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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39851. |
A particle in a circular motion covers a distance of 0.5 pi rwhere r is the radius of the circular path. What is the angular displacement ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@)`</body></html> | |
| 39852. |
A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (iv) period |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Given, `y=0.5cos(1500pit+0.8)=0.5sin((<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(2)-1500pit-0.8)=0.5sin[-1500pit-(0.8-(pi)/(2))]` <br/> `y=-0.5sin[1500pit+(0.8-(pi)/(2))]` <br/> Now (iv) `"period "=(1)/("<a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a>")=(1)/(750)=0.00133=1.33xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)s.`</body></html> | |
| 39853. |
A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (iii) angular frequency |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a>, `y=0.5cos(1500pit+0.8)=0.5sin((<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(2)-1500pit-0.8)=0.5sin[-1500pit-(0.8-(pi)/(2))]` <br/> `y=-0.5sin[1500pit+(0.8-(pi)/(2))]` <br/> Now (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) angular <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> `omega=1500pi=4.713xx10^(3)" rads"^(-1)`</body></html> | |
| 39854. |
300 g of water at 25^(@)C is added to 100 g of ice at 0^(@)C. The final temperature of the mixture is |
| Answer» <html><body><p>`(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)/( 3) ° <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`(-5)/( <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)° C`<br/>`-5^(@) C`<br/>`0^(@) C`</p>Answer :D</body></html> | |
| 39855. |
A child stands, hands at the side, on a turntable. The kinetic energy of system is K. The child now raises his arms, and the moment of inertia of system becomes twice. Then the kinetic energy of system will be ………… |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2k-300402" style="font-weight:bold;" target="_blank" title="Click to know more about 2K">2K</a>`<br/>`(K)/(2)`<br/>`(K)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`4K`</p>Solution :No <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> is acting so angular momentum is constant <br/> `therefore I_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)omega_(1)=I_(2)omega_(2)` <br/> `therefore omega_(2)=(I_(1)omega_(1))/(I_(2))=(omega_(1))/(2)[because I_(2)=2I_(1)]` <br/> Now rotational kinetic energy <br/> `therefore K_(1)=(1)/(2)I_(1)omega_(1)^(2)` and <br/> `therefore K_(2)=(1)/(2)I_(2)omega_(2)^(2)` <br/> `=(1)/(2)(2I_(1))((omega_(1))/(2))^(2)` <br/> `=(1)/(2)(I_(1)omega_(1)^(2))/(2)` <br/> `=(K)/(2)`</body></html> | |
| 39856. |
The standard scale of temperature is |
| Answer» <html><body><p>the <a href="https://interviewquestions.tuteehub.com/tag/mercury-558950" style="font-weight:bold;" target="_blank" title="Click to know more about MERCURY">MERCURY</a> scale<br/>the gas scale <br/>the platinum <a href="https://interviewquestions.tuteehub.com/tag/resistance-1186351" style="font-weight:bold;" target="_blank" title="Click to know more about RESISTANCE">RESISTANCE</a> scale <br/><a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> scale</p>Solution :N//A</body></html> | |
| 39857. |
A lead ball dropped into a take from a diving board 5m above the water hitsthe water with certain velocity and then sinks to the bottom with the same constant velocity. If it reaches the bottom in 3s after it is dropped the depth of the take is (g=10ms^(-2)) |
| Answer» <html><body><p>30m<br/>15m<br/>10m<br/>20m</p>Answer :D</body></html> | |
| 39858. |
A particle of mass m _(1) makes a head on elastic collision with a stationary particle of mass m _(2). What fraction of kinetic energy is (a) retained by m _(1) (b) transferred onto m _(2) ? |
| Answer» <html><body><p></p>Solution :(a) ` v _(1) = (( m _(1) - m _(2)) u + <a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a> _(2) (o))/( m _(1) + m _(2)) <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> (( v _(1))/(u ))^(2) = ((m_(1) - m _(2))/(m _(1) + m _(2))) ^(2)` <br/> `implies ((1)/(2) m _(1) v _(1) ^(2))/( (1)/(2) m _(1) u ^(2)) = ((m _(1) - m _(2)) /( m _(1) +m _(2))) ^(2) (KE of 1 ^(st ) " particle finally")/(KE of 1 ^(st) "particle initially") = (( m _(1) - m _(2))/( m _(1) + m _(2))) ^(2)` <br/> `therefore` fraction of KE retained by `1 ^(st)` body `f _(1) = ((m _(1) - m _(2))/( m _(1) + m _(2)) ) ^(2)`<br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `v _(2) = (2 m _(1) u + ( m _(2) - m _(1)) 0o)/(m _(1) + m_(2)) implies(v _(2))/( u ) = (2m _(1))/( m _(1) + m _(2))` <br/> `f _(2) = ((1)/(2) m _(2) v _(2) ^(2))/( (1)/(2) m _(1) u ^(2))= (m_(2))/( m _(1)) [ ( 2m _(1))/( m _(1) + m _(2)) ] ^(2)` <br/> `therefore f _(2) = ( 4m _(1) m _(2))/( ( m _(1) + m _(2)) ^(2))` (fraction of KE given to `2 ^(nd)` body)</body></html> | |
