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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37351. |
A and B are two objects-moving with velocities oversettoV_Aand oversettoV_B. What is the velocity of A relative to B? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`oversettoV_(<a href="https://interviewquestions.tuteehub.com/tag/ab-360636" style="font-weight:bold;" target="_blank" title="Click to know more about AB">AB</a>)=oversettoV_A-oversettoV_B`</body></html> | |
| 37352. |
A heavy ball of radius R is travelling on a smooth horizontal surface with a velocity of u0 towards left. A horizontally moving small ball of mass mstrikes it at a height (R)/(2) above the centre whiletravelling with velocity u towards right. (a) After collision the small ball moves in vertically upwards direction with velocity u.Prove that this can happen only if ugt sqrt(3)u_(0) (b) Find the velocity of small ball after collision if the collision is elastic and the balls are smooth. |
| Answer» <html><body><p><br/></p>Answer :(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>^(2)+3u_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)^(2)+3u u_(0))`</body></html> | |
| 37353. |
(A): Equal moles of helium and oxygen gases are given cqual quantities of heat at constant volume. There will be greater rise in the temperature of helium compared to that of oxygen. (R): The molecular weight of oxygen is greater than the moleculat weight of helium. |
| Answer» <html><body><p>Both (A) and ( <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R ) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>Both (A) and (R ) are false </p>Answer :B</body></html> | |
| 37354. |
To maintain a rotor at a uniform angular speed of 200 rad s^(-1), an engine needs to transmit a torque of 180 N m. The power required by the engine. Assume that the engine is 100% efficient. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a> <a href="https://interviewquestions.tuteehub.com/tag/kw-1063128" style="font-weight:bold;" target="_blank" title="Click to know more about KW">KW</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/18-278913" style="font-weight:bold;" target="_blank" title="Click to know more about 18">18</a> kW <br/><a href="https://interviewquestions.tuteehub.com/tag/48-318016" style="font-weight:bold;" target="_blank" title="Click to know more about 48">48</a> kW<br/>72 kW </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37355. |
A physical quantity is represented by x=M^(a)L^(b)T^(c ). The percentage of errors in the measurements are alpha %, beta %, gamma % then the maximum percentage error is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> a+beta <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>-<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <a href="https://interviewquestions.tuteehub.com/tag/gamma-470142" style="font-weight:bold;" target="_blank" title="Click to know more about GAMMA">GAMMA</a>`<br/>`alpha a+beta b+gamma c`<br/>`alpha a-beta b-gamma c`<br/>`alpha a-beta b+gamma c`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 37356. |
Three uniform spheres each of mass .m. and diameter D are kept in such a way that each touches the other two, then the magnitude of the gravitational force on any one sphere due 82 to other two is |
| Answer» <html><body><p>`(3Gm^2)/D^2` <br/>`(2sqrt3Gm^2)/D^2` <br/>`(sqrt3Gm^2)/(4D^2)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)(Gm^2)/D^2` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37357. |
A travelling harmonic wave on a string is described by y(x,t) = 7.5 sin (0.005 x + 12t+ pi//4) (a) what are the displacement and velocity of oscillation of a point at x=1 cm, and t=1s? Is this velocity equal to the velocity of wave propagation? (b) Locate the points of the string which have the same transverse displacements and velocity as the x=1 cm point at t=2s, 5s and 11s |
| Answer» <html><body><p></p>Solution :(a) 1.66 cm, `87.75 cm s^(-1)`, No, the velocity of <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> propagation is `-24ms^(-1)` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) All <a href="https://interviewquestions.tuteehub.com/tag/points-1157347" style="font-weight:bold;" target="_blank" title="Click to know more about POINTS">POINTS</a> at distance of `<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> <a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a> (n = +- 1, +-2, +-3..)` where `lamda= 12.6m` from the point x=1 cm</body></html> | |
