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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 38401. |
Explain the horizontal oscillations of a spring. |
| Answer» <html><body><p></p>Solution :`(i)` Let `'m'` be the mass of a block attached to a mass less spring <br/> `(ii) '<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>'` be the stiffness <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> or force constant or spring constant of the spring. <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) 'x_(0)'` be the mean or equilibrium position of the block. <br/> `(iv) 'x'` be the small displacement of the block towards right, and the released. <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)` The block will oscillate back and forth about `x_(0)` <br/> `(vi)` If `F` be the restoring force, then it is proportional to the `'x'` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_QP_MAR_19_E04_008_S01.png" width="80%"/> <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_QP_MAR_19_E04_008_S02.png" width="80%"/> <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_QP_MAR_19_E04_008_S03.png" width="80%"/> <br/> `F prop x` <br/> `F=-kx` <br/> `m(d^(2)x)/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>^(2))=-kx` <br/> `(d^(2)x)/(dt^(2))=-(k)/(m)x` <br/> `omega^(2)=(k)/(m)` <br/> `omega=sqrt((k)/(m))rads^(-1)` <br/> `f=(omega)/(2pi)=(1)/(2pi)hertz` <br/> `T=(1)/(f)=2pisqrt((m)/(k))` second</body></html> | |
| 38402. |
The horizontal distance x and the vertical height y of a projectile at time t are given by x = a tandy = bt^(2)+ct wherea, b and c are constants. Then |
| Answer» <html><body><p>The speed of the projectile 1 second after it is fired is `(a^(2)+b^(2)+<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>^(2))^(1//2)`<br/>The angle with the horizontal at which the projectile is fired is `tan^(-1)(c//a)`<br/>The <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> due to gravity is `-<a href="https://interviewquestions.tuteehub.com/tag/2b-300274" style="font-weight:bold;" target="_blank" title="Click to know more about 2B">2B</a>`<br/>The <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> speed of the projectile is `(a^(2)+c^(2))^(1//2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B::C::D</body></html> | |
| 38403. |
In thermal steady state of rod, temperature gradient is 5^(@) C/cm and temperature of its hot end is 100^(@)C, then at. . . . . . cm distance from hot end its temperature becomes 60^(@)C. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>=(T)/(dT//dx)=(<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)=<a href="https://interviewquestions.tuteehub.com/tag/8cm-340152" style="font-weight:bold;" target="_blank" title="Click to know more about 8CM">8CM</a>`</body></html> | |
| 38404. |
The number of revolutions made by a flywheel change from 300 rpm to 1500 rpm in 10 s. Calculate angular acceleration assuming it to be uniform. Also calculate the number of revoluations made during the time. |
| Answer» <html><body><p><br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> = omega - omega_(0)//t = <a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> (25-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)//10 - 4pi rad//s^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>), theta = 2pi xx 5 xx 10 +(1//2) xx 4pi xx 10^(2) = 300 pi, n = 150` <a href="https://interviewquestions.tuteehub.com/tag/rev-1188006" style="font-weight:bold;" target="_blank" title="Click to know more about REV">REV</a>.</body></html> | |
| 38405. |
Assertion : When two tuning forks are vibrating with frequencies 256 Hz and 480 Hz are held near each other, beats cannot be heard. Reason : The principle of super position is valid if the frequencies of the oscillators are nearly equal. |
