InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39701. |
Two bodies whose masses are in the ratio 2:1 are dropped simultaneously at two places A and B where the accelerations due to gravity are g_(A)andg_(B) respectively. If they reach the ground simultaneously, the ratio of the heights from which they are dropped is |
| Answer» <html><body><p>`g_(A):g_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)`<br/>`2g_(A):g_(B)`<br/>`g_(A):2g_(B)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(g_(a)):sqrt(g_(b))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39702. |
In an aluminium sheet there is a hole of diameter 1 m and is horizontally mounted on a stand. Onto this hole an iron sphere of diameter 1.004 m is resting. Initial temperature of this system is 25^(@)C. Find at what temperature, the iron sphere will fall down through the hole in sheet. The coefficients of linear expansion for aluminium and iron are 2.4xx10^(-5)and1.2xx10^(-5) respectively. |
| Answer» <html><body><p></p>Solution :As value of coefficient of linear <a href="https://interviewquestions.tuteehub.com/tag/expansion-980011" style="font-weight:bold;" target="_blank" title="Click to know more about EXPANSION">EXPANSION</a> for aluminium is more thant that for iron, it expands faster than iron. So at some higher temperature when <a href="https://interviewquestions.tuteehub.com/tag/diameter-950836" style="font-weight:bold;" target="_blank" title="Click to know more about DIAMETER">DIAMETER</a> of hole will exactly become <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to that of iron sphere, the sphere will pass through the hole. Let it happen at some higher temperature T. Thus we have at this temperature T, <br/> `("diameter of hole" )_(Al)` = `("diameterof sphere")_("ion")` <br/> ` 1 [ 1 + alpha_(Al) (T - 25) ] = 1.004 [ 1 + alpha_("iron") ( T - 25) ]` <br/> `alpha_(Al) ( T - 25) = 0.004 + 1.004 alpha_("iron") (T - 25)` <br/> or `T = ((0.004)/(alpha_(A <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>) - 1.004 alpha_("iron")) + 25 ) ""^(@)C ` <br/> or T = `(0.004)/(1 xx 2.4 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) - 1.004 xx 1.2 xx 10^(-5)) + 25 ` <br/> or T = `359.7^(@)` C</body></html> | |
| 39703. |
State two basic characterstic ofan oscillating system |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/basic-15343" style="font-weight:bold;" target="_blank" title="Click to know more about BASIC">BASIC</a> <a href="https://interviewquestions.tuteehub.com/tag/characteristics-19445" style="font-weight:bold;" target="_blank" title="Click to know more about CHARACTERISTICS">CHARACTERISTICS</a> are <a href="https://interviewquestions.tuteehub.com/tag/elasticity-14238" style="font-weight:bold;" target="_blank" title="Click to know more about ELASTICITY">ELASTICITY</a> and <a href="https://interviewquestions.tuteehub.com/tag/inertia-1043176" style="font-weight:bold;" target="_blank" title="Click to know more about INERTIA">INERTIA</a>.</body></html> | |
| 39704. |
When a body is projected vertically up from ground, the ratio of its potential to kinetic energies at a height 'h' above the ground is 3: 4. The height above ground at which the ratio of potential to kinetic energies becomes 4:3 is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>`<br/>`(4)/(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)h`<br/>`(3)/(7)h`<br/>`(7)/(4)h`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39705. |
Velocity -time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all the forces on the particle is |
| Answer» <html><body><p>400 J<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/400j-1874721" style="font-weight:bold;" target="_blank" title="Click to know more about 400J">400J</a>`<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/200j-290162" style="font-weight:bold;" target="_blank" title="Click to know more about 200J">200J</a>`<br/>`200J`</p>Answer :B</body></html> | |
| 39706. |
three pieces of wire of the same intererinal and radius but of different length are tied to three -colliner , , equispesd pege in the ceiling of a room knotted together at their other ends so that the side wirs subtend the same angle alpha with the middaone .If a load P is attached to the knot ,calculate the tension in the wires. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/pcos-2918553" style="font-weight:bold;" target="_blank" title="Click to know more about PCOS">PCOS</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>)/((1+2 cos^(3) alpha)),(p)/((1+2cos^(3)alpha))`</body></html> | |
| 39707. |
The displacement of a particle of mass 3 gm executing S.H.M is given by y = 3 sin(0.2 t) in S.I units. The K.E of a particle at a point which is at a distance equal to 1/3 of its amplitude from its mean position |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(3)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`25 xx 10^(-3)J`<br/>`0.48 xx 10^(-3)J`<br/>`0.24 xx 10^(-3)J`</p>Answer :C</body></html> | |