| 37358. |
Equation of continuity expresses the law of conservation of |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> <br/>none</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37359. |
At a pressure of 24xx10^(5) dyne/cm^(2),the volume of O_(2) is 10 litre and mass is 20 gm.The r.m.s velocity will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/800-338448" style="font-weight:bold;" target="_blank" title="Click to know more about 800">800</a> m/sec<br/>400 m/sec<br/>600 m/sec<br/>200 m/sec</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37360. |
The side of a cube, as measured with a vernier calipers of least count 0.01cm is 3.00cm. The maximum possible error in the measurement of volume is |
| Answer» <html><body><p>`+- 0.01 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`+- 0.06cm^(3)`<br/>`+- 0.0cm^(3)`<br/>`+- 0.27cm^(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37361. |
A plate of area 10m^(2) is made to move horizontally with a speed of 0.5 ms^(-1) by applying a force over the surface a liquid. If the depth of the liquid is 2.5m, coefficient of viscosity of liquid is 10^(-3)Nsm^(-2), then calculate the horizontal force needed to move the plate. |
| Answer» <html><body><p></p>Solution :Given `Deltav=0.5 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)` <br/> `Deltax=2.5m` <br/> velocity gradient `=(Deltav)/(Deltax)=(0.5)/(2.5)=0.2(ms^(-1))/(m)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SPH_ABT_PHY_QB_XI_C10_E04_006_S01.png" width="80%"/> <br/> We <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> that |<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>| `=etaA((Deltav)/(Deltax))=10^(-3) xx 10^(2) xx 10^(-2)=10^(-3)N` <br/> Hence `10^(-3)N` of force is needed to be applied, to <a href="https://interviewquestions.tuteehub.com/tag/keep-527902" style="font-weight:bold;" target="_blank" title="Click to know more about KEEP">KEEP</a> the <a href="https://interviewquestions.tuteehub.com/tag/plate-1156364" style="font-weight:bold;" target="_blank" title="Click to know more about PLATE">PLATE</a> moving.</body></html> | |
| 37362. |
A sphere of mass 3 kg and radius 0.2 m rolls down from the slope of height 7 m, its rotational kinetic energy will be …………. |
| Answer» <html><body><p>`42J`<br/>`60J`<br/>`36J`<br/>`70J`</p>Solution :Velocity of body at the <a href="https://interviewquestions.tuteehub.com/tag/bottom-401202" style="font-weight:bold;" target="_blank" title="Click to know more about BOTTOM">BOTTOM</a> slope of height h when the rolls is <br/> `v=sqrt((2gh)/(1+(k^(2))/(R^(2))))=sqrt((2gh)/(1+(2)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)))[because k=sqrt((2)/(5))Rrarr" for sphere"]` <br/> `therefore v=sqrt((10gh)/(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>))=sqrt((10xx10xx7)/(7))=10m//s` <br/> Now rotational <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energy <br/> `therefore k=(1)/(2)Iomega^(2)` <br/> `therefore k=(1)/(2)xx(2)/(5)<a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(2)xx(v^(2))/(R^(2))[because" For sphere "I=(2)/(5)MR^(2),omega=(v)/(R)]` <br/> `therefore k=(1)/(5)Mv^(2)=(1)/(5)xx3xx(10)^(2)=(300)/(5)` <br/> `therefore k=60J`</body></html> | |
| 37363. |
(A) : When a bicycle is in motion, the force of friction exerted by the ground on the two wheels is always in forward direction.(R ) : The frictional force only when the bodies are in contact. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R ) is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37364. |
If k is the force constant of a spring the work done [against restoring force] in increasing its extension from l_(1) to l_(2) will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>(l_(2)-l_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))`<br/>`K//2(l_(2)+l_(1))`<br/>`K(l_(2)^(2)-l_(1)^(2))`<br/>`(K)/(2)(l_(2)^(2)-l_(1)^(2))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></body></html> | |
| 37365. |
To move an object, which one is easier, push or pull? Explain |