| 39859. |
Two capillary tubes of same length but different radii r_1 and r_2 are fitted in parallel to the bottom of a vessel. The pressure head is P. What should be the radius of a single tube that can replace the two tubes so that the rate of flow is same as before |
| Answer» <html><body><p>`r_(1)^(4) + r_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)^(4)`<br/>`(r_(1)^(2) + r_(2)^(2) )^(1/4)`<br/>`(r_(1)^(4) + r_(2)^(4) )^(1/4)`<br/>`r_(1) + r_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39860. |
The specific heat capacity of a gas at constant pressure is greater than that at constant volume because |
| Answer» <html><body><p>at <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> volume, all the heat supplied <a href="https://interviewquestions.tuteehub.com/tag/goes-2676180" style="font-weight:bold;" target="_blank" title="Click to know more about GOES">GOES</a> to <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> the <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> energy of the gas <br/>at constant there is no change in temperature of the gas when heat is supplied <br/>at constant pressure, there is no change in internal energy of the gas when heat is supplied<br/>the gas expands when its temperature increase at constant pressure</p>Answer :A</body></html> | |
| 39861. |
A uniform chain of length .L. and mass .m. is on a smooth horizontal table, with (1)/(n) th part of its length hanging from the edge of the table. Find the kinetic energy of the chain as it completely slips off the table. |
| Answer» <html><body><p></p>Solution :With respect to the top of the table, the initial potential energy of the chain, <br/>`U_(1)= PE` of the chain lying on the table + PE of the <a href="https://interviewquestions.tuteehub.com/tag/hanging-1015416" style="font-weight:bold;" target="_blank" title="Click to know more about HANGING">HANGING</a> <a href="https://interviewquestions.tuteehub.com/tag/part-596478" style="font-weight:bold;" target="_blank" title="Click to know more about PART">PART</a> of the chain<br/>`=L(1-(1)/(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>))mg(0)+(m)/(n)g(-(L)/(2n))=-(mgL)/(2n^(2))`<br/>P.E of the chain, when it just slips off the table,<br/>`U_(2)=mg((-L)/(2))=-(mgL)/(2)`<br/>From law os conservation of energy<br/>`<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> K =- Delta U "" K_(f)-K_(i)=-(U_(f)-U_(i))`<br/>`because K_(i)=0 , K_(f)=-[-(mgL)/(2)-(-(mgL)/(2n^(2)))]`<br/>`K_(f)=(mgL)/(2)[1-(1)/(n^(2))]`<br/>If .V. is the velocity of the chain, then,<br/>`(1)/(2)mv^(2)=(mgL)/(2)[1-(1)/(n^(2))] <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> v=sqrt(gL[1-(1)/(n^(2))]`</body></html> | |
| 39862. |
If the net torque acting on the body is zero, then the body is in |
| Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/translational-3229278" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLATIONAL">TRANSLATIONAL</a> <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a><br/> <a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> equilibrium<br/>mechanical equilibrium<br/>none </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39863. |
Explain linear expansion . |
| Answer» <html><body><p></p>Solution :Increase in length of substance `(Deltal)` is directly proportional to original length ..l.. and increase in <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> `..DeltaT..`, <br/> `:.Deltalalphal" and "Deltal alphaDeltaT` <br/> `:.DeltalalphalDeltaT` (combinely) <br/> `:.(Deltal)/(l)alphaDeltaT` <br/> Hence, the fractional change in length. `((Deltal)/(l))` is directly proportional to `DeltaT`. <br/> `:.(Deltal)/(l)propDeltaT` <br/> `:.(Deltal)/(l)=alpha_(l)DeltaT` <br/> `:.Deltal=alpha_(l)lDeltaT` . . . . (1) <br/> Where `alpha_(l)` is coefficient of linear expansion and is characteristic of material. <br/> Value of `alpha_(l)` depends on type of material and temperature. <br/> If the temperature difference is not <a href="https://interviewquestions.tuteehub.com/tag/large-1066424" style="font-weight:bold;" target="_blank" title="Click to know more about LARGE">LARGE</a> then `.alpha_(l).