| Answer» <html><body><p>Both assertion and <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> are true and reason is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of the assertion <br/>Both assertion and reason are true and reason is notthe correct explanation of the assertion <br/>Both assertion and reason are false <br/>Assertion is true and reason is false </p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/beats-14673" style="font-weight:bold;" target="_blank" title="Click to know more about BEATS">BEATS</a> can be heard only if the difference in the frequecies of two <a href="https://interviewquestions.tuteehub.com/tag/source-1219297" style="font-weight:bold;" target="_blank" title="Click to know more about SOURCE">SOURCE</a> do not <a href="https://interviewquestions.tuteehub.com/tag/exceed-978351" style="font-weight:bold;" target="_blank" title="Click to know more about EXCEED">EXCEED</a> 10 Hz.</body></html> | |
| 38406. |
A rigid mass less rod of length L is rotating in a vertical plane about a horizontal axis passing through one of its ends. At the other end of the rod there is a mass less metal plate welded to the rod. This plate supports a heavy small bead that can slide on the rod without friction. Just above the bead there is another identical metal plate welded to the rod. The bead remains confined between the plates. The gap between the plates is negligible compared to L. The angular speed of the rod when the bead is at lowest position of the circle is omega=2sqrt(g/L). How many times a clink ofthe bead hitting a metal plate is heard during one full rotation of the rod ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 38407. |
A couple produces ________ motion. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pure-1172806" style="font-weight:bold;" target="_blank" title="Click to know more about PURE">PURE</a> <a href="https://interviewquestions.tuteehub.com/tag/linear-1074458" style="font-weight:bold;" target="_blank" title="Click to know more about LINEAR">LINEAR</a> motion<br/>pure <a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> motion<br/>no motion<br/>both linear and rotational motion</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38408. |
The speed of sound in oxygen (O_(2)) at a certain temp is 460 ms^(-1) the speed of sound in helium at the same temperature will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/460-317760" style="font-weight:bold;" target="_blank" title="Click to know more about 460">460</a> <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`500 ms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/650-331163" style="font-weight:bold;" target="_blank" title="Click to know more about 650">650</a> ms^(-1)`<br/>`1420 ms^(-1)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38409. |
An artifical satellite is moving in a circularorbit around the earth with a speed equal to half gthe magnitude of the escape velocity from the earth. IF the satellite is sloppedsuddenly is its orbit and allowed to fall freely, on to the earth. Find the speed (in kmps) with which it hits the surface of the earth (g = 10/sec^(2) and R= 6400 km) |
| Answer» <html><body><p>4<br/>8<br/>5<br/>11</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38410. |
10 gm of ice at -10^(@)C is mixed with 100 gm of water at 50^(@)C contained in a calorimeter weighing 50 gm. (Specific heat of water = 1"cal".gm^(-1).""^(@)C^(-1), Latent heat of ice = 80cal/gm, specific heat of ice = 0.5"cal"//gm//""^(@)C and specific heat of copper = 0.09"cal"//gm//""^(@)C). The final temperature reached by the mixtures is |
| Answer» <html><body><p>`25.5^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`30.0^(@)C`<br/>`38.2^(@)C`<br/>`40.0^(@)C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 38411. |
A particle of mass m_(1) is projected to the right with speed v_(1) onto a smooth wedge of mass m_(2) which is simulateoulsy projected due the left with a speed v_(2). If the particle attains the highest point of the wedge, find h. |
| Answer» <html><body><p></p>Solution :Applying work energy <a href="https://interviewquestions.tuteehub.com/tag/theorem-706777" style="font-weight:bold;" target="_blank" title="Click to know more about THEOREM">THEOREM</a> <br/> `W_("<a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a>")=/_\K_("blocks",cm)+/_\K_(cm)` <br/> As no external forces <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a>, the velocity of centre of mass will be constant. Hence `/_\K_(cm)=0` <br/> Hence `W_("total")=/_\K_("blocks",cm)` <br/> `W_("gravity")=[1/2muv_(rel)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)]_("final")-[1/2muv_(rel)^(2)]_("initial")` <br/> `-m_(1)gh0-1/2((m_(1)m_(2))/(m_(1)+m_(2)))(v_(1)+v_(2))^(2)` <br/> `-m_(1)gh=-1/2((m_(1)m_(2))/(m_(1)+m_(2)))(v_(1)+v_(2))^(2)` <br/> `h=1/2(m_(2)(v_(1)+v_(2))^(2))/(g(m_(1)+m_(2)))`</body></html> | |