| Answer» <html><body><p></p>Solution :When a body is pushed at an arbitraryangle `theta(0 " to " (pi)/(2))`, the applied force F can be resolved into two components as F `<a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta` <a href="https://interviewquestions.tuteehub.com/tag/parallel-1146369" style="font-weight:bold;" target="_blank" title="Click to know more about PARALLEL">PARALLEL</a> to the surface and F `cos theta` perpendicularto the surface as shown in Figure. The total downward force <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on the body is `mg+Fcos theta`. It implies that the normal force acting on the body increases. Since thereis no acceleration along the verticaldirectionthe normal force N is equal to <br/> `N_("push")=mg+F cos theta""...(1)` <br/> As a result the maximal static friction also increases and is equal to <br/> `f_(s)^("max")=N_("push")=mu_(s)(mg+Fcos theta)""...(2)` <br/> Equation (2) shows that a greater force needs to be applied to push the <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> into motion.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_G_MQP_02_E04_012_S01.png" width="80%"/> <br/> When an object is pulled at an angle `theta`, the applied force is resolved into two components as shown in Figure. The total downward force acting on the object is <br/> `N_("pull")=mg+F cos theta"" ...(3)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_G_MQP_02_E04_012_S02.png" width="80%"/> <br/> Equation (3) shows that the normal force is less than `N_("push")`. From equations (1) and (3), it is <a href="https://interviewquestions.tuteehub.com/tag/easier-447966" style="font-weight:bold;" target="_blank" title="Click to know more about EASIER">EASIER</a> to pull an object than to push to make it move.</body></html> | |
| 37366. |
The solar radiation spectrum reveals that the intensity corresponding to a wave length of 4750 A^(@) is maximum. Estimate the surface temperature of the sun (Given Wien's constant = 2.89xx10^(-3)m-K) |
| Answer» <html><body><p></p>Solution :From Wien.s displacement law, the temperature T of a body <a href="https://interviewquestions.tuteehub.com/tag/corresponding-935567" style="font-weight:bold;" target="_blank" title="Click to know more about CORRESPONDING">CORRESPONDING</a> to maximum intensity wavelength `lamda_(m)` is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by <br/> `T=b/lamda_(m)" "thereforeT=(2.89xx10^(-3)m-K)/(4750xx10^(-10)m)=6084K` <br/> This temperature is corresponding to the <a href="https://interviewquestions.tuteehub.com/tag/chromosphere-916274" style="font-weight:bold;" target="_blank" title="Click to know more about CHROMOSPHERE">CHROMOSPHERE</a> (surface) of the sun.</body></html> | |
| 37367. |
Two pendulums of lengths 100 cm and 121 cm suspended side by side. A suspended bobs suspended at its end stretched and leave together. After how many minimum oscillations of big pendulum, both are in same phase? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>`<br/>`10`<br/>`21`<br/>`20`</p>Solution :Suppose `T_(1)" and "T_(2)` are the <a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> time of two pendulums <br/> `T_(1)= 2pi sqrt((100)/(g))" and "T_(2)= 2pi sqrt((121)/(g))""[therefore T_(1) <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> T_(2)," because "l_(1) lt l_(2)]` <br/> Suppose at t=0, both oscillate at same time but their oscillations are the same due to different period. <br/> Suppose pendulum of long string <a href="https://interviewquestions.tuteehub.com/tag/makes-2811811" style="font-weight:bold;" target="_blank" title="Click to know more about MAKES">MAKES</a> n oscillations and pendulum of short string makes `(n+1)` oscillations. <br/> `therefore (n+1)T_(1) = nT_(2)` <br/> `therefore (n+1)xx 2pi sqrt((100)/(g))= n xx 2pi sqrt((121)/(g))` <br/> `therefore (n+1)10= 11n` <br/> `therefore 10n +10 = 11n` <br/> `therefore n = 10`.</body></html> | |
| 37368. |
A block of mass 1 kg starts from rest at x = 0 and moves along the x - axis under the action of a force F = kt, where t is time and k = 1 N/s. The distance the block will travel in 6 seconds is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a> m<br/>72 m<br/>108 m<br/>18 m<br/></p>Solution :F = kt or , m`(<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/(dt) = kt " " or, (dv)/(dt) = (k)/(m)`t <br/> or, `int_(0)^(v) = (k)/(m)int_(0)^(t)" "or, v = (1)/(2)(k)/(m)cdot t^(2) " " or, (dx)/(dt) = (1)/(2)(k)/(m)t^(2)` <br/> `or," " int_(0)^(x) dx = (1)/(2)(k)/(m)int_(0)^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) t^(2) dt` <br/> `or," "x = (1)/(2)(k)/(m)(6^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))/(3) xx (1)/(2)xx(1)/(1) xx (216)/(3) [ because k = 1 N//s, m = 1 kg]` <br/> = 36 m <br/> The option A is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a>.</body></html> | |
