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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36851. |
A solid sphere is kept over a smooth surface as shown in figure. It is hit by a cute at height h above the centre C. In case 1, h=(R)/(2) and in case 1 the sphere acquires a total kinetic energy k_(1) and in case 2 total kinetic energy is k_(2) . Then, |
| Answer» <html><body><p>`k_(1)=k_(2)`<br/>`k_(1) gt k_(2)`<br/>`k_(1)<a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> k_(2)`<br/><a href="https://interviewquestions.tuteehub.com/tag/data-25577" style="font-weight:bold;" target="_blank" title="Click to know more about DATA">DATA</a> is sufficient</p>Answer :C</body></html> | |
| 36852. |
A particle is moving in the xy plane on a sinusoidal course determined by y = A sin kx, where k and A are constants. The X component of the velocity of the particle is constant and is equal to v_(0) and the particle was at origin at time t = 0. Find the magnitude of the acceleration of the particle when it is at point having x co ordinate x = (pi)/(2k). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`Ak_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)v_(0)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`</body></html> | |
| 36853. |
What is oscillatory motion? Give its examples. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :If a body moves to and fro back and forth or up and down about a fixed point in a definite interval of time, such a motion is called an oscillatory motion. <br/> For example : <br/> (1) A <a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> placed in a bowl will be in equilibrium at the bottom. If displaced a little from the point, it will perform oscillatory in the bowl. <br/> (2) The motion of the pendulum of a wall clock is oscillatory motion. <br/> (3) The motion of a loaded spring, when the load attached to the spring is palled once a little from its mean position and left to itself. <br/> Every oscillatory motion is periodic, but every periodic motion need not be oscillatory. <br/> <a href="https://interviewquestions.tuteehub.com/tag/restoring-1187260" style="font-weight:bold;" target="_blank" title="Click to know more about RESTORING">RESTORING</a> force is produced in such type of motion <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> no external force <a href="https://interviewquestions.tuteehub.com/tag/constantly-2017529" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANTLY">CONSTANTLY</a> needed for continuation this motion. <br/> Such type of motion is also known as harmonic motion.</body></html> | |
| 36854. |
A ball of mass .m., moving with uniform speed, collides elastically with another stationary ball. For what mass of stationary ball the incident ball will lose maximum kinetic energy? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :m</body></html> | |
| 36855. |
Explain the lift of an aircraft wing using Bernoulli's principle. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/wings-1457588" style="font-weight:bold;" target="_blank" title="Click to know more about WINGS">WINGS</a> of an airplane (aerofoil) are so designed that its upper <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> is more curved than the lower surface and the <a href="https://interviewquestions.tuteehub.com/tag/front-1000768" style="font-weight:bold;" target="_blank" title="Click to know more about FRONT">FRONT</a> edge is broader than the real edge. As the aircraft moves, the air moves <a href="https://interviewquestions.tuteehub.com/tag/faster-985028" style="font-weight:bold;" target="_blank" title="Click to know more about FASTER">FASTER</a> above the aerofoil than at the bottom as shown in Figure.<br/>According to Bernoulli's Principle, the pressure of air below is greater than above, that creates an upthrut called the dynamic lift to the aircraft.<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E02_123_S01.png" width="80%"/></body></html> | |
| 36856. |
A particle moving withg uniform retardation covers distance 18 m .14 m and 10 m in successive seconds .It comes to rest after travelling a further distance of |
| Answer» <html><body><p>50m<br/>8m<br/>12m<br/>42m</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36857. |