| 38412. |
We usually say thattime moves in forward direction', but time is not a vector quantity . Why ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :does notobey <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> <a href="https://interviewquestions.tuteehub.com/tag/algebra-19699" style="font-weight:bold;" target="_blank" title="Click to know more about ALGEBRA">ALGEBRA</a></body></html> | |
| 38413. |
In a molecule of sodium chloride, the masses of sodium and chlorine atoms are in the ratio 23 : 36. If the separation between the two atoms is d., distance of centre of mass of the molecule from sodium atom |
| Answer» <html><body><p>36d/59<br/>23d/59<br/>59/23<br/>59/36</p>Answer :A</body></html> | |
| 38414. |
The M.I. of a body is 1.2 kg m^(2). Initially the body is at rest. In order to produce a rotational kinetic energy of 1500 J an angular acceleration of 25 rad s^(-2) must be applied about the axis for a duration of |
| Answer» <html><body><p>2s<br/>4s<br/>8s<br/>10s</p>Answer :A</body></html> | |
| 38415. |
For a certain mass of gas Isothermal relations between 'P' and 'V' are shown by graphs at two different teperature T_(1) and T_(2) then |
| Answer» <html><body><p>`T_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = T_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`T_(1) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> T_(2)`<br/>`T_(1) lt T_(2)`<br/>`T_(1) <a href="https://interviewquestions.tuteehub.com/tag/ge-1003146" style="font-weight:bold;" target="_blank" title="Click to know more about GE">GE</a> T_(2)`</p>Answer :C</body></html> | |
| 38416. |
A body of mass 2 kg starts from rest and moves with uniform acceleration. It acquires a velocity 20 m/s in 4 s. The power exerted on the body in 2 s in Watt is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> W`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> W`<br/>`250W`<br/>`200 W`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38417. |
A 10 kg object collides with a stationary 5 kg object and after collision, they stick together and move forward with velocity 4 ms^(-1). What is the velocity with which the 10 kg object hits the second one ? |
| Answer» <html><body><p>`4 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> ms^(-1)`<br/>`10 ms^(-1)`<br/>`12ms^(-1)`</p>Solution :Here `m_1 = 10 kg, m_2 = <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> kg, u_1 = ? , u_2 = 0, <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = 4 m//s` <br/> Applying the principle of conservation of linear momentum, <br/> `m_1u_1 + m_2u_2 = (m_1 + m_2)v , 10 u_1+ 5 xx 0 = (10 + 5) 4` <br/> `10 u_1 = 60 " or " u_1 = 60/10 = 6 ms^(-1)`.</body></html> | |
| 38418. |
A wheel of grindstone has applied at its axle 2 cm in radius a constant tangential force of 600 N. Find the change in angular momentum acquired after 8 s and also the torque acting |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/tau-663951" style="font-weight:bold;" target="_blank" title="Click to know more about TAU">TAU</a>=rF=0.02 xx 600 = <a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> Nm, dL = tau xx dt = 12 xx 8 = <a href="https://interviewquestions.tuteehub.com/tag/96-342541" style="font-weight:bold;" target="_blank" title="Click to know more about 96">96</a> J-s`</body></html> | |
| 38419. |
A spherical steel ball released at the topp of a long column of glycerine of length l falls through a distance l//2 with accelerated motion and the remaining distance l//2 with uniform velocity V. Let t_(1) and t_(2) denote the times taken to cover the first and second half and W_(1) and W_(2) the work done agaist gravity in the two halves, then compare times and work done. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> in the first half of the distance `ltv`, while in the second half the average velocity is v. There fore, `t_(1s)gtt_(2)`. The workdone against gravity in both halves is `<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> l//2` <br/> `:.t_(1s)gt_(2)""w_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=w_(2)`</body></html> | |
| 38420. |
