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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39451. |
A metal metre scale gives correct measurement at 0^(@) C. It is generally used at a temperature of 40^(@) C. The correction to be made for every metre is ( alpha = 10^(-6) //1^(@) C) |
| Answer» <html><body><p>`4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) m`<br/>`4 xx 10^(-5) ` m to be <a href="https://interviewquestions.tuteehub.com/tag/added-367625" style="font-weight:bold;" target="_blank" title="Click to know more about ADDED">ADDED</a> <br/>`4 xx 10^(-5)` m must be deducted<br/>None of the above</p>Answer :B</body></html> | |
| 39452. |
A tank of height 5 m is full of water. There is a hole of cross-sectional area 1cm^(2) in its bottom. The volume of water that will come out from this hole per second is (g=10m//s^(2)) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3)m^(3)//s`<br/>`10^(-4)m^(3)//s`<br/>`10m^(3)//s`<br/>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)m^(3)//s`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39453. |
Speed of sound in air is 331 ms^(-1) at 0^(@)C. Prove that it increases at a rate of 0.6 ms^(-1).^(@)C^(-1) for small temperature increase. |
| Answer» | |
| 39454. |
A mass 'm' attached to a spring oscillates with a period 2 seconds when the mass is increased by 2kgthe period increases by 1 second. The initial mass 'm' is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/4kg-318964" style="font-weight:bold;" target="_blank" title="Click to know more about 4KG">4KG</a><br/>`1.6kg`<br/>`0.8kg`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2kg-300729" style="font-weight:bold;" target="_blank" title="Click to know more about 2KG">2KG</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39455. |
A light ray is incident normally on a glass slab of thickness t and refractive index mu as shown in the figure. Then find time taken by the light ray to travel through the slab. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XII_V02_A_C02_SLV_020_S01.png" width="80%"/> <br/> From the figure distance <a href="https://interviewquestions.tuteehub.com/tag/travelled-7256865" style="font-weight:bold;" target="_blank" title="Click to know more about TRAVELLED">TRAVELLED</a> by the <a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> ray through the <a href="https://interviewquestions.tuteehub.com/tag/slab-1211590" style="font-weight:bold;" target="_blank" title="Click to know more about SLAB">SLAB</a> is t. <br/> Velocity of light in glass `=(distance travell ed) / (<a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a>)` <br/> `c/mu=t/ (time) , time = (mu t)/c`</body></html> | |
| 39456. |
An unknown planet orbits the sun with distance twice the semi major axis distance of the Earth's orbit. It the Earths time period is T_(1) , what is the time period of this period is planet? |
| Answer» <html><body><p></p>Solution :By Kepler.s 3rd <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a>`T^(2)prop a^(3)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> periodof unknownplanet = `T_(2)`<br/> Time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of <a href="https://interviewquestions.tuteehub.com/tag/earth-13129" style="font-weight:bold;" target="_blank" title="Click to know more about EARTH">EARTH</a> =`T_(1)` <br/> Distance of unknown <a href="https://interviewquestions.tuteehub.com/tag/planet-1155613" style="font-weight:bold;" target="_blank" title="Click to know more about PLANET">PLANET</a> from the Sun= `a_(2)` <br/>`(T_(1)^(2))/(T_(2)^(2)) = (a_(1)^(2))/(a_(2)^(3))`<br/> `T_(2) = ((a_(2))/(a_(1)))^(3/2)T_(1)""a_(2)=2a`<br/> `T_(2) = ((2a_(1))/(a_(1)))^(3/2)T_(1) rArrT_(2) =2sqrt(2)T_(1)`</body></html> | |
| 39457. |
Assertion : The moment of inertia of a rigid body reduces to its minimum value, when the axis of rotation passes through its centre of gravity. Reason : The weight of a rigid body always acts through its centre of gravity. |
| Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and reason are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and reason is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of assertion.<br/>If both assertion and reason are true but reason is not the correct explanation of assertion<br/>If assertion is true but reason is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>.<br/>If both assertion and reason are false. </p>Solution :By theorem of <a href="https://interviewquestions.tuteehub.com/tag/parallel-1146369" style="font-weight:bold;" target="_blank" title="Click to know more about PARALLEL">PARALLEL</a> axis both statements are correct and reason is the correct explanation of assertion.</body></html> | |