| 39708. |
Estimate the average mass density of a sodium atom assuming its size to be about 2.5Å. (Use the known values of Avagardo's number and the atomic mass of sodium). Compare it with the mass density of sodium in its crystalline phase : 970 kg m^(-3). Are the two densities of the same order of magnitude ? If so, why ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Radius of sodium atom `r=2.5Å` <br/> `=2.5xx10^(-10)m` <br/> Volume of sodium atom `V.=(4)/(3)pir^(3)` <br/> `=(4)/(3)xx3.14xx(2.5xx10^(-10))^(3)` <br/> `65.416xx10^(-30)` <br/> `~~65.42xx10^(-30)m^(3)` <br/> No. of atoms in 1 mole `N=6.023xx10^(23)` <br/> volume of 1 mole of sodium <br/> V=NV. <br/> `=65.42xx10^(-30)xx6.023xx10^(23)` <br/> `=394.02xx10^(-7)` <br/> `~~3.94xx10^(-5)m^(3)` <br/> Mass of 1 mole of sodium = sodium mass <br/> `M=23g=23xx10^(-3)kg` <br/> Average density of 1 mole atoms of sodium <br/> `rho=(M)/(V)` <br/> `:.rho=(23xx10^(-3))/(3.94xx10^(-5))` <br/> `=5.8375xx10^(2)` <br/> `:.rho~~584kgm^(-3)` <br/> Density of sodium in crystalline <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> <br/> `rho~~970kgm^(-3)` <br/> Ratio `(rho)/(rho.)=(584)/(<a href="https://interviewquestions.tuteehub.com/tag/970-342753" style="font-weight:bold;" target="_blank" title="Click to know more about 970">970</a>)` <br/> =0.6020 <br/> 0.6 <br/> Yes, both densities are in same no. of power. Because atoms are <a href="https://interviewquestions.tuteehub.com/tag/bound-390843" style="font-weight:bold;" target="_blank" title="Click to know more about BOUND">BOUND</a> strongly in solid form. Therefore, <a href="https://interviewquestions.tuteehub.com/tag/atomic-2477" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMIC">ATOMIC</a> density is close to density of solid.</body></html> | |
| 39709. |
What is the temperature of the aluminium junction in the steady state of the system shown in Fig. Length of the load =15.0 cm, length of the aluminium rod =10.0 cm temperature of the furnace = 400" "^(@)C, temperature of the other end =0" "^(@)C. The area of cross section of the lead rod is twice that of the aluminium rod. (Thermal conductivity of steel =34.9" J s"^(-1)m^(-1)K^(-1), and copper =205" J s"^(-1)m-1" "K^(-1)) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`T=56.24^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</body></html> | |
| 39710. |
A particle in a certain conservative force field has a potential energy given by V=(20xy)/(z). The force exerted on it is |
| Answer» <html><body><p>`((20y)/(z))<a href="https://interviewquestions.tuteehub.com/tag/hat-1016178" style="font-weight:bold;" target="_blank" title="Click to know more about HAT">HAT</a>(i)+((20x)/(z))hat(<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>)+((<a href="https://interviewquestions.tuteehub.com/tag/20xy-1822250" style="font-weight:bold;" target="_blank" title="Click to know more about 20XY">20XY</a>)/(z^(2)))hat(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)` <br/>`-((20y)/(z))hat(i)-((20x)/(z))hat(j)+((20xy)/(z^(2)))hat(k)` <br/>`-((20y)/(z))hat(i)-((20x)/(z))hat(j)-((20xy)/(z^(2)))hat(k)` <br/>`((20y)/(z))hat(i)+((20x)/(z))hat(j)-((20xy)/(z^(2)))hat(k)` </p>Answer :B</body></html> | |
| 39711. |
A vessel is filled with mercury to a hiegt of 0.9 m . Could the vessul be completely empited with the aid of a siphon ? If not , to what extent can it be empited ? (Barometer reading is 0.7 mmercury) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.7 m</body></html> | |
| 39712. |
Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms^(-2). The force of friction per quintal is 0.5 N. |
| Answer» <html><body><p></p>Solution :Force of friction = 0.5 N per <a href="https://interviewquestions.tuteehub.com/tag/quintal-611642" style="font-weight:bold;" target="_blank" title="Click to know more about QUINTAL">QUINTAL</a> <br/>`f = 0.5 xx 2000= 1000`per quintal <br/>m = 2000 quintals =` 2000 xx 100` kg <br/>` sin theta = 1/50 , a=2m//s^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` <br/>In <a href="https://interviewquestions.tuteehub.com/tag/moving-548882" style="font-weight:bold;" target="_blank" title="Click to know more about MOVING">MOVING</a> up an inclined <a href="https://interviewquestions.tuteehub.com/tag/plane-1155510" style="font-weight:bold;" target="_blank" title="Click to know more about PLANE">PLANE</a>, force <a href="https://interviewquestions.tuteehub.com/tag/required-1185621" style="font-weight:bold;" target="_blank" title="Click to know more about REQUIRED">REQUIRED</a> against gravity <br/>`= mg sin theta= 39200N` <br/>And force required to produce acceleration = ma. <br/>` = 2000 xx 100 xx 2 = 40,0000 N` <br/>Total force required = 1000+ 39,200 + 40,0000 = 440200 N.</body></html> | |
| 39713. |
