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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39801. |
A sphere made of a material of specific gravity 8 has a concentric spherical cavity and just sinks in water. Calculate the ratio of the radius of the cavity to that of the outer radius of the sphere. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let the radius of the <a href="https://interviewquestions.tuteehub.com/tag/sphere-1222094" style="font-weight:bold;" target="_blank" title="Click to know more about SPHERE">SPHERE</a> be <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> and that of the cavity be r. Then, since the sphere just sinks in water, <br/> `4/3 pi (R^3 - r^3) rho g = 4/3 pi R^3 rho_w g` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> - (r/R)^3= (rho_w)/(rho) = 1/8` <br.></br.></body></html> | |
| 39802. |
A stone of mass m tied to the end of a string revolves in a vertical circle of radius R. The net force at the lowest and highest points of the circle directed vertically downwards are: [ Choose the correct alternative] Lowest Point"" Highest point (a) mg +T_(1)""mg + T_(2) (b) mg +T_(1)""mg - T_(2) (c ) mg + T_(1)- (mv_(1)^(2))//R""mg - T_(2) + (mv_(1)^(2))//R (d) mg -T_(1) -(mv_(1)^(2))//R"" mg + T_(2) + (mv_(1)^(2))//R T_(1) and v_(1) denote the tension and speed at the lowest point. T_(2) and v_(2) denote corresponding values at the highest point. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Alternative (a) is correct. Note: <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> + `T_(2) = mv_(2)^(2)`/R, <br/> `T_(1) - mg = mv_(1)^(2)`/R in this <a href="https://interviewquestions.tuteehub.com/tag/example-978283" style="font-weight:bold;" target="_blank" title="Click to know more about EXAMPLE">EXAMPLE</a></body></html> | |
| 39803. |
Show the nature of the following graph for a satellite orbiting the earth. (a) KE versus orbital radius R (b) PE versus orbital radius R (b) TE versus orbital radius R |
| Answer» <html><body><p></p>Solution :`implies` consider the diagram, where a satellite of mass m, moving around the earth in a circular <a href="https://interviewquestions.tuteehub.com/tag/orbit-1138163" style="font-weight:bold;" target="_blank" title="Click to know more about ORBIT">ORBIT</a> of radius R. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_030_S01.png" width="80%"/> <br/> Orbital speed of the satellite orbiting the earth isgiven by `V_0=sqrt((GM)/R)` <br/> where, M and R are the mass and radius of the earth.<br/> (a) ` :.`KE of a satellite of mass m, <br/>`K=1/2 mv_0^2 =1/2 mxx(GM)/R` <br/> `:. K prop 1/R` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_030_S02.png" width="80%"/> <br/> It means the KE decreases exponentially with radius. The graph for KE versus orbital radius R is shown in figure<br/> (b) Potential energy of a satellite.<br/> P.<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>. `=-(GMm)/R` <br/> `P.E. prop -1/R` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_030_S03.png" width="80%"/> <br/> The graph for PE versus orbital radius R is shown in figure <br/> (c) Total energy of the satellite <br/> `E = K +U = (GMm)/(2R) - (GMm)/R` <br/> `=- (GMm)/(2R)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E04_030_S04.png" width="80%"/> <br/>The graph for total energy versus orbital radius R is shown in figure <br/> <a href="https://interviewquestions.tuteehub.com/tag/note-1125278" style="font-weight:bold;" target="_blank" title="Click to know more about NOTE">NOTE</a> : We should keep in <a href="https://interviewquestions.tuteehub.com/tag/mind-1096965" style="font-weight:bold;" target="_blank" title="Click to know more about MIND">MIND</a> that Potential energy (PE) and Kinetic Energy (KE) of the satellite-earth system is always <a href="https://interviewquestions.tuteehub.com/tag/negative-570381" style="font-weight:bold;" target="_blank" title="Click to know more about NEGATIVE">NEGATIVE</a>.</body></html> | |
| 39804. |
