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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39951. |
A heavy iron rod of weight 'W' is having its one end on the ground and the other on the shoulder of a man. The rod makes an angle 'theta' with the horizontal. What is the weight experienced by the man ? |
| Answer» <html><body><p>W `sintheta`<br/>W`costheta`<br/>W<br/>`(W)/(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> acts at the <a href="https://interviewquestions.tuteehub.com/tag/middle-1096062" style="font-weight:bold;" target="_blank" title="Click to know more about MIDDLE">MIDDLE</a> of the bar.So the weight <a href="https://interviewquestions.tuteehub.com/tag/experienced-13456" style="font-weight:bold;" target="_blank" title="Click to know more about EXPERIENCED">EXPERIENCED</a> by the man is `W/2`</body></html> | |
| 39952. |
The acceleration due to gravity at the poles is 10ms^(-2) and equitorial radius is 6400km for the earth. Then the angular velocity of rotation of the earth about its axis so that the weight of a body at the equator reduces to 75% is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/1600 "<a href="https://interviewquestions.tuteehub.com/tag/rads-3786464" style="font-weight:bold;" target="_blank" title="Click to know more about RADS">RADS</a>"^(-1)`<br/>`1/800"rads"^(-1)`<br/>`1/400"rads"^(-1)`<br/>`1/200"rads"^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39953. |
The situations are shown in fig(a) & (b), in each case, m_(1)=3kg and m_(2)=4kg. If a_(1), a_(2) are the respective accelerations of the blocks in these situations, then the values of a_(1) and a_(2) are respectively [g=10 ms^(-2)] |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)/(7)<a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-2), (25)/(7)ms^(-2)` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>)/(7)ms^(-2), (5)/(7)ms^(-2)` <br/>`(40)/(7)ms^(-2), (10)/(7)ms^(-2)` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>)/(7)ms^(-2),(10)/(7)ms^(-2)` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39954. |
If a cylinder of diameter 1.0cm at 30°c is to be slide into a hole of diameter 0.9997 cm in a steel plate at the same temperature, then minimum required rise in the temperature of the plate is [coefficient of linear expansion of steel = 12 xx 10^(-6) //^(@) C ] |
| Answer» <html><body><p>`25^(@) C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a>^(@) C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@) C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/55-325247" style="font-weight:bold;" target="_blank" title="Click to know more about 55">55</a>^(@) C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39955. |
What will be the difference in temperatures between two sides of a metallic plate 10 mm thick if heat is conducted at the rate of 5 xx 10^5cal/min/m^2 . K for metal is 0.7 cal s^(-1)cm^(-1) ""^@C^(-1) . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Delta x = 10 <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a> = 1 cm` <br/> `K = 0.7 <a href="https://interviewquestions.tuteehub.com/tag/cal-412083" style="font-weight:bold;" target="_blank" title="Click to know more about CAL">CAL</a> s^(-1) cm^(-1) K^(-1)` <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = 5 xx 10^5 cal , A = 1m^2 = 10^4cm^2`<br/> t = 1 min = 60 s <br/> ` Q = (KA(T_1 - T_2)t)/(Delta x)` <br/> ` rArr T_1 - T_2 = (Q Delta x)/(KA t) = (5 xx 10^5 xx 1)/(0.7 xx 10^4 xx 60)` <br/> ` T_1 - T_2 = 1.19^@C`</body></html> | |
| 39956. |
Consider the motion of the tip of the minute hand of a clock . In one hour (i) the displacement is zero (ii) the distance covered is zero (iii) the average speed is zero (iv) the average velocity is zero |
| Answer» <html><body><p>(i), (ii) are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a><br/>(i), (ii) ,(<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) are correct<br/>(i),(iii) are correct<br/>(i),(<a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a>) are correct</p>Solution :Displacement =` x_f - x_i =0` <br/>velocity `=("displacement")/("time") = 0`</body></html> | |
| 39957. |
A uniform cylinder of height h and radius r is placed with its circular face on a rough inclined plane and the inclination of the plane to the horizontal gradually in creased. If mu is the coefficeint of friction, then under what conditions the cylinder will a) slide before topping b) topple before sliding |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_C07_SLV_091_S01.png" width="80%"/> <br/> (a) The Cylinder will slide if <br/> `Mgsintheta gt mu Mgcosthetaimpliestantheta gt mu`……….`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> The cylinder will <a href="https://interviewquestions.tuteehub.com/tag/topple-3224023" style="font-weight:bold;" target="_blank" title="Click to know more about TOPPLE">TOPPLE</a> if <br/> `(Mgsintheta)(h)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) gt (Mg costheta)rimpliestantheta gt (2r)/(h)`…………`(2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, the condition of sliding is `tantheta gt mu` and condition of toppling `tantheta gt (2r)/(h)`. Hence, the cylinder will slide before toppling if `mu <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> (2r)/(h)` <br/> (b) The cylinder will topple before sliding if `my gt (2r)/(h)`</body></html> | |
| 39958. |
Three equal masses .m. are placed at the three vertices of an equilateral triangle of side a. Find the gravitational force exerted by this system on another particle of mass ‘m. placed a) at the mid point of a side and (b) at the centroid of the triangle. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`a) 4Gm^2 // 3a^2 , <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>`</body></html> | |
| 39959. |
A piece of brass (Cu and Zn) weighs 12.9 g in air. When completely immersed in water, it weights 11.3 g. The relative densities of Cu and Zn are 8.9 and 7.1 respectivey. Calculate the mass of copper in the alloy |
| Answer» <html><body><p>6.6 gm<br/>7.6 gm<br/>8.6 gm<br/>5.6 gm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39960. |
When a solid sphere is undergoing pure rolling, the ratio of translational kinetic energy to rotational kinetic energy is |
| Answer» <html><body><p>`2:5`<br/>`5:2`<br/>`1:5`<br/>`5:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39961. |
Give the vector form of the relation between v and omega. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The vector <a href="https://interviewquestions.tuteehub.com/tag/relation-1183220" style="font-weight:bold;" target="_blank" title="Click to know more about RELATION">RELATION</a> between linear velocity and <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> velocity `omega` is `barv=vecrxxbaromega`</body></html> | |
| 39962. |
The resultant of two forces, one double the other in magnitude is perpendicular to the smaller of the two forces. The angle between the two forces is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/150-275254" style="font-weight:bold;" target="_blank" title="Click to know more about 150">150</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a>^(@)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39963. |
Two satellites S_(1) and S_(2) are revolving around a planet P in circular orbits of radii 4R and 9R respectively. If the speed of satellite S_(1) is 2V, then calculate the speed of satellite S_(2). |
| Answer» <html><body><p></p>Solution :As we know orbital speed `V_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>) = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((GM)/(R ))` <br/> For `S_(1), ""<a href="https://interviewquestions.tuteehub.com/tag/2v-300496" style="font-weight:bold;" target="_blank" title="Click to know more about 2V">2V</a> = sqrt((GM)/(4R))` …(i) <br/> For `S_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>), ""V. = sqrt((GM)/(<a href="https://interviewquestions.tuteehub.com/tag/9r-1937718" style="font-weight:bold;" target="_blank" title="Click to know more about 9R">9R</a>))` …(ii) <br/> Dividing (i) by (ii) we get <br/> `(V.)/(2V) = sqrt((GM)/(9R)).sqrt((4R)/(GM))` <br/> `v. = 2V.2//3 = 4V//3`</body></html> | |
| 39964. |
A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find frequency |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/comparing-2531631" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARING">COMPARING</a> <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> `y= 0.02sin(3.14t+ (pi)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`with the general from of the equation , `y= A sin(omegat+phi_(0))` <br/> Frequency `v= (1)/(T)= (1)/(2)Hz= 0.5 Hz`</body></html> | |
| 39965. |
In the previous problem, If 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mercury-558950" style="font-weight:bold;" target="_blank" title="Click to know more about MERCURY">MERCURY</a> will <a href="https://interviewquestions.tuteehub.com/tag/rise-1189674" style="font-weight:bold;" target="_blank" title="Click to know more about RISE">RISE</a> in the arm containing spirit, the difference in <a href="https://interviewquestions.tuteehub.com/tag/levels-1072811" style="font-weight:bold;" target="_blank" title="Click to know more about LEVELS">LEVELS</a> of mercury will be 0.221 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>.</body></html> | |
| 39966. |
An object of mass 0.20kg executes simple harmonic oscillations along X-axis with a frequency of (25//pi) Hz. At the position x=0,04 the object has kinetic energy of 0.5J and potential energy 0.4J. The amplitude of oscillations is: |