| 37369. |
Find the work done in stretching a wire Im long and area of cross section 0.03 cm under a load of 100 N if Young.s modulus of the material of the wire is 2 xx 10^(11)N//m^(2) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`8.33xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`</body></html> | |
| 37370. |
A large cylindrical tank has a hole of area A at its bottom. Water is poured in the tank by as tube of equal cross sectional area A ejecting water at the speed v. |
| Answer» <html><body><p>The water level in the tank will <a href="https://interviewquestions.tuteehub.com/tag/keep-527902" style="font-weight:bold;" target="_blank" title="Click to know more about KEEP">KEEP</a> on rising<br/>No water can be <a href="https://interviewquestions.tuteehub.com/tag/stored-7260220" style="font-weight:bold;" target="_blank" title="Click to know more about STORED">STORED</a> in the tank<br/>The water level will <a href="https://interviewquestions.tuteehub.com/tag/riseto-2995712" style="font-weight:bold;" target="_blank" title="Click to know more about RISETO">RISETO</a> a height `v^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)//2g` and then stop<br/>The water level will oscillate.</p>Answer :C</body></html> | |
| 37371. |
A body istied at the end of a string of length .l. and rotated in a vertical circle. The string is just taut when the body is at the highest point. Velocity of the body when the string is in horizontal position is |
| Answer» <html><body><p>`3sqrt(<a href="https://interviewquestions.tuteehub.com/tag/gr-1010452" style="font-weight:bold;" target="_blank" title="Click to know more about GR">GR</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(gr)`<br/>`sqrt(5gr)`<br/>`sqrt(3gr)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37372. |
A uniformcylinder of length L and mass M having cross - sectional area A is suspended , with its length vertical from a fixed point by a massless spring , such that it is half submerged in a liquidof density sigma atequilibrium position .The extension x_(0)of the spring when it is in equilibrium is . |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>)/k ` <br/>`(Mg)/k (1-(LAsigma)/M)`<br/>`(Mg)/k (1-(LAsigma)/(2M))`<br/>`(Mg)/k (1+(LAsigma)/M)`</p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C06_E05_056_S01.png" width="80%"/><br/> Mass of cross section A , `M = (AL)/2 ` and <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> `L/2 `<br/> ` :. ` Buoyant force in liquid of sensity `sigma `<br/> `F_(B) = igma Mg = sigma (Alg)/2 ` <br/> Suppose extension of spring is `x_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)`<br/> ` :. ` Restoring force in upward direction in spring ` = kx_(0)`<br/> When k = spring constant and force of <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> on the cylinder in downward direction = Mg <br/> ` :. ` For equilibrium condition of cylinder ,<br/> ` :. mg = (sigmaALg)/2 + kx_(0)` <br/> ` :. kx_(o)=mg - (sigmaALg)/2 ` <br/> ` :. x_(0) =(mg-(sigmaALg)/2)/k` <br/> ` :. x_(0) =(Mg)/k (1- (sigmaLA)/(2M))`</body></html> | |
| 37373. |
A student measures the thickness of a human hair by looking at it through a microscope of magnification 100. He makes 20 observations and finds that the average width of the hair in the field of view of the microscope is 3.5mm. What is the estimate on the thickness of hair? |
| Answer» <html><body><p>0.5cm<br/>0.035cm <br/>0.035mm<br/>3.5 cm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37374. |
Why there is no hydrogen in earth's atmosphere ? |
| Answer» <html><body><p></p>Solution :As the <a href="https://interviewquestions.tuteehub.com/tag/root-1190914" style="font-weight:bold;" target="_blank" title="Click to know more about ROOT">ROOT</a> mean square speed of hydrogen is much less than that of nitrogen , it <a href="https://interviewquestions.tuteehub.com/tag/easily-964537" style="font-weight:bold;" target="_blank" title="Click to know more about EASILY">EASILY</a> escapes from the Earth's <a href="https://interviewquestions.tuteehub.com/tag/atmosphere-13116" style="font-weight:bold;" target="_blank" title="Click to know more about ATMOSPHERE">ATMOSPHERE</a>.</body></html> | |
| 37375. |