A 2 kg mass moving with a velocity of 10 mS^(-1)collides with another 6 kg mass moving in opposite direction with a velocity of 20 ms^(-1)During collision, they stick together. Find the magnitudes of their common velocity and the momentum. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`12.5 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a> ^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>), <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> ms ^(-1)`</body></html> | |
| 39714. |
Three rods A, B and C form an equilateral triangle at 0°C. Rods AB and BC have same coefficient of expansion alpha_(1) and rod AC has alpha_2. If change in angle between AB and BC isd theta then temperature through which system is heated. |
| Answer» <html><body><p>`( sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) d <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>)/( <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> ( alpha_(2) - alpha_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) ))`<br/>`(sqrt(3) d theta )/( 2 (alpha_(2) - alpha_(1) ) )`<br/>`( sqrt(2) d theta )/( 5 (2 alpha_(2) -alpha_(1) ) )`<br/>`( sqrt(3) d theta )/( alpha_(2) - alpha_(1) ) `</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39715. |
The radius of gyration of a body about an axis at a distance of 12 cm from its centre of mass is 13 cm. Find its radius of gyration about a parallel axis through its centre of mass. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :By <a href="https://interviewquestions.tuteehub.com/tag/parallel-1146369" style="font-weight:bold;" target="_blank" title="Click to know more about PARALLEL">PARALLEL</a> axes theorem,<br/>`M(13)^(2)=I_(0)+M(12)^(2)`<br/>`I_(0)=M(13^(2)-12^(2))=M(<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>)`<br/>Its radius of gyration about a parallel <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> through its centre of mass<br/>`<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> = sqrt((I_(0))/(M))=sqrt(25) = 5cm`</body></html> | |
| 39716. |
A physical quantity P is related to four observables a, b, c and d as follows: P= (a^(3)b^(2))/(sqrt(c)d)The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. What is the percentage error in the quantity P? |
| Answer» <html><body><p>`12%`<br/>`13%`<br/>`15%`<br/>`16%`</p>Solution :As `P= (a^(3)<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(sqrt(c)d)` <br/> The percentage error in P is <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/deltap-2053537" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAP">DELTAP</a>)/(P)xx100= [3((Deltaa)/(a))+ 2((Deltab)/(b))+ (1)/(2)((Deltac)/(c))+ (<a href="https://interviewquestions.tuteehub.com/tag/deltad-2053513" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAD">DELTAD</a>)/(d)] xx <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>` <br/> `[ 3 xx 1%+ 2 xx 3%+ (1)/(2) xx 4%+ 2%]= 13%`</body></html> | |
| 39717. |
A sphere rolls down in an inclined plane without slipping. The percentage of translational energy in its total energy is |
| Answer» <html><body><p>`29.6%`<br/>`33.4%`<br/>`71.4%`<br/>`50%`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> `K.E .E_("rot")=(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2) omega^(2)=(1)/(2)((2)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)MR^(2)) omega^(2)=(1)/(5)MR^(2) omega^(2)` <br/> Translational K.E `(E_("<a href="https://interviewquestions.tuteehub.com/tag/trans-1425477" style="font-weight:bold;" target="_blank" title="Click to know more about TRANS">TRANS</a>"))=(1)/(2)Mv^(2)=(1)/(2)MR^(2)omega^(2)` <br/> `E_("rot")=E_("rot")+E_("trans") =(1)/(5) MR^(2)+(1)/(2) MR^(2) omega^(2)=(7)/(10) MR^(2) omega^(2)` <br/> `%"of" E_("trans")=(E_("trans"))/(E_("Tot"))xx100%=(5)/(7)%=71.4%`</body></html> | |
| 39718. |
If a simple pendulum of length 1 is about to start to make SHM, when it is brought a position so that its length has a maximum angular displacement q. If the mass of the bob is m, then the maximum K.E at its mean position is |
| Answer» <html><body><p>`1/2m(l/g)`<br/>`1/2mgl sinq`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> 1`<br/>`mg1(1-cos <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>)`</p>Answer :D</body></html> | |
| 39719. |
What is the difference between radiation and thermal radiation? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The total energy emitted by a body including heat, light. X-rays, y-rays etc. is <a href="https://interviewquestions.tuteehub.com/tag/called-907796" style="font-weight:bold;" target="_blank" title="Click to know more about CALLED">CALLED</a> radiation. The radiation emitted by a body due to its <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> is called <a href="https://interviewquestions.tuteehub.com/tag/thermal-706916" style="font-weight:bold;" target="_blank" title="Click to know more about THERMAL">THERMAL</a> radiation.</body></html> | |
| 39720. |