` doesn.t depend on temperature. <br/> Unit of `alpha_(l)` is `(""^(@)C)^(-1)` or `K^(-1)`. <br/> In equation (1), `Deltal=l_(2)-l_(1)` and `DeltaT=T_(2)-T_(1)`, <br/> `l_(2)=l_(1)=alpha_(l)l_(1)(T_(2)-T_(1))` <br/> `:.l_(2)=l_(1)+alpha_(l)l_(1)(T_(2)-T_(1))` <br/> `:.l_(2)=l_(1)[1+alpha_(l)(T_(2)-T_(1))]` <br/> By taking `alpha_(l)=alpha` and `l_(1)=l` <br/> `l_(2)=l[1+alpha(T_(2)-T_(1))]` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C11_E01_010_S01.png" width="80%"/> <br/> In above table, special average values are given for some <a href="https://interviewquestions.tuteehub.com/tag/elements-969381" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENTS">ELEMENTS</a> for `0^(@)C` to `100^(@)C` temperature interval. <br/> From this table, if `alpha_(l)` for glass and <a href="https://interviewquestions.tuteehub.com/tag/copper-933790" style="font-weight:bold;" target="_blank" title="Click to know more about COPPER">COPPER</a> are compared, then it is seen that for the same increases in temperature, copper expands 5 times more than glass. <br/> In general, expansion is more in <a href="https://interviewquestions.tuteehub.com/tag/metals-1094891" style="font-weight:bold;" target="_blank" title="Click to know more about METALS">METALS</a> and their values of `alpha_(l)` are high.</body></html> | |
| 39864. |
A monkey of mass 40 kg climbs on a rope (fig) which can stand a maximum tension of 600 N. In which of the following case will the rope break the monkey (a) climbs up with an acceleration of 6 m s^(-2)(b) climbs down with an acceleration of 4 m s^(-2)(c ) climbs up with a uniform speed of 5 m s^(-1) (d) falls down the rope nearly freely under gravity(Ignore the mass of the rope) |
| Answer» <html><body><p></p>Solution :(a) When the monkey climbs up with an acceleration of `6 ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`, the tension in the <a href="https://interviewquestions.tuteehub.com/tag/rope-1191046" style="font-weight:bold;" target="_blank" title="Click to know more about ROPE">ROPE</a> is<br/>`T=m(g+a)=40(9.8+60=632 N`<br/>It is greater than breaking strength (600 N).<br/> So the rope breaks.<br/>(b) When the monkey climbs up withan acceleration of `<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> ms^(-2)`, the tension in the rope is<br/>`T=m(g+a)=40(9.8+4)=552N`<br/>It is smaller than breaking strength (600 N). So the rope does not break.<br/>(c ) When the monkey climbs up with an uniform speed of `5 ms^(-1)`, the tension in the rope is<br/>`T=m(g)=40(9.8)=<a href="https://interviewquestions.tuteehub.com/tag/392-1861291" style="font-weight:bold;" target="_blank" title="Click to know more about 392">392</a> N`<br/>It is smaller than breaking strength (600 N). So the rope does not break.<br/>(d) When the monkey falls down the rope nearly freely under gravity then the tension is almost zero. So the rope does not break.</body></html> | |
| 39865. |
A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (ii) frequency |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a>, `y=0.5cos(1500pit+0.8)=0.5sin((pi)/(2)-1500pit-0.8)=0.5sin[-1500pit-(0.8-(pi)/(2))]` <br/> `y=-0.5sin[1500pit+(0.8-(pi)/(2))]` <br/> Now (ii) frequency `=(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2k-300402" style="font-weight:bold;" target="_blank" title="Click to know more about 2K">2K</a>)=(1500pi)/(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)=750Hz.`</body></html> | |
| 39866. |
A cylindrical piece of cork of density of base area A and height h floats in a liquid of density p_(l). The cork is depressed slightly and then released. Show that the cork oscillates up and down simple harmonically with a period T=2pisqrt((hp)/(p_(1)g)) where p is the density of cork. (Ignore damping due to viscosity of the liquid). |
| Answer» <html><body><p></p>Solution :In equilibrium, weight of the cork equals the up <a href="https://interviewquestions.tuteehub.com/tag/thrust-709467" style="font-weight:bold;" target="_blank" title="Click to know more about THRUST">THRUST</a>. When the cork is depressed by an amount x, the net upward <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> is `Axp_(1)g`. Thus the force constant `k = Ap_(1)g `. Using m = <a href="https://interviewquestions.tuteehub.com/tag/ahp-362384" style="font-weight:bold;" target="_blank" title="Click to know more about AHP">AHP</a>, and `T=2pisqrt(m/k)` one gets the given expression.</body></html> | |
| 39867. |
The magnitude of potential energy per unit mass of the object at the surface of earth is 'E'. The scape velocity of the object is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2e-300683" style="font-weight:bold;" target="_blank" title="Click to know more about 2E">2E</a>)`<br/>`4E^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>)`<br/>`sqrt(E//2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39868. |