The radius of earth's orbit is 1.5xx10^(8) km and that of Mars is 2.5xx10^(11)m. In how many years, does the Mars complete its one revolution ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :2.15 <a href="https://interviewquestions.tuteehub.com/tag/years-1464846" style="font-weight:bold;" target="_blank" title="Click to know more about YEARS">YEARS</a></body></html> | |
| 37376. |
If you want to pile up sand onto a circular area of radius R. The greatest height of the sand pile that can be created without spilling the sand onto the surrounding. Area, if mu is the coefficient of friction between sand particle is: |
| Answer» <html><body><p>`mu^(2) <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/mur-2849480" style="font-weight:bold;" target="_blank" title="Click to know more about MUR">MUR</a>`<br/>R<br/>`R/mu`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :b</body></html> | |
| 37377. |
A bullet of mass 50 g is fired from below into a suspended object of mass 450 g. The object rises through a height of 1.8 m with bullet remaining inside the object. Find the speed of the bullet. Take g=10ms_(-2) |
| Answer» <html><body><p></p>Solution :`m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)50g=0.05kg,m_(2)=450g=0.45g` <br/>The speed of the bullet is up. The second <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> is at rest`(u_(2)=0)`. Let the common velocity of the bullet and the object after the bullet is embedded into the object is <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>. <br/> `v=(m_(1)u_(1)+m_(2)u_(2))/((m_(1)+m_(2))` <br/> `v(00.5u_(1)+(0.45xx0))/((00.5+0.45))=(0.05)/(0.50)u_(1)` <br/> The combined velocity is the <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> velocity for the vertical upward motion of the combine bullet and the object. From second equation of motion, <br/> `v=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2gh)` <br/> `v=sqrt(2xx10xx1.8)=sqrt(36)` <br/> `v=6ms^(-1)` <br/> Substituting this in the above equation, the value of `U_(1)` is <br/> `6=(0.05)/(0.50)u_(1) "or" u_(1)(0.50)/(0.05)xx6=10xx6` <br/> `v=60ms_(-1)`<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V01_C04_SLV_021_S01.png" width="80%"/></body></html> | |
| 37378. |
A gun (mass = M) fires a bullet (mass = m) with speed v_(r) relative to barrel of the gun which is inclined at an angle of 60^(@) with horizontal. The gun is placed over a smooth horizontal surface. Find the recoil speed of gun. |
| Answer» <html><body><p></p>Solution :Let the recoil seed of gun is `v`. Taking gun`+`bullet as the system. Net <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> force on the system in horizontal directioin zero. <br/> initial the system was rest. Therfore, applying the <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a> of conservation of inear momentum in horizontal direction, we get <br/> `<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>-m(v_(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)cos60^(@)-v)+0` <br/> `:. v=(mV_(r)cos60^(@))/(M+m)` <br/> or `v=(mV_(r))/(2(M+m))`</body></html> | |
| 37379. |
A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find maximum velocity |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/comparing-2531631" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARING">COMPARING</a> equation `y= 0.02sin(3.14t+ (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(2))`with the general from of the equation , `y= A sin(omegat+phi_(0))` <br/> Maximum <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> `v_("max")= <a href="https://interviewquestions.tuteehub.com/tag/aomega-2436739" style="font-weight:bold;" target="_blank" title="Click to know more about AOMEGA">AOMEGA</a>= 0.02 xx 3.14= 0.68 ms^(-1)`</body></html> | |
| 37380. |
A barometer kept in an elevator reads 76 cm when it is at rest. If the elevator goes up with increasing speed, the reading will be |
| Answer» <html><body><p>Zero<br/>76 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a><br/>`gt76cm`<br/>`lt76cm`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37381. |
A body take 1 1/3 times as much time to slide down a rough inclined plane as it takes to slide down an identical but smooth inclined plane. If the angle of inclination is 45^(@), find the coefficient friction. |
| Answer» <html><body><p> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`mu_(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)=7/16`</body></html> | |