The gravitational field in a region is given by vec(E) = (2hat(i) + 3hat(j))N//Kg. The workdone by the field when the particle is moved on the line 3y + 2x = 5 |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`vec(E) = 2hat(i) + 3 hat(j)` <br/> The field is represented as <br/> Slope `m_(1) = Tan theta_(1) = 3//2` <br/> The line `<a href="https://interviewquestions.tuteehub.com/tag/3y-311505" style="font-weight:bold;" target="_blank" title="Click to know more about 3Y">3Y</a> + <a href="https://interviewquestions.tuteehub.com/tag/2x-301182" style="font-weight:bold;" target="_blank" title="Click to know more about 2X">2X</a> = 5` can be represented as <br/> slope `m_(2) = Tan theta_(2) = -2//3` <br/> `m_(1) xx m_(2) = -1` <br/> Since, the direction of the field and <a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> are <a href="https://interviewquestions.tuteehub.com/tag/perpendicular-598789" style="font-weight:bold;" target="_blank" title="Click to know more about PERPENDICULAR">PERPENDICULAR</a> the workdone by the field on the particle is zero. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_SLV_035_S01.png" width="80%"/></body></html> | |
| 39805. |
A well insulated box has two compartments A and B with a conducting wall between them. 100 g of ice at 0^(@)C is kept in compartment A and 100 g of water at 100^(@)C is kept in B at time t = 0. The temperature of the two parts A and B is monitored and a graph is plotted for temperatures T_(A) and T_(B) versus time (t) [Fig. (b)]. Assume that temperature inside each compartment remains uniform. (a) Is it correct to assert that the conducting wall conducts heat at a uniform rate, irrespective of the temperature difference between A and B? (b) Find the value of time t_(1) and temperature T_(0) shown in the graph, if it is known that t_(0) = 200 s. Specific heat of ice = 0.5 cal g^(-1) .^(@)C^(-1) Specific heat of water = 1.0 cal g^(-1) .^(@)C^(-1) Latent heat of fusion of ice = 80 cal g^(-1) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) yes , (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `T_(0) = 13.3^(@)C, t_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = <a href="https://interviewquestions.tuteehub.com/tag/217-1823516" style="font-weight:bold;" target="_blank" title="Click to know more about 217">217</a> s`</body></html> | |
| 39806. |
One end of a U-tube containing mercury is connected to a suction pump and the other end to atmosphere. A small pressure difference is maintained between the two columns. Show that, when the suction pump is removed, the column of mercury in the U-tube executes simple harmonic motion. |
| Answer» <html><body><p></p>Solution :When suction pump connected through one end of U-tube, the mercury depressed by h in one limb and in other arm mercury raised by 2h. <br/> The difference in height of mercury in both the limbs = <a href="https://interviewquestions.tuteehub.com/tag/2y-301307" style="font-weight:bold;" target="_blank" title="Click to know more about 2Y">2Y</a> and pressure of `P = 2hpg` in this arms. Here p= density of mercury and g is the acceleration <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a>. If the cross sectional area of arms is A, then force produced due to height of 2h, <br/> `<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= PA` <br/> `=2hpg xxA = (<a href="https://interviewquestions.tuteehub.com/tag/2pga-1836135" style="font-weight:bold;" target="_blank" title="Click to know more about 2PGA">2PGA</a>)h` <br/> `therefore F propto h ""therefore F = kh` <br/> Where `k= 2pgA` is constant. <br/> This force is opposite to displacement, `F= -kh` <br/> Hence, restoring force acts on oscillation of mercury column is directly proportional to displacement and opposite to displacement. So the motion of mercury in U-tube is simple harmonic motion.</body></html> | |
| 39807. |
A capillary tube of radius 0.25mm is submerged vertically in water so that 25mm of its length is outside water. The radius of curvature of the meniscus will be ( T = 75 xx 10^(-3) "N/m") |
| Answer» <html><body><p>0.2 mm<br/>0.4 mm<br/>0.6 mm<br/>0.8 mm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39808. |