A source of sound moves towards an observer with a velocity 108km//h and the observer also moves towards the source with the velocity 5 km/h, then the velocity of sound is |
| Answer» <html><body><p>`320ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`330ms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/340ms-1856857" style="font-weight:bold;" target="_blank" title="Click to know more about 340MS">340MS</a>^(-1)`<br/>Data insufficient</p>Solution :`n._(app)=n[(V+V_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>))/(V-V_(S))]`</body></html> | |
| 36858. |
What is the moment of inertia of a ring about a tangent to the circle of the ring? |
| Answer» <html><body><p></p>Solution :The tangent to the ring in the plane of the ring is <a href="https://interviewquestions.tuteehub.com/tag/parallel-1146369" style="font-weight:bold;" target="_blank" title="Click to know more about PARALLEL">PARALLEL</a> to one of the <a href="https://interviewquestions.tuteehub.com/tag/diameters-950922" style="font-weight:bold;" target="_blank" title="Click to know more about DIAMETERS">DIAMETERS</a> of the ring. <br/> The <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> between these two parallel axes is R, the radius of the ring. Using the parallel axes theorem, <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BEN_PHY_XI_P1_C07_SLV_012_S01.png" width="80%"/> <br/> `I_("tangent")=I_(dia)+MR^(2)=(MR^(2))/(2)+MR^(2)=(3)/(2)MR^(2)`.</body></html> | |
| 36859. |
A sphere can roll on a surface inclined at an angle theta if the friction coefficient is more than (1)/(7)g tan theta . If a sphere is relased from rest on the incline |
| Answer» <html><body><p>it will stay at rest<br/>it will make pure translational motion<br/>it will <a href="https://interviewquestions.tuteehub.com/tag/translate-1426121" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLATE">TRANSLATE</a> and rotate about the centre<br/>the angular <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> of the <a href="https://interviewquestions.tuteehub.com/tag/sphere-1222094" style="font-weight:bold;" target="_blank" title="Click to know more about SPHERE">SPHERE</a> about its centre will <a href="https://interviewquestions.tuteehub.com/tag/remain-1184279" style="font-weight:bold;" target="_blank" title="Click to know more about REMAIN">REMAIN</a> constant</p>Answer :C</body></html> | |
| 36860. |
What work has to be done to make a hoop out of a copper band of length l=3m,width h=6 cm and thickness delta =1mm? (Y of copper =1.3xx10^(11) ""Nm^(-2) ) [Hint: Consider strain energy in a a thin layer and intergraate from r-delta//2 "to" r+delta//2] |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(1)/(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)pi^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)hdelta^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)Y//=80J`</body></html> | |
| 36861. |
A 1 kg block situated on a rough incline is connected to a spring of spring constant 100 Nm^(-1) as shown in Fig. 6.17. The block is released from rest with the spring in the unstreched position. The block moves 10 cm down the incline before coming to rest. Find the coefficient of friction between the block and the incline. Assume that the spring has a negligible mass and the pulley is frictionless. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`= 0.125`</body></html> | |
| 36862. |
In which of the following cases is the angular momentum conserved ? |
| Answer» <html><body><p>The planet Neptune moves in an elliptical orbit with the sun at one of the foci of the ellipse. <br/>An electron <a href="https://interviewquestions.tuteehub.com/tag/describes-948998" style="font-weight:bold;" target="_blank" title="Click to know more about DESCRIBES">DESCRIBES</a> a Sommerfield elliptical orbit round the nucleus. <br/>An `alpha`- particle, approaching a nucleus, is scattered by the force of electronstatic repulsion between the two. <br/>A boy <a href="https://interviewquestions.tuteehub.com/tag/hurls-7688383" style="font-weight:bold;" target="_blank" title="Click to know more about HURLS">HURLS</a> a stone <a href="https://interviewquestions.tuteehub.com/tag/tied-7301691" style="font-weight:bold;" target="_blank" title="Click to know more about TIED">TIED</a> to a string ina horizontal <a href="https://interviewquestions.tuteehub.com/tag/circle-916533" style="font-weight:bold;" target="_blank" title="Click to know more about CIRCLE">CIRCLE</a>. </p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::C</body></html> | |