Show that Laplace correction for elasticity of gaseous medium is E = gamma p, where 'gamma' is the ratio of specific heates. |
| Answer» <html><body><p></p>Solution :Consider adiabatic variation in the <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> and volume of gasesousmedium. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/pv-593601" style="font-weight:bold;" target="_blank" title="Click to know more about PV">PV</a>^(gamma) =0 ` <br/> i.e., `gamma PV^(gamma-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) Dleta V + V^(gamma) Delta P = 0` <br/> i.e., Bulk modulus-`( Delta P )/((DeltaV)/( V)) = gamma P` <br/> Hence in the expression`v = sqrt((E )/(rho ))`, Elasticity 'E' is replaced by `gamma P`. <br/> <a href="https://interviewquestions.tuteehub.com/tag/laplace-539362" style="font-weight:bold;" target="_blank" title="Click to know more about LAPLACE">LAPLACE</a> equation is written as `v =sqrt((gamma P )/( rho ))` <br/> Where `gamma = 1+ 2 //f` and'f' is number of degrees of freedom of gaseous molecule.</body></html> | |
| 39869. |
The temperature of equal masses of three different liquids A, B and C are 12^@C, 19^@C, and 28^@Crespectively. The temperature when A and B are mixed is 16^@Cand when B and C are mixed it is 23^@CWhat should be the temperature when A and C are mixed? |
| Answer» <html><body><p>`20.26^@<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`15.87^@C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>^@C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^@C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39870. |
If for hydrogen C_p - C_v = m and for nitrogen C_p - C_v = n, Where C_p and C_vrefer to specific heatsper unit mass respectively at constant pressure and constant volume, the relation between m and n is (molecular weight of hydrogen = 2 and molecular weight or nitrogen = 14) |
| Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> = <a href="https://interviewquestions.tuteehub.com/tag/14m-273942" style="font-weight:bold;" target="_blank" title="Click to know more about 14M">14M</a> <br/>n =<a href="https://interviewquestions.tuteehub.com/tag/7m-336154" style="font-weight:bold;" target="_blank" title="Click to know more about 7M">7M</a><br/> m = <a href="https://interviewquestions.tuteehub.com/tag/7n-336171" style="font-weight:bold;" target="_blank" title="Click to know more about 7N">7N</a> <br/>m = 14n</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39871. |
How does the gravity change inside the mines ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a></body></html> | |
| 39872. |
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to |
| Answer» <html><body><p>`t^(1/2)`<br/>`t`<br/>`t^(3/2)`<br/>`t^2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39873. |
Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity? |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_059_O01.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_059_O02.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_059_O03.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_059_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39874. |
The magnitude and direction of the accelerationof a body are constant. Will the path of the body necessarily be a straight line ? |
| Answer» <html><body><p></p>Solution :If the magnitude as wall as <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> of the acceleration of a body is constant, then it is not necessary the the path of the body is a straight line.<br/>Eg: In projectile motion, the projectile is under acceleration <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to gravity which has constant magnitude `(9.8 m//s^(2))`and constant direction (vertically <a href="https://interviewquestions.tuteehub.com/tag/downward-2061463" style="font-weight:bold;" target="_blank" title="Click to know more about DOWNWARD">DOWNWARD</a>) . The path of projectile is <a href="https://interviewquestions.tuteehub.com/tag/parabolic-2912016" style="font-weight:bold;" target="_blank" title="Click to know more about PARABOLIC">PARABOLIC</a> and not a straight line.</body></html> | |
| 39875. |
Define rotational motion. Give example. |
| Answer» <html><body><p></p>Solution :Ifevery point in the object transverses a circular path about an axis, during a <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> then the motion is called <a href="https://interviewquestions.tuteehub.com/tag/rotation-11281" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATION">ROTATION</a> (except the points located on the axis) Eg: Rotation of a disc about an axis through its <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a>.</body></html> | |
