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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 38451. |
A missile is launched with a velocity less than the escape velocity. The sum of its kinetic and potential |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a><br/><a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a><br/>zero<br/>may be positive or negative <a href="https://interviewquestions.tuteehub.com/tag/depending-7263846" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDING">DEPENDING</a> on its <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> velocity</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38452. |
(a) A boy on a skateboard is sliding down on a smooth incline having inclination angle q. He throws a ball such that he catches it back after time T. With what velocity was the ball thrown by the boy relative to himself ? (b)Barrel of an anti aircraft gun is rotating in vertical plane (it is rotating up from the horizontal position towards vertical orientation in the plane of the fig). The length of the barrel is L = sqrt(2) m and barrel is rotating with angular velocity omega = 2 rad//s.At the instant angle theta is 45° a shell is fired with a velocity 2 sqrt(2) m//s with respect to the exit point of the barrel. The tank recoils with speed 4 m//s. What is the launch speed of the shell as seen from the ground? |
| Answer» <html><body><p><br/></p>Answer :(a) `(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)Tg <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta` Perpendicualr to the incline (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `4sqrt(2) <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`</body></html> | |
| 38453. |
The triple-point of water is a standard fixed point in modern thermometry. Why? What is wrong in taking the melting point of Ice and the bothing point of water as standard fixed points as was originally done in the Celsius scale) ? |
| Answer» <html><body><p></p>Solution :Triple - <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> has a <a href="https://interviewquestions.tuteehub.com/tag/unique-720618" style="font-weight:bold;" target="_blank" title="Click to know more about UNIQUE">UNIQUE</a> temperature, fusion point and <a href="https://interviewquestions.tuteehub.com/tag/boiling-17187" style="font-weight:bold;" target="_blank" title="Click to know more about BOILING">BOILING</a> point temperature <a href="https://interviewquestions.tuteehub.com/tag/depend-948478" style="font-weight:bold;" target="_blank" title="Click to know more about DEPEND">DEPEND</a> on pressure .</body></html> | |
| 38454. |
A polished metal with rough black spot on it is heated about 1400K and quickly taken to a dark room. Which of the following statements will be true ? |
| Answer» <html><body><p>The spot will appear brighter than the <a href="https://interviewquestions.tuteehub.com/tag/plate-1156364" style="font-weight:bold;" target="_blank" title="Click to know more about PLATE">PLATE</a> <br/>The spot will appear darker than the plate <br/>The spot and plate will be <a href="https://interviewquestions.tuteehub.com/tag/equally-2065515" style="font-weight:bold;" target="_blank" title="Click to know more about EQUALLY">EQUALLY</a> <a href="https://interviewquestions.tuteehub.com/tag/bright-391129" style="font-weight:bold;" target="_blank" title="Click to know more about BRIGHT">BRIGHT</a> <br/>The spot and plate will not be visible in <a href="https://interviewquestions.tuteehub.com/tag/dark-943775" style="font-weight:bold;" target="_blank" title="Click to know more about DARK">DARK</a> </p>Answer :A</body></html> | |
| 38455. |
A mass m is released from the top of a vertical circular track of radius r with a horizontal speed v_(theta). Calculate the angle theta with respect to the vertical where it leaves contact with the track. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/forces-16875" style="font-weight:bold;" target="_blank" title="Click to know more about FORCES">FORCES</a> acting on the body are its weight mg and <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> as shown in Fig. <br/> So for circular motion of the body at any position `theta` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP2_C06_SLV_031_S01.png" width="80%"/> `(mv^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(r)=mgcostheta-NorN=mgcostheta-(mv^(2))/(r)` <br/> The body will have contact where N = 0 <br/> i.e., mg `cos theta = (mv^(2))/(r) = 0` <br/> i.e, `cos theta = (v^(2))/(rg) "" .............