Obtain an expression for total energy of a satellite revolving in circular orbit around a planet . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :GravitationalP.E. at a point above the surface of the earth at a distance r = R + h is given by P.E. = `(-GM m)/(r)` where 'M' is mass of the earth and m is the mass of the satellite . <br/> kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of satellite = `(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) (GMm)/(r)` <br/> Total energy of satellite = E = PE + KE <br/> Hence E = `(-GMm)/(r) + (1)/(2) (GMm)/(r)` <br/> i.e., `E = - (1)/(2) (GMm)/(r)` <br/> The `-ve` sign <a href="https://interviewquestions.tuteehub.com/tag/indicates-1041501" style="font-weight:bold;" target="_blank" title="Click to know more about INDICATES">INDICATES</a> that the satellite is bounded to the earth .</body></html> | |
| 39809. |
At what points along the path of a simple pendulum is the tension in the string maximum and |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> is maximun at the <a href="https://interviewquestions.tuteehub.com/tag/mean-1091459" style="font-weight:bold;" target="_blank" title="Click to know more about MEAN">MEAN</a> <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> (=<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>)</body></html> | |
| 39810. |
A lift is moving upward with an acceleration a. The apparent weight of a person standing in the lift will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> than the <a href="https://interviewquestions.tuteehub.com/tag/actual-361632" style="font-weight:bold;" target="_blank" title="Click to know more about ACTUAL">ACTUAL</a> weight<br/>more than the actual weight<br/>zero<br/>same as his actual weight</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39811. |
A particle of mass m is moving yz-plane with a uniform velocity v with its trajectory running parallel to +ve y-axis and intersecting z-axis at z = a. The change in its angular momentum about the origin as it bounces elastically from a wall at y = constant is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mva-6227" style="font-weight:bold;" target="_blank" title="Click to know more about MVA">MVA</a> `bar(i)`<br/>2 mva `bar(j)`<br/>`-mva bar(j)`<br/>`-2amv bar(i)` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39812. |
Which physical quantity is conserved during the oscillation of a simple pendulum ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of the <a href="https://interviewquestions.tuteehub.com/tag/bob-399946" style="font-weight:bold;" target="_blank" title="Click to know more about BOB">BOB</a> is conseved.</body></html> | |
| 39813. |
An equilateral triangle ABCformed from a uniform wire has two small identical beads initially located at A. The triangle is set rotating about the vertical axis AO. Then the beads are released from rest simultaneously and allowed to slide down, one along AB and other along AC as shown. Neglecting frictional effects, the quantities that are conserved as the beads slide down, are: |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> velocity and total energy<br/>Total angular <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> and total energy<br/>Angular velocity and M.I. about the <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> of rotation<br/>Total angular momentum and M.I. about the axis of rotation</p>Answer :B</body></html> | |
| 39814. |
A solid cylinder of mass.m. rolls without slippling down an inclined plane making an angle theta with the horizontal. The fricitional force between the cylinder and the incline is: |
| Answer» <html><body><p>`mg <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta`<br/>`(mg sin theta)/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`mg cos theta`<br/>`(2mg sin theta)/3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39815. |
At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume gamma=1.41. Thework done on gas will be |
| Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/1280j-1783430" style="font-weight:bold;" target="_blank" title="Click to know more about 1280J">1280J</a> <br/>1610 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/> <a href="https://interviewquestions.tuteehub.com/tag/1824-1799163" style="font-weight:bold;" target="_blank" title="Click to know more about 1824">1824</a> J<br/>2025 J</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39816. |