| 39876. |
One end of V-tube containing mercury is connected to a suction pump and the other end to atmosphere. The two arms of the tube are inclined to horizental at an angle of 45^(@) each. A small pressure difference is created between two columns when the suction pump is removed. Will the column of mercury in V-tube execute simple harmonic motion? Neglect capillary and viscous forces. Find the time period of oscillation. |
| Answer» <html><body><p></p>Solution :Figure shown as below <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C14_E04_040_S01.png" width="80%"/> <br/> Let <a href="https://interviewquestions.tuteehub.com/tag/small-1212368" style="font-weight:bold;" target="_blank" title="Click to know more about SMALL">SMALL</a> liquid column of length dx is in the left of tube at x height from horizontal <br/> Potential energy due to dx element, <br/> `d(PE)= dmgx""[PE=" from mgh "]` <br/> `=p V gx ""[therefore m= pV" and "V= A dx]` <br/> `=p A dx gx` <br/> `= pA g x dx` <br/> <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> potential energy of liquid in left column <br/> `P.E= int_(0)^(h_1) Ap gx"" dx` <br/> `=A pg int_(0)^(h_1) x dx` <br/> `=A pg[(x^2)/(2)]_(0)^(h_1)= (A pg h_(1)^(2))/(2)` <br/> From figure `h_(1)= l sin 45^(@)= (l)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2))` <br/> `therefore P.E = (A p gl^(2))/(4)` <br/> Total potential energy of liquid in V-tube <br/> `P.E= (A pg l^(2))/(4)+ (Apg l^(2))/(4)` <br/> Initial `P.E. = (A pg l^(2))/(4)"""......."(1)` <br/> When the <a href="https://interviewquestions.tuteehub.com/tag/suction-1233369" style="font-weight:bold;" target="_blank" title="Click to know more about SUCTION">SUCTION</a> pump is removed and due to pressure difference, let element moves towards right side by y unit. <br/> Then the liquid column in left arm `=(l-y)` <br/> And the liquid in right arm `=l+y` <br/> Total potential energy `=Ap g(l-y)^(2) sin^(2) 45^(@)+ Ap g (l+y)^(2) sin^(2)45^(@)` <br/> Final `P.E. = (A pg (l-y)^(2))/(2)+ (Ap g(l+y)^(2))/(2)"""......"(2)` <br/> Potential energy difference <br/> `triangle PE =` final P.E. - initial P.E. <br/> `=(A pg)/(2)[(l-y)^(2)+(l+y)^(2)-l^(2)]""` [From equation (1) and (2) ] <br/> `=(Apg )/(2) [2l^(2)+2y^(2)-l^(2)]` <br/> `=(A pg )/(2) [l^(2)+2y^(2)]"""........"(3)` <br/> If change in velocity v of total liquid column <br/> `triangle KE= (1)/(2)mv^(2)""[" where "m= pV= pA xx 2l]` <br/> `triangle KE = Ap lv^(2)"""......."(4)` <br/> From law of conservation of energy, <br/> `triangle PE + triangle KE= 0` <br/> `A pg (l^(2)+2y^(2))+ <a href="https://interviewquestions.tuteehub.com/tag/apl-363630" style="font-weight:bold;" target="_blank" title="Click to know more about APL">APL</a> v^(2) = 0"""........."(5)` <br/> Difference w.r.t time .t. <br/> `Apg [(d)/(dt)(l^(2)+2y^(2))]+ Apl (d)/(dt)(v^2)=0` <br/> `Apg (0+2y(dy)/(dt))+Apl (2v(dv)/(dt))=0` <br/> `2A pg y v + Apl (2v)a=0` <br/> Dividing by `2Apv`, <br/> `gy+la=0""[therefore 2Apv ne 0]` <br/> `therefore a= -(g)/(l)y`, comparing with this to <br/> `(d^(2)y)/(dt^(2))= -omega^(2)y` <br/> `therefore omega = sqrt((g)/(l))` <br/> `therefore (2pi)/(T)= sqrt((g)/(l))` <br/> `therefore T= 2pi sqrt((l)/(g))` is time period.</body></html> | |
| 39877. |
A spring balance has a scale which ranges from 0 to 25 kg and the length of the scale is 0.25 m. It is taken to an unknown planet X where the acceleration due to gravity is 11.5ms^(-1). Suppose a body a mass M kg is suspended in this spring and made to oscillate with a period of 0.50 s. Compute the gravitational force acting on the body. |
| Answer» <html><body><p></p>Solution :Let us first calculate the stiffness constant of the spring balance by <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> equation `(m)/(k)=(l)/(g)` <br/> `k=(mg)/(l)=(25xx11.5)/(0.25)=1150Nm^(-1)` <br/> The time period of oscillations is given by `T=2pisqrt((M)/(k))`, where M is the mass of the <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a>. <br/> Since, M is unknown, rearranging, we get <br/> `M=(<a href="https://interviewquestions.tuteehub.com/tag/kt-1063108" style="font-weight:bold;" target="_blank" title="Click to know more about KT">KT</a>^(2))/(4pi^(2))=((1150)(0.5)^(2))/(4pi^(2))=7.3kg` `M=(kT^(2))/(4pi^(2))=((1150)(0.5)^(2))/(4pi^(2))=7.3kg` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/gravitational-476409" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITATIONAL">GRAVITATIONAL</a> force <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on the body is <br/> `W=Mg=7.3xx11.5=83.95N~~84N`</body></html> | |