| 37382. |
The distance between the object and the real image formed by a convex lens is d. IF the linear magnificationis m, find the focal length of the lens in terms of d and m. |
| Answer» <html><body><p></p>Solution :The convex lens formula for a real image is <br/> `1/v+1/u=1/f` <br/> Where no sign conventions are to be used, Multiplying by u we get <br/> `u/v+1=u/f or 1/m=u/f-1=(u-f)/f`<br/> or `m(u-f)=f or u=((l+m)f)/m`……..(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <br/> Multiplying (i) by v we get <br/> `1+v/u=v/f or 1+m=v/f or v=f(1+m)`......(iii) <br/> Now u+v=d Using (ii) and (iii) wehave <br/> `d=((1+m)f)/m+f(1+m)` which gives `f=(<a href="https://interviewquestions.tuteehub.com/tag/md-557525" style="font-weight:bold;" target="_blank" title="Click to know more about MD">MD</a>)/(1+m)^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`</body></html> | |
| 37383. |
In a smooth circular tube a radius R a mass of 3m at rest splits into two fragments of m and 2m respectively. The smaller mass attains a speed of 2V_(0) tangentially at that point and continues to move in circular path. The other fragment also moves in the circular tube. The arrangement is present in a horizontal plane. Which of the following is/are correct. |
| Answer» <html><body><p>instantaneously the heavier fragment <a href="https://interviewquestions.tuteehub.com/tag/acquires-847831" style="font-weight:bold;" target="_blank" title="Click to know more about ACQUIRES">ACQUIRES</a> a <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of `2V_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)`<br/>instantaneously the heavier fragment acquires a speed of `V_(0)`<br/>the two meet each other after a time interval of `2pi R//3V_(0)`<br/>the two meet each other after a time interval of `2pi R//4V_(0)`</p>Answer :A::B::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37384. |
A light rod of length 200cm is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of cross-section 0.1cm^(2) and the other of brass of cross-section 0.2 cm^(2). A distance long the rod at which a weight may be hung to produce equal stresses in both the wires? |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)/(3)` m from steel <a href="https://interviewquestions.tuteehub.com/tag/wire-1457703" style="font-weight:bold;" target="_blank" title="Click to know more about WIRE">WIRE</a><br/>`(4)/(3)` m from brass wire<br/>1m from steel wire<br/>`(1)/(4)` m from brass wire</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MTG_NEET_GID_PHY_XI_C07_E01_004_S01.png" width="80%"/> <br/> As stresses are equal, so `(T_(1))/(A_(1)) = (T_(2))/(A_(2))`<br/> or `(T_(1))/(T_(2)) = (A_(1))/(A_(2)) = (0.1)/(0.2) or T_(2) = 2T_(1)` <br/> Now for <a href="https://interviewquestions.tuteehub.com/tag/translatory-3229314" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLATORY">TRANSLATORY</a> equilibrium of the rod, <br/> `T_(1) + T_(2) = W` <br/> From (i) and (ii), we get `T_(1)= (W)/(3), T_(2) = (2W)/(3)` <br/> Now, if <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> is the distance of weight W from steel wire, then for rotational equilibrium of rod, `T_(1) x = T_(2) (2-x) or (W)/(3) x = (2W)/(3) (2-x) :. x= (4)/(3)m`</body></html> | |
| 37385. |
Calculate the efficiency of a carnot engine working between the two temperatures: 30^(@)Cand 100^(@)C |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Temperature of source `= T _(1) = 100+ <a href="https://interviewquestions.tuteehub.com/tag/273-1832932" style="font-weight:bold;" target="_blank" title="Click to know more about 273">273</a> = 373 K` <br/> Temperature of <a href="https://interviewquestions.tuteehub.com/tag/sink-1210432" style="font-weight:bold;" target="_blank" title="Click to know more about SINK">SINK</a> `= T_(2) = <a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a> + 273 = 303 K` <br/> <a href="https://interviewquestions.tuteehub.com/tag/efficiency-20674" style="font-weight:bold;" target="_blank" title="Click to know more about EFFICIENCY">EFFICIENCY</a> `= eta= (T_(1) - T_(2))/(T_(1)) = (373-303)/(373) = 0.188 = 18.8 %`</body></html> | |
| 37386. |
