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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1201. |
What do we call the gravitational force between the earth and an object? |
| Answer» SOLUTION :GRAVITATIONAL force between the earth and an OBJECT is KNOWN as the weight of the object. | |
| 1202. |
Calculate the angle of (a) 1^(@)(degree) (b) 1' (minute of arc or arc minute) |
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Answer» SOLUTION :`360^(@)=2PI and rad, 1^(@)=60',1'=60^(@)` (a) `360^(@)=2pirad` `therefore 1^(@)=(2pi)/(360)rad=1.745xx10^(-2)rad` (B) `1^(@)=60'=1.745xx10^(-2)rad` `therefore a'=(1.745)/(60)xx10^(-2) and rad CONG 2.91xx10^(-4)rad` |
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| 1203. |
A man travels a distance of 1.5 m towards East, then 2.0 m towards South and finally 4.5 m towards north. (i) Calculate the total distance travelled. (ii) Calculate the resultant displacement. |
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Answer» Solution :The man STARTS from A and travels `1.5 m` towards EAST and reaches point B. For B 2m towards SOUTH reaches point C. From `C 4.5 m` towards north and teaches point D. Total distance travelled `= AB + BC +CD` `= (1.5 + 2 + 4.5) m = 8m ` The resultant displacement is AD. In right angled `Delta ABD, AB = 1.5 m.` `BD=DC - BC = (4.5 -2) = 2.5 m.` By Pythogoras. theorem, `AD ^(2) = AB^(2) + BD^(2)` ` = (1.5) ^(2) + (2.5) ^(2) = 2.25 + 6.25 = 8.50` ` THEREFORE AD = sqrt (8.50) ~~2.92 m` (i) Total distance travelled `= 8m.` (II) The resultant displacement `= 2.92 m.` 
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| 1204. |
Why are the ultrasonic sounds preferred to audible and infrasonic sounds in detecting the tumors in a physical body . |
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Answer» Solution :(i) Directionality of ULTRASONICS , application of ultrasonics , IMAGING on internal organ (ii) Is the wavelength of ultrasonics larger or SHORTER when COMPARED with that of audible and infrasonic sounds ? When are the waves reflected sharply at the BOUNDARIES of an obstacle ? Is it possible when their wavelength is shorter or longer ? |
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| 1205. |
What are the factors affecting buoyancy? |
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| 1206. |
In what direction and at what point does the buoyant force on a body due to a liquid, act? |
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| 1207. |
How does a stethoscope help a doctor to hear the sound of a patient's heart-beat ? |
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Answer» Solution :Is the TUBE connecting the diaphragm OFA stethoscope and its ear phones hollow or SOLID ? Does the tube reflect the SOUND at different points in the process of TRANSMITTING it from the diaphragm to the head phones ? |
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| 1208. |
Compare approximately the speed of sound in air and steel. |
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Answer» Solution :The speed of sound in air is nearly 330 `MS^(-1)` and in STEEL is nearly 5100 m `s^(-1)`. Thus, the ratio of speed of sound in air and steel is `("Speed of sound in air")/("Speed of sound in steel")`= (330 ms^(-1))/(5100 ms^(-1)) = 1/(15) ` nearly |
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| 1209. |
What type of sound waves are produced by a vibrating simple pendulum? |
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| 1210. |
Correct the statement if any wrong. An object moving with uniform speed along a circular path undergoes velocity changes due to the change in speed. |
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| 1211. |
A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two rotations. When the flat end of the screw is in contact with the stud, the zero of circular scale lies below the base line and 4th division of circular scale is in line with the base line. Find the zero error, of the screw gauge. |
| Answer» SOLUTION :`+0.04 MM` | |
| 1212. |
The length of a second pendulum is |
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Answer» 0.5 m |
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| 1213. |
A floating boat displaces water weighing 6000 newtons . (i) What is the buoyant force on the boat ? (ii) What is the weight of the boat ? |
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| 1214. |
