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False a concave lens is a diverging lens

FalseA concave lens is a diverging lens.Convex lens is a converging lens When the rays of light is incident on a concave lens, they diverge.When light is incident on a convex lens,the rays of light converge at a common point to form an image of the source of light.

Answer:-

Case (a)

Mass of the monkey,m= 40 kgAcceleration due to gravity,g= 10 m/sMaximum tension that the rope can bear,Tmax= 600 NAcceleration of the monkey,a= 6 m/s² upwardUsing Newton’s second law of motion, we can write the equation of motion as:T–mg= ma∴T=m(g+ a)= 40 (10 + 6)= 640 NSinceT>Tmax, the rope will break in this case.

Case (b)Acceleration of the monkey,a= 4 m/s2downwardUsing Newton’s second law of motion, we can write the equation of motion as:mg –T=ma∴T=m(g– a)= 40(10 – 4)= 240 NSinceT<Tmax, the rope will not break in this case.

Case (c)The monkey is climbing with a uniform speed of 5 m/s. Therefore, its acceleration is zero, i.e.,a= 0.Using Newton’s second law of motion, we can write the equation of motion as:T–mg= maT–mg = 0∴T=mg= 40 × 10= 400 NSinceT<Tmax, the rope will not break in this case.

Case (d)When the monkey falls freely under gravity, its will acceleration become equal to the acceleration due to gravity, i.e.,a =gUsing Newton’s second law of motion, we can write the equation of motion as:mg –T=mg∴T=m(g–g) = 0SinceT<Tmax, the rope will not break in this case.

Let`s say east be positive X direction. And north be +Y direction. Now VA=10iVB= 20j

Now VAB =Va-Vb= 10i-20j so the sqrt(500) = 10sqrt522.36 m/s

Given that

VA =10 m/s i

VB = 20 m/s j

Vab = Va - Vb = 10i - 20j

Vab = √(10)^2 + (-20)^2 = √500

Vab = 10√5 = 22.30 m/s is the answer

The answer is option A.

Thehydraulicpressdepends onpascalprinciple: the pressure throughout a closed system is constant.

3) is the correct answer

It is Mayer's equation.

Derivation:

ΔU = ΔQ + ΔW ΔU = Cv ΔT (At pressure is constant)

ΔQ = Cp ΔT (At pressure is constant)

ΔW = -P ΔV (Negative since the calculation been complete)

Pv = RT (1 mole of gas)

Because of pressure is constant, R is also constant

Change in V will make change in T

PΔV = R ΔT

Cv ΔT = CpΔT - RΔT

Divided by ΔT

Cv = Cp - R

Cp - Cv = R

Scientific method is an organized way to investigate a problem

Areform movementis a type ofsocial movementthat aims to bring a social or political system closer to the community's ideal. A reform movement is distinguished from more radical social movements such asrevolutionary movementswhich reject those old ideals in the ideas are often grounded inliberalism, although they may be rooted insocialist(specifically,social democratic) orreligiousconcepts. Some rely on personal transformation; others rely on small collectives, such asMahatma Gandhi'sspinning wheeland the self-sustaining village economy, as a mode ofsocial change.Reactionary movements, which can arise against any of these, attempt to put things back the way they were before any successes the new reform movement(s) enjoyed, or to prevent any such successes.

The dyne (symbol dyn, from Greek dynamis, meaning power, force) is a derived unit of force specified in the centimetre–gram–second (CGS) system of units, a predecessor of the modern SI.

(a) is correct option

Loss of weight in water = weight in air / specific gravity = 5/3Weight of stone in water = 5-5/3 = 10/3Force = 10/3 x 9.8 = 98/3Work done = 5 x 98/3 = 163.3

called momentum of the body.

final velocity of the iron sphere just before ground is v² = (2)*(10)*(0.80) = 16v = √16 = 4m/s

now... momentum transfer to the ground is ∆m = m(v1-v2) = 10(4) = 40kg-m/s

98 N

Velocity when it hits the groundu = sqrt(2gH)= sqrt(2 * 9.8 * 9.8)= 9.8 sqrt(2) m/s