(2)` <br/> Now applying conservationof mechanical energy between H and P, we get <br/> `(1)/(2)mv^(2)=(1)/(2)mv_(0)^(2)+<a href="https://interviewquestions.tuteehub.com/tag/mgr-2831250" style="font-weight:bold;" target="_blank" title="Click to know more about MGR">MGR</a>(1-costheta)` <br/> where .v. is the velocity at .P. <be> `[as y = r(1-cos theta)]` <br/> `or v^(2)=v_(0)^(2)+2gr(1-costheta).........(3)` <br/> substituting the value of `v^(2)` in Equation (2) <br/> `cos theta=(v_(0)^(2))/(rg)+2(1-costheta)` <br/> `i.e., cos theta=[(v_(0)^(2))/(3rg)+(2)/(3)]ortheta=cos^(-1)[(v_(0)^(2))/(3rg)+(2)/(3)]`</be></body></html> | |
| 38456. |
A bob executes shm of period 20 s. Its velocity is found to be 0.05 ms^(-1)after 2 s when it has passed through its mean position. Find the amplitude of the bob. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T = 20 s, v=0.05 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1), t=2 s` <br/> `omega = (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/T =2/20 pi = (pi)/10 rad//s` <br/> `v = aomega <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> omegat` <br/> `=0.05 = (api)/10 cos""(pi)/10 xx2 = (pia)/10 cos""pi/5` <br/> `0.05 = (pia)/10 xx0.809` <br/> `a= (0.05xx10)/(3.14 xx0.809)=0.197m`</body></html> | |
| 38457. |
A railway engine of mass 50 tons is pulling a wagon of mass 40 tons with a force of 4500N. The resistance force acting is 1N per ton. The tension in the coupling between the engine and the wagon is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1600-277322" style="font-weight:bold;" target="_blank" title="Click to know more about 1600">1600</a> <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/2000-289566" style="font-weight:bold;" target="_blank" title="Click to know more about 2000">2000</a> N<br/>200 N <br/>1500N</p>Solution :`F=ma, a=(F_("net"))/(m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)+m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))` <br/> For engine `F-f-T=m_(1)a`</body></html> | |
| 38458. |
The conceptof CMis applicable |
| Answer» <html><body><p>onlyfor rigidbodies <br/>onlyfor a systemof collection of particles <br/>for both , systemof collectionof particlesand rigidbodies . <br/>noneof the above ( here , <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> = centreof <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> ) </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38459. |
Using constraint equations find the relation between a_(1)"and" a_(2) |
| Answer» <html><body><p></p>Solution :Points <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>,2,3 and 4 are movable . Let their dis-placements from a fixed line be `x_(1),x_(2),x_(3) "and" x_(4)`<br/> `x_(1)+x_(3)=l_(1)`<br/> `(x_(1)-x_(3))+(x_(4)-x_(3))=l_(2)`<br/> `(x_(1)-x_(4))+(x_(2)-x_(4))=l_(3)`<br/> On double differentiating with respect to time , <br/> we will get following three constraint <a href="https://interviewquestions.tuteehub.com/tag/relations-15885" style="font-weight:bold;" target="_blank" title="Click to know more about RELATIONS">RELATIONS</a> :`a_(1)+a_(3)=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>`....(i)<br/>`a_(1)+a_(4)-2a_(3)=0`....(ii)<br/>`a_(1)+a_(2)-2a_(4)=0`....(iii)<br/> Solving Eqs. (i), (ii), and(iii) we get `a_(2)=-7a_(1)`<br/>Which is desired <a href="https://interviewquestions.tuteehub.com/tag/relation-1183220" style="font-weight:bold;" target="_blank" title="Click to know more about RELATION">RELATION</a> between `a_(1) "and" a_(2)`<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_A_C06_SLV_027_S01.png" width="80%"/></body></html> | |
| 38460. |
Force F is given by F=at+bt^(2). Where ''t'' is time. What are the dimensions of ''a'' and ''cb''? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/mlt-2163963" style="font-weight:bold;" target="_blank" title="Click to know more about MLT">MLT</a>^(-3)` and `MLT^(-4)`<br/>`MLT^(-1)` and `MLT^(0)`<br/>`MLT^(-3)` and `MLT^(4)`<br/>`MLT^(-4)` and `MLT`</p>Solution :`F= at + bt^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>According to principle of homogeneity , the <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> becomes, <br/> `MLT^2 = MLT^(-2) + MLT^(-2)` <br/>Comparing (1) and (2) , we get a `= MLT^(-3) , b= MLT^(-4)`</body></html> | |
| 38461. |
