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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37401. |
The horse power needed to pump 1000 kg of water in a tank in 5 minutes under pressure of 100 g wt/(mm)^(2) is appromiately equalt o x (1 hp =746 Watt). Find the value of x. |
| Answer» <html><body><p></p>Solution :`m=1000 kg` <br/> `t=<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>"min"=5 xx 60=300s` <br/> `P=100"g <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a> (mm)"^(2)` <br/> `=(100)/(1000) xx (9.8)/((10^(-3))^(2)) m^(2)` <br/> `=(9.8 xx 10^<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/(10)` <br/> `=9.8 xx 10^(6))/(10)` <br/> `=9.8 xx 10^(5) N//m^(2)` <br/> `P=W/t=(PV)/(t)` <br/> `=(9.8 xx 10^(5) xx "<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>")/(300 xx "density")` <br/> `=(9.8 xx 10^(5) xx 1000)/(300 xx 1000)` <br/> `=4.37 hp approx 4`</body></html> | |
| 37402. |
Explain primary concept of force. |
| Answer» <html><body><p></p>Solution :To bringstationaryobjectin motionforceis required.Similarlyto slowdownobjectinmotionor tostopmovingobjectforceisrequired<br/> <a href="https://interviewquestions.tuteehub.com/tag/effectof-2603852" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECTOF">EFFECTOF</a> <a href="https://interviewquestions.tuteehub.com/tag/forceon-995404" style="font-weight:bold;" target="_blank" title="Click to know more about FORCEON">FORCEON</a> a <a href="https://interviewquestions.tuteehub.com/tag/bodycan-2478191" style="font-weight:bold;" target="_blank" title="Click to know more about BODYCAN">BODYCAN</a> befollowing<br/> (i)<a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> canbringbody inrestto motionorbodyin motionto rest. <br/>(ii)forcechangeshapeof anobject.</body></html> | |
| 37403. |
The kinetic energy of a particle continuously increases with time. a) The resultant force on the particle must be parallel to the velocity at all instants b) The resultant force on the particle must be at an angle less than 90o all the time Its height above the ground level mus continuously decrease The magnitude of its linear momentum is increasing continuously |
| Answer» <html><body><p>a, b are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/> b, <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct<br/>a, d are correct<br/>b, d are correct</p>Answer :D</body></html> | |
| 37404. |
Which of the following shows the correct relationship between the perssure and density of an ideal gas constant temperature ? |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C09_E01_010_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C09_E01_010_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C09_E01_010_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V02_C09_E01_010_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37405. |
A point on the rim of a rim of a wheel 3 m in diameter has linear velocity of 18 ms^(-1). The angular velocity of the wheel is |
| Answer» <html><body><p>`4 <a href="https://interviewquestions.tuteehub.com/tag/rads-3786464" style="font-weight:bold;" target="_blank" title="Click to know more about RADS">RADS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> rads^(-1)`<br/>`6 rads^(-1)`<br/>`18 rads^(-1)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37406. |
Angle and strain have no dimensions. Why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :They are the <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of <a href="https://interviewquestions.tuteehub.com/tag/similar-1207900" style="font-weight:bold;" target="_blank" title="Click to know more about SIMILAR">SIMILAR</a> <a href="https://interviewquestions.tuteehub.com/tag/quantities-1174208" style="font-weight:bold;" target="_blank" title="Click to know more about QUANTITIES">QUANTITIES</a>.</body></html> | |
| 37407. |
In a barometer tube of 1m long and 2cm^(2) cross -section, mercury stands at a height of 75 cm of Hg. When a small amount of oxygen is introduced in the space above the mercury, the level falls by 10 cm . Find the mass of oxygen introduced. ( Room tempetature = 27^(@)C, density of mercury= 13.6 gm/cc, g = 10 ms^(-2) ) |
| Answer» <html><body><p></p>Solution :Volume of <a href="https://interviewquestions.tuteehub.com/tag/oxygen-1144542" style="font-weight:bold;" target="_blank" title="Click to know more about OXYGEN">OXYGEN</a> <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> xx (100 - 65) xx 10^(-6) = 70 xx 10^(-6) m^(3)` <br/> Pressure of oxygen, P = `rho` gh <br/> `= (13.6 xx 10^(3)) (10) (10 xx 10^(-2)) = 13,6000 Nm^(2)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> oxygen T = 300 K, <br/> `therefore ` mass of oxygen, <br/> m `= (PVM)/(RT ) = 13,600 xx 70 xx 10^(-6) xx 32 xx (10^(-3))/(8.3 xx 300) ` <br/> = 0.012 gm</body></html> | |
