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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39651. |
Which of the following statements is correct for a bulb thermometer |
| Answer» <html><body><p>The bulb of the thermometer is <a href="https://interviewquestions.tuteehub.com/tag/made-3718337" style="font-weight:bold;" target="_blank" title="Click to know more about MADE">MADE</a> of a conducting material<br/>The bulb of the thermometer is made of a poorly conducting material <br/>Sole purpose of making the walls of the bulb thin is to provide <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> possible space for <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> <br/>Specific heat of liquid <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> in the bulb must have large value </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39652. |
Associative law is obeyed by |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/addition-367641" style="font-weight:bold;" target="_blank" title="Click to know more about ADDITION">ADDITION</a> of vectors<br/>subtraction of vectors<br/>both<br/>none</p>Answer :A</body></html> | |
| 39653. |
Rain drop have ……. Free surface |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a></body></html> | |
| 39654. |
The study of production and propagation of sound waves…….. |
| Answer» <html><body><p>Astrophysics<br/><a href="https://interviewquestions.tuteehub.com/tag/acoustics-17924" style="font-weight:bold;" target="_blank" title="Click to know more about ACOUSTICS">ACOUSTICS</a><br/>Relativity<br/>Atomic physics</p>Solution :Acoustics</body></html> | |
| 39655. |
What are the maximum number of rectangular components of a vector can be split in space and in plane respectively. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>, 2<br/>3,3<br/>2,2<br/>`<a href="https://interviewquestions.tuteehub.com/tag/oo-583684" style="font-weight:bold;" target="_blank" title="Click to know more about OO">OO</a>, oo`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39656. |
A block is placed on a smooth inclined plane at an angle thetato the horizontal. The acceleration must the plane be moved horizontally so that the block to fall freely is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> tan q` <br/>`g cot q` <br/>`g <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> q ` <br/>`g cos q ` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39657. |
If for hydrogen C_p-C_v = m and for nitrogen C_p -C_v= n , where C_p and C_v refer to specific heats perunit mass respectively at constant pressure and constant volume, the relation between m and n is : (Molecular weight of hydrogen = 2 molecular weight or nitrogen= 14 ) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> = <a href="https://interviewquestions.tuteehub.com/tag/14m-273942" style="font-weight:bold;" target="_blank" title="Click to know more about 14M">14M</a> <br/>n= 7m<br/>m=7n<br/>m=14n</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39658. |
Out of the following the correct order of dimensions of mass increases is (A) Velocity (B) Power (C ) Gravitational Constant |
| Answer» <html><body><p>A,<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>,<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <br/>C, A, B<br/>A,C , B<br/>B,C, A</p>Answer :B</body></html> | |
| 39659. |
On a P-V diagram starting from an initial state (P_0 V_0) plot an adiabatic expansion to 2V_0 an isothermal expansion to 2V_0 and an isobaric expansion to 2V_0 Use this graph to determine in which process the least work is done by the system |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a></body></html> | |
| 39660. |
A car of mass 1000 kg is moving with a velocity 20m /s on a horizontal straight road. If the driver applies brakes to produce a constant breaking force of 5000 Newton, the acceleration of the car i s ..... m /s^(2). |
| Answer» <html><body><p>`-5`<br/>50<br/>5<br/>none </p>Solution :FromNewton.ssecondlaw ofmotion <br/> <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= ma HereF=breakingforce <br/>`=-<a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> N` <br/> <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a>`a= (F )/( m ) = (5000)/( 1000) =0 5 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(2)`</body></html> | |
| 39661. |
A simple pendulum is vibrating with an angular amplitude of 90^(@) as shown in the figure. For what value of a is the acceleration directed i) vertically upwards ii) horizontally iii) vertically downward |