A wire is bent in the formof a U. shape and a sider of negligible mass is connecting the two verticalslides of the U-shape. This arrangement is dipped in to soap solutiona and lifted, a thin soap film is formed in the frame. It supports a weight of 2.0xx10^(-3)N. If the length of the slider is 40 cm, what is the surface tension of the film? |
| Answer» <html><body><p></p>Solution :`W=2.0xx10^(-2)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>,l=40cm=0.4m` <br/> Upward <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to surface tesion `=Sxx2l` <br/> In equilibrium `W=Sxx2l` <br/> `S=W/(2l)=(2xx10^(-2))/(2xx0.4)=2.5xx10^(-2)Nm^(-1)`</body></html> | |
| 39721. |
Precision of measurement depends on |
| Answer» <html><body><p>Least count of measuring <a href="https://interviewquestions.tuteehub.com/tag/instrument-1046405" style="font-weight:bold;" target="_blank" title="Click to know more about INSTRUMENT">INSTRUMENT</a> <br/>Temperature of <a href="https://interviewquestions.tuteehub.com/tag/surrounding-1235953" style="font-weight:bold;" target="_blank" title="Click to know more about SURROUNDING">SURROUNDING</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/carefulness-406861" style="font-weight:bold;" target="_blank" title="Click to know more about CAREFULNESS">CAREFULNESS</a> of <a href="https://interviewquestions.tuteehub.com/tag/observer-1127626" style="font-weight:bold;" target="_blank" title="Click to know more about OBSERVER">OBSERVER</a> <br/>All of the above </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39722. |
Though the statement quoted above may be disputed, most physicists do have a feeling that the great laws of physics are at once simple and beautiful. Some of the notable physicists, besides Dirac, who have articulated this feeling, are Einstein, Bohr, Heisenberg, Chandrasekhar and Feynman. You are urged to make special efforts to get access to the general books and writings by these and other great masters of physics. (See the Bibliography at the end of this book.) Their writings are truly inspiring! |
| Answer» <html><body><p></p>Solution :`to` (1) Dialogue concerning the two <a href="https://interviewquestions.tuteehub.com/tag/chief-417885" style="font-weight:bold;" target="_blank" title="Click to know more about CHIEF">CHIEF</a> <a href="https://interviewquestions.tuteehub.com/tag/world-1460172" style="font-weight:bold;" target="_blank" title="Click to know more about WORLD">WORLD</a> System <br/> By Galileo in 1632. <br/>(2) <a href="https://interviewquestions.tuteehub.com/tag/de-945063" style="font-weight:bold;" target="_blank" title="Click to know more about DE">DE</a> Revolutionibus Orbium Coelestium. <br/> By <a href="https://interviewquestions.tuteehub.com/tag/nicolas-578392" style="font-weight:bold;" target="_blank" title="Click to know more about NICOLAS">NICOLAS</a> Copernicus in 1543. <br/> (3) <a href="https://interviewquestions.tuteehub.com/tag/physica-2221235" style="font-weight:bold;" target="_blank" title="Click to know more about PHYSICA">PHYSICA</a> by Aristotle <br/> By Aristotle.</body></html> | |
| 39723. |
In perfect elastic collision, the relative velocity of the body before impact is: |
| Answer» <html><body><p>before impact is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> <br/>before impact is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to that after impact <br/>after impact is zero<br/>None of the above is true</p>Solution :`v_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)-v_(2)=0`</body></html> | |
| 39724. |
Doppler's effect will not be applicable when the velocity of sound source is |
| Answer» <html><body><p> Equal to that of the <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a><br/> <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> than the velocity of sound<br/>Greater than the velocity of sound <br/><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 39725. |
The molecular weight of a gas is 2. Find the root mean square velocity of its molecules at 100°C (R=8.3 "J mol"^(-1) "K"^(-1) ) |
| Answer» <html><body><p>`2.155 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) "m/s"`<br/>`1.5 xx 10^(3)` m/s<br/>`3.155 xx 10^(3)` m/s<br/>`4.155 xx 10^(3)` m/s</p>Answer :A</body></html> | |
| 39726. |
A bar magnet of length 5.0 cm and breadth 1.2 cm is rotated about an axis passing through its center and perpendicular to its plane. Find its moment of inertia if the mass of the magnet is 200 g. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a> of inertia `I=(M(l^(2)+b^(2)))/(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)`<br/>`=200xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)(((5xx10^(-2))^(2)+(1.2xx10^(-2))^(2))/(12))`<br/>`= 4.407xx10^(-5)kgm^(2)`</body></html> | |
| 39727. |
A bag of mass M hangs by a long thread and a bullet (mass m) comes horizontally with velocity v and gets caught in the bag. Then for the combined system (bag + bullet) |