| 37408. |
A boy can throw a stone up to a maximum height of 10m. The maximum horizontal distance that the boy can throw the same stone up to will be : |
| Answer» <html><body><p>10m<br/>`10sqrt2 m` <br/><a href="https://interviewquestions.tuteehub.com/tag/20m-293046" style="font-weight:bold;" target="_blank" title="Click to know more about 20M">20M</a><br/>`20 <a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a> m` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37409. |
"Steam engine is called a reciprocating double-acting engine". Why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The incoming <a href="https://interviewquestions.tuteehub.com/tag/steam-1226863" style="font-weight:bold;" target="_blank" title="Click to know more about STEAM">STEAM</a> <a href="https://interviewquestions.tuteehub.com/tag/acts-848461" style="font-weight:bold;" target="_blank" title="Click to know more about ACTS">ACTS</a> on both sides of the <a href="https://interviewquestions.tuteehub.com/tag/pistion-2929643" style="font-weight:bold;" target="_blank" title="Click to know more about PISTION">PISTION</a> and pushes to and fro. So it is called a <a href="https://interviewquestions.tuteehub.com/tag/reciprocating-620516" style="font-weight:bold;" target="_blank" title="Click to know more about RECIPROCATING">RECIPROCATING</a> double-acting engine,</body></html> | |
| 37410. |
Distance covered by ball thrown upwards with speed 'u' in last 't' seconds before it reaches max. height is ............. |
| Answer» <html><body><p>` (u + g t)t ` <br/>ut <br/>`1/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> g t^(2)`<br/>`ut -(1)/(2) g t^(2)` </p>Solution :` (##KPK_AIO_PHY_XI_P1_C03_E06_001_S01.png" width="<a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a>%"> <br/> Suppose time taken by ball to reach max, height is T. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> v = u - gT In v =0` <br/> Final velocity is zero at max. height <br/> `therefore u = gT` <br/> `therefore T = u/g ""…(1)`<br/> velocity gained by ball in `(T-t)s,` <br/> `v =u -g (T-t)` <br/> `=u -g ((u)/(g) -t) (because` From (1)) <br/> `=u - u + g t` <br/> `therefore v = g t""...(2)` <br/> Distance <a href="https://interviewquestions.tuteehub.com/tag/covered-2552266" style="font-weight:bold;" target="_blank" title="Click to know more about COVERED">COVERED</a> in last .t. <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a>, <br/> `d = vt - 1/2 g t^(2)` <br/> `= (g t)t - 1/2 g t^(2) (because ` For (2)) <br/> `= g t ^(2) -1/2 g t^(2)` <br/> `therefore d = 1/2 g t^(2)`</body></html> | |
| 37411. |
A motor cyclist is trying to jump across a path as shown by driving horizontally off a cliff A at a speed of 5 m s^(-1). Ignore air resistance and take g = 10 m s^(-2). The speed with which he touches the cliff B is |
| Answer» <html><body><p>`2.0 ms^(-1)`<br/>`12 m s^(-1)`<br/>`25 ms^(-1)`<br/>`15 m s^(-1)` </p>Solution :Speed in horizontal direction remains constant during whole <a href="https://interviewquestions.tuteehub.com/tag/journey-1062300" style="font-weight:bold;" target="_blank" title="Click to know more about JOURNEY">JOURNEY</a> because there is no acceleration in this direction. <br/> So, `v_1 = <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> ms^(-1)` <br/> In vertical direction <br/> Loss of <a href="https://interviewquestions.tuteehub.com/tag/gravitational-476409" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITATIONAL">GRAVITATIONAL</a> potential energy = gain in kinetic energy <br/> `:. mgh = 1/2 mv_2^2` <br/> or `v_2^2 = 2gh = 2 xx 10 xx (70 - 60) = <a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a>` <br/> Hence , the speed with which he touches the cliff B is <br/> `v= sqrt(v_1^2 + v_2^2) = sqrt(25 + 200) = sqrt(<a href="https://interviewquestions.tuteehub.com/tag/225-294624" style="font-weight:bold;" target="_blank" title="Click to know more about 225">225</a>) = 15 ms^(-1)`.</body></html> | |
| 37412. |
What is the difference between forced oscillation and resonance ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) Forced oscillation: Frequency of the external <a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> is different from the natural frequency. <br/> (ii) Reasonance : Frequency of the external periodic force is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the natural frequency.</body></html> | |
| 37413. |
When air bubble comes from bottom to the top of a lake its radius becomes n times. If temperature remains constant through out the lake the depth of the lake will be, |