| Answer» <html><body><p>0.06 m <br/>0.08 m <br/>0.10 m<br/>0.12 m </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39967. |
(A) : For a satellite revolving very near to earth's surface the time period of revolution is given by 1 hour 24 minutes. (R) : The period of revolution of satellite depends upon its height above the earth's surface. |
| Answer» <html><body><p>Both (A) and (R) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39968. |
A mass of 2kg is suspendedfrom a fixed point by a wire of length 3m and diameter 0.5 mm. Initially the wire is just unstretched, the mass resting on a fixed support. By hoH' much must the temperature fall if the mass is to be entirely supported by the wire? Given that Y of the wire = 206 G Pa, alpha = 11 xx 10^(-6)//^(0) C . |
| Answer» <html><body><p></p>Solution :When the temperature <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> the wire contracts in length and <a href="https://interviewquestions.tuteehub.com/tag/lifts-1073381" style="font-weight:bold;" target="_blank" title="Click to know more about LIFTS">LIFTS</a> the mass up. But the weight begins to produce a stress and counteracts the contraction <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a>. Hence the contraction due to cooling is equal to the stretching produced by the weight W.<br/> `therefore <a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> L = (WL)/(AY) = (2 xx 9.8 xx 3)/(pi (0.25)^(2) xx 10^(-6) xx 206 xx 10^(9))` <br/> Now the contraction due to cooling <br/>` = L alpha d theta = 3 xx 11 xx 10^(-6) xx d theta` <br/> Since the contraction due to cooling = extension produced by the weight. On solving `d theta = 44^(@)`C</body></html> | |
| 39969. |
Let I_(A) and I_(B) be moments of inertia of a body about two axes A and B respectively. The axis A passes through the centre of mass of the body but B does not. |
| Answer» <html><body><p>`I_(A)<a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> I_(B)`<br/>If `I_(A)lt I_(B)` the <a href="https://interviewquestions.tuteehub.com/tag/axes-386573" style="font-weight:bold;" target="_blank" title="Click to know more about AXES">AXES</a> are <a href="https://interviewquestions.tuteehub.com/tag/parallel-1146369" style="font-weight:bold;" target="_blank" title="Click to know more about PARALLEL">PARALLEL</a> <br/>If the axes are parallel, `I_(A)lt I_(B)` <br/>If the axes are not parallel `I_(A)gt I_(B)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 39970. |
can a physical quantity having both magnitude and direction be a vector? |
| Answer» <html><body><p></p>Solution :No, it is not necessary that a physical quantity having both <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> and direction is a vector . For example, <a href="https://interviewquestions.tuteehub.com/tag/current-940804" style="font-weight:bold;" target="_blank" title="Click to know more about CURRENT">CURRENT</a> <a href="https://interviewquestions.tuteehub.com/tag/flowing-993418" style="font-weight:bold;" target="_blank" title="Click to know more about FLOWING">FLOWING</a> in a conductor is having both magnitudeand direction but is a scalar quantity because the laws of vector <a href="https://interviewquestions.tuteehub.com/tag/addition-367641" style="font-weight:bold;" target="_blank" title="Click to know more about ADDITION">ADDITION</a> but is a scalar quantity because the laws of vecrtor addition are not applicable to <a href="https://interviewquestions.tuteehub.com/tag/electric-967871" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRIC">ELECTRIC</a> current .</body></html> | |
| 39971. |
Consider a compound slab consisting of two different materials having equal thicknesses and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is. . . . . .. . |
| Answer» <html><body><p>`sqrt(2K)`<br/><a href="https://interviewquestions.tuteehub.com/tag/3k-310983" style="font-weight:bold;" target="_blank" title="Click to know more about 3K">3K</a><br/>`4/3K`<br/>`2/3K`</p>Solution :For <a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> see <a href="https://interviewquestions.tuteehub.com/tag/section-25668" style="font-weight:bold;" target="_blank" title="Click to know more about SECTION">SECTION</a> - E <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>. no. 5</body></html> | |
| 39972. |
When temperature of a body made of brass increases its moment of inertia. |
| Answer» <html><body><p>increases<br/>decreases<br/>remains same<br/>becomes zero</p>Answer :A</body></html> | |
| 39973. |
Two wires of same material have masses in the ratio 3:4 the ratio of their extensions under the same load if their lengths are in the ratio 9:10 is |
| Answer» <html><body><p>`5:3`<br/>`27:40` <br/>`6:5` <br/>`27:25`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></body></html> | |
| 39974. |
The earth revolves round the sun in an elliptical orbit, its speed is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/going-1008806" style="font-weight:bold;" target="_blank" title="Click to know more about GOING">GOING</a> on <a href="https://interviewquestions.tuteehub.com/tag/decreasing-946148" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASING">DECREASING</a> continuousely<br/>greatest when is <a href="https://interviewquestions.tuteehub.com/tag/closest-2016788" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSEST">CLOSEST</a> to the sun<br/>Greatest when it is farthest from the sun<br/>constant at all the <a href="https://interviewquestions.tuteehub.com/tag/points-1157347" style="font-weight:bold;" target="_blank" title="Click to know more about POINTS">POINTS</a> on the orbit</p>Answer :B</body></html> | |
| 39975. |
State newton three laws and discus theirsignificance |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Newton'sfirstlaw : Everyobjectcontinuestobe in the stateof restor ofuniformmotionunless thereis externalforceactingon it. <br/> Newton'ssecondlaw : Theforceactingon an object is equalto the rateof changeof itsmomenturm. <br/> `vec(F ) = (vec(dp))/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a> )` <br/> newton'sthirdlaw :Newton'sthirdlasw statesthat foreveryactionthere isan equaland oppositereaction .<br/> Singificanceof Newton'slaswof <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a><br/> (i)Newton'slawsare vectorlaws: <br/> (ii)Theaccelerationexperieneed bythe bodyat time1 dependson theforcewhichactson thebodyat thatinstant oftime <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>)In generalthe <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> of a forcemaybe differentfrom the directionof motion<br/> (iv) The totalforce `(vec(F )_(max))` is equivalentto thevectorialsum of the individualforces . <br/> (v)If noforceactson thebodythenNewton'ssecond`m(d vec(v ))/(dt )=0` <br/> (vi) Newton'ssecondlaw has causeadn effectrelation.Force is tehcauseadn accelerationis teheffect.</body></html> | |
| 39976. |
If f=x^(2) then what will be relative error in measurement of f ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/deltaf-2053516" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAF">DELTAF</a>)/(f)=<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(<a href="https://interviewquestions.tuteehub.com/tag/deltax-2570672" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAX">DELTAX</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)`</body></html> | |
| 39977. |
A ball of mass 0.4 kg moving with a uniform speed of 2ms^(-1) strikes normally a wall and rebounds. Assuming the collision to be elastic and the time of contact of the ball with the wall as 0.4s, find the force exerted on the ball. |
| Answer» <html><body><p>1N<br/>2N<br/>3N<br/>4N</p>Answer :D</body></html> | |
| 39978. |
A body on the surface of the earth at latitude 60° will be under weight lessness state if the angular velocity of rotation of the earth becomes |
| Answer» <html><body><p>`sqrt((GM)/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(3))`<br/>`sqrt((<a href="https://interviewquestions.tuteehub.com/tag/2gm-300695" style="font-weight:bold;" target="_blank" title="Click to know more about 2GM">2GM</a>)/R^(3))`<br/>`sqrt((GM)/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>^(3))`<br/>`sqrt((4GM)/R^(3))` </p>Answer :D</body></html> | |
| 39979. |
What change of surface energy will be noticed when a drop of radius R splits into 1000 droplets radius r, surface tension being T |
| Answer» <html><body><p>`4piR^2T`<br/>`7piR^2T`<br/>`16piR^2T`<br/>36piR^2T`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39980. |
Find the time at which ratio of kinetic energy to potential energy of a particle is 3. The particle starts SHM from its equilibrium position. T is the time period of oscillation: |
| Answer» <html><body><p>`T//6`<br/>`T//12`<br/>`T//8`<br/>`T//24`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39981. |
A uniform cube is subjected to volume compression. If each side is decreased by 1%, then bulk strain is: |
| Answer» <html><body><p>0.01<br/>0.02<br/>0.06<br/>0.03</p>Solution :If side of the cube is L then,<br/>`V=L^(3)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>""(dV)/(V)=3(dL)/(L)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>%"<a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in volume"=3xx(%"change in length")` <br/>`=3xx1%=3%` <br/>`therefore"Bulk strain"(DeltaV)/(V)=0.03`</body></html> | |
| 39982. |
Vectors which act along the same line whose angle between them can be 0^(@) or 180^(@) are called ___________. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/orthogonal-2900235" style="font-weight:bold;" target="_blank" title="Click to know more about ORTHOGONAL">ORTHOGONAL</a> vectors<br/>Collinear vectors<br/>Unit vectors<br/>Resultant vectors</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39983. |
Galileo , inhis book Two new sciences , stated that for elevations which exceed or fall short of 45^(@) by equal amounts , the ranges are equal . Prove this statement. |
| Answer» <html><body><p></p>Solution :For a projectilelaunched with velocity `v_(@)` at an angle `theta_(@)` , therange is given by<br/>`R=(v_(0)^(2)sin2theta_(0))/(g)`<br/>Now , for angles , `(45^(@)+alpha)and(45^(@)-alpha),2theta_(0)` is`(<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@)+2alpha)and(90^(@)-2alpha)`, respectively . The valuesof `sin(90^(@)+2alpha)andsin(90^(@)-2alpha)` are the same , <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to that of `cos2alpha`. <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> , <a href="https://interviewquestions.tuteehub.com/tag/ranges-1177066" style="font-weight:bold;" target="_blank" title="Click to know more about RANGES">RANGES</a> are equal for elevations which exceed of fall short of `45^(@)` by equal amounts `alpha`.</body></html> | |
| 39984. |
A ball is projected from a cliff of height h = 19.2 m at an angle a to the horizontal. It hits an incline passing through the foot of the cliff, inclined at an angle theta to the horizontal. Time of flight of the ball is T = 2.4 s. Foot of the cliff is the origin of the co-ordinate system, horizontal is x direction and vertical is y direction (see figure). Plot of y co-ordinate vs time and y component of velocity of the ball (v_(y)) vs its x co-ordinate (x) is as shown.x and y are in m and time is in s in the graph. [g = 10 m//s^(2)] (a) Find the angle of projection a (b) Find the inclination (theta) of the incline. (c) If the ball is projected with same speed but at an angle theta (= inclination of incline) to the horizontal, will it hit the incline above or below the point where it struck the incline earlier? |
| Answer» <html><body><p><br/></p>Answer :(a) `<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> = <a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>^(-) ((3)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))` (b) `theta = tan^(-) (1)/(2)` (c) The ball will <a href="https://interviewquestions.tuteehub.com/tag/hit-1028201" style="font-weight:bold;" target="_blank" title="Click to know more about HIT">HIT</a> at a point lower than the earlier <a href="https://interviewquestions.tuteehub.com/tag/spot-1222851" style="font-weight:bold;" target="_blank" title="Click to know more about SPOT">SPOT</a>.</body></html> | |
| 39985. |
A uniform cylinder of diameter 8 cm is kept on a rough inclined plane whose angle of inclination with the ground is 30^(@). What should be the maximum height of the cylinder so that it does not topple? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/cylinder-942617" style="font-weight:bold;" target="_blank" title="Click to know more about CYLINDER">CYLINDER</a> ABCD is kept on the plane of inclination `30^(@)`. Suppose the cylinder is on the verge of toppling over when its <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> is 2 h. At this stage the line of action of gravity <a href="https://interviewquestions.tuteehub.com/tag/must-2185568" style="font-weight:bold;" target="_blank" title="Click to know more about MUST">MUST</a> pass vertically through the end point A at the base of the cylinder.From Fig <br/> tan`30^(@) =(AE)/(EG)` <br/> or, `(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(sqrt(3))=(r)/(h) " ""or", h = sqrt(3)r = 4sqrt(3) `cm <br/> Hence, maximum permissible height = 2h = `2xx4 sqrt(3)` <br/> =`8sqrt(3)` cm. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P1_U05_C01_SLV_027_S01.png" width="80%"/></body></html> | |
| 39986. |
A cylinder containe 20 kg of N_(2) gas (M= 28 kg K^(-1) mol^(-1)) at a [ressire pf 5 atm. The mass of hydrogen (M = 28 kg K^(-1) mol^(-1)) at a pressure of 3 atm contained in the same cylinder at same temperature is |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.08 kg<br/>0.86 kg<br/>0.68 kg<br/>1.68 kg</p>Solution : `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>/T=(nR)/p` <br/> V and T for both <a href="https://interviewquestions.tuteehub.com/tag/cases-910165" style="font-weight:bold;" target="_blank" title="Click to know more about CASES">CASES</a> in same. Hence <br/> `(n_(1))/(p_(1))=(n_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(p_(2))or (m_(1))/(p_(1)M_(1))=(m_(2))/(p_(2)M_(2))` <br/> or `""m_(2)(p_(2)M_(2))/(p_(1)M_(1)).m_(1)=((3)(2))/((5)(28)).20=0.86kg`</body></html> | |
| 39987. |
A mass of 2 kg oscillates on a spring with constant 50 N/m. By what factor does the frequency of oscillation decrease when a damping force with cosntant b=12 is introduced? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(50/2)=5r//s` <br/> `w=sqrt(w^(2)-(b/(2m))^(2))=sqrt(5^(2)-3^(2))=4` <br/> fr <a href="https://interviewquestions.tuteehub.com/tag/reduces-621012" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCES">REDUCES</a> by 1r/s or 20%</body></html> | |
| 39988. |
When a satellite is orbitting round a planet in circular orbit, workdone by the gravitational force acting on the satellite is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> on <a href="https://interviewquestions.tuteehub.com/tag/completing-7374603" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETING">COMPLETING</a> <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> <a href="https://interviewquestions.tuteehub.com/tag/revolution-623158" style="font-weight:bold;" target="_blank" title="Click to know more about REVOLUTION">REVOLUTION</a> only<br/>zero always<br/>infinite<br/>negative</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39989. |
Work done to increase the temperature of one mole of an odeal gas by 30^@C, if it is expanding under the condition V prop T^(2//3) is , ( R = 8.314 J// mol//K) |
| Answer» <html><body><p>16.62 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a> <br/>166.2 J <br/>1662 J <br/>1.662 J</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39990. |
A man is sitting in a boat, which is floating in a pond. If the man drink some water from the pond, will the level of water in the pond decrease ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No. When he drinks water, say w kg, he displaces w kg of water and hence the <a href="https://interviewquestions.tuteehub.com/tag/level-1072714" style="font-weight:bold;" target="_blank" title="Click to know more about LEVEL">LEVEL</a> <a href="https://interviewquestions.tuteehub.com/tag/tends-7717049" style="font-weight:bold;" target="_blank" title="Click to know more about TENDS">TENDS</a> to increase But <a href="https://interviewquestions.tuteehub.com/tag/already-1974237" style="font-weight:bold;" target="_blank" title="Click to know more about ALREADY">ALREADY</a> the w kg has gone inside his <a href="https://interviewquestions.tuteehub.com/tag/stomach-14451" style="font-weight:bold;" target="_blank" title="Click to know more about STOMACH">STOMACH</a>. So the level remains constant</body></html> | |
| 39991. |
When a constant torque is applied on a rigid body, then |
| Answer» <html><body><p>The body moves with <a href="https://interviewquestions.tuteehub.com/tag/lincar-2792082" style="font-weight:bold;" target="_blank" title="Click to know more about LINCAR">LINCAR</a> acceleration<br/>The body rotates with constant <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> velocity<br/>The body rotates with constant angular accelaration<br/>The body undergoes <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> angular displace ment in equal intervals of time</p>Answer :C</body></html> | |
| 39992. |
A particle undergoes uniform circular motion. The angular momentum of the particle remain conserved about: |
| Answer» <html><body><p>the centre point of the circle<br/>the point on the circumference of the circle<br/>any point inside the circle<br/>any point <a href="https://interviewquestions.tuteehub.com/tag/outside-1143075" style="font-weight:bold;" target="_blank" title="Click to know more about OUTSIDE">OUTSIDE</a> the cicle</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/vecl-2320290" style="font-weight:bold;" target="_blank" title="Click to know more about VECL">VECL</a>=vecrxxvecP` <br/> `vecL=vecrxxmvecv` <br/> `vecL=` Constant <br/> when `<a href="https://interviewquestions.tuteehub.com/tag/vecr-3257533" style="font-weight:bold;" target="_blank" title="Click to know more about VECR">VECR</a>` and `<a href="https://interviewquestions.tuteehub.com/tag/vecv-3257988" style="font-weight:bold;" target="_blank" title="Click to know more about VECV">VECV</a>=` Constant</body></html> | |
| 39993. |
Can we predict the direction of motion of a body from the direction of force on it |
| Answer» <html><body><p></p>Solution :Yes. The direction of motion is always opposite to the <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> of <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> friction. By <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> the principle of equilibrium, the direction of force of static friction can be <a href="https://interviewquestions.tuteehub.com/tag/determined-949906" style="font-weight:bold;" target="_blank" title="Click to know more about DETERMINED">DETERMINED</a>. When the object is in equilibrium, the frictional force must point in the direction which <a href="https://interviewquestions.tuteehub.com/tag/results-2643" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTS">RESULTS</a> as a net force is zero.</body></html> | |
| 39994. |
A particle has an initial velocity 3 hati+4hatj and an acceleration of 0.4 hati + 0.3 hatj. Its speed after 10s is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/units-1438468" style="font-weight:bold;" target="_blank" title="Click to know more about UNITS">UNITS</a><br/>`7sqrt2` units<br/>7 units<br/>8.5 units</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39995. |
why are strings of different thicknesses and materials used in a sitar or a violin ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Fundamental frequency of streched string `v= 1/2L sqrt T/m`. when we use string of <a href="https://interviewquestions.tuteehub.com/tag/defferent-2048560" style="font-weight:bold;" target="_blank" title="Click to know more about DEFFERENT">DEFFERENT</a> thiknesses and materials, they have different values of <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> as <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> unit length (m). So the strings will <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a> notes of different frequencies.</body></html> | |
| 39996. |
A particle is projected making an angle of 45^@ with the horizontal having kinetic energy K.The kinetic energy at the highest point will be |
| Answer» <html><body><p>`K/sqrt2`<br/>`K/2`<br/>2K<br/>K</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39997. |
The accuracy n. measurement depends on the limit or the resolution of the measuring instrument. State whether the above statement is TRUE or FALSE. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/ture-1429019" style="font-weight:bold;" target="_blank" title="Click to know more about TURE">TURE</a></body></html> | |
| 39998. |
Why are stationary waves called so ? |
| Answer» <html><body><p></p>Solution :In a <a href="https://interviewquestions.tuteehub.com/tag/stationary-633001" style="font-weight:bold;" target="_blank" title="Click to know more about STATIONARY">STATIONARY</a> wave, the <a href="https://interviewquestions.tuteehub.com/tag/particles-1147533" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLES">PARTICLES</a> of the medium vibrate about their <a href="https://interviewquestions.tuteehub.com/tag/mean-1091459" style="font-weight:bold;" target="_blank" title="Click to know more about MEAN">MEAN</a> <a href="https://interviewquestions.tuteehub.com/tag/positions-1159905" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIONS">POSITIONS</a>, but distrbances do <a href="https://interviewquestions.tuteehub.com/tag/mot-548817" style="font-weight:bold;" target="_blank" title="Click to know more about MOT">MOT</a> treval in any direction.</body></html> | |
| 39999. |
If S_(P) and S_(V) denote the specific heats of nitrogen gas per unit mass at constant pressure and constant volume respectively, then |
| Answer» <html><body><p>`s_p-s_V=28R` <br/>`s_p - s_V = <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>//28`<br/>`s_p-s_v=R//14`<br/>`s_p-s_v=R`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`C_p-C_v = R`<br/> For diatomic gas `N_2` no. of <a href="https://interviewquestions.tuteehub.com/tag/degrees-947393" style="font-weight:bold;" target="_blank" title="Click to know more about DEGREES">DEGREES</a> of <a href="https://interviewquestions.tuteehub.com/tag/freedom-999700" style="font-weight:bold;" target="_blank" title="Click to know more about FREEDOM">FREEDOM</a> = 5 <br/> `S_P - S_V=R/28`</body></html> | |
| 40000. |
A body weighs 64 N on the surface of the Earth. What is the gravitational force on it (in N) due to the Earth at a height equal to one-third of the radius of the Earth? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/linear-1074458" style="font-weight:bold;" target="_blank" title="Click to know more about LINEAR">LINEAR</a> velocity v=72 km/h = `(72 xx 1000)/(60 xx 60) = 20` m/s <br/> Initial angular velocity of the wheel `=omega_(0) = v/r = 20/(0.25) = 80` rad/s <br/> Final angular velocity =`omega =0` <br/> Time =t= <a href="https://interviewquestions.tuteehub.com/tag/16s-277872" style="font-weight:bold;" target="_blank" title="Click to know more about 16S">16S</a> <br/>Angular <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> = `alpha` = ? <br/> `alpha = (omega-omega_(0))/t = (0-80)/16 = -<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> "rad"//s^(2)` <br/> Average torque `=tau = lalpha = 5 xx 5 = 25` Nm</body></html> | |