| Answer» <html><body><p>momentum is m `Mv"/"(M+m)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/ke-527890" style="font-weight:bold;" target="_blank" title="Click to know more about KE">KE</a>" is "(1/2)Mv^(2)`<br/>Momentum is m `Mv"/"(M+m)M`<br/>`KE" is "m^(2)v^(2)"/"2 (M+m)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39728. |
Two identical heavy spheres are separated by a distance 10 times their radius. Will an object placed at the mid-point of the line joining their centres be in stable equilibrium or unstable equilibrium ? Give reason for your answer. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`implies` Let the <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> and radius of each identical heavy sphere be M and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> respectively. An object of mass m be placed at the mid-point P of the line joining their centres. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_029_S01.png" width="80%"/> <br/> Force acting on the object placed at the midpointdue to each sphere `F_1 =F_2 =(<a href="https://interviewquestions.tuteehub.com/tag/gmm-2090431" style="font-weight:bold;" target="_blank" title="Click to know more about GMM">GMM</a>)/((5R)^2)`The direction of forces are opposite, therefore net force acting on the object is zero. This is equilibrium. <br/>If we move object towards A by distance <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>, <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_029_S02.png" width="80%"/><br/> `F._1=(GMm)/((5R-x)^2)` <br/> `F._2=(GMm)/((5R+x)^2)`<br/> As `F._1 gt F_2,`therefore a resultant force `(F_1 - F_2.)` acts on the object towards sphere A, therefore object start to move towards sphere A and hence equilibrium is unstable.</body></html> | |
| 39729. |
In the Ingenhausz's methodto comparethe thermalconductivityof differentof different substance , the lengthupto whichwax meltedin copper and zinc rods are 9.3 cm and 5 cm respectively . Compare theirthermalconductivites . |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> and `l_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) = <a href="https://interviewquestions.tuteehub.com/tag/5cm-326441" style="font-weight:bold;" target="_blank" title="Click to know more about 5CM">5CM</a>` <br/> `therefore (k_(c))/(k_(z)) = (l_(c)^(2))/(l_(z)^(2)) = ((9.3 cm)/(5cm))^(2) = 3.46` <br/> Thus , the thermal conductivityof copperis 3.46 times <a href="https://interviewquestions.tuteehub.com/tag/thatof-3109688" style="font-weight:bold;" target="_blank" title="Click to know more about THATOF">THATOF</a> <a href="https://interviewquestions.tuteehub.com/tag/zinc-751325" style="font-weight:bold;" target="_blank" title="Click to know more about ZINC">ZINC</a>.</body></html> | |
| 39730. |
a wooden block is floating in a liquid. About 50% of its volume is inside the liquid when the vessel is stationary. Percentage volume immersed when the vessel moves upwards with acceleration a=g.2 is |
| Answer» <html><body><p>0.75<br/>0.25<br/>0.5<br/>`33.33%`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39731. |
The breaking strength of the cable used to pull a body is 40 N. A body of mass 8 kg is resting on a table of coefficient of friction mu=0.20. The maximum acceleration which can be produced by the cable is ( take , g=ms^(-2) ) |
| Answer» <html><body><p>`6 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> ms^(-2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> ms^(-2)`<br/>`8 ms^(-2)`</p>Solution :(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `a_("max")=(T_("max")-mu mg)/(m)=()40-0.2xx8xx(10)/(8)=3 ms^(-2)`</body></html> | |
| 39732. |
In the above problem, the time taken by the displacement vectors of the two fragments to become perpendicular to each other is |
| Answer» <html><body><p>1s<br/>1.5s<br/>2s<br/>4s </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39733. |
What is the temperature of the triple - point of water on an absolute scale whose unit interval size is equal to that of the Fahrenheit scale ? |
| Answer» <html><body><p></p>Solution :Rotation between Fahrenheit and kelvin scale. <br/> `(T_(F)-32)/(180)=(T_(K)-273)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)`. . . (1)<br/> <a href="https://interviewquestions.tuteehub.com/tag/fo-457881" style="font-weight:bold;" target="_blank" title="Click to know more about FO">FO</a> different <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>, <br/> `(T_(F)^(.)-32)/(180)=(T_(K)^(.)-273)/(100)`. . . (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <br/> By subtracting equating (2) from equation (1) <br/> `(T_(F)^(.)-T_(F))/(180)=(T_(K)^(.)-T_(K))=(T_(K)^(.)-T_(K))/(100)` <br/> `:.T_(F)^(.)-T_(F)=(180)/(100)(T_(K)^(.)-T_(K))` <br/> But `T_(K)^(.)-T_(K)=1K` <br/> `:.T_(F)^(.)-T_(F)=(180)/(100)` <br/> Now new temperature at triple point is `273.16K`, <br/> Tmeprature `=273.16xx(180)/(100)` <br/> `=491.688" "^(@)F~~491.69^(@)F`</body></html> | |
