Explore topic-wise InterviewSolutions in Class 11.

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.

36451.

A round disc of moment of inertia I_(2) about its axis perpendicular to its plane and passing through its centre is placed over another disc of moment of inertia I_(1) rotating with an angular velocity omega about the same axis. The final angular velocity of the combination of disc is.............

Answer» <html><body><p>`((I_(1)+I_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))omega)/(I_(1))` <br/>`(I_(2)omega)/(I_(1)+I_(2))` <br/>`omega`<br/>`(I_(1)omega)/(I_(1)+I_(2))` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C07_E05_050_S01.png" width="80%"/> <br/> According to <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> of momentum, <br/> `L=L.` <br/> `therefore I_(1)omega=(I_(1)+I_(2))omega.` <br/> `therefore omega.=(I_(1)omega)/(I_(1)+I_(2))`</body></html>
Discussion
36452.

A boat at anchor is rocked by waves whose crests are 100 m apart and velocity is 25 m/sec. The boat bounces up once in every

Answer» <html><body><p>2500 s <br/>75 s <br/>4 s <br/>`0.<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> a` </p>Solution :We <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a>, `v = (lamda)/(T) <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> T =(lamda)/(v) = (<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)/(25) =<a href="https://interviewquestions.tuteehub.com/tag/4s-318811" style="font-weight:bold;" target="_blank" title="Click to know more about 4S">4S</a> `</body></html>
Discussion
36453.

Two chambers, one containing m_1g of a gas at P_1 pressure and other containing m_(2)g of a gas at P_2 pressure are put in communication with each other. If temperature remains constant, the common pressure reached will be

Answer» <html><body><p>`(P_1 P_2 (m_1 + m_2) )/( P_1 m_2 + P_2 m_1)`<br/>`(P_1 P_2 (m_1 - m_2) )/( P_1 m_2+P_2 m_1)`<br/>`(P_1 P_2 (m_1 + m_2) )/( P_1 m_1 + P_2 m_2) `<br/>`(P_1P_2 (m_2 - m_1) )/( P_1 m_1 + P_2 m_2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
36454.

An optical microscope uses visible light of wavelength ranging from ………….. To ………….

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/4xx10-1883351" style="font-weight:bold;" target="_blank" title="Click to know more about 4XX10">4XX10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)m` ; `<a href="https://interviewquestions.tuteehub.com/tag/8xx10-1931283" style="font-weight:bold;" target="_blank" title="Click to know more about 8XX10">8XX10</a>^(-7)m`.</body></html>
Discussion
36455.

A particle (A) of mass m_(1) elastically collides with another stationary particle (B) of mass m_(2). Then :

Answer» <html><body><p>`(m_(1))/(m_(2)) = (1)/(2)` and the particles fly a part in the opposite direction with equal velocities.<br/>`(m_(1))/(m_(2)) = (1)/(3)` and the particles fly apart in the opposite direction with equal velocities.<br/>`(m_(1))/(m_(2)) = (2)/(1)` and the collision angle between the particles is `60^(@)` symmetrically.<br/>`(m_(1))/(m_(2)) = (2)/(1)` and the particles fly apart symmetrically at an angle `90^(@)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`m_(1)<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> + 0 = -m_(1)v+m_(2)v`……….(1) <br/> From kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> <br/> `(1)/(2)m_(1)u^(2) = (1)/(2)m_(1)v^(2) + (1)/(2)m_(2)v^(2)`………..(2) <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_PHY_XI_V02_C05_E01_050_S01.png" width="80%"/> <br/> From eq. (1) and and eq. (2) we get , `(m_(1))/(m_(2)) = (1)/(3)` <br/> So, choice (b) is correct. <br/> `P^(2) = P_(1)^(2) + P_(2)^(2)+2P_(1)P_(2) <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta`.........(1) <br/> Also from conservation of kinetic energy <br/> `(P^(2))/(2m_(1)) = (P_(1)^(2))/(2m_(1)) + (P_(2)^(2))/(2m_(2))`............(2) <br/> Since particles fly symmetrically <br/> `P_(1) sin "(theta)/(2) = P_(2) sin "(theta)/(2)`..........(3) <br/> Solving eq. (1), (2) and (3) we get <br/> `(m_(1))/(m_(2)) = (2)/(1)`</body></html>
Discussion
36456.

