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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37901. |
A glass flask of volume 1000cm. is completely filled with mercury at 0^(@)C. The coefficient of cubical expansion of mercury is 182 xx 10 ^(4) // ^(@)Cand that of glass is 30 xx 10 ^(-4) //^(@)C. If the flask is now placed in boiling water at 100°C, how much mercury will over flow? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`15.2 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> ^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</body></html> | |
| 37902. |
A cylinderical wooden block of cross-section 15.0 cm^(2) and 250 gram attached to its bottom. The cylinder floats vertically. From the state of equilibrium, it is slightly depressed and released. If the specific gravity of wood is 0.3 and g=9.8 ms^(-2), deduce the frequency of oscillation of the block. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Here, `(250+30)980=15.0xxlxxlxx980` <br/> or `l=56//3 cm.` <br/> <a href="https://interviewquestions.tuteehub.com/tag/use-1441041" style="font-weight:bold;" target="_blank" title="Click to know more about USE">USE</a> the relation `T=2pisqrt(l//g)` and put the <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a>.</body></html> | |
| 37903. |
A metal rod of Young's modulus and coefficient of thermal expansion alpha is held at its two ends such that its length remains invariant. If its temperature is raised by t^(@)C, the linear stress developed it its is ..... |
| Answer» <html><body><p>`(alpha t )/(F)`<br/>`(Y)/(alpha t)`<br/>`Y prop t `<br/>`(1)/(Y prop t)`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> l = alpha l Delta T` <br/> `therefore (Delta l )/(l) = alpha Delta T ""...(1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/young-749721" style="font-weight:bold;" target="_blank" title="Click to know more about YOUNG">YOUNG</a> modulus `Y = ("stress" <a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a> _(l))/("<a href="https://interviewquestions.tuteehub.com/tag/strain-17653" style="font-weight:bold;" target="_blank" title="Click to know more about STRAIN">STRAIN</a>" G_(l))` <br/> `therefore epsi _(l ) = (sigma _(l))/(Y)` <br/> `therefore (Delta l )/(l) = (sigma _(l))/( Y) ""...(2)` <br/> From equation (1) and (2) <br/> `(sigma _(1))/(Y) = alpha Delta T` <br/> `therefore sigma _(l) = Y prop Delta T` <br/> `therefore sigma _(l) = Y prop T` (where `Delta T =l ^(@)C)`</body></html> | |
| 37904. |
A circular ring of mass m and radius r is rotating in a horizontal plane about an axis vertical to its plane. What will its rotational kinetic energy? (Angular speed of ring is w) |
| Answer» <html><body><p>`(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(2)w^(2)`<br/>`mr^(2)w^(2)`<br/>`(1)/(2)mrw^(2)`<br/>`mrw^(2)`</p>Solution :Rotational kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> = `(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/iomega-2133375" style="font-weight:bold;" target="_blank" title="Click to know more about IOMEGA">IOMEGA</a>^(2)` but for <a href="https://interviewquestions.tuteehub.com/tag/ring-1189545" style="font-weight:bold;" target="_blank" title="Click to know more about RING">RING</a> <br/> `I=mr^(2)` <br/> `=(1)/(2)mr^(2)omega^(2)`</body></html> | |
| 37905. |
A thermodynamic process is shown in figure. In process ab, 600 J of heat is added, and in process bd 200 J of heat is added. The total heat added in process acd is |
| Answer» <html><body><p>550 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/>650 J<br/>750 J<br/>850 J</p>Solution :There is no volume change in process ab, so <a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a> = 0Process <a href="https://interviewquestions.tuteehub.com/tag/bd-389836" style="font-weight:bold;" target="_blank" title="Click to know more about BD">BD</a> occurs at constant pressure, so the work done by the system is<br/> `W = P(V_(2) - V_(1)) = (8 xx 10^(4) Pa)(5 xx 10^(-3)m^(3) - 2 xx 10^(-3) m^(3)) = 240 J` <br/> Thus the total work for abd is W = 240 J and the total heat for abd is Q = 800 J. <br/> `:. Delta U = Q - W = 800 J - 240 J = 560 J` <br/> Because `Delta U` is independent of path, the <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> energy change is the same for the path acd as for abd, that is, 560 J. The total work for path acd is<br/> `W = (3 xx 10^(4) Pa)(5 xx 10^(-3)m^(3) - 2 xx 10^(-3) m^(3)) = <a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a> J` <br/> `:.` Total heat added in the path acd is<br/> `Q = Delta U + W = 560 J + 90 J = 650 J`</body></html> | |