Pendulum of a clock consists of very thin sticks of iron and an alloy. At room temperature the iron sticks 1 and 2 have length L_0 each. Length of each of the two alloy sticks 4 and 5 is 0 and the length of iron stick 3 (measured up to the centre of the iron bob) is l_0. Thickness of connecting strips are negligible and mass of everything except the bob is negligible. The pendulum oscillates about the horizontal axis shown in the figure. It is desired that the time period of the pendulum should not change even if temperature of the room changes. Find the coefficient of linear expansion (alpha) of the alloy if the coefficient of linear expansion for iron is alpha_(0). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>=((L_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)+lambda_(0))alpha_(0))/(l_(0))`</body></html> | |
| 37387. |
Two bodies of masses 1 kg 3 kg are tied at the two ends of a thread 60 cm and the arrangement is kept diametrically on a table. If the table is rotated about an axis passing through its centre, then it is observed that no motion in the thread is generated along the diameter. What is the distance of the 1 kg mass from the centre of the table? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a> <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a></body></html> | |
| 37388. |
Hydraulic brakes are based on |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pascal-596772" style="font-weight:bold;" target="_blank" title="Click to know more about PASCAL">PASCAL</a>'s <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/torricelli-711056" style="font-weight:bold;" target="_blank" title="Click to know more about TORRICELLI">TORRICELLI</a>'s law <br/><a href="https://interviewquestions.tuteehub.com/tag/newton-11212" style="font-weight:bold;" target="_blank" title="Click to know more about NEWTON">NEWTON</a>'s law<br/>Boyle's law </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37389. |
(A) A famouspainting was painted by not using brush strokes in the usual manner, but rather a myriad of small colour dots. In this painting the colour you see at any given place on the painting changes as you move away. ( R) The angular separation of adjacent dots changes with the distance from the painting. |
| Answer» <html><body><p>Both A and R are true and R is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A<br/>Both A and R are true and R is not the correct explanation of A<br/>A is true and R is false<br/>Both A and R is false</p>Answer :A</body></html> | |
| 37390. |
Drope of water fall at regular intervals from the roof of a building of height H=16m, the first dro striking the ground at the same moment as the fifth drop detaches from the roof. Find the distance between the successive drops. |
| Answer» <html><body><p></p>Solution :Step-I : Time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> by the first • <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <br/> drop to touch the ground = `t=sqrt((2h)/(g))` • 4 <br/> For `h=16m,t=sqrt((2xx16)/(g))=4sqrt((2)/(g))` • <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> <br/> Time interval between two drops is • 2 <br/> `t_("interval")=((1)/(n-1))t=((1)/(4))t=sqrt((2)/(g))` • 1 <br/> Where n =number of drops <br/> Step - <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> : <br/> Distance between first and second drops <br/> `=S_(1)-S_(2)=(1)/(2)g t_("interval")^(2)[4^(2)-3^(2)]=7m` <br/> Distance between second and third drops <br/> `=S_(2)-S_(3)=(1)/(2)g t_("interval")^(2)[3^(2)-2^(2)]=5m` <br/> Distance between third and fourth drops <br/> `=S_(3)-S_(4)=(1)/(2)g t_("interval")^(2)[2^(2)-1^(2)]=3m` <br/> Distance between fourth and <a href="https://interviewquestions.tuteehub.com/tag/fifth-987488" style="font-weight:bold;" target="_blank" title="Click to know more about FIFTH">FIFTH</a> drops. <br/> `=S_(4)-S_(5)=(1)/(2)g t_("interval")^(2)[1^(2)-0]=1m`.</body></html> | |
| 37391. |
A girl is swinging a swing in the sitting position. What will be the effect on the time period of the swing if she stand up? |
| Answer» <html><body><p>increase<br/>decrease <br/><a href="https://interviewquestions.tuteehub.com/tag/remain-1184279" style="font-weight:bold;" target="_blank" title="Click to know more about REMAIN">REMAIN</a> same <br/>increase if the child is tall and decrease if the child is short</p>Solution :When child stands up, <a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a> of inertia decreases, hence angular speed `omega` increases and as a result <a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> time decreases.</body></html> | |
| 37392. |