A body is droped from a height 122.5 m. If its stopped after 3 seconds and again released the further time of descent is (g=9.8m//s^(2)) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> s<br/>3 s<br/>4 s<br/>5 s</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38421. |
The mass of a planet is half that of the earth and the radius of planet is one fourth that of the earth. If we plan to send an artificial satellite from the planet, the escape velocity will be nearly (V_(e) of earth is 11 kms^(-1)) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a> <a href="https://interviewquestions.tuteehub.com/tag/kms-1064571" style="font-weight:bold;" target="_blank" title="Click to know more about KMS">KMS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`5.5 kms^(-1)`<br/>`15.5 kms^(-1)`<br/>`7.7 kms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38422. |
ML^(2) T^(-2)I^(-2) is the dimensional formula for |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/self-1199734" style="font-weight:bold;" target="_blank" title="Click to know more about SELF">SELF</a> inductance<br/>Magnetic induction<br/>Magnetic moment<br/>Electric conductance</p>Answer :A</body></html> | |
| 38423. |
During a projectile motion if the maximum height equals the horizontal range,then the angle of projection with the horizontal is : |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>^(-1) (1)` <br/>`tan^(-1) (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/>`tan^(-1) (3)` <br/>`tan^(-1) (4)` </p>Solution :`(u^(2) <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> ^(2) theta)/(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>)= (u^(2) sin 2 theta)/(g)`<br/>`:. (sin^(2)theta)/(2) = 2 sin theta <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta`<br/>`:. (sin theta)/( cos theta) = 4`<br/>`tan theta = 4`<br/>`:. theta = tan^(-1)(4)`</body></html> | |
| 38424. |
A particle traversed half of the distance with a velocity of V_(0). The remaining parts of the distance was covered with velocity V_(1), for half of the time and with V_(2) for other half of the time. Find the mean velocity of the particle averaged and the whole time of motion |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C03_SLV_002_S01.png" width="80%"/> <br/> Average <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> for the second <a href="https://interviewquestions.tuteehub.com/tag/half-1014510" style="font-weight:bold;" target="_blank" title="Click to know more about HALF">HALF</a> distance = `(v_(1)(t)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+v_(2)(t)/(2))/((t)/(2)+(t)/(2))=(v_(1)+v_(2))/(2)` <br/> Average velocity for the first half distance = `V_(0)` (`because` it is constant) <br/> Average velocity for total path <br/> `=(2v_(0)((v_(1)+v_(2))/(2)))/(v_(0)+(v_(1)+v_(2))/(2))=(2v_(0)(v_(1)+v_(2)))/(v_(1)+v_(2)+2v_(0))`</body></html> | |
| 38425. |
If g is the acceleration due to gravity on the surface of earth, its value at a height equal to double the radius of earth is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>`<br/>`(g)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(g)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`(g)/(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38426. |
A ball thrown in vertically upward direction attains maximum height of 20 meter. At what height would its velocity be half of its initiall velocity? |
| Answer» <html><body><p>15 m <br/>6m <br/>12 m <br/>9m </p>Solution :For motion of a ball in <a href="https://interviewquestions.tuteehub.com/tag/vertically-3260386" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICALLY">VERTICALLY</a> upward direction, suppose`v _(0) = ` initial velocity = ?. <br/> v = velocity at maximum height `(20 m) =0. ` <br/> `a =- <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> and d = 20 m` <br/> From equation `2d=v _(2) -v _(0) ^(2) ,` we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a>, <br/> `- 2g xx 20 = (0) ^(2) -v _(0) ^(2)` <br/> `therefore - 40 g=- v_(0) ^(2)` <br/> `therefore v _(0) ^(2) = 40 g ""...(1)` <br/> Now, suppose velocity at height `h = v = (v _(0))/(2)` <br/> ` therefore` From equation `2 ad = v ^(2) -v _(0) ^(22),` we get, <br/> `- 2 gh = (v _(0) ^(2))/( <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) = (because a=-g, d = h, v = (v _(0))/(2))` <br/> `therefore -2gh =- ( 3v _(0) ^(2))/( 4)` <br/> `therefore -h = ( 3v _(0) ^(2))/( 4 xx 2g)` <br/> `therefore h = (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> xx 40 g)/(8g)` (From eq. (i)) <br/> `therefore h = 15m`</body></html> | |