| 39734. |
A metre stick is balanced on a knife edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12.0 cm mark, the stick is found to be balanced at 45.0 cm. What is the mass of the metre stick? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`66.0 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>`</body></html> | |
| 39735. |
A metal piece of mass 120 g is stretched to form a plane rectangular sheet of area of cross section 0.54m^(2). If length and breadth of this sheet are in the ratio 1:6, find its moment of inertia about an axis passing through its centre and perpendicular to its plane. |
| Answer» <html><body><p></p>Solution :Mass `M=120g=120xx10^(-3)<a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>` <br/> area `lb=0.54m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> `(l)/(b)=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>),"":.l=(b)/(6)` <br/> `lb=0.54,""(b)/(6).b=0.54` <br/> `b^(2)=0.54xx6impliesb=sqrt3.24=1.8m` <br/> Similarly `l=(0.54)/(1.8)=0.3m`. <br/> Moment of <a href="https://interviewquestions.tuteehub.com/tag/inertia-1043176" style="font-weight:bold;" target="_blank" title="Click to know more about INERTIA">INERTIA</a> <br/> `I=(M(l^(2)+b^(2)))/(12)=(120xx10^(-3)[(0.3)^(2)+(1.8)^(2)])/(12)` <br/> `I=33.3xx10^(-3)<a href="https://interviewquestions.tuteehub.com/tag/kgm-2769156" style="font-weight:bold;" target="_blank" title="Click to know more about KGM">KGM</a>^(2)`</body></html> | |
| 39736. |
A ballet dancer spins about a vertical axis at 120 rpm with arms outstretched. With her arms folded, the moment of inertia about the axis of rotation decreases by 4%. Calculate the new rate of rotation. |
| Answer» <html><body><p></p>Solution :`n_(1)=<a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a>` rpm, `n_(2)=?` <br/> `I_(1(omega_(1)=I_(2)omega_(2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> `I_(1)=<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>` units , then `I_(2)=<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>` units <br/> `100xx120=60xxomega_(2)` <br/> `omega_(2)=200`rpm</body></html> | |
| 39737. |
In the question number 46, if the mass M is hung the free end of the wire, then the extension produc in the wire is |
| Answer» <html><body><p>`(mugL^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) + MgL)/(2YA)`<br/>`(2mugL^(2) + MgL)/(YA)`<br/>`(mugL^(2) + 2MgL)/(2YA)`<br/>`(mugL^(2) + MgL)/(YA)`</p>Solution :Consider a <a href="https://interviewquestions.tuteehub.com/tag/small-1212368" style="font-weight:bold;" target="_blank" title="Click to know more about SMALL">SMALL</a> element oflengthdx at a distance x fromthe load as shown in thewire. <br/><a href="https://interviewquestions.tuteehub.com/tag/tensionin-3102866" style="font-weight:bold;" target="_blank" title="Click to know more about TENSIONIN">TENSIONIN</a> the wire at a distance x from <a href="https://interviewquestions.tuteehub.com/tag/thelower-3191402" style="font-weight:bold;" target="_blank" title="Click to know more about THELOWER">THELOWER</a> end is`T(x) = mugx + Mg` <br/>Let dl be increase in lengthof the elemenet <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_OBJ_FING_PHY_XI_C09_E01_047_S01.png" width="80%"/><br/> Then `Y= (T(x)//A)/(dl//dx)` <br/>`dl =(T(x)dx)/(YA) = ((mugx+Mg)/(YA))dx ""("<a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> (i)")` <br/>`therefore` Totalextensionproduced in thewire is `l = underset(0)overset(L)int ((mugx+Mg)/(YA))dx = (1)/(Y) [(mugx)/(2) +Mgx]_(0)^(L) = (1)/(YA) [(mugL^(2))/(L)+Mgl] =(mugx^(2)+2MgL)/(2YA)`</body></html> | |
| 39738. |
Statement I : A cylinder fitted with a movable piston contains a certain amount of liquid in equilibrium with its vapour. The temperature of the system is kept constant with the help of a thermostat. When the volume of the vapour is decreased by moving the piston inwards, the vapour pressure does not increase. Statement II : Vapour in equilibrium with its liquid, at a constant temperature, does not obey Boyle's law. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/statement-16478" style="font-weight:bold;" target="_blank" title="Click to know more about STATEMENT">STATEMENT</a> I is <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>, statement <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> is true , statement II is a correct explanation for statement I.<br/>Statement I is true, statement II is true , statement II is not a correct explanation for statement I.<br/>Statement I is true, statement II is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>.<br/>Statement I is false, statement II is true.</p>Answer :A</body></html> | |
| 39739. |
