</body></html> | |
| 36421. |
A block of mass 500 g is at rest on a horizontal table. What steady force is required to give the block a velocity of 200 cms^(-1)in 4 s? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Use`F= ma ` <br/> ` a = (<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> - u)/(t ) = (200 - <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) = <a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> cm//s^2` <br/> ` F = 500 xx 50 =25,000 `dyne</body></html> | |
| 36422. |
For liquids, the graph between temperature and coefficient of viscosity is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/straight-633156" style="font-weight:bold;" target="_blank" title="Click to know more about STRAIGHT">STRAIGHT</a> line<br/>Parabola<br/>Rectangular hyperbola<br/>Ellipse</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36423. |
Five persons A, B, C, D & E are pulling a cart of mass 100kg on a smooth surface and cart is moving with acceleration 3 m//s^(2)in east direction. When person 'A' stops pulling, it moves with acceleration Im/s in the west direction. When person 'B' stops pulling, it moves with acceleration 24m//s^(-2)in the north direction. The magnitude of acceleration of the cart when only A & B pull the cart keeping their directions same as the old direction is |
| Answer» <html><body><p>` <a href="https://interviewquestions.tuteehub.com/tag/26-298265" style="font-weight:bold;" target="_blank" title="Click to know more about 26">26</a> m//s^2 `<br/>` 3sqrt71 m//s^2 `<br/> `<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> m//s^2`<br/>` <a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a> m//s^2 `</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36424. |
A small source of sound vibrating at frequenc 500 Hz is rotated in a circle of radius (100//pi)cmat a constant angular speed of 5.0 revolutions per second . The speed of sound in air is 330 m .s^(-1) . An observer (A) is situated at a great distance on a straight lineperpendicular to the plane of the circle , through its centre . Another observer (B) is at rest at a great distance from the centre of the circle byt nearly in the same plane . After something the source of sound comes to rest after reaching the centre of the circle . At that time , another observer (C) moves towards the source with a constant speed of 20 m .s^(-1) , along the radial line to the centreThe change in the frequency of the source heard by C will be |
| Answer» <html><body><p>0.06<br/>0.03<br/>0.02<br/>0.09</p>Solution :N/A</body></html> | |
| 36425. |
A small source of sound vibrating at frequenc 500 Hz is rotated in a circle of radius (100//pi)cmat a constant angular speed of 5.0 revolutions per second . The speed of sound in air is 330 m .s^(-1) . An observer (A) is situated at a great distance on a straight lineperpendicular to the plane of the circle , through its centre . Another observer (B) is at rest at a great distance from the centre of the circle byt nearly in the same plane . After something the source of sound comes to rest after reaching the centre of the circle . At that time , another observer (C) moves towards the source with a constant speed of 20 m .s^(-1) , along the radial line to the centreThe mininum and the maximum values of the apparent frequency heard by B will be |
| Answer» <html><body><p>455 <a href="https://interviewquestions.tuteehub.com/tag/hz-493442" style="font-weight:bold;" target="_blank" title="Click to know more about HZ">HZ</a> and 535 Hz <br/><a href="https://interviewquestions.tuteehub.com/tag/s-right-485-318359" style="font-weight:bold;" target="_blank" title="Click to know more about 485">485</a> Hz and 515 Hz <br/>485 Hz and 500 Hz <br/>500 Hz and 515 hz </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N/A</body></html> | |
| 36426. |