A man sitting on a swing which is moving to an angle of 60^(@) from the vertical is blowing a whistle which has frequency of 2.0 KHZ. The whistle is 2.0 m from the fixed support point of the swing. A sound detector which detects the whistle sound is kept in front of the swing. The maximum frequency the sound detector detected is :

Answer» <html><body><p>`2.027 kHz`<br/>`1.974 kHz`<br/>`9.74kHz`<br/>`1.011kHz`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>= 2 kHz` <br/> Velocity of whistle (<a href="https://interviewquestions.tuteehub.com/tag/source-1219297" style="font-weight:bold;" target="_blank" title="Click to know more about SOURCE">SOURCE</a>) `v_(s)=2m` <br/> Velocity of sound `v=332m/s`<br/> Maximum frequency `v_("max")=((V+V_(s))/(V))v` <br/> `=((<a href="https://interviewquestions.tuteehub.com/tag/332-1856202" style="font-weight:bold;" target="_blank" title="Click to know more about 332">332</a>+2)/(332))xx2` <br/> `=((<a href="https://interviewquestions.tuteehub.com/tag/the-equation-r-f-0hm-v-sdz-334-308076" style="font-weight:bold;" target="_blank" title="Click to know more about 334">334</a>)/(332)xx2` <br/> `1.006xx2` <br/> `2.012 kHz`</body></html>
Discussion
36457.

The mathematical operation in which the accuracy is limited to least accurate term is

Answer» <html><body><p>addition <br/><a href="https://interviewquestions.tuteehub.com/tag/subtraction-1231773" style="font-weight:bold;" target="_blank" title="Click to know more about SUBTRACTION">SUBTRACTION</a> <br/>multiplication &amp; <a href="https://interviewquestions.tuteehub.com/tag/division-957437" style="font-weight:bold;" target="_blank" title="Click to know more about DIVISION">DIVISION</a> <br/>both a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> </p>Answer :D</body></html>
Discussion
36458.

During an experiment an ideal gas is found to obey an additional law VP^(2)= constant. The gas is initially at a temperature 'T' and volume 'V'. When it expands to a volume 2V, the temperature becomes

Answer» <html><body><p>T<br/>2T<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a>` T<br/>`(T)/( sqrt2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
36459.

An unhappy mouse of mass m_(0) moving on the end of a spring of spring constant p is acted upon by a damping force F_(X)= -b vartheta_(X). For what value of b the motion is critically damped?

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;`<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>= sqrt((p)/(m_0))`<br/>`b= 2sqrt(pm_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>))`<br/>`b= sqrt((p^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(2m_0))`<br/>`b= sqrt((P)/(2m_0))`</p>Answer :B</body></html>
Discussion
36460.

The periods of a pendulum on two planets are in the ratio 3:4. The acceleration due to gravity on the mare in the ratio

Answer» <html><body><p>`9:16`<br/>`3:4`<br/>`4:3`<br/>`16:9`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
Discussion
36461.

A ball of mass .m. is rotated in a vertical circle with constant speed. The difference in tension at the top and bottom would be

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> mg <br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> mg <br/>mg</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
36462.

Derive an expression for excess of pressure (pressure difference) inside the drop and bubble.

Answer» <html><body><p></p>Solution :In figure (a) a gas <a href="https://interviewquestions.tuteehub.com/tag/bubble-904920" style="font-weight:bold;" target="_blank" title="Click to know more about BUBBLE">BUBBLE</a> in <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> is shown and in figure (b) this bubble is shown spherical and in figure (c ) a soap bubble in air is shown .<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C10_E01_067_S01.png" width="80%"/><br/>Suppose , bubble formed by this way radius of bubble is r and inside pressure is `P_(i)`and outside pressure is `P_(0)`.<br/>Letus obtain `P_(i)-P_(0)` for bubble in liquid or drop of liquid .<br/>The pressure insidethe drop is `P_(i)` and outsideis `P_(0).P_(i)` is slightly higher than `P_(0)`.<br/>When bubble increase by `Deltar`, new radius becomes `r+Deltar`.<br/>Area of this surface `A_(2)=4pi(r+Deltar)^(2)`<br/>`A_(2)=4pi(r^(2)+2r*Deltar+Deltar^(2))`<br/> `Deltar^(2)`is very small comparedto others terms<br/>`thereforeA_(2)=4pi(r^(2)+2rDeltar)` ....(2)<br/>The change inarea of surfaceof drop<br/>`DeltaA=A_(2)-A_(1)`<br/>`DeltaA=4pi(r^(2)+2rDeltar)-4pir^(2)`<br/> `=4pi(r^(2)+2rDeltar-2r^(2))`<br/> =`4pi(2rDeltar)`<br/> `Deltar=8pirDeltar` ...(3)<br/>The work done for increase area `DeltaA` of free surface of drop.<br/> `W=S_(la)(DeltaA)`<br/>`W=S_(la)(8pirDeltar)` ....(4)<br/>In the process of blowing bubble the force due to pressure <a href="https://interviewquestions.tuteehub.com/tag/difference-951394" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENCE">DIFFERENCE</a> `(P_(i)-P_(0)` on the inside surface of area `4pir^(2)` is `(P_(i)-P_(0))4pir^(2)` . Under the <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> of this force , surface moved by `Deltar` displacement , hence work done on the surface, <br/>`W=("force")<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>("Displacement")` <br/> `W=("pressure difference")xx("area")xx("displacement")` <br/>`W=(P_(i)-P_(0))(4pir^(2))(Deltar)`...5<br/>Comparing equation (4) and (5),<br/>`(P_(i)-P_(0))(4pir^(2)Deltar)=S_(la)(8pirDeltar)`<br/>`thereforeP_(i)-P_(0)=(2S_(la))/(r)`.....(6)<br/>Bubble in liquid and drop of liquid has one free surface . For them equation of pressure difference ontain according to equation (6).<br/>Bubble in air have two free surface . For them formula for pressure difference obtained as below.<br/>`P_(i)-P_(0)=(4S_(la))/(r)` ....(7)<br/>From this it can be said that for drop or bubble <br/>`P_(i)-P_(0)prop(1)/(r)`</body></html>
Discussion
36463.