| Answer» <html><body><p>`0^(@), cos^(-1)(1/sqrt3), 90^(@)`<br/>`90^(@), cos^(-1)(1/sqrt3), 0^(@)`<br/>` cos^(-1)(1/sqrt3),0^(@), 90^(@)`<br/>` cos^(-1)(1/sqrt3),90^(@), 0^(@)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_NEET_PHY_XI_P2_C06_E11_006_S01.png" width="80%"/> <br/> At "C", `T cos alpha = <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> .......(i)` <br/>`P.E_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) = K.E_(A) Rightarrow mgr = 1/2(mv_(A)^(2))` <br/> hence at "C" , `v = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a> (v_(A)^(2) - 2gr(1-cos alpha))` <br/> `T -Mg cos alpha = (Mv)^(2)/(r) = (M.2 <a href="https://interviewquestions.tuteehub.com/tag/gr-1010452" style="font-weight:bold;" target="_blank" title="Click to know more about GR">GR</a> cos alpha)/(r)`</body></html> | |
| 39662. |
Which body will emit more radiation under the similar condition, a black body or polished body ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/black-898687" style="font-weight:bold;" target="_blank" title="Click to know more about BLACK">BLACK</a> <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a></body></html> | |
| 39663. |
When the distance between the two atoms becomes gamma_(0), then the inter atomic force will be, |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>Infinity <br/><a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a><br/>Positive constant </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Zero</body></html> | |
| 39664. |
Two forces equal to P and 2P newton act on a particle . If the first be doubled and the second be increased by 20 newton, the direction of the resultant is unaltered . Find the value of P . |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :Let the resultant make angle `beta`with the force P .<br/>`:.`In <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> case,<br/>`tan beta = (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> P sin theta)/( P + 2 P cos theta)`<br/>In second case,<br/>`tan beta = ((2P + 20) sin theta)/(2P + (2P + 20) cos theta)`<br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>,<br/>`((2P + 20) sin theta)/( 2 P + (2P + 20) cos theta) = (2P sin theta)/(P + 2 P cos theta)`<br/>(or)`(2P sin theta)/( P +2 P cos theta) = (2 0 sin theta)/( P + 2 0 cos theta)`[`:' (a)/(b) = (c)/(d) = (a-c)/(b-d)` ]<br/>From the above <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> , 2P = 20<br/>(or) P = 10 N</body></html> | |
| 39665. |
Why angular diameter of the sun and the moon in the sky same? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> diameter of any object in the <a href="https://interviewquestions.tuteehub.com/tag/sky-1211556" style="font-weight:bold;" target="_blank" title="Click to know more about SKY">SKY</a> can be measured as : `alpha=(d)/(D)` <br/> Here d is the diameter of object and D is the distance object and the earth. <br/> In case of the moon and sun, by coincidence, the <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> d : D is same for both and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> their angular diameter is same in the sky.</body></html> | |
| 39666. |
A stone is dropped from a height of 10cm above the top of a window 80 cm high. The time taken by the stone to cross the window is |
| Answer» <html><body><p>`1/7 s `<br/>`3/7 s `<br/>`2/7 s ` <br/>`4/7 s ` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39667. |
Which of the following will make the volume of an ideal gas four times ? |
| Answer» <html><body><p>double the <a href="https://interviewquestions.tuteehub.com/tag/absolute-11456" style="font-weight:bold;" target="_blank" title="Click to know more about ABSOLUTE">ABSOLUTE</a> temperature and double the pressure.<br/>Halve the absolute temperature and double the pressure.<br/><a href="https://interviewquestions.tuteehub.com/tag/quarter-611191" style="font-weight:bold;" target="_blank" title="Click to know more about QUARTER">QUARTER</a> the absolute temperature at <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> pressure.<br/>Quarter the pressure at constant temperature.</p>Solution :Quarter the pressure at constant temperature.</body></html> | |
| 39668. |
A cannon and a target are 5.10 km apart and located at the same level. How soon will the shell launched with the initial velocity 240 m/s reach the target in the absence of air drag ? |
| Answer» <html><body><p></p>Solution :Here, `v_(0) = <a href="https://interviewquestions.tuteehub.com/tag/240-295938" style="font-weight:bold;" target="_blank" title="Click to know more about 240">240</a> ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>), R = 5.10 km = 5100 m`, <br/> `g = 9.8 ms^(-2), <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> = ? ""R = (v_(0)^(2) sin 2 alpha)/(g)` <br/> `sin 2 alpha = (Rg)/(v_(0)^(2)) ""rArr alpha = 30^(@)` or `<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)` <br/> using `= T = (2v_(0)sin alpha)/(g)` <br/> when, `alpha = 30^(@) , T_(1) = (2 xx 240 xx 0.5)/(9.8) = 24.5 s` <br/> When, `alpha = 60^(@), T_(2) = (2 xx 240 xx 0.867)/(9.8) = 42.41s`</body></html> | |