An object of mass 1 kg travelling in a straight line with a velocity of 10ms^(-1) collides with, and strikes to a stationary wooden block of mass 5 kg . Then they both move off together in the same straight line. Calculate the total momentum just before the impact andjust after the impact. Also calculate the velocity of the combined object . |
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Answer» Solution :Mass of the objcet `m_1 =1kg` Velcity of wooden block before collision `v_1=10m//s` Mass of the stationary wooden black `m_2=5 KG` Velocity of the wooden block before collision `V_2 =O m//s` Total MOMENTUM before collision = `m_1v_1+m_2v_2` `1(10)+5(0)=10 kg MS^(-1)` It is given that after collision the object and the wooden block stick together . Total mass of the combined system `=m_1+m_2` Velocity of the combined object =v. ACCORDING to the law of conservation momentum . Total momentum before collision = Total momentum after collision `m_1v_1+m_2v_2=(m_1+m_2)v` `1(10)+5(0)=(1+5)v` V=10/6 =5/3 The total momentum after collision is also 10 kg m/s Total momentum just before the impact =10 kg m/s Total momentum just after theimpact `=(m_1+m_2)v= 6+5//3= 10 kg ms^(-1)` |
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| 1215. |
Thedistancebetween twoconsecutivethreadson thescrewof ascrewgaugeis 0.5mm. Thenumberofdivisionson thecircular scaleis 100. a wireis placedbetween of thestudsof the screw gauge.Find thediameter ofthe wireif thepitchscaleshows 14th division and 40th circulardivision coincideswiththe baseline. Thegivenapparatus wasdetected to havenegative zeroerror. The 90th division on the circular scale of coincides withreferenceline, whenthe studsare incontact. |
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Answer» SOLUTION :1 MSD=1 mm `" Pitc " = (5 MSD)/(5) =1 MSD =1MM` Leastcount `= (P)/(N)` `N=(1 mm)/(1 MU m) =100` N=500 , P =(N) `xx` (L.C.) =500 `xx 1 mu m = 0.5` mm PITCH =0.5 mm |
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| 1217. |
A watertank has a capacity of 1000 litres. It is in the shape of a cylinder. The length of the cylinder is 1 metre. An electric motor pump set is used to fill the water in the tank. This pumpset lifts 120 litres of water per minute. What is the velocity in the shift of centre of gravity of the water tank? |
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Answer» Solution :The values of the cylinder having 1000 litres CAPACITY is 1 `m^(3)`. Find the area of the cross SECTION and the height of the cylinder. If 120 litres of water is pumped into the cylinder for every one minute, then the level of water RISES up by the rate of `(120)/(1000)`m. Will the C.G. of the water tank rise by `(120)/(1000)` m in one minute? Now, find the change in C.G. of the water tank in one second by dividing (2) by 60 SECONDS. |
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| 1218. |
Give an example of negative acceleration. |
| Answer» Solution :When the BRAKES are applied to a VEHICLE in MOTION, acceleration produced in the vehicle is NEGATIVE. | |
| 1219. |
{:("1 . Ratio of height of image to height of object","(a) Concave mirror"),("2. Used in hairpin bends in mountains", "(b) Total internal reflection"),("3. Coin inside water appearing slightly raised","(c) Magnification"),("4. Mirage","(d) Convex mirror"),("5. Used as Dentist's mirror","(e) Refraction"):} |
| Answer» SOLUTION :1. (c) 2. (d) 3.(e) 4. (B) 5. (a) | |
| 1220. |
The mass suspended from the stretched string of a sonometer is 4 kg and the linear mass density of string 4 xx 10^(-3) kg m^(-1) . If the length of the vibrating string is 100 cm , arrange the following steps in a sequential order to find the frequency of the tuning fork used for the experiment . (A) The fundamental frequency of the vibratinng string is , n = (1)/(2l) sqrt((T)/(m)). (B) Get the value of length of the string (l) , and linear mass density (m) of the string from the data in the problem . (C) Calculate the tension in the string using , T = mg . (D) Substitute the appropriate values in n = (1)/(2l) sqrt((T)/(m)) and find the value of 'n' . |
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Answer» BCAD `m = 4 xx 10^(-3) kg m^(-1)` (b) T = mg = `4 xx 9.8 = 39.2`N (c) Consider , the fundamental frequency of the vibration STRING is n , = `(1)/(2l) sqrt((T)/(m))` (a) SUBSTITUTE the values of l , T and m in n = `(1)/(2l) sqrt((T)/(m))` and calculate the VALUE of n and this frequency of tuning fork (d) . |
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| 1221. |
Three different vibrating objects produce three types of sounds X,Y and Z. sounds X and Y cannot be heard by a man having normal range of hearing but sound Z. can be heared easily. The sound X is used in hosphitals to break kidneys stones of a patient into fine grains which then get flushed out with urine. The sound Y is similar to that which is produced during an earthquake before the main shock wave is generated. (a) What type of sounds are (i) X (ii) Y, and (iii) Z? (b) Name one device which can produce sound like X. (c) Name one device in a science laboratory which can produce sound like Y. (d) Name one device in our homes which can produce sound like Z. (e) What is the frequency range of sounds like Z? |
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| 1222. |
The magnitude of buoyant force acting on an object immersed in a liquid depends on............ of the liquid |
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| 1223. |
How does the speed of sound in air vary with temperature ? |
| Answer» Solution :The SPEED of SOUND increases by 0-61 m `s^(-1)` for each `1^@C` rise in TEMPERATURE. | |
| 1224. |
How many would be reqruied to make 1 kg? m_(p)=1.67xx10^(-7)kg |
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Answer» <P> SOLUTION :NUMBER of proton `(N)xxm_(p)=1kgtherefore n=(1)/(m_(p))=(1)/(1.67xx10^(-27))=5.99xx10^(26)`. |
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| 1225. |
A transformer can step up direct current |
| Answer» SOLUTION :Correct STATEMENT: A transformer can STEP up alternating CURRENT. | |
| 1227. |
The type of energy possessed by a simple pendulum, when it is at the mean position is: |
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Answer» KINETIC energy |
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| 1228. |
Which among the following is not a device to measure mass ? |
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Answer» SPRING balance |
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| 1229. |
Ocean waves of time period 10 s have wave velocity 15 ms^(-1). Find : the horizontal distance between a wave crest and its adjoining wave trough. |
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Answer» SOLUTION :The DISTANCE between a wave crest and its adjoining wave TROUGH =`lambda/2 = 1/2 xx 150 m = 75 m` |
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| 1230. |
A bus is moving with the initial velocity of 'u' m/s. After applying the breaks, its retardation is 0.5 m/s^(2) and it stoped after 12s. Find the initial velocity (u) and distance travel by the bus after applying the breaks. |
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Answer» Solution :a = 0.5 `m//s^(2)` v = 0 m/s t = 12 s u = ? v = u + at 0 = u + `(-0.5 XX 12 )` 0 = u- 6 u = 6 m/s INITIAL velocity of the bus 6 m/s . s = ut + `(1)/(2) at^(2)` = `( 12 xx 6 ) + (1)/(2) ( - 0.5 xx 12^(2) )` = 72 -` (1)/(2) (72)` = 36 m Bus has stoped 36 m distance after applying the break |
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| 1231. |
How are the (i) mass, (ii) volume, and (iii) densilty of a metallic piece affected, if at all with increase in temperatur? |
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| 1232. |
An object is put turn in three liquids having different densities. The object floats with (1)/(9), (2)/(11) and (3)/(7) parts of its volume outside the liquid surface in liquids of densities d_1,d_2 and d_3 respectively. Which of the following statements is correct? |
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Answer» `d_(1)gtd_(2)gtd_(3)` |
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| 1233. |
A block of wood of volume 25cm^(3) floats on water with 20cm^(3) of its volume immersed. Calculate (i) the density, and (ii) the weight of block of wood. |
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Answer» Solution :Given: volume of block `V=25cm^(3)` Volume immersed in WATER `v=20cm^(3)` (i) If DENSITY of wood is `rho g cm^(-3)` then by PRINCIPLE of floatation. Weight of block of wood = Weight of water DISPLACED by the immersed part of block. `V rho g=vxx1xxg`(since density of water `=1gcm^(-3)`) `:. rho=v/(V=2)/25=0.8gcm^(-3)` (ii) Weight of block of wood `=V rho g` `=25xx0.8xxg=20g` dyne `=20` gf |
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| 1234. |
A musical instrument is producing continuous note. This note cannot beheard by a person having a normal hearing range. This note must then be passing through ………. |
| Answer» ANSWER :D | |
| 1236. |
When a beam of white light passes through a prism it gets ....................... . |
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Answer» reflected |
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| 1237. |