| 36863. |
State galileo 's law of inertia |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :A bodymovingin astraightlinewithcertainspeedwillcontinuemovingin thesamestraightline <a href="https://interviewquestions.tuteehub.com/tag/witha-1458013" style="font-weight:bold;" target="_blank" title="Click to know more about WITHA">WITHA</a> samespeedin theabsenceof anyexternalforce .</body></html> | |
| 36864. |
A prism of refractive angle 4^@ is made of a material of refractive index 1.652. Find its angle of minimum deviation. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`A=<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>^@, mu=1.652, <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a>=?` <br/> <a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> in `delta=A(mu-1)=4^@(1.652-1)` <br/> `=4^@ <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> 0.652=2.608^@`</body></html> | |
| 36865. |
Three vectors satisfy the relation A.B = 0 and A.C = 0, then A is parallel to |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>B<br/>`BxxC`<br/>`B.C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 36866. |
Match the following according to conversion by heat : |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a-ii), (b-i)</body></html> | |
| 36867. |
In the digram shown in figure |
| Answer» <html><body><p>`X=A+B-C+D`<br/>`Y=B+C-A`<br/>`Z=B+C`<br/>`W=A+B`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(b.,c) Apply <a href="https://interviewquestions.tuteehub.com/tag/polygon-602436" style="font-weight:bold;" target="_blank" title="Click to know more about POLYGON">POLYGON</a> law , <br/> We <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a>` Y=B+C-Aand Z=B+C`</body></html> | |
| 36868. |
G = 6.67xx10^(-11) N m^(2)(kg)^(-2) = ………. (cm)^(3)s^(-2)g^(-1). |
| Answer» <html><body><p></p>Solution :`G-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>.67xx10^(-11) Nm^(-2)(kg)^(-2)` <br/> `=6.67xx10^(-11) (kg <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2)) m^(2) kg^(-2) "" ( :. 1N= <a href="https://interviewquestions.tuteehub.com/tag/1k-282789" style="font-weight:bold;" target="_blank" title="Click to know more about 1K">1K</a> g ms^(-2))` <br/> `=6.67xx10^(-10) m^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)s^(2)-kg^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> `=6.67xx10^(-11)(10^(2) cm)^(3)s^(-2)(10^(3) g)^(-1)` <br/> `=6.687xx10^(-11)xx10^(6)cm^(3)s^(-2)xx10^(-3) g^(-1)` <br/> `=6.67xx10^(-8) cm^(3) s^(-2)g^(-1)`</body></html> | |
| 36869. |
If a disc of mass m and radius r is reshaped into a ring of radius2r, the mass remining the same, the radius of gyration about centrodal axis perpendicular to plane goes up by a factor of |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2)`<br/>2<br/>`2 sqrt(2)`<br/>4</p>Solution :The radius of <a href="https://interviewquestions.tuteehub.com/tag/gyration-1014165" style="font-weight:bold;" target="_blank" title="Click to know more about GYRATION">GYRATION</a>, `K_(D)=sqrt((I_(D))/(m))=sqrt(((1)/(2)mr^(2))/(m))=(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)/(sqrt(2))` <br/> `K_(R)=sqrt((I_(PR))/(m))=sqrt((m(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>)^(2))/(m))=2r` <br/> `:. (K_(R))/(K_(D))=2 sqrt(2)`.</body></html> | |
| 36870. |
Figures depicts two circular motions. The radius of the circle, the period of revolution, the initial position and the sense of revolution are indicated on the figures. Obtain the simple harmonic motions of the x-projection of the radius vector of the rotating particle P in each case. |