The total energy of a particle executing simple harmonic motion is: |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>`<br/>`prop x^2`<br/><a href="https://interviewquestions.tuteehub.com/tag/independent-505826" style="font-weight:bold;" target="_blank" title="Click to know more about INDEPENDENT">INDEPENDENT</a> of x <br/>`prop x^(1//2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38462. |
A particle of mass m performs SHM along a stright line with frequency f and amplitude A. |
| Answer» <html><body><p>The average kenetic energy of the particle is zero.<br/>The average potential energy is `m <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>^(2)f^(2)A^(2)`. <br/>The frequency of ocillation of kinetic energy is `2f`. <br/><a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> funciton <a href="https://interviewquestions.tuteehub.com/tag/leads-540453" style="font-weight:bold;" target="_blank" title="Click to know more about LEADS">LEADS</a> <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> by `pi//2`. </p>Answer :B::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38463. |
A new unit of length is chosen such that the speed of sound at room temperature is taken as unit. The sound of an explosion reaches a listener in 10s. Find the distance between the listener and the place where explosion took place. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> `=vt=1xx10=10` <a href="https://interviewquestions.tuteehub.com/tag/units-1438468" style="font-weight:bold;" target="_blank" title="Click to know more about UNITS">UNITS</a>.</body></html> | |
| 38464. |
A spring balance reads W_(1) when a ball is suspended from it. A weighing machine reads W_(2) when a tank of liquid is kept on it. When the ball is immersed in the liquid, the spring balance readsd W_(3) and the weighting machine reads W_(4). |
| Answer» <html><body><p>`W_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)ltW_(3)`<br/>`W_(1)ltW_(3)`<br/>`W_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)ltW_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`W_(2)gtW_(4)`</p>Answer :A::C</body></html> | |
| 38465. |
Due to higher specific heat of water compared to other solids and liquids |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> <a href="https://interviewquestions.tuteehub.com/tag/warms-3267385" style="font-weight:bold;" target="_blank" title="Click to know more about WARMS">WARMS</a> up <a href="https://interviewquestions.tuteehub.com/tag/quickly-610723" style="font-weight:bold;" target="_blank" title="Click to know more about QUICKLY">QUICKLY</a> but <a href="https://interviewquestions.tuteehub.com/tag/cools-933584" style="font-weight:bold;" target="_blank" title="Click to know more about COOLS">COOLS</a> down slowly<br/>water cools down quickly but warms up slowly<br/>water warms up or cools down slowly<br/>water warms up or cools down quickly</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38466. |
What is the work done in increasing the angular frequency of a circular ring of mass 2 kg and radius 25 cm from 10 rpm to 20 rpm about is axis ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done = Increase in <a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> `=(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)I(omega_(f)^(2)-omega_(i)^(2))=(1)/(2)MR^(2)(omega_(f)^(2)-omega_(i)^(2))`<br/>`= (1)/(2)xx2xx(0.25)^(2)(((<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(3))^(2)-((pi)/(3))^(2))=0.2058 J`</body></html> | |
| 38467. |
You are given total mass M. How do you divide it into two parts so that the gravitational force between them at a given distance is maximum |
| Answer» <html><body><p>`M/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>),(<a href="https://interviewquestions.tuteehub.com/tag/3m-310999" style="font-weight:bold;" target="_blank" title="Click to know more about 3M">3M</a>)/4` <br/>`M/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>),(<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>)/3` <br/>`M/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>),(4M)/5` <br/>`M/(2),(M)/2` </p>Answer :D</body></html> | |
| 38468. |
The escape velocity of a body on the earth.s surface is v_(e ). A body is thrown up with a speed of kv_(e) where k gt 1 . Assuming that the sun and planets do not influence the motion of the body, then the velocity of the body at the infinite distance in |
| Answer» <html><body><p>`(v_(e))/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-1))`<br/>`(v_(e))/(sqrt(k^(2)-1))`<br/>`v_(e )(k^(2)-1)`<br/>`(v_(e ))/(k-1)` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38469. |