A horizontal stick of mass m has its right end attached to a pivot on a wall, while its left end rests on the top of a cylinder of mass m which in turn rests on an incline plane inclined at an angle theta. The stick remains horizontal. The coefficient of friction between the cylinder and both the plane and the stick is mu. Find the minimum value ofmuas function of theta for which the system stays in equilibrium. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> sin theta)/(1 + cos theta)`</body></html> | |
| 39817. |
A ball of mass m strikes a bat with velocity v. If it retraces its path with the same speed, what is the impulse imparted by the bat ? |
| Answer» <html><body><p>zero<br/>2 mv<br/>mv<br/>3 mv</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39818. |
When a force of 10.0 N is exerted on the handle of a door, the door can be just opened. If the handle is a distance of 50 cm from the hinges find the torque applied on the door. |
| Answer» <html><body><p></p>Solution :`tau = <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta = 0.50 xx 10.0 sin 90^(@)=5Nm`</body></html> | |
| 39819. |
Two parallel plane sheets 1 and 2 carry uniform charge densities sigma_(1) and sigma_(2) as in fig. Find the electric field in the region marked prod (sigma_(1) gt sigma_(2)) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`((sigma_1-sigma_2))/(2in_0)`</body></html> | |
| 39820. |
Two solids spheres of diameter d_(1) and d_(2) having material densities rho_(1) and rho_(2) are placed in contact with each other on the horizontal plane. The height of the combined center of mass from plane |
| Answer» <html><body><p>`h=((d_(1)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)rho_(1)+d_(2)^(2)rho_(2))/(d_(1)rho_(1)+d_(2)rho_(2)))`<br/>`h=(d_(1)^(4)rho_(1)+d_(2)^(4)rho_(2))/(2(d_(1)^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)rho_(1)+d_(2)^(3)rho_(2)))`<br/>`h=((d_(1)rho_(1)+d_(2)rho_(2))/(rho_(1)+rho_(2)))`<br/>`h=((d_(1)^(2)rho_(1)+d_(2)^(2)rho_(2))/(d_(1)^(3)rho_(1)+d_(2)^(3)rho_(2)))`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39821. |
A projectile fired with velocity u at right angle to the slope which is inclined at an angle thetawith horizontal. The expression for R is |
| Answer» <html><body><p>`(2u^2)/(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>) <a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>` <br/>`(2u^2)/(g) <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a> theta `<br/>`(2u^2)/(g) tan^2 theta` <br/>`(2u^2)/(g) tan theta sec theta `</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39822. |
The velocity time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 sec are respectively. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> m, 16m<br/>16m, 8m<br/>16m, 16m<br/>8m, 8m</p>Answer :A</body></html> | |
| 39823. |
Sometimes when the speed of vehicle increased, its body start to bounce why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Natural frequency of vehicle and frequency of vehicle <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to rough road becomes <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> then rosonance occurs and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> the amplitude becomes large, So <a href="https://interviewquestions.tuteehub.com/tag/vehicles-1444476" style="font-weight:bold;" target="_blank" title="Click to know more about VEHICLES">VEHICLES</a> bounces.</body></html> | |
| 39824. |
Four rods of equal length l and mass m each form a square as shown in figure. The moment of inertia of the system about the axis 1 and axis 2 is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>/<a href="https://interviewquestions.tuteehub.com/tag/3ml-1863565" style="font-weight:bold;" target="_blank" title="Click to know more about 3ML">3ML</a>^(2),5/3ml^(2)`<br/>`5/3ml^(2),(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)/3ml^(2)`<br/>`1/3ml^(2),5/3ml^(2)`<br/>`(10)/(3)ml^(2),2/3ml^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39825. |
(A) : In a measurement, two readings obtained are 10.001 and 10.0001. The second measurement is more precise. (R) : Measurement having more decimal places is more precise. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :A</body></html> | |
| 39826. |
(A) : Power associated with torque is product of torque and angular speed of the body about the axis of rotation.(R ) : Torque in rotational motion is analogue to force in translatory motion. |