| 39878. |
One mole of an ideal gas undergoes a process such thatP prop 1/sqrtT . The molar heat capacity of thisprocess is 4R, where R is universal gas constant. Then, |
| Answer» <html><body><p>the work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> by the gas is 1.<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> `RDelta T`where `DeltaT`is the <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in temperature <br/><a href="https://interviewquestions.tuteehub.com/tag/degree-47" style="font-weight:bold;" target="_blank" title="Click to know more about DEGREE">DEGREE</a> of freedom of the gas is 5 <br/>on <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> of temperature, volume increases <br/>on increases of temperature, volume decreases </p>Answer :A::B::C</body></html> | |
| 39879. |
A wedge of mass M rests with one face in contact with horizontal , smooth surface . A particle of mass m is placed on the smooth face on it , inclined at an angle alphato the horizontal and released . Find the velocity of the wedge and that of the particle relative to the wedge when the particle has slipped a distance x down the face of the wedge . Also calculate the acceleration of the wedge and that of the particle relative to the wedge and the smooth surface . [Hint : Apply principal of conservation of momentum along the horizontal and energy conservation principle . See Example 8 ) |
| Answer» <html><body><p><br/></p>Answer :`sqrt((<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> m^(2)<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> x "<a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a>"alpha <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a>^(2) alpha)/((M + m) (M + m sin^(2)alpha))) ,sqrt((2(M+ m) g x "sin"alpha)/(M + m sin^(2) alpha)) ((M + m) g "sin"alpha)/(M + m sin^(2)alpha) , (mg"sin" alpha "cos"alpha)/(M + m sin^(2) alpha)`</body></html> | |
| 39880. |
A partilcle moves according to the law x = a cos""(pi t)/(2). The distance covered by it in the time interval between t = 0 to t =3 sec is |
| Answer» <html><body><p>2a<br/>3a<br/>4a<br/>a</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39881. |
A 2 kg ball moving at 24 ms undergoes inelastic head on collision with a 4 kg ball moving in the opposite direction at 48 ms. If the coefficient of restitution is 2/3, their velocities in ms-after impact are |
| Answer» <html><body><p>`-56, -8`<br/>`-28, -<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>`<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>, -<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`-7,-1`</p>Answer :A</body></html> | |
| 39882. |
The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@)C. (i) At constant volume. Find out the amount of heat supplied and the rise in internalenergy in case. Given , R = 2 cal cdot mol^(-1) cdot K^(-1) , for oxygen, c_(v) = 0.155 cal cdot g^(-1) cdot^(@)C^(-1). |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> supplied at constant <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a>, <br/> `Q_(v) = mc_(v) (t_(f) - t_(i))` <br/> `=20 xx 0.155 xx (100-50) = 155 cal` <br/> Work done, W = 0 <br/> So, rise in internal <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> , <br/>`U_(f) - U_(i) = <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> - W = 155 - 0 = 155 cal` <br/> `= 155 xx 4.2 J = 651 J`.</body></html> | |
| 39883. |
The time period of a mass loaded spring is .T.. If 20% of its turns are cut and removed, the same massis attached to the remaining spring would oscillate with a time period of |
| Answer» <html><body><p>`(5T)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)T)/(2)`<br/>`(4T)/(5)`<br/>`(2T)/(sqrt(5))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39884. |
A truck starts from rest and accelerates uniformly at 2.0 m s^(-2).At t = 10 s, a stone is dropped by a person standing on the top of the truck (6 m high from the ground). What are the (a) velocity, and (b) acceleration of the stone at t = 11s ?(Neglect air resistance.) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a)Velocity of car ( at t = 10 s ) =` <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> + 2 x× 10 = 20 m s^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/>By the First Law, the <a href="https://interviewquestions.tuteehub.com/tag/horizontal-1029056" style="font-weight:bold;" target="_blank" title="Click to know more about HORIZONTAL">HORIZONTAL</a> component of velocity is` 20 m s^(-1)`throughout. Vertical component of velocity (at t = 11s) ` = 0 + 10 xx 1 = 10 ms^(-1)`<br/>Velocity of stone (at t = 11s) ` = sqrt( 20^2 + 10^2) = sqrt 500 = 22.4 ms^(-1)` at an angle of `tan^(-1) (1//2)` with the horizontal. (b) `10 ms^(-2)` vertically <a href="https://interviewquestions.tuteehub.com/tag/downwards-959173" style="font-weight:bold;" target="_blank" title="Click to know more about DOWNWARDS">DOWNWARDS</a> .</body></html> | |
| 39885. |
If R is the Rydberg constant, C is the velocity and h is the Planck's constant, then RCh has the dimensions of |
| Answer» <html><body><p>power<br/>Angular frequency<br/>Wavelength<br/>Energy</p>Answer :D</body></html> | |
| 39886. |
For a prism of refractive index 1.732 the angle of minimum deviation is equal to the angle of the prism. The angle of prism is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^@`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^@`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^@`<br/>`80^@`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39887. |
Suppose universal gravitational constant starts to decrease, then (a)length of the year will decrease (b) earth will folllow a spiral path of decreasing order (c) kinetic energy of earth will decrease |
| Answer» <html><body><p>only a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> <br/>only a and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true<br/>only b and c are true <br/>all are true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39888. |
A clock regulated by a seconds pendulum keeps correct time. During summer the length of the pendulum increases to 1.01 m. How much will the clock gain or loose in one day ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :752.9 s <a href="https://interviewquestions.tuteehub.com/tag/loses-1079374" style="font-weight:bold;" target="_blank" title="Click to know more about LOSES">LOSES</a> <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a></body></html> | |
| 39889. |
In CGS system the magnitude of the force is 100 dyne.In another system where the fundamental physical quantities are kilogram, metre and minutc, the magnitude of the force is |
| Answer» <html><body><p>`0.036`<br/>`0.<a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a>`<br/>`3.6`<br/>`36`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39890. |
Three identical masses are kept at the corners of an equilateral triangle ABC. A moves towards B with a velocity V,B moves towards C with velocity V and C moves towards A with same velocity V. Then the velocity of centre of mass of the system of particles is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a><br/>zero<br/>3V<br/>`(V)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39891. |
Starting from rest a wooden block moves with a velocity of 25 ms^(-1) along a rough ground and comes to rest. Calculate the distance travelled by the wooden block on the rough surface of coefficient of friction 0.25. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/50m-324207" style="font-weight:bold;" target="_blank" title="Click to know more about 50M">50M</a> <br/>75m<br/>100m<br/>125m</p>Answer :D</body></html> | |
| 39892. |
Calculate the power of an engine which can pull a mass of 500 metric ton up an incline rising 1 in 100 with a velocity of 10 m/s. |
| Answer» <html><body><p></p>Solution :`sin theta = (1)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)`, Velocity = 10 m/s , Mass m = 500 metric ton `= 500 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` kg <br/> F = Force applied , `= 500 xx 10^(3) xx 9.8 xx (1)/(100) = <a href="https://interviewquestions.tuteehub.com/tag/49-318440" style="font-weight:bold;" target="_blank" title="Click to know more about 49">49</a> xx 10^(3)` N <br/> Power `P = F upsilon = 49 xx 10^(3) xx 10 = 49 xx 10^(4)` watts = 490 kw.</body></html> | |
| 39893. |
A body subjected to strain a number of times does not obey Hooke.s law due to |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/yield-1465134" style="font-weight:bold;" target="_blank" title="Click to know more about YIELD">YIELD</a> point<br/>Breaking stress<br/>Elastic fatigue<br/>Permanent set</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a></body></html> | |
| 39894. |
Two particles having mass M and m are moving in a circular path having radius R and r. If their time period are same then the ratio of angular velocity will be |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)/(R)`<br/>`(R)/(r)`<br/><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((R)/(r))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39895. |