| Answer» <html><body><p></p>Solution :(a) As shown in figure, <a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> a particle moving with uniform circular motion is at `P_1` at time t=0 and makes and angle `<a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a> = 45^(@)((pi)/(4)<a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a>)` with <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> x-axis. After time `t_1` it covers an angle `omega t` and reaches at `P_2` and makes an angle `theta = omega t + phi` with positive x-axis. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C14_E02_012_S01.png" width="80%"/> <br/> Makes an angle `theta = (2pi)/(T)t+ (pi)/(4)` <br/> The projection of OP on the x-axis at time t is given by `x (t) = A <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> ((2pi)/(T)t+(pi)/(4))" have "OP_(2) = A cos (omega t+phi)` <br/> It `t= 4s` then, `x(t) = A cos ((2pi)/(4)t+(pi)/(4)) = A cos ((pi)/(4)+(pi)/(4)) = A sin (pi)/(4)`. <br/> Which is a SHM of amplitude A, period 4s and an initial phase `= (pi)/(4) rad`. <br/> (b) As shown in figure, suppose a particle moving with uniform circular motion is on P at time t=0 and makes an angle `phi = 90^(@) =(pi/2)` with positive x-axis after a time t, it covers an angle of `omega t` and reaches at `P_1` with clockwise direction and makes an angle of `theta = (pi)/(2) - omega t`. The projection of `P._1` on the x-axis `OP._1`. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C14_E02_012_S02.png" width="80%"/> <br/> `x(t) = B cos theta = B cos((pi)/(2)- omega t)= B sin omega t` <br/> `= B cos (omega t-(pi)/(2))""[therefore cos(-theta)= cos theta]` <br/> `therefore x(t) = B cos ((pi)/(15)t- (pi)/(2))` <br/> This represents a SHM of amplitude B, period T= 30s and an initial phase of `-(pi)/(2)`.</body></html> | |
| 36871. |
The following does not give the unit of energy |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/watt-1450279" style="font-weight:bold;" target="_blank" title="Click to know more about WATT">WATT</a> <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/kilowatt-533225" style="font-weight:bold;" target="_blank" title="Click to know more about KILOWATT">KILOWATT</a> hour <br/><a href="https://interviewquestions.tuteehub.com/tag/newton-11212" style="font-weight:bold;" target="_blank" title="Click to know more about NEWTON">NEWTON</a> <a href="https://interviewquestions.tuteehub.com/tag/meter-1095017" style="font-weight:bold;" target="_blank" title="Click to know more about METER">METER</a> <br/>pascal metre</p>Answer :D</body></html> | |
| 36872. |
The handles of a table-drawer are equidistant from the sides of the drawer and are distant c from each other. Show that it will be impossible to pull the drawer out by pulling one handle if l le mu c where l is the length of the drawer from back to front and mu is the coefficient of friction [Hint : Consider a force applied at inclination theta with the knob of the handle. Apply conditions for translational and rotational equilibrium. Hence show it is possible to draw when tan theta ge (l-muc)/(mu^(2)c+2mu^(2)x+2muI) Since tan theta is positive, l ge mu c] |
| Answer» | |
| 36873. |
An ideal gas expands in such a way that its. Pressure and volume satisfy with the condition PV^2= constant. During this process, the gas is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/heated-1017243" style="font-weight:bold;" target="_blank" title="Click to know more about HEATED">HEATED</a><br/>Cooled<br/>First heated then cooled<br/>Neither '<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>' nor '2'</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36874. |
A conveyer belt is moving at a constant speed of 2 ms^(-1) A box is gently dropped on it. The coefficient of friction between them is mu = 0.5. The distance that the box will move relative to belt before coming to rest on it, taking g= 10 ms^(-2), is |
| Answer» <html><body><p>`0.4 m`<br/>1.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> m<br/>0.6m<br/>zero</p>Solution :Forceof Friction` f^(-)mu <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> ` <br/> ` thereforea = (f)/( m )= (mu mg)/( m)= mu g= 0.5xx 10= <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a>`v^2- u^2= 2aS `<br/> ` 0^2 -2^2 =2 (-5) xx SimpliesS= 0.4m`</body></html> | |
| 36875. |
