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The direction of motion of the particle and the direction of the magnetic field are known. Therefore, we can find the direction of the magnetic force acting on a positive and negative charge using Lorent's law.

red black orangehence Red is 2--1st digitblack 0 --2nd digitorange ,000--thousand20000-2K ohm resistor.

Emf induced in a moving conductor. The emf induced in a straight conductor of length l moving with velocity v perpendicular to a magnetic field B is

1) E = Blv

where B, l and v are mutually perpendicular. The emf is in volts when B is in webers/m2, l is in meters, and v is in m/sec.

1) is the correct answer

1) is the right answer of the following

3) is the correct answer

Carbon composition and carbon film resistors are too small to have the resistance value printed on their housings. Therefore, bands of color are used to represent the resistance value.

The first and second band represent the numerical value of the resistor and the color of the third band specify the power of ten multiplier. The color bands are always read from left to right starting with the side that has a band closer to the edge.

Brown = 1, Black = 0, Gold - multiplier = 0.1, so 10 X 0.1 = 1 ohm.Brown

Components and wires arecodedwithcolorsto identify their value and function. Thecolorsbrown, red, green, blue, and violet are used as tolerancecodeson 5-bandresistorsonly. All 5-bandresistorsuse a colored tolerance band.

42×10^8 ohm using color coding of resistors.

In parallel current will be differentso V= 220and I = i1+I2= 50/220+60/220= 110/220= 1/2= 0.5amp

power of lens = 1/focal length.power of lens is inversely proportional to the focal length, as power increases focal length decreases.

3)40% is the correct answer

1) 27 % is the correct answer

energy of one photon is = h* freq

power is the energy per unit time

therfore the energy given per second is 2 * 10^3

number of photons * energy of one photon = total energy

number of photons = (2*10^3)/(6.636*10^-34 * 6 * 10^14)

approxi mately = 5 * 10^23 photons .

(i) Ultrasound is used in industry to clean parts located in hard-to-reach places, for example, spiral tube, odd shaped parts, electronic components, etc.

(ii) Ultrasound is used in industry to detect cracks and flaws in metal blocks without damaging them.

(iii) Ultrasound is used to investigate the internal organs of the human body such as liver, gall bladder, kidneys, uterus, etc

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Theinstantaneous velocityof an object is thevelocityat a certaininstantof time.Velocityis the change in position divided by the change in time, and theinstantaneous velocityis the limit ofvelocityas the change in time approaches zero. This is equivalent to the derivative of position with respect to time.

at E

slope of graph gives the instantaneous velocity

and it is -ve at point E

so, option 4

The mode of propagation is HF radio propagation.a)Ground-wave or surface-wavepropagation(up to 2 MHz)

b)Space-wave or Line of Sight (LOS) or troposphericpropagation(above 30 MHz)

i think option (I) is correct

Option a) is correct as P.E∝h[∵P.E= mgh]

¹st diagram is correct

since the expression of kinetic energy is 1/2*m*v² so the graph will be like parabolic. as v² is changing as the ball goes up and fall down. since the initial velocity will decrease as it goes up and stops then the velocity will become 0. again when fall down starts it will follow same curve but the curve will be increasing. ao the correct answer is A.

f=c/lamdaf=3*10^8/6000*10^-10f=1/2*10^15Hz5*10^14 Hz=fhence the radiation will emit photoelectrons.

Use R=p l/a p=2.8×10^-8ohmmeter l=2m a=1.5×10^-6m^2 R=0.036ohms

∫sin^4(x)

=> ∫ [sin^2(x)]^2

=> ∫ [(1 -cos(2x)/2)]^2

=>1/4 ∫[1 + cos^2(2x) - 2cos(2x)]

=>1/4 [1 - 2cos(2x) + (1 + cos(4x)/2 ]

=> ∫ (1/4) - ∫(1/2)cos(2x) + ∫(1/8) + ∫(1/8)cos(4x)

=> ∫(3/8) - ∫(1/2)cos(2x) +∫ (1/8)cos(4x)

so ∫sin^4(x)dx = 3/8∫dx - 1/2∫cos(2x) dx + 1/8∫cos(4x) dx

∫sin^4(x)dx = (3/8)x - (1/2)sin(2x)*(1/2) + (1/8)sin(4x)*(1/4) + c

∫sin^4(x)dx = (3/8)x - (1/4)sin(2x) + (1/32)sin(4x) + c

Explaination-# Given-R = 35 ohmL = 2 mr = 0.4 mm = 4×10^-4 mT = 30 °C

# Solution-Resistivity of the material is given by the formula - ρ = RA / Lρ = Rπr^2 / Lρ = 35×3.142×(4×10^-4)^2 / 2ρ = 8.8×10^-6 ohm-m.

Therefore, resistivity of given metal wire at 30 °C is 8.8×10^-6 ohm-m.

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