| 37906. |
When F = 2 N , the frictional force between 5 kg block and ground is : |
| Answer» <html><body><p>2N<br/>0<br/>8 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a><br/>10 N </p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_AM_PHY_C07_E01_159_S01.png" width="80%"/> <br/> If F = 2N <br/> `f_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = F = 2N` <br/> `f_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = f_(1)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_AM_PHY_C07_E01_159_S02.png" width="80%"/></body></html> | |
| 37907. |
At a metro station, a girl walks up a stationary escalator in time. t _(1),If she remains stationary on the escalator, then the escalator take her up in time t_(2). The time taken by her to walk up on the moving escalator will be |
| Answer» <html><body><p>`(t_(1) +t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)) //2`<br/>`t _(1) t _(2) // (t - t _(1))`<br/>`t _(1) t _(2) //(t_(2) + t _(1))`<br/>`t _(1) - t _(2)` </p>Solution :Net velocity with respectto the Earth that will be equal to velocity of the girl plus velocity of esaclator. <br/> Let displacemtn is L, then <br/> velocity of girl `v _(g) = (L)/(t _(1)) ` <br/> velocity of escaltoor `v _(e) = (L)/(t _(2))` <br/> Net velocity of the girl, `v =v _(g) + v _(e) = (L)/(t_(1)) + (L)/(t_(2)) ...(i)` <br/> If t is total time taken in covering distance L, then `v = L/t` <br/> Using in (i) `L/t = (L)/(t _(1)) + (L)/(t _(2)) <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> t = (t_(1) t_(2))/(t _(1) + t _(2))`</body></html> | |
| 37908. |
A stone is allowed to fall from a top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s.The two stones will melt after : |
| Answer» <html><body><p>40s<br/>0.<a href="https://interviewquestions.tuteehub.com/tag/4s-318811" style="font-weight:bold;" target="_blank" title="Click to know more about 4S">4S</a><br/>4s<br/>0.04s</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2) <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> t^(2) "" . . . (1) ` <br/>` s = ut - (1)/(2) g t^(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> - x = 25 t - (1)/(2) g t^(2) "". . . (2)`<br/>Adding (1) and(2) we get ,<br/>100 = 25 t<br/>`:. t = (100)/(25) = 4s`</body></html> | |
| 37909. |
The reading of centigrade thermometer coincides with that of Fahrenheit thermometer in a liquid. The temperature of the liquid is |
| Answer» <html><body><p>`-40^(@) <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`0^(@) C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>^(@) C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>^(@) C`</p>Answer :A</body></html> | |
| 37910. |
The ratio of the distance travelled in the third and fourth second by a particle moving over a straight path with constant acceleration is ...... |
| Answer» <html><body><p>`7/<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>`<br/>`5/7`<br/>`7/3`<br/>`3/7`</p>Solution :`S _(n) = 9/2 (<a href="https://interviewquestions.tuteehub.com/tag/2n-300431" style="font-weight:bold;" target="_blank" title="Click to know more about 2N">2N</a> -1)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> S _(3) = 9/2 (5)` <br/> `therefore S_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) = 9/2 (7)` <br/> `therefore (S_(3))/(S _(4)) = (5)/(7)`</body></html> | |
| 37911. |
Draw the stationary wave pattern in the fundamental mode for the following cases: (i) an open organ pipe (ii) resonance column apparatus (iii) a rigid metallic rod clamped in the middle, the rod is hit with a stick at one of its free ends . |
| Answer» <html><body><p></p>Solution :Fig. 4.24 (a) : Two antinodes at the two open <a href="https://interviewquestions.tuteehub.com/tag/ends-971392" style="font-weight:bold;" target="_blank" title="Click to know more about ENDS">ENDS</a> and a node between them .<br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)Fig . 4 . 24 (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) : An antinode at the open end and the nearest node at thetop of the liquid surface .<br/>(iii)fig . 4.24 (c) : twoantinodes at the free ends and only one node between them at the clamped mid-point.<br/>In Fig. 4 . 24 (a) and 4 . 24 (b) , it is to be notedthat sound waves are <a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a> longitudinal waves.For convenience only they have been drawn as trans-verse waves .<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U10_C04_E08_007_S01.png" width="80%"/></body></html> | |