A particle is moving with shm in a-straight line. When the distance of the particle from the equilibrium position has the values 2 cm and 4 cm, the corresponding values of velocities are 5 cms^(-1)and 3 cms^(-1)respectively. Find the length of the path and the period.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T=2pi[x_2^2-x_1^2)//(v_1^2-v_2^2)]^(1//2)=5.4,v_1^2=omega^2(a^2-x_1^2),a=477 ` <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> ` = 2xx4.77 = 9.54 ` cm</body></html>
Discussion
36464.

A capillary tube of diameter 0.20 mm is lowered vertically into water in a vessel. What should be the pressure inN//m^(2)to be applied on the water in the capillary tube so that water level in the tube is same as that in the vessel ? (surface tension of water is 0.07 N/m and atm pressure is10^(5)N//m^(2))

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;`10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`99xx10^(3)`<br/>`100xx10^(3)`<br/>`101.4xx10^(3)`</p>Solution :Consider the <a href="https://interviewquestions.tuteehub.com/tag/meniscus-1093619" style="font-weight:bold;" target="_blank" title="Click to know more about MENISCUS">MENISCUS</a> of <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> of water in capillary as bubble , <br/>`P_(i)=P_(o)+(2T)/(R)`<br/>`=10^(5)+(2xx0.07)/(0.1xx10^(-3))`<br/>`=10^(5)+14xx10^(2)`<br/>`=1,00,000+1400`<br/>`=10.1.4xx10^(3)Nm^(-2)`</body></html>
Discussion
36465.

Radius of a glass capillary is 0.5 mm . Find the height of the column of water when it is held vertical in water . The density of wateris 10^(3)kgm^(-3) and the the angle of contact between glass and water is 0^(@),g=9.8ms^(-2) and the surface tension of water T=0.0727Nm^(-1).

Answer» <html><body><p></p>Solution :`r=0.5mm=5xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)m`<br/>`rho=10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/kgm-2769156" style="font-weight:bold;" target="_blank" title="Click to know more about KGM">KGM</a>^(-3)`<br/>`theta=0 "" thereforecos0^(@)=1`<br/>`g=9.8ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`T=0.0727Nm^(-1)`<br/>`T=(rhrhog)/(2costheta)`<br/> `thereforeh=(2Tcostheta)/(rrhog)`<br/>`=(2xx0.0727xx1)/(5xx10^(-4)xx10^(3)xx9.8)`<br/>`thereforeh=0.0296m`<br/>`thereforeh=2.96cm`</body></html>
Discussion
36466.

The density of the atmosphere at sea level is 1.29kg//m^(3) . Assume that it does not change with altitude . Then how high would the atmosphere extended ? (g=9.8ms^(-2))

Answer» <html><body><p></p>Solution :We use Eq.10.7 <br/> `pgh=1.29 kg m^-3 times 9.8 ms^2 times h m=1.01 times 10^5 Pa` <br/> `therefore h=7989 m=8km` <br/> In <a href="https://interviewquestions.tuteehub.com/tag/reality-620184" style="font-weight:bold;" target="_blank" title="Click to know more about REALITY">REALITY</a> the density of air decreases with <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a>. So does the value of g. The atmospheric cover extends with decreasing pressure over 100km. we should also <a href="https://interviewquestions.tuteehub.com/tag/note-1125278" style="font-weight:bold;" target="_blank" title="Click to know more about NOTE">NOTE</a> that the <a href="https://interviewquestions.tuteehub.com/tag/sea-638310" style="font-weight:bold;" target="_blank" title="Click to know more about SEA">SEA</a> level atmospheric pressure is not always 760 nm of Hg. A drop in the Hg level by 10mm or more is a sign of an approaching <a href="https://interviewquestions.tuteehub.com/tag/storm-21158" style="font-weight:bold;" target="_blank" title="Click to know more about STORM">STORM</a>.</body></html>
Discussion
36467.

State and explain equation of continuity.

Answer» <html><body><p></p>Solution :For ideal fluid <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> of <a href="https://interviewquestions.tuteehub.com/tag/flow-993213" style="font-weight:bold;" target="_blank" title="Click to know more about FLOW">FLOW</a> <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> `A_(1)v_(1)A_(2)v_(2)`</body></html>
Discussion
36468.

When an external force is applied at the centre of mass of a system of particles, then it undergoes

Answer» <html><body><p>Only <a href="https://interviewquestions.tuteehub.com/tag/translatory-3229314" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLATORY">TRANSLATORY</a> motion<br/>Only <a href="https://interviewquestions.tuteehub.com/tag/rotatory-2998718" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATORY">ROTATORY</a> motion<br/>both translatory and rotatory motion<br/>an <a href="https://interviewquestions.tuteehub.com/tag/oscillatory-2208020" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATORY">OSCILLATORY</a> motion</p>Answer :A</body></html>
Discussion
36469.

A pipe in the form of a half ring is placed on a horizontal surface. If it is rotated through a small angle, and then released, assuming that it rolls without sliding determine the period of oscillations. The center of gravity of such a body is at distance (2r)/pi) from the center where r is the radius of the ring. Hint: (vec_(c) = alpha rhat(i) and vec(a_(c)) = vec(a_(c)) +(veca_(G//c))_("tangent") +(veca_(G//c))_("normal")

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`2nsqrt(((pi-2)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>))`</body></html>
Discussion
36470.

A bullet is projected upwards from the top of a tower of height 90 m with the velocity 30 ms^(-1) making an angle 30^(@)with the horizontal. Find the time taken by it to reach the ground is (g=10 ms^(-2))

Answer» <html><body><p>2s<br/>3s<br/>24s<br/>6s</p>Answer :D</body></html>
Discussion
36471.

If a person enters a room at 25^(@)C, will thermal equilibrium be established?

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/normal-1123860" style="font-weight:bold;" target="_blank" title="Click to know more about NORMAL">NORMAL</a> body temperature of a <a href="https://interviewquestions.tuteehub.com/tag/human-1032714" style="font-weight:bold;" target="_blank" title="Click to know more about HUMAN">HUMAN</a> being is `37^(@)C`. The human body maintains this temperature, generating energy through food intake. Hence, thermal equilibrium will not be established <a href="https://interviewquestions.tuteehub.com/tag/unless-7277693" style="font-weight:bold;" target="_blank" title="Click to know more about UNLESS">UNLESS</a> the temperature of the room rises to `37^(@)C` due to some external reasons.</body></html>
Discussion
36472.

Round - off the following numbers as indicated. (a) 17.234 to 3 digits(b) 3.996 xx 10^(5) to 3 digits (c) 3.6925 xx 10^(3) to 2 digits(d) 124783 to 5 digits.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) 17.2 (b) `4.00 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)` (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) `3.7 xx 10^(3)` (d) 124780</body></html>
Discussion
36473.

(i) Consider an infinitesimally thin triangular strip having mass M and length L. Find the moment of inertia of the strip about on axis passing through its tip and perpendicular to the plane. Compare the result with moment ofinertia of a uniform disc of mass M and radius L about an axis passing through its centre and perpendicular to the plane the disc. Why the two expressions are same? (ii)A circular fan made of paper is in shape of a disc of radius R. The fan can be folded (various stages shown in figure (a) through (f))to the shape of a thin stick. The moment of inertia of the circular fan about an axis passing through centre O and perpendicular to the plane of the figure is I_(0) = (1)/(2) MR^(2) where M = mass of the fan. (a) How does the moment of inertia (I), about an axis perpendicular to the plane of the figure passing through O, change as the fan is folded through stage a to b to c to d to e? (b) When the fan is completely folded in the shape of a stick (fig. (f)), write its moment of inertia about the above mentioned axis. Note : Moment of inertia of a uniform rod about an axis through its end and perpendicular to it is(ML^(2))/(3)

Answer» <html><body><p><br/></p>Answer :(i) `(ML^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(2)` <br/> (ii) (a) <a href="https://interviewquestions.tuteehub.com/tag/moi-548644" style="font-weight:bold;" target="_blank" title="Click to know more about MOI">MOI</a> does not <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> <br/> (b) `I = I_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>) = (1)/(2) MR^(2)`</body></html>
Discussion
36474.

In Qunick's acoustic interferometer , it is found that the sound intensity has a minimum value of 100 units at one position of the sliding tube , and cocontinuously climbs to a maximum of 900 units at a second position 1.65 cm from the first . Find (a) the frequency of the sound emitted by the source and (b) the relative amplitudes of the two waves arriving at the detector. Velocity of sound in air= 340 m//s.

Answer» <html><body><p></p>Solution :a. Let `d_(1)` be the length of the <a href="https://interviewquestions.tuteehub.com/tag/fixed-457597" style="font-weight:bold;" target="_blank" title="Click to know more about FIXED">FIXED</a> path and `d_(2)` be the length of other path that can be varied . Then for minimum <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> ` d_(2) - d_(1)= ( <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> + 1) lambda`. When the adjustable tube is <a href="https://interviewquestions.tuteehub.com/tag/moved-7266899" style="font-weight:bold;" target="_blank" title="Click to know more about MOVED">MOVED</a> out by `x` , the length of the path becomes ` d_(2) + 2 x`. For the next maximum sound <br/> `( d_(2) + 2 x ) - d_(1) = ( n + (1)/( 2)) lambda + ( lambda)/(2) = n lambda+ lambda` <br/> Subtracting ` 2 x= ( lambda)/( 2) orx = ( lambda)/( 4)` <br/> Here `x = 1.65 cm`. <br/> `:. lambda = 4 xx 1.65 = 6.6 cm = 6.6 xx 10^(-2) m` <br/> `C = n lambda or n = ( c)/( lambda) = (340)/( 6.6 xx 10^(-2)) = 5152 Hz` <br/> b. If `a and b`are the amplitudes of the waves , then minimum amplitude ` = a - b` and maximum amplitude ` = a + b` . <br/>` :. (I_(<a href="https://interviewquestions.tuteehub.com/tag/min-548008" style="font-weight:bold;" target="_blank" title="Click to know more about MIN">MIN</a>))/(I_(max)) = (( a - b)^(2))/(( a + b)^(2)) or (100)/(900) = (( a - b)^(2))/(( a + b)^(2))` <br/> or ` (a)/(b) = (2)/(1)`</body></html>
Discussion
36475.

One can easily weighs the earth by calculating the mass of the earth by using the formula (in usual notation)

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)/(g)R_(<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a> )^(2)`<br/>`(g)/(G)R_(E )^(2)`<br/>`(g)/(G)R_(E )`<br/>`(G)/(g)R_(E )^(3)`</p>Answer :B</body></html>
Discussion
36476.

A thin uniform rod of mass M and length L is hinged at end released from rest in the horizontal position. The tention at a point located at a distance L/3 from the hinge point, when the rod becomes vertical, will be

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/22mg-1825218" style="font-weight:bold;" target="_blank" title="Click to know more about 22MG">22MG</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/11mg-268884" style="font-weight:bold;" target="_blank" title="Click to know more about 11MG">11MG</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>)`<br/>`(6Mg)/(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)`<br/>2Mg</p>Answer :D</body></html>
Discussion
36477.

Two wires A and B of the same material have their length in the ratio 1:2 and diameters in the ratio 2:1.If they stretched by the same force the ratio of their elongation is

Answer» <html><body><p>1:8<br/>1:4<br/>1:2<br/>1:1</p>Answer :A</body></html>
Discussion
36478.

If Earth completes one revolution in 24 hours, what is the angular displacement made by Earth in one hour?Express your answer in both radian and degree.

Answer» <html><body><p></p>Solution :Given , One <a href="https://interviewquestions.tuteehub.com/tag/revolution-623158" style="font-weight:bold;" target="_blank" title="Click to know more about REVOLUTION">REVOLUTION</a> of earth i <a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a> hours<br/>t = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> hour<br/>`theta = ? ? `<br/>24 haur`= 360^(@)`<br/>In <a href="https://interviewquestions.tuteehub.com/tag/degrees-947393" style="font-weight:bold;" target="_blank" title="Click to know more about DEGREES">DEGREES</a> ` 1 hour = (360^(@))/(24^(@)) = 15^(@) (or)`<br/>In radian1 hour`= (2pi)/(24^(@)) = (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(12)`rad</body></html>
Discussion
36479.

A mass m is attached to a thin wire and whirled in a verticle circle. The wire is most likely to break when

Answer» <html><body><p>inclined at an <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of `60^@` from <a href="https://interviewquestions.tuteehub.com/tag/vertical-726181" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICAL">VERTICAL</a> <br/>the mass is at the highest point <br/>the <a href="https://interviewquestions.tuteehub.com/tag/wire-1457703" style="font-weight:bold;" target="_blank" title="Click to know more about WIRE">WIRE</a> is horizontal <br/>the mass is at the lowest point </p>Solution :In vertical circular <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a>, tension in the wire is <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> at the lowermost point, so the wire is most likely to break when the mas is at the lowermost point.</body></html>
Discussion
36480.

Find the natural frequency of the system as shown in the figure. The pulleys are massless and frictionless. (Take k=9pi^(2)N//m and m=4kg)

Answer» <html><body><p></p>Solution :To find frequency we have to first calculate the acceleration of the block as a function of displacement. In such type of <a href="https://interviewquestions.tuteehub.com/tag/complicated-2533514" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLICATED">COMPLICATED</a> systems we can find this by <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> the equation of energy conservation and then <a href="https://interviewquestions.tuteehub.com/tag/differentiating-953151" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENTIATING">DIFFERENTIATING</a> it. One important point is to be noted is that the spring is already stretched by some amount and beyond this <a href="https://interviewquestions.tuteehub.com/tag/extension-981025" style="font-weight:bold;" target="_blank" title="Click to know more about EXTENSION">EXTENSION</a> we can not take energy to be equal to `(1//2)kx^(2)` so we have to first find out the initial extension. <br/> `mg=T_(1)`, `T_(1)=2T_(2)` <br/> `T_(2)=2T_(3)`, `T_(3)kx_(0)` <br/> `rArr x_(0)=(mg)/(4k)` <br/> If suppose the block is further pulley down by `x`, spring stretches by `4x` <br/> `U`(Total energy of system) `=(1)/(2)k(x_(0)+4x)^(2)-mgx+(1)/(2)mv^(2)` <br/> `(dU)/(dt)=0` <br/> `k(x_(0)+4x)4(dx)/(dt)-mg"(dx)/(dt)+mv(dv)/(dt)=0` <br/> `(dv)/(dt)=(d^(2)x)/(dt^(2))=-16(k)/(m)x` <br/> `rArr f=(1)/(2pi)sqrt((16k)/(m))rArrf=3`. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FIT_JEE_PHY_GMP_MOD2_C09_S01_047_S01.png" width="80%"/></body></html>
Discussion
36481.

Assertion : In simple harmonic motion the velocity is maximum when the acceleration is minimum. Reason : In simple harmonic motion the phase difference between velocity and acceleration is (pi)/(2) Select the correct option form the following.

Answer» <html><body><p>Both assertion and reason are true and reason is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of assertion<br/>Both assertion and reason are true and reason is not the correct explanation of assertion<br/>Both assertion and reason are false <br/>Assertion is true and reason is false </p>Solution :In simple harmonic motion, the <a href="https://interviewquestions.tuteehub.com/tag/valocity-3254582" style="font-weight:bold;" target="_blank" title="Click to know more about VALOCITY">VALOCITY</a> and acceleration of a particle differ in phase by `(<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(2)`.</body></html>
Discussion
36482.

A spherical shell of inner radius R_(1) and outer radius R_(2) is having variable thermal conductivity given by K=a_(0)Txxr, where a_(0) is constant and T is temperature in kelvin and r is the distance from the centre. Two surface of the shell are maintained at temperature T1 (inner surface) and T_(2) (outer surface), respectively (T_(1)gt T_(2)). The heat current flowing through the shell would be

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4pi-1882352" style="font-weight:bold;" target="_blank" title="Click to know more about 4PI">4PI</a> a_(0)(T_(1)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-T_(2)^(2)))/(R_(2)-R_(1))xxR_(1)R_(2)`<br/>`(4pi a_(0)R_(1)^(2)R_(2)^(2)(T_(1)^(2)-T_(2)^(2)))/(R_(2)^(2)-R_(1)^(2))`<br/>`(4pi a_(0)(T_(1)^(2)-T_(2)^(2))R_(1)R_(2))/(R_(2)-R_(1))`<br/>`(4pi a_(0)(T_(1)^(2)-T_(2)^(2))(R_(1)+R_(2))^(2))/(R_(2)-R_(1))` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
36483.

A reference frame attached to the earth (a) is an inertial frame by definition (b) can not be an inertial fram because the earth is revolving around the sun(c ) is an inertial frame because Newton's laws are applicable in this frame(d) cannot be an inertial frame because the earth is rotating about its axis

Answer» <html><body><p>a, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>, <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a><br/>b only correct <br/>b and d are correct <br/>All are correct</p>Answer :C</body></html>
Discussion
36484.