In Exercises 3.13 and 3.14, we have carefully distinguished between average speed and magnitude of average velocity. No such distinction is necessary when we consider instantaneous speed and magnitude of velocity. The instantaneous speed is always equal to the magnitude of instantaneous velocity. Why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In Exercises 3.13 and 3.14, we have <a href="https://interviewquestions.tuteehub.com/tag/carefully-2014243" style="font-weight:bold;" target="_blank" title="Click to know more about CAREFULLY">CAREFULLY</a> <a href="https://interviewquestions.tuteehub.com/tag/distinguished-440820" style="font-weight:bold;" target="_blank" title="Click to know more about DISTINGUISHED">DISTINGUISHED</a> between average <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> and magnitude of average velocity. No such distinction is necessary when we <a href="https://interviewquestions.tuteehub.com/tag/consider-2017521" style="font-weight:bold;" target="_blank" title="Click to know more about CONSIDER">CONSIDER</a> instantaneous speed and magnitude of velocity. The instantaneous speed is always equal to the magnitude of instantaneous velocity. Why?</body></html> | |
| 36876. |
Explain the motion of blocks connected by a string in (i) vertical motion (ii) horizontal motion . |
| Answer» <html><body><p></p>Solution : Verticalmotion : Let us considertwoblocksof masses `m_(1)` and `m_(2) (m_(1) gtm_(2))`connectedby alightandinextensiblestringthatpassesovera pulley <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E01_029_S01.png" width="80%"/> <br/>Let thetensionin thestringbe Tand acceleration aWhenthe systemisreleasedboth theblocksboth thestartmoving`m_(2)`verticallyupwardwithsameaccelerationa. The gravitationalforce `m_(1)`<a href="https://interviewquestions.tuteehub.com/tag/gon-474881" style="font-weight:bold;" target="_blank" title="Click to know more about GON">GON</a> <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> `m_(1)` is usedto lift the mass `m_(2)` <br/> theupwarddirection is selectedas ydirection. the free bodydiagrams ofbothmasses. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E01_029_S02.png" width="80%"/><br/> Horizontal motion : in this case mass `m_(2)` is kept on a horizontal table and mass `m_(1)`is hanging through a smalll pulley it is assumed that there is no friction on the surface<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E01_029_S03.png" width="80%"/> <br/> As both the <a href="https://interviewquestions.tuteehub.com/tag/blocks-21562" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCKS">BLOCKS</a> are <a href="https://interviewquestions.tuteehub.com/tag/connectedto-2538398" style="font-weight:bold;" target="_blank" title="Click to know more about CONNECTEDTO">CONNECTEDTO</a> the unstrechable stringif `m_(1)` moves with an acclereation a downward athen `m_(2)`also moves iwth the same acceleration a horizontally<br/> The forces acting on mass `m_(2)`are <br/> (i) horizontal tension (T) exerted by the string <br/> (ii) upward normal force (N) exerted by the surface <br/> (iii) Downard normal gravitational force `(m_(2)g)`<br/> The forces acting on mass `m_(1)` are<br/> (i)Tension (T) acting upwards <br/> (ii) Downward gravitational force `(m_(1)g)` the free body diagrams for both the masses is<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C03_E01_029_S04.png" width="80%"/></body></html> | |
| 36877. |
State the theorem of parallel axis. |
| Answer» <html><body><p></p>Solution :The moment of inertia of a <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> about any axis is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the sum of moments of inertia of the body about a parallel axis passing through the centre of mass and the product of mass of the square of the <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> between the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> parallel axes. <br/> i.e., `I=I_0+Md^2`</body></html> | |
| 36878. |
In Fig. there are n identical suspended with wires of equal length. The spheres are almost in contact with each other. Sphere 1 is pulled aside and released. If sphere 1 strikes sphere 2 with velocity u. find an expression for velocity v_(n) of the nth sphere immediately after being struck by the one adjacent to it. The coefficient of restitution for all the impacts is e. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> velocities of <a href="https://interviewquestions.tuteehub.com/tag/sphere-1222094" style="font-weight:bold;" target="_blank" title="Click to know more about SPHERE">SPHERE</a> `1` and `2` after <a href="https://interviewquestions.tuteehub.com/tag/collision-922060" style="font-weight:bold;" target="_blank" title="Click to know more about COLLISION">COLLISION</a> be `v_(1)` and `v_(2)`, respectively, then <br/> `(v_(2)-v_(1))/u=e` and `mv_(2)+mv_(1)="mu"` <br/> From above equations `v_(2)=((1+e)u)/2` <br/> Now sphere `2` will collide with sphere `3` and affter collision velocity of `3` can be formed as <br/> `v_(3)=((1+e)/2)^(2)u` <br/> Hence, similarly velocity of `nth` sphere can be formed as <br/> `v_(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)=((1+e)/2)^(n-1)u`</body></html> | |