The velocity of the image of a moving object in situation shown in figure is (given velocity w.r.t ground) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :We know for the perpendicular component <br/> `(vecV_(1//M))_(bot)=-(vecV_(o//M))_(bot)` <br/> `(V_(IG))_(bot)-(V_(<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>))_(bot)=-[(V_(<a href="https://interviewquestions.tuteehub.com/tag/og-583305" style="font-weight:bold;" target="_blank" title="Click to know more about OG">OG</a>))_(bot)-(V_(MG))_(bot)]` <br/> `(V_(MG))_(bot)= ((V_(OG))_(bot)+(V_(IG))_(bot))/2 <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> -30=(10+(V_(IG))_(bot))/2 implies` <br/> `(V_(IG))_(bot)=-70` <br/> THe parallel component of velocity of image is same as that of <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> w.r.t ground . It does not depend on the velocity of mirror. So `(V_(IG))_(II)=5m//s`</body></html> | |
| 38470. |
At what distance 'd' from the surface of asolid sphere of radius 'R', (a)potential is sme as at a distance (R)/(2) from the centre ? (b) field strengt is ame as at a distance (R)/(4) fromcentre. |
| Answer» <html><body><p><br/></p>Solution :(a) Given, `V_("outside") = V_("inside")` <br/> No Such <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> will <a href="https://interviewquestions.tuteehub.com/tag/exist-979486" style="font-weight:bold;" target="_blank" title="Click to know more about EXIST">EXIST</a>. Because potential at <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> is `(-1.5GM)/(R)`. Potential at surface is `(-<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(R)` <br/> and potential at infinity is zero . From centre to surface potential between `(-1.5GM)/(R)` <br/> and `(-GM)/(R)`. From surface to infinity potential varies between `(-GM)/(R)` and zero . <br/> Given, `E_("inside") = E_("outside")` <br/> `:. (GM)/(R^(3))(r_1) = (GM)/(r_(2)^(2))` <br/> Here, `r_(1)` and `r_(2)` are the distances from centre. <br/> `:. (GM)/(R^(3)) ((R)/(4)) = (GM)/((R+d)^(2))` <br/> Solving this <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> , WE get <br/> `d=R`.</body></html> | |
| 38471. |
Which of the following is an example of completely inelastic collision |
| Answer» <html><body><p>The collision between <a href="https://interviewquestions.tuteehub.com/tag/nuclei-1125994" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEI">NUCLEI</a> and <a href="https://interviewquestions.tuteehub.com/tag/fundamental-466867" style="font-weight:bold;" target="_blank" title="Click to know more about FUNDAMENTAL">FUNDAMENTAL</a> particles<br/>The collision between ivory (or) glass balls<br/>The collision between grossy bodies <br/> Collision between the bullet and <a href="https://interviewquestions.tuteehub.com/tag/target-25812" style="font-weight:bold;" target="_blank" title="Click to know more about TARGET">TARGET</a> when the bullet <a href="https://interviewquestions.tuteehub.com/tag/remains-621920" style="font-weight:bold;" target="_blank" title="Click to know more about REMAINS">REMAINS</a> embeded in the target</p>Answer :D</body></html> | |
| 38472. |
You lift a suitcase from the floor and keep it on a table. The work done by you on the suitcase does not depend on (a) the path taken by the suitcase (b) the time taken by you in doing so ( c) the weight of the suitcase (d) your weight |
| Answer» <html><body><p>a, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> & d are correct<br/>a, b & c are correct<br/>b, c & d are correct<br/>all are correct</p>Answer :A</body></html> | |
| 38473. |
The displacement vector of a mass m is given by r (t) = hati A cos omegat + hatj B sin omegat (a) Show that the trajectory is an ellipse (b) Show that F = - m omega^(2) r . |
| Answer» <html><body><p></p>Solution :Here (a) ` vec(r) (t) = <a href="https://interviewquestions.tuteehub.com/tag/hati-2693493" style="font-weight:bold;" target="_blank" title="Click to know more about HATI">HATI</a> A cos omegat + hatj B sin omegat, :. x = A cos omegat, y = B sin omegat ` <br/> ` x^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(A^(2)) + y^(2)/(B^(2)) cos^(2) omegat + sin^(2) omegat = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>` which is the equation of an <a href="https://interviewquestions.tuteehub.com/tag/ellipse-450431" style="font-weight:bold;" target="_blank" title="Click to know more about ELLIPSE">ELLIPSE</a> <br/> `:.` The trajectory of the particle is elliptical <br/> (b) Now ` vec(upsilon) =vec(dr)/(dt) = -hatiomega A sin omegat + hatjomega Bcos omegat ` <br/> ` vec(a) = vec (d upsilon)/(dt) = hati omega^(2) A cos omegat - hatj omega^(2) B sin omegat = - omega^(2) [hati A cos omegat + hatjBsin omegat] = - omega^(2) vec(r) ` <br/> ` vec(F) = m vec (a) = - m omega^(2) vec(r) ` .</body></html> | |