It is common observation that rain clouds can be at about a kilometre altitude above the grond. (a) If a rain drop falls from such a height freely under gravity, what will be its speed ? Also calculate in km //h. (g=10 m//s^2) (b) A typical rain drop is about4 mm diameter. Vomentum is mass xxspeed in vagnitude . Estimate its momentum when it hits ground. (c ) Estimate the time required to flatten the drop. (d) Rete of change of momentum id force. Fstmate how much forece such a drop would exert you. (e) Estiate the order of magitude force of magnitude force on umbrella.Typical lateral separation between tao rain drops is5 cm. (Assume that umbrella is circular and has a diameter of1 m and cloth is not prierced through it) |
| Answer» <html><body><p></p>Solution :Here, ` <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>= 1000 m, g=10 m//s^2` <br/> (a) Velcoity of rain drop after fallin height (h) si <br/> ` v = sqrt (2 gh) = sqrt (2 xx 10 xx 1000) = 100 sqrt 2 m//s = ( 100 sqer 2 xx 60 xx 60)/(1000) km// h = 36 0 sqrt 2~~ 510 km //h` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Diameter of drop, ` d = 2 =4 mm or r= 2 mm = 2 xxx 10^(-3)m` <br/> Mass of rain drop, ` m= 4/3/ pi r^3 roh = 4/3 xx (220/7 xx ( 2 xx 10^3)^3 xx 10^(-3)^3 xx 10^3 ~~ 3.4 xx 10 ^(-5) kg` <br/> Mumentum of rain drop when it hits the ground, ` P = mu = ( 3.4 xx 10 ^(-5) xx 100 sqrt 2 ~~ 4.7 xx 10^(-3) kg m//s` <br/> (c ) Timerequired to flatten the frop is <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> t = d/v = (4 xx 10^(-3))/(100 sqrt 2) = 0/028 xx 10^(-3) = 28 xx 10^(-6) s` <br/> (d) Force, ` F= (change in momentum )/(time) = ( P-0)/(Delta t) = ( 4. 7 xx 10^(-3))/(28 xx 10^(-6)) ~~ 16 <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> N` <br/> (e) Given , rakies of umbrella, ` R = 1//2 m` <br/> Area of umbrella ` =pi R^2 = 922) /7 9 1/2 )^2 = (22)/(28) = (11)/(14) ~~ 0.8 m^@` <br/> with average separaion of ` 5 cm (= 5 xx 10^(-2) m), number of drops those will hit nubrella simultanceously <br/> ` = (0.8)/((5 xx 10^(-2))^2` <br/> Net force on umbrella`= 320 xx 168 = 53760 N ~~ 54000 N`.</body></html> | |
| 39740. |
A ball is thrown at a speed of 20 m/s at an angle of 30^(@) with the horizontal. The maximum height reached by the ball is (use g = 10m//s^(2)) |
| Answer» <html><body><p>2m<br/>3m<br/>4m<br/>5m</p>Answer :D</body></html> | |
| 39741. |
transverse waves: |
| Answer» <html><body><p>both in a <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> and in a <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> <br/>in a gas but not in a metal <br/>not in a gas but in a metal<br/> <a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> in a gas nor in a metal </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :both in a gas and in a metal</body></html> | |
| 39742. |
Pendulum clock shows correct time at O^(@)C. At a higher temperature the clock |
| Answer» <html><body><p>Loses time <br/>Gains time <br/><a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> gains nor losees time <br/>all the above are <a href="https://interviewquestions.tuteehub.com/tag/possible-592355" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBLE">POSSIBLE</a> <a href="https://interviewquestions.tuteehub.com/tag/depending-7263846" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDING">DEPENDING</a> on the <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of linear expansion of the pendulum</p>Answer :D</body></html> | |
| 39743. |
Calculate the difference between the two principal specific heat capacities for hydrogen, Given density of hydrogen at a temperature of 270 K and pressure 10 Nm ^(-2) is 0.090 kgm ^(-3). |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> _(P) -C_(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)=r, P //rho = r T, r = P //rho T = <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) //0.09 xx 270 = 4115.22 J kg ^(-1) K ^(-1).`</body></html> | |
| 39744. |
The displacement of an elastic wave is given by the function y = 3 sin omega t + 4 cos omega t.where y is in cm and t is in second. Calculate the resultant amplitude. |
| Answer» <html><body><p></p>Solution :Here `y =3 sin (<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a> t ) + <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> cos (omega t) ""…(1)` <br/> But for a harmonic wave, `y = sin (omega t + phi)` <br/> `therefore y = a [sin (omega t) cos phi+ cos (omega t ) sin phi]` <br/> `therefore y = (a cos phi ) sin (omega t ) + (a sin phi) cos (omega t ) ...(2)` <br/> Comparing equations (1) and (2), we get, <br/> `a cos phi =3""...(3)` <br/> `a sin phi =4""...(4)` <br/> Squaringand adding `a ^(2) cos ^(2) phi + a ^(2) sin ^(2) phi = <a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a> + 16 ` <br/> `therefore a ^(2) (sin ^(2) phi + cos ^(2) phi ) = 25` <br/> `thereofre a ^(2) (1) = 25` <br/> `therefore a ^(2) = 25` <br/> `therefore a = 5 cm (because a gt <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)` <br/> Taking ratio of <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> (4) to equation (3), <br/> `(a sin phi)/( a cos phi) = 4/3` <br/> `therefore tan phi = (4)/(3) implies phi = tan^(-1) ((4)/(3))`</body></html> | |
| 39745. |
Assertion: A combination of two simple harmonic motions with a arbitrary amplitudes and phases is not necessarily periodic. Reason: A periodic motion can always be expressed as a sum of infinite number of harmonic motions with appropriate amplitudes. |
| Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and reson are true and reason is the correct explanation of assertion<br/>If both assertion and reason are true but reason is not the correct explanation of assertion.<br/>If assertion is true but reason is false.<br/>If both assertion and reason are false.</p>Solution :A combination of <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> simple harmonic <a href="https://interviewquestions.tuteehub.com/tag/motions-1104155" style="font-weight:bold;" target="_blank" title="Click to know more about MOTIONS">MOTIONS</a> with arbitrary amplitudes and phases is periodic only if frequency of one motion is an integral multiple of the other's frequency.</body></html> | |
| 39746. |
A satellite is in a circular polar orbit of altitude 300 km. Determine the sparation d at the equator between the ground tracks associated with two successive overhead passes of the satellite. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`d = 2520 <a href="https://interviewquestions.tuteehub.com/tag/km-1064498" style="font-weight:bold;" target="_blank" title="Click to know more about KM">KM</a>`</body></html> | |
| 39747. |
Assertion :Water in a U-tube executes S.H.M when water is replaced by mercury filled up to the same height , the time period of S.H.Mwill increases. Reasion :Time period of liquid oscillating in a U-tube increases with density of liquid . |
| Answer» <html><body><p> If the assertion and reason are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and reason is a correct explanation of the assertion <br/> If both assertion and reason are correct but reason is not the correct explanation of assertion <br/> If assertion is correct but reason is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a> <br/> If both assertion and reason are incorrect </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of oscillation of a liquid in a U-tube is independent of the <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> of liquid.</body></html> | |
| 39748. |
Calculatethe force .F. needed to punch a 1.46cm diameter hole in a steel plate 1.27 cm thick (as shown in fig). The ultimate shear strength of steel is 345 M N//m^(2) |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C10_SLV_040_S01.png" width="80%"/> <br/> As in punching, shearelasticity is involved, the hole will be punched it<br/> `((F_(11))/(A)) gt` ultimateshear stress<br/> `F_(11) gt ` (<a href="https://interviewquestions.tuteehub.com/tag/shear-1205062" style="font-weight:bold;" target="_blank" title="Click to know more about SHEAR">SHEAR</a> stress ) <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> Area <br/> `F_(11)` min `=(3.45xx10^(8))(2pi <a href="https://interviewquestions.tuteehub.com/tag/rl-614468" style="font-weight:bold;" target="_blank" title="Click to know more about RL">RL</a>)(A=2pirL)` <br/> `=(3.45xx10^(8)) (2xx3.14)xx0.73xx10^(-2) xx 1.27 xx 10^(-2)` <br/> `=200KN`</body></html> | |
| 39749. |
The Ratio of the numerical values of the average velocity and average speed of a body is always |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/unity-1438497" style="font-weight:bold;" target="_blank" title="Click to know more about UNITY">UNITY</a><br/>unity or <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> than <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <br/>unity or more<br/>less than unity</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39750. |
A wall OP is inclined to the horizontal ground at an angle alpha. Two particles are projected from points A and B on the ground with same speed (u) in directions making an angle theta to the horizontal (see figure). Distance between points A and B is x_(0) = 24 m. Both particles hit the wall elastically and fall back on the ground. Time of flight (time required to hit the wall and then fall back on to the ground) for particles projected from A and B are 4 s and 2 s respectively. Both the particles strike the wall perpendicularly and at the same location. [In elastic collision, the velocity component of the particle that is perpendicular to the wall gets reversed without change in magnitude] (a) Calculate maximum height attained by the particle projected fromA. (b)Calculate the inclination of the wall to the horizontal (alpha) [g =10 m//s^(2)] |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) `11.25 m` (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>^(-) ((<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>))`</body></html> | |