| 39458. |
What is the period of a simple pendulum whose length is 50 cm? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T=2pisqrt(l//g) = <a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(0.5//9.8)` = 1.42 <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a></body></html> | |
| 39459. |
A beaker full of hot water is kept in a room. It cools from 80^(@) C " to " 75^(@)Cin t_(1)minutes, 75^(@) C to 70^(@)Cin t_(2) minutes and 70^(@)C " to " 65^(@)C in t_(3) minutes in the same surroundings. Then |
| Answer» <html><body><p>`t_(1) = t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = t_(3)`<br/>`t_(1) lt t_(2) lt t_(3)` <br/>`t_(1) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> t_(2) gt t_(3)` <br/>`t_(1) lt t_(2) = t_(3)` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39460. |
In a given process on an ideal gas, dW = 0and dQ lt 0. Then for the gas |
| Answer» <html><body><p>The temperature <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> <br/>The <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> increases<br/>The <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> remains constant <br/>The temperature increases</p>Answer :A</body></html> | |
| 39461. |
Two bodies of masses m_(1) and m_(2) are initially at rest a infinite distance apart. They are then allowed to move towards each other under mutual gravitaitonal attraction. Their relative velocity of approach at a separation distance r between them is |
| Answer» <html><body><p>`[2G((m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)-m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)))/(r)]^(1//2)`<br/>`[(2G)/(r)(m_(1)+m_(2))]^(1//2)`<br/>`[(r)/(2G(m_(1)m_(2)))]^(1//2)`<br/>`[(2G)/(r)m_(1)m_(2)]^(1//2)`</p>Answer :B</body></html> | |
| 39462. |
What is free fall of a body ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> of a body falling <a href="https://interviewquestions.tuteehub.com/tag/towardsthe-3226665" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDSTHE">TOWARDSTHE</a> Earth froma small altitude `(h lt lt R)`, <a href="https://interviewquestions.tuteehub.com/tag/purely-2962981" style="font-weight:bold;" target="_blank" title="Click to know more about PURELY">PURELY</a> under the force of gravity is <a href="https://interviewquestions.tuteehub.com/tag/called-907796" style="font-weight:bold;" target="_blank" title="Click to know more about CALLED">CALLED</a> free fall.</body></html> | |
| 39463. |
A block of mass m is resting on an inclined plane. The inclination of the plane to the horizontal is gradually increased. It is found that when angle of inclination is theta , the block just begins to slide down the plane. What is the minimum force F applied parallel to the plane that would just make the block move up the plane? |
| Answer» <html><body><p>`2mgsin <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>`<br/>`mg sintheta`<br/>`mg <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> mgcos theta`</p>Solution :`2mgsin theta`</body></html> | |
| 39464. |
Which of the following is a dimensionless quantity? |
| Answer» <html><body><p> Specific heat<br/> Strain<br/> Quantity of heat <br/> Stress</p>Solution :`"Strain"= ("<a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in length")/("Orginal length")= ([L])/([L])= [L^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)]` <br/> <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> strain is a dimensionless quantity.</body></html> | |
| 39465. |
Which one of the following pairs of physical quantities do not have the same dimensions? |
| Answer» <html><body><p>Work and energy<br/>Strain and angle<br/>Stress and pressure<br/><a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> and surface tension.</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/dimensions-439808" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONS">DIMENSIONS</a> of tension `=[MLT^(-2)]` <br/>Dimensions of surface tension `=[<a href="https://interviewquestions.tuteehub.com/tag/mt-566013" style="font-weight:bold;" target="_blank" title="Click to know more about MT">MT</a>^(-2)]`</body></html> | |
| 39466. |
Rocket is the only means of travel in space - explain. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Usually, a <a href="https://interviewquestions.tuteehub.com/tag/vehicle-1444426" style="font-weight:bold;" target="_blank" title="Click to know more about VEHICLE">VEHICLE</a> applies some force on its surrounding objects, the reaction force exerted by those objects on the vehicle is actually responsible for its motion. <br/> On the other hand, let a system of two comparable masses be initially at rest , so that the total momentum is zero. let one of the masses be somehow detached, and allowed to move with a certain momentum in a definite <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a>. then the other mass would acquire an equal momentum in the opposite direction.Hence, the total momentum will <a href="https://interviewquestions.tuteehub.com/tag/still-653256" style="font-weight:bold;" target="_blank" title="Click to know more about STILL">STILL</a> be zero. i.e., be conserved. in this way, the masses can acquire motion without any external force, and without the aid of the surrounding objects. <br/> A rocket in space utilises this principle. the spaceship and the fuel constitude the two different masses. As the fuel is ejected backwards, the spaceship successfully moves forward. It should be noted that , in space, (1) on external force can be applied on a vehicle, and (2) the vacuum in outer space can provide no surrounding object.A rocket is, therefore, the only <a href="https://interviewquestions.tuteehub.com/tag/means-1091780" style="font-weight:bold;" target="_blank" title="Click to know more about MEANS">MEANS</a> of travel in outer space.</body></html> | |
| 39467. |
A uniform rope of length 12 m and mass6 kg hangs vertically from a rigid support . A block of mass2 kg is attached to the free end of the rope . A transverse pulse of wavelengths 0.06 m is produced at the lower end of the rope . What is the wavelength of the pulse when it reaches the top of the rope? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Tension at the <a href="https://interviewquestions.tuteehub.com/tag/lower-1080637" style="font-weight:bold;" target="_blank" title="Click to know more about LOWER">LOWER</a> end of the rope , <br/> `T_(1) = 2 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> = 2 xx 9.8 = 19.6 N` <br/> Tension at the upper end of rope , <br/> Let `v_(1) and v_(2)` be the <a href="https://interviewquestions.tuteehub.com/tag/speeds-650188" style="font-weight:bold;" target="_blank" title="Click to know more about SPEEDS">SPEEDS</a> of pulse at the lower and upper end , respectively . So <br/> `v = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a> (((T_(1))/(m))), v_(2) = sqrt(((T_(2))/(m)))` <br/> On dividing , we get <br/> `(v_(2))/( v_(1)) = sqrt(((T_(2))/( T_(1)))) = sqrt(((78.4)/(19.6))) = sqrt(4) = 2` <br/> As frequency is independent of medium , therefore if `lambda_(1) and lambda_(2)` are wavelengths at lower and upper ends respectively . Then <br/> `v_(1) = n lambda_(1) and v_(2) = n lambda_(2)` <br/> So, `(lambda_(2))/(lambda_(1)) = (v_(2))/( v_(1)) = 2` <br/> Therefore , the wavelength of pulse at upper end ` = 2 lambda`. <br/> `= 2 xx 0.06 = 0.12 m`</body></html> | |
| 39468. |
A 3m long ladder weighing 20 kg leans on a frictionless wall. Its feet rest on the floor 1 m from the wall as shown in Fig.7.27. Find the reaction forces of the wall and the floor. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_GUJ_PHY_XI_P1_C07_SLV_009_S01.png" width="80%"/> <br/> The ladder AB is 3 m long, its foot A is at distance `AC = 1 m` from the wall. From Pythagoras theorem, `BC = 2 <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2) m`. The forces on the ladder are its weight W acting at its centre of gravity D, reaction forces `F_(1) and F_(2)` of the wall and the floor respectively. <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> `F_(1)` is perpendicular to the wall, <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> the wall is frictionless. Force `F_(2)`is resolved into two components, the normal reaction N and the force of friction F. Note that F <a href="https://interviewquestions.tuteehub.com/tag/prevents-605529" style="font-weight:bold;" target="_blank" title="Click to know more about PREVENTS">PREVENTS</a> the