| 38427. |
When you touch a piece of metal and a piece of wood simultaneously, metal appears colder or hotter. Can wood and metal feel equally cold or hot when touched? |
| Answer» <html><body><p></p>Solution :Yes. When our <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> is at the same <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> as that of the metal or <a href="https://interviewquestions.tuteehub.com/tag/wood-1458679" style="font-weight:bold;" target="_blank" title="Click to know more about WOOD">WOOD</a>.</body></html> | |
| 38428. |
If (d^(2)y)/(dt^(2))+4=0 is the difference equation of SHM then period of oscillation is………second. |
| Answer» <html><body><p></p>Solution :Comparing <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> `(d^(2)y)/(dt^(2))+4y=0` with general <a href="https://interviewquestions.tuteehub.com/tag/differential-953008" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENTIAL">DIFFERENTIAL</a> equation `(d^(2)y)/(dt^(2))+omega^(2)x=0` <br/> `omega^(2)= 4` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> omega =2` <br/> `therefore (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(T)= 2` <br/> `therefore T= pi s` <br/> `therefore T= 3.14 s`.</body></html> | |
| 38429. |
If energy 'E' momentum 'P' and force 'F' are choosen as fundamental units.Dimension of angular momentum in new system is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/pef-3769688" style="font-weight:bold;" target="_blank" title="Click to know more about PEF">PEF</a>^(2)` <br/>`PEF^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`PE^(2)<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>^(-1)`<br/>`PEF^(-2)`</p>Answer :B</body></html> | |
| 38430. |
The density of a material of a cube is calculated by measuring its mass and side . The error in measurement of mass and side are respectively 4% and 3%. Then the maximum percentage of error in measurement of density is |
| Answer» <html><body><p>0.12<br/>13<br/>0.07<br/>0.09</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38431. |
In Millikan's oil drop experiment , what is the terminal speed of an uncharged drop of radius 2.0xx10^(-5)mand density 1.2xx10^(3)kgm^(-3) . Take the viscosity of air at the temperature of the experiment to be 1.8xx10^(-5) Pa.s . Howmuch is the viscous force on the drop at thatspeed ?Neglect buoyancy of the drop due to air . |
| Answer» <html><body><p></p>Solution :Here radius of <a href="https://interviewquestions.tuteehub.com/tag/drop-443018" style="font-weight:bold;" target="_blank" title="Click to know more about DROP">DROP</a> `r=2.0xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)m` <br/>Density of oil`rho=1.2xx10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)kgm^(-3)`<br/>Density of air (dropis of air ) `rho_(o)=0`<br/>The <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of viscosity of oil, <br/>`<a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a>=1.8xx10^(-5)` Pas<br/>Terminal velocityfrom Stock.s law ,<br/>`v_(t)=(2)/(9)(r^(2)g)/(eta)(rho-rho_(o))`<br/>`=(2r^(2)gQ)/(9eta)`<br/>`=(2xx4xx10^(-10)xx9.8xx1.2xx10^(3))/(9xx1.8xx10^(-5))`<br/>`=5.807xx10^(-2)`<br/>`v_(t)=5.8cms^(-1)`<br/>Viscous force on drop from Stoke.s law <br/>`F_(v)=6pietarv_(t)`<br/>`=6xx3.14xx1.8xx10^(-5)xx2xx10^(-5)xx5.8xx10^(-2)`<br/>`=393.34xx10^(-12)`<br/> `=3.93xx10^(-10)N`</body></html> | |
| 38432. |
A massless spring, having force constant k, oscillates with a frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from one of the parts. The frequency of oscillation will now be…………. |
| Answer» <html><body><p>n <br/>`nsqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(n)/(sqrt(2))`<br/>2n</p>Solution :`n=(1)/(2pi)sqrt((<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)/(m)),n.=(1)/(2)sqrt((2)/(2))=n`</body></html> | |
| 38433. |
The relative velocity of two consecutive layers in 8 cm/s . If the perpendicular distance between the layrs is. 0.1 cm, then the velocity gradient will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`80sec^(-1)`<br/>`0.8sec^(-1)`<br/>`0.08sec^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38434. |
What is the fractional decrease in the value of free-fall acceleration g for a particle when it is lifted from the surface to an elevation h ? (h lt lt R) |
| Answer» <html><body><p>`(-h)/(R)`<br/>`(-2h)/(R)`<br/>`(-3h)/(R)`<br/>`(-4h)/(R)`</p>Solution :As, `<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>=(GM)/(R^(2))<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>(<a href="https://interviewquestions.tuteehub.com/tag/dg-431744" style="font-weight:bold;" target="_blank" title="Click to know more about DG">DG</a>)/(dR)=(-2GM)/(R^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))` <br/> `rArr (dg)/(h)=-(2GM)/(R^(2))=(1)/(h)` <br/> `rArrv (dg)/(g)=-2 ((h)/(R))`</body></html> | |
| 38435. |
A strip cantilever gets depressed by 3 mm due to some load. Find the depression will be produced in another cantilever with length and breath double those of the first? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/depression-948762" style="font-weight:bold;" target="_blank" title="Click to know more about DEPRESSION">DEPRESSION</a> produced in cantilever <br/> `delta=(4WI^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/ybd-3888697" style="font-weight:bold;" target="_blank" title="Click to know more about YBD">YBD</a>^(3)) :. Delta alpha(I^(3))/(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) :. (delta_(2))/(delta_(1))=((I_(2))/(I_(1)))^(3)((b_(1))/(b_(2)))=2^(3)xx(1)/(2)=4 :. delta=4xx12 <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a>`</body></html> | |
| 38436. |
If vecP-vecQ then which of the following is incorrect? |
| Answer» <html><body><p>`vecP=vecQ`<br/>`|vecP|=|vecQ|`<br/>`PhatQ=QhatA`<br/>`hatPhatQ=PQ`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38437. |
Utensils are coated black outside. Give the reason |
| Answer» <html><body><p></p>Solution :Cooking <a href="https://interviewquestions.tuteehub.com/tag/utensils-1441777" style="font-weight:bold;" target="_blank" title="Click to know more about UTENSILS">UTENSILS</a> are blackened at the bottom and <a href="https://interviewquestions.tuteehub.com/tag/polished-602182" style="font-weight:bold;" target="_blank" title="Click to know more about POLISHED">POLISHED</a> on the upper surface. Black coating will absorb all the heat from the furance and the upper surface will not <a href="https://interviewquestions.tuteehub.com/tag/allow-362909" style="font-weight:bold;" target="_blank" title="Click to know more about ALLOW">ALLOW</a> the heat <a href="https://interviewquestions.tuteehub.com/tag/inside-1045864" style="font-weight:bold;" target="_blank" title="Click to know more about INSIDE">INSIDE</a> the utensils to flow out.</body></html> | |
| 38438. |
A 1.0 HP motor pumps out water from a well of depth 20 m and fills a water tank of volume 2238 litres at a height of 10 m from the ground. The running time of the motor to fill the empty tank is (g=10ms^(-2)) |
| Answer» <html><body><p>5min<br/>10min<br/>15min<br/>20min</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38439. |
When the P.E of the particle executing S.H.M is one fourth of its maximum value during the oscillation its displacement from the equilibirum in terms of its amplitude .a. is |
| Answer» <html><body><p>`a"/"<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>`<br/>`a"/"3`<br/>`a"/"<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a>"/"3`</p>Answer :C</body></html> | |
| 38440. |
Assertion : Time period of a simple harmonic oscillator depends on amplitude and force cosntant Reason : Frequency of a simple harmonic oscillatior is determined by tis elasticity and inertia . |
| Answer» <html><body><p> If the <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and reason is a correct explanation of the assertion <br/> If both assertion and reason are correct but reason is not the correct explanation of assertion <br/> If assertion is correct but reason is incorrect <br/> If both assertion and reason are incorrect </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38441. |
What is progressive wave ? |
