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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36651. |
Two equal spheres B and C, each of mass m, are in contact on a smooth horizontal table. A third sphere A of same size as that of B or C but mass m//2 impinges symmetrically on them with a velocity u and is itself brought to rest. Find the velocity acquired by each of the spheres B and C after collision. |
| Answer» <html><body><p>`u/sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`(2u)/sqrt(3)`<br/>`u/(2sqrt(3))`<br/>`u/2`</p>Solution :`u=`velocity of sphere `A` before impact. As the spheres are identical, the triangle `ABC` formed by joining their centres is equilateral. The spheres `B` and `C` will move in direction `AB` and `AC` after impact making can angle of `30^(@)` with the origina <a href="https://interviewquestions.tuteehub.com/tag/lines-1074819" style="font-weight:bold;" target="_blank" title="Click to know more about LINES">LINES</a> of <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> of <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> `A`. <br/> Let `v` be the speed ofthe balls `B` and `C` after impact. <br/> Momentum conservationgives <br/> `(m/2)u=mvcos30^(@) +mvcos30^(@)` <br/> `u=2sqrt(3)vimpliesv=u/(2sqrt(3))`.......i <br/> From Newton's experimental law, for an oblique collision, we have take components along normal, i.e. along `AB` for balls `A` and `B`. <br/> `v_(B)-v_(A)=-e(u_(B)-u_(A))` <br/> `v-0=-e(0-ucos30^(@))` <br/> `v=eucos30^(@)`.........ii <br/> <a href="https://interviewquestions.tuteehub.com/tag/combining-922870" style="font-weight:bold;" target="_blank" title="Click to know more about COMBINING">COMBINING</a> eqn i and ii we get `e=1/3` <br/> Loss in `KE =1/2 m/2 u^(2)-2(1/2mv^(2))` <br/> `=1/4mu^(2)-m(u/(2sqrt(3)))^(2)=1/6mu^(2)`</body></html> | |
| 36652. |
Two equal spheres B and C, each of mass m, are in contact on a smooth horizontal table. A third sphere A of same size as that of B or C but mass m//2 impinges symmetrically on them with a velocity u and is itself brought to rest. The coefficient of restitution between the two spheres A and B (or between A and C) is |
| Answer» <html><body><p>`1//3`<br/>`1//4`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>//3`<br/>`3//4`</p>Solution :`u=`velocity of sphere `A` before impact. As the spheres are identical, the triangle `ABC` formed by joining their centres is equilateral. The spheres `B` and `C` will move in <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> `AB` and `AC` after impact making can <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of `30^(@)` with the origina lines of motion of <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> `A`. <br/> Let `v` be the speed ofthe balls `B` and `C` after impact. <br/> Momentum conservationgives <br/> `(m/2)u=mvcos30^(@) +mvcos30^(@)` <br/> `u=2sqrt(3)vimpliesv=u/(2sqrt(3))`.......i <br/> From Newton's experimental law, for an oblique collision, we have take components along normal, i.e. along `AB` for balls `A` and `B`. <br/> `v_(B)-v_(A)=-e(u_(B)-u_(A))` <br/> `v-0=-e(0-ucos30^(@))` <br/> `v=eucos30^(@)`.........ii <br/> Combining <a href="https://interviewquestions.tuteehub.com/tag/eqn-973463" style="font-weight:bold;" target="_blank" title="Click to know more about EQN">EQN</a> i and ii we get `e=1/3` <br/> Loss in `KE =1/2 m/2 u^(2)-2(1/2mv^(2))` <br/> `=1/4mu^(2)-m(u/(2sqrt(3)))^(2)=1/6mu^(2)`</body></html> | |
| 36653. |
A vessel is half filled with a liquid at 0^(@) C. When the vessel is heated to 100^(@) C, the liquid occupies 3/4 volume of the vessel. Coefficient of apparent expansion of the liquid is |
| Answer» <html><body><p>0.5/°<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>0.05/°C<br/>0.005/°C<br/>0.0005/°C</p>Answer :C</body></html> | |
| 36654. |
A trolley of mass 200 kg moves with a uniform speed of 36 km/h on a frictionless track. A child of mass 20 kg runs on the trolley from one end to the other (10 m away) with a speed of 4 ms^(-1) relative to the trolley in a direction opposite to the its motion, and jumps out of the trolley. What is the final speed of the trolley? How much has the trolley moved from the time the child begins to run? |
| Answer» <html><body><p></p>Solution :The child gives an impulse to the trolley at the start and then runs with a constant <a href="https://interviewquestions.tuteehub.com/tag/relative-1183377" style="font-weight:bold;" target="_blank" title="Click to know more about RELATIVE">RELATIVE</a> velocity of `4 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)` with respect to the trolley.s <a href="https://interviewquestions.tuteehub.com/tag/new-1114486" style="font-weight:bold;" target="_blank" title="Click to know more about NEW">NEW</a> velocity. Apply momentum conservation for an observer <a href="https://interviewquestions.tuteehub.com/tag/outside-1143075" style="font-weight:bold;" target="_blank" title="Click to know more about OUTSIDE">OUTSIDE</a>. `10.36 ms^(-1), 25.9m`.</body></html> | |
| 36655. |
A satellite close to earth is in orbit above equator with a period of motion of 1.5 hours. If its is above point P on equator at some time, it will be above P a gain time… |
| Answer» <html><body><p>1.5 hours <br/>1.6 hours if it is <a href="https://interviewquestions.tuteehub.com/tag/rotating-1191156" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATING">ROTATING</a> from <a href="https://interviewquestions.tuteehub.com/tag/west-1451899" style="font-weight:bold;" target="_blank" title="Click to know more about WEST">WEST</a> to <a href="https://interviewquestions.tuteehub.com/tag/east-447972" style="font-weight:bold;" target="_blank" title="Click to know more about EAST">EAST</a> <br/>24/17 hours if it is rotating from east to west <br/>hours if it is rotating from west to east </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::C</body></html> | |
| 36656. |
The increase in length of a wire on stretching is 0.025%. If its poisson ratio is 0.4, then the percentage decrease in the diameter is : |
| Answer» <html><body><p>0.01<br/>0.02<br/>0.02<br/>0.04</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a></body></html> | |
| 36657. |
The coordinates of a body moving in a plane at any instant of time t are x=alphat^(2) and y = betat^(2). The velocity of the body is |
| Answer» <html><body><p></p>Solution :`x=alphat^(2)rArrv_(x)=(dx)/(dt)=2alphat` <br/> `y = betat^(2).rArr v_(y)=(dy)/(dt)=2betat` <br/> `:."<a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a>" v = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((2alphat)^(2)+(2betat)^(2))` <br/> `=2tsqrt(alpha^(2)+<a href="https://interviewquestions.tuteehub.com/tag/beta-2557" style="font-weight:bold;" target="_blank" title="Click to know more about BETA">BETA</a>^(2))`</body></html> | |
| 36658. |
A student was asked a question 'why are there summer and winter for us? He replied as 'since Earth is orbiting in an elliptical orbit, when the Earth is very faraway from the Sun (aphelion) there will be winter, when the Earth is nearer to the Sun (perihelion) there will be winter}. Is this answer correct? If not, what is the correct explanation for the occurrence of summer and winter? |
| Answer» <html><body><p></p>Solution :Early astronomers <a href="https://interviewquestions.tuteehub.com/tag/proved-7287273" style="font-weight:bold;" target="_blank" title="Click to know more about PROVED">PROVED</a> that <a href="https://interviewquestions.tuteehub.com/tag/earth-13129" style="font-weight:bold;" target="_blank" title="Click to know more about EARTH">EARTH</a> is spherical in shape by looking at the shape of the <a href="https://interviewquestions.tuteehub.com/tag/shadow-1204489" style="font-weight:bold;" target="_blank" title="Click to know more about SHADOW">SHADOW</a> cast by Earth in the Moon during lunar eclipse.</body></html> | |
| 36659. |
Unbalanced system of forces can produce acceleration as well as deformation in a body, but balanced system of forces produces deformation only explain. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In case of an unbalanced system of forces acting on a body, a resultant force acts at the centre of mass . The body accelerates, as per the equation, F= ma. But for a balanced system fo forces the resultantforce is zero andhence acceleration ofthe centre of mass is zero However in both the situations, different <a href="https://interviewquestions.tuteehub.com/tag/parts-1148278" style="font-weight:bold;" target="_blank" title="Click to know more about PARTS">PARTS</a> of the body <a href="https://interviewquestions.tuteehub.com/tag/may-557248" style="font-weight:bold;" target="_blank" title="Click to know more about MAY">MAY</a> have relative velocities with respect to one another. Hence, deformation may take place. For example, if a rubber ropeis pulled on both ends with equal forces , the rope extends in length ,i.e., it is deformed, but its centre of massremains steady atone place . when the forces applied at theends are unequal, the rope not only extends , but <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> <a href="https://interviewquestions.tuteehub.com/tag/moves-1104598" style="font-weight:bold;" target="_blank" title="Click to know more about MOVES">MOVES</a> in the direction of thegreater force.</body></html> | |
| 36660. |
Deduce the formula of Reynolds number in the form of inertial force and viscous force . |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/reynolds-623232" style="font-weight:bold;" target="_blank" title="Click to know more about REYNOLDS">REYNOLDS</a> number `R_(e)=(rhov^(2))/(((etav)/d))` <br/> Multiplying and <a href="https://interviewquestions.tuteehub.com/tag/dividing-957391" style="font-weight:bold;" target="_blank" title="Click to know more about DIVIDING">DIVIDING</a> by A to right side equation,<br/>`R_(e)=(rhoAv^(2))/(((etaAv)/(d)))`<br/>`R_(e) = ("<a href="https://interviewquestions.tuteehub.com/tag/inertial-1043204" style="font-weight:bold;" target="_blank" title="Click to know more about INERTIAL">INERTIAL</a> force")/("Viscous force")`<br/>Thus `(R_(e)`represets the ratio of inertial force, that is force due to mass of moving fluid or due to inertia of obstable in its path to viscous force)<br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>`R_(e)` represents the ratio of inertial force of to viscous force.</body></html> | |
| 36661. |
Two capillary tubes of lengths in .the ratio 2: 1 and radii in the ratio 1 :2 are connected in series. Assume the flow of the liquid through the tube is steady. Then, the ratio of pressure difference across the tubes is |
| Answer» <html><body><p>`1:8`<br/>`1:16`<br/>`32:1`<br/>`1:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36662. |
(A) : It is hotter at the same distance over the top of a fire than it is on the sides. (R) : Heat is transmitted equally in all directions by radiation but convection takes heat upwards only |
| Answer» <html><body><p>Both 'A' and '<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>' are true and 'R' is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of 'A' <br/>Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A' <br/>'A' is true and 'R' is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A' is false and 'R' is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36663. |
Find the ratio of escape velocities of two planets if values of g on the two planets are 9.8 m//s^(2) and 3.3 m//s^(2) and ther radii are 6400 km and 3400 km respectively. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/escape-975157" style="font-weight:bold;" target="_blank" title="Click to know more about ESCAPE">ESCAPE</a> velocity in <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> of g and R is <br/> The ratio of escape velocities `(V_(<a href="https://interviewquestions.tuteehub.com/tag/e1-444665" style="font-weight:bold;" target="_blank" title="Click to know more about E1">E1</a>))/(V_(<a href="https://interviewquestions.tuteehub.com/tag/e2-961697" style="font-weight:bold;" target="_blank" title="Click to know more about E2">E2</a>)) = sqrt((g_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)R_(1))/(g_(2)R_(2)))` <br/> `(V_(e1))/(V_(e2)) = sqrt(((9.8)/(3.3))((6400)/(3400))) = (2.364)/(1)` <br/> `V_(e1) : V_(e2) = 2.364:1`.</body></html> | |
| 36664. |
Three particles of the same mass are kept at the vertices of an equilateral triangle. The mass of each particle is m and the length of an arm of the triangle isl. Due to the the mutual gravitational force of attraction, the particles revolve along the circumcircle of the triangle. Find the velocity of each particle. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/abc-360912" style="font-weight:bold;" target="_blank" title="Click to know more about ABC">ABC</a> is an equilateral triangle . At its vertices three particles A,B and C each of mass m , are kept [Fig.1.4]. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P1_U06_C01_SLV_002_S01.png" width="80%"/> <br/> The point of intersection of the medians of ABC is O, which is also the centre of the circumcircle of the triangle. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, radius of the circumcircle, <br/> `r=OA =2/3AD =2/3AB sin <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^@= 2/3*l*sqrt(3)/2=l/sqrt(3)`. Hence the centripetal force needed by each particle to revolve along the circumcircle with velocity v is <br/> `F_1=(mv^2)/r=(mv^2)/(l/sqrt(3))=(sqrt(3)mv^2)/l` <br/> Now the gravitational force acting on the particle at point can be calculated. The force of gravitation on the particle A due to the particle at B along AB, <br/> `F=(G*m*m)/((AB)^2)=(Gm^2)/(l^2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/component-926634" style="font-weight:bold;" target="_blank" title="Click to know more about COMPONENT">COMPONENT</a> of this force along AE =`cos 60^@` and that along `AD=Fsin 60^@` <br/> Again , gravitational attraction onthe particle at A due to the particle kept at C is F along AC. <br/> Components ofthis force along `AH =F cos 60^@` and that along `AD =F sin 60^@`. <br/> Clearly, components along AH an AE cancel each other Hence , the resultant force `F_2` on the particle kept at A =sum of the components along AD. <br/> `therefore F_2=F sin 60^@ +Fsin 60^@ =2Fsin 60^@` <br/> `=2F*(sqrt(3))/(2)=sqrt(3)F=(sqrt(3)Gm^2)/(l^2)` <br/> As <a href="https://interviewquestions.tuteehub.com/tag/par-1146244" style="font-weight:bold;" target="_blank" title="Click to know more about PAR">PAR</a> the question, this force of attraction due to gravitation supplies the necessary centripetal force. Hence <br/> `F_1=F_2 or, (sqrt(3)mv^2)/l =(sqrt(3)Gm^2)/(l^2) or, v^2 =(Gm)/lor, v=sqrt((Gm)/l)`.</body></html> | |
| 36665. |
Two solid rubber balls A and B having masses 200 and 400 g respectively are moving in opposite directions with velocity of A equal to 0.3 m/s. After collision the two balls come to rest, then find the velocity of B. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Initial linear <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> of system `= m _(A) v _(A) = m _(B) v _(B)` <br/> `= 0.2 xx 0.3 +0.4 xx v_(B)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/finally-461212" style="font-weight:bold;" target="_blank" title="Click to know more about FINALLY">FINALLY</a> both <a href="https://interviewquestions.tuteehub.com/tag/balls-891923" style="font-weight:bold;" target="_blank" title="Click to know more about BALLS">BALLS</a> come to rest <br/> `therefore `Final linear momentum = 0 <br/> By the law of conservation of linear momentum `0.2 xx 0.3 +0.4 xx v _(B) =0` <br/> `therefore u _(B)= (0.2xx 0.3)/( 0.4) =- 0.15 m//s`<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_B_C04_SLV_012_S01.png" width="80%"/></body></html> | |
| 36666. |
Two particles of same mass fall down on to the surface of the earth one from infinity and the other from an alitutude 3R. The ratio of velocities on reaching the earth is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> : <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`3 : 2`<br/>`2 : <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3)`<br/>`sqrt(3) : 2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36667. |
Two satellites of earth. S_(1) and S_(2) are moving in the same orbit. The mass of S_(1) is four times the mass of S_(2). Which one of the following statement is true ? |
| Answer» <html><body><p>The <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> <a href="https://interviewquestions.tuteehub.com/tag/energies-971455" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGIES">ENERGIES</a> of earth satellites in the two cases are equal.<br/>`S_(1)` and `S_(2)` are moving with the same speed <br/>The <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energies of the two satellites are equal<br/>The time period of `S_(1)` is four times that of `S_(2)`.</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36668. |
A uniform piece of metal sheet is cut in the form as shown in the fig. Locate the center of mass of the piece. |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP2_C07_SLV_020_S01.png" width="80%"/> <br/> Let the mass per unit area be `<a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>` We divide the <a href="https://interviewquestions.tuteehub.com/tag/structure-1230280" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURE">STRUCTURE</a> into parts 1, 2 and 3. The mass of <a href="https://interviewquestions.tuteehub.com/tag/part-596478" style="font-weight:bold;" target="_blank" title="Click to know more about PART">PART</a> 1 is 300 `sigma`, mass of part 2 is 200 `sigma` and that of part 3 in 100 `sigma`. The coordinates of centre of mass of part 1 are (5, 15), that of part 2 are (20,5), and that of part 3 are (15, 25) <br/> Using the Eq. <br/> `x_(cm)=((300sigma)5+(200sigma)20+(100sigma)15)/(600sigma)~~11.7` <br/> `y_(cm)=((300sigma)15+(200sigma)5+(100sigma)25)/(600sigma)~~13.3` <br/> In vector notation `barr_(cm)=11.7hati+13.3hatj`</body></html> | |
| 36669. |
A resonance tube is resonated with tuning fork of frequency 512 Hz. Two successive lengths of the resonated air-column are 16.0 cm and 51.0 cm. The experiment is performed at the room temperature of 40^(@)C calculate the speed of sound at 0^(@)Cand the end correction. |
| Answer» <html><body><p></p>Solution :Here `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=512Hz, L_(1)=16.0cm=0.16m, L_(2)=51.0cm=0.51m` <br/> <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> at `<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>^(@)C`, <br/> `v=2V(L_(2)-L_(1))` <br/> `=2xx512xx(0.51-0.16)` <br/> `=358.4ms^(-1)` <br/> Speed of sound at `0^(@)C` is given by <br/> `v_(o)=v-0.61t=358.4-0.61xx40` <br/> `=350.4-24.4-334ms^(-1)` <br/> End correction <br/> `=(L_(2)-3L_(1))/(2)=(51.0-48.0)/(2)` <br/> =1.5cm.</body></html> | |
| 36670. |
A uniform chain of mass 'm' and length 'L' is kept on a horizontal table with half of its length hanging from the edge of the table. Work done in pulling the chain on to the so that only (1)/(5)th of its length now hangs from the edge is, |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/mgl-2176708" style="font-weight:bold;" target="_blank" title="Click to know more about MGL">MGL</a>)/(8)`<br/>`(mgl)/(<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>)`<br/>`(mgl)/(18)`<br/>`(mgl)/(200)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36671. |
Under what condion will a car skid on a leveled circular road ? |
| Answer» <html><body><p></p>Solution :On a leveled circular road, if the <a href="https://interviewquestions.tuteehub.com/tag/static-1226026" style="font-weight:bold;" target="_blank" title="Click to know more about STATIC">STATIC</a> <a href="https://interviewquestions.tuteehub.com/tag/friction-21545" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTION">FRICTION</a> is not able to provide <a href="https://interviewquestions.tuteehub.com/tag/enough-446095" style="font-weight:bold;" target="_blank" title="Click to know more about ENOUGH">ENOUGH</a> centripetal force to turn, the <a href="https://interviewquestions.tuteehub.com/tag/vehicle-1444426" style="font-weight:bold;" target="_blank" title="Click to know more about VEHICLE">VEHICLE</a> will start to skid. <br/> `mu_(5)<a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a>(v^(2))/(rg)`</body></html> | |
| 36672. |
A man sitting on a swing which is moving to an angle of 60^(@) from the vertical is blowing a whistle is 2.0 m from the fixed support point of the whistle sound is kept in front of the swing. The maximum frequency the sound detechor detected is : |
| Answer» <html><body><p>`2.027 <a href="https://interviewquestions.tuteehub.com/tag/khz-1063029" style="font-weight:bold;" target="_blank" title="Click to know more about KHZ">KHZ</a>`<br/>`1.974 kHz`<br/>`9.74kHz`<br/>`1.011kHz`</p>Solution :Frequency `v= 2 kHz` <br/> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of whistle (source) `v_(s)=2m` <br/> Velocity of sound `v=332m/s`<br/> <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> frequency `v_("<a href="https://interviewquestions.tuteehub.com/tag/max-546895" style="font-weight:bold;" target="_blank" title="Click to know more about MAX">MAX</a>")=((V+V_(s))/(V))v` <br/> `=((332+2)/(332))xx2` <br/> `=((334)/(332)xx2` <br/> `1.006xx2` <br/> `2.012 kHz`</body></html> | |
| 36673. |
The ratio of the mean absolute error to the mean value is called as........... |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/absolute-11456" style="font-weight:bold;" target="_blank" title="Click to know more about ABSOLUTE">ABSOLUTE</a> <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a><br/> <a href="https://interviewquestions.tuteehub.com/tag/random-11853" style="font-weight:bold;" target="_blank" title="Click to know more about RANDOM">RANDOM</a> error <br/><a href="https://interviewquestions.tuteehub.com/tag/relative-1183377" style="font-weight:bold;" target="_blank" title="Click to know more about RELATIVE">RELATIVE</a> error <br/><a href="https://interviewquestions.tuteehub.com/tag/percentage-13406" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENTAGE">PERCENTAGE</a> error</p>Solution :Relative error</body></html> | |
| 36674. |
Two waves y_(1)=a sin (pi/2 x-omegat) and y_(2)=a sin (pi/2 x+omegat+pi/3) get superimposed in the region x ge 0. Find the number of nodes in the region 0 le x le 6 m. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`</body></html> | |
| 36675. |
{:(,"SECTION-A",,"SECTION-B"),("a)","Equation of continuity","e)","Less than critical velocity"),("b)","Bernoullie's theorem","f)","Formation of eddies & vortices"),("c)","Turbulent flow","g)","Law of conservation of mass"),("d)","Stream line flow","h)","Law of conservation of energy"):} |
| Answer» <html><body><p>a-h, b-f, c-e, d-g<br/>a-g, b-e, c-g, d-f<br/>a-f, b-g, c-h, d-e<br/>a-g, b-h, c-f, d-e </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36676. |
In the above problem ,whichwill reachthe bottomwith greater velocity? |
| Answer» <html><body><p>A<br/>B<br/>Both with same <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36677. |
Can we use the equations of kinematics to find the height attained by a body projected upward with any velocity . |
| Answer» <html><body><p></p>Solution :No, because equations of <a href="https://interviewquestions.tuteehub.com/tag/motions-1104155" style="font-weight:bold;" target="_blank" title="Click to know more about MOTIONS">MOTIONS</a> are <a href="https://interviewquestions.tuteehub.com/tag/applicable-882014" style="font-weight:bold;" target="_blank" title="Click to know more about APPLICABLE">APPLICABLE</a> as long as the acceleration is <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> .</body></html> | |
| 36678. |
Explain the variation of 'g' with latitude. |
| Answer» <html><body><p></p>Solution :Variation of g with latitude: <br/> Wherever we analyze the motion of object in <a href="https://interviewquestions.tuteehub.com/tag/rotating-1191156" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATING">ROTATING</a> frames we must take into account the centrifugal force. Even though we treat the Earth as an inertial <a href="https://interviewquestions.tuteehub.com/tag/frame-998974" style="font-weight:bold;" target="_blank" title="Click to know more about FRAME">FRAME</a>, it is not exactly correct because the Earth spins about its own axis. So when and object is on the surface of the Earth, it experiences a centrifugal force that depends on the latitude of the object on Earth. If the Earth were not spinning, the force on the object would have been 'mg'. <a href="https://interviewquestions.tuteehub.com/tag/however-1032379" style="font-weight:bold;" target="_blank" title="Click to know more about HOWEVER">HOWEVER</a>, the object experiences an additional centrifugal force due to spinning of the Earth. <br/> This centrifugal force is given by `momega^(2) R'`. <br/> where `lambda` is the latitude. The component of centrifugal acceleration experienced by the object in the direction opposite to g is <br/> `a_(c) = <a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(2) R' cos lambda = omega^(2) R cos^(2) lambda` <br/> since `R' = R cos lambda` <br/> Therefore, `g' = g - omega^(2) R cos^(2) lambda""......(2)` <br/> From <a href="https://interviewquestions.tuteehub.com/tag/hte-2718409" style="font-weight:bold;" target="_blank" title="Click to know more about HTE">HTE</a> expression (2), we can infer that at equator ,`lambda = 0, g ' = g - omega^(2)R`. The acceleratoin due to gravity is minimum. At poles `lambda = 90, g' = g`, it is maximum. At the equator, g' is minimum. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C06_E03_008_S01.png" width="80%"/></body></html> | |
| 36679. |
Explain why the temperature of a wire under tension will charge if it snaps suddenly? |
| Answer» <html><body><p></p>Solution :During elongation of a <a href="https://interviewquestions.tuteehub.com/tag/wire-1457703" style="font-weight:bold;" target="_blank" title="Click to know more about WIRE">WIRE</a> that <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done remains <a href="https://interviewquestions.tuteehub.com/tag/stored-7260220" style="font-weight:bold;" target="_blank" title="Click to know more about STORED">STORED</a> as elastic potential energy in the wire. When the wire snaps suddenly, that stored potential energy is <a href="https://interviewquestions.tuteehub.com/tag/transformed-661783" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSFORMED">TRANSFORMED</a> into heat energy resulting in increase in temperature.</body></html> | |
| 36680. |
Is it possible for a body to be accelerated without speeding up or slowing down ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/yes-749457" style="font-weight:bold;" target="_blank" title="Click to know more about YES">YES</a>, an <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> in <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> <a href="https://interviewquestions.tuteehub.com/tag/circular-916697" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCULAR">CIRCULAR</a> motion is accelerating but its <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> neither decreasesnot increases .</body></html> | |
| 36681. |
In the figure shown a plank of mass m is lying at rest on a smooth horizontal surface. A cylinder of same mass m and radius r is rotated to an angular speed w0 and then gently placed on the plank. It is found that by the time the slipping between the plank and the cylinder cease, 50%of total kinetic energy of the cylinder and plank system is lost. Assume that plank is long enough and um is the coefficient of friction between the cylinder and the plank. (a) Find the final velocity of the plank. (b) Calculate the magnitude of the change in angular momentum of the cylinder about its centre of mass. (c) Distance moved by the plank by the time slipping ceases between cylinder and plank. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) `(romega_(0))/(4)` <br/> `(b) (1)/(4) <a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) omega_(0)` <br/> (c) `(r^(2) omega_(0)^(2))/(32 mu g)`</body></html> | |
| 36682. |
(A) : The angular velocity of a platets orbiting around the sun increases when they are nearest to the sun. (R) : The angular momentum of body is propotional to angular velocity. |
| Answer» <html><body><p>Both 'A' and '<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>' are true 'R' is the correct explanation of 'A' <br/>Both 'A' and 'R' are true 'R' is not the correct explanation of 'A' <br/>A' is true and 'R' is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A' is false and 'R' are true </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36683. |
A system is taken from state A to state N along two different paths 1 and 2. The heat absorbed and work done by system along these two paths are Q_(1) and Q_(2), andW_(1) and W_(2) respectively. Then |
| Answer» <html><body><p>`Q_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = Q_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`W_(1) = W_(2)`<br/>`Q_(1) - W_(1) = Q_(2) - W_(2)`<br/>`Q_(1) + W_(1) = Q_(2) + W_(2)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36684. |
The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe L meter long. The length of the open pipe will be |
| Answer» <html><body><p>`L/2m`<br/>`4Lm`<br/>`Lm`<br/><a href="https://interviewquestions.tuteehub.com/tag/2l-300409" style="font-weight:bold;" target="_blank" title="Click to know more about 2L">2L</a> m</p>Solution :(i) For open pipe of <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> L. second overtone `=(<a href="https://interviewquestions.tuteehub.com/tag/3v-310794" style="font-weight:bold;" target="_blank" title="Click to know more about 3V">3V</a>)/(2L.)` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) For closed pipe of length L first overtone `= (3v)/(4L)` <br/> As per the <a href="https://interviewquestions.tuteehub.com/tag/statement-16478" style="font-weight:bold;" target="_blank" title="Click to know more about STATEMENT">STATEMENT</a>, `(3v)/(2L.) = (3v)/(4L)` <br/> `therefore L. = 2L`</body></html> | |
| 36685. |
If the coefficient of volume expansion of glass would have been equal to the coefficient of real expansion of mercury, a mercury thermometer would not be active-explain. |
| Answer» <html><body><p></p>Solution :A thermometer shows the apparent expansion of the thermometric <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a>. <br/>But, the <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of apparent expansion of mercury = the coefficient of real expansion of mercury - the coefficient of volume expansion of glass = 0, if `gamma_(glass)=gamma_(mercury)` (given). Therefore, the mercury within the tube <a href="https://interviewquestions.tuteehub.com/tag/would-3285927" style="font-weight:bold;" target="_blank" title="Click to know more about WOULD">WOULD</a> <a href="https://interviewquestions.tuteehub.com/tag/remain-1184279" style="font-weight:bold;" target="_blank" title="Click to know more about REMAIN">REMAIN</a> at the same level, no matter what the change in temperature is.</body></html> | |
| 36686. |
Two parallel forces P and Q (P gt Q) are acting at two points, A and B, of a body. If the forces interchange their positions, by how much will the point of action of the resultant of the resultant of the two forces shift along the line AB? |
| Answer» <html><body><p></p>Solution :In Fig. <a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> C is the point of <a href="https://interviewquestions.tuteehub.com/tag/action-2544" style="font-weight:bold;" target="_blank" title="Click to know more about ACTION">ACTION</a> of the resultant in the first case. <br/> `:. PxxAC=QxxBC""cdots(1)` <br/> If the <a href="https://interviewquestions.tuteehub.com/tag/new-1114486" style="font-weight:bold;" target="_blank" title="Click to know more about NEW">NEW</a> <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> of the point of action of the resultant is C. then <br/> `QxxAC.=PxxBC. ""cdots(2)` <br/> From (1) we get, <br/> `PxxAC = Q(AB-AC) " ""or", (P+Q)xxAC=QxxAB` <br/> `:. AC=(Q)/(P+Q)xxAB` <br/> Similarly from (2) we get, <br/> `AC.=(P)/(P+Q)xxAB ""cdots(4)` <br/> `:.` Subtracting equation (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) from equation (4) we get, <br/> `AC. -AC =(AB)/((P+Q))(P-Q) " ""or", "CC".= (P-Q)/(P+Q) xxAB`. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P1_U05_C01_SLV_019_S01.png" width="80%"/></body></html> | |
| 36687. |
What is the nature of a fluid flow when the speed of the fluid exceeds critical velocity? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/turbulent-662225" style="font-weight:bold;" target="_blank" title="Click to know more about TURBULENT">TURBULENT</a></body></html> | |
| 36688. |
Four particles , each of mass M and equidistant from each other, move along a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is: |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)` <br/>`sqrt(2sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(GM)/R)` <br/>`sqrt((GM)/R(1+2sqrt(2)))` <br/>`1/2sqrt((GM)/R(1+2sqrt2))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36689. |
Which of the function of time represent (a) simple harmonic. (b) periodic but not simple harmonic. and (c) non periodic motion ? Give period for each case of periodic motion (omega is any positive constant), sinomegat-cosomegat |
| Answer» <html><body><p></p>Solution :`sinomegat-cosomegat= sqrt(2)[sinomegatcos((pi)/(4))-cosomegatsin((pi)/(4))]= sqrt(2)sin(<a href="https://interviewquestions.tuteehub.com/tag/omegat-2889234" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGAT">OMEGAT</a>-(pi)/(4))` <br/> It is <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a> with a time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> `T = (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(omega)`</body></html> | |
| 36690. |
(A) When a body is thrown into air, at its maximum height its KE is zero always. (B) If a body is moved along a rough circular path in the horizontal plane, work done by the force applied is zero |
| Answer» <html><body><p>A is <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>, B is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>A is false, B is true<br/>A & B are true<br/>A & B are false</p>Answer :D</body></html> | |
| 36691. |
Which of the function of time represent (a) simple harmonic. (b) periodic but not simple harmonic. and (c) non periodic motion ? Give period for each case of periodic motion (omega is any positive constant), 1+omegat+omegat^(2) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`1+omegat+omegat^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` is not <a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> as <a href="https://interviewquestions.tuteehub.com/tag/function-11303" style="font-weight:bold;" target="_blank" title="Click to know more about FUNCTION">FUNCTION</a> increases with increase in t with out <a href="https://interviewquestions.tuteehub.com/tag/repetition-1185163" style="font-weight:bold;" target="_blank" title="Click to know more about REPETITION">REPETITION</a>.</body></html> | |
| 36692. |
Which of the function of time represent (a) simple harmonic. (b) periodic but not simple harmonic. and (c) non periodic motion ? Give period for each case of periodic motion (omega is any positive constant), e^(-omega^(2)t^(2)) |
| Answer» <html><body><p></p>Solution : `e^(-<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(2)t^(2))` is not periodic as t <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> the <a href="https://interviewquestions.tuteehub.com/tag/function-11303" style="font-weight:bold;" target="_blank" title="Click to know more about FUNCTION">FUNCTION</a>`e^(-omega^(2)t^(2))` decreases and <a href="https://interviewquestions.tuteehub.com/tag/tends-7717049" style="font-weight:bold;" target="_blank" title="Click to know more about TENDS">TENDS</a> to zero as `t to oo`</body></html> | |
| 36693. |
Which of the function of time represent (a) simple harmonic. (b) periodic but not simple harmonic. and (c) non periodic motion ? Give period for each case of periodic motion (omega is any positive constant), cosomegat+cos3omegat+cos5omegat |
| Answer» <html><body><p></p>Solution :`cosomegat+ cos3omegat+ cos5omegat` is a periodic function but not <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a>. The time periods of each periodic function are `(2pi)/(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>), (2pi)/(3omega)` and `(2pi)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> omega)`. <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> `(2pi)/(omega)` is the multiple of the other two periods , the given sum is periodic with time period `(2pi)/(omega)`</body></html> | |
| 36694. |
Which of the function of time represent (a) simple harmonic. (b) periodic but not simple harmonic. and (c) non periodic motion ? Give period for each case of periodic motion (omega is any positive constant), 3cos(pi//4-2omegat) |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/3cos-310909" style="font-weight:bold;" target="_blank" title="Click to know more about 3COS">3COS</a>(pi//4-2omegat)= 3cos(2omegat-pi//4)`it is simple <a href="https://interviewquestions.tuteehub.com/tag/harmonic-1015999" style="font-weight:bold;" target="_blank" title="Click to know more about HARMONIC">HARMONIC</a> with a time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> `T= (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(2omega)= (pi)/(omega)`</body></html> | |
| 36695. |
Which of the function of time represent (a) simple harmonic. (b) periodic but not simple harmonic. and (c) non periodic motion ? Give period for each case of periodic motion (omega is any positive constant), sin^(3)omegat |
| Answer» <html><body><p></p>Solution :`sin^(3)omegat` is a periodic <a href="https://interviewquestions.tuteehub.com/tag/function-11303" style="font-weight:bold;" target="_blank" title="Click to know more about FUNCTION">FUNCTION</a> but not simple harmonic because `aalpha-y` <a href="https://interviewquestions.tuteehub.com/tag/condition-409743" style="font-weight:bold;" target="_blank" title="Click to know more about CONDITION">CONDITION</a> is not <a href="https://interviewquestions.tuteehub.com/tag/satisfied-636887" style="font-weight:bold;" target="_blank" title="Click to know more about SATISFIED">SATISFIED</a>. Its time period is `T= (2pi)/(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>)`</body></html> | |
| 36696. |
The velocity ofa river current is u. A man crosses the river with velocity v making an angle theta with thedirection of the current. If the width of the river is d, find the time taken to cross the river and the displacement of the man in the direction of the current. What would be the minimum time required for crossing the river ?In what time could he reach exactly the opposite point ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`d/(<a href="https://interviewquestions.tuteehub.com/tag/vsin-3857785" style="font-weight:bold;" target="_blank" title="Click to know more about VSIN">VSIN</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>);<a href="https://interviewquestions.tuteehub.com/tag/dcot-3598205" style="font-weight:bold;" target="_blank" title="Click to know more about DCOT">DCOT</a> theta;d/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(u^2+v^2-2uvcos theta));d/(sqrt(v^2-2uvcos theta))`</body></html> | |
| 36697. |
The acceleration due to gravity at the latitude 45° on the earth becomes zero if the angular velocity of rotation of earth is equal to |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2/(<a href="https://interviewquestions.tuteehub.com/tag/gr-1010452" style="font-weight:bold;" target="_blank" title="Click to know more about GR">GR</a>))`<br/>`sqrt(2gR)`<br/>`sqrt((2g)/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)`<br/>`sqrt((5R)/2)` </p>Answer :C</body></html> | |
| 36698. |
Express cross and dot product of two vectors in Cartesian coordinate. |
| Answer» <html><body><p></p>Solution :Let `vecA and vecB` be the two vectors. <br/> `vecA=vecA_(x)hati+vecA_(s)<a href="https://interviewquestions.tuteehub.com/tag/hatj-2693584" style="font-weight:bold;" target="_blank" title="Click to know more about HATJ">HATJ</a>+vecA_(z)hatk, vecB=vecB_(x)hati+vecB_(y)hatj+vecB_(z)hatk` <br/> Cross product of `vecA and vecB`. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/vecaxxvecb-3257247" style="font-weight:bold;" target="_blank" title="Click to know more about VECAXXVECB">VECAXXVECB</a>=(vecA_(x)hati+vecA_(y)hatj+vecA_(z)hatk)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(vecB_(x)hati+vecB_(y)hatj+vecB_(z)hatk)` <br/> `=vecA_(x)vecB_(x)hatixxhati+vecA_(x)vecB_(y)hatixxhatj+vecA_(x)vecB_(z)hatixxhatk` <br/> `+vecA_(y)vecB_(y)hatjxxhati+vecA_(y)vecB_(z)hatjxxhatj+vecA_(z)B_(z)atkxxhatk` <br/> `vecAxxvecB=vecA_(x)vecB_(y)(hatk)+A_(x)B_(z)(-hatj)+vecA_(y)vecB_(x)(-hatk)+vecA_(y)vecB_(y)(0)` <br/> `+vecA_(y)vecB_(z)(hati)+vecA_(z)vecB_(x)(hatj)+vecA_(z)vecB_(z)(0)` <br/> `(vecAxxvecB)=(vecA_(y)vecB_(z)-vecA_(z)vecB_(y))hati+(vecA_(z)vecB_(x)-vecA_(x)vecB_(z))hatj+(vecA_(x)vecB_(y)-vecA_(y)vecB_(x))hatk` <br/> `[because hatixx hati=hatjxxhatj=hatkxxhatk=0` <br/> `hatixxhatj=k, hatixxhatk=-hatj, hatjxxhati=-k,hatjxxhatk=hati, hatk xxhati=+hatjxxhatj=-hatk]` <br/> It can be in <a href="https://interviewquestions.tuteehub.com/tag/determinant-949880" style="font-weight:bold;" target="_blank" title="Click to know more about DETERMINANT">DETERMINANT</a> form as, <br/> `vecA xx vecB=|(hati,hatj,hatjk),(A_(x),A_(y),A_(z)),(B_(x),B_(y),B_(z))|` <br/> `=hati(A_(y)B_(z)-B_(y)A_(z))-hatj(A_(x)B_(z)-B_(y)A_(z))+hatk(A_(x)B_(y)-B_(x)A_(y))` <br/> <a href="https://interviewquestions.tuteehub.com/tag/dot-958484" style="font-weight:bold;" target="_blank" title="Click to know more about DOT">DOT</a> product of `vecA and vecB`. <br/> `vecA=vecA_(x)hati+vecA_(y)hatj+vecA_(z)hatk, vecB=vecB_(x)hati+vecB_(x)hatj_vecB_(z)hatk` <br/> `vecA.vecB=(vecA_(x)hati+vecA_(y)hatj+vecA_(z)hatk).(vecB_(x)hati+vecB_(y)hatj+vecB_(z)hatk)` <br/> `(vecA_(x)vecB_(x)(hati.hatj)+vecA_(x)vecB_(y)(hati.hatj)` <br/> `+vecA_(x)vecB_(z)(hati.hatk)+vecA_(y)vecB_(x)(hatj.hatk)+vecA_(y)vecB_(y) (hati.hatj)` <br/> `+vecA_(y)vecB_(z)(hatj.hatk)+vecA_(z)vecB_(x)(hatk.hati)+vecA_(z)vecB_(y)(hatk.hatj)` <br/> `+A_(z)B_(z)(hatk.hatk)` <br/> `vecA.vecB=vec(A_(x))vec(B_(x))(1)+vec(A_(x))vec(B_(y))(0)+vecA_(x)vec(B_(z))(0)+vec(A_(y))vec(B_(z))(0)+vec(A_(y))vec(B_(y))(1)` <br/> `+vec(A_(y))vec(B_(z))(0)+vec(A_(z))vec(B_(x))(0)+vec(A_(z))v_(y)(0)+A_(z)B_(z)(1)` <br/> `vecA.vecB=vecA_(x)vecB_(x)+vec(A_(y))vec(B_(y))+vecA_(z)vecB_(z)` <br/> `[because hati.hati=hatj.hatj=hatk.hatk=1` <br/> `hati.hatj=hati.hatk=0, hatj.hati=hatj.hatk=0, hatk.hati=hatk.hatj=0]`</body></html> | |
| 36699. |
The angular momentum (M) of a particle relative to a certain point (O), varies with time as vec(M)=vec(a)+vec(b)t^(2) where vec(a) and vec(b) are constant vectors and vec(a) is perpendicular to vec(b). The moment of the force (N) relative to the point O, acting on the particle, when N makes 45^(@) with M is xbsqrt(a//b). Find the value of x ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 36700. |
A wire of length L and cross section area A is kept on a horizontal surface and one of its end is fixed at point 0. A ball of mass m is tied to its other end and the system is rotated with angular velocity omega.Show that increase in its length. Delta l = (m omega ^(2) L ^(2))/(AY). Y is young’s modulus. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P2_C09_E02_040_S01.png" width="80%"/> <br/> By rotating the ball of <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> m with angular speed <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>, the pseudo centifugal force acting on it due to centripetal force <br/> `F = ( mv ^(2))/() = ( <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> ^(2) omega ^(2))/( <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> )` <br/> `F = mL iomega^(2)` <br/> `therefore` ongitudinal stress `sigma = (F)/(A) = (mL omega ^(2))/(A) ` <br/> Let increase in length of rod `= Dela L` <br/> `therefore` strain `= (Delta L )/(L)` <br/> Young modulus `Y = ("stress")/("strain") = ( m Lomega ^(2))/(A) //(Delta L )/(L)`<br/> `therefore Delta L = (m L ^(2) omega ^(2))/(A.Y)`</body></html> | |