| 37912. |
How is Physics related to society ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> (a) <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a></body></html> | |
| 37913. |
In an n type silicon, which of the following statements is true: |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_058_O01.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_058_O02.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_058_O03.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E05_058_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`v ^(2) =v _(0) ^(2) + <a href="https://interviewquestions.tuteehub.com/tag/2as-1836799" style="font-weight:bold;" target="_blank" title="Click to know more about 2AS">2AS</a> and v _(0) =0` <br/> `therefore v ^(2) = 2as` <br/> `thereforfe s to v` has <a href="https://interviewquestions.tuteehub.com/tag/parabola-1146268" style="font-weight:bold;" target="_blank" title="Click to know more about PARABOLA">PARABOLA</a> <a href="https://interviewquestions.tuteehub.com/tag/shape-1204673" style="font-weight:bold;" target="_blank" title="Click to know more about SHAPE">SHAPE</a>.</body></html> | |
| 37914. |
Two seconds after projection, a projectile is moving at 30^(@) above the horizontal. After one more second it is moving horizontally. If g = 10ms^(-2), the velocity of projection is |
| Answer» <html><body><p>`10sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/><a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> m/s <br/><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> m/s <br/>`20sqrt(3)` m/s</p>Answer :D</body></html> | |
| 37915. |
From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre ? |
| Answer» <html><body><p>`13MR^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)//<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a>`<br/>`11MR^(2)//32`<br/>`9MR^(2)//32`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> <a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(2)//32` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37916. |
A string of mass 2.50kg is under a tension of 200N. The length of the stretched string is 20.0m. If the transverse jerk is struck at one end of the string, how long does the disturbance take to reach the other end? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.5s</body></html> | |
| 37917. |
A player throws a ball upwards with an initial speed of 29.4 ms^(-1) (a) What is the direction of acceleration during the upward motion of the ball ? (b) What are the velocity and acceleration of the ball at the highest point of its motion ?(c) Choose the x = 0 m and t=0 s to be the location and time of the ball at its highest point vertically downward direction to be the positive direction of x-axis and give the signs of position, velocity and acceleration of the ball during its upward and downward motion. (d) To what height does the ball rise and after how long does the ball return to the player's hands ? (Take g = 9.8 ms^(-2) and neglect air resistance). |
| Answer» <html><body><p></p>Solution :(a) Vertically downwards, (b) <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> velocity, <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> of `9.8 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2)` downwards, (c ) `<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> gt 0` (upward and downward motion), `<a href="https://interviewquestions.tuteehub.com/tag/upsilon-3249910" style="font-weight:bold;" target="_blank" title="Click to know more about UPSILON">UPSILON</a> lt 0` (upward), `upsilon gt 0` (downward), `a gt 0` throughout, (d) 44.1 m, 6 s.</body></html> | |
| 37918. |
The stress- strain graphs for two materials A and B are shown in Fig. (The graphs are to the same scale). (i)Which of the materials has greater Young.s modulus ? (ii) Which of the two is the stronger material ? |
| Answer» <html><body><p></p>Solution : i) Young.s modulus= stress/strain = <a href="https://interviewquestions.tuteehub.com/tag/slope-15649" style="font-weight:bold;" target="_blank" title="Click to know more about SLOPE">SLOPE</a> of the straight portion of the stress-strain <a href="https://interviewquestions.tuteehub.com/tag/graph-17327" style="font-weight:bold;" target="_blank" title="Click to know more about GRAPH">GRAPH</a>. Since `<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a> theta_A gt tan theta_B` , slope of <a href="https://interviewquestions.tuteehub.com/tag/op-1136171" style="font-weight:bold;" target="_blank" title="Click to know more about OP">OP</a> > slope of `OP^1` . Y for material-A > Y for material B.<br/>ii) Strength of a material is determined by the highest point on the stress-strain curve. The stress corresponding to this point is called the ultimate strength `(S_u)`. Since this point(C) for material-B is higher than corresponding point`(C^1)`for material-A, `(S_u)_B gt (S_u)_A`.Hence, material B is stronger than material-A.</body></html> | |
| 37919. |
A train is moving along a straight line with a constant acceleration 'a' . A boy standing in the train throws a ball forward with a speed of 10 m//s , at an angle of 60(@) to the horizontal. The boy has to move forward by 1.15 minside the train to catch the ball back at the initial height . the acceleration of the train , in m//s^(2) , is |
| Answer» <html><body><p>3 m `s^(-2)` <br/>5 m `s^(-2)` <br/><a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> m `s^(-2)` <br/><a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> m `s^(-2)` </p>Solution :Here, `u=10ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>),theta=60^(@)` <br/> `:.u_(x)=ucostheta=10xxcos60^(@)=<a href="https://interviewquestions.tuteehub.com/tag/5ms-1900301" style="font-weight:bold;" target="_blank" title="Click to know more about 5MS">5MS</a>^(-1)` and `u_(y)=usintheta=10xxsin60^(@)=5sqrt3ms^(-1)` <br/> `:.t=(2u_(y))/(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)=(2xx5sqrt3)/(10)=sqrt(3)s` <br/> and `1.15=u_(x)t-(1)/(2)at^(2),` where a is the acceleration of train <br/> `1.15=5xxsqrt(3)-(1)/(2)xxaxx(sqrt(3))^(2)` <br/> `(3a)/(2)=5sqrt(3)-1.15=8.65-1.15-7.5` <br/> `a=7.5xx(2)/(3)=5ms^(-2)`</body></html> | |
| 37920. |
Calculate the stress developed inside a tooth cavity that filled with copper. When hot tea at temperature 57^(@)C is drunk. You can take body (tooth) temperature to be 37^(@)C and alpha = 1.7 xx 10^(-5//""^(@))C bulk modules for copper = 140 xx 10^(9) Nm^(–2). |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/thermal-706916" style="font-weight:bold;" target="_blank" title="Click to know more about THERMAL">THERMAL</a> stress = Kx strain = `(KDeltaV)/(V)` <br/> Now , `"" <a href="https://interviewquestions.tuteehub.com/tag/gamma-470142" style="font-weight:bold;" target="_blank" title="Click to know more about GAMMA">GAMMA</a>= (DeltaV)/(VDeltaT) or (DeltaV)/(V)=gammaDeltaT`<br/> Thermal stress `=K gamma DeltaT= <a href="https://interviewquestions.tuteehub.com/tag/3k-310983" style="font-weight:bold;" target="_blank" title="Click to know more about 3K">3K</a> alpha DeltaT "" [because gamma=3alpha]`<br/> `=3xx140xx10^(9)xx1.7xx10^(-5)xx20` <br/> `=1.428xx10^(8)Nm^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`</body></html> | |
| 37921. |
Is itpossibleif workis doneby theinternalforce, whatwillbe thechangein kineticenergy ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/yes-749457" style="font-weight:bold;" target="_blank" title="Click to know more about YES">YES</a> . Thispossibleif <a href="https://interviewquestions.tuteehub.com/tag/workis-1460077" style="font-weight:bold;" target="_blank" title="Click to know more about WORKIS">WORKIS</a> donebythe internalforcesthenkineticenergywillbeincreased.As <a href="https://interviewquestions.tuteehub.com/tag/anexample-875344" style="font-weight:bold;" target="_blank" title="Click to know more about ANEXAMPLE">ANEXAMPLE</a>, whena bombexplodes, thecombinedkineticemergy of <a href="https://interviewquestions.tuteehub.com/tag/allthe-2411782" style="font-weight:bold;" target="_blank" title="Click to know more about ALLTHE">ALLTHE</a> fragmentsis greaterthanthe initial energy.</body></html> | |
| 37922. |
The temperature of a solid object is observed to rise in a period. In this period . |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> is <a href="https://interviewquestions.tuteehub.com/tag/certainly-2506813" style="font-weight:bold;" target="_blank" title="Click to know more about CERTAINLY">CERTAINLY</a> supplied to it <br/>heat is certainly not supplied to it <br/>heat may have supplied to it <br/>work may have been done on it </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |
| 37923. |
Masses each 1 kg are placed at the verticies of an isosceles triangle ABC in which AC = BC = 5cm and AB = 8 cm. The distance of centre of mass of the system from the vertex C is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> cm<br/>1 cm<br/>1.5 cm<br/>3 cm</p>Answer :A</body></html> | |
| 37924. |
The Kundt's tube experiment shows that the sound waves are |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/longitudinal-2160200" style="font-weight:bold;" target="_blank" title="Click to know more about LONGITUDINAL">LONGITUDINAL</a> in nature<br/>Transverse in nature<br/>Electromagnetic waves<br/>Polarised waves</p>Answer :A</body></html> | |
| 37925. |
A ball moving with velocity 2m/s collides head on with another stationaryball of double the mass . If coefficient of restitution is 0.5 then their velocities after collision will be ………. ms^(-1) . |
| Answer» <html><body><p>0,1<br/>1,1<br/>`1,0.05`<br/>0,2</p>Solution :Coefficient of restitution ` e = (v_(1)^(.)-v_(2)^(.))/(v_(2)-v_(1))` <br/> ` :. 0.5 = (v_(2)-v_(1))/2 ` <br/> ` :. V_(2) = 1 + v_(1) ""………(1)` <br/> From conservation of momentum <br/> `mv_(1)+2mv_(2)=mv_(1)+2mv_(2),v_(1)=2m//s <a href="https://interviewquestions.tuteehub.com/tag/nd-576191" style="font-weight:bold;" target="_blank" title="Click to know more about ND">ND</a> v_(2) = 0 ` <br/> ` 2m = mv_(1) +2mv_(2) "".....(2)` <br/> From <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> (1) and (2) <br/> ` :. 2 = v_(1)+2(1+v_(1))` <br/> ` :. 2 =v_(1)+2+2v_(1)` <br/> ` :. 3v_(1)=0` <br/> ` :. v_(1)=0`<br/> From equation (1) `v_(2) =1 ` m/s .</body></html> | |
| 37926. |
A bus travels 6 km towards north at an angle of 45^(@)to the east and then travels 4 km towards north at an angle of 135^(@)to the east . How for is its final position , due east and due north ? How far is the point from the starting point ? What angle does the straight line joining its initial andfinal position makes with the east ? |
| Answer» <html><body><p></p>Solution :Net movement along x-direction (<a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> east)<br/>`= (6 - <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) cos 45^(@)`<br/>`= 2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> (1)/(sqrt(2)) = sqrt(2) km`<br/>Net movement along y-direction (due <a href="https://interviewquestions.tuteehub.com/tag/north-1124498" style="font-weight:bold;" target="_blank" title="Click to know more about NORTH">NORTH</a>)<br/>`= ( 6 + 4) sin 45^(@)`<br/>`= 10 xx (1)/(sqrt(2)) = 5 sqrt(2) km`<br/>Netmovement from starting point<br/>= 6 + 4 = 10 km<br/>Angle which makes with the east direction <br/>`<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a> theta = ("y-component")/("x-component") = (5 sqrt(2))/(sqrt(2))`<br/>`:. theta = tan^(-1) (5) `(or)<br/>`theta = 79^(@) `(approx).<br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C02_E02_255_S01.png" width="80%"/></body></html> | |
| 37927. |
Precise measurements of physical quantities are a need of science. For example, to ascertain the speed of an aircraft, one must have an accurate method to find its positions at closely separated instants of time. This was the actual motivation behind the discovery of radar in World War II. Think of different examples in modern science you can, give a quantitative idea of the precision needed. |
| Answer» <html><body><p></p>Solution :In modern science accurate measurement is necessary. For example in statellite <a href="https://interviewquestions.tuteehub.com/tag/launch-1069588" style="font-weight:bold;" target="_blank" title="Click to know more about LAUNCH">LAUNCH</a> system time of `1mus` accuracy is required. <br/> While dealing with LASER <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> (<a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a>) `1Å(1Å=<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-10)m)` measurement is required. <br/> Also in measurement of size of <a href="https://interviewquestions.tuteehub.com/tag/nucleus-18220" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEUS">NUCLEUS</a> accuracy of `10^(-15)m` is required. When mass of molecule is measured by using mass spectometer accuracy of `10^(-30)` kg is required.</body></html> | |
| 37928. |
The position of a particle moving along a straight line is given by x =2 - 5t + t ^(3). Find the acceleration of the particle at t =2 s. (x is metere). |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> (t) = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> - 5t + t ^(3)` is given, <br/> `therefore <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = (dx)/(dt) = (d)/(dt) [2- 5t +t ^(3)]` <br/> `therefore v =-5 + <a href="https://interviewquestions.tuteehub.com/tag/3t-311358" style="font-weight:bold;" target="_blank" title="Click to know more about 3T">3T</a> ^(2)` and <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> <br/> `a = (dv)/(dt) = (d)/(dt) [-5 + 3t ^(2) ] = 6t` acceleration at 2s, `a = 6 xx 2 =12 ms ^(-2)`</body></html> | |
| 37929. |
N. m^(-1) is the S.I unit of |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/spring-11487" style="font-weight:bold;" target="_blank" title="Click to know more about SPRING">SPRING</a> constant <br/>Surface <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> <br/>1,2 and <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> </p>Answer :D</body></html> | |
| 37930. |
A bullet of mass m strikes a pendulum bob of mass M with velocity u. It passes through and emerges out with a velocity u/2 from bob. The length of the pendulum is l. What should be the minimum value of u if the pendulum bob will swing through a complete circle? |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>)/mxxsqrt(5gl)`<br/>`M/(2m)<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(5gl)`<br/>`(2M)/mxx1/sqrt(5gl)`<br/>`M/(2m)xx1/sqrt(5gl)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37931. |
For the travelling harmonic wave y(x,t) = 2.0 cos 2 pi (10 t - 0.0080 x + 0.35) where x and y in cm and t in s. Calculate the phase difference between oscillatory motion of two points seperated by a distance of (a) 4 m, (b) 0.5 m, (c ) lamda//2, (d) 3lamda//4 |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) `6.4 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>` <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `0.8pi` rad (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ) `pi` rad (d) `(pi//2)` rad</body></html> | |
| 37932. |
(A) : When an object is placed between two plane parallel mirror, then all the images found are of un equal intensity. (R ): In case of plane parallel mirrors, only two images are possible. |
| Answer» <html><body><p>Both A and R are true and R is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of A<br/>Both A and R are true and R is not the correct explanation of A<br/>A is true and R is false<br/>Both A and R is false</p>Answer :C</body></html> | |
| 37933. |
Three particles each of mass.m. are located at the three vertices of an equilateral tirangle of side .a.. If the system is revolving in a uniform circle due to their mutual force of attraction, then the angular velocity of each particle is |
| Answer» <html><body><p>`sqrt((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(3a^(3)))`<br/>`sqrt((<a href="https://interviewquestions.tuteehub.com/tag/3gm-1863190" style="font-weight:bold;" target="_blank" title="Click to know more about 3GM">3GM</a>)/a^(3))`<br/>`sqrt((Gm^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(3a^(3)))`<br/>`sqrt((Gm^(2))/a^(3))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37934. |
When temperature of a body made of brass sincreases its moment of inertia. |
| Answer» <html><body><p>increase<br/>decrease<br/>remains same<br/>becomes zero</p>Answer :A</body></html> | |
| 37935. |
When some vehicle moves towards a stationary person, he finds difference in the frequency of horn by 2.5% of original frequency. If speed of sound is 320 m/s then, find speed of this vehicle. |
| Answer» <html><body><p>`8m//s`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/800-338448" style="font-weight:bold;" target="_blank" title="Click to know more about 800">800</a> m//s`<br/>`7m//s`<br/>`80m//s`</p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C15_E06_015_S01.png" width="80%"/> <br/> We have, `(f _(L))/( <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> + v _(L)) = (f _(S))/( v + v _(S))` <br/> Here if `f _(S) = <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> Hz,` then `f _(L) = 102.5 Hz` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> ( 102.5)/(320+0) = (100)/(320 -v _(S))` <br/> `therefore 320 -v _(S) = (32000)/(102.5)` <br/> `therefore 320 - (32000)/(102.5) =v _(S)` <br/> `therefore v _(S) = ((320 xx 102.5) - 32000)/(102.5)` <br/> `v _(S) = (800)/( 102.5) = 7.<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> (m)/(s) ~~ 8 (m)/(s)`</body></html> | |
| 37936. |
If bodies at a latitude of 45^@of the earth are to be weightless, what should be earth.s time period of rotation? |
| Answer» <html><body><p></p>Solution : The acceleration due to gravity at latitude `phi`is<br/>`g_phi =g - R omega^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> cos^2 phi`<br/>For bodies to be <a href="https://interviewquestions.tuteehub.com/tag/weightless-3272644" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHTLESS">WEIGHTLESS</a> at a latitude of`45^@` then “ `g_phi` ” must be zero.<br/>` rArr <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> = g - R omega^2 cos^2 45^@ rArr 0 = g - R omega^(2) 1/2 rArr R omega^2 = 2g rArr omega = sqrt((2g)/(R ))`<br/> We <a href="https://interviewquestions.tuteehub.com/tag/know-534065" style="font-weight:bold;" target="_blank" title="Click to know more about KNOW">KNOW</a> that , `omega = (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(T) rArr (2pi)/(T) = sqrt((2g)/(R ))rArr T = 2pi sqrt((R)/(2g)) " or " T = pi sqrt((2R)/(g))`</body></html> | |
| 37937. |
When a motor cyclist takes a U-turn in 4s what is the average angular velocity of the motor cyclist? |
| Answer» <html><body><p>0.7855<br/>0.7955<br/>0.8955<br/>0.9955</p>Answer :A</body></html> | |
| 37938. |
The surface energy of a liquid drop is E. It is sprayed into 1000 equal droplets. Then their surface energy is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a> E`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> E`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> E`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37939. |
(x^(2))/("mass") has the dimensions of kinetic energy. Then x has the dimensions of |
| Answer» <html><body><p>Pressure<br/>Torque<br/>Moment of Inertia<br/>Impulse</p>Answer :D</body></html> | |
| 37940. |
At t = 0, block B in figure starts moving with a velocity 15 cm/s and with a constant acceleration. It is observed that after blocks travels 24 cm to the right its velocity is 6cm/s. Find: (a) The accelerations of A and B, (b) The acceleration of point M of the string. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :[`1.33 m//s^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>), 2 cm//s^(2)` <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a>, (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `1.33 m//s^(2)` <a href="https://interviewquestions.tuteehub.com/tag/right-1188951" style="font-weight:bold;" target="_blank" title="Click to know more about RIGHT">RIGHT</a>]</body></html> | |
| 37941. |
Pick out the only vector quantity in the following list : Temperature , pressure impulse , time, power , total path length , energy , gravitational potential , coefficient of friction , charge . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/impulse-504956" style="font-weight:bold;" target="_blank" title="Click to know more about IMPULSE">IMPULSE</a></body></html> | |
| 37942. |
A circular disc is made to rotate in horizontal plane about its centre at the rate of 2 rps. The greatest distance of a coin placed on the disc from its centre so that it does not skid is (mu is coefficient of friction) |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a>)/(6.2)m`<br/>`6.2 mu <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`<br/>`(mu)/(6.2) cm`<br/>`(mu <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)/(6.2) cm`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37943. |
Choose the wrong option. |
| Answer» <html><body><p> Inertial <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> is a measure of difficulty of accelerating a body by an <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> force whereas the gravitational mass is <a href="https://interviewquestions.tuteehub.com/tag/relevant-613818" style="font-weight:bold;" target="_blank" title="Click to know more about RELEVANT">RELEVANT</a> in determining the gravitational force on it by an external mass <br/>That the gravitational mass and inertial mass are equal is an experimental result <br/>That the acceleration <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to gravity on the earth is the same for all bodies is due to the equality of gravitational mass and inertialmass<br/> Gravitational mass of a particle like proton can depend on the presence of neighbouringheavy <a href="https://interviewquestions.tuteehub.com/tag/objects-20533" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECTS">OBJECTS</a> but the inertial mass cannot </p>Answer :D</body></html> | |
| 37944. |
A wire stretched between two rigid supports vibrates in tits fndamental mode with a frequency of 45 Hz. The mass of the wire is 3.5 xx 10 ^(-2) kg andits inear mass density is 4.0 xx 10 ^(-2) kg m ^(-1). What is (a) the speed oa a transverse wave on the string, and (b) the tension in the string ? |
| Answer» <html><body><p></p>Solution :(a) Fundamental frequency of stationary wave, <br/> `f _(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = (<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2l-300409" style="font-weight:bold;" target="_blank" title="Click to know more about 2L">2L</a>) implies f _(1) =(v mu)/(2 xx M)` <br/> `(because mu = (M)/(L) implies L = (M)/(mu)) ` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> v =(2f _(1) M )/( mu) = (2 xx 45 xx 0.035)/(0.04) = 78.75 (m)/(s)` <br/> (b) Wave speed of transverse wave, <br/> `v = sqrt ((T)/(mu))` <br/> `therefore v ^(2) = (T)/(mu) implies T = muv ^(2)` <br/> `therefore T = (0.04) (78,75)^(2) = 248.1 N`</body></html> | |
| 37945. |
A thin but large plank of mass 2m is placed on a horizontal smooth surface. A solid cylinder of mass m and radius r is given only translation velocity V_(0) and gently placed on the plank as shown in the figure. The coefficient of kinetic friction between the plank and the cylinder is mu. Match List - I with List - II and selected the correct answer using the codes given below the lists : {:("List-I","List-II"),("(A) Final Kinetic energy of the plant",(P)(14mv_(0)^(2))/(98)),("(B) Final kinetic energy of the cylinder",(Q)(mv_(0)^(2))/(49)),("(C) Magnitude of work done by kinetic frictionally till the cylinder starts",(R)(24mv_(0)^(2))/(98)),("(D) Final kinetic energy of the cylinder with respect to the plank",(S)(33)/(98)mv_(0)^(2)):} |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A-Q;B-S;C-P;D-R</body></html> | |
| 37946. |
The dimensions of (l)/(KA) are (l is the length of rod, K is the thermal conductivity of rod and A is the area of cross-section of rod) |
| Answer» <html><body><p>`[ML^(2)T^(-3)<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>^(-1)]`<br/>`[M^(-1)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>^(-2)T^(3)K]`<br/>`[ML^(2)T^(-3)K^(-2)]`<br/>`[<a href="https://interviewquestions.tuteehub.com/tag/mlt-2163963" style="font-weight:bold;" target="_blank" title="Click to know more about MLT">MLT</a>^(-3)K^(-1)]`</p>Solution :Rate of heat flow `(<a href="https://interviewquestions.tuteehub.com/tag/dq-959213" style="font-weight:bold;" target="_blank" title="Click to know more about DQ">DQ</a>)/(dt)= (Kad theta)/(l)` <br/> or `(l)/(KA)= (d theta)/(dQ//dt) :. [(l)/(KA)]= [(K)/(ML^(2)T^(-3))]= [M^(-1)L^(-2)T^(3)K]`</body></html> | |
| 37947. |
A man can jump to a height of 1.5 m on a planet A . What is the height he may be able to jump on another planet whose density and radius are, respectively, one-quarter and one-third that of planet A |
| Answer» <html><body><p>1.5 m<br/>15 m<br/>18 m<br/>28m</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37948. |
A freely falling body travels _____ of total distance in 5th second |
| Answer» <html><body><p>0.08<br/>0.12<br/>0.25<br/>0.36</p>Answer :D</body></html> | |
| 37949. |
In Exercise 14.9, let us take the position of mass when the spring is unstreched as x = 0, and the direction from left to right as the positive direction of x-axis. Give x as a function of time t for the oscillating mass if at the moment we start the stopwatch (t = 0), the mass is (a) at the mean position, (b) at the maximum stretched position, and (c) at the maximum compressed position. In what way do these functions for SHM differ from each other, in frequency, in amplitude or the initial phase? |
| Answer» <html><body><p></p>Solution :(a) <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> 20t <br/> (b) x = 2 cos 20t <br/> (c) x = - 2 cos 20t <br/> where x is in cm. These functions differ <a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> in amplitude nor frequency. They differ in initial phase.</body></html> | |
| 37950. |
A piece of iron having a square cross-section has a length of 30 cm, and it floats on mercury at 0^(@)C. If the temperature is raised to 100^(@)C, then what additional length of the piece will be immersed? Density of mercury at 0^(@)C=13.6g*cm^(-3), density of iron at 0^(@)C=7.6 g*cm^(-3), coefficient of real expansion of mercury =1.82 times 10^(-4@)C^(-1) and coefficient of volume expansion of iron =3.51 times 10^(-5@)C^(-1). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.27 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a></body></html> | |