| Answer» <html><body><p>Both (A) and (R ) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>Both (A) and (R ) are false </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39827. |
A gas occupying a volume of 10^(-2) m ^(3).at a pressure of 5 atmospheres expands isothermally to a pressure of 1 atmosphere. Calculate the work done. |
| Answer» <html><body><p></p>Solution :`W =<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> . 303 <a href="https://interviewquestions.tuteehub.com/tag/rt-615359" style="font-weight:bold;" target="_blank" title="Click to know more about RT">RT</a> log _(10) (<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> _(2) //V _(1)) = 2. 303 P _(1) V _(1) log _(10) (P_(1) //P_(2)) = 2. 303 xx 5 xx 101325 xx 10 ^(-2) log _(10) (5//1) = <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>. 155 xx 10 ^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) Nm`</body></html> | |
| 39828. |
In the adiabatic compression, the decrease in volume is associated with |
| Answer» <html><body><p>Increase in temperature and increase in <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/decrease-946104" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASE">DECREASE</a> intemperature and increase in pressure <br/><a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> intemperature and decrease in pressure <br/>increase intemperature and decrease in pressure </p>Answer :A</body></html> | |
| 39829. |
Define wave vector and reciprocal vectors also write the relationship between velocity and reciprocal vectors. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The wave number is the <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> of a vector called wave vector. The points in space of wave <a href="https://interviewquestions.tuteehub.com/tag/vectors-14090" style="font-weight:bold;" target="_blank" title="Click to know more about VECTORS">VECTORS</a> are called reciprocal vectors, `veck`. <br/> Dimensions of `vec k` is `L^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> Velocity, `v= <a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a>, f=(lambda)/(2pi) (2pi f)` <br/> `=(2pi lambda)/(2pi//lambda)` <br/> `=(omega)/(k)`</body></html> | |
| 39830. |
If R is the range of a projectiel on a horizontal plane and h its maximum height, the maximum horizontal range with the same velocity ofprojection is: |
| Answer» <html><body><p>2h<br/>`(R^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(8h)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>+(h^(2))/(8R)`<br/>`2h+(R^(2))/(8h)`</p>Solution :`2h+(R^(2))/(8h)=(2u^(2)<a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a>^(2)theta)/(2g)+(u^(4)sin^(2)theta//<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>^(2))/(8xxu^(2)sin ^(2)theta//2g)` <br/> `=(u^(2))/(g) sin^(2)theta+(u^(2))/(g) cos^(2)theta` <br/> `=(u^(2))/(g)=R_("max")`</body></html> | |
| 39831. |
A thin wire of mass.m. and length .L. is bent in the form of a ring. The M.I. of the ring about a tangential axis parallel to any of its diameters is: |
| Answer» <html><body><p>`(mL^(2))/(2pi^(2))`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/3ml-1863565" style="font-weight:bold;" target="_blank" title="Click to know more about 3ML">3ML</a>^(2))/(8pi^(2))`<br/>`(2mL^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/5pi-1900435" style="font-weight:bold;" target="_blank" title="Click to know more about 5PI">5PI</a>^(2))`<br/>`(mL^(2))/(6pi^(2))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39832. |
A smooth sphere 'A' of mass 'm' is moving with a contant speed 'v' on the smooth horizontal surface collides elastically with an identical sphere at 'B' at rest. After elastic speed of sphere 'A' is V/2 then the speed of sphere of 'B' is |
| Answer» <html><body><p>`(V)/(2)`<br/>`(3V)/(2)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3)V)/(2)`<br/>`(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)V)/(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39833. |
Total energy of particle performing S.H.M. depends on |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/amplitude-859568" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDE">AMPLITUDE</a>, <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> <br/>Amplitude, Time period and displacement<br/>Amplitude, displacement<br/>Time period displacement</p>Answer :A</body></html> | |
| 39834. |
A certain number of spherical drops of a liquid of a liquid of radius r coalesce to form a single drop of radius R and volume V. if T is the surface tension of the liquid, then |
| Answer» <html><body><p>`"<a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>"=4VT(1/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>-1/R)"is released"`<br/>`"energy"=3VT(1/r+1/R)"is absorbed"`<br/>`"energy"=3VT(1/r-1/R)"is released"`<br/>energy is <a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> released nor absorbed.</p>Solution :`A_f=4piR^2=3/34pi(R^3)/( R)=(3V)/(R )` <br/> `A_i=nxx4pir^2=(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)/(4/3 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> r^3)4pir^2=(3V)/( r)` <br/> Hence, energy released `=(A_i-A_f)T=3VT(1/r-1/R)`</body></html> | |
| 39835. |
In Q.4. work done by tangential force on the body is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> <br/>non-zero <br/><a href="https://interviewquestions.tuteehub.com/tag/sometimes-648384" style="font-weight:bold;" target="_blank" title="Click to know more about SOMETIMES">SOMETIMES</a> zero and other <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> not<br/>cannot say</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39836. |
What is average acceleration? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> acceleration is defined as the <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of change in velocity over the time <a href="https://interviewquestions.tuteehub.com/tag/interval-1049953" style="font-weight:bold;" target="_blank" title="Click to know more about INTERVAL">INTERVAL</a> `a_(avg)=(DeltavecV)/(Deltat)`. It is a <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> quantity.</body></html> | |
| 39837. |
A flywheel of mass 100 kg and radius 1 m is rotating at the rate of 420 rev/min. Find the constant retarding torque to stop the wheel in 14 revolutions, the mass is concentrated at the rim. M.I. of the flywheel about its axis of rotation I = mr^(2). |
| Answer» <html><body><p></p>Solution :Mass of flywheel = m = <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> kg <br/> Radius= <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> = 1m <br/> `I = mr^(2) = 100 xx 1^(2) = 100 kg m^(2)` <br/> Initial angular velocity `=omega_(0) = 2pir = 2 xx 3.14 xx 420/60 = 43.96 "rad"//s^(2)` <br/> Final angular velocity `=omega =0` <br/> Angular displacement in 14 <a href="https://interviewquestions.tuteehub.com/tag/revolution-623158" style="font-weight:bold;" target="_blank" title="Click to know more about REVOLUTION">REVOLUTION</a> = `14 xx <a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> = 28 pi` radian. <br/> `alpha = (omega^(2) - omega_(0)^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>) = (0-43.96^(2))/(2 xx 28 pi) =-10.99 "rad"//s^(2)`<br/> Torque required to stop the flywheel `=tau = Ialpha = 100 xx 10.99 = 1099` Nm</body></html> | |
| 39838. |
A couple produces ....... |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/pure-1172806" style="font-weight:bold;" target="_blank" title="Click to know more about PURE">PURE</a> rotation<br/>pure translation<br/>rotation and translation<br/>no motion</p>Answer :A</body></html> | |
| 39839. |
In the given expression X=(abz^2)/(h^3), which physical quantity should be measured more accurately to give the most accurate answer? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Since the power of h is highest, it should be <a href="https://interviewquestions.tuteehub.com/tag/measured-7257656" style="font-weight:bold;" target="_blank" title="Click to know more about MEASURED">MEASURED</a> most accurately to <a href="https://interviewquestions.tuteehub.com/tag/give-468520" style="font-weight:bold;" target="_blank" title="Click to know more about GIVE">GIVE</a> accurate <a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a>.</body></html> | |
| 39840. |
Given in figure. Are examples of some potential energy functions in one dimension (i) to (iv). The total energy E of the particle is indicated by the cross mark on energy axis. In each case, specify the refions, if any, in which the particle cannot be found for the given energy. Also, indicatethe minimum total energy the particle must have in each case. Think of simple physical contests for which these potential energy shapes are relevant. |
| Answer» <html><body><p></p>Solution :We know that total <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> `<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>=K.E.+P.E.` or `K.E.=E-P.E.` and `K.E.` can never be negative. The object cannot exist in the region, where its K.E. would becomenegative. <br/> (i) For`<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> gt a`, P.E. `(V_(0) gt E` <br/> `:.` K.E. becomes negative. Hence, the objectconnot exist in the region `xgta`. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)For `x lt a` and `x gt bP.E. (V_(0)) gt E.` <br/> `:.` K.E. becomes negative. Hencethe objectcannot be present in the region `x gt a` and `x gt b`. <br/> (iii) Object cannot exist in any region because P.E. ` (V_(0) gt E` in <a href="https://interviewquestions.tuteehub.com/tag/every-976721" style="font-weight:bold;" target="_blank" title="Click to know more about EVERY">EVERY</a> region. <br/> (iv) On the same basis, the object cannot exist in the region`-b//2 lt x lt -a//2` and `a//2 lt x lt b//2`.</body></html> | |
| 39841. |
Two masses 8 kg and 12 kg are connected at the two ends of a light inextensible string that goes over a frictionless pulley. Find the acceleration of the masses, when the masses are released. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :T`- <a href="https://interviewquestions.tuteehub.com/tag/8xx-1931282" style="font-weight:bold;" target="_blank" title="Click to know more about 8XX">8XX</a> 10 = <a href="https://interviewquestions.tuteehub.com/tag/8a-340116" style="font-weight:bold;" target="_blank" title="Click to know more about 8A">8A</a>, 12 xx 10 - T = 12 a`<br/> i.e.,a = 2m`cdot s^(-2)`, T = <a href="https://interviewquestions.tuteehub.com/tag/96-342541" style="font-weight:bold;" target="_blank" title="Click to know more about 96">96</a> N</body></html> | |
| 39842. |
When a mass 'm' is attached to a vetical spring and slowly released, the extension in the spring is 'x'. When a mass '2m' is attached to the same spring and released suddenly, the extension in the spring is |
| Answer» <html><body><p>x<br/>2x<br/>3x<br/>4x</p>Answer :D</body></html> | |
| 39843. |
A bimetallic strip is made by rivetting two thin linear strips of copper ( alpha_C) and Iron ( alpha_1) at a temperature of theta_0. The thickness of each strip is 'd' and length of each is L_0. At some higher temperature theta, the bimetallic bends into an arc of angle theta as shown, so that the two electricalcontacts touch and electrical control system is activated. Now phi= (L_0)/( K alpha) ( alpha_( C) - alpha_(1) ) ( theta - theta_(0) ) , where K= |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 39844. |
If a body is raised from the surface of the earth upto height R, what is the change in potential energy? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mgr-2831250" style="font-weight:bold;" target="_blank" title="Click to know more about MGR">MGR</a><br/>`(3)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)mgR`<br/>`(mgR)/(2)`<br/>`(mgR)/(4)`</p>Solution :`P.E=mgh` <br/> `h=(R )/(2)` <br/> `therefore P.E=(mgR)/(2)`</body></html> | |
| 39845. |
A uniform chain of length L and mass M overhangs a horizontal table with its two third part on the table. The friction coefficient between the table and the chain is mu. The work done by the friction during the period the chain slips off the table is -(2muMgL)//x). Find x. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a></body></html> | |
| 39846. |
10 gm of ice at- 10° C is mixed with 100 gm of water at 50° C contained in a calorimeter weighing 50gm. (Specific heat of water = cal, gm^(-1).°C^(-1), Latent heat of ice = 80 cal//gm,specific heat of ice =0.5 "cal/gm/°C" and specific heat of copper = 0.09 "cal/gm/"°C). The final temperature reached by the mixtures is |
| Answer» <html><body><p>25.5°<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>30.0°C<br/>38.2°C<br/>40.0°C</p>Answer :C</body></html> | |
| 39847. |
An aircraft is flying at a height of 3400 m above the ground. If the angle subtended at a ground observation point by the aircraft positions 10.0 s apart is 30°, what is the speed of the aircraft ? (tan = 15° = 0.2679) |
| Answer» <html><body><p></p>Solution :Let O be the <a href="https://interviewquestions.tuteehub.com/tag/ground-1013213" style="font-weight:bold;" target="_blank" title="Click to know more about GROUND">GROUND</a> observation point and A, B, C be the <a href="https://interviewquestions.tuteehub.com/tag/positions-1159905" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIONS">POSITIONS</a> of the aircarft at t = <a href="https://interviewquestions.tuteehub.com/tag/0s-256530" style="font-weight:bold;" target="_blank" title="Click to know more about 0S">0S</a>, t = 5s and t = 10 s respectively, <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_C04_SLV_022_S01.png" width="80%"/> <br/> Clearly, `tan15^(@) = (AB)/(OB)` or `AB= OB tan 15^(@)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, distance travelled by the <a href="https://interviewquestions.tuteehub.com/tag/aircraft-3321" style="font-weight:bold;" target="_blank" title="Click to know more about AIRCRAFT">AIRCRAFT</a> in 10s, <br/> i.e., `s = AC = 2AB = 2(OB tan 15^(@))` <br/> `= 2 xx 3400 xx 0.2679 = 1822 m` <br/> Speed of the aircraft `= (s)/(t) = (1822m)/(10s) = 182.2 m//s`</body></html> | |
| 39848. |
State the law of equipartition of energy. |
| Answer» <html><body><p></p>Solution :According to kinetic theory the average kinetic energy of system of molecules in thermnal equilibrium at tempreture T is uniformly distributed all degrees of freedom (x or y or z direction of motion ) so that each degree of freedom will <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> `(1)/(2)kT` of energy. This is called <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of <a href="https://interviewquestions.tuteehub.com/tag/equipartition-2618579" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIPARTITION">EQUIPARTITION</a> of energey. <br/> Average <a href="https://interviewquestions.tuteehub.com/tag/kinectic-2147477" style="font-weight:bold;" target="_blank" title="Click to know more about KINECTIC">KINECTIC</a> energy of <a href="https://interviewquestions.tuteehub.com/tag/monatomic-2840882" style="font-weight:bold;" target="_blank" title="Click to know more about MONATOMIC">MONATOMIC</a> molecule `(with int=3)=3xx(1)/(2)kT=(3)/(2)kT` <br/>Average kinectic energy of diatomic molecule at low tempreture `(withint=5)=5xx(1)/(2)kT=(5)/(2)kT` <br/>Average kinectic energy of diamotic molecule at thehigh tempreture `(withint=7)=7xx(1)/(2)kT=(7)/(2)kT` <br/>Average kinectic energy of linear triatomicmolecule `(withint=7)=7xx(1)/(2)kT=(7)/(2)kT` <br/> Average kinectic energy of non linear triatomicmolecule `(withint=6)=6xx(1)/(2)kT=3kT`.</body></html> | |
| 39849. |
The length of a pendulum is measured as 1.01m and time for 30 oscillations is measured as one minute 3 seconds. Error in length is 0.01m and error in time is 3 secs. The percentage error in the measurement of acceleration due to gravity is |
| Answer» <html><body><p>`1`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>`<br/>`10`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a>`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39850. |
During an experiment, an idea/gas is found to obey an additional law VP^(2) = constant . The gas is initially at temperature T and volume V. What will be the temperature of the gas when it expands to a volume 2 V? |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :According to the given problem `VP^(2)` =<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>. constant. So the gas equation <a href="https://interviewquestions.tuteehub.com/tag/pv-593601" style="font-weight:bold;" target="_blank" title="Click to know more about PV">PV</a> = nRT in the light of above (eliminating P) <a href="https://interviewquestions.tuteehub.com/tag/yields-1465159" style="font-weight:bold;" target="_blank" title="Click to know more about YIELDS">YIELDS</a> <br/> `((K)/(sqrt(V))) V = nRt , `i.e., `sqrt(V)= (nR)/(K ) T ` <br/> `therefore sqrt((V_(1))/(V_(2))) = ((T_(1))/(T_(2)))," i.e., " sqrt((V)/(2V)) = (T)/(T^(1))` <br/> or `T^(1) = (sqrt(2))T `</body></html> | |