| 39669. |
(A) : Centripetal force does no work in circular motion. (R ) : Force and displacement are perpendicular to each other in circular motion |
| Answer» <html><body><p>Both 'A' and 'R' and true and 'R' is the correct <a href="https://interviewquestions.tuteehub.com/tag/explantation-2628194" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANTATION">EXPLANTATION</a> of 'A'<br/>Both 'A' and 'R' and true and 'R' is <a href="https://interviewquestions.tuteehub.com/tag/notthe-2877399" style="font-weight:bold;" target="_blank" title="Click to know more about NOTTHE">NOTTHE</a> correct explantation of 'A'<br/>A' is true and 'R' is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>A' is false and 'R' is true</p>Answer :A</body></html> | |
| 39670. |
A door of moment of inertia 4 kg m^(2) is at rest. When a torque of 2 pi Nm acts on it find its angular acceleration. Find also its angular velocity after 1 s. |
| Answer» <html><body><p></p>Solution :`alpha=(<a href="https://interviewquestions.tuteehub.com/tag/tau-663951" style="font-weight:bold;" target="_blank" title="Click to know more about TAU">TAU</a>)/(I)=(2pi)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)=(<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)rad//s^(2)` <br/> `omega_(2)-omega_(1)=alphat""omega_(2)=(pi)/(2)<a href="https://interviewquestions.tuteehub.com/tag/xx1-1463705" style="font-weight:bold;" target="_blank" title="Click to know more about XX1">XX1</a>` <br/> `omega_(2)=1.57` rad/sec.</body></html> | |
| 39671. |
"Speed of a particle can be negative ". Is this statement correct ? If not why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :NO, <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> cannot be <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a> .it is a <a href="https://interviewquestions.tuteehub.com/tag/scalar-629745" style="font-weight:bold;" target="_blank" title="Click to know more about SCALAR">SCALAR</a> <a href="https://interviewquestions.tuteehub.com/tag/quantity-1174212" style="font-weight:bold;" target="_blank" title="Click to know more about QUANTITY">QUANTITY</a>.</body></html> | |
| 39672. |
If the inertial mass and gravitational mass of the simple pendulum of length 1 are not equal, then the time period of the simple pendulum is |
| Answer» <html><body><p>`T=2pisqrt((m_(i)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(m_(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)g))` <br/>`T=2pisqrt((m_(g)l)/(m_(i)g))` <br/>`T=2pi(m_(g))/(m_(i))<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((l)/(g))` <br/>`T=2pi(m_(i))/(m_(g))sqrt((l)/(g))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39673. |
100 g cms^(-1)=x Ns then x=.... |
| Answer» <html><body><p>`3.6xx10^(-3)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1xx10-1804645" style="font-weight:bold;" target="_blank" title="Click to know more about 1XX10">1XX10</a>^(-3)`<br/>`6xx10^(-4)`<br/>`1xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`<br/></p>Solution :`100 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> ms^(-1)= x kg ms^(-1)` <br/> `=x(1xx10^(3)g)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(10^(2)cm)xx1 (s^(-1))` <br/> `=x xx10^(5) g cms^(-1)` <br/> `=10^(-3)=x`<br/> `:.x=1xx10^(-3)`</body></html> | |
| 39674. |
If 'g' on the surface of the earth is 9.8ms^(-2), find its value at a depth of 3200 km (radius of the earth = 6400 km) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :with d = 3200 km <br/> `g_(d) = g[<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>-(d)/(R)]<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> g_(d) = 4.9 ms^(-2)`</body></html> | |
| 39675. |
A train runs along an unbanked circular track of radius 30 m at a speed of 54 km/h. The mass of the train is 10^(6) kg. What provides the centripetal force required for this purpose - The engine or the rails ? What is the angle of banking required to prevent wearing out of the rail ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The centripetal force is provided by the lateral thrust by the <a href="https://interviewquestions.tuteehub.com/tag/rail-1176462" style="font-weight:bold;" target="_blank" title="Click to know more about RAIL">RAIL</a> on the flanges of the wheels.By the <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> Law, the train exerts an equal and opposite thrust on the rail causing its wear and tear.<br/>Angle of banking ` = tan^(-1)( (v^2)/(R <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)) = tan^(-1) ( (15 xx 15)/(30 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)) = 37^@`</body></html> | |