A small source of sound vibrating at frequenc 500 Hz is rotated in a circle of radius (100//pi)cmat a constant angular speed of 5.0 revolutions per second . The speed of sound in air is 330 m .s^(-1) . An observer (A) is situated at a great distance on a straight lineperpendicular to the plane of the circle , through its centre . Another observer (B) is at rest at a great distance from the centre of the circle byt nearly in the same plane . After something the source of sound comes to rest after reaching the centre of the circle . At that time , another observer (C) moves towards the source with a constant speed of 20 m .s^(-1) , along the radial line to the centreThe apparent frequency of the source heard by A will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> then <a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> Hz <br/>smaller then 500 Hz <br/>always 500 Hz <br/>greater for half the circle and smaller during the other half </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N/A</body></html> | |
| 36427. |
A particle of mass 0.1 kg executes SHM under a force F=-10x(N). Speed of particle at mean position is 6m/s. Find its amplitude of oscillations . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :From conservationfo <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> <br/> `1/2kA^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=1/2mv^(2)` or `A=vsqrt(m/k)=6sqrt(0.1/10)=6/10=0.6m`</body></html> | |
| 36428. |
The unit of position vector of center of mass is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a><br/>`kg m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>m<br/>`m^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36429. |
The minimum and maximum distance of a satellite from the centre of the earth 2R and 4R respectively. Where R is the radius of the earth and M is the mass of earth. Its maximum speed is |
| Answer» <html><body><p>`sqrt((GM)/(6R))` <br/>`sqrt((2GM)/(<a href="https://interviewquestions.tuteehub.com/tag/3r-311113" style="font-weight:bold;" target="_blank" title="Click to know more about 3R">3R</a>))` <br/>`sqrt((GM)/(3R))` <br/>`sqrt((2GM)/(<a href="https://interviewquestions.tuteehub.com/tag/5r-326350" style="font-weight:bold;" target="_blank" title="Click to know more about 5R">5R</a>))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36430. |
How will you calculate the length of the S period. |
| Answer» <html><body><p></p>Solution :According to Newton.s second <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> <br/>`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= (dp)/(dt)` i.e. `dp = F dt` <br/><a href="https://interviewquestions.tuteehub.com/tag/integrate-2131645" style="font-weight:bold;" target="_blank" title="Click to know more about INTEGRATE">INTEGRATE</a> it over a time interval from `t_1 ` to `t_f`<br/>`int_i^f dp = int_(t_1)^(t_f)F dt` <br/>`P_f - P_i = int_(t_1)^(t_2) F. dt` <br/>`P_1 to` initial momentum of the object at `t_1`<br/>`P_f to ` Final momentum of the object at `t_f` <br/>`P_f - P_i = <a href="https://interviewquestions.tuteehub.com/tag/deltap-2053537" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAP">DELTAP</a>=` <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in momentum during the time interval `Deltat. int_(t_1)^(t_f) F dt` = J is called the impulse. <br/>If the force is constant over the time interval `Deltat`, then<br/>`int_(t_1)^(t_f) F dt = F int_(t_1)^(t_f) dt = F(t_f - t_i) = F Deltat`<br/>`J = F Deltat= Deltap` <br/>Hence the proof.</body></html> | |
| 36431. |
A spring balance has a scale that reads 0 to 20 kg. The length of the scale is 10 cm. A body suspended from this balance, when displaced and released, oscillates, with period of (pis)/10. What is the mass of the body |
| Answer» <html><body><p>4.9 kg<br/>9.8 kg<br/>19.6 kg<br/>14.7 kg</p>Answer :A</body></html> | |
| 36432. |
Calculate the rate at which water flows thorugh a capillary tube of length 0.5 m with an internal radius of 1 mm. Coefficient of viscosity is 1.3 xx 10^(-3) kg//m^(-s). The pressure head is 20 cm of water . |
| Answer» <html><body><p></p>Solution :`P= (20-10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) xx 1000 xx 9.<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>) Nm^(-2) , r = 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m , l= 0.5 m` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a> = 1.3 xx 10^(-3)Kg//m^(-s) ,` From Poiseuill.s formula `V = (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> Pr^4)/(8 etal)` <br/>`=(3.14xx20 xx 10^(-2) xx 1000 xx 9.8 xx (10^(-3))^4)/(8xx1.3 xx 0.5) = 1.2 xx 10^(-6) m^3 s^(-1)`.</body></html> | |
