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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37851. |
Two capillary tubes of lengths in the ratio 2:1 and radii in the ratio 1:2 are connected in series. Assume the flow of the liquid through the tube is steady. Then, the ratio of pressure difference across the tubes is |
| Answer» <html><body><p>`1:8`<br/>`1:16`<br/>`32:1`<br/>`1:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37852. |
The gravitational potential at centre of earth is |
| Answer» <html><body><p>`-(<a href="https://interviewquestions.tuteehub.com/tag/2gm-300695" style="font-weight:bold;" target="_blank" title="Click to know more about 2GM">2GM</a>)/R` <br/>`-(<a href="https://interviewquestions.tuteehub.com/tag/3gm-1863190" style="font-weight:bold;" target="_blank" title="Click to know more about 3GM">3GM</a>)/R` <br/>`(3GM)/R` <br/>`-(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37853. |
The units and dimensions of impedance in terms of charge Q are |
| Answer» <html><body><p>ohm, `<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)T^(-2)<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>^(-2)`<br/>ohm, `ML^(2) T^(-1) Q^(-2)`<br/>ohm, `ML^(2)T^(-2)Q^(-1)`<br/>ohm, `<a href="https://interviewquestions.tuteehub.com/tag/mlt-2163963" style="font-weight:bold;" target="_blank" title="Click to know more about MLT">MLT</a>^(-1)Q^(-1)`</p>Answer :B</body></html> | |
| 37854. |
The dimensional formula for Torque is |
| Answer» <html><body><p>`M^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)LT^(-2)`<br/>`ML^(2)T^(-2)`<br/>`M^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)L^(2)T^(-2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/mlt-2163963" style="font-weight:bold;" target="_blank" title="Click to know more about MLT">MLT</a>^(-2)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37855. |
A particle executes SHM on a straight line. At two positions, its velocities are u and v while accelerations are alpha and beta respectively [beta gt alpha gt 0]. The distance between these two positions is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>^(2)+<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>+ beta)`<br/>`(u^(2)-v^(2))/(alpha+ beta)`<br/>`(u^(2)-v^(2))/(alpha- beta)`<br/>`(u^(2)+v^(2))/(alpha- beta)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37856. |
Consider a long steel bar under a tensile stress due to force F acting at the edges along the length of the bar (as shown in figure). Consider a plane making an angle with the length. What are the tensile and shearing stresses on this plane? (a) For what angle is the tensile stress a maximum ? (b) For what angle is the shearing stress a maximum ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/think-661001" style="font-weight:bold;" target="_blank" title="Click to know more about THINK">THINK</a> below figure, <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P2_C09_E04_024_S01.png" width="80%"/> <br/> Suppose A is the cross sectional area of the bar. Let for balance of pane aa. angle `pi/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> - theta` between perpendicular ON to the pane and <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> F. The parallel component of force to the pane, <br/> `F_(P) = F sin ((pi)/(2) - theta) = F cos theta and ` <br/> Perpendicular component, <br/> `F_(N) = F cos ((pi)/(2) -theta)= F sin theta` <br/> Suppose A is area of pane (face) aa. <br/> `therefore (A)/(A.) = sin theta` <br/> `therefore A. = (A)/(sin theta )` <br/> Tensile stress `= ("perpendicular force")/("area") = (F _(N))/(A.)= (F sin thea)/(A//sin theta)` <br/> `therefore` Tensile stress `= F/A sin ^(2) theta ` <br/> (a) For <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> stress `F/A sin ^(2) theta ` should be maximum. <br/> `sin ^(2) theta =1` <br/>`therefore sin theta =1` <br/> `therefore theta = (pi)/(2)` <br/> For this `theta = <a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@)` <br/> Shearing stress `= ("parallel force")/("area") = (F _(p ))/(A.)` <br/> ` = (F cos theta )/(A //sin theta) = F/A sin theta cos theta= (F)/(2A) xx sin 2 theta` <br/> `[ because 2 sin theta cos theta = sin 2 theta]` <br/> (b) For shearing stress to be maximum `sin 2 theta =1` <br/> `therefore 2 theta =90^(@)` <br/> `therefore theta = 45^(@)`</body></html> | |