| 38474. |
A body is projected with an initial Velocity 20 m/s at 60° to the horizontal. Its initial velocity vector is- (g=10 m//s^2) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10i-1773781" style="font-weight:bold;" target="_blank" title="Click to know more about 10I">10I</a> - 20 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`10sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)I + <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> j`<br/>`10 I + 10sqrt(3)j`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/5i-326324" style="font-weight:bold;" target="_blank" title="Click to know more about 5I">5I</a> + 5sqrt(3) j`</p>Answer :C</body></html> | |
| 38475. |
stateprevosttheoryof heatexchnage. |
| Answer» <html><body><p></p>Solution :Prevost theory <a href="https://interviewquestions.tuteehub.com/tag/states-1225920" style="font-weight:bold;" target="_blank" title="Click to know more about STATES">STATES</a> that all <a href="https://interviewquestions.tuteehub.com/tag/bodies-900171" style="font-weight:bold;" target="_blank" title="Click to know more about BODIES">BODIES</a> emit thermal radiation at all <a href="https://interviewquestions.tuteehub.com/tag/temperatures-1241229" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURES">TEMPERATURES</a> above absolute zero irrespective of the <a href="https://interviewquestions.tuteehub.com/tag/nature-1112013" style="font-weight:bold;" target="_blank" title="Click to know more about NATURE">NATURE</a> of the <a href="https://interviewquestions.tuteehub.com/tag/surroundings-1235986" style="font-weight:bold;" target="_blank" title="Click to know more about SURROUNDINGS">SURROUNDINGS</a>.</body></html> | |
| 38476. |
What are the conditions in which force can not produce torque ? |
| Answer» <html><body><p></p>Solution :The torque is zero with `vecr` and `vecF` are parallel or antiparallel. If parallel then `theta=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>^(@)` and `<a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> 0^(@)=0`. If antiparallel, then `theta=180^(@)` and `sin 180^(@)=0`. Hence `tau=0` <br/> The torque is zero if the force <a href="https://interviewquestions.tuteehub.com/tag/acts-848461" style="font-weight:bold;" target="_blank" title="Click to know more about ACTS">ACTS</a> at the reference point. i.e. as `vecr=0, tau=0`.</body></html> | |
| 38477. |
An electron starting from rest has a velocity that increases linearly with the time that is v=kt,where k=2 m//sec^(2).The distance travelled in the first 3 seconds will be |
| Answer» <html><body><p>9m<br/>16m<br/>27m<br/>36m</p>Answer :A</body></html> | |
| 38478. |
The Young's modulus for a perfect rigid body is: |
| Answer» <html><body><p>0<br/>1<br/>0.5<br/>infinity</p>Answer :D</body></html> | |
| 38479. |
The two gases are seperated by a fixed diathermic wall, with initial states as (P_(A), V_(A)) and (P_(b), V_(B)) |
| Answer» <html><body><p>The thermodynamics states of A and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> will not change with time <br/>There will be a flow of energy between the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> systems until the equilibrium is attained<br/>The states of the two systems will change until the equilibrium will change until the equilibrium is attained <br/>Both <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> and <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> are correct</p>Answer :D</body></html> | |
| 38480. |
Masses 8, 2, 4, 2 kg are placed at the corners A, B, C, D respectively of a square ABCD of diagonal 80 cm. The distance of centre of mass from A is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> cm <br/><a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a> cm <br/><a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> cm <br/>60 cm </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38481. |
If wavelengths of maximum intensity of radiations emitted by the sun and the moon are 05.xx 10^(-6) m and 10^(-4) m respectively, the ratio of their temperatures is |
| Answer» <html><body><p>`1//100`<br/>`1//200`<br/>100<br/>200</p>Answer :D</body></html> | |