ladder from sliding away from the wall and is therefore directed toward the wall. <br/> For translational equilibrium, taking the forces in the vertical direction, <br/> `N – W = 0` (i)<br/> Taking the forces in the horizontal direction, `F – F_(1) = 0` (ii) <br/> For <a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> equilibrium, taking the moments of the forces about A, <br/> `2sqrt(2)F_(1)-(1//2)W=0` (iii) <br/> Now `W = 20 g = 20 × 9.8 N = 196.0 N` <br/> From (i) `N = 196.0 N` <br/> From (iii) `F_(1)=W//4sqrt(2)=196.0//4sqrt(2)=34.6N` <br/> From (ii) `F=F_(1)=34.6N` <br/> `F_(2)=sqrt(F^(2)+N^(2))=199.0N` <br/> The force `F_(2)` makes an angle `α` with the horizontal, <br/> `tanalpha=N//F=4sqrt(2),alpha=tan^(-1)(4//sqrt(2))~~80^(@)`</body></html> | |
| 39469. |
(A) : At critical temperature, surface tension of a liuid becomes zero. (R ) : At this temperature, intermolecular forces for liquids and gases become equal. Liquid can expand without any restriction. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are true and (R ) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>Both (A) and (R ) are false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39470. |
The body projected with velocity 30ms^(-1) reaches its maximum height in 1.5s. Find its range (g=10ms^(-2)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a> m</body></html> | |
| 39471. |
Why can.t two persons each of say 100 kg standing 1m a part experience any gravitational attractionbetween them? |
| Answer» <html><body><p></p>Solution : <a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to Newton.s law of gravitation the force of <a href="https://interviewquestions.tuteehub.com/tag/attraction-887653" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTION">ATTRACTION</a> between the two persons turns out to be `10^(-7) N`which is very very small. Hence the persons in question do not experience the <a href="https://interviewquestions.tuteehub.com/tag/minute-1098123" style="font-weight:bold;" target="_blank" title="Click to know more about MINUTE">MINUTE</a> force that exists between them.</body></html> | |
| 39472. |
Two masses M_(1) and M_(2) connected by means of a string which is made to pass over light, smooth pulley are in equilibrium on a fixed smooth wedge as shown in figure. If theta = 60^(@) and alpha = 30^(@), the ratio of M_(1) to M_(2) is |
| Answer» <html><body><p>`1:2`<br/>`2:<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/>`1:sqrt(3)` <br/>`sqrt(3):1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39473. |
A particle in SHM is described by the displacement function, X(t) = B sin (omega t + alpha), omega (2pi)/T. If the initial (t = 0) position of the particle is lem and its initial velocity is pi cm//s, what are its amplitude uninitial phase angle ? The angular frequency of the particle is pi//s, nsqrt(2), mpi//4 then n & m are |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a></body></html> | |
| 39474. |
At 20^(@)C to attain the terminal velocity how fast will an aluminium sphere of radii I mm fall through water. Assume flow to be laminar flow and specific gravity (AI) -2.72 |
| Answer» <html><body><p>5m/s<br/>`4.6m//s`<br/>4m/s<br/>2m/s</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39475. |
Temperature of a body theta is slightly more than the temperature of the surroundings theta_(0). Its rate of cooling ( R ) versus temperature of body theta is plotted, its shape would be |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C04_E03_050_O01.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C04_E03_050_O02.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C04_E03_050_O03.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_PHY_XI_V01_D_C04_E03_050_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39476. |
The system as shown in fig is released from rest. Calculate the tension in the strings and force exerted by the strings on the pulley. Assuming pulleys and strings are massless |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T_(1)-1g=1a"____(1)"` <br/> `T_(2)-T_(1)=3a"____(2)"` <br/> `2g-T_(2)=<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a>"____(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)"` <br/> Solving the above equations, <br/> we get, `a=(g)/(6)m//s^(2)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_NEET_PHY_XI_P2_C05_SLV_031_S01.png" width="80%"/> <br/> `T_(1)=(7g)/(6)N, T+(2)=(5g)/(3)N` <br/> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> on pulley `P_(1)` is `F_(1)=sqrt(T_(1)^(2)+T_(1)^(2))` <br/> `=sqrt2T_(1)=(7g)/(3sqrt2)N` <br/> Force on pulley `P_(2)` is `F_(2)=sqrt(T_(2)^(2)+T_(2)^(2))` <br/> `=sqrt2T_(2)=(5sqrt2g)/(3)N`</body></html> | |
| 39477. |
Figure below shows two paths that may be taken by a gas to go from state A to a state C. In process AB, 400 Jof heat is added to the system and in proces BC, 100 J of heat isadded to the system. The heat absorbed by the system in the process AC will be |
| Answer» <html><body><p>460 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/>300 J<br/><a href="https://interviewquestions.tuteehub.com/tag/380-310180" style="font-weight:bold;" target="_blank" title="Click to know more about 380">380</a> J<br/>500 J</p>Solution :As initial and final points are same so `Delta U_(ABC) = Delta U_(AC)` <br/> AB is isochoric <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a>. `Delta W_(AB) = 0` <br/> `Delta Q_(AB) = Delta U_(AB) = 400 J` <br/> B is isobaric process. <br/> `Delta Q_(BC) = Delta U_(BC) + Delta W_(BC)` <br/> `100 = Delta U_(BC) + <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx 10^(4)` <br/> `(4 xx 10^(-3) - 2 xx 10^(-3))` <br/> `100 = Delta U_(BC) + 12 xx 10` <br/> `Delta U_(BC) = 100 - <a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a> = -20 J` <br/> As, `Delta U_(ABC) = Delta U_(AC)` <br/> `Delta U_(AB) + Delta U_(BC) = Delta Q_(AC) - Delta W_(AC)` <br/> `400 - 20 = Delta Q_(AC) - (2 xx 10^(4) xx 2 xx 10^(-3) + (1)/(2) xx 2 xx 10^(-3) xx 4 xx 10^(4))` <br/> `380 = Delta Q_(AC) - (40 + 40), Delta Q_(AC) = 380 + 80 = 460 J` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MTG_NEET_GID_PHY_XI_C08_E03_014_S01.png" width="80%"/></body></html> | |
| 39478. |
Pressure at a point inside a liquid does not depend on |
| Answer» <html><body><p>the nature of the liquid<br/>shape of the container <br/>the depth of point below the <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> of the liquid<br/>acceleration <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> at that point</p>Answer :B</body></html> | |
| 39479. |
The shadow of a pole standing on a level around is found to be 45 m longer when the Sun's altitude is 30^(@) than when it was 60^(@). Determine the height of the pole. [Given sqrt(3) = 1.73] |
| Answer» <html><body><p></p>Solution :Solution `(x-45)/(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>) = <a href="https://interviewquestions.tuteehub.com/tag/cot-936468" style="font-weight:bold;" target="_blank" title="Click to know more about COT">COT</a> 30^(@) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> h = (x+45)/(cot 30^(@))` <br/> `x/h = cot 60^(@)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> the value of x in the above equation <br/> `h = (h cot 60^(@) + 45)/(cot 30^(@))` <br/> `h cot 30^(@) = h cot 60^(@) + 45` <br/> `h = (45)/(cot 30^(@) - cot 60^(@)) = (45)/(sqrt(3) - (1)/(sqrt(3))) = 38.97` m</body></html> | |
| 39480. |
A calorimeter full of hot water is hung in vaccum. It will |
| Answer» <html><body><p>Cool by <a href="https://interviewquestions.tuteehub.com/tag/conduction-928825" style="font-weight:bold;" target="_blank" title="Click to know more about CONDUCTION">CONDUCTION</a> <br/>Cool by <a href="https://interviewquestions.tuteehub.com/tag/convection-425641" style="font-weight:bold;" target="_blank" title="Click to know more about CONVECTION">CONVECTION</a> <br/>Cool by <a href="https://interviewquestions.tuteehub.com/tag/radiation-1175811" style="font-weight:bold;" target="_blank" title="Click to know more about RADIATION">RADIATION</a> <br/>Not cool at all </p>Answer :C</body></html> | |
| 39481. |
A rod of length 1 m having cross-sectional area 0.75m^(2) conducts heat at 6000Js^(-1). Then the temperature difference acorss the rod is, if K=200Wm^(-1)K^(-1) |
| Answer» <html><body><p>`20^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>^(0)C`<br/>`80^(0)C`<br/>`100^(0)C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39482. |
A square plate of side length 2m has a groove made in the shape of two quarter circles joining at the centre of the plate. The plate is free to rotate about vertical axis passing through its centre. The moment of inertia of the plate about this axis is 4 kg - m^(2). A small block of mass 1 kg enters the groove at end A travelling with a velocity of 2//s parallel to the side of the square plate. The block move along the frictionless groove of the horizontal plate and comes out at the other end B with speed V. Find V assuming that width of the groove is negligible. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) m//s`</body></html> | |
| 39483. |
The period of a simple pendulum suspended from the ceiling of a car is T when the car is at rest. If the car moves with a constant acceleration the perod of the pendulum |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/unaltered-7384523" style="font-weight:bold;" target="_blank" title="Click to know more about UNALTERED">UNALTERED</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> <br/>None</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39484. |
Consider a uniform U-tube with a diaphragm at the bottom and filled with a liquid to different heights in each limb as shown in Fig. Now imagine that the diaphragm is punctured so that the liquid flows from left to right. (a) Show that the application of Bernoulli's particle to points (1) and Diaphragm (2) leads to a constradiction. (b) Explain why Bernoulli's principle is not applicabe here |
| Answer» <html><body><p></p>Solution : <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> the height of the liquid in the <a href="https://interviewquestions.tuteehub.com/tag/limbs-1073960" style="font-weight:bold;" target="_blank" title="Click to know more about LIMBS">LIMBS</a> (1) and (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) be` y_1 and y_2` and the velocity of the liquid be `v_1 and v_2` respectively. Applying Bernoulli.s equation to the points (1) and (2) <br/> ` "" P + (1)/(2) rho v_1^(2)= P+ (1)/(2)rho v_2^(2)+ rho gy_2` <br/>Where P is the atmospheric pressure <br/>But ` ""v_1 =v_2=0 ` <br/>` therefore ""rho gy_1= rho gy_2` <br/> `"" y_1= y_2` <br/>This is a contradictionbecause `y_1 ` is not equal to `y_2` <br/> (b)Bernouli.s <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a> cannot be applied here because the flow is not steady.</body></html> | |
| 39485. |
If |vecAxxvecB|=sqrt(3)vecA*vecB, then |vecA+vecB|=? |
| Answer» <html><body><p>`(A^2+B^2+<a href="https://interviewquestions.tuteehub.com/tag/ab-360636" style="font-weight:bold;" target="_blank" title="Click to know more about AB">AB</a>)^(1/2)`<br/>`(A^2+B^2+(AB)/<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))^(1/2)`<br/>`A+B`<br/>`(A^2+B^2+sqrt(3)AB)^(1/2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39486. |
Figureshows a plot of the transverse displacements of the particles of a string at t = 0 through which a travelling wave is passing in the positive x-direction. The wave speed is 20 cms^-1. Find (a) the amplitude, (b) the wavelength, (c) the wave number and (d) the frequency of the wave.. |
| Answer» <html><body><p><br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> that `v=20cm/s` <br/> a. amplitude `A=1mm` <br/>b. `Wavelength <a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a>=4cm` <br/> c. Wave <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> `<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>=(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/lamda` <br/> `=((2xx3.14))/4` <br/> `=1.57cm^-1` <br/> `(wave number =k)` <br/> d. Frequencey `f=1/T=20/4=5Hz` <br/> `(where time period T=lamada/v)`</body></html> | |
| 39487. |
A car is travelling in steady rain with constant acceleration in a stright line. When it begins to move the driver sees tha the rain drops make track an an angle of 37^(@) with the vertical. After 20 sec the rain drops make track at an angle 53^(@) with vertical in same direction . Rain is falling at 3 m/s. Find acceleration of car in cm//s^(2) |
| Answer» <html><body><p> <br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a></body></html> | |
| 39488. |
A small particle of mass on is projected with an initial velocity v at an angle 8 with x axis in X-Y plane as shown in Figure. Find the angular momentum of the particle. |
| Answer» <html><body><p></p>Solution :Let the particle of mass m cross a horizontal distance x in time t. <br/> <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> momentum `vecL= int vec <a href="https://interviewquestions.tuteehub.com/tag/tau-663951" style="font-weight:bold;" target="_blank" title="Click to know more about TAU">TAU</a> dt` <br/>But `vectau= vecr xx vec F` <br/> `vecr=xhati+yhatj and vecF=-mg hatj` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V01_C05_SLV_028_S01.png" width="80%"/> <br/> `:. Tau=(x hati+y hatj)xx(hati xx hatj)=-mgx hatk` <br/> `vecL=-mg int (x dt) hatk=- mgv cos theta( intdt) hatk)` <br/> Let <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> time =0 and final time `t=t_(1)` <br/> `:. vecL= mgv cos theta( underset(0) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(t_(f)) int t dt) hatk=-(1)/(2) mgv cos theta t_(f)^(2) hatk` <br/> Negative <a href="https://interviewquestions.tuteehub.com/tag/sign-1207134" style="font-weight:bold;" target="_blank" title="Click to know more about SIGN">SIGN</a> indicates, `vecL` point inwards</body></html> | |
| 39489. |
A proton is kept at rest. A positively charged particle is released from rest at a distance .d. in its field. Consider two experiments, one in which the charged particle is a proton and in another a position. In the same time .t. the work done on the two moving charged particles is |
| Answer» <html><body><p>Same as the same force law is <a href="https://interviewquestions.tuteehub.com/tag/involved-7257329" style="font-weight:bold;" target="_blank" title="Click to know more about INVOLVED">INVOLVED</a> in the two experiments <br/>Less for the <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> of a positron, as the positorn moves away more rapidly and the force on it weakens <br/>More for the case of a position, as the positron moves an a <a href="https://interviewquestions.tuteehub.com/tag/larger-1067345" style="font-weight:bold;" target="_blank" title="Click to know more about LARGER">LARGER</a> distance <br/>Same as the work done by charged particle on the stationary <a href="https://interviewquestions.tuteehub.com/tag/proton-1170983" style="font-weight:bold;" target="_blank" title="Click to know more about PROTON">PROTON</a>. </p>Answer :C</body></html> | |
| 39490. |
A wire of length L and radius r is clamped rigidly at one end. When the other end of the wire is pulled by a force f its length increases by l. Another wire of the same material of length 2L and radius 2r is pulled by a force 2f. Then find the increase in length of this wire. |
| Answer» <html><body><p>`l/2`<br/>`l`<br/>`2l`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/4l-318786" style="font-weight:bold;" target="_blank" title="Click to know more about 4L">4L</a>`</p>Solution :`Y = (<a href="https://interviewquestions.tuteehub.com/tag/fl-462549" style="font-weight:bold;" target="_blank" title="Click to know more about FL">FL</a> )/( Al) = (f L )/( pi <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ^(2)l )` <br/> `therefore l = ( fL )/( pi r ^(*2) Y)` <br/> Now for increase in <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> for second wire, <br/> `l . = ((2 f ) (2L ))/( pi (2r) ^(2) l )= (<a href="https://interviewquestions.tuteehub.com/tag/4f-318725" style="font-weight:bold;" target="_blank" title="Click to know more about 4F">4F</a> L )/( 4pi r ^(2) l )` <br/> `l .=l`</body></html> | |
| 39491. |
A manometer contains a liquid of density rho. The difference in the levels when the manometer rotates at a constant angular velocity omega about one of its vertical limbs. (Let 1 be the length of horizontal tube) |
| Answer» <html><body><p>`( omega^(2) l^(2) )/( 2g)`<br/>`( omega^(2) l^(2) )/( <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)`<br/>`( 2 omega^(2) l^(2) )/( g)`<br/>`( 3 omega^(2) l^(2) )/( g)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39492. |
Unit of impulse of force and energy gradient are equal. |
| Answer» <html><body><p><br/></p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>. Unit of impulse of force is Ns where s unit if energy <a href="https://interviewquestions.tuteehub.com/tag/gradient-13951" style="font-weight:bold;" target="_blank" title="Click to know more about GRADIENT">GRADIENT</a>, <br/> `(U/y=-F)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>`</body></html> | |
| 39493. |
The angular velocityof the earth about its polar axis so that the weight of the body at the equator will be zero is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.25xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) "<a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> s"^(-1)`<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> rad `s^(-1)`<br/>1 rad `s^(-1)`<br/>0</p>Answer :A</body></html> | |
| 39494. |
A cylindrical container has mass M and height H. the centre of mass of the empty container is at height (H)/(2) from the base. A liquid, when completley filled in the container, has mass (M)/(2) this liquid is poured in the empty contaienr. (a) How does the centre of mass of the system (container+liquid) move as the height (x) of liquid column changes from zero to H? Explain your answer qualitatively. Draw a graph showing the variation of height of centre of mass of the system (x_(cm)) with x. (b) Find the height of liquid column x for which the centre of mass is at its lowest position. |
| Answer» <html><body><p><br/></p>Answer :(a) The COM first <a href="https://interviewquestions.tuteehub.com/tag/falls-983294" style="font-weight:bold;" target="_blank" title="Click to know more about FALLS">FALLS</a> attains a minimum <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> and then it rises to original height `(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> (b) `x=(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(6)-2)H`</body></html> | |
| 39495. |
Two cars moving with speeds 40 km/hr and 80 km/hr respectively with uniform acceleration. How many times the stopping distance of car with 80 km/hr is greater than another car ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Four times <a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>, <br/> `d = (v _(0) ^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(2a)`</body></html> | |
| 39496. |
All particles of a body are situated at a distance R from the origin. The distance of centre of mass of the body from the orign is |
| Answer» <html><body><p>`=<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/ler-2156291" style="font-weight:bold;" target="_blank" title="Click to know more about LER">LER</a>`<br/>`gtR`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/ger-468132" style="font-weight:bold;" target="_blank" title="Click to know more about GER">GER</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39497. |
A planet revolves around sun in an elliptical orbit of ecentricity 'e'. If 'T' is the time period of the planet then show that the time spent by the planet between the end of the minor axis and close to sun it T((1)/(4)-(e)/(2pi)) |
| Answer» <html><body><p></p>Solution :`(dA)/(d t)` = constant, <br/> `(t_(AB))/(T) = ("(Area) SAB")/("(Area) ellipse") = ((<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> ab)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)-(1)/(2)b(ea))/(pi ab)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_SLV_002_S01.png" width="80%"/></body></html> | |
| 39498. |
At the same temperature a drop of water of diameter 1 mm is broken into 10^6 equal water droplets of spherical shape. How much mechanical work should be done in forming the new surface area ? Surface tension of water =0.074 N. m^-1. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`230xx10^-7 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`</body></html> | |
| 39499. |
A force of 10 N acts on a body of mass 1.0 kg at rest. Find the work done in 4 seconds. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :F = 10 N,m = 1.0 kg , u = 0, t = 4s, acceleration `a = (F)/(m) xx (10)/(1) = <a href="https://interviewquestions.tuteehub.com/tag/10ms-267176" style="font-weight:bold;" target="_blank" title="Click to know more about 10MS">10MS</a>^(-1)`. <br/> Its displacement `S=ut+(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)at^(2)=0+(1)/(2)(10)4^(2)=80m` <br/> The work done W = FS = <a href="https://interviewquestions.tuteehub.com/tag/mas-1088358" style="font-weight:bold;" target="_blank" title="Click to know more about MAS">MAS</a> = `1.0 xx 10 xx <a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a> = 800j`</body></html> | |
| 39500. |
A man coveres 60 cm distance in one minute on the surface of earth. The distance he will cover on the surface of moon in one minute is(g_(m) = (g_(e))/(6)) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> m<br/>`60 xx <a href="https://interviewquestions.tuteehub.com/tag/6m-332078" style="font-weight:bold;" target="_blank" title="Click to know more about 6M">6M</a>`<br/>`(60)/(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) m`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(60) m`</p>Answer :A</body></html> | |