| 37857. |
If at STP, velocity of sound in a gas (y=1.5) is 600m//s, the rms velocity of the gas molecules at STP will be |
| Answer» <html><body><p>`400m//s`<br/>`600m//s`<br/>`600sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)m//s`<br/>`300sqrt(2)m//s`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`V=sqrt((gammaRT)/(M))`</body></html> | |
| 37858. |
A satellite appears to be at rest when seen from. the equator of the earth. The height of the satellite from the surface of the earth is |
| Answer» <html><body><p>36000km<br/>6400km<br/>40000km<br/>1000km</p>Answer :A</body></html> | |
| 37859. |
If an experiment to measure coefficient of viscosity radius of tube measured r = (0.100 +- 0.001) cm and length 1 = (50.0 +- 0.1) cm and volume of fluid coming out of capillary in unit time is V = (0.25 +-0.01) cm//^(2). If pressure difference between end of tube is p = 10^(6) dyne/ cm^(2), then by using Poeisullie's law V=(pi pr^(4))/(8 eta l) Find coefficient of viscosity. |
| Answer» <html><body><p></p>Solution :By using Poesullie.s law. <br/> `V=(pi p r^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))/(8 etal)` <br/> `:. eta=(pi p r^(2))/(8 Vl) ""...(1)` <br/> `=(3.14xx10^(6)xx(0.1)^(4))/(8xx50xx0.25)` <br/> `=3.14` <a href="https://interviewquestions.tuteehub.com/tag/poise-601896" style="font-weight:bold;" target="_blank" title="Click to know more about POISE">POISE</a> <br/> Relative error in `eta` <br/> `(Delta eta)/(eta)=((Deltar)/(r))+((DeltaV)/(V))+((Deltal)/(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)) "" [ :. (pi)/(8)` <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> ] <br/> `=4xx(0.001)/(0.1)+(0.01)/(0.25)+(0.1)/(50)` <br/> `=0.04+0.04+0.002` <br/> `=0.082` <br/> `:.(Delta eta)/(3.14)=0.082` <br/> `:.Delta eta=0.0082xx3.14` <br/> `=0.25748~~0.257` <br/> `:. eta+Deltan=(3.14+-0.257)` Poise <br/> OR <br/> Second method : <br/> `(Delta eta)/(eta)<a href="https://interviewquestions.tuteehub.com/tag/xx100-3292680" style="font-weight:bold;" target="_blank" title="Click to know more about XX100">XX100</a>%=0.082xx100%` <br/> `=8.2` <br/> `:. eta=3.14+-8.2%` Poise</body></html> | |
| 37860. |
A mass attached to a spring is free to oscillate, with angular velocity omega, in a horizontal plane without friction or damping. It is pulled to a distance x_(0) and pushed towards the centre with a velocity v_(0) at time t = 0. Determine the amplitude of the resulting oscillations in terms of the parameters omega, x_(0) and v_(0). [Hint : Start with the equation x = a cos (omegat+theta) and note that the initial velocity is negative.] |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`sqrt((x_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)^(2)+(v_(0)^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(2))))`</body></html> | |
| 37861. |
For isothermal process of an ideal gas (dP)/P= _____ |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`-(<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/V` <br/> For isothermal <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> PV=constant, <br/> Differentiate it <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` PdV+dPV=0 <br/> `therefore` dPV=-PdV <br/> `therefore (dP)/P=-(dV)/V`</body></html> | |
| 37862. |
What is the physical quantity of the time rate of the angular momentum? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The time rate of change of angular <a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a> indicates <a href="https://interviewquestions.tuteehub.com/tag/torque-1422441" style="font-weight:bold;" target="_blank" title="Click to know more about TORQUE">TORQUE</a> `(dvecL)/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>)=vectau`</body></html> | |
| 37863. |
which of the following is a unitless quantity |
| Answer» <html><body><p>velocity gradient <br/>pressure gradient <br/><a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> gradient <br/><a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> gradient </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37864. |
A student sees a jet plane flying from east to west. When the jet is seen just above his head, the sound of jet appears to reach him making angle of 60^(@) with the horizontal from the east. If the velocity of the sound is V, then that of the jet plane is |