| 36433. |
Inner and outer radii of a spool are r and R I, respectively. A thread is wound over its inner surface and spool is placed over a rough horizontal surface. Thread is pulled by a force F as shown in Fig. In case of pure rolling, which of the following statements are false? |
| Answer» <html><body><p>Thread unwinds, spool rotates anticlockwise and friction acts leftwards. <br/>Thread winds, spool rotates clockwise and friction acts leftwards. <br/>Thread winds, spool moves to the right and friction acts rightwards. <br/>Thread winds, spool moves to the right and friction does not <a href="https://interviewquestions.tuteehub.com/tag/come-409636" style="font-weight:bold;" target="_blank" title="Click to know more about COME">COME</a> into existence. </p>Solution :Since, the spool rolls over the <a href="https://interviewquestions.tuteehub.com/tag/horizontal-1029056" style="font-weight:bold;" target="_blank" title="Click to know more about HORIZONTAL">HORIZONTAL</a> surface, <a href="https://interviewquestions.tuteehub.com/tag/instantaneous-516608" style="font-weight:bold;" target="_blank" title="Click to know more about INSTANTANEOUS">INSTANTANEOUS</a> axis of rotation passes through the point of contact of spool with the horizontal surface. <br/> About the instantaneous axis if rotation, <a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a> produced by `F` is clockwise. Therefore, the spool rotates clockwise. In that case, acceleration will be <a href="https://interviewquestions.tuteehub.com/tag/rightward-1189400" style="font-weight:bold;" target="_blank" title="Click to know more about RIGHTWARD">RIGHTWARD</a> and thread will wind. <br/> If rotational motion of the spool is considered about its own, then the resultant moment on it must be clockwise. But moment produced by the force is anticlockwise and its magnitude is equal to `F_(1)//r`. Hence, moment produced by the friction (about its own axis) must be clockwise and its magnitude must be greater than `Fr`. It is possible only when friction acts leftwards. Therefore, Option (b) is correct</body></html> | |
| 36434. |
A car accelerates from rest at a constant rate alpha for sometime after which it decelerates at a constant rate beta to come to rest.If the total time lapsed it t seconds,find (i) the maximum velocity reached and (ii) the total distance travelled. |
| Answer» <html><body><p>`((<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+<a href="https://interviewquestions.tuteehub.com/tag/beta-2557" style="font-weight:bold;" target="_blank" title="Click to know more about BETA">BETA</a>^(2))/(alpha beta))t`<br/>`((alpha^(2)-beta^(2))/(alpha beta))t`<br/>`(alpha beta t)/(alpha+beta)`<br/>`((alpha+beta)t)/(alpha beta)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36435. |
A thin rotates about an axis passing through its centre and perpendicular to its plane with a constant angularvelocity .omega. I is the moment of inertia of that discand .L. is its angular momentum about the given axis. Then rotational kinetic energy of the disc .E. is(A) E alpha L^(2)(B) E alpha L^(-2)(C ) E alpha I(D) E alpha I^(-1) (if L constant) |
| Answer» <html><body><p>A & <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct<br/>B & C are correct<br/>B & D are correct<br/>A & D are correct</p>Answer :D</body></html> | |
| 36436. |
A vanis moving with a speed of 72 Kmph on a level road, where the coefficient of friction between tyres and road is 0.5. The minimum radius of curvature, the road must have, for safe driving of van is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a> m <br/>40 m<br/>20 m <br/>4 m</p>Solution :`F=mu_(S)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>, (<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2))/(r )=mumg`</body></html> | |
| 36437. |
A car of mass 1200 kg is traveling around a circular path of radius 300 m with a constant speed of 15m/s. calculate its angular momentum. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> momentum, `L=rmv` <br/> `=300xx1200xx15` <br/> `L=54xx10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)kgm^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)s^(-1)`</body></html> | |