| 38482. |
What are heat rays ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Infrared rays are <a href="https://interviewquestions.tuteehub.com/tag/called-907796" style="font-weight:bold;" target="_blank" title="Click to know more about CALLED">CALLED</a> heat rays, because these rays <a href="https://interviewquestions.tuteehub.com/tag/give-468520" style="font-weight:bold;" target="_blank" title="Click to know more about GIVE">GIVE</a> heat.</body></html> | |
| 38483. |
At what common temperature would a block of wood and a block of metal feel equally cold or equally hot when touched with? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :This will <a href="https://interviewquestions.tuteehub.com/tag/happen-1015459" style="font-weight:bold;" target="_blank" title="Click to know more about HAPPEN">HAPPEN</a> when both the blocks are at the temperature of the body in case when either of blocks is touched , there will be no <a href="https://interviewquestions.tuteehub.com/tag/transfer-1425652" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSFER">TRANSFER</a> of heat from the block to the body (human) or vice <a href="https://interviewquestions.tuteehub.com/tag/versa-1444865" style="font-weight:bold;" target="_blank" title="Click to know more about VERSA">VERSA</a> .So ,on touching they will be filled equally <a href="https://interviewquestions.tuteehub.com/tag/hot-1029680" style="font-weight:bold;" target="_blank" title="Click to know more about HOT">HOT</a> aur equally cold.</body></html> | |
| 38484. |
Write down the equation of a freely falling body under gravity. |
| Answer» <html><body><p></p>Solution :(i) Distanced traveled by an object falling for time .t., u = 0 , s = d , a = g<br/> `s = ut + 1/2 at^2` <br/> ` therefore = 1/2 "<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a>"^2` <br/>Time .t. <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> for an object to <a href="https://interviewquestions.tuteehub.com/tag/fail-982965" style="font-weight:bold;" target="_blank" title="Click to know more about FAIL">FAIL</a> distance .d.. <br/>` t = sqrt((2d)/(g))` <br/>Instantaneous <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> `v_i`of a falling object after elapsed time .t.<br/> ` v_i = sqrt(2gd)` <br/>Instantaneous velocity `v_i`of a falling object that has traveled distance .d.<br/>` v_i = sqrt(2gd)` <br/>(ii) ` u = - 19.6 ms^(-1)` <br/> `u = 9.8 ms^(-2)` <br/> t = 6 sec <br/> height of the building <br/> ` s = ut + 1/2 at^2` <br/> ` = (-19.6 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 6) + 1/2 (9.8)(6)^2 = - 117.6 + 176.4` <br/> s = 58.8 m</body></html> | |
| 38485. |
A wire whose cross-sectional area is 4 mm^2is stretched by 0.1 mm by a certain load. If a similar wire of double the area of cross section is under the same load, then the elongation would be |
| Answer» <html><body><p>0.<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a> <br/>0.05 mm <br/>0.005 mm <br/>5 mm </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 38486. |
In which case, weight of body will be maximum (i) in air (ii) vacuum (iii) in water |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :A <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> will <a href="https://interviewquestions.tuteehub.com/tag/weigh-734298" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGH">WEIGH</a> <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> in <a href="https://interviewquestions.tuteehub.com/tag/vacuum-1442069" style="font-weight:bold;" target="_blank" title="Click to know more about VACUUM">VACUUM</a>.</body></html> | |
| 38487. |
A stone is dropped from a height of 10cm above the top of a window 80 cm high.the time taken by the stone to cross the window is (g=9.8 ms^(-2)) |
| Answer» <html><body><p>`1/7s`<br/>`3/7s`<br/>`2/7s`<br/>`4/7s`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38488. |
An infinite number of particles each of mass m are placed on the positive x-axis at 1m, 2m, 4m, 8m,…. from the origin. The magnitude of the resultant gravitational force on mass 'm' kept at the origin is |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_SLV_015_S01.png" width="80%"/> <br/> The resultant gravitational <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> <br/> `F = (Gm^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) + (Gm^(2))/(4) + (Gm^(2))/(16)+…..` <br/> `= Gm^(2)((1)/(1)+(1)/(4)+(1)/(16)+….) = Gm^(2)((1)/(1-(1)/(4)))` <br/> (`because` sum of the <a href="https://interviewquestions.tuteehub.com/tag/infinit-2737095" style="font-weight:bold;" target="_blank" title="Click to know more about INFINIT">INFINIT</a> <a href="https://interviewquestions.tuteehub.com/tag/trms-3834233" style="font-weight:bold;" target="_blank" title="Click to know more about TRMS">TRMS</a> in G.P is `S_(prop) = (a)/(1-r)`) <br/> `= (4)/(3)Gm^(2)`</body></html> | |