| Answer» <html><body><p>`2V`<br/>`((<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))V`<br/>`((2)/(sqrt(3)))V`<br/>`(V)/(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37865. |
What do you mean by inertia of direction? Give one example. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/whena-3274932" style="font-weight:bold;" target="_blank" title="Click to know more about WHENA">WHENA</a> stonetiedto a <a href="https://interviewquestions.tuteehub.com/tag/stringis-3080589" style="font-weight:bold;" target="_blank" title="Click to know more about STRINGIS">STRINGIS</a> in whiring motionand if thestringis cutsuddenlythe stonewill not continueto movein circularmotionbutmovestangentialto <a href="https://interviewquestions.tuteehub.com/tag/thecircle-3192972" style="font-weight:bold;" target="_blank" title="Click to know more about THECIRCLE">THECIRCLE</a>.</body></html> | |
| 37866. |
A small spherical ball is suspended through a string of length l. The whole arrangement is placed in a vehicle, which is moving with velocity v. Now suddenly the vehicle stops and ball stats moving along a circular path. If tension in the string at the highest point is twice the weight of the ball, then |
| Answer» <html><body><p>`v=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(5gl)`<br/>`v=sqrt(7gl)`<br/>Velocity of the ball at <a href="https://interviewquestions.tuteehub.com/tag/highest-1022683" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHEST">HIGHEST</a> <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> is `sqrt(gl)`<br/>Velocity of the ball at highest point is `sqrt(3gl)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B::D</body></html> | |
| 37867. |
At what points is the energy entirely Potential in SHM ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> at <a href="https://interviewquestions.tuteehub.com/tag/extreme-981946" style="font-weight:bold;" target="_blank" title="Click to know more about EXTREME">EXTREME</a> <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a>.</body></html> | |
| 37868. |
If the length of the simple pendulum is equal to the radius of the earth, and it oscillates just above the surface of the earth then its time period is a) 2pisqrt((R)/(2g))(b)2pisqrt((R)/(g)) c) nearly 59.5 minutes d) 84.6 minutes |
| Answer» <html><body><p>a is only <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a><br/>b is only correct<br/>a and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct<br/> a and b are correct</p>Answer :C</body></html> | |
| 37869. |
Two identical billiard balls strike a rigid wall with the same speed but at different angles, and get reflected without any change in speed,as shown in Fig. 5.6. What is (i) the direction of the force on the wall due to each ball? (ii) the ratio of the magnitudes of impulses imparted to the balls by the wall ? |
| Answer» <html><body><p></p>Solution : An instinctive answer to (i) might be that the force on the <a href="https://interviewquestions.tuteehub.com/tag/wall-1448655" style="font-weight:bold;" target="_blank" title="Click to know more about WALL">WALL</a> in case (a) is normal to the wall, while that in case (b) is inclined at 30° to the normal. This answer is wrong.The force on the wall is normal to the wall in both cases. How to find the force on the wall? The trick is to consider the force (or impulse) onthe ball due tothe wall using the second law, and then use the third law to answer (i). Let u be the speed of each ball before and after collision with the wall, and m the mass of each ball. <a href="https://interviewquestions.tuteehub.com/tag/choose-419254" style="font-weight:bold;" target="_blank" title="Click to know more about CHOOSE">CHOOSE</a> the x and y <a href="https://interviewquestions.tuteehub.com/tag/axes-386573" style="font-weight:bold;" target="_blank" title="Click to know more about AXES">AXES</a> as shown in the figure, and consider the change in momentum of the ball in each case :<br/>Case (a)<br/> `(p_x)_("initial")` = mu`(p_y)_("initial") = 0` <br/>`(p_x)_("final")`= -mu`(p_y)_("final") = 0` <br/>Impulse is the change in momentum vector. Therefore ,<br/> x-component of impulse=– 2 m u <br/>y-component of impulse=0<br/>Impulse and force are in the same direction. Clearly, from above, the force on the ball due to the wall is normal to the wall, along the <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> x-direction.Using Newton’s third law of motion, the force on the wall due to the ball is normal to the wall along the positive x-direction. The magnitude of force cannot be ascertained since the small time taken for the collision has not been specified in the problem.<br/> case (b)<br/> `(p_x)_("initial") = ` mu cos `30^@ , (p_y)_("initial") = ` - mu sin `30^@` <br/>`(p_x)_("final")`= - mu cos `30^@ , (p_y)_("final") = ` - mu sin `30^@`<br/><a href="https://interviewquestions.tuteehub.com/tag/note-1125278" style="font-weight:bold;" target="_blank" title="Click to know more about NOTE">NOTE</a> while `p_x` changes sign after collision , `p_y` does not. therefore<br/>x - component of impulse= - mu `cos 30^@` <br/> y = component impulse = 0 <br/> The direction of impulse (and force) is the same as in (a) and is normal to the wall along the negative x direction.As before, using Newton’s third law, the force on the wall due to the ball is normal to the wall along the positive x direction. The ratio of the magnitudesof the impulses imparted to the balls in (a) and (b) is<br/> 2mu/(2mu cos `30^@`) = `(2)/(sqrt3) = 1.2`</body></html> | |
| 37870. |
Two moles of a perfect gas heated to increaseits temperature by 4^(@)C absorbs heat of 32 Cal at constant volume. If the same gas is heated at constant pressure the amount of heat supplied is (R = 2 Cal /mol K) |
| Answer» <html><body><p>32 <a href="https://interviewquestions.tuteehub.com/tag/cal-412083" style="font-weight:bold;" target="_blank" title="Click to know more about CAL">CAL</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/48-318016" style="font-weight:bold;" target="_blank" title="Click to know more about 48">48</a> Cal <br/><a href="https://interviewquestions.tuteehub.com/tag/56-325545" style="font-weight:bold;" target="_blank" title="Click to know more about 56">56</a> Cal <br/><a href="https://interviewquestions.tuteehub.com/tag/64-330663" style="font-weight:bold;" target="_blank" title="Click to know more about 64">64</a> Cal </p>Answer :B</body></html> | |
| 37871. |
The smallest physical unit of time is………….. |
| Answer» <html><body><p>second<br/>minute<br/>hour<br/>year</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/shake-11439" style="font-weight:bold;" target="_blank" title="Click to know more about SHAKE">SHAKE</a></body></html> | |
| 37872. |
Which of the following qauntities is dependent of the choice of orientation of coordinates axes? |
| Answer» <html><body><p>`vecA + vecB` <br/>`A_(x) + B_(y)` <br/>`|vecA + vecB|` <br/>Angle between `vecA and vecB` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :A vector, its magnitude and the angle between two vectors do not depend on the choice of the orientation of the coordinate axes. `vecA + vecB, |vecA + vecB|`,angle between `vecA and vecB` are independent of the orientation of the coordinate axes. <br/> but the <a href="https://interviewquestions.tuteehub.com/tag/quantity-1174212" style="font-weight:bold;" target="_blank" title="Click to know more about QUANTITY">QUANTITY</a> `A_(x) + B_(y)` depends upon the magnitude of the <a href="https://interviewquestions.tuteehub.com/tag/component-926634" style="font-weight:bold;" target="_blank" title="Click to know more about COMPONENT">COMPONENT</a> along x and y-axes, <a href="https://interviewquestions.tuteehub.com/tag/soit-7847042" style="font-weight:bold;" target="_blank" title="Click to know more about SOIT">SOIT</a> will change with change in coordinate axes.</body></html> | |
| 37873. |
Which of the following is not characteristics of simple harmonic motion? |
| Answer» <html><body><p>The motion is periodic<br/>the motion is along a straight line about the mean position<br/>The <a href="https://interviewquestions.tuteehub.com/tag/oscillations-22507" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATIONS">OSCILLATIONS</a> are responsible for the energy conversion.<br/>The <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> of the particle is <a href="https://interviewquestions.tuteehub.com/tag/directed-440230" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTED">DIRECTED</a> <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> the extreme position.</p>Solution :In SHM, the acceleration of the particle is directed towards <a href="https://interviewquestions.tuteehub.com/tag/themean-3199929" style="font-weight:bold;" target="_blank" title="Click to know more about THEMEAN">THEMEAN</a> position.</body></html> | |