| 36438. |
Two rigid bodies have same angular momentum about their axes of symmetry. If same torque is applied about their axes, the ratio of times after which they will be stopped is |
| Answer» <html><body><p>`1:1`<br/>`1:2`<br/>`2:1`<br/>`2:3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36439. |
The acceleration due to gravity on moon is 1/6th of that on the earth. If the length of the seconds pendulum is 96 m on the earth, what is its length on the moon ? |
| Answer» <html><body><p></p>Solution :For <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a> pendulum , time period is <a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a> , `T= 2pi sqrt(l/g)` for <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> pendulum <br/>time remains <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> in both the planets , `l/g `= constant<br/> `therefore (l_m)/(g_m) = (l_e)/(g_e) ` (or) `(l_m)/((g_3)/(6)) = (96)/(g_e) = lm = 16 ` <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>.</body></html> | |
| 36440. |
A cart of mass 500 kg is taken along a polished inclined surface to the top of a platform which is at a height of 2m above the ground level. Find the work done by the external force in moving the cart to the top. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :9.8 <a href="https://interviewquestions.tuteehub.com/tag/kj-1063034" style="font-weight:bold;" target="_blank" title="Click to know more about KJ">KJ</a></body></html> | |
| 36441. |
Can a vector be zeroif any of itscomponents is not zero? |
| Answer» <html><body><p></p>Solution :In <a href="https://interviewquestions.tuteehub.com/tag/terms-1242559" style="font-weight:bold;" target="_blank" title="Click to know more about TERMS">TERMS</a> of componentsin three dimestions,<br/> `vecA = hati A_(x) + hatj A_(y) + <a href="https://interviewquestions.tuteehub.com/tag/hatk-2693615" style="font-weight:bold;" target="_blank" title="Click to know more about HATK">HATK</a> A_(<a href="https://interviewquestions.tuteehub.com/tag/z-750254" style="font-weight:bold;" target="_blank" title="Click to know more about Z">Z</a>)`with `A = sqrt(A_(x)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+ A_(y)^(2) + A_(z)^(2))` <br/> so if any of `A_(x),A_(y) and A_(z)`is not zero(or <a href="https://interviewquestions.tuteehub.com/tag/null-17167" style="font-weight:bold;" target="_blank" title="Click to know more about NULL">NULL</a>)all itscomponentsmustvanish.</body></html> | |
| 36442. |
An eraser weighing 2N is pressed against the black board with a force of 5N. If the coefficient of friction is 0.4. How much force parallel to the black board is required to slide the eraser upwards |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2n-300431" style="font-weight:bold;" target="_blank" title="Click to know more about 2N">2N</a> <br/>`2.8 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> `<br/>`<a href="https://interviewquestions.tuteehub.com/tag/4n-319008" style="font-weight:bold;" target="_blank" title="Click to know more about 4N">4N</a>`<br/>`4.8N` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36443. |
Which of the following does not hold when two particles of masses m_(1) and m_(2) undergo elastic collision |
| Answer» <html><body><p>when `m_(1)=m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` and `m_(2)` is stationary, there is maximum <a href="https://interviewquestions.tuteehub.com/tag/transfer-1425652" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSFER">TRANSFER</a> to kinetic energy in head an collision <br/>when `m_(1)=m_(2)` and `m_(2)` is stationary, there is maximum transfer to <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> in head an collision <br/>where `m_(1) gt gt m_(2)` and `m_(2)` is stationary, after head on collision `m_(2)` moves with twice the velocity of `m_(1)`<br/>when the collision is oblique and `m_(1)=m_(2)` with `m_(2)` stationary, after the collision the <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> move in <a href="https://interviewquestions.tuteehub.com/tag/opposite-1137237" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSITE">OPPOSITE</a> direction. </p>Solution :When the collision is oblique and `m_(1)=m_(2)` with `m_(2)` stationary, after the collision the practice move in opposite direction.</body></html> | |