| 36879. |
Block of mass m is placed on frictionless slope with angle 0. Normal force acting on block due to surface will be ..... |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> <br/>`(mg)/(<a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>)`<br/>`mg cos theta`<br/>`mg sin theta` </p>Solution :As <a href="https://interviewquestions.tuteehub.com/tag/shownin-1206577" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWNIN">SHOWNIN</a> figure<br/>perpendicularcomponentofweightmg thatismg cos`theta`providenormalforce N = mg cos`theta ` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C05_E05_038_S01.png" width="80%"/></body></html> | |
| 36880. |
A gas consisting of rigid diatomic molecules is expanded adiabatically. How many times has the gas to be expanded to reduce the R.M.S velocity of the molecules 1.5 times ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :7.6 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a></body></html> | |
| 36881. |
A force of (7hati +6hatk) newton makes a body move on a rough plane with a velocity of (3 hatj+4hatk) ms^(-1). The power in watt is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a> <br/>34 <br/>21 <br/><a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a> </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/power-2475" style="font-weight:bold;" target="_blank" title="Click to know more about POWER">POWER</a>, `P , vecF .Vecv = (7 hati + 6hatk).(3hatj + 4hatk) = 24 <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>`.</body></html> | |
| 36882. |
A piece of wire is bent in the shape of a parabola y = kx^(2)(y-axis vertical) with a bead of mass 'm' on it. The bead can slide on the wire without friction. The wire is now accelerated parallel to the x-axis where the with an acceleration'a'. The distance of the new equilibrium position of the bead isa/(xgk) where the bead can stay at rest with respect to the wire from y-axis. The value of x' is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 36883. |
A 6kg mass collides with a body at rest. After the collision, they travel together with a velocity one third the velocity of 6 kgmass.The mass of the secon body is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> kg<br/>3 kg<br/>12 kg<br/>18 kg</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36884. |
What is called forced convection ? |
| Answer» <html><body><p></p>Solution :If the <a href="https://interviewquestions.tuteehub.com/tag/movement-1104563" style="font-weight:bold;" target="_blank" title="Click to know more about MOVEMENT">MOVEMENT</a> of material is <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> by artificial <a href="https://interviewquestions.tuteehub.com/tag/instruments-1046453" style="font-weight:bold;" target="_blank" title="Click to know more about INSTRUMENTS">INSTRUMENTS</a> like Fan, pump, etc. then <a href="https://interviewquestions.tuteehub.com/tag/convection-425641" style="font-weight:bold;" target="_blank" title="Click to know more about CONVECTION">CONVECTION</a> is called forced convection.</body></html> | |
| 36885. |
Calculate the amount of energy released if 27 drops of diameter 10^(-9)m each coalesce to form a bigger drop. The surface tension of water is 0.072 N/m. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`4.07 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/18-278913" style="font-weight:bold;" target="_blank" title="Click to know more about 18">18</a>)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`</body></html> | |
| 36886. |
A particle of mass m_(1)=4 kg moving at 6hat(i) m/s collides perfectly elastically with a particle of mass m_(2)=2kg moving at 3hat(i)m//s. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of centre mass is `5hat(i)m//s` <br/>The velocities of the particles relative to the centre of mass have same <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of individual particle before and after collision remains same <br/>The velocity of particles relative to <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> after collision are `<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(V)_(1f//cm)=-hat(i)m//s vec(V)_(2f//cm)=-2hat(i)m//s` </p>Answer :A::D</body></html> | |