Velocity just after hitting the groundv = sqrt(2gH)= sqrt(2 * 9.8 * 4.9)= 9.8 m/s

Impulse = change in momentum= mass × change in velocity= m * (v - u)= 1kg * (9.8 - (-9.8*sqrt(2)) m/s= 9.8 * (1 + sqrt(2)) kgm/s= 9.8 * 1.414 kgm/s= 13.8572 kgm/s

Average Force = Impulse / Time taken= 13.8572 / 0.1= 1.38 N

wrong ans

Lenz's law, named after the physicist Emil Lenz who formulated it in 1834, states that the direction of the current induced in a conductor by a changing magnetic field is such that the magnetic field created by the induced current opposes the initial changing magnetic field.

As the weight of the balloon is less than the weight of air displaced by it therefore the balloon rises in air. In balloons hydrogen is normally filled because it is lighter than air.

Bernoulli Equation

The Bernoulli Equation can be considered to be a statement of theconservation of energyprinciple appropriate for flowing fluids. The qualitative behavior that is usually labeled with the term "Bernoulli effect" is the lowering of fluid pressure in regions where the flow velocity is increased. This lowering of pressure in a constriction of a flow path may seem counterintuitive, but seems less so when you consider pressure to beenergy density. In the high velocity flow through the constriction, kinetic energy must increase at the expense of pressure energy.



Steady-state flow caveat: While the Bernoulli equation is stated in terms of universally valid ideas like conservation of energy and the ideas of pressure, kinetic energy and potential energy, its application in the above form is limited to cases of steady flow. For flow through a tube, such flow can be visualized aslaminar flow, which is still an idealization, but if the flow is to a good approximation laminar, then the kinetic energy of flow at any point of the fluid can be modeled and calculated. The kinetic energy per unit volume term in the equation is the one which requires strict constraints for the Bernoulli equation to apply - it basically is the assumption that all the kinetic energy of the fluid is contributing directly to the forward flow process of the fluid. That should make it evident that the existence of turbulence or any chaotic fluid motion would involve some kinetic energy which is not contributing to the advancement of the fluid through the tube.

It should also be said that while conservation of energy always applies, this form of parsing out that energy certainly does not describe how that energy is distributed under transient conditions. A good visualization of the Bernoulli effect is theflow through a constriction, but that neat picture does not describe the fluid when you first turn on the flow.

Another approximation involved in the statement of the Bernoulli equation above is the neglect of losses fromfluid friction. Idealized laminar flow through a pipe can be modeled byPoiseuille's law, which does include viscous losses resulting in a lowering of the pressure as you progress along the pipe. The statement of the Bernoulli equation above would lead to the expectation that the pressure would return to the value P1past the constriction since the radius returns to its original value. This is not the case because of the loss of some energy from the active flow process by friction into disordered molecular motion (thermal energy). More accurate modeling can be done by combining the Bernoulli equation with Poiseuille's law. A real example which might help visualize the process is the pressure monitoring of the flow through aconstricted tube.

Bernoulli calculation

Bernoulli's principlestates that an increase in the speed of a fluid occurs simultaneously with a decrease inpressureor a decrease in thefluid'spotential energy.[1](Ch.3)[2](§ 3.5)The principle is named afterDaniel Bernoulliwho published it in his bookHydrodynamicain 1738.[3]Although Bernoulli deduced that pressure decreases when the flow speed increases, it wasLeonhard Eulerwho derivedBernoulli's equationin its usual form in 1752.[4][5]The principle is only applicable forisentropic flows: when the effects ofirreversible processes(liketurbulence) and non-adiabatic processes(e.g.heat radiation) are small and can be neglected.