| 36444. |
A uniform disc of mass m and radius R with a spring connected (spring constant k) to its centre stand in static equilibrium on a very rough incline plane. Now a constant moment of couple M_(0), is applied at the centre as shown such that the disc rolls down incline. The maximum distance the disc's centre of mass will go down as measured from initial position is |
| Answer» <html><body><p>`(M_(o))/(<a href="https://interviewquestions.tuteehub.com/tag/rk-1190208" style="font-weight:bold;" target="_blank" title="Click to know more about RK">RK</a>)+(2mgsintheta)/(3K)`<br/>`(2M_(o))/(RK)+(2mgsintheta)/(3K)` <br/>`(2M_(o))/(RK)`<br/>`(2M_(o))/(RK)+(mgsintheta)/(K)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36445. |
(A) : Out of the measurements A= 10.00 and B = 10.000, B is more accurate. (R) : Percentage error in B is less than the percentage error in A. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :A</body></html> | |
| 36446. |
In an experiment if the measured values of a physical quantity have a high degree of closeness to the true value. These measurements are said to be |
| Answer» <html><body><p>both <a href="https://interviewquestions.tuteehub.com/tag/precise-604705" style="font-weight:bold;" target="_blank" title="Click to know more about PRECISE">PRECISE</a> and <a href="https://interviewquestions.tuteehub.com/tag/accurate-847229" style="font-weight:bold;" target="_blank" title="Click to know more about ACCURATE">ACCURATE</a><br/>precise<br/>accurate<br/>neither accurate nor precise</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36447. |
An important milestone in the evolution of the universe just after the Big Bang is the Planck time t_(p), the value of which depends on three fundamental constants-speed of light in vacuum c, Gravitational constant G and Planck's constant h. Then, t_(p) prop |
| Answer» <html><body><p>`Ghc^(5)`<br/>`(C^(5))/(<a href="https://interviewquestions.tuteehub.com/tag/gh-468237" style="font-weight:bold;" target="_blank" title="Click to know more about GH">GH</a>)`<br/>`(Gh)/(c^(5)`<br/>`((Gh)/(c^(5)))^(1//2)`</p>Solution :`[Gh]= [M^(-1)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(3)T^(-2)][ML^(2)T^(-1)]= [M^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)L^(5)T^(-3)], [c]= [LT^(-1)]` <br/> `:. [(Gh)/(c^(5))]^(1//2)=[ T]` <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, `t_(p) prop ((Gh)/(c^(5)))^(1//2) :. [t_(p)]= [T]`</body></html> | |
| 36448. |
The ratio of the time periods of two satellites at heights h_(1), h_(2) from the surface of the earth. |
| Answer» <html><body><p>`((h_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))/(h_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))^(3//2)`<br/>`((R+h_(1))/(R+h_(2)))^(3//2)`<br/>`((R+h_(2))/(R+h_(1)))^(3//2)`<br/>`((h_(2))/(h_(1)))^(3//2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36449. |
How much heat energy is gained when 5kg of water at 20^(@)C is brought to its boiling point (Specific heat of water = 4.2 kJ kg^(-1^(@))C^(-1) |
| Answer» <html><body><p></p>Solution :`Q _(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = mcd T + mL = 2000 xx 1 xx 25 + 2000 xx 80 = 2.1 xx 10 ^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) cal. Q _(1) = Q _(2) T _(1) //T_(2)` <br/> `Q _(1) = 2.1 xx 10 ^(5) xx 298 // 258 = 2.42 xx 10 ^(5) cal. ` Energy needed `= Q _(1) - Q _(2) = 3.25 xx 10 ^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) cal= 3.25 xx 10 ^(4) xx 4.2 //3600 = 37.92 Wh.`</body></html> | |
| 36450. |
A point moves such that its displacement as a function of time is given by x^(2)=t^(2)+1. It's acceleration at time t is given by |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(3))`<br/>`(-t)/(x^(3))`<br/>`(1)/(x)-(t^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(x^(3))`<br/>`1/x - (t)/(x^(2))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |