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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39501. |
The diameters of open and narrow ends of a pipe connected to a venturi-meter is 20 cm and 15 cm, respectively. If the difference of pressure at the ends is 25 cm of Hg, then calculate the volume of water flowing through the pipe per second. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`11.04 m^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</body></html> | |
| 39502. |
Answer the following question : Time period of a particle in SHM depends on the force constant k and mass m of the particle: T=2pisqrt(m/k). A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For a simple pendulum, <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> itself is proportional to m, so m <a href="https://interviewquestions.tuteehub.com/tag/cancels-908215" style="font-weight:bold;" target="_blank" title="Click to know more about CANCELS">CANCELS</a> out</body></html> | |
| 39503. |
Some of the most profound statements on the nature of science have come from Albert Einstein, one of the greatest scientists of all time. What do What do you think did Einstein mean when he said : ''The most incomprehensible thing about the world is that it is comprehensible ''? |
| Answer» <html><body><p></p>Solution :The physcial world, when <a href="https://interviewquestions.tuteehub.com/tag/seen-3017120" style="font-weight:bold;" target="_blank" title="Click to know more about SEEN">SEEN</a> by a layman, presents us with such a wide diversity of things. It seems <br/> incomprehensible, i.e., as if it cannot be understood. On study and analysis, the scinetists <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> that the <a href="https://interviewquestions.tuteehub.com/tag/physical-600035" style="font-weight:bold;" target="_blank" title="Click to know more about PHYSICAL">PHYSICAL</a> phenomene from atomic to astronomical <a href="https://interviewquestions.tuteehub.com/tag/ranges-1177066" style="font-weight:bold;" target="_blank" title="Click to know more about RANGES">RANGES</a> can be usderstood in terms of only a few basic <br/> <a href="https://interviewquestions.tuteehub.com/tag/concepts-928161" style="font-weight:bold;" target="_blank" title="Click to know more about CONCEPTS">CONCEPTS</a>, i.e., the physcial world becomes comperhensible. This is what is meant by Einstein's statement <br/> made above.</body></html> | |
| 39504. |
When a satellite is lifted from a lower orbit to a higher orbit a) Gravitational potential energy increases b) KE decreses c) Gravitational PE decreases d) KE increases |
| Answer» <html><body><p> a is only <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/> a & d are correct <br/> a and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct<br/> a & <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39505. |
In gravity-free space, a particle is in contact with the inner surface of a hollow vertical cylinder and moves in horizontal circular path along the surface. There is some friction between the particle and the surface. The retardation of the particle is |
| Answer» <html><body><p>zero<br/>independent of its <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a><br/> <a href="https://interviewquestions.tuteehub.com/tag/proportional-1170279" style="font-weight:bold;" target="_blank" title="Click to know more about PROPORTIONAL">PROPORTIONAL</a> to its velocity<br/>proportional to the <a href="https://interviewquestions.tuteehub.com/tag/square-650836" style="font-weight:bold;" target="_blank" title="Click to know more about SQUARE">SQUARE</a> of its velocity </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39506. |
The force Which acts in order to oppose the relative motion of the layer is known as _______ force. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/static-1226026" style="font-weight:bold;" target="_blank" title="Click to know more about STATIC">STATIC</a> <a href="https://interviewquestions.tuteehub.com/tag/friction-21545" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTION">FRICTION</a> <br/> <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> friction<br/>friction <br/><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :static friction</body></html> | |
| 39507. |
For example, if you, by habit, always hold your head a bit too far to the right while reading the position of a needle on the scale, you will introduce an error called as |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/random-11853" style="font-weight:bold;" target="_blank" title="Click to know more about RANDOM">RANDOM</a> errors<br/>Perfect errors<br/>Parallax errors<br/>Least <a href="https://interviewquestions.tuteehub.com/tag/count-936718" style="font-weight:bold;" target="_blank" title="Click to know more about COUNT">COUNT</a> errors</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39508. |
The dimensions of electric current in electric conductivity are |
| Answer» <html><body><p>1<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>3<br/>`-2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39509. |
There is a small air bubble inside a glass sphere of radius 10cm. The bubble is 4cm below the surface and is viewed normally from the outside. The apparent depth of the bubble is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3cm-310901" style="font-weight:bold;" target="_blank" title="Click to know more about 3CM">3CM</a> below the <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a><br/>5cm below the surface<br/>8cm below the surface <br/><a href="https://interviewquestions.tuteehub.com/tag/10cm-267056" style="font-weight:bold;" target="_blank" title="Click to know more about 10CM">10CM</a> <a href="https://interviewquestions.tuteehub.com/tag/belwo-2465848" style="font-weight:bold;" target="_blank" title="Click to know more about BELWO">BELWO</a> the surface</p>Answer :A</body></html> | |
| 39510. |
If a force F is applied on a body and the body moves with velocity V the power will be |
| Answer» <html><body><p>`F.V`<br/>`F/V`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/fv-458643" style="font-weight:bold;" target="_blank" title="Click to know more about FV">FV</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`F/V^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39511. |
If the mass of the electron (9xx10^(-31)kg) is taken as unit of mass, the radius of the first Bohr orbit (0.5xx10^(-10)m) as unit of length and 500 newton as the unit of force, then the unit of time in the new system would be |
| Answer» <html><body><p>`3 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-22) s ` <br/>`1.5 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)s ` <br/>`15 xx 10^(-20)s ` <br/>`45 xx 10^(-20)s `</p>Answer :A</body></html> | |
| 39512. |
An ideal gas (C_p//C_V =gamma) is taken through a process in which the pressure and the volume vary as P=aV^b.Find the value of b for which the specific heat capacity in the process is zero. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`- <a href="https://interviewquestions.tuteehub.com/tag/gamma-470142" style="font-weight:bold;" target="_blank" title="Click to know more about GAMMA">GAMMA</a>`</body></html> | |
| 39513. |
A vessel of volume 'V' is half filled with a liquid of density '2d' and coefficient of apparent expansion 'x' and the other half is filled with another liquid of density 'd' but coefficient of apparent expansion '2x'. The temperature is raised through 2^(@) C, the mass of the liquid expelled out |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/9v-343148" style="font-weight:bold;" target="_blank" title="Click to know more about 9V">9V</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> d`<br/>`6V xx d`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3v-310794" style="font-weight:bold;" target="_blank" title="Click to know more about 3V">3V</a> xx d`<br/>`1.5 V xx d`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 39514. |
Which of the following units could be associated with a scalar quantity ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`<br/>`kg m^(2) s^(2)`<br/><a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> `s^(2)`</p>Answer :C</body></html> | |
| 39515. |
The Young's modulus of the material of a wire is Y.If the radius of the wire is doubledthe Young's modulus of the new wire will be. |
| Answer» <html><body><p>Y<br/>2Y<br/>Y/2<br/>Y/4</p>Answer :A</body></html> | |
| 39516. |
A block of mass m is lowered with the help of a rope of negligible mass through a distance d with an acceleration of g/3.Work done by the rope on the block is |
| Answer» <html><body><p>`(2Mgd)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`-(2Mgd)/(3)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/mgd-2831421" style="font-weight:bold;" target="_blank" title="Click to know more about MGD">MGD</a>)/(3)`<br/>`-(Mgd)/(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39517. |
A simple pendulum of length L_(1) has a time period T_(2) then the time period of pendulum of length (L_(1)+L_(2)) is |
| Answer» <html><body><p>`T1+T2`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(T_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)+T_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`sqrt(T_(1)T_(2))`<br/>`sqrt(T_(1)^(2)+T_(2)^(2))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39518. |
One car moving on a straight road covers one third of the distance with 20 km/hr and the rest with 60 km/hr. The average speed is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> km/hr<br/>80 km/hr<br/>`<a href="https://interviewquestions.tuteehub.com/tag/46-317673" style="font-weight:bold;" target="_blank" title="Click to know more about 46">46</a>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)km//hr` <br/><a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a> km/hr</p>Answer :D</body></html> | |
| 39519. |
The position ofa particle is given byr=3.0hati-2.0t^(2)hatj+4.0hatkmwhere t is in seconds and the coefficients have proper units for r to be inmetres . (a)Find the v and a of the particle ? (b)What is the magnitude and direction of velocity of the particle at t=2.0s ? |
| Answer» <html><body><p><br/></p>Answer :(a) `v(t)=(3.0hati-4.0thatj)<a href="https://interviewquestions.tuteehub.com/tag/hata-2693428" style="font-weight:bold;" target="_blank" title="Click to know more about HATA">HATA</a>(t)=-4.0hatj`<br/>(b) `8.54 " ms "^(-1),<a href="https://interviewquestions.tuteehub.com/tag/70-333629" style="font-weight:bold;" target="_blank" title="Click to know more about 70">70</a>^(@)` with <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> - <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a>.</body></html> | |
| 39520. |
Two wires of same material and same length but diameters in the ratio 2:3 are stretched by the same length. The ratio of the forces applied on two wires is ---- |
| Answer» <html><body><p>`4:3` <br/>`4:9` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>:5` <br/>`9:4` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :2</body></html> | |
| 39521. |
Keeping the number of the moles,volume and tempreture the same,which of the following are the same for all ideal geases? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/rms-1190227" style="font-weight:bold;" target="_blank" title="Click to know more about RMS">RMS</a> <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of a <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a> <br/>Density<br/>pressure<br/>average <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> of momentum</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39522. |
In the previous question, if dv//dt = 0, then the angular acceleration of the ladder when alpha= 45^@ is. |
| Answer» <html><body><p>`2 <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(2) L^(2)`<br/>`v^(2)//2L^(2)`<br/>`sqrt(2) [v^(2)//L^(2)]`<br/>None</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NG_PHY_MEC_V01_C03_E01_046_S01.png" width="80%"/> <br/> `v' sin theta = v cos theta`….(1) <br/> let <a href="https://interviewquestions.tuteehub.com/tag/instantaneous-516608" style="font-weight:bold;" target="_blank" title="Click to know more about INSTANTANEOUS">INSTANTANEOUS</a> axis of rotation is at distance `l` from <a href="https://interviewquestions.tuteehub.com/tag/end-971042" style="font-weight:bold;" target="_blank" title="Click to know more about END">END</a> `A`. <br/> `omega = (v sin theta)/(l) = (v' cos theta)/((L-l))` ....(2) <br/> from (1) & (2) `omega = (v sin theta)/(l) = (v cos^(2) theta)/(sin theta (L - l))` <br/> `l = L sin^(2) theta`... (3) <br/> from (2) & (3) <br/> `omega = (v cosec theta)/(L)` <br/> `(d omega)/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>) = (v)/(L) (-cos ec theta. cot theta) xx (d theta)/(dt)` <br/> `(d omega)/(dt) = (v)/(L) (-cos ec theta. cot theta) xx (v)/(L) cos ec theta` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> = - (v^(2))/(L^(2))cos ec^(2) theta. cot theta` <br/> `alpha = - (v^(2))/(L^(2)) cos ec^(2) 45^@. cot 45^@ rArr alpha = -(2v^(2))/(L^(2))`.</body></html> | |
| 39523. |
You are riding in an automobile of mass 3000 kg. Assuming that you are examining the oscillation characteristics of its suspension system. The suspension sags 15cm when the entire automobile is placed on it. Also, the amplitude of oscillation decreases by 50% during one complete oscillation. Estimate the values of (a) the spring constant k and (b) the damping constant b for the spring and shock absorber system of one wheel, assuming that each wheel supports 750 kg. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`F= mg = 3000 xx 10 = 3 xx 10^(4) N. <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> =-15 x× 10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) m` 4 springs in parallel K=4K, F=-(4K) x.<br/> `K= -(F)/(4x)= (-3 xx 10^(4))/(4(-15xx 10^(2)))= 5 xx 10^(4) N//m` <br/> b) mass supported by each spring`m = (3000)/(4)= 750 Kg` damped oscillations amplitude `A_(t)= Ae^(-bt//2m)` <br/> time period `T= 2pisqrt((m)/(K))= 2 xx 3.14 sqrt((750)/( <a href="https://interviewquestions.tuteehub.com/tag/5xx-1901301" style="font-weight:bold;" target="_blank" title="Click to know more about 5XX">5XX</a> 10^(4)))= 77xx 10^(-2) "seconds"` <br/> Amplitude decreases by 50% then `At =A//2` and t = T <br/> `:. (A)/(2)= Ae^(-bt//2m)` or `b= (0.693 xx 2m)/(T)` <br/> `b= 1350 kg//s`</body></html> | |
| 39524. |
For the damped oscillator shown in Fig. 14.19, the mass m of the block is 200 g, k = 90 N m^(-1) and the damping constant b is 40 g s^(-1). Calculate (a) the period of oscillation, (b) time taken for its amplitude of vibrations to drop to half of its initial value, and (c) the time taken for its mechanical energy to drop to half its initial value. |
| Answer» <html><body><p></p>Solution :(a) We see that <a href="https://interviewquestions.tuteehub.com/tag/km-1064498" style="font-weight:bold;" target="_blank" title="Click to know more about KM">KM</a> = `90x×0.2 = 18 kg Nm^(-1)=kg^(2)s^(-2),` therefore `sqrt(km)=4.243kgs^(-1)`, and `b = 0.04 kg s^(-1)`. Therefore, b is much less than `sqrt(km)` . Hence, the <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> period T from Eq. (14.34) is given by <br/> `T=2pisqrt(m/k)` <br/> `=2pisqrt((0.2kg)/(90Nm^(-1)))` <br/> = 0.3 s <br/> (b) Now, from Eq. (14.33), the time, `T_(1//2)`, for the <a href="https://interviewquestions.tuteehub.com/tag/amplitude-859568" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDE">AMPLITUDE</a> to drop to half of its initial value is given by <br/> `T_(1//2)=("ln"(1//2))/(b//2m)` <br/> `=(0.693)/(40)xx2xx200s` <br/> `=6.93s` <br/> (c) For calculating the time, `t_(1//2)`, for its mechanical energy to drop to half its initial value we make use of Eq. (14.35). From this equation we have, <br/> `E(t_(1//2)//E(0)=exp(-bt_(1//2)//m)` <br/> Or `1//2=exp(-bt_(1//2)//m)` <br/> `"ln"(1//2)=-(bt_(1//2)//m)` <br/> Or `t_(1//2)=(0.693)/(40gs^(-1))xx200g` <br/> =3.46 s <br/> This is just half of the <a href="https://interviewquestions.tuteehub.com/tag/decay-945588" style="font-weight:bold;" target="_blank" title="Click to know more about DECAY">DECAY</a> period for amplitude. This is not surprising, because, according to Eqs. (14.33) and (14.35), energy depends on the square of the amplitude. <a href="https://interviewquestions.tuteehub.com/tag/notice-25787" style="font-weight:bold;" target="_blank" title="Click to know more about NOTICE">NOTICE</a> that there is a factor of 2 in the exponents of the two exponentials.</body></html> | |
| 39525. |
The mass and diameter of a planet are two times those of earth. If a seconds pendulum is taken to it, the time period of the pendulum is seconds is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`(1)/(2)`<br/>`2sqrt(2)`<br/>`sqrt(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39526. |
Force (5, 6, 7) N acts on a particle with position vector (2, 2, 1) m. The magnitude of phi torque on the particle will be ………. Nm. |
| Answer» <html><body><p>`sqrt(13)`<br/>`sqrt(149)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/61-330126" style="font-weight:bold;" target="_blank" title="Click to know more about 61">61</a>)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>)`</p>Solution :`|vectau|=|vecrxxvecF|` <br/> `=|(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>,2,1)xx(5,6,7)|` <br/> `=|(2,2,1)xx(5,6,7)|` <br/> `=|hati(14-6)-<a href="https://interviewquestions.tuteehub.com/tag/hatj-2693584" style="font-weight:bold;" target="_blank" title="Click to know more about HATJ">HATJ</a>(14-5)+hatk(12-10)|` <br/> `=|8hati-9hatj+2hatk|` <br/> `=sqrt((8)^(2)+(-9)^(2)+(2)^(2))` <br/> `=sqrt(64+81+4)` <br/> `=sqrt(149)`</body></html> | |
| 39527. |
A small mass is suspended by a string from the ceiling of a car. As the car accelerates at a rate 'a' the string makes an angle theta with the vertical. Then the tension in the string |
| Answer» <html><body><p>mg <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> `theta` <br/>ma <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> `theta`<br/>`m sqrt(a^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)+<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>^(2))` <br/>`ma sqrt(a^(2)+g^(2))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 39528. |
The density of ice is x gm/cc and that of water is y gm/cc. what is the change in volume in ce, when m gm of ice melts ? |
| Answer» <html><body><p>M(y-x)<br/>(x-y)/m<br/>mxy(x-y)<br/>m(1/y-1/x)</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39529. |
A closed container of volume 0.02 m^(3) contains a mixture of neon and argon gases at 27^(@)C temperature and 1.0 times 10^(5)N/m^(2) pressure. If the gram-molecular weight of neon and argon are 20 and 40 respectively, find the masses of the individual gases in the container. Assuming them to be ideal (R = 8.314 J/mol-K). Total mass of the mixture is 28 g. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let m be the mass of the neon gas, then mass of argon will be 28 - m. <br/> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of moles of neon, `n_(1)=m/20` <br/> Number of moles of argon, `n_(2)=(28-m)/40` <br/> Now by <a href="https://interviewquestions.tuteehub.com/tag/ideal-1035490" style="font-weight:bold;" target="_blank" title="Click to know more about IDEAL">IDEAL</a> gas equation, we have PV = nRT <br/> Here `n=n_(1)+n_(2)=m/20+(28-m)/40, P=1.0 times <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(5)N//m^(2)` <br/> `T=273+27=300K, V=0.02 m^(3)` <br/> `therefore (1.0 times 10^(5)) times 0.02=[m/20+((28-m))/40] times 8.314 times 300` <br/> After solving , we get m = 4.07 g , `""` Mass of neon gas = 4.07 g <br/> Mass of argon gas = 28 - m = 28 - 4.07 = 23.93 g</body></html> | |
| 39530. |
In a P-V diagram for an ideal gas (where P is along the y-axis and V is along the x-axis), the valueof the ratio, slope of the adiabatic curve/slope of the isothermal curve at any point will be: (where symbols have their usual meanings) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a><br/>`C_p//C_v`<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>`C_v//C_p` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39531. |
Answer the following question : A man with a wristwatch on his hand falls from the top of a tower. Does the watch give correct time during the free fall ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/yes-749457" style="font-weight:bold;" target="_blank" title="Click to know more about YES">YES</a>, the <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> in the <a href="https://interviewquestions.tuteehub.com/tag/wristwatch-1461816" style="font-weight:bold;" target="_blank" title="Click to know more about WRISTWATCH">WRISTWATCH</a> depends on spring action and has <a href="https://interviewquestions.tuteehub.com/tag/nothing-581732" style="font-weight:bold;" target="_blank" title="Click to know more about NOTHING">NOTHING</a> to do with <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> due to gravity.</body></html> | |
| 39532. |
When a spring is compresssed by 3 cm the potential energy stored in it is U. When it is compressed further by 3cm, the increase in potential energy is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> U<br/>U<br/>2 U<br/>3 U</p>Answer :D</body></html> | |
| 39533. |
Equal masof three liquid are keptin three identical cylindrical vessels A,B and C. The densities are rho_(A),rho_(B),rho_(C) will rho_(A)ltrho_(B)ltrho_(C). The force on the base will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> in <a href="https://interviewquestions.tuteehub.com/tag/vessel-1445872" style="font-weight:bold;" target="_blank" title="Click to know more about VESSEL">VESSEL</a> A<br/>Maximum in <a href="https://interviewquestions.tuteehub.com/tag/vessels-1445910" style="font-weight:bold;" target="_blank" title="Click to know more about VESSELS">VESSELS</a> B<br/>Maximum in vessel C<br/>Equal in all the vessels</p>Answer :D</body></html> | |
| 39534. |
Show that veca.(vecbxxvec c) is equal in magnitude to the volume of the parallelopiped formed on the three vectors, veca,vecb and vec c |
| Answer» <html><body><p></p>Solution :Suppose `<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(OA)=vecb,vec(OC)=vecc and vec(OE)=<a href="https://interviewquestions.tuteehub.com/tag/veca-3257210" style="font-weight:bold;" target="_blank" title="Click to know more about VECA">VECA</a>` `vecb and vec c` are adjacent sides of parallelogram OABC <br/> Area of `squareOABC,vecS=vecbxxvecc` <br/> `:.Shatn=vecbxxvecc` <br/> where `<a href="https://interviewquestions.tuteehub.com/tag/hatn-2693621" style="font-weight:bold;" target="_blank" title="Click to know more about HATN">HATN</a>` unit vector perpendicular to plane form by `vecb and vecc and theta` is angle between `veca and vecS`. <br/> `:.veca.(vecbxxvecc)=veca.vecS [because vecbxxvecc=vecS]` <br/> `=aScostheta` <br/> `=(acostheta)S` <br/> `=hS""......(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> where in `DeltaEOE., EE.=h=acostheta` <br/> Suppose <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of parallelepiped OABCDEF is V. <br/> `:.V` = Area of `squareOABCxx` perpendicular (h) of parallelogram OABC from E <br/> `:. V=sh"".....(2)` <br/> From result (1) and (2) <br/> `veca.(vecbxxvecc)=V`</body></html> | |
| 39535. |
Calculate the ratio of electric and gravitational force between two protons. Charge of each proton is 1.6 xx 10^(-19)C, mass is 1.672 xx 10^(-27)kg and G= 6.67 xx 10^(-11) Nm^(2) kg^(-2). |
| Answer» <html><body><p></p>Solution :The electric force <a href="https://interviewquestions.tuteehub.com/tag/fe-460008" style="font-weight:bold;" target="_blank" title="Click to know more about FE">FE</a> `(e^2)/(4piepsilon_(0)r^2)` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/gravitational-476409" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITATIONAL">GRAVITATIONAL</a> force `Fg = (Gm^2)/r^2` <br/> `:. (Fe)/(Fg)=1/(4piepsilon_(0))xxe^2/(m^2G) = <a href="https://interviewquestions.tuteehub.com/tag/9xx10-1938449" style="font-weight:bold;" target="_blank" title="Click to know more about 9XX10">9XX10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)xx` <br/> `((1.6xx10^(-19))^2)/((9.1xx10^(-31))xx^(2) xx 6.67xx 10^(-11)) = 4.17 xx10^(42)`</body></html> | |
| 39536. |
For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE) against its displacement d. Which one of the following represents these correctly? (Graphs are schematic and not frawn to scale) |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U10_C01_E17_002_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U10_C01_E17_002_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U10_C01_E17_002_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U10_C01_E17_002_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39537. |
It is easier to stand on two legs than to stand on a single leg. Why? |
| Answer» <html><body><p></p>Solution :A body <a href="https://interviewquestions.tuteehub.com/tag/remains-621920" style="font-weight:bold;" target="_blank" title="Click to know more about REMAINS">REMAINS</a> in stable equilibrium when the vertical line through its <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> of gravity remains well within its base. Equilibrium is disturbed when this vertical line falls outside the base. It is difficult to maintain the vertical line passing through <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> foot only. This reduces the stability while standing on one leg. Standing on two legs increases <a href="https://interviewquestions.tuteehub.com/tag/thebase-1403267" style="font-weight:bold;" target="_blank" title="Click to know more about THEBASE">THEBASE</a> area through which the vertical line is more likely to <a href="https://interviewquestions.tuteehub.com/tag/pass-1148402" style="font-weight:bold;" target="_blank" title="Click to know more about PASS">PASS</a> and hence a higher stability of equilibrium is achieved.</body></html> | |
| 39538. |
Define the term wave motion? |
| Answer» <html><body><p></p>Solution :Wave motion is a kind of disturbances which travels through a <a href="https://interviewquestions.tuteehub.com/tag/medium-1092763" style="font-weight:bold;" target="_blank" title="Click to know more about MEDIUM">MEDIUM</a> due to <a href="https://interviewquestions.tuteehub.com/tag/repeated-1185068" style="font-weight:bold;" target="_blank" title="Click to know more about REPEATED">REPEATED</a> <a href="https://interviewquestions.tuteehub.com/tag/vibrations-726480" style="font-weight:bold;" target="_blank" title="Click to know more about VIBRATIONS">VIBRATIONS</a> of the particles of the medium about their mean positions, the disturbance being handed over from one <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> to the next.</body></html> | |
| 39539. |
A particle is moving in a circle of radius R=1 m with constant speed v=4m//s. The ratio of the displacement to acceleration of the foot of the perpendicular drawn from the particle onto the diameter of the circle is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>)s^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(1)/(2)s^(2)`<br/>`2s^(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/16s-277872" style="font-weight:bold;" target="_blank" title="Click to know more about 16S">16S</a>^(2)`</p>Answer :A</body></html> | |
| 39540. |
A passing aeroplane sonetimes causes the rattling of the windows of a house.Why? |
| Answer» <html><body><p></p>Solution :When the <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> of sound <a href="https://interviewquestions.tuteehub.com/tag/waves-13979" style="font-weight:bold;" target="_blank" title="Click to know more about WAVES">WAVES</a> from the engine of an matches with the natural frequency of a window,resonance <a href="https://interviewquestions.tuteehub.com/tag/takes-1238575" style="font-weight:bold;" target="_blank" title="Click to know more about TAKES">TAKES</a> place which <a href="https://interviewquestions.tuteehub.com/tag/causes-910982" style="font-weight:bold;" target="_blank" title="Click to know more about CAUSES">CAUSES</a> the rattling of window.</body></html> | |
| 39541. |
The angular frequency of a fan of moment of inertia 0.1kg m^(2) is increased from 30 rpm to 60 rpm when a torque of 0.03 Nm acts on it. Find the number revolutions made by the fan while the angular frequency is increased from 30 rpm to 60 rpm. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Work done `=(1)/(2)I(omega_(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)^(2)-omega_(i)^(2))` `tau theta=(1)/(2)I(omega_(f)^(2)-omega_(i)^(2))` <br/> `theta=(1)/(2)((I)/(tau))(omega_(f)^(2)-omega_(i)^(2))=(0.1)/(2xx0.03)((2pi)^(2)-pi^(2))=5pi^(2)` <br/> The number of revolutions, `(theta)/(2pi)=(5pi^(2))/(2pi)=(5pi)/(2)=7.855`<a href="https://interviewquestions.tuteehub.com/tag/rev-1188006" style="font-weight:bold;" target="_blank" title="Click to know more about REV">REV</a></body></html> | |
| 39542. |
A hollow cylindrical shell of radius R has mass M. It is completely filled with ice having mass m. It is placed on a horizontal floor connected to a spring (force constant k) as shown. When it is disturbed it performs oscillations without slipping on the floor. (a) Find time period of oscillation assuming that the ice is tightly pressed against the inner surface of the cylinder. (b) If the ice melts into non viscous water, find the time period of oscillations. (Neglect any volume change due to melting of ice) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) 2pi <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((4M+3m)/(<a href="https://interviewquestions.tuteehub.com/tag/2k-300402" style="font-weight:bold;" target="_blank" title="Click to know more about 2K">2K</a>));` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) ` 2pi sqrt((2M +m)/(K))`</body></html> | |
| 39543. |
The acceleration of a particle is increasing linearly with time t as bt. The particle starts from the origin with an initial velocity v_0 . The distance travelled by the particle in time t will be |
| Answer» <html><body><p>`v_0t + 1/3 bt^2` <br/>`v_0t + 1/2 bt^2` <br/>`v_0 t + 1/6 bt^3`<br/>`v_0t + 1/3 bt^2` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39544. |
If the temperature of the Sun were to increase from T to 2T and its radius from R to 2R. The ratio of radiant energy received on earth to what it was previously will be. . . .. . . |
| Answer» <html><body><p>4<br/>16<br/>32<br/>64</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/amount-374803" style="font-weight:bold;" target="_blank" title="Click to know more about AMOUNT">AMOUNT</a> of radiant <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>, `W=esigmaAT^(4)` (Stefan-Boltzmann.s law) <br/> `W=e <a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>(4piR^(2))T^(4)(becauseA=4piR^(2))` <br/> `WpropR^(2)T^(4)` <br/> `:.(W_(2))/(W_(1))=((R_(2))/(R_(1)))^(2)((T_(2))/(T_(1)))^(4)` <br/> `=((2R)/(R))^(2)((2T)/(T))^(4)` <br/> `=4xx16=64`</body></html> | |
| 39545. |
A particle moves along a horizontal circle witrr constant speed. If 'a' is its acceleration and 'E' is its kinetic energy A) a is constant B) E is constant C) a is variable D) E is variable |
| Answer» <html><body><p>A & <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are correct<br/>C & D are correct<br/>A & D are correct<br/>B & C are correct</p>Answer :D</body></html> | |
| 39546. |
Why are bridges declared unsafe after long use? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Due to repeated stress and strain, the elastic strength of the bridge gets reduced. After a <a href="https://interviewquestions.tuteehub.com/tag/long-537592" style="font-weight:bold;" target="_blank" title="Click to know more about LONG">LONG</a> time, thebridge <a href="https://interviewquestions.tuteehub.com/tag/develops-950370" style="font-weight:bold;" target="_blank" title="Click to know more about DEVELOPS">DEVELOPS</a> elastic fatigue and <a href="https://interviewquestions.tuteehub.com/tag/ultimately-7384516" style="font-weight:bold;" target="_blank" title="Click to know more about ULTIMATELY">ULTIMATELY</a> may collapse.</body></html> | |
| 39547. |
The energy required to shift a satellite from oribital radius 'r' to radius 2r is E. What energy will be required to shift the satellite from orbital radius 2r to 3r? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>`<br/>`E"/"2`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3e-310704" style="font-weight:bold;" target="_blank" title="Click to know more about 3E">3E</a>"/"<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>`<br/>`E"/"<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`</p>Answer :D</body></html> | |
| 39548. |
A balloon from rest accelerates uniformly upward with .a. ms^2, for it seconds of time. A stone is released from the balloon. Now read the following statements to pick the right ones. (a) The stones initial velocity is zero, relative to to ballon (b) The stone.s initial velocity is nonzero, relative to earth (c) The time taken to reach the ground from the balloon.s frame of reference is inversely proportional to sqrt(a+g) (d) The time take to reach the ground from earth.s frame of reference is directly proportional to sqrt(a+g). |
| Answer» <html><body><p>a,<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>,<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <br/>a,c,d<br/>a,b,d<br/>a,c</p>Answer :A</body></html> | |
| 39549. |
The heart of a man pumps 5 litre of blood through the arteries per minute at a pressure of 150 mm of mercury.If the density of mercury be 13.6 xx10^(3) kg//m^(3)and g = 10 m//s^(2) then the power of heart in watt is : |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`1.50` <br/>`1.70`<br/>`2.35`<br/>`3.00`</p>Solution :Pumping of blood `(dv)/(dt) = (5mm)/(<a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a>) =(5xx10^(-3))/60 (m^(3))/S` <br/> Pressure P = 150 mm of Hg `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> = 150 xx10^(-3) m ` <br/> Power of heart ` = P (dv)/(dt)` <br/> ` = rho gh (dv)/(dt)` <br/> ` = 13.6 xx10^(3) xx10 xx150 xx10^(-3) xx (5xx10^(-3))/60`<br/> Power of heart` = 1700 xx 10^(-3) = 1.70 `<a href="https://interviewquestions.tuteehub.com/tag/watt-1450279" style="font-weight:bold;" target="_blank" title="Click to know more about WATT">WATT</a> = 1.70 W</body></html> | |
| 39550. |
A vertically thrown up body reaches 20m at a place on the earth. The height to which it goes on the moon if projected with same velocity is [g_("moon")=(g_("earth"))/(6)] |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> m<br/>80 m<br/>100 m<br/>120 m </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |