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h2=-3.3cm and v=16.67

Given, height of object = 5cm

Position of object, u = - 25cm

Focal length of the lens, f = 10 cm

Hence, position of image, v =?

We know that,

1/v - 1/u = 1/f

1/v + 1/25 = 1/10

So, 1/v = 1/10 - 1/25

S0, 1/v = (5 - 2)/50

That is, 1/v = 3/50

So, v= 50/3 = 16.66 cm

Thus, distance of image is 16.66 cm on the opposite side of lens.

Now, magnification = v/u

That is, m = 16.66/-25 = -0.66

Also, m= height of image/height of object

Or, -0.66 = height of image / 5 cm

Therefore, height of image = -3.3 cm

The negative sign of height of image shows that an inverted image is formed.

Thus, position of image = At 16.66 cm on opposite side of lens

Size of image = - 3.3 cm at the opposite side of lens

Nature of image – Real and inverted....

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A transistor is a semiconductor device used to amplify or switch electronic signals and electrical power. It is composed of semiconductor material usually with at least three terminals for connection to an external circuit.

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f, the focal length, is positive for a concave mirror, and negative for aconvexmirror. When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the image distance is negative, the image is behind the mirror, so the image isvirtualand upright.

In telecommunications and signal processing, frequency modulation is the encoding of information in a carrier wave by varying the instantaneous frequency of the wave.

Transistor is a semiconductor device with three terminals viz., Emitter (E), Base (B) and Collector (C) and thus has two junctions viz., Base-Emitter (BE) junction and Base-Collector (BC) junction as shown by Figure 1a. Such a device can operate in three different regions viz., cutoff, active and saturation. Transistors are fully-off in cut-off region while fully-on when operating in saturation region. However, while they operate in active region, they act as amplifiers i.e. they can be used to increase the strength of the input signal without altering it significantly.The reason behind such a behavior can be understood by analyzing the working of transistor in terms of charge carriers. For this, let us consider a npn bipolar junction transistor(BJT) biased to operate in active region (BE junction is forward biased while BC junction is reverse biased) as shown by Figure 1b.

Here, in general, the emitter will be heavily doped, the base will be lightly doped and the collector will be moderately doped. Further the base will be narrow, the emitter will be broader and the collector will be much broader.

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Amplifieris a circuit that is used for amplifying a signal. The input signal to anamplifierwill be a current or voltage and the output will be an amplified version of the input signal. Anamplifiercircuit which is purely based on atransistorortransistorsis called atransistor amplifier.

Ans :- The Common EmitterAmplifiercircuit has a resistor in its Collector circuit. The current flowing through this resistor produces thevoltageoutput of theamplifier. The Base of thetransistorused in a common emitter amplifieris biased using two resistors as a potential divider network.

The bandwidth represents the amount or "width" of frequencies, or the "band of frequencies," that the amplifier is MOST effective in amplifying.

Diamond : The cut of the diamond favors total internal reflection. Most rays entering the top of the diamond will internally reflect until they reach the top face of the diamond where they exit. This gives diamonds their bright sparkle. Notice in this animation that a ray entering the top doesn't exit the diamond until it reaches the top surface.

Fiber Optics : A fiber optic is a glass "hair" which is so thin that once light enters one end, it can never strike the inside walls at less than the critical angle. The light undergoes total internal reflection each time it strikes the wall. Only when it reaches the other end is it allowed to exit the fiber.Fiber optic cables are used to carry telephone and computer communications.

Telescope : The construction of telescope is based on total angle reflection.

Applications of total internal reflection :

1] Totally reflecting prism are used in reflex cameras, binoculars and periscopes.

2] Optical fibres (thin fibres of high quality glass) are used in communications and endoscopy (the visual observation pf various internal body cavities) transmit light signals by total internal reflection.

3] A diamond gem is given strategic cuts so that total internal reflections give the gem its sparkling brilliance.

2x+3=0=>2x+3-3=0-3=>2x=-3=>x=-3/2

2x+3 =02x=-3X=-3/2

star hotel but planet not hotel

star has own light.but planet has not its own light.

When in an amplifier circuit only one transistor is used for amplifying a weak signal, the circuit is known as single stage amplifier.

However, a practical amplifier consists of a number of single stage amplifiers and hence a complex circuit. Therefore, such a complex circuit can be conveniently split into several single stages and can be effectively analysed.

The above fig. shows a single stage transistor amplifier.

When a weak a.c. signal is applied to the base of the transistor, a small base current starts flowing in the input circuit.

Due to transistor action, a much larger (β times the base current) a.c. current flows through the the load Rc in the output circuit.

Since the value of load resistance Rc is very high, a large voltage will drop across it.

Thus, a weak signal applied

The various circuit elements and their functions are described as follows :

(i) Biasing Circuit. ...

(ii)InputCapacitor (Cin) ...

(iii) Emitter Bypass Capacitor (CE) ...

(iv) Coupling Capacitor (CC) ...

Various Circuit Currents.

(i)BaseCurrent. ...

(ii) Collector Current. ...

(iii) Emitter Current.