| Answer» <html><body><p></p>Solution :From Boyle.s law <br/> <a href="https://interviewquestions.tuteehub.com/tag/pv-593601" style="font-weight:bold;" target="_blank" title="Click to know more about PV">PV</a> = constant `P_(1)V_(1)=P_(2)V_(2),4/3piR^(3)(P_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)+hrhog+(2S)/R)=(P_(0)+(2S)/(nR))4/3pi(nR)^(3)` <br/> `hrhog=P_(0)(n^(3)-1)+(2S)/(nR)n^(3)-(2S)/R,<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>=(P_(0)(n^(3)-1)+(2S)/R[n^(2)-1])/(rhog)`</body></html> | |
| 37414. |
What is micron? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> "<a href="https://interviewquestions.tuteehub.com/tag/micron-1095758" style="font-weight:bold;" target="_blank" title="Click to know more about MICRON">MICRON</a>"=<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)m`</body></html> | |
| 37415. |
The Shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to sqrt(3)//2 times its amplitude . Determine its time period. |
| Answer» <html><body><p><br/></p>Solution :`y = a <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> omegat , (<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3//<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))a = sin omegat, sin omegat = sqrt(3//2)= sinpi//3, t = 2 s, (2pi//T) = pi//3 , T= <a href="https://interviewquestions.tuteehub.com/tag/12s-271682" style="font-weight:bold;" target="_blank" title="Click to know more about 12S">12S</a>`</body></html> | |
| 37416. |
At equilibrium, the springs are released, mass M is oscillating under the influence of three springs, k_(1),k_(2)andk_(3) as shown. Its frequency (upsilon) of oscillation is (1)/(2pi)sqrt((k_(eq))/(M)), where k_(eq) I such that |
| Answer» <html><body><p>`k_(eq)=k_(1)+k_(2)+k_(3)` <br/>`k_(eq)=(k_(1)+k_(2)+k_(3))/(3)` <br/>`(1)/(k_(eq))=(1)/(k_(1))+(1)/(k_(2))+(1)/(k_(3))` <br/>`k_(eq)=(k_(1)+k_(2)-k_(3))` </p>Solution :When the mass M is <a href="https://interviewquestions.tuteehub.com/tag/displaced-440680" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACED">DISPLACED</a> <a href="https://interviewquestions.tuteehub.com/tag/slightly-3037487" style="font-weight:bold;" target="_blank" title="Click to know more about SLIGHTLY">SLIGHTLY</a> to the right, the resultant <a href="https://interviewquestions.tuteehub.com/tag/forces-16875" style="font-weight:bold;" target="_blank" title="Click to know more about FORCES">FORCES</a> acting on the mass M is as shown. <br/> `F_("net")=-(k_(1)+k_(2)+k_(3)).x,` <br/> Thus, `k_(eq)=k_(1)+k_(2)+k_(3)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/MTG_NEET_GID_PHY_XI_C10_SLV_005_S01.png" width="80%"/></body></html> | |
| 37417. |
Two blocks of mass 2 kg and 5 kg are connected by an ideal string passing over a pulley. The block of mass 2 kg is free to slide on a surface inclined at an angle of 30^@with the horizontal whereas 5 kg block hangs freely. Find the acceleration of the system and the tension in the string. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V01_C03_E02_156_S01.png" width="80%"/> <br/>Let a be the acceleration of the <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a> and T be the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> in the string. Equations of motions for 5 kg and 2 kg blocks are 5g - T = 5a...(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) <br/> `T =2 g sin theta - f = 2a`...(2) <br/> where f= force of limiting friction <br/> `mu R = mu mg cos theta = 0.3 xx 2 g xx cos 30^@` <br/> <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a> (1) and (2) <br/> `a = 4.87 m//s^2` <br/> `T = 24.65 N`</body></html> | |
| 37418. |
Acyclist comes to a skidding stop in 10m. During this process, the forceon the cycle due to the road is 200 N and is directy opposed to the motion. How much work does the cycle do on the road? |
| Answer» <html><body><p></p>Solution :Work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> on the cycle by the road is the work done by the stopping (frictional) force on the cycle due to the road. <br/> From Newton.s <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> an equal and opposite force acts on the road due to the cycle. Its magnitude is <a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a> N. However, the road <a href="https://interviewquestions.tuteehub.com/tag/undergoes-1436539" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERGOES">UNDERGOES</a> no displacement. Thus, work done by cycle on the road zero.</body></html> | |
| 37419. |
Acyclist comes to a skidding stop in 10m. During this process, the forceon the cycle due to the road is 200 N and is directy opposed to the motion. How much work does the road do on the cycle? |