V=46.1m/sU=18.5m/sT=2.47 secV=u+at46.1=18.5+a*2.472.47a=46.1-18.5=27.6a=27.6/2.47==11.17m/sec^2Distance=ut+.5at^2 =(18.5*2.47)+(0.5*11.47*2.47*2.47)=45.695+34.99=80.68m

it's answer can be found by 2nd equation of motions=ut+1/2at^2

Distance=speed*time=30*20=600m

To cross the bridge, the train will have to cover a distance equal to the sum of length of the bridge and length of the train.

speed of train = 30 m/stime taken = 20sdistance covered = 30 × 20 = 600m

now, length of bridge = 400mlength of train = 600 - 400 = 200m

Let the length of train be xthen , distance covered by train = 400m + xspeed = 30m/s time = 20sso , we know that , speed = distance/time distance = speed × time d(400+x) = 30 × 20400+x = 600x = 200m length of train = 200mhope this helps

the answer would be 3. c

the correct answer is A 1.

A system is inunstable equilibriumif, when displaced, it experiences a net force or torque in the same direction as the displacement fromequilibrium. A system inunstable equilibriumaccelerates away from itsequilibriumposition if displaced even slightly. An obvious example is a ball resting on top of a hill.

Option

option c is the correct answer

option C) is the correct answer

It is at point D

Thanks for asking

option 4, d is the right answer

The main hazards with electricity are:

contact with live parts causing shock and burns

faults which could cause fires;

fire or explosion where electricity could be the source of ignition in a potentially flammable or explosive atmosphere.

Avoid corded phones. However, cordless or cellular phones are safe to use during a storm. Lightningstrikesmay be rare, but they still happen and the risk of serious injury or death issevere. So take thunderstorms seriously.

Mitosis is required for growth and replacement while meiosis is required for gamete formation.

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R = √HH1 option second is correct

is the correct answer = R = √HH1

Given :

BX = 1/2 AB i.e. 2BX = AB

BY = 1/2 BCi.e2BY = BC

We have, AB = BCSo,2BX = 2 BYDivide 2 on both sidesBX = BY

the dimension of work is answer A

the dimension of work[ML2T−2]

The dimensions of work is answer À

dimension of work is answer A

Global warming, the phenomenon of increasing averageairtemperaturesnear the surface ofEarthover the past one to two centuries. Climate scientists have since the mid-20th century gathered detailed observations of variousweatherphenomena (such as temperatures,precipitation, and storms) and of related influences onclimate(such asocean currentsand the atmosphere’s chemical composition).

Sol. At point B (i.e. over 1.8 m from ground) the kid should be catched. For kid- initial velocity u = 0 Acceleration = 9.8 m/s2 Distance S = 11.8 – 1.8 = 10 m S = ut + ½ at2 ⇒ 10 = 0 + ½ (9.8) t2 ⇒ t2 = 2.04 ⇒ t = 1.42. In this time the man has to reach at the bottom of the building. Velocity s/t = 7/1.42 = 4.9 m/s.

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= mass/volume

= 96/12 g/cm³

= 8 g/cm³

To determine the focal length of concave mirror.

We require a concave mirror preferably mounted on a stand, a lighted candle and a white screen to catch the image after reflection

Keep the mounted concave mirror on a plane surface (say a long table). Keep in front of the reflecting surface a bright candle at sufficient distance from the concave mirror on the principal axis so that we can get a clear image somewhere. Now adjust the screen ,candle and the mounted concave mirror so that they are all on the principal axis. Move the screen back and forth and determine the position for the brightest clearest image.

Note down for the clear image distance v and the corresponding object distance u from the pole of the mirror along the principal axis. Then, if f is the the focal length of the mirror, solve for f = uv/(u+v) which determines the focal length f on one single trial.

You make the following table of observation for repeated trials varying object distance u and the image distance v:

Trial no: Dist u of object from the pole . Distance v of image from the pole. Focal legnth f = uv/((u+v)

After doing different trials you can find the average focal length from the last column.

option a)Ds/dt = ksqrt(s) s^(-1/2) ds = k dt s^(1/2) / (1/2) = kt 2sqrt(s) = kt s = k^2 t^2 / 4 a = d2s / dt2 = k^2 / 2 dW = F dS = ma dS Since the force is constant, W = ma integral(dS) = ma S = (mk^2 / 2) x (k^2 t^2 / 4)

Ans :- Modern steam turbines are a combination of the reaction and impulse design. Typically, higher pressure sections are impulse type and lower pressure stages are reaction type.

The specific heat of ironis 0.11cal(g°C) .