The slope of the given graph gives us the inverse of resistance .resistance of a material increases with increasing temperature because the collision between the molecules increases. In the given graph , given T2 has smaller slope and hence corresponds to higher resistance .Therefore,T2>T1

Whentemperaturesare equal,nomoreheatcan be transferred, even though the hot and cold objects still containheat. Whenheatisconverted into work, thetemperatureof theheatsource falls, approaching that of theheat sink. ... The only exception is that 100% of any useful energy can be dissipated as wasteheat.it is imposssible to have any body that can continuously converts heat into energy

8085 Microprocessor – Functional Units

Accumulator. It is an 8-bit register used to performarithmetic, logical, I/O & LOAD/STORE operations.

Arithmeticand logic unit.

General purpose register.

Program counter.

Stack pointer.

Temporary register.

Flag register.

Instruction register and decoder.

Basically these three are temperature units.Following are the conversion formulae,

Celsius to Fahrenheit° F = 9/5 × ( ° C) + 32Kelvin to Fahrenheit° F = 9/5(° K - 273) + 32Fahrenheit to Celsius° C = 5/9(° F - 32)Celsius to Kelvin K = ° C + 273Fahrenheit to Kelvin K = 5/9 (° F - 32) + 273

The Kelvin scale is an absolute, thermodynamic scale (meaning twice the number, twice the heat indicated) with the two defining points absolute zero at 0 and the triple point of water at 273.16.

The Celsius temperature is defined to be exactly 273.15 less than the Kelvin temperature. Combining this with the information above about the Kelvin scale yields the two defining points absolute zero at −273,15 and the triple point of water at +0.01. (Contrary to popular belief, the definition of the Celsius scale has nothing to do with the melting point of ice nor the boiling point of water at standard atmospheric pressure.)

The Fahrenheit scale is defined so that the Fahrenheit temperature is 32 more than 1.8 times the Celsius temperature. Combining this with the information above about the Celsius scale yields the two defining points absolute zero at −459.67 and the triple point of water at +32.018. (Contrary to popular belief, the definition of the Fahrenheit scale no longer has anything to do with the melting point of ice and the boiling point of water at standard atmospheric pressure.)

The formulas for converting between degree Celsius and degree Fahrenheit are:°F = (°C * 9/5) + 32°C = (°F - 32) * 5/9To find the temperature when both are equal, we use an old algebra trick and just set ºF = ºC and solve one of the equations.°C = (°C * 9/5) + 32°C - (°C * 9/5) = 32-4/5 * °C = 32°C = -32 * 5/4°C = -40°F = (°F * 9/5) + 32°F - (°F * 9/5) = 32-4/5 * °F = 32°F = -32 * 5/4°F = -40

So the temperature when both the Celsius and Fahrenheit scales are the same is -40 degrees

Ans :- Osmotic pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in pure solvent by osmosis.

Osmotic pressure is a colligative property I.e. it depends upon number of particles of solute present in the solution. In case of solute which undergo association or dissociation, osmotic pressure is not normal ,it is more or less than the expected.

most welcome

We have m1= 20kg, m2= 250 kg, r = 0.3m, F = 0.25 mg wt = 0.25 x 10^-6kg wt.

F = 0.25 x 9.80 x 10^-6N

We have the formula F = G m1m2/ r^2

or G = F r^2/ m1m2

G = 0.25 x 9.80 x 10^-6x 0.30 x 0.30 / 20 x 250

= 0.2205 x 10^-6 / 5 x 10^3

G = 0.0441 x 10^-9

Now g = GM / R^2

g = g x R^2/ G

= 9.8 x (6 x 10^6)^2/ 0.0441 x 10^-9

= 8000 x 10^21

g = 8 x 10^24kg

the correct answer is 85

answer is 225Nm or jule

The period of a periodic wave is 0.02s. At a particular position, there is a crest at t = 0. A trough appears at this position at t = 0.01.Reason: Time period of an oscillation is the time taken for one complete oscillation. The distance between two consecutive crests or two consecutive troughs is called the wavelength. The crest and following trough make half the wavelength. Therefore, the time taken will be half the time period i.e. 0.02/ 2 = 0.01. Since the crest is at t=0, the next trough will be at t=0.01.

The period of a periodic wave is 0.02s. At a particular position, there is a crest at t = 0. A trough appears at this position at t = 0.01.Reason: Time period of an oscillation is the time taken for one complete oscillation. The distance between two consecutive crests or two consecutive troughs is called the wavelength. The crest and following trough make half the wavelength. Therefore, the time taken will be half the time period i.e. 0.02/ 2 = 0.01. Since the crest is at t=0, the next trough will be at t=0.01.

A journey, especially an arduous or hazardous one, undertaken with extensive planning and a definite objective: anexpeditionagainst the enemy stronghold; a scientificexpeditionto the South Pole. b. The people undertaking such a journey, considered as a group.

thanx

(1) The Dipole Moment is given by P=qd

Where, q= charged=distance between the charges.

Clearly dipole moment has the unit Coulomb meter (Cm) in S.I.

(2) Force in electric field is given by:F = qEE = F/qunit of electric field is N/C i.e newton per coulomb.

Arrangement pattern of the veins of the leaf

The design made by veins in a leaf is called leaf venation.

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Lightning is a sudden electrostatic discharge that occurs typically during a thunderstorm. This discharge occurs between electrically charged regions of a cloud, between two clouds, or between a cloud and the ground.

The scalar product's only have magnitude