| Answer» <html><body><p></p>Solution :A jerk is given on a stretched string ast time t= 0 s. Assume that the wave pulse created during this disturbance moves along positive x direction with constant speed v as <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in Figure (a). <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C11_E15_009_S01.png" width="80%"/> <br/> Represent the shape of the wave pulse, mathematically as y=y(x,0)=f(x) at time t= 0s. Assume that the shape of the wave pulse remains the same during the propogation. After some time t, the pulse moving towards the right and any point on it can be represented by x' (read it as x prime) as shown in Figure (b). Then, <br/> `y(x,t) =f(x') = f(x-vt)`. <br/> Similarly, if the wave pulse moves towards left with constant speed v, then y=f(x+vt). Both waves `y=f(x+vt)` and `y=f(x-vt)` will satisfy the following one dimensional differential <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> known as the wave equation. <br/> `(d^(2)y)/(dx^(2)) =1/v^(2)(d^(2)y)/(dt^(2))` <br/> where the symbol `rho` represent partial <a href="https://interviewquestions.tuteehub.com/tag/derivative-948877" style="font-weight:bold;" target="_blank" title="Click to know more about DERIVATIVE">DERIVATIVE</a> (read `(dy)/(dx)` as partial y by partial x). Not all the solutions satisfying this differential equation can represent waves, because any physical acceptable wave must take finite <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a> for all values of x and t. But if the function represents a wave then it must satisfy the differential equation. <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a>, in one dimension (one independent variable),the partial derivative with respect to x is the same as total derivatives in coordinate x, we write So it can be written as<br/> `(d^(2)y)/(dx^(2)) =1/v^(2) (d^(2)y)/(dt^(2))`</body></html> | |
| 38442. |
A geyser heats 5kg/min water , from 25^@C " to " 80^@C . Find the rate of consumption of the fuel if the geyser operates on a gas burner , TakeHeat of cosumbustion= 5 xx 10^4 J//g sepcific heat of water= 4.20 xx 10^3 J//kg//K |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = mc <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> T` <br/>= 5kg/min ` xx 4.20 xx 10^3 J//kg//K xx (80 - 25)` <br/> ` = 115.5 xx 10^4 `J/min <br/> Rate of combustion of <a href="https://interviewquestions.tuteehub.com/tag/fuel-1001053" style="font-weight:bold;" target="_blank" title="Click to know more about FUEL">FUEL</a> `= (Q)/("<a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> of combustion")` <br/> ` = (115.5 xx 10^4)/(5 xx 10^4) = 23.1 ` g/min</body></html> | |
| 38443. |
(A) : An object placed on the rotating horizontal table may fly off at lower angular velocity when placed far away from the axis.(R ) : An object placed at the edge of the rotating table experiences more centrifugal force than at nearer position |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R ) is true </p>Answer :C</body></html> | |
| 38444. |
For two vectors A and B, |barA + barB| = |barA-barB| is always true when (i)|barA| = |barB| != 0""(ii) A_|_B (iii) |barA| = |barB| != 0 and A and B are parallel or anti parallel When either A or B is zero. |
| Answer» <html><body><p> i and <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a><br/>ii, iii and iv are true <br/>i, ii and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true <br/>ii and iv are true</p>Answer :D</body></html> | |
| 38445. |
A stone is dropped from the top of tall tower and one second later another stone is dropped from a balcany20 m below the top . If both the stones reach the ground at the same instant , determine the height of the tower .take g = 10 ms^(-2) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :31.25 m</body></html> | |
| 38446. |
On the surface of earth, the time period of a simple pendulum is T_(e). When the pendulum is taken to a height of 2R above the surface of earth, the time period becomes T_(h). (R is radius of earth.) The value of (T_(e))/(T_(h)) is |
| Answer» <html><body><p>`1 : 9`<br/>`9 : 1`<br/>`1 : <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`3 : 1`</p>Solution :As time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of a <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> <a href="https://interviewquestions.tuteehub.com/tag/pendulum-1149901" style="font-weight:bold;" target="_blank" title="Click to know more about PENDULUM">PENDULUM</a> <br/> `T = 2pisqrt((l)/(g))` <br/> On earth.s surface `g_(e) = (GM)/(R^(2))` <br/> At a height `h = <a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>, g_(h) = (GM)/((R + 2R)^(2)) = (GM)/(9R^(2))` <br/> `(T_(e))/(T_(h)) = sqrt((g_(h))/(g_(e))) = sqrt((GM.R^(2))/(9R^(2).GM))` <br/> `(T_(e))/(T_(h)) = sqrt((1)/(9)) = 1:3`</body></html> | |
| 38447. |
The radiation emitted by a star "A" per second is 10,000 times that of the sun. If the surface temperatures of the sun and the star A are 6000K and 2000K respectively, the ratio of the radii of the star A and the sun is |
| Answer» <html><body><p>`300:1`<br/>`600:1`<br/>`900:1`<br/>`1200:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38448. |
A frame of reference A is moving rectilinearly and uniformly with a velocity vec(u) with respect to an inertial frame B. Abody is moving with velocity vec(v) and acceleration vec(a) in an inertial system. (A): When we use Newton's second law in frame B we write Sigma vec(F)_("net")=mvec(a) Now, when we use the same in frame A we will write exactly same vec(F)_("net") and vec(a) (R): All inertial systems are equally suitable for the description of physical phenomenon. |
| Answer» <html><body><p>If both A <a href="https://interviewquestions.tuteehub.com/tag/andr-2423570" style="font-weight:bold;" target="_blank" title="Click to know more about ANDR">ANDR</a> are true and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A<br/>If both A and R are true but R is not correct explanation of A<br/>If A is true but R is false<br/>If A is false but R is true</p>Answer :A</body></html> | |
| 38449. |
If the position vector of the particle is given by vecr = 3 t^2 hati + 5t hatj + 4hatk.Find the velocity of the particle at t = 3s. |
| Answer» <html><body><p></p>Solution :The velocity `vecv = (dvecr)/(dt) = (dx)/(dt) hati + (dy)/(dt) hatj + (dz)/(dt) <a href="https://interviewquestions.tuteehub.com/tag/hatk-2693615" style="font-weight:bold;" target="_blank" title="Click to know more about HATK">HATK</a> ` <br/>we obtain `vecv (t) = 6t hati + 5 hatj` <br/> The velocity has only two components `v_x = 6t` , depending on <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> t and ` v_y = 5` which is <a href="https://interviewquestions.tuteehub.com/tag/independent-505826" style="font-weight:bold;" target="_blank" title="Click to know more about INDEPENDENT">INDEPENDENT</a> of time . <br/> The velocity at t = 3s is `vecv (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) = 18 hati + 5hatj `</body></html> | |
| 38450. |
Explain critical speed , White Water Rapids and turbulent flow . |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/critical-427694" style="font-weight:bold;" target="_blank" title="Click to know more about CRITICAL">CRITICAL</a> speed : Steady flow is achieved at low flow speeds beyond a limiting <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> , called critical speed .<br/>Turbulent flow : In alimiting value , called critical speed . "<br/> Turbulent flow: In a fluid flow ,if the velocity of the fluid changes erratically from point to point as well as from time to time ,the flow is known as a turbulent flow.<br/> If speed of fluid , becomes more to the critical speed ,this flow loses steadiness and becomes turbulent .<br/>White water rapids : When a fast flowing stream encounters <a href="https://interviewquestions.tuteehub.com/tag/rocks-1190591" style="font-weight:bold;" target="_blank" title="Click to know more about ROCKS">ROCKS</a> , small foamy whirlpool like regions called white water rapids are formed <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C10_E01_033_S01.png" width="80%"/><br/>(a) Some streamlines for fluid flow.<br/>A jet of air striking a <a href="https://interviewquestions.tuteehub.com/tag/flat-992377" style="font-weight:bold;" target="_blank" title="Click to know more about FLAT">FLAT</a> <a href="https://interviewquestions.tuteehub.com/tag/plate-1156364" style="font-weight:bold;" target="_blank" title="Click to know more about PLATE">PLATE</a> placed perpendicular to it .This is an example of turbulent flow.</body></html> | |