| 36887. |
When a body moves along a rough horizontalsurface which of the following formula is incorrect |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/retardation-1187717" style="font-weight:bold;" target="_blank" title="Click to know more about RETARDATION">RETARDATION</a> `a=(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)/(m)= mu g` <br/><a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> of <a href="https://interviewquestions.tuteehub.com/tag/friction-21545" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTION">FRICTION</a> `f=muR=mumg`<br/>workdone against friction `W=tauxx s`<br/>power p = f x v =`mu mgv` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36888. |
The temperatures T_1 and T_2of two heat reservoirs in the ideal Carnot engine are 1500^@C and 500^@Crespectively. Which of these, increasing T_1 by 100^@Cor decreasing T_2 by 100^@C , would result in a greater improvement in the efficiency of the engine? |
| Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/increasing-1040633" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASING">INCREASING</a> `T_1`<br/><a href="https://interviewquestions.tuteehub.com/tag/decreasing-946148" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASING">DECREASING</a> `T_2`<br/> either (a) or (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)<br/>None </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 36889. |
Suppposing Netwon's law of gravitationa for gravitation forces overset rarr(F_(1)) and overset rarr(F_(2)) between two masses m_(1) and m_(2) at positions overset rarr(r_(1)) and oversetrarr(r_(2)) read oversetrarr(F_(1)) = - oversetrarr(F_(2)) = -(oversetrarrr_(12))/(r_(12)^(3)) GM_(0)^(2) ((m_(1)m_(2))/(M_(0)^(2)))^(n) where M_(0) is a constant of dimension of mass, oversetrarr(r_(12)) =oversetrarr(r_(1)) -oversetrarr(r_(2)) and n is a number. in such a case, |
| Answer» <html><body><p>the <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to gravity on earth will be different for different objects.<br/>none of the three laws of kepler will be valid.<br/>only of the third law will become invalid.<br/>for `n` negative, an object ligther than water will sink in water.</p>Solution :`F = (r_(12))/(r_(12)^(<a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>)) GM_(0)^(2) [(m_(1)m_(2))/(M_(0)^(2))]^(n) = (GM_(0)^(2(1 - n)))/(r_(12)^(12))(m_(1)m_(2))^(n)` <br/> Acceleration due to gravity, `g = (F)/(mass) = (GM_(0)^(2(1 - n)))/(r_(12)^(12)) ((m_(1)m_(2))^(n))/(mass)`<br/> Thus acceleration due to gravity on earth is different for different objects. In this situation Kepler's third law will not be valid. <br/> When `n` is negative, then <br/> `g = (GM_(0)^(2(1 + n)))/(r_(12)^(12)) ((m_(1)m_(2))^(-n))/(mass)` <br/> which is <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> as `M_(0) gt m_(1)` or `m_(2)`. <br/> Therefore, object ligher than water will sink in water.</body></html> | |
| 36890. |
Which oneof the force does not depend on the velocity - frictional force betweencontact surface of two solid or viscous force ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Frictiona <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> between <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> -<a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> of two <a href="https://interviewquestions.tuteehub.com/tag/solids-1216975" style="font-weight:bold;" target="_blank" title="Click to know more about SOLIDS">SOLIDS</a> does not depend on velocity .</body></html> | |
| 36891. |
The force constant of a particle of mass 1 kg is SHM of amplitude 4 cm is 100N/mwhen particle is at mean position at t=0 then find macimum speed. |
| Answer» <html><body><p>`0.4 m//s`<br/>`0.6 m//sec`<br/>`0.8 m//sec`<br/><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> sec</p>Answer :A</body></html> | |
| 36892. |
The electric force between two electric charges is given by F= (1)/(4pi epsi_(0))(q_(1)q_(2))/(r^(2)). where is a distance . between charges q_(1) and q_(2) . So, unit and dimensional formula of epsi_(0), is ...... and...... respectively. |