| 37874. |
The unit of Stefan's constant is |
| Answer» <html><body><p>`Wm^-2K^-1`<br/>`WmK^-4`<br/>`Wm^-2K^-4`<br/>`Nm^-2K^-4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37875. |
can a heat engine convert full intake of heat into work ? |
| Answer» <html><body><p></p>Solution :no according to second law of <a href="https://interviewquestions.tuteehub.com/tag/thermodynamics-12722" style="font-weight:bold;" target="_blank" title="Click to know more about THERMODYNAMICS">THERMODYNAMICS</a> the whole of <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> cannot be <a href="https://interviewquestions.tuteehub.com/tag/converted-2543437" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERTED">CONVERTED</a> into work</body></html> | |
| 37876. |
A bicycle is motion. The force of friction exerted by the ground on its wheel is such that it acts : |
| Answer» <html><body><p>in <a href="https://interviewquestions.tuteehub.com/tag/forward-464460" style="font-weight:bold;" target="_blank" title="Click to know more about FORWARD">FORWARD</a> direction on both wheel it is <a href="https://interviewquestions.tuteehub.com/tag/accelerating-366486" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATING">ACCELERATING</a> <br/>in forward direction on front wheel and in <a href="https://interviewquestions.tuteehub.com/tag/backward-391901" style="font-weight:bold;" target="_blank" title="Click to know more about BACKWARD">BACKWARD</a> direction on rear wheel <a href="https://interviewquestions.tuteehub.com/tag/brakes-14257" style="font-weight:bold;" target="_blank" title="Click to know more about BRAKES">BRAKES</a> are <a href="https://interviewquestions.tuteehub.com/tag/applied-380664" style="font-weight:bold;" target="_blank" title="Click to know more about APPLIED">APPLIED</a> on rear wheel only <br/>in backward direction on front wheel and in forward direction on rear when brakes are applied on rear wheel only <br/>in forward direction on both the wheel when brakes are applied on both the wheels </p>Answer :B</body></html> | |
| 37877. |
A body of mass m is moved to a height to equal to the radius of earth.The increase in P.E is |
| Answer» <html><body><p>mgR<br/>1/2 mgR<br/>2mgR<br/>1/4 mgR</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37878. |
The difference in the value of .g. at pole and at a latitude is (3)/(4)Rw^(2) then latitude angle is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)` <br/>`45^(@)` <br/>`95^(@)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37879. |
A body executing forced oscillations under driving force is in sharp resonance. If damping increases, then sharpness of resonance |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a><br/>remains same <br/><a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a><br/>first increases then decreases </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37880. |
A: During takeoff of an aeroplane, velocity of air above the wing is greaterthan velocity below the wing R: Bernoulli.s principle is based on law of conservation of energy |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and R is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of A<br/>Both A and B are true and R is not the correct explanation of A<br/>A is true and R is false<br/>A is false and R is true</p>Answer :B</body></html> | |
| 37881. |
In damped oscilation the directions of the restoring force and the resistive force |
| Answer» <html><body><p>are the same <br/>are opposite<br/>maybe same or opposite<br/>no relation</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37882. |
A body with constant acceleration always moves along a straight line. A body with constant magnitude of acceleration may not speed up. |
| Answer» <html><body><p>Statement (I) is true, Statement (II) is true , statement (II) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> for Statement (I).<br/>Statement (I) is true, Statement (II) is true , statement (II) is not the correct explanation for Statement (I).<br/>Statement (I) is true, Statement (II) is false.<br/>Statement (i) is false, Statement (II) is true.</p>Solution :(d) Projectile motion is a motion with constant acceleration but it is not a straight line motion. <br/> A body with constant magnitude of acceleration may not speed up, this is <a href="https://interviewquestions.tuteehub.com/tag/possible-592355" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBLE">POSSIBLE</a> in <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> circular motion.</body></html> | |