The value of C_p/C_v is |
| Answer» <html><body><p>zero<br/>negative<br/>between <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> and 1<br/>greater than 1</p>Answer :D</body></html> | |
| 37393. |
When a cycle tyre suddenly bursts, the air inside the tyre expands. This process is……. |
| Answer» <html><body><p>isothermal<br/><a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a><br/>isobaric<br/>isochoric</p>Solution :adiabatic</body></html> | |
| 37394. |
Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point and moved with velocities u_(1)=3.0ms^(-1) and u_(2)=4.0ms^(-1) horizontally in opposite directions. Find the distance betwen the particles at the moment when their velocity vectors become mutually perpendicular. |
| Answer» <html><body><p></p>Solution :The situation is shown fig. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_A_C05_SLV_022_S01.png" width="80%"/> <br/> Let the velocity vectors become <a href="https://interviewquestions.tuteehub.com/tag/perpendicular-598789" style="font-weight:bold;" target="_blank" title="Click to know more about PERPENDICULAR">PERPENDICULAR</a> after time t when both particles has fallen same vertical distance `1/2"<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a>"^(2)` and have acquired same vertical velocites gt. <br/> Let their <a href="https://interviewquestions.tuteehub.com/tag/resultant-1187362" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTANT">RESULTANT</a> velocities make angle `theta_(1)` and `theta_(2)` with horizontal. <br/> Then `tan theta_(1)=("gt")/(v_(1))` and `tan theta_(2)=("gt")/(v_(2))` <br/> Since velocity vectors are perpendicular <br/> `theta_(1)+theta_(2)=90^(@)`, hence `tan theta_(2)=cot theta_(1)` <br/> It makes `tan theta_(1)=("gt")/(v_(1))` and `cot theta_(1)=("gt")/(v_(2))` <br/> On multiplying we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> `t=(sqrt(v_(1)v_(2)))/g` and `D=(u_(1)+u_(2))t`</body></html> | |
| 37395. |
A clock regulated by a seconds pendulum keeps correct time. During summer the length of the pendulum increases to 1.02m. How much will the clock gain or lose in one day? |
| Answer» <html><body><p>`2280 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1230-271094" style="font-weight:bold;" target="_blank" title="Click to know more about 1230">1230</a> sec`<br/>`1180 sec`<br/>`1380 sec`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37396. |
According to Bemoulli's theorem the pressure of water should remain constant in a pipe of uniform radius. But in practice, it goes on decreasing. Why? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a></body></html> | |
| 37397. |
The distance travelled by a body during last second of its upward journey is d when the body is projected with certain velocity vertically up. If the velocity of projection is doubled, the distance travelled by the body during last second of its upward journey is |
| Answer» <html><body><p>2d<br/>d<br/>`2d+g/2`<br/>`2d-g/2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37398. |
A stone is projected from the top of a tower with velocity 20ms^(-1) making an angle 30(@) with the horizontal. If the total time of flight is 5s and g = 10ms^(-2), |
| Answer» <html><body><p>the <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> of the tower is 75m<br/>the <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> height of the <a href="https://interviewquestions.tuteehub.com/tag/stone-1228007" style="font-weight:bold;" target="_blank" title="Click to know more about STONE">STONE</a> from the ground is 80m <br/>both of the above are true <br/>none of the above is true</p>Answer :C</body></html> | |
| 37399. |
The percentage errors in measurement of mass and velocity are 2 % and 3% resoectively . How much will be the maximum wrror in estimate of kinetic energy , obtained by measuring mass and velocity ? |
| Answer» <html><body><p>1<br/>5<br/>8<br/>11</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37400. |
A particle of mass 0.1 kg executes SHM under a force F =-10x (N). Speed of particle at mean position is 6m//s. Find its amplitude of oscillations |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : From conservation of mechanical energy. <br/> `(1)/(2)kA^(2)= (1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)` or `A= vsqrt((m)/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>))= 6sqrt((0.1)/(10))= (6)/(10)= 0.6 m`</body></html> | |