| Answer» <html><body><p>`N^(1)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>^(2)m^(-2),M^(-1)L^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)T^(4)A^(2)`<br/>`N^(-1)<a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>^(-2),M^(-1)L^(-1)T^(-1)A`<br/>`N^(2)C^(2)m^(-2)M^(-1)L^(-3)T^(4)A^(2)`<br/>`NCm^(-2),MLTA`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`F=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/4pi-1882352" style="font-weight:bold;" target="_blank" title="Click to know more about 4PI">4PI</a> epsi_(0)).(q_(1)q_(2))/(r^(2))` <br/> `:.epsi_(0)=(q_(1)q_(2))/(4pi Fr^(2))` <br/> `:.` Units of `epsi_(0)=(C^(2))/(Nm^(2))=N^(-1)C^(2)m^(-2)` <br/> `[epsi_(0)]=([C^(2)])/([N][m^(2)])=(A^(2)T^(2))/((M^(1)L^(1)T^(-2))(L^(2)))` <br/> `=M^(-1)L^(-3)T^(4)A^(2)`</body></html> | |
| 36893. |
Give values of amplitude at node and anti-node. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Amplitude at nodal point =<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> <br/> Amplitude at antinodal point = <a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a> = <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> amplitude in a stationary wave <br/> (Where A = amplitude of one of two <a href="https://interviewquestions.tuteehub.com/tag/component-926634" style="font-weight:bold;" target="_blank" title="Click to know more about COMPONENT">COMPONENT</a> waves of stationary waves).</body></html> | |
| 36894. |
For the damped oscillator x(t)= x_(m) e^(-bt"/"2m), if m= 250gm, k= 85 N"/"m and b= 70 g"/"s, the period of motion is |
| Answer» <html><body><p>`0.34 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>`<br/>`0.68 sec`<br/>`1.02 sec`<br/>`0.17 sec`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36895. |
A gas with C_(P)//C_(V)= goes from an initial state (P_(1), V_(1), T_(1)) to a final state (P_(2), V_(2), T_(2)) through an adiabatic process. The work done by the gas is a)nR((T_(1)-T_(2)))/(gamma-1) b)(P_(1)V_(1)-P_(2)V_(2))/(gamma-1) c) nRgamma(T_(1)-T_(2)) |
| Answer» <html><body><p>a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> <br/>b and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true <br/>both a and c are true <br/>a, b, c are true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36896. |
Two metal balls having masses 50g and 100gcollides with a target with same velocity. Then the ratio of their rise in temperatures is |
| Answer» <html><body><p>`1:2` <br/>`4:1` <br/>`2:1` <br/>`1:1` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36897. |
A body is dropped from a height 135 m. If after 3 sec acceleration due to gravity of earth cases to act then the further time of descent is (g=10m//s^(2)) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> sec<br/>6 sec<br/>4 sec<br/>2 sec</p>Answer :A</body></html> | |
| 36898. |
A well insulated box is packed with ice at 0°C and kept in a room at a temperature of 30°C. The lid of the box is made of a cardboard sheet of thickness 4 mm and area 100 "cm"^(2). If the ice melts at the rate of 0.045 kg per hour, calculate the thermal conductivity of cardboard assuming that heat can enter the box only through the lid. [L.H. of fusion of ice = 336 "KJ/kg" ] |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`0.056 "<a href="https://interviewquestions.tuteehub.com/tag/wm-744315" style="font-weight:bold;" target="_blank" title="Click to know more about WM">WM</a>"^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) "<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>"^(-1)`</body></html> | |
| 36899. |
Intensity of Magnetization has the same dimensions as |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/magnetic-551115" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNETIC">MAGNETIC</a> susceptibility<br/>Magnetic moment<br/>Intensity of <a href="https://interviewquestions.tuteehub.com/tag/magnetizing-2808480" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNETIZING">MAGNETIZING</a> field<br/>Magnetic permeability</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36900. |
A car moves for half of its time at 80 km/h and for rest half of time at 40 km/h. Total distance covered is 60 km. What is the average speed of the car |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> km/h<br/>80 km/h<br/>120 km/h<br/>180 km/h </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |