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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39551. |
A uniform rope of length 10 m and mass 3 kg hangs vertically from a rigid support. A block of mass 1 kg is attached to the free end of the rople. A transverse pulse of wavelength 0.05 m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is |
| Answer» <html><body><p>0.10 m<br/>0.12 m<br/>0.16 m<br/>0.18 m </p>Solution :Since the <a href="https://interviewquestions.tuteehub.com/tag/rope-1191046" style="font-weight:bold;" target="_blank" title="Click to know more about ROPE">ROPE</a> has a mass, the tension <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> its length is <a href="https://interviewquestions.tuteehub.com/tag/variable-1442996" style="font-weight:bold;" target="_blank" title="Click to know more about VARIABLE">VARIABLE</a>. At the top end, its tension is `(3+1)g N` or `4g N`. At the bottom end, its tension is 1g N. <br/> Now, <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of the <a href="https://interviewquestions.tuteehub.com/tag/transverse-1426606" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSVERSE">TRANSVERSE</a> wave on the string, `c=sqrt((T)/(mu))` <br/> `upsilonlambda=sqrt((T)/(mu))""(because c=upsilonlambda)` <br/> As frequency `upsilon and mu`, the linear density are constant, so `sqrt(T)/(lambda)`is a constant.</body></html> | |
| 39552. |
The least count of stop watch is 0.5s. The time of 40 oscillation of the pendulum is found to be 40s. The percentage error in the measurement of time period is ……………… % |
| Answer» <html><body><p>0.75<br/>0.5<br/>1.25<br/>0.25</p>Solution :`"Least <a href="https://interviewquestions.tuteehub.com/tag/count-936718" style="font-weight:bold;" target="_blank" title="Click to know more about COUNT">COUNT</a> = 0.5a"` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/deltat-2053483" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAT">DELTAT</a>=0.5a` <br/> `T=<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>` <br/> `%" <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> "=(DeltaT)/(T)xx100` <br/> `=(0.5)/(40)xx100=(<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>)/(40)=1.25`</body></html> | |
| 39553. |
Find the moment of inertia andradius of gyration of uniform cross-section rod of mass 4 kg and length 90 cm about an axis through one end and perpendicular to the length of rod. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`I=1.08 <a href="https://interviewquestions.tuteehub.com/tag/kgm-2769156" style="font-weight:bold;" target="_blank" title="Click to know more about KGM">KGM</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>),k=0.5196m`</body></html> | |
| 39554. |
A king ordered his Goldsmith to make a crown which should be of pure gold. SO the goldsmith to made a crown of pure gold & brought it to king. but the king was not contended with the crown as he suspected whether it is made of pure gold or not. So he called for Archimedes and asked him to check whether it is a pure gold crowm. Archimedes was serious about this and went his home thinking how to solve this issue. He wanted to take bath, all of a sudden the jumped on to the bath tub. Water inside the tub had splashed out of it. An idea striked him suddenly he went running naked straight from his bathroom to the king's pace shouting Eureka Eureka on the road side. From this what do we infer ? State Archimedes principle. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/archimedes-381352" style="font-weight:bold;" target="_blank" title="Click to know more about ARCHIMEDES">ARCHIMEDES</a> discovered that the weight of his body is equal to the weight of the displaced (splashed) liquid out of the tub. So Archemedes principle was the out come of this incidence, heer 'Eurcka' <a href="https://interviewquestions.tuteehub.com/tag/means-1091780" style="font-weight:bold;" target="_blank" title="Click to know more about MEANS">MEANS</a> I have <a href="https://interviewquestions.tuteehub.com/tag/found-458144" style="font-weight:bold;" target="_blank" title="Click to know more about FOUND">FOUND</a> out. <br/> Archimedes Principle <a href="https://interviewquestions.tuteehub.com/tag/states-1225920" style="font-weight:bold;" target="_blank" title="Click to know more about STATES">STATES</a> that, when a body is partially or wholly immersed in a fluid, it experiences an upward <a href="https://interviewquestions.tuteehub.com/tag/thrust-709467" style="font-weight:bold;" target="_blank" title="Click to know more about THRUST">THRUST</a> equal to the weight of the fluid displaced by it. <br/> i.e. `V rho g = mg`.</body></html> | |
| 39555. |
A king ordered his Goldsmith to make a crown which should be of pure gold. SO the goldsmith to made a crown of pure gold & brought it to king. but the king was not contended with the crown as he suspected whether it is made of pure gold or not. So he called for Archimedes and asked him to check whether it is a pure gold crowm. Archimedes was serious about this and went his home thinking how to solve this issue. He wanted to take bath, all of a sudden the jumped on to the bath tyb. Water inside the tub had splashed out of it. An idea striked him suddenly he went running naked straight from his bathroom to the king's pace shouting Eureka Eureka on the road side. From this what do we infer ? How Archimeded would have solved this problem ? |
| Answer» <html><body><p></p>Solution :Archimedes discovered that the weight of his <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> is equal to the weight of the displaced (splashed) liquid out of the tub. So Archemedes <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a> was the out come of this incidence, heer 'Eurcka' means I have found out. <br/> (i) Archimedes was told by the goldsmith about the quantity of gold used in the crown. So he took that much <a href="https://interviewquestions.tuteehub.com/tag/amount-374803" style="font-weight:bold;" target="_blank" title="Click to know more about AMOUNT">AMOUNT</a> Gold and immersed in water and measured its original weight. Then, when he immersed the crown, the weight of the actual gold was not shown by the duplicate gold crown, from this he guessed, the goldsmith had made the crown with some other metals too along with Gold. (i.e. <a href="https://interviewquestions.tuteehub.com/tag/impure-1039183" style="font-weight:bold;" target="_blank" title="Click to know more about IMPURE">IMPURE</a> gold). Goldsmith was caught <a href="https://interviewquestions.tuteehub.com/tag/red-613739" style="font-weight:bold;" target="_blank" title="Click to know more about RED">RED</a> handed by the king.</body></html> | |
| 39556. |
Raman got Nobel prize in Physics for |
| Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/scattering-18435" style="font-weight:bold;" target="_blank" title="Click to know more about SCATTERING">SCATTERING</a> of <a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a><br/>Atmospheric pressure - <a href="https://interviewquestions.tuteehub.com/tag/barometer-394088" style="font-weight:bold;" target="_blank" title="Click to know more about BAROMETER">BAROMETER</a><br/> <a href="https://interviewquestions.tuteehub.com/tag/reflection-13747" style="font-weight:bold;" target="_blank" title="Click to know more about REFLECTION">REFLECTION</a> of light<br/> refraction of light</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/raman-618154" style="font-weight:bold;" target="_blank" title="Click to know more about RAMAN">RAMAN</a> got Nobel prize for Raman effect, which deals with scattering of light.</body></html> | |
| 39557. |
Moment of inertia of a ring is minimum |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/bout-903241" style="font-weight:bold;" target="_blank" title="Click to know more about BOUT">BOUT</a> its <a href="https://interviewquestions.tuteehub.com/tag/geometric-472345" style="font-weight:bold;" target="_blank" title="Click to know more about GEOMETRIC">GEOMETRIC</a> axis<br/>about a diameter<br/>about a <a href="https://interviewquestions.tuteehub.com/tag/tangent-1238980" style="font-weight:bold;" target="_blank" title="Click to know more about TANGENT">TANGENT</a> in its plane<br/>tangent <a href="https://interviewquestions.tuteehub.com/tag/perpendicular-598789" style="font-weight:bold;" target="_blank" title="Click to know more about PERPENDICULAR">PERPENDICULAR</a> to its plane</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39558. |
The dimensions of universal gravitational constant are |
| Answer» <html><body><p>`[M^(-1) L^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) T^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)]`<br/>`[ML^(2) T^(-1) ]`<br/>`[M^(-2) L^(3) T^(-2) ]`<br/>`[M^(-2) L^(2) T^(-1) ]`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39559. |
For a car taking a turn on a horizontal surface, let N_(1) and N_(2) be the normal reactions of the road on the inner and outer wheels respectively. |
| Answer» <html><body><p>`N_(1)` is always greater than `N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/>`N_(2)` is always greater than `N_(1)` <br/>`N_(1)` is always equal to `N_(2)` <br/>Either (a) or (b) <a href="https://interviewquestions.tuteehub.com/tag/depending-7263846" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDING">DEPENDING</a> on the speed of the car and the radius of <a href="https://interviewquestions.tuteehub.com/tag/curvature-20184" style="font-weight:bold;" target="_blank" title="Click to know more about CURVATURE">CURVATURE</a> of the road. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39560. |
If the temperature and pressure of a gas is doubled the mean free path of the gas molecules |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>remains same <br/>doubled <br/>tripled <br/>quadruples</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mean-1091459" style="font-weight:bold;" target="_blank" title="Click to know more about MEAN">MEAN</a> <a href="https://interviewquestions.tuteehub.com/tag/free-465311" style="font-weight:bold;" target="_blank" title="Click to know more about FREE">FREE</a> path of the <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> <br/> `gamma=(kT)/(sqrt2pid^(2)P` <br/> If T and P are double, `gamma=(2kT)/(sqrt2pid^(2)(2P))=(kT)/(sqrt2pid^(2)P)`</body></html> | |
| 39561. |
A body slides without friction from a height H = 60 cm and then loops the loop of radius R = 20 cm at the bottom of incline. The ratio of forces exerted on the body by the track at A,B and C are (g = 10 ms^(-2)) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> : <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> : <a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>`<br/>`7 : 4 : 1`<br/>`4 : 1 : 7`<br/>`7 : 1 : 4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39562. |
A block A of mass M moving with speed u collides elastically with block B of mass m which is connected to block C of mass m with a spring. When the compression in spring is maximum, the velocity of block C with respect to block A is (Neglect the friction everywhere) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`(M/(M+m))u`<br/>`(m/(M+m))u`<br/>`(m/M)u`</p>Solution :`v_(A) = (M-m)/(M+m) u and v_(B) = (<a href="https://interviewquestions.tuteehub.com/tag/2mu-1837999" style="font-weight:bold;" target="_blank" title="Click to know more about 2MU">2MU</a>)/(M+m)` <br/> Velocity of C at maximum <a href="https://interviewquestions.tuteehub.com/tag/compression-20610" style="font-weight:bold;" target="_blank" title="Click to know more about COMPRESSION">COMPRESSION</a> = `v_(B)/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` <br/> `v_(c) = 1/2[(2M)/(M+m)]u = (M/(M+m))u` <br/> `v_(CA) = v_(C)-v_(A) = (m/(M+m))u`</body></html> | |
| 39563. |
In the Fig, shown below with what angular speed 'omega' must 'm' with a radius 'r' rotate on a frictionless table so that 'M' does not move ? (b) If m = 1.0 kg, M = 10.0 kg and r = 0.5 m, find omega. |
| Answer» <html><body><p></p>Solution :(a) Tension in the <a href="https://interviewquestions.tuteehub.com/tag/string-11290" style="font-weight:bold;" target="_blank" title="Click to know more about STRING">STRING</a> = Weight of the hanging mass M.<br/>The tension in the string supplies the required <a href="https://interviewquestions.tuteehub.com/tag/centripetal-415325" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRIPETAL">CENTRIPETAL</a> force to the body of mass m to revolve in a circular orbit of radius r.<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C05_SLV_109_S01.png" width="80%"/><br/>`T=mr <a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`therefore mr omega^(2)=Mg`<br/><a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> speed,<br/>`omega = sqrt((Mg)/(mr))=sqrt((10xx9.8)/(1xx0.5))=sqrt(196)=14 rad s^(-1)`.</body></html> | |
| 39564. |
A triangular lamina made of aluminium is of the shape of an equilateral triangle of edge a = 10cm and surface mass density 500 g//m^(2). It is heated from 20°C to 50°C slowly. Determine the increase in its moment of inertia about any of its side. Coefficient of linear expansion of aluminium is 22.9 xx 10^(-6)//^(@) C. |
| Answer» <html><body><p><br/></p>Answer :`3.72 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>- cm^(2)`</body></html> | |
| 39565. |
What is the magnitude of the vec(GB) ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`vec(GB)=vec(OB)-vec(<a href="https://interviewquestions.tuteehub.com/tag/og-583305" style="font-weight:bold;" target="_blank" title="Click to know more about OG">OG</a>)` <br/> `=ahat(i)+bhat(<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>)-chat(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)` <br/> Thus, from now on we shall understand that `|vec(GB)|=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(a^(2)+b^(2)+c^(2))`</body></html> | |
| 39566. |
If a planet was suddenly stopped in its orbit supposed to be circular, show that it would fall onto the sun in a time equal to (sqrt2 //8)times the period of planet.s revolution. |
| Answer» <html><body><p></p>Solution :If M is mass of the <a href="https://interviewquestions.tuteehub.com/tag/sun-1234558" style="font-weight:bold;" target="_blank" title="Click to know more about SUN">SUN</a> and r is radius of the planet.s orbit, its orbital <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> is `V_0 = sqrt((GM)/(r ))`<br/>Orbital time period `T = (2pi r)/(v_0) " or " T^2 = (4pi^2 r^3)/(GM)`<br/> After stopping the planet, if it has velocity <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>, when it is at a distance x from the sun, from conservation of <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> energy,<br/>` 1/2 mv^2 - (GMm)/(x) = - (GMm)/(r ) <a href="https://interviewquestions.tuteehub.com/tag/ie-496825" style="font-weight:bold;" target="_blank" title="Click to know more about IE">IE</a>, - ((dx)/(dt))^2 = (2GM)/(r ) [ (r - x)/(x)]`<br/>`(-dx)/(dt) = sqrt((2GM)/(r )) sqrt((r-x)/(x)) ,int_0^t dt = - sqrt((r)/(2GM)) int_r^0 ( sqrt((x)/(r - x)) )dx ` After solving , we get `t = (sqrt2)/(8) T`</body></html> | |
| 39567. |
In case of a uniform ring of mass M and radius .R. match the following. {:("List-I",,"List-II"),("(A) Intensity of gravitational field at a distance x from its centre on its axis.",,(P) -(GM)/(sqrt(R^(2) + x^(2)))),("(B) Intensity of gravitational field at its centre " ,,(Q) -(GM)/(R)),("(C) Gravitational potential at its centre",,"(R) zero"),("(D) Gravitational potential at a distance x from its centre on its axis",,(S) (GMx)/((R^(2) + x^(2))^(3//2))):} |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A-S; B-R; C-Q; D-P</body></html> | |
| 39568. |
What is meant by an echo? Explain. |
| Answer» <html><body><p></p>Solution :An echo is a repetition of sound produced by the reflection of sound waves from a wall, <a href="https://interviewquestions.tuteehub.com/tag/mountain-565001" style="font-weight:bold;" target="_blank" title="Click to know more about MOUNTAIN">MOUNTAIN</a> or other obstructing surfaces. The speed of sound in air at `20^(@)`C is 344 `m s^(-1)`. If we <a href="https://interviewquestions.tuteehub.com/tag/shout-1206524" style="font-weight:bold;" target="_blank" title="Click to know more about SHOUT">SHOUT</a> at a wall which is at 344 m away, then the sound will take 1 second will take one more second to reach us. <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, we hear the echo after two seconds. <br/> Scientists have estimated that we can hear two <a href="https://interviewquestions.tuteehub.com/tag/sounds-1219274" style="font-weight:bold;" target="_blank" title="Click to know more about SOUNDS">SOUNDS</a> properly if the time gap or time interval between eachsound is `(1/10)^(th)` of a second (persistence of hearing) i.e., 0.1 s. Then, <br/> Velocity `=("Distance travelled")/("time taken") =(<a href="https://interviewquestions.tuteehub.com/tag/2d-300662" style="font-weight:bold;" target="_blank" title="Click to know more about 2D">2D</a>)/t` <br/> 2d= `344 xx 0.1 = 34.4` m<br/> d= 17.2 m<br/> The minimum distance from a sound reflecting wall to hear an echo at `20^(@)` C is 17.2 meter.</body></html> | |
| 39569. |
One car moving on a straight road covers one third of the distance with 20km//hr and the rest with 60 km//hr . The average speed is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a> km//hr`</body></html> | |
| 39570. |
A disc of mass 5 kg is kept floating horizontally in mid air by firing 10 bullets per second vertically up. If the mass of each bullet is 50 gm and bullets rebound with same speed, the speed of each bullet is, (g=10 ms^(-2)) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a> ms^(-1)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> ms^(-1)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ms^(-1)` </p>Answer :C</body></html> | |
| 39571. |
70 cal of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from 30°C to 35°C. What temperature of same gas through the same range at constant volume ?(R = 2 "cal/mole/K") |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/28-299271" style="font-weight:bold;" target="_blank" title="Click to know more about 28">28</a> J<br/>50 <a href="https://interviewquestions.tuteehub.com/tag/cal-412083" style="font-weight:bold;" target="_blank" title="Click to know more about CAL">CAL</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/75-334971" style="font-weight:bold;" target="_blank" title="Click to know more about 75">75</a> J<br/>Zero</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39572. |
A simple pendulum of length .l. carries a bob of mass m. If the breaking strength of the string is 2 mg, the maximum angular amplitude from the vertical can be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)`<br/>`90^(@)`</p>Answer :C</body></html> | |
| 39573. |
Two blocks are connected by a massless string that passes over a frictionless peg as shown in figure. One end of the string is attached to a mass m_1=3kg, i.e., a distance R=1.20m from the peg. The other end of the string is connected to a block of mass m_2=6kg resting on a table. From what angle theta, measured from the vertical, must the 3-kg block be released in order to just lift the 6kg block off the table? |
| Answer» <html><body><p><br/></p>Solution :This problem involves several concepts. First we will apply conservation of energy to find the <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of the <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> `m_1` at the bottom of the circular path as a function of `theta` and the radius of the path, R. <br/> From Newton's second law we will <a href="https://interviewquestions.tuteehub.com/tag/determine-437910" style="font-weight:bold;" target="_blank" title="Click to know more about DETERMINE">DETERMINE</a> the tension at the bottom of its path as function of given <a href="https://interviewquestions.tuteehub.com/tag/parameters-11881" style="font-weight:bold;" target="_blank" title="Click to know more about PARAMETERS">PARAMETERS</a>. Finally, the block `m_2` will lift off the ground when the upward force (tension) exerted by the cord just exceeds the weight of the block. We take bottom of the circle as <a href="https://interviewquestions.tuteehub.com/tag/reference-1181544" style="font-weight:bold;" target="_blank" title="Click to know more about REFERENCE">REFERENCE</a> level. <br/> From conservation of energy, we have <br/> `KE_i+U_i=KE_f+U_f` <br/> `0+m_1g(R-Rcostheta)=1/2m_1v^2+0` <br/> `v^2=2gR(1-costheta)` (i) <br/> Applying Newton's second law on block of mass `m_2`, we have <br/> `sum F_n=T-m_1g=m_1v^2/R` <br/> `T=m_1g+(m_1v^2)/(R)` (ii) <br/> As the string is massless, tenstion T is constant throughout. When `m_2` just lifts off the normal reaction becomes zero. For block `m_2`, we have <br/> `T=m_2g` (iii) <br/> From Eqs. (i), (ii), and (iii), we get <br/> `m_2g=m_1g+m_1(2gR(1-costheta))/(R)` <br/> `cos theta=(3m_1-m_2)/(2m_1)=(3xx3-6)/(2xx3)=1/2` <br/> `theta=60^@`</body></html> | |
| 39574. |
A carof mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circular path of radius 20 mon a level raod what should be the frictional force between the car and the raod so that the car does not slip what should be thevalueof the coefficent of friction to attain this force |
| Answer» <html><body><p></p>Solution :Given `m= 15000 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>` <br/> `v=12.5 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)` <br/> `r=25 m` <br/> Frictionforce = Requiredcentripetalforce <br/> or`f= (mv^(2))/(r ) = (15000 xx 12.5 xx 12.5)/(20)` <br/> `=1.172 xx 10^(4) N` <br/> But `f= muR =<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>` <br/> coefficientof friction<br/> `mu = (f )/(mg ) =- (1.172 xx 10^(4))/( 1500 xx 9.8 ) = 0.8`</body></html> | |
| 39575. |
State the factors on which the position of the CM of a rigid body depends. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i)Geometricla shape of the <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a>. <br/> (ii) Distribution of <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> in the body.</body></html> | |
| 39576. |
A 20 g particle moves in SHM with a frequency of 3 oscillations per second and amplitude of 5 cm. Through what total distance does the particle move during one oscillation ? What is its average speed ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) 20 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> , (ii) `60 cms^(-1)`</body></html> | |
| 39577. |
A calorimeter full of hot water is hung in vacuum. It will: |
| Answer» <html><body><p>Cool by conduction <br/>Cool by <a href="https://interviewquestions.tuteehub.com/tag/convection-425641" style="font-weight:bold;" target="_blank" title="Click to know more about CONVECTION">CONVECTION</a> <br/>Cool by <a href="https://interviewquestions.tuteehub.com/tag/radiation-1175811" style="font-weight:bold;" target="_blank" title="Click to know more about RADIATION">RADIATION</a> <br/>Not cool at all </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39578. |
(A) : Snow is a better insulator than ice (R) : Snow contains air pockets and air is a bad conductor of heat |
| Answer» <html><body><p>Both 'A' and '<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>' are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and 'R' is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of 'A' <br/>Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A' <br/>'A' is true and 'R' is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A' is false and 'Ris true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39579. |
As shown in adjacent figure if a load of mass (m) is attached at lower end of lower wire. Then find the displacements of the points B, C, D are |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_C_C10_SLV_023_S01.png" width="80%"/> <br/>As shown in figure<br/> <a href="https://interviewquestions.tuteehub.com/tag/elongation-969692" style="font-weight:bold;" target="_blank" title="Click to know more about ELONGATION">ELONGATION</a> of <a href="https://interviewquestions.tuteehub.com/tag/1st-283090" style="font-weight:bold;" target="_blank" title="Click to know more about 1ST">1ST</a> wire `e_1 = ((mg)l_1)/(Ay_1)` <br/>elongation of 2nd wire `e_2 = ((mg)l_2)/(Ay_2)` <br/>elongation of <a href="https://interviewquestions.tuteehub.com/tag/3rd-311114" style="font-weight:bold;" target="_blank" title="Click to know more about 3RD">3RD</a> wire `e_3 = ((mg)l_3)/(Ay_3)` <br/>displacement of B is `e_1` <br/>displacement of C is `e_1 + e_2` <br/>displacement of D is `e_1 + e_2 + e_3`</body></html> | |
| 39580. |
When a particle is performing linear SHM its K.E. is two times its P.E. at a position A and its P.E. is two times its K.E. at another position B. Find the ratio of K.E, at A to K.E. at B. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :TE at A = K.E. at A+P.E at A.<br/> But K.E. at A= <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(P.E. at A) <br/> `P.E. "at" A= (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)(K.E. at A)= (3)/(2)K.E. at A` <br/> Similarly, T.E at <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> = K.E. at B + P.E. at B.<br/> But P.E, at B = 2(K.E. at B) <br/> T.E. at B = K.E. at B+ 2 (K.E. at B) = 3 K.E. at B. <br/> By the principle of <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> of energy <br/> T.E. at A=T.E. at `B= (3)/(2)K.E`. <br/> at `A= 3K.E at B= ("K.E. at A")/("K.E. at B")`</body></html> | |
| 39581. |
Which of the following represents conservation laws? a. equation of continuity b.Bernoullie.s Theorem c.Magnus effect d. Toricellis Theoum |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>, d are correct<br/>a,c are correct<br/>a,<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are correct<br/>a,b,c are correct</p>Answer :A</body></html> | |
| 39582. |
A hollow sphere is filled up with water and is suspended using a long string. As water trickels out slowly through an orifice at the lower part of the sphere, it is observed that the time period of the pendulum first increases and later continues to decrease. Explain these observations. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Time period of a simple pendulum at a <a href="https://interviewquestions.tuteehub.com/tag/fixed-457597" style="font-weight:bold;" target="_blank" title="Click to know more about FIXED">FIXED</a> place is directly proportional to the <a href="https://interviewquestions.tuteehub.com/tag/square-650836" style="font-weight:bold;" target="_blank" title="Click to know more about SQUARE">SQUARE</a> root of the effective length of the pendulum. Distance between the point of suspension and the centre of gravity of the bob is the effective length. Time period of oscillation increases or decreases with the increase or decrease of its effective length. <br/> Centre of gravity of the spherical bob, completely, filled with water, lies at the centre of the sphere. As water trickles out through the orifice, the <a href="https://interviewquestions.tuteehub.com/tag/upper-721698" style="font-weight:bold;" target="_blank" title="Click to know more about UPPER">UPPER</a> <a href="https://interviewquestions.tuteehub.com/tag/part-596478" style="font-weight:bold;" target="_blank" title="Click to know more about PART">PART</a> of the sphere starts getting emptied making the lower half heavier than the upper half. As a result, the centre of gravity of the bob starts going down from the centre of the sphere and the effective length begins to increase. Time period also starts increasing. When more water trickles out, the centre of gravity of the bob again starts shifting towards the centre of the sphere resulting in a decrease in the effective length, and consequently, lowering of the time period. When the hollow sphere becomes completely empty, the centre of gravity shifts back to the centre of the sphere and the effective length regains its initial value. As a result, the final value of the time period equals its initial value.</body></html> | |
| 39583. |
Which of the following represents conservation laws? a) equation of continuity b) Bernoullie's Theorem c) Magnus effect d) Toricelli's Theorem |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>, d are correct<br/>a, c are correct<br/>a, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are correct<br/>a, b, c are correct</p>Answer :A</body></html> | |
| 39584. |
Explain why : a body with large reflectivity is a poor emitter. |
| Answer» <html><body><p></p>Solution :(i) This is because a body with <a href="https://interviewquestions.tuteehub.com/tag/large-1066424" style="font-weight:bold;" target="_blank" title="Click to know more about LARGE">LARGE</a> reflectivity is <a href="https://interviewquestions.tuteehub.com/tag/poor-602678" style="font-weight:bold;" target="_blank" title="Click to know more about POOR">POOR</a> absorber of heat, and poor absorbers of heat are emitters. <br/> (ii) When we touch a brass tumber onchilly day, heat <a href="https://interviewquestions.tuteehub.com/tag/flows-993448" style="font-weight:bold;" target="_blank" title="Click to know more about FLOWS">FLOWS</a> from our body to the tumbler quickly (as thermal conductivity of brass is very high) and as a result, it appears colder. <br/> (iii) On the other hand, as the wood a bad conductor, heat does not <a href="https://interviewquestions.tuteehub.com/tag/flow-993213" style="font-weight:bold;" target="_blank" title="Click to know more about FLOW">FLOW</a> to the wooden tray from our body, on louching it.</body></html> | |
| 39585. |
As you have learnt in the text, a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth’s gravity at the site of this satellite ? (Take the potential energy at infinity to be zero). Mass of the earth = 6.0 xx 10^(24) kg." radius" = 6400km . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`-9.4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)` J/kg</body></html> | |
| 39586. |
A light thread is wrapped tightly a few turns around a disc P of mass M. One end of the thread is fixed to the ceiling at B. The other end of the thread is passed over a mass less pulley (Q) and carries a block of mass M. All segment of the thread (apart from that on the pulley and disc) are vertical when the system is released. Find the acceleration of block A. On which object – the block A or the ceiling at B – does the thread exert more force ? |
| Answer» <html><body><p><br/></p>Answer :`(4g)/(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)`; Thread <a href="https://interviewquestions.tuteehub.com/tag/exerts-979377" style="font-weight:bold;" target="_blank" title="Click to know more about EXERTS">EXERTS</a> more force on A</body></html> | |
| 39587. |
A car is moving along a straight line, say OP in It move from O to P in 18 s and returns from P to Q in6 s, where OP=360 m and OQ=240 m. What are the average velocity and average speed of the car in going (a) from O to P ? And (b) from O to P and back to Q ? |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E02_001_S01.png" width="80%"/> <br/> (a) Average <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> `= ("Displacement")/("Time taken")` <br/> `bar v = (360- <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)/(18) = (360)/(18)` <br/> `therefore bar v = <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> ms ^(-1)` <br/> Average speed `= ("Path length")/("Time taken")` <br/> `= (360)/(18) = 20 ms ^(-1)` <br/> `therefore` The value of Average speed is same as Average velocity <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Average velocity `= ("Displacement <a href="https://interviewquestions.tuteehub.com/tag/oq-583888" style="font-weight:bold;" target="_blank" title="Click to know more about OQ">OQ</a>")/(18 +6)` <br/> ` = (240)/(24) ` <br/> `bar v = 10 ms ^(-1)` br> Average speed `= ("Path length")/("Time taken")` <br/> `= (OP+ PQ)/(18+6)= (360+ 120)/(24) = (480)/(24) = 20 ms ^(-1)` <br/> Here, Average speed `gt ` Average velocity,</body></html> | |
| 39588. |
The average speed of blood in the artery (diameter =2mm ) during the resting part of heart's cycle is about 30 "cm" s^(-1). Density of blood 1.05 xx 10^(2) "Kg m"^(-3).eta = 2.7 xx 10^(-3) "Pa" - s. The characteristic of flow is |
| Answer» <html><body><p>laminar<br/>turbulent<br/>both<br/>none</p>Answer :A</body></html> | |
| 39589. |
The given plot shows the variation of U, the potential energy of interaction between two particles with the distance r separating them. a) B and C are equilibrium points b) C is a point of stable equilibrium c) The forceof interaction between the twoparticles between D and E d) The forceof interaction between particles is repulsive between points E and F. Which of the absove statements are correct 1) a and b 2) a and d 3) b and d 4) b and c |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The corresponding <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> - r graph is shown below <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP2_C06_SLV_073_S01.png" width="80%"/> <br/> If particle at C is displaced either of the side, the force will bring it <a href="https://interviewquestions.tuteehub.com/tag/back-389278" style="font-weight:bold;" target="_blank" title="Click to know more about BACK">BACK</a> to C. Hence .C. is a <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> of stable equlibrium. Force on a particle at D is negative, it is directed towards C and is directed away from D. Hence force of interaction is <a href="https://interviewquestions.tuteehub.com/tag/attractive-887662" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTIVE">ATTRACTIVE</a> between C and D while repulsive between D and E.</body></html> | |
| 39590. |
A body is projected vertically up with certain velocity. At a point .P. in its path, the ratio of its potential to kinetic energies is 9 : 16. The ratio of velocity of prokection to velocity at .P. is, |
| Answer» <html><body><p>`3:4`<br/>`5:4`<br/>`9:25`<br/>`25:16`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39591. |
The ratio of SI unit to CGS unit of Planck's constant is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)`<br/>`10^(-7)`<br/>`10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39592. |
A cylinder ABC consists of two chambers 1 and 2 which contains two different gases. The wall C is rigid but the walls A and B are thin diaphragms. A vibrating tuning fork approaches the wall A with velocity u = 30 m//s and air column in chamber 1 and 2 vibrates with minimum frequency such that there is node (displacement) at B and antinode (displacement) at A. Find : (i) the fundamental frequency of air column (ii) find the frequency of tuning fork. Assume velocity of sound in the first and second chamber be 1100 m/s and 300 m/s respectively. . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(i) <a href="https://interviewquestions.tuteehub.com/tag/1650-277626" style="font-weight:bold;" target="_blank" title="Click to know more about 1650">1650</a> <a href="https://interviewquestions.tuteehub.com/tag/hz-493442" style="font-weight:bold;" target="_blank" title="Click to know more about HZ">HZ</a> <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <a href="https://interviewquestions.tuteehub.com/tag/1500-275573" style="font-weight:bold;" target="_blank" title="Click to know more about 1500">1500</a> Hz</body></html> | |
| 39593. |
As temperature is increased, the time period of a simple pendulum |
| Answer» <html><body><p>increases as its <a href="https://interviewquestions.tuteehub.com/tag/effective-966090" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECTIVE">EFFECTIVE</a> length increases even though its <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> of mass <a href="https://interviewquestions.tuteehub.com/tag/still-653256" style="font-weight:bold;" target="_blank" title="Click to know more about STILL">STILL</a> <a href="https://interviewquestions.tuteehub.com/tag/remains-621920" style="font-weight:bold;" target="_blank" title="Click to know more about REMAINS">REMAINS</a> at centre of bob<br/>remains same as its centre of mass still remains at centre of the bob<br/>increases as its effective length increases <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to shifting of its centre of mass below the centre of bob<br/>decreases as its effective length remains same but the centre of mass shifts above the centre of the bob</p>Answer :A</body></html> | |
| 39594. |
In heat transfer, which method is based on gravitation ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/natural-575613" style="font-weight:bold;" target="_blank" title="Click to know more about NATURAL">NATURAL</a> converction<br/>Conduction<br/>Radiation<br/>Stirring of liquids</p>Answer :A</body></html> | |
| 39595. |
Centrifugal force acts in |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/inertial-1043204" style="font-weight:bold;" target="_blank" title="Click to know more about INERTIAL">INERTIAL</a> <a href="https://interviewquestions.tuteehub.com/tag/frame-998974" style="font-weight:bold;" target="_blank" title="Click to know more about FRAME">FRAME</a><br/>non-inertial frame<br/>both (a) and (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)<br/>linear <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :non-inertial frame</body></html> | |
| 39596. |
A slab consists of two parallel layers of iron and brass 10 cm and 10.9 cm thick and of thermal conductivities 500 "Wm"^(-1) "K"^(-1) and 109 "Wm"^(-1) "K"^(-1) respectively. The area of opposite faces are 2m^(2) each and are at temperatures 373 K and 273 K. Find heat conducted per second across the slab and also the temperature of the interface. |
| Answer» <html><body><p><br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> (373 - theta) // 1.75 xx 10^(-2) = 0.05 xx A ( theta - 273) // 2 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) , theta=356.33 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>`</body></html> | |
| 39597. |
Acceleration of a particle a= -bx, where x is the displacement of particle from mean position and b is constant. What is the periodic time of oscillation ? |
| Answer» <html><body><p>`2pi <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(b)`<br/>`(2pi)/(sqrt(b))`<br/>`(2pi)/(b)`<br/>`2 sqrt(((pi)/(b))`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/comparing-2531631" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARING">COMPARING</a> `a= -kx` with `a= -omega^(2)x, omega^(2)= b` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> omega = sqrt(b)` <br/> `therefore (2pi)/(T)= sqrt(b)` <br/> `therefore T= (2pi)/(sqrt(b))`.</body></html> | |
| 39598. |
If the equation for the displacement of a particle moving on a circle path is given by, theta = 2t^(2)+0.5 where, theta is in radian and t is in second, then the angular velocity of the particle after 2 s is |
| Answer» <html><body><p>`8 rad s^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> rad s^(-1)`<br/>`24 rad s^(-1)`<br/>`36 rad s^(-1)`</p>Solution :Angular <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a>, `<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>=(d theta)/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>)=6t^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`, At `t=2s` <br/> `omega = 6(2)^(2)=24 "rads"^(-1)`.</body></html> | |
| 39599. |
The equation fo state of a gas is given by (P+(a)/(V^(3)))(V-b^(2))=cT, where P,V,T are pressure, volume and temperature respectively, and a,b,c are constants. The dimesions of a and b are respectively |
| Answer» <html><body><p>`[ML^(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)T^(-2)] and [L^(3//2)]`<br/>`[ML^(5)T^(-2)] and [L^(3)]`<br/>`[ML^(5)T^(-2)] and [L^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)]`<br/>`[ML^(6)T^(-2)] and [L^(3//2)]`</p>Solution :Given `[P+(a)/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(3))](V-b^(2))=cT` <br/> Dimension of `(a)/(V^(3))`=dimension of `<a href="https://interviewquestions.tuteehub.com/tag/pv-593601" style="font-weight:bold;" target="_blank" title="Click to know more about PV">PV</a>^(3)` <br/> `[a]=[(F)/(A)V^(3)]""(becauseP=(F)/(A))` <br/> `=([MLT^(-2)])/([L^(2)])xx[L^(3)]^(3)=[ML^(8)T^(-2)]` <br/> <a href="https://interviewquestions.tuteehub.com/tag/dimensions-439808" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONS">DIMENSIONS</a> of `b^(2)`=dimensions of V <br/> `therefore[b]=[V]^(1//2)=[L^(3)]^(1//2)` or `[b]=[L^(3//2)]`</body></html> | |
| 39600. |
Find the gravitational potential due to a hemispherical cup of mass M and radius R, at its centre of curvature. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`-(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> )`</body></html> | |