| 37883. |
The frequency of vibrating air column in closed organ pipe is n. If it length be boubled and radius halved. Its frequency will be nearly : |
| Answer» <html><body><p>`(n)/(2)`<br/>`4n`<br/>n<br/>`2n`</p>Solution :For a closed organ pipe, <br/> `n=(v)/(4L) rArr n <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)` <br/> If `L=2L` <br/> Then `n' prop (1)/(2L)` <br/> `(n')/(n')=(L)/(2L)` <br/> (or) `n'(n)/(2)` <br/> Radius has no effect on frequency.</body></html> | |
| 37884. |
The maximum distance to which a man can throw a ball by projecting it horizontally from a height h is h. The maximum distance to which he can throw it vertically up is |
| Answer» <html><body><p>h<br/>2h<br/>h/2<br/>h/4</p>Answer :D</body></html> | |
| 37885. |
Heat is associated with |
| Answer» <html><body><p>kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of <a href="https://interviewquestions.tuteehub.com/tag/random-11853" style="font-weight:bold;" target="_blank" title="Click to know more about RANDOM">RANDOM</a> <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> of molecules.<br/>kinetic energy of <a href="https://interviewquestions.tuteehub.com/tag/orderly-587493" style="font-weight:bold;" target="_blank" title="Click to know more about ORDERLY">ORDERLY</a> motion of molecules.<br/>total kinetic energy of random and orderly motion of molecules.<br/>kinetic energy of random motion in some cases and kinetic energy of orderly motion in other.</p>Answer :A</body></html> | |
| 37886. |
What is the effect of decreasing the height of a satellite orbiting around earth on its time period? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a>` Time period of satellite `T=2pisqrt(((R_e+h)^<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(GM_e))`hence, h decreases, its time period decreases.</body></html> | |
| 37887. |
A block is dragged on a smooth plane with the help of a rope which moves with velocity (v) shown in Fig. 2 (CF). 25 , The horizontal velocity of the block is . |
| Answer» <html><body><p>`v` <br/>` v <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> `<br/>v//sin theta`<br/>`v//cos theta`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> ` AB = X, then ` <a href="https://interviewquestions.tuteehub.com/tag/ac-361271" style="font-weight:bold;" target="_blank" title="Click to know more about AC">AC</a>= x cos theta` <br/> :. ` (d(AC)/(dt) = d/(dt) (x cos theta) = (<a href="https://interviewquestions.tuteehub.com/tag/dx-960990" style="font-weight:bold;" target="_blank" title="Click to know more about DX">DX</a>)/(dt) cos theta + x (- sin theta) (d theta)/(dt)` <br/> But `(d(AC)/(dt) = 0 `, so ` 0= (dx)/(dt) cos theta + x ( - sin theta) ( d theat)/(dt)` <br/> or ` v cos theta = x sin theta = x sin theta (d theta)/(dt)` or ` (dtheta)/(dt) = ( v cos theta)/(x sin theta)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XI_V01_C02_E01_371_S01.png" width="80%"/>. <br/> Also , ` CB = x sin theta`. <br/> Velocity of block will be <br/> ` u = sin theta + x cos theta xx (v cos theta)/( x sin theta)` <br/> ` (v (sin^@ theta + cos^2 theta)/( sin theta) = v/(sin theta)`.</body></html> | |
| 37888. |
The magnitude of gravitational potential energy of the moon-earth system is U with zero potential energy at infinite separation. The kinetic energy of the moon with respect to the earth is K. |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>`<br/>`U <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> K`<br/>U = K<br/>None</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37889. |
Which of the following potential energy curves in figure cannot describe the elastic collision of twobilliard balls ? Here r is the distance between centres of the balls . |
| Answer» <html><body><p></p>Solution :Distance between centre of <a href="https://interviewquestions.tuteehub.com/tag/balls-891923" style="font-weight:bold;" target="_blank" title="Click to know more about BALLS">BALLS</a> is <a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a> when both ball collide . <br/> During every elastic collision , the shape of ball slightly <a href="https://interviewquestions.tuteehub.com/tag/changes-913881" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGES">CHANGES</a> . <br/> In elastic collision potential energy <a href="https://interviewquestions.tuteehub.com/tag/converted-2543437" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERTED">CONVERTED</a> into kinetic energy . <br/> The potential energy of a system of two masses is inversely proportional to the separation between them . <br/> ` :.V prop 1/r` <br/> Out of the given graph , curve (v) only satisfies these two <a href="https://interviewquestions.tuteehub.com/tag/consitions-2539411" style="font-weight:bold;" target="_blank" title="Click to know more about CONSITIONS">CONSITIONS</a> .Therefore , all other curves cannot possibly describe the elastic collision of two billiard balls .</body></html> | |
| 37890. |
Prove that the ratio of the rate of change of g at a height equal to the earth's radius from the surface of the earth of the value of g at the surface of the earth is equal to (-1)/(4R_e) |
| Answer» <html><body><p></p>Solution :`implies` Gravitational acceleration at .r. `(r <a href="https://interviewquestions.tuteehub.com/tag/ge-1003146" style="font-weight:bold;" target="_blank" title="Click to know more about GE">GE</a> R_e)`from the <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> of <a href="https://interviewquestions.tuteehub.com/tag/earth-13129" style="font-weight:bold;" target="_blank" title="Click to know more about EARTH">EARTH</a> . <br/> `g(r) = (GM_e)/r^2` <br/> Differentiating w.r.t. to <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> r, <br/> `(dg(r))/(<a href="https://interviewquestions.tuteehub.com/tag/dr-959219" style="font-weight:bold;" target="_blank" title="Click to know more about DR">DR</a>) = (-2GM_e)/r^3` <br/> `= -(2GM_e)/((8R_e)R_(e)^2)[ :. (GM_e)/R_e^2="ge"]` <br/> `:. [(dg(r))/(dr)]_(2R_e) =(-"ge")/(4R_e)` <br/> =`[(dg(r))/(dr)]_(2Re)/("ge")=-1/(4R_e)` .</body></html> | |
| 37891. |
For a gas at a temperature T the Root mean square velocity v_(rms) ,the most probable speed v_(mp),and the average speed a_(av) obey the relationship |
| Answer» <html><body><p>`v_(<a href="https://interviewquestions.tuteehub.com/tag/av-888878" style="font-weight:bold;" target="_blank" title="Click to know more about AV">AV</a>) gt v_(<a href="https://interviewquestions.tuteehub.com/tag/rms-1190227" style="font-weight:bold;" target="_blank" title="Click to know more about RMS">RMS</a>) gt v_(mp)`<br/>`v_(rms) gt v_(av) gt v_(mp)`<br/>`v_(mp) gt v_(av) gt v_(rms)` <br/>`v_(mp) gt v_(rms) gt v_(av)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 37892. |
Three particles A, B and C of respective masses m_(1), m_(2) and m_(3) lie on a smooth horizontal surface, and an fastened to two light inextensible strings as shown in Fig. The particle A is imparted an impulse J along vec(BA) . Find the initial speed of each particle. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`J-J_(1)=m_(1)v_(1)` ………i <br/> `J_(1)-J_(2)(cos45^(@))=m_(2)v_(2y)`…………..ii <br/> <img src="https://d10lpgp6xz60nq.cloudfront.<klux>NET</klux>/physics_images/BMS_VOL2_C01_E01_061_S01.png" width="80%"/> <br/> `J_(2)sin45^(@)=m_(2)v_(2x)`…………..iii <br/> `J_(2)=m_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)v_(3)` ……………iv. <br/> Now `v_(2y)=v_(1)` and `v_(2y)cos45^(@)-2_(2x)cos45^(@)=v_(3)` <br/> Solve to get `v_(y)=(sqrt2m_(2)J)/(m_(1)m_(3)+2m_(2)(m_(1)+m_(2)+m_(3)))` <br/> `v_(1)=((m_(3)+2m_(2))J)/(m_(1)m_(3)+2m_(2)(m_(1)m_(2)+m_(3)))` <br/> `v_(2x)=(m_(3)v_(3)cos45^(@))/m_(2)=(m_(3)J)/(m_(1)m_(3)+2m_(2)(m_(1)+m_(2)+m_(3)))` <br/> Net velocity of `m_(2)` <br/> `=sqrt(v_(1)^(2)+v_(2x)^(2))=(sqrt2(m_(2)^(2)+(m_(2)+m_(3))^(2))^(1//2))/(m_(1)m_(3)+2m_(2)(m_(1)+m_(2)+m_(3)))`</body></html> | |
| 37893. |
The value of resistance is 10.84 ohm and current is 3.23 A . The potential difference is 35.02935 V its value in significant number will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a> V<br/>35.0 V<br/>35.03 V<br/>35.0290V</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37894. |
The length of a metallic sheet is measured as 10.0 cm using a metre scale of L.C. 0.1cm and its breadth is measured as 1.00 cm using a vernier callipers of L.C. 0.01cm, the error in area is |
| Answer» <html><body><p>`pm0.01 cm^2` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a> 0.1 cm^2` <br/>`+0.11 cm^2` <br/>`pm 0.2 cm^2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37895. |
Give any two examples for parallelogram law of vectors. |
| Answer» <html><body><p></p>Solution :(i) the <a href="https://interviewquestions.tuteehub.com/tag/flight-462826" style="font-weight:bold;" target="_blank" title="Click to know more about FLIGHT">FLIGHT</a> of a <a href="https://interviewquestions.tuteehub.com/tag/bird-898337" style="font-weight:bold;" target="_blank" title="Click to know more about BIRD">BIRD</a> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <a href="https://interviewquestions.tuteehub.com/tag/working-1459914" style="font-weight:bold;" target="_blank" title="Click to know more about WORKING">WORKING</a> of a sling.</body></html> | |
| 37896. |
The minimum force required to move a body up an inclined plane is three times the minimum force required to prevent it from sliding down the plane. If the coefficient of friction between the body and the inclined plane (1)/(2sqrt3),is the angle of the inclined plane is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@)`<br/>`30^(@)`<br/>`15 ^(@)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 37897. |
In which process, the p - v indicator diagram is a straight line parallel to volume axis? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/isothermal-520014" style="font-weight:bold;" target="_blank" title="Click to know more about ISOTHERMAL">ISOTHERMAL</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/isobaric-1052329" style="font-weight:bold;" target="_blank" title="Click to know more about ISOBARIC">ISOBARIC</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/irreversible-519610" style="font-weight:bold;" target="_blank" title="Click to know more about IRREVERSIBLE">IRREVERSIBLE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Isobaric</body></html> | |
| 37898. |
A nucleus is at rest in the laboratory frame of reference.Show that if it disintegrates into two smaller nuclei the products must move in opposite directions. |
| Answer» <html><body><p></p>Solution : By <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> conservation <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a>, <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> final momentum is zero.Two momentum vectors cannot sum to a <a href="https://interviewquestions.tuteehub.com/tag/null-17167" style="font-weight:bold;" target="_blank" title="Click to know more about NULL">NULL</a> momentum unless they are equal and opposite.</body></html> | |
| 37899. |
An aircraft is flying at a height of 3400mabove the ground . If the angle subtended at a ground observation point by the aircreaft positions 10.0 s apart is 30^(@) , what is the speed of the aircraft ? |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MOD_UNT_PHY_XI_P1_C04_E04_025_S01.png" width="80%"/> <br/><a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> A and B be the positions of the aircraft for which ` <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> ACB=30^(@)` <br/> Time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> by the aircraft to go from A to B =10 s <br/> Here OC =3400 m <br/> `tan 15^(@)=(<a href="https://interviewquestions.tuteehub.com/tag/oa-582846" style="font-weight:bold;" target="_blank" title="Click to know more about OA">OA</a>)/(OC)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> OA=OC tan 15^(@)` <br/> `=3400xx0.267=907.8m` <br/>Speed of aircraft` =("Distance "AB)/("Time")` <br/> `=(2xxOA)/(10 s)=(2xx907.8)/(10)` <br/> `=181.56`m</body></html> | |
| 37900. |
Assertion : Rule is an example for Orthogonal vectors. Reason : When we stretch first three fingers of our right hand, Magnetic field along fore finger (i.e. X- axis ) current direction along middle finger (i.e. Y - axis ) and motion of the conductor along the thumb direction (i.e. Z axis) |
| Answer» <html><body><p>Assertion and Reason are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and Reason is correct explanation of Assertion <br/>Assertion and Reason are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> but Reason is the false explanation of the Assertion <br/>Assertion is true but Reason is false <br/>Assertion is false but Reason is true </p>Answer :A</body></html> | |