| Answer» <html><body><p></p>Solution :Work done on the cycle by the <a href="https://interviewquestions.tuteehub.com/tag/road-1190248" style="font-weight:bold;" target="_blank" title="Click to know more about ROAD">ROAD</a> is the work done by the stopping (frictional) force on the cycle due to the road. <br/> The stopping foce and the <a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> <a href="https://interviewquestions.tuteehub.com/tag/make-546668" style="font-weight:bold;" target="_blank" title="Click to know more about MAKE">MAKE</a> an angle of `180^(@) (pi rad)` with each other. Thus, work done by the road, <br/> `W_(r )= Fd cos theta` <br/> `=200 xx 10 xx cos pi = -2000 J` <br/> It is negative work that <a href="https://interviewquestions.tuteehub.com/tag/brings-2488276" style="font-weight:bold;" target="_blank" title="Click to know more about BRINGS">BRINGS</a> the cycle to a halt in accordance with WE theorem.</body></html> | |
| 37420. |
Why are the spoles fitted in a cycle wheel? |
| Answer» <html><body><p></p>Solution :To <a href="https://interviewquestions.tuteehub.com/tag/preserve-1164137" style="font-weight:bold;" target="_blank" title="Click to know more about PRESERVE">PRESERVE</a> the circular structure of the rim of the <a href="https://interviewquestions.tuteehub.com/tag/wheel-736315" style="font-weight:bold;" target="_blank" title="Click to know more about WHEEL">WHEEL</a>. <br/> (b) To withstand the centripetal force, <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> radially inwards, when the wheel is in circular <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> during <a href="https://interviewquestions.tuteehub.com/tag/running-1192206" style="font-weight:bold;" target="_blank" title="Click to know more about RUNNING">RUNNING</a> along a road.</body></html> | |
| 37421. |
1 g of water at 100^(@)C is converted into steam at the same temperature. If the volume of steam is 1671 cc find the change in internal energy of the system. Latent heat of steam =2256 J g ^(-1). |
| Answer» <html><body><p></p>Solution :According to first law of thermodynamics <br/> `dQ = dU + PdV` <br/> `mL = dU + P( <a href="https://interviewquestions.tuteehub.com/tag/vs-724135" style="font-weight:bold;" target="_blank" title="Click to know more about VS">VS</a> - Vw)` <br/> Mass of water `= m = 1 g = 10 ^(-3) kg ` <br/> Latent heat of <a href="https://interviewquestions.tuteehub.com/tag/steam-1226863" style="font-weight:bold;" target="_blank" title="Click to know more about STEAM">STEAM</a> `= L = <a href="https://interviewquestions.tuteehub.com/tag/2256-1824965" style="font-weight:bold;" target="_blank" title="Click to know more about 2256">2256</a> Jg ^(-1) = 2256 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10 ^(3) Jkg ^(-1)` <br/> Changle in internal energy ` = dU = ?` <br/> Atmospheric pressure ` = P = 1. 013 xx 10^(5) Nm ^(-2)` <br/> Volume of steam `V_(s) = 1671 c c = 1671 xx 10 ^(-6) m ^(3)` <br/> Volume fo water `V_(w) = ( "mass")/("density") = (10 ^(-3))/( 10 ^(3)) = 10 ^(-6) m ^(3)` <br/> `dU = mL - P (Vs - vW)` <br/> `= 10^(-3) xx 2256 xx 10 ^(3) - 1. 013 xx 10 ^(5) (1617 xx 10 ^(-5) - 10 ^(-6))` <br/> `= 1156 - 1.013 xx 10 ^(5) xx 10 ^(-6) xx 1670` <br/> `= 2256 - 169.171 = 2086 . 829 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`</body></html> | |
| 37422. |
A student writes the equation for the capillary rise of a liquid in a tube as h=(rhog)/(2Tcos theta), where r is the radius of the capillary tube, rho is the density of liquid, T is the surface tension and theta is the angle of contact. Check the correctness of the equation using dimensional analysis? |
| Answer» <html><body><p><br/></p>Solution :`h to [L], [rho g //T]=[ML^(_3)xxLT^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)//<a href="https://interviewquestions.tuteehub.com/tag/mt-566013" style="font-weight:bold;" target="_blank" title="Click to know more about MT">MT</a>^(-2)]=[L^(-2)]`. Equation is not <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a>.</body></html> | |
| 37423. |
In the rho-T graph shown in figure, match the following. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><br/></p>Answer :(A)Q,R, (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) P,R (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) Q,S, (D) P,S</body></html> | |
| 37424. |
A vertical hollow cylinder of height 1.52 m is fitted with a movable piston of negligible ,nass and thickness. The lower half portion of the cylinder contains an ideal gas and the upper half is filled with mercury. The cylinder is initially at 300 K. When the temperature is raised, half of the mercury comes out of the cylinder. Find this temperature, assuming the thermal expansion of mercury to be negligible. |
| Answer» <html><body><p></p>Solution :Initially, <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> = 76 + 76 = 152 cm of Hg <br/> From PV = <a href="https://interviewquestions.tuteehub.com/tag/nrt-1109890" style="font-weight:bold;" target="_blank" title="Click to know more about NRT">NRT</a><br/> `(152 xx 76 xx A)/(<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>) = nR ` .... (1) <br/> final pressure = 76 + 38 = 114 cm <br/> of Hg `therefore (114 xx (76 + 38) A)/(T )= nR `.... (2) <br/> From (1) and (2) <br/> `(152 xx 76)/(300) = (114 xx 114)/(T)` <br/> `T = (300 xx 114 xx 114)/(152 xx 76) = (300 xx <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(4) xx (3)/(2) = 337.5 ` K <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C12_SLV_077_S01.png" width="80%"/></body></html> | |
| 37425. |
How will you convert SI unit of enregy (Joule) to CGS unit of energy (erg)? |
| Answer» <html><body><p></p>Solution :`1 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>= <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(7) `<a href="https://interviewquestions.tuteehub.com/tag/ergs-452723" style="font-weight:bold;" target="_blank" title="Click to know more about ERGS">ERGS</a></body></html> | |
| 37426. |
A ball of sqrt(3)xx10^(-2) kg hits a hard surface at 45^(@) to normal with speed 4sqrt(2) m//s and rebounds with 8//sqrt(3)m//s , at 60^(@) angle. If ball remains in contact for 0.1 sec, what force does it exert ? |
| Answer» <html><body><p></p>Solution :During rebounce, <a href="https://interviewquestions.tuteehub.com/tag/horizontal-1029056" style="font-weight:bold;" target="_blank" title="Click to know more about HORIZONTAL">HORIZONTAL</a> component of momentum (parallel to surface) does not change but <a href="https://interviewquestions.tuteehub.com/tag/vertical-726181" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICAL">VERTICAL</a> component (normal to surface) changes by,<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C05_SLV_015_S01.png" width="80%"/><br/>`Delta p = mv_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)cos 60-(-mv_(1)cos <a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>)`<br/>`= m(8//sqrt(3))1//2+m(4sqrt(2))1//sqrt(2)=m((4//sqrt(3))+4)`<br/>`= sqrt(3)xx10^(-2)((4//sqrt(3))+4)=(4+4sqrt(3))xx10^(-2)=10.92xx10^(-2)N-s`<br/>`therefore <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>=(Delta p)/(Delta t)=(10.92xx10^(-2))/(0.1)=10.92xx10^(-1)N`,<br/>Normal to surface.</body></html> | |
| 37427. |
Let V,T,L,K and r denote the speed, time period, angular momentum, kinetic energy and radius of satellite in circular orbit, then (a)V prop r^(-1) , (b)L prop r^(1//2) , (c)T prop r^(3//2) , (d)K prop r^(-2) |
| Answer» <html><body><p>only a & <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are true<br/>only b & <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true<br/>only a, b & d are true<br/>only a, b & c are true</p>Answer :B</body></html> | |
| 37428. |
The following four wires are made of the same material. Which of these will have the largest extension when the same tension is applied? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> = 200 cm, diameter = 0.5 mm<br/>length = 200 cm, diameter = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> mmm<br/>length = 200 cm, diameter = 2 mm<br/>length = 200 cm, diameter = <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> m</p>Solution :`Y=(Fl)/(Ax)` <br/>`Y=(Fl)/(((<a href="https://interviewquestions.tuteehub.com/tag/pid-1154482" style="font-weight:bold;" target="_blank" title="Click to know more about PID">PID</a>^(2))/(4))x)` <br/>Y is same.<br/>`thereforex=(Fl)/(((pid^(2))/(4))y)` <br/>`thereforexprop(1)/(d^2)` <br/>Hence the value of l must be most and that of d must be least.</body></html> | |
| 37429. |
A block of mass 1kg and of volume of 10^(-2)m^(3) is completely submerged in water and tied with a string and a spring of spring constant K=100N/m as shown in the figure. The natural length of spring is 0.2 meter and the length of the string is 0.1 meter. The tak is accelerated upward with an acceleration of 1m//s^(2) The tension in the string is |
| Answer» <html><body><p>109N<br/>99N<br/>79N<br/>59N</p>Answer :A</body></html> | |
| 37430. |
A body at rest breaks up into three parts. If two parts having equal masses, flyr off perpendicularly, to each with a speed of 12ms^(-1). The mass of the tird fragment is thrice the mass of the each of the other fragments, then |
| Answer» <html><body><p>the speed of the <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> fragment is `6sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)ms^(-1)`<br/>the speed of the third fragment is `4sqrt(2)ms^(-1)`<br/>the <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> of motion of the third fragment is `135^(@)` from the other two<br/>the direction of motion of the third fragment is `<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@)` from one of the fragments</p>Answer :B::C</body></html> | |
| 37431. |
Water is filled in a vessel at a certain temperature. When the vessel is heated or cooled water overflows. What is the initial temperature of the water? |
| Answer» <html><body><p></p>Solution :The initial temperature is `4^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` since <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> <a href="https://interviewquestions.tuteehub.com/tag/expands-2076032" style="font-weight:bold;" target="_blank" title="Click to know more about EXPANDS">EXPANDS</a> on either side of `4^(@)C `</body></html> | |
| 37432. |
Bernoulli's principle is not involved in the working explanation of |
| Answer» <html><body><p>movement of <a href="https://interviewquestions.tuteehub.com/tag/spinning-1222315" style="font-weight:bold;" target="_blank" title="Click to know more about SPINNING">SPINNING</a> ball<br/>carburetor of automobile<br/>blades of a <a href="https://interviewquestions.tuteehub.com/tag/kitchen-533901" style="font-weight:bold;" target="_blank" title="Click to know more about KITCHEN">KITCHEN</a> mixer<br/>dyanmic life of an aeroplane</p>Solution :Movement of spinning ball, carburetor of automobile and dynamic lift of an aeroplane all are <a href="https://interviewquestions.tuteehub.com/tag/based-389387" style="font-weight:bold;" target="_blank" title="Click to know more about BASED">BASED</a> on the Bernoulli.s <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a>.</body></html> | |
| 37433. |
A particle of mass 4 kg moves between two points A and B on a smooth horizontal surface under the aciton of two forces such that when it is at a point P, the forces are 2vec(P)AN and 2vec(P)B N.If the particle is released from rest at A, find the time it takes to travel a quarter of the way A toB. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a></body></html> | |
| 37434. |
If speed of light (c), acceleration due to gravity (g) and pressure (P) are taken as fundamental units, the dimensions of gravitational constant (G) are |
| Answer» <html><body><p>`[c^(0)gP^(-3)]`<br/>`[c^(2)g^(3)P^(-2)]`<br/>`c^(0)g^(2)P^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)]`<br/>`c^(2)g^(2)P^(-2)]`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let`G= kc^(x)g^(y)P^(z)` <br/>Where k is a dimensionless constant. <br/> `:. [M^(-1)L^(3)T^(-2)]= [LT^(-1)]^(x)[LT^(-2)]^(y)[ML^(-1)T^(-2)]^(z)= [M^(z)L^(x+y-z)T^(-x-2y-2z)]` <br/> Applying <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a> of <a href="https://interviewquestions.tuteehub.com/tag/homogeneity-1028735" style="font-weight:bold;" target="_blank" title="Click to know more about HOMOGENEITY">HOMOGENEITY</a> of dimensions we get, <br/> z=- 1...(i) <br/> x+y-z= 3...(ii) <br/>-x-2y-2z= -2,..(iii) <br/> On solving (i), (ii) and (iii) we get, <br/> `x=0, y=2, z=-1 :. [G]= [c^(0)g^(2)P^(-1)]`</body></html> | |
| 37435. |
When a body revolves in a circular path at a constant speed it is in an unstable equilibrium ___ true or false? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a></body></html> | |
| 37436. |
The below shown graphs represent the same motion. But one of them is incorrect. Find it. |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_070_O01.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_070_O02.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_070_O03.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_070_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(1) This is `vto t` graph for an object thrown upwards and the motion is constant. <br/> (2) Object doesn.t cover same distance in same time. Motion is not constant. <br/> (3) This graph <a href="https://interviewquestions.tuteehub.com/tag/shows-1206590" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWS">SHOWS</a> motion of object in <a href="https://interviewquestions.tuteehub.com/tag/upward-721781" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARD">UPWARD</a> <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> <br/> (4) This is also a constant motion. <br/> Hence, (A), (C) and (D) represent same constant motion. (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) doesn.t represent the same.</body></html> | |
| 37437. |
Energy required to move a body of mass 'M' from an orbit of radius 2R to 3R is........ |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(12R)`<br/>`(GMm)/(3R^(2))`<br/>`(GMm)/(<a href="https://interviewquestions.tuteehub.com/tag/8r-1930864" style="font-weight:bold;" target="_blank" title="Click to know more about 8R">8R</a>)`<br/>`(GMm)/(<a href="https://interviewquestions.tuteehub.com/tag/6r-331986" style="font-weight:bold;" target="_blank" title="Click to know more about 6R">6R</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Change in P.E in displacing a body from `r_(1)and r_(2)` is given by :<br/> `DeltaU = GMm [1/(r_(1))-1/(r_(2))]= GMm [1/(2R) -1/(3R)] = (GMm)/(6R)`</body></html> | |
| 37438. |
Two different adiabatic parts for the same gas intersect two isothermals at T_(1) "and" ^_(2) as shown in P-V diagram . Then the ratio of (V_(a))/(V_(b)) will be |
| Answer» <html><body><p>`(V_(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ))/(V_(d))`<br/>`(V_(d))/(V_(c))`<br/>`gamma(V_(d))/(V_(c))`<br/>`(1)/(gamma)(V_(d))/(V_(c))`</p>Solution :For adiabatic curve BC <br/> `T_(1)V_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)^(gamma-1)=T_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)V_(C)^(gamma-1)` <br/> Dividing (i) by (ii)<br/> `(V_(b))/(V_(a))^(gamma-1)=(V_(C))/(V_(d))^(gamma-1) rArr (V_(a))/(V_(b))=(V_(d))/(V_(C))`</body></html> | |
| 37439. |
Moment of inertia of a rigid body depends on (A) Mass of body (B) Position of axis of rotation (C) Angular velocity of the body (D) Time period of its rotation |
| Answer» <html><body><p>A and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/>B and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct <br/>A and C are correct <br/>C and D are correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37440. |
Two solidsphere of same matericalbut diameters in the raito of 5: 4 are at temperature 227^(@)Cand 127^(@)Crespectively. Thetemperatureof thesurroundingis 270^(@)Cand Stefan's lawholds . Calculatethe rates of heatradiation of thespheres ? |
| Answer» <html><body><p></p>Solution :If `E_("net")` is the enegylostper secondby unitsurfacce area , then `E_("net") = sigma (T^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) - T_(0)^(4))` <br/>`therefore ` Energy lostby the wholesphere in <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> sec ` = 4pi r^(2) sigma (T^(4) - T_(0)^(4))` <br/> Now `("Rateof heat lostby sphere I")/("Rateof heat lost by sphere II") =(r_(1)^(2)(T_(1)^(4) - T_(0)^(4)))/(r_(2)^(2)(T_(2)^(4) - T_(0)^(4))) = ((5)/(4))[(500^(4) - 300^(4))/(<a href="https://interviewquestions.tuteehub.com/tag/400-315233" style="font-weight:bold;" target="_blank" title="Click to know more about 400">400</a>^(4) - 300^(4))] = (<a href="https://interviewquestions.tuteehub.com/tag/34-308171" style="font-weight:bold;" target="_blank" title="Click to know more about 34">34</a>)/(7)`</body></html> | |
| 37441. |
Define coefficient of linear expansion. Give its unit. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of <a href="https://interviewquestions.tuteehub.com/tag/linear-1074458" style="font-weight:bold;" target="_blank" title="Click to know more about LINEAR">LINEAR</a> expansion of the material of a <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a> rod is defined as the increase in length per unit original length per degree rise in its temperature. The unit of `alpha_(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>) " is "^(@)C^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) (or) K^(-1)`</body></html> | |
| 37442. |
What isthermodynamicsystem ? Giveexample |
| Answer» <html><body><p></p>Solution :Thermodynamic system: A thermodynamic system is a finite part of the <a href="https://interviewquestions.tuteehub.com/tag/universe-13255" style="font-weight:bold;" target="_blank" title="Click to know more about UNIVERSE">UNIVERSE</a>. It is a collection of <a href="https://interviewquestions.tuteehub.com/tag/large-1066424" style="font-weight:bold;" target="_blank" title="Click to know more about LARGE">LARGE</a> number of particles (<a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> and molecules) <a href="https://interviewquestions.tuteehub.com/tag/specified-1221578" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIFIED">SPECIFIED</a> by certain parameters called pressure (P), Volume (V) and Temperature (T). The remaining part of the universe is called <a href="https://interviewquestions.tuteehub.com/tag/surrounding-1235953" style="font-weight:bold;" target="_blank" title="Click to know more about SURROUNDING">SURROUNDING</a>. Both are separated by a boundary. <br/> Examples: A thermodynamic system can be liquid, solid, gas and radiation.</body></html> | |
| 37443. |
In the previous question, if the two gases are compressed to the same final volume |
| Answer» <html><body><p> the final temperature is greater for the adiabatic process<br/>the final <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> is greater for the adiabatic process<br/>the <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done on the gas is greater for the adiabatic process<br/>all the above <a href="https://interviewquestions.tuteehub.com/tag/options-1137914" style="font-weight:bold;" target="_blank" title="Click to know more about OPTIONS">OPTIONS</a> are incorrect </p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::C</body></html> | |
| 37444. |
Explain the physical significance of momentum with example . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let <a href="https://interviewquestions.tuteehub.com/tag/us-718298" style="font-weight:bold;" target="_blank" title="Click to know more about US">US</a> consider a butterfly and a stone , both moving towardsus with same <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a>`5ms^(-1)`. If both hityour body, the effects with not be the same. The effects not only depend <a href="https://interviewquestions.tuteehub.com/tag/upon-2315586" style="font-weight:bold;" target="_blank" title="Click to know more about UPON">UPON</a> the velocity , but also on the mass . The stone has greater mass than to the butterfly . Themomentum of the stone is thus greater than the momentumofthe butterfly .</body></html> | |
| 37445. |
Two particlesA andBof masses 1kg and 2kg respectively are kept at very large separation. They are released from rest and move under their gravitational attraction. If the speedof .A. at certain instance is 4ms^(-1) speed of .B. at that instance in ms^(-1) is ____________ |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 37446. |
A boy executes S.H.M. The potential energy (PE), kinetic energy (KE) and total energy (TE) are measured as friction of displacement (x). Which of the following statement is true |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/ke-527890" style="font-weight:bold;" target="_blank" title="Click to know more about KE">KE</a> is <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> when <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>=0<br/>TE is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> at x=0<br/>KE maximum when 'x' is maximum<br/>PE is maximum when x=0</p>Answer :A</body></html> | |
| 37447. |
The efficiency of an ideal heat engine working between the freezing point and boiling point of water is ____ |
| Answer» <html><body><p>`12.5%`<br/>`26.8%`<br/>`6.25%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>%`</p>Solution :Freezing point of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> `T_2=0^@C`=273 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> <br/> Boiling point of water `T_1=100^@C` =<a href="https://interviewquestions.tuteehub.com/tag/373-1860225" style="font-weight:bold;" target="_blank" title="Click to know more about 373">373</a> K <br/> Efficiency `<a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a>=(T_1-T_2)/T_1xx100%` <br/> `=(373-273)/373xx100%` <br/> `=100/373xx100%` <br/> `=26.8%`</body></html> | |
| 37448. |
A point moves along the x axis according to the law x = sin^2(omega t - pi//4) the amplitude and period of oscillations are 2/n and (m pi)/omegathen the values of n and m are |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :4,1</body></html> | |
| 37449. |
What is the nature of the graph in the following : i) pressure and volume, keeping temperature constant. ii) pressure and reciprocal volume, keeping temperature constant. |
| Answer» <html><body><p></p>Solution :i) Shape of pressure (P) and volume (V) graph at constant temperatures is a rectangular <a href="https://interviewquestions.tuteehub.com/tag/hyperbola-1034512" style="font-weight:bold;" target="_blank" title="Click to know more about HYPERBOLA">HYPERBOLA</a>. <br/> <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) Shape of pressure (P) and <a href="https://interviewquestions.tuteehub.com/tag/reciprocal-1180061" style="font-weight:bold;" target="_blank" title="Click to know more about RECIPROCAL">RECIPROCAL</a> of volume (1/V) graph at constant temperature is a <a href="https://interviewquestions.tuteehub.com/tag/straight-633156" style="font-weight:bold;" target="_blank" title="Click to know more about STRAIGHT">STRAIGHT</a> line.</body></html> | |
| 37450. |
How does the velocity of flow change with the cross sectional area of a tube of flow? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Increase with <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> in <a href="https://interviewquestions.tuteehub.com/tag/cross-939411" style="font-weight:bold;" target="_blank" title="Click to know more about CROSS">CROSS</a> <a href="https://interviewquestions.tuteehub.com/tag/sectional-2255905" style="font-weight:bold;" target="_blank" title="Click to know more about SECTIONAL">SECTIONAL</a> area</body></html> | |