A road runs parallel to a vertical cliff at a distance of 495 m as shown in the figure . A car standing at A blows the horn and the driver of the car hears the echo after 3 s. But a person standing at B hears the sounds of horn twice within an interval of 2s . Explain why the person at 'B' heard the sound twice . Also find the distance between the car and the person . |
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Answer» SOLUTION :(i) EQUATION of echo , Pythagoras theorem (II) `v = (2d)/(t_(1))` `v = (("distance covered by SOUND waves") + ( "distance between DRIVER and person"))/(t_(2))` Pythagoras theorem (iii) 412 m |
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| 1239. |
On what principle does a bicycle work ? What is the mechanical advantage of abicycle? Determine the velocityratio of a bicycle in which the ratio of teeth on the rear sprocketwheel to that on the front wheel is 1: 3. |
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Answer» Solution :(i) Consider how the effort applied is transmitted. (ii) Bicycle uses more thanone simple machine. (III) Let L = LENGTH of pedal E = effort applied on pedal W = load to be overcome R = radius of rear wheel (iii) Find the M.A. of cycle using principle of lever: effort `xx` DISPLACEMENT of effort = load `xx` displacement of load `M.A. = (W)/(E)` (iv) Velocity ratio = ratio of number of teeth on front wheel to that on rear SPROCKET wheel |
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| 1240. |
Name the instrument which can measure accurately the following the diameter of a pencil. |
| Answer» SOLUTION :SCREW GAUGE | |
| 1241. |
The stone tied to a thread is suspending from a spring balance. What do you observe? |
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| 1242. |
When a sound is reflectedfrom a distant object, anecho is produced . Let the distance between the reflecting surface and the source of sound production remains the same. Do you hear echo sound on a hotter day ? |
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| 1244. |
State two ways by which the strength of magnetic field of an electromagnet can be increased. |
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Answer» REVERSING the directions of current |
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| 1245. |
The figure show a simple pendulum consisting a bob of mass 100 g. Initially the bob of the pendulum is at rest at O. It is displaced to one side at A. The height of A above O is 5 cm. (i) What is the value of potential energy of the bob at A? (ii) What is the value of kinetic energy of the bob at position P, whose height above O is 2 cm? (Take g=10ms^(-2)) |
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Answer» `g=10ms^(-2)` `E_(P)` at the POINT `A=mgh` `=0.1xx10xx0.05J` `=0.05J` (ii) `E_(K)=(1)/(2)MV^(2)`. As the bob swings FREELY. `v^(2)=2as=2gh` `therefore E_(k)=(1)/(2)m(2gh)=mgh` `=0.1xx10xx0.02J [because h=2cm=0.02m)` `=0.02J` |
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| 1246. |
Which has the higher frequency - ultrasonic sound or infrasonic sound? |
| Answer» SOLUTION :ULTRASONIC SOUND | |
| 1247. |
A boy moves along the path ABCD. What is the total distance covered by the boy ? What is his net displacement ? |
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Answer» SOLUTION :(a)TOTAL distance COVERED by a boy =110 m (b)Net DISPLACEMENT =`sqrt(30^2+40^2)` `=sqrt2500` =50 m 
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| 1248. |
What is Artisan aquifer? |
| Answer» Solution :An artesian aquifer is a confined aquifer ( an UNDERGROUND water bearing permeablerocks) containing groundwater that will flow upwards out of a well without the NEED for PUMPING. In recharging aquifers, this happens because the water table at its RECHARGE zone is at a higher clevation than the head of the well. | |
| 1249. |
The figure shows a jar containing honey and kerosene Which liquid has higher buouancy? |
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| 1250. |
Illustrate the law of conservation of energy by discussing the energy changes which occur when we draw a pendulumbob to one side and allow it to oscillate. Why does the bob eventually come to rest ? What happens to its energy eventually? Is it a violation of the law of conservation of energy? |
| Answer» SOLUTION :When pendulum oscillates in extreme ends. There is a continuous EXCHANGE between potential energy and kinetic energy and the sum of TWO types of energy remain constant According to the LAW of CONSERVATION of energy. This is true in case there is no loss of energydue to external force. | |