| 39676. |
A force can change the velocity of a particle in three different ways explain with example |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) themagnitude of thevelocitycan bechangedwithoutchangingthe directionof <a href="https://interviewquestions.tuteehub.com/tag/thevelocity-3207609" style="font-weight:bold;" target="_blank" title="Click to know more about THEVELOCITY">THEVELOCITY</a> . <a href="https://interviewquestions.tuteehub.com/tag/eg-445433" style="font-weight:bold;" target="_blank" title="Click to know more about EG">EG</a>. Particlefallingdownverticallybikemovingin astraightroadwithaccelerationetc.<br/> (ii) the directionof motionalonecan bechangedwithoutchangingthe <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a>. ifthishappenscontinusouslythen it iscalledasuniformciruclarmotion. <br/> (iii)Both thedirectionand magnitudeof velocitycan bechanged. if thishappens then non-ciruclarmotionoccurs. Forexampleoscillation of aswingor asimplependulum ellipticalmotionof planeltsaroundthe sun.</body></html> | |
| 39677. |
A large vessel with a small hole at the bottom is filled with water and kerosene. The height of he water column is 20 cm and that of the kerosene is 25 cm. The velocity with which water flows out of the hole is (density of kerosene = 0.8 gm/cc) (Neglect viscous forced) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2ms-1837988" style="font-weight:bold;" target="_blank" title="Click to know more about 2MS">2MS</a>^(-1)`<br/>`4ms^(-1)`<br/>`2.8ms^(-1)`<br/>`3ms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39678. |
Figure shows a cylindrical tank of cross sectional are A having a small pipe at its bottom with a cross sectional area a, containing a liquid of density rho and specific heat capacity s, filled to an initial height H. The initial temperature is T_(0). The liquid is heated by means of a heater at t = 0, emitting heat at the rate of P Simultaneously the lower tap is opened. Find the temperature of the liquid (contained in the tank) as a function time t where t ltA/a sqrt((2H)/g) |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`T_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)+P/(Arhoslamda)[<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/((sqrtH-lamdat))-1/sqrtH] "where" <a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a> a/Asqrt(g/sqrt2)`</body></html> | |
| 39679. |
A string with one end fixed on a rigid wall, passing over a fixed frictionless pulley at a distance of 2 m from the wall, has a point mass M of 2 kg attached to it at a distance of 1 m from the wall. A mass in of 0.5 kg is attached to the free end. The system is initially held at rest so that the string is horizontal between wall and pulley and vertical beyond the pulley as shown in Fig. The system is released from the rest from the position as shown. The ratio of velocity of M and m when M strikes the wall is |
| Answer» <html><body><p>`(sqrt(5))/2`<br/>`2/sqrt(5)`<br/>`3/sqrt(5)`<br/>`(sqrt(5))/3`</p>Solution :When `M` strikes the wall, vertically downward component of its displacement from initital position is `1 m` and its distance from pulley `B` is <br/> `C'B=sqrt(1^(2)+2^(2))=sqrt(5)m` <br/> When its <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> distance from the pulley was `CB=1m`. It means vertically upward displacement of mass `m` is `(sqrt(5)-1)m`. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VOL2_C01_E01_314_S01.png" width="80%"/> <br/> Let `M` strike the wall velocity `v`. Since the string between the two blocks always <a href="https://interviewquestions.tuteehub.com/tag/remains-621920" style="font-weight:bold;" target="_blank" title="Click to know more about REMAINS">REMAINS</a> taut, therefore at any instant speed of `m` is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to that component of velocity of `M` which which is along the string `C'B`. Hence , velocity of `m` when `M` strikes the wall is `vcostheta`, where<br/> `costheta=2/sqrt(5)` <br/> `:. (v_(M))/(v_(m))=v/(vcostheta)=(sqrt(5))/2` <br/>According to law of energy, <a href="https://interviewquestions.tuteehub.com/tag/loss-1079380" style="font-weight:bold;" target="_blank" title="Click to know more about LOSS">LOSS</a> of potential energy of `M=`increase in `<a href="https://interviewquestions.tuteehub.com/tag/pe-590719" style="font-weight:bold;" target="_blank" title="Click to know more about PE">PE</a>` of `m+KE` of `M+KE` of `m` <br/> `Mgxx1=mg(sqrt(5)-1)+1/2Mv^(2)+1/2m(vcostheta)^(2)` <br/> `v=5sqrt((5-sqrt(5))/6)m//s`</body></html> | |