A uniform slender rod of length L, cross -sectional area A and young's modulus Y is acted upon the forces shown in figure. The elongation of the rod is |
| Answer» <html><body><p>`(3FL)/(5AY)` <br/>`(2FL)/(5AY)` <br/>`(3FL)/(<a href="https://interviewquestions.tuteehub.com/tag/8ay-1930459" style="font-weight:bold;" target="_blank" title="Click to know more about 8AY">8AY</a>)` <br/>`(8FL)/(3AY)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39896. |
Draw graphs a to t, v to t and x to tfor the object falling freely. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E01_027_S01.png" width="80%"/> <br/> For object <a href="https://interviewquestions.tuteehub.com/tag/falling-983241" style="font-weight:bold;" target="_blank" title="Click to know more about FALLING">FALLING</a> freely, <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> is constant and equation to negative g. Thus, graph (a) shows the change in acceleration with respect to time `(a to t ).` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E01_027_S02.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/velcity-3258504" style="font-weight:bold;" target="_blank" title="Click to know more about VELCITY">VELCITY</a> of object falling freely, `v =- g t.` THus, graph (b) is obtained for `v to t.` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KPK_AIO_PHY_XI_P1_C03_E01_027_S03.png" width="80%"/><br/> For object falling freely, `h = 1/2 g t ^(2).` Thus graph (c) is obtained for `x to t.`</body></html> | |
| 39897. |
In increasing the area of a film of soap solution from 50 "cm"^(2)" ""to"" "100"cm"^(2) 3xx10^(-4) J of work is done. Calculate the value of surface tension of the soap solution. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/3xx10-1865443" style="font-weight:bold;" target="_blank" title="Click to know more about 3XX10">3XX10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))`</body></html> | |
| 39898. |
A thin liquid convex lens is formed in glass, Refractive index of liquid is 4//3. And that of glass is 3//2. If f. is the focal length of the liquid lens in air, its focal length and nature in the glass is |
| Answer» <html><body><p>`f_1` <a href="https://interviewquestions.tuteehub.com/tag/convex-933348" style="font-weight:bold;" target="_blank" title="Click to know more about CONVEX">CONVEX</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>,` concave<br/>2f,concave<br/>3f,concave</p>Answer :D</body></html> | |
| 39899. |
A man is sitting in a boat which is floating in a pond. If the man drinks some water from the pond, what will happen to the level of water in the pond? |
| Answer» <html><body><p></p>Solution :If the mandrinks m gram of water from thepond, te <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of (boat + <a href="https://interviewquestions.tuteehub.com/tag/man-1085541" style="font-weight:bold;" target="_blank" title="Click to know more about MAN">MAN</a>) system will increase by mg and so the system will displace m gram more water for floating. So due ot removal <a href="https://interviewquestions.tuteehub.com/tag/fo-457881" style="font-weight:bold;" target="_blank" title="Click to know more about FO">FO</a> water from pond, the water level in pond will fall but due to water displaced by the floating system the water level in the pond will rise and so the water <a href="https://interviewquestions.tuteehub.com/tag/removed-2986295" style="font-weight:bold;" target="_blank" title="Click to know more about REMOVED">REMOVED</a> <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> the pond is equal to the water displaced by the system, the level of water in the pond will remain unchanged.</body></html> | |
| 39900. |
A running man has the same kinetic energy as that of a boy of half his mass. The man speeds up by 2 ms^(-1) and the boy changes his speed by x m s^(-1) so that the kinetic energies of the boy and the man are again equal. Then x in m s^(-1) is |
| Answer» <html><body><p>1/2 <br/>`2sqrt(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2)`<br/>`2`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let the <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of man be m. <br/> Therefore, mass of the <a href="https://interviewquestions.tuteehub.com/tag/boy-903339" style="font-weight:bold;" target="_blank" title="Click to know more about BOY">BOY</a> is `m/2` <br/> As. `1/2 mv_1^2 = 1/2(m/2) v_2^2 :. v_1= (v_2)/(sqrt2)` <br/> `1/2 m(v_1 + 2)^2 = 1/2[m/2 (v_2 + <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)^2]` <br/> `:. (v_1 + 2)^2 = ((v_2 + x)^2)/(2) " or " v_1 + 2 = (v_2+ x)/(sqrt2)` <br/> But `v_1 = (v_2)/(sqrt2) :. x/(sqrt2) = 2 " or " x = 2sqrt(2)`.</body></html> | |