Two limbs of a manometer consist of uniform capillary tubes of radii r_(1)andr_(2) respectively (r_(1)gtr_(2)). If the level of liquid in narrower tube stands at a height .h. above that in the broader tube then the exact pressure difference will be

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;</p>Solution :If `P_(1)andP_(2)` are the pressures in broader and <a href="https://interviewquestions.tuteehub.com/tag/narrower-2857361" style="font-weight:bold;" target="_blank" title="Click to know more about NARROWER">NARROWER</a> <a href="https://interviewquestions.tuteehub.com/tag/tubes-1428682" style="font-weight:bold;" target="_blank" title="Click to know more about TUBES">TUBES</a> <br/> Then `P_(A)=P_(B)+hrhog` <br/> `P_(1)-(<a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a>)/r_(1)=P_(2)-(2S)/r_(2)+<a href="https://interviewquestions.tuteehub.com/tag/hdg-3657699" style="font-weight:bold;" target="_blank" title="Click to know more about HDG">HDG</a>` <br/> `P_(1)-P_(2)=hrhog-2S[1/r_(2)-1/r_(1)]`</body></html>
Discussion
36485.

A spring has spring constant k and l. If it cut into piece spring in the proportional to alpha : beta : gamma then obtain the spring constant of every piece in term of spring constant of original spring (Here, alpha, beta " and "gamma are integers).

Answer» <html><body><p></p>Solution :Suppose length of `<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>, <a href="https://interviewquestions.tuteehub.com/tag/beta-2557" style="font-weight:bold;" target="_blank" title="Click to know more about BETA">BETA</a>" and "gamma" are "l_(1), l_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)" and "l_(3)` respectively and total length `l= alpha+beta + gamma= l_(1), l_(2), l_(3)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> l_(1)=` spring constant of `alpha` length <br/> `k_(1) = (kl)/(l_1)= (<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>(alpha+beta+gamma))/(alpha)` <br/> ` l_(2)=` spring constant of `beta` length <br/> `k_(2) = (kl)/(l_2)= (k(alpha+beta+gamma))/(beta)` <br/> and ` l_(3)=` spring constant of `gamma` length <br/> `k_(3) = (kl)/(l_3)= (k(alpha+beta+gamma))/(gamma)`.</body></html>
Discussion
36486.

An infinite number of particles each of mass m are placed on the positive x-aris at lm, 2m, 4m, 8m, ----- from the origin. The magnitude of the resultant gravitational force on mass .m. kept at the origin is

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP2_C09_SLV_018_S01.png" width="80%"/> <br/> The resultant gravitational force <br/> `F = (Gm^2)/1+(Gm^2)/<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>+(Gm^2)/16 +........`<br/> `=Gm^(2)(1/1+1/4+1/16+ .........)= Gm^(2)(1/(1-(1)/4))` <br/> ( `:. ` <a href="https://interviewquestions.tuteehub.com/tag/sum-1234400" style="font-weight:bold;" target="_blank" title="Click to know more about SUM">SUM</a> of the <a href="https://interviewquestions.tuteehub.com/tag/infinite-515764" style="font-weight:bold;" target="_blank" title="Click to know more about INFINITE">INFINITE</a> terms in G.P is `S_(prop) = a/(1-r))=4/3Gm^2`</body></html>
Discussion
36487.

Which is more accurate 8.0 or 8.00?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Since 8.00 is correct to second <a href="https://interviewquestions.tuteehub.com/tag/place-1155224" style="font-weight:bold;" target="_blank" title="Click to know more about PLACE">PLACE</a> of decimal as <a href="https://interviewquestions.tuteehub.com/tag/compared-7256615" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARED">COMPARED</a> to 8.0, which is correct only to first place of decimal, 8.00 is more accurate.</body></html>
Discussion
36488.

The lengthof a rod is 5 xx 10^(2) m , theorder ofmagnitudeof the lengthof the rod is

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m`<br/>`10^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)m`<br/>`10^(1)m`<br/>`10^(-1)m`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :b</body></html>
Discussion
36489.

A constant torque acting on a uniform circular wheel changes its angular momentum from A to 4 A in 4S. The torque acted on it is

Answer» <html><body><p>`(3A)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`(A)/(4)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a>)/(3)`<br/>`(3A)/(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
36490.

Even if the average velocity of a body is zero, its average speed may be non-zero-is it possibIe?

Answer» <html><body><p></p>Solution :Displacement of a particle <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> zero if the particle returns to its starting <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> after completion of the journey. Then the average velocity <br/> =`("total displacement ")/("total <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a>") = 0 ` <br/> Again average speed = `("total distance <a href="https://interviewquestions.tuteehub.com/tag/covered-2552266" style="font-weight:bold;" target="_blank" title="Click to know more about COVERED">COVERED</a> ")/("total time")`, as the total distance covered is non-zero here the average speed is not equal to zero.</body></html>
Discussion
36491.

Bernoulli's Principle

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The wings of an airplane (aerofoil) are so designed that its <a href="https://interviewquestions.tuteehub.com/tag/upper-721698" style="font-weight:bold;" target="_blank" title="Click to know more about UPPER">UPPER</a> surface is more curved than the lower surface and the front edge is broader than the real edge. As the aircraft moves, the air moves faster above the aerofoil than at the bottom as <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in Figure.<br/>According to Bernoulli's Principle, the <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of air below is greater than above, that creates an upthrut called the <a href="https://interviewquestions.tuteehub.com/tag/dynamic-11476" style="font-weight:bold;" target="_blank" title="Click to know more about DYNAMIC">DYNAMIC</a> lift to the aircraft.<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E02_123_S01.png" width="80%"/></body></html>
Discussion
36492.

Velocity of particle at time t = 0 is 2ms^(-1) . A constant acceleration of 2ms^(-2) acts on the particle for 1 second at an angle of 60^@ with its nitnial velocity. Find the magnitude of velocity at the end of 1second.

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt3-3056952" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT3">SQRT3</a> m//s ` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/2sqrt3-1838932" style="font-weight:bold;" target="_blank" title="Click to know more about 2SQRT3">2SQRT3</a> m//s ` <br/>`4m//s`<br/>`8m//s ` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
36493.

(A) : The maximum horizontal range of projectile is proportional to square of velocity. ( R) : The maximum horizontal range of projectile is equal to maximum height at tained by projectile.

Answer» <html><body><p>Both (A) and ( <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/ture-1429019" style="font-weight:bold;" target="_blank" title="Click to know more about TURE">TURE</a> and ( R) is the correct explanation of (A) <br/>Both (A) and ( R) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and ( R) is not the correct explanation of (A)<br/>(A) is true but ( R) is false <br/>Both (A) and ( R) are false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
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36494.

A constant torque of 1000 N-m, turns á wheel of moment of inertia 200 kg-m^(2)about an axis through its centre. Its angular velocity after 3 s is, (in rad/s)

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a>"<a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a>"s^(-1)`<br/>`22"rad"s^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/28-299271" style="font-weight:bold;" target="_blank" title="Click to know more about 28">28</a>"rad"s^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>"rad"s^(-1)`</p>Answer :A</body></html>
Discussion
36495.

What is the meaning by pseudo force ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Pseudo <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> is an apparent force which has no origin. It arises <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to the non-inertial <a href="https://interviewquestions.tuteehub.com/tag/nature-1112013" style="font-weight:bold;" target="_blank" title="Click to know more about NATURE">NATURE</a> of the frame considered</body></html>
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36496.

A shell in flight explodes into n equal fragments, k of the fragments reach the ground earlier than the other fragments. The acceleration of their centre of mass subsequently will be

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a><br/>`(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>-<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)g`<br/>`((n-k)g)/(k)`<br/>`((n-k))/(n)g`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
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36497.

A person standing between two parallel hills fires a gun and hears the first echo after t_(1) sec and the second echo after t_(2) sec. The distance between the two hills is

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>(t_(1)-t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))/(2)`<br/>`(v(t_(1)t_(2)))/(2(t_(1)+t_(2)))`<br/>`v(t_(1)+t_(2))`<br/>`(v)/(2)(t_(1)+t_(2))`</p>Solution :Distance b/w <a href="https://interviewquestions.tuteehub.com/tag/man-1085541" style="font-weight:bold;" target="_blank" title="Click to know more about MAN">MAN</a> and hill 1, `d_(1)= (vt_(1))(2)` <br/> Distance b/w man and hill 2, `d_(2)= (vt_(2))(2)` <br/> Distance b/w the two hills, `d =d_(1)+ d_(2)` <br/> `d= (v(t_(1)+t_(2)))/(2)`</body></html>
Discussion
36498.

If M is the magnetic moment, B is the magnetic induction and T is the time, then MBT^2has the dimensions of

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/intensity-1047474" style="font-weight:bold;" target="_blank" title="Click to know more about INTENSITY">INTENSITY</a> of <a href="https://interviewquestions.tuteehub.com/tag/magnetization-18799" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNETIZATION">MAGNETIZATION</a><br/> Intensity of magnetic field <br/> <a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a> of Inertia<br/>Magnetic permeability</p>Answer :C</body></html>
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36499.

A vessel contains 7g of nitrogen and 11g of carbon dioxide at a temperature of T=290K and pressure of 1 atm. Find the density of this mixture, assuming the gases to be ideal.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`1.5kgm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</body></html>
Discussion
36500.

What is the power needed to maintain uniform circular motion?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No power is needed to maintain <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> <a href="https://interviewquestions.tuteehub.com/tag/circular-916697" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCULAR">CIRCULAR</a> motion. <br/> Power <a href="https://interviewquestions.tuteehub.com/tag/required-1185621" style="font-weight:bold;" target="_blank" title="Click to know more about REQUIRED">REQUIRED</a> `=vecF.vecv=Fv cos theta` <br/> `=Fv cos 90^(@)=0`</body></html>
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