| 39680. |
Two block of masses 1 kg 2 are connected by a metal wire going over a smooth pulley. The breaking stress of metal is 40/(3pi) xx10^(6)Mm^(-2) . What should be the minimum radius of wire used if it should not break?(g=10ms^-2) |
| Answer» <html><body><p>0.5mm<br/>1mm<br/>1.5mm<br/>2mm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39681. |
Work of 3.0xx10^(-4) Joule is required to be done in increasing the size of a soap film from 10cmxx6cm to 10cmxx11cm. The surface tension of the film is …… |
| Answer» <html><body><p>`5xx10^(-2)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>//m`<br/>`3xx10^(-2)N//m`<br/>`1.5xx10^(-2)N//m`<br/>`1.2xx10^(-2)N//m`</p>Solution :Surface tension T`=("work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a>")/("<a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> in <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a>")`<br/> Soap film has two free surface , <br/>`thereforeT=(3.0xx10^(-4)J)/(<a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a>(10xx11-10xx6)xx10^(-4))`<br/>`=3xx10^(-2)(N)/(m)`</body></html> | |
| 39682. |
A dancer spins about a vertical axis at 60 rpm with her arms folded. If she strectes her hands so that M.I. about the vertical axis increases by 25% the new rate of revolvution is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/48-318016" style="font-weight:bold;" target="_blank" title="Click to know more about 48">48</a>` <a href="https://interviewquestions.tuteehub.com/tag/rpm-615000" style="font-weight:bold;" target="_blank" title="Click to know more about RPM">RPM</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/75-334971" style="font-weight:bold;" target="_blank" title="Click to know more about 75">75</a>` rpm<br/>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a>` rpm<br/>`<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>` rpm</p>Answer :A</body></html> | |
| 39683. |
How much is the empty space in 1 mole of Helium gas at STP if the radius of helium molecule is about 0.98 dot(A)? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`=99.98%`</body></html> | |
| 39684. |
At a given temperature the r.m.s velocity will be greater for |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> <br/>Oxygen<br/>Equal for both<br/>Nothing is definite</p>Answer :A</body></html> | |
| 39685. |
Select the alternatatives. (a) A diverging beam of light form a point source S having divergence angle alpha ,falls symmetrically on a glass slabas shown .the angles of incidence of the two extreme rays are equal .Fi the thickness of the glass slab is tand the refractive index nthe n the divergence angle of the emergent beam is (A) zero,(B) alpha(C ) sin^(-1)(1//n)(D) 2 sin^(-1)(1//n) (b) Arectangular glass slabABCDof refractive index n_(1) is immersed in water of refractive indexn_(2)(n_(1)gtn_(2)) A ray of light is incident at the surface ABof the slab as shown .The maximum value of the angle of incidenc ealpha_(max)such that the ray comes out only from the other surface CD is given by (A) "sin"^(-1)[(n_(1))/(n_(2))cos("sin"^(-1)n_(2)/n_(1))] (B)sin^(-1)[(n_(1))/(n_(2))cos("sin"^(-1)(1)/n_(2))] (C)sin^(-1)((n_(1))/(n_(2)))(D)sin^(-1)((n_(2))/n_(1)) (c) A point source of lightB is placed at a distance L inother of the centre of a mirror of width hung vertically onawall A man walks is front of the mirror along a line parallel to the mirror at a distance 2L from it as shown .the greatest distance over which he can see the image of the light source in the mirror is (A)d//2 (B) d,(c )2d,(d)3d, a hollow double concave lens is made of very thin transparents meterial .It can be filledwith air or either of two liquids L_(1)andL_(2)having refractive indicesn_(1)and n_(2)respectively(n_(2)gtn_(!)gt1) the lens will diverge a parallel beam of light of it is filled with (A)air and placed in air.(B) air and immersed inL_(1)(C ),L_(1) and immersed inL_(2) (D),L_(2) ans immersed in L_(1) |
| Answer» <html><body><p><br/></p>Solution :[B]<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NG_PHY_RO_C01_E01_045_S01.png" width="80%"/> <br/> For critical angle at `A,D,`taking refraction at`AD` <br/> `n_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)sinC=n_(2) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> sinC=(n_(2))/(n_(1))rArr C="<a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a>"^(-1)(n_(2))/(n_(1)) ….(1)` <br/> taking refractor at AB`n_(2) sin alpha _(max)=n_(1) sin(90-C) rArr n_(2)sinalpha_(max)=n_(1)cosC` <br/> `rArr alpha_(max)="sin"^(-1)(n_(1))/(n_(2)) cosC ...(2)` <br/> from(1)&(2) `alpha_(max)=sin^(-1)[(n_(1))/(n_(2))"cos"("sin"^(-1)(n_(2))/(n_(1)))]` <br/> (c ) `[D](d//2)/(L) =(x)/(2L) rArr x=L` <br/> greastest distance=`2x+d` <br/> `=3d` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NG_PHY_RO_C01_E01_045_S02.png" width="80%"/> <br/> (d) [B] Behaviour of lens will be change when <a href="https://interviewquestions.tuteehub.com/tag/ray-1177996" style="font-weight:bold;" target="_blank" title="Click to know more about RAY">RAY</a> <a href="https://interviewquestions.tuteehub.com/tag/incidence-1039767" style="font-weight:bold;" target="_blank" title="Click to know more about INCIDENCE">INCIDENCE</a> from optically denser medium .</body></html> | |
| 39686. |
"In hilly areas, sand is thrown on tracks covered with snow ". Why ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/hilly-1024063" style="font-weight:bold;" target="_blank" title="Click to know more about HILLY">HILLY</a> areas, <a href="https://interviewquestions.tuteehub.com/tag/train-1425202" style="font-weight:bold;" target="_blank" title="Click to know more about TRAIN">TRAIN</a> <a href="https://interviewquestions.tuteehub.com/tag/could-410026" style="font-weight:bold;" target="_blank" title="Click to know more about COULD">COULD</a> not be able to move upwards. By throwing <a href="https://interviewquestions.tuteehub.com/tag/sand-1194769" style="font-weight:bold;" target="_blank" title="Click to know more about SAND">SAND</a> friction is <a href="https://interviewquestions.tuteehub.com/tag/increased-1040402" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASED">INCREASED</a> then the train would be able to move upwards.</body></html> | |
| 39687. |
Which of the following functions of time represent (a) simple harmonic motion and (b) periodic but not simple harmonic? Give the period for each case. (1) sinomegat-cosomegat (2) sin^(2)omegat |
| Answer» <html><body><p></p>Solution :(a) `sinomegat-cosomegat` <br/> `=sinomegat-sin(pi//<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>-omegat)` <br/> `=2cos(pi//4)sin(omegat-pi//4)` <br/> `=sqrt2sin(omegat-pi//4)` <br/> This function represents a simple harmonic motion having a period `T=2pi//omega` and a <a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a> angle `(-pi//4)` or `(7pi//4)` <br/> (b) `sin^(2)omegat` <br/> `=1//2-1//2cos2omegat` <br/> The function is periodic having a period `T = pi//omega`. It also represents a harmonic motion with the point of equilibrium <a href="https://interviewquestions.tuteehub.com/tag/occurring-1127842" style="font-weight:bold;" target="_blank" title="Click to know more about OCCURRING">OCCURRING</a> at `1//2` <a href="https://interviewquestions.tuteehub.com/tag/instead-516622" style="font-weight:bold;" target="_blank" title="Click to know more about INSTEAD">INSTEAD</a> of zero.</body></html> | |
| 39688. |
Briefly explain the concept of super position principle. |
| Answer» <html><body><p></p>Solution :When two or more waves in a medium overlap., their <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> displacement is the <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> sum of individual displacements. <br/> Let us consider two fucntions which <a href="https://interviewquestions.tuteehub.com/tag/characterize-2016103" style="font-weight:bold;" target="_blank" title="Click to know more about CHARACTERIZE">CHARACTERIZE</a> the displacement of the waves, for example, <br/> `y_(1)=a sin (kx- omegat)` <br/> and `y_(2)=A_(2)cos(kx- omegat)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> both `y_(1) and y_(2)` satisfy the wave equation (solutions of wave equation) then their algebraic sum <br/> `y=y_(1)+y_(2)` <br/> also satisfies the wave equation. It is meant that, the displacement are additive.</body></html> | |
| 39689. |
The vector product of two vectors will have maximum magnitude when theta is equal to |
| Answer» <html><body><p>(a) `0^(@)`<br/>(b) `90^(@)`<br/>(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) `180^(@)`<br/>(d) `<a href="https://interviewquestions.tuteehub.com/tag/360-309472" style="font-weight:bold;" target="_blank" title="Click to know more about 360">360</a>^(@)`</p></body></html> | |
| 39690. |
Can the couple acting on a rigid body produce translatory motion? |
| Answer» <html><body><p></p>Solution :No, the couple <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on a rigid <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> cannot rotatory <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> as the <a href="https://interviewquestions.tuteehub.com/tag/resultant-1187362" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTANT">RESULTANT</a> force is zero.</body></html> | |
| 39691. |
A square lead slab of side 50 cm and thickness 10 cm is subject to a shearing force on its narrow face) of 9.0 xx 10 ^(4) N.The lower edge is riveted to the floor. How much will the upper edge be displaced ? Shear modulus of lead G=5.8 xx 10 ^(9) N//m^(2) |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P2_C09_E02_008_S01.png" width="80%"/> <br/> The load slab is <a href="https://interviewquestions.tuteehub.com/tag/fixed-457597" style="font-weight:bold;" target="_blank" title="Click to know more about FIXED">FIXED</a> and the force is applied parallel to the narrow face. The <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a> of the face parallel to which this force is applied is, <br/> `A=l xx <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>` <br/> `= 50 cm xx 10 cm = 0.5 m xx 0.1 m` <br/> `therefore A = 0.05 m ^(2)` <br/> Stress = `("Force")/("Area")= (9 xx 10 ^(4))/(0.05) =1.8 xx 10 ^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) Nm ^(-2)`<br/> Shear modulus `(G) =("Stress")/("Shear strain")` <br/> `therefore` Shear strain`= ("Stress")/(G)` <br/> ` (Delta x)/(L) = ("Stress")/(G)` <br/> `therefore Deleta x = ("Stress")/(G) xx l` <br/> `therefore Delta x = (1.8 xx 10 ^(6))/(5.6 xx 10 ^(9)) xx 0.5` <br/> `therefore Delta x =0.1607 xx 10 ^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/> `therefore Delta x ~~ 1.6 xx 10 ^(-4) m = 0.16 mm`</body></html> | |
| 39692. |
The force on a body executing SHM is 2N when the displacement is 2cm. If the amplitude of oscillation is 5cm, what is the total energy associated with the SHM? |
| Answer» <html><body><p>`1.25 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-2) J`<br/>`125 xx 10^(-2) J`<br/>`12.5 xx 10^(-2) J`<br/>`0.125 xx 10^(-2)J`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 39693. |
StatementI: A quasi -static process is so called bacause it is a sudden and large change of the system. Statement II: An adiabatic process is not quasi- static because it is a sudden and large change of the system. |
| Answer» <html><body><p>Statement I: is true, StatementII is true and Statement II is the correct explanation for Statement I. <br/>Statement I: is true, Statement II is true and Statement II is NOT the correct explanation for Statement I.<br/>Statement I is true, Statement II is false. <br/>Statement I is false, Statement II is true. </p>Solution :It is true that forreal gases, and for the real <a href="https://interviewquestions.tuteehub.com/tag/procedures-15993" style="font-weight:bold;" target="_blank" title="Click to know more about PROCEDURES">PROCEDURES</a> in the laboratory, an adaibatic process is a sudden and large change of the systemobtained in a small time. However, for an ideal gas, and for an ideal procedure, we assume for such a gas, an adiabatic process is <a href="https://interviewquestions.tuteehub.com/tag/considered-7257760" style="font-weight:bold;" target="_blank" title="Click to know more about CONSIDERED">CONSIDERED</a> quasi`-` static, in which the system passes through a continuous succession of equilibrium states, which we can <a href="https://interviewquestions.tuteehub.com/tag/plot-1156761" style="font-weight:bold;" target="_blank" title="Click to know more about PLOT">PLOT</a> ona `P-V` diagram. Such a process is also assumed to be reversible through, of course, a quasi `-` static process may or may not be reversible. Such ideal consitions as we assume may not be <a href="https://interviewquestions.tuteehub.com/tag/obtained-7273275" style="font-weight:bold;" target="_blank" title="Click to know more about OBTAINED">OBTAINED</a> in particle but almose all real systems deviate little from the results of our ideal procedures, which may therefore be considered <a href="https://interviewquestions.tuteehub.com/tag/approximations-883185" style="font-weight:bold;" target="_blank" title="Click to know more about APPROXIMATIONS">APPROXIMATIONS</a> to real processes.</body></html> | |
| 39694. |
A cycle followed by an engine (made of one mole of perfect gas in a cylinder with a piston) is shown if Fig. A to B : Volume constant B to C : adiabatic C to D : volume constant D to A : adiabatic V_(C) = V_(D) = 2V_(A)=2V_(B) ( a) In which part of the cycle heat is supplied to the engine from outside? (b) In which part of the cycle heat is being given to the surrounding by the engine? (c) What is the work done by the engine in one cycle? Write your answer in term of P_(A),P_(B) V_(A) . (d) What is the efficiency of the engine? [gamma=5/3" for the gas "],[C_(v)=3/2R" for one mole"] |
| Answer» <html><body><p></p>Solution :(a) A to B since each one is an isochoric <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> <br/>( b) C to D <br/>( c) `W_(AB)=int_(A)^(B)pdV=0,W_(CD)=0`<br/> Similarly `W_(BC) =[int_(B)^(C)pdV=k int_(B)^(C)(<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/(V^(gamma) )= (V^(-gamma+1))/(-gamma+1)]_(V_(B))^(V_(C))`<br/> `=1/(1-gamma) (P_(c )V_(c)-P_(B)V_(B))` [ work done during <a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a> process ]<br/> Similarly, `W_(DA)==1/(1-gamma)(P_(A)V_(A)-P_(D)V_(D))`<br/> Now `P_(C)=P_(B)((V_(B))/(V_(C)))^(gamma) =2^(-gamma)P_(B)[ :. V_(C )=2V_(B)] `<br/> Similarly, `P_(D) =P_(A)2^(-gamma)` , Total work done ` = W_(BC)+W_(DA)`<br/> `=1/(1-gamma) [P_(B)V_(B)(2^(-gamma+1)-1)P_(A)V_(A)(2^(-gamma+1)-1)]` <br/> `1/(1-gamma) (2^(1-gamma)-1) (P_(B)-P_(A))V_(A) ""( :. V_(A)=V_(B))` <br/> `=3/2 (1-(1/2)^(2//3))(P_(B)-P_(A))V_(A)` <br/> Heat supplied during process A,B `dQ_(AB)=dU_(AB)`<br/> `Q_(AB)=3/2nR(T_(B)-T_(A))=3/2(P_(B)-P_(A))V_(A)` <br/> Efficiency = `("Net Work done")/("Heat Supplied") =(1-(1/2)^(2//3))`</body></html> | |
| 39695. |
The co-ordinates of centre of mass of letter E which is cut from a uniform metal sheet are (Take origin at bottom left corner and width of letter 2 cm every where): |
| Answer» <html><body><p>(2 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>, <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> cm)<br/>(2.4cm, 4cm)<br/>(<a href="https://interviewquestions.tuteehub.com/tag/3cm-310901" style="font-weight:bold;" target="_blank" title="Click to know more about 3CM">3CM</a>, 5cm)<br/>(3.3cm, 5cm)</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39696. |
Two waves with wavelength lamda have phase difference of 60° at the point of superposition. Find path difference between them. |
| Answer» <html><body><p>`lamda/6`<br/>`lamda/2`<br/>`2lamda`<br/>`lamda/4`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :We have `Delta <a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a> = (<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(lamda) (Delta x)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> (<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> )/(3) = (2pi )/( lamda ) (Delta x)` <br/> `therefore Delta x = (lamda )/(6)`</body></html> | |
| 39697. |
Select the correct pair from the following pairs with reference to acceleration due to gravity (g). |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> is minimum at poles and it is maximum at equator.<br/>g is maximum at poles and it is minimum at equator<br/>g is maximum at equator and it is minimum at poles<br/>g decreases with depth and it <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> with height.</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39698. |
A block slides down a frictionless incline kept on the floor of a chamber . Find the acceleration of the block relative to the incline when the chamber is carried by a helicopter with upward acceleration a at inclination theta with the vertical . Consider the special cases when theta = 0 ^(@) and theta = 90^(@) . The inclination of the plane is 90^(@) - alpha to the vertical in the same sense as theta . |
| Answer» <html><body><p><br/></p>Answer :`a_("down") = g "<a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a>" <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> + a "sin"(<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> + alpha) , a_("down") = g "sin" alpha + a "<a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a>" alpha`</body></html> | |
| 39699. |
The main difference between liquid surface and an elastic membrane is |
| Answer» <html><body><p>Hook.s law is not obeyed by <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> <br/>Surface tension increases with <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> of surface area <br/>Both <br/>None</p>Answer :A</body></html> | |
| 39700. |
At what height from the surface of Earth the gravitational force will be reduced by 10% if the radius of Earth is 6400 km? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Gravitational <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> on the Earth surface<br/>`F_(s)=(GMm)/(R_(E)^(2))` <br/>Gravitational force at <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> h<br/>`F_(h)=(GMm)/((R_(E)+h)^(2))` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>(F_s)/(F_h)=((R_(E)+h)^(2))/(R_(E)^(2))=(10)/(9)` <br/>`3(R_(E)+h)=3.162R_(E)` <br/>`3h=(3.162-3)R_(E)` <br/>`=0.162R_(E)` <br/>`(R_(E)+h)/(R_E)=(3.162)/(3)` <br/>`therefore` Height h `=(0.162xx6400)/(3)` <br/>(or) h = 345.6 <a href="https://interviewquestions.tuteehub.com/tag/km-1064498" style="font-weight:bold;" target="_blank" title="Click to know more about KM">KM</a></body></html> | |