| 38489. |
Two parallel rail tracks run north-south. Train A moves north with a speed of 54 km h^(-1), and train B moves south with a speed of 90 km h^(-1). What is the (a) velocity of B with respect to A ?, (b) velocity of ground with respect to B ?, and (c) velocity of a monkey running on the roof of the train A against its motion (with a velocity of 18 km h^(-1) with respect to the train A) as observed by a man standing on the ground ? |
| Answer» <html><body><p></p>Solution :Choose the positive direction of x-axis to be from <a href="https://interviewquestions.tuteehub.com/tag/south-1219419" style="font-weight:bold;" target="_blank" title="Click to know more about SOUTH">SOUTH</a> to north. Then,<br/>`upsilon_(A)=+54 km h^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = 15 ms^(-1)`<br/>`upsilon_(B)=-90 km h^(-1)=-25 ms^(-1)`<br/>Relative velocity of B with respect to `A=upsilon_(B)-upsilon_(A)=-<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> ms^(-1)`, i.e. the <a href="https://interviewquestions.tuteehub.com/tag/train-1425202" style="font-weight:bold;" target="_blank" title="Click to know more about TRAIN">TRAIN</a> B appears to A to move with a speed of 40 m s–1 from north to south. <br/>Relative velocity of ground with respect to<br/>`B=0-upsilon_(B)=25 ms^(-1)`.<br/>In (c), let the velocity of the monkey with respect to ground be `upsilon_(M)`. Relative velocity of the monkey with respect to A,<br/>`upsilon_(MA)=upsilon_(M)-upsilon_(A)=-18 km h^(-1)=-5 ms^(-1)`. Therefore, `upsilon_(M)=(15-5)ms^(-1)=<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ms^(-1)`.</body></html> | |
| 38490. |
A uniform cylinder of height h and radius r is placed with its circular face on a rough inclined plane and the inclination of the plane to the horizontal gradually in creased. If mu is the coefficeint of friction, then under what conditions the cylinder will (a) slide before topping (b) topple before sliding |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C07_SLV_031_S01.png" width="80%"/><br/>(a) The Cylinder will slide if<br/>`Mg <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta gt mu Mg cos theta rArr tan theta gt mu` …..(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)<br/>the cylinder will topple if<br/>`(Mg sin theta) (h)/(2)gt (M <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> cos theta) r rArr tan theta gt (2r)/(h)` ...(2)<br/>Thus, the condition of sliding is `tan theta gt mu` and condition of toppling `tan theta gt (2r)/(h)`. Hence, the cylinder will slide before toppling if `mu <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> (2r)/(h)`<br/>(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) The cylinder will topple before sliding if `mu gt (2r)/(h)`</body></html> | |
| 38491. |
Two balls of equal masses are thrown at the same time in vacuum. While they are in vacuum, the acceleration of their centre of mass |
| Answer» <html><body><p>depends on <a href="https://interviewquestions.tuteehub.com/tag/masses-1088822" style="font-weight:bold;" target="_blank" title="Click to know more about MASSES">MASSES</a> of the balls <br/>depends on direction of <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> of the balls <br/>depends on speeds of the balls <br/>is equal to acceleration due to <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38492. |
A particle is fastened at the end of a string and is whirled in a vertical circle with the other end of the string being fixed. The motion of the particle is |
| Answer» <html><body><p>Periodic<br/>oscillatory<br/><a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> harmonic<br/>angular simple harmonic</p>Answer :A</body></html> | |
| 38493. |
A particle moves along a circle with uniform acceleration. Workdone by the resultant force acting on that particle |
| Answer» <html><body><p>is <a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a> zero<br/>may be zero<br/>is not <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to zero<br/>is infinity</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38494. |
Weighing the earth : Youare given the following data : g =9.81 ms^(-2).R_(E)= 6.37 xx10^(6) m, the distance to the moon R = 3.84xx10^(8)m and the time period of the moons revolution is 27 .3 days . Obtain the mass of the earth M_E in two different ways. |
| Answer» <html><body><p></p>Solution :We know that <br/> `M_E=(gR_E^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/G=(9.81 xx(6.37xx10^(6))^2)/(6.67 xx10^(-11))=5.97xx10^(24)kg`<br/> The moon is a <a href="https://interviewquestions.tuteehub.com/tag/satellite-1195060" style="font-weight:bold;" target="_blank" title="Click to know more about SATELLITE">SATELLITE</a> of the <a href="https://interviewquestions.tuteehub.com/tag/earth-13129" style="font-weight:bold;" target="_blank" title="Click to know more about EARTH">EARTH</a>. According to Kepler.s Third law <br/> `T^(2) = (<a href="https://interviewquestions.tuteehub.com/tag/4pi-1882352" style="font-weight:bold;" target="_blank" title="Click to know more about 4PI">4PI</a>^2R^3)/(GM_E) M_(E) =(4pi^(2)R^3)/(GT^2)` <br/> `= (4xx3.14 xx3.14 xx(3.84)^3xx10^(24))/(6.67xx10^(-11) xx(27.3xx24xx60xx60)^(2))=6.02xx10^(24)` kg <br/> Both methods yields almost the same answer , the difference between them being less than <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>% .</body></html> | |
| 38495. |
Should the centre of mass of a body necessarily lie inside the body ? |
| Answer» <html><body><p></p>Solution :No, example the centre of mass of a <a href="https://interviewquestions.tuteehub.com/tag/ring-1189545" style="font-weight:bold;" target="_blank" title="Click to know more about RING">RING</a> <a href="https://interviewquestions.tuteehub.com/tag/lies-1073086" style="font-weight:bold;" target="_blank" title="Click to know more about LIES">LIES</a> in its <a href="https://interviewquestions.tuteehub.com/tag/hollow-1028416" style="font-weight:bold;" target="_blank" title="Click to know more about HOLLOW">HOLLOW</a> <a href="https://interviewquestions.tuteehub.com/tag/portion-1159785" style="font-weight:bold;" target="_blank" title="Click to know more about PORTION">PORTION</a>.</body></html> | |
| 38496. |
(A): The path followed by one projectile as observed by another projectile is a straight line in uniform gravitation field. (R) : The relative velocity between two projectiles at a given place doesn't change with time. Because their relative acceleration is zero. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>(A) is false but (R) is true </p>Answer :A</body></html> | |
| 38497. |
The greatest height to which a man can throw a stone is h. What will be the greatest distance upto which he can throw the stone? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Maximum height: <br/> `H=(<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>^(2)sin^(2)<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>)/(g)impliesH_(max)=(u^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>)=h(at""theta=90^(@))` <br/> Maximum range `R_(max)=(u^(2))/(g)=<a href="https://interviewquestions.tuteehub.com/tag/2h-300377" style="font-weight:bold;" target="_blank" title="Click to know more about 2H">2H</a>`</body></html> | |
| 38498. |
A ball is projected vertically upward with speed v. another ball of the same mass is projected at an angle of 60^(@) with the vertical with the same speed. The ratio of their potential energy at the highest point is: |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></body></html> | |
| 38499. |
Efficiency of a heat engine whose sink is at temperature of 300 K is 40% . To increase the efficiency to 60 % keeping the sink temperature same, the source temperature must be increased by |
| Answer» <html><body><p></p>Solution :`(T_(2))/(T_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))=1-eta=1-(40)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)=(3)/(5)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> T_(1)=(5)/(3)T_(2) rArr T_(1)=(5)/(3)xx300=500K` <br/> New efficiency `eta=60%` <br/> `(T_(2))/(T_(1))=1-eta=1-(60)/(100)=(2)/(5)""T_(1)=(5)/(2)xx300=750K`, <br/> `DeltaT=750-500=250K`</body></html> | |
| 38500. |
A rope is wound around a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceleration of the cylinder if the rope is pulled with a force of 30 N ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> m//s^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> m//s^(2)` <br/>`0.25 rad//s^(2)` <br/>`25 rad//s^(2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |