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6601.

tal

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6602.

DEFECT oF Myopia

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Myopia: (nearsightedness) This is adefectof vision in which far objects appear blurred but near objects are seen clearly. The image is focused in front of the retina rather than on it usually because the eyeball is too long or the refractive power of the eye's lens too strong.Please hit the like button if this helped you

6603.

Type of myopia

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Ans :- There aretwo typesof myopia. The first one is simple myopia (which is not considered a visual disease) which is less than 6 diopters. The second one is high myopia, when the patient exceeds 6 diopters, it is then an eye disease.

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6604.

The defect of eye seen when the size of the sphericaleye increases is of type(1) Hypermetropia (2) Myopia(3) Astigmatism (4) of these48.

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in astigmatism the eye becomes more spherical and hence cylindrical lenses are to be used.

6605.

Doctor has prescribed a lens havingpower +1.5 D. What will be the focallength of the lens? What is the typeof the lens and what must be thedefect of vision?

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power of lens = +1.5Dfocal length = 1/P= 1/1.5= 2/3+0.67The prescribed lens is converging type in nature

6606.

WhichWhich eye defect is shown in figure ?

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this defect is myopia for correctionwe use concave lens

6607.

Which defect of the eye is shown in the figure given below?

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The defect show in the figure is hypermetropia

Far sightedness (Hypermetropic eye)

6608.

i. Doctor has prescribed a lens havingpower +1.5 D. What will be the focallength of the lens? What is the typeof the lens and what must be thedefect of vision?

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power of lens is given by power p aap equal to one upon app f is equal to 1 upon p B equal to f equal to one upon -1.5 f is equal to minus 6 point 6 centimetre since the power is negative the lens is of a diverging nature dot therefore it's a concave lens

6609.

45. The pulleys and strings shown in figure are smooth and of negligible mass.EAMCET / Board & Competitive Exanequilibrium, the angle θ should beor the system to remain,0i0吻/m(2) 30°(4) 60°(3) 4546. If two identical masses, attached by a linht string

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6610.

define myopia? which lens doctor prefer for remedy ? draw a diagram

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6611.

Hypermetropia & Long sightedness/)

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Hypermetropia (long-sightedness) is a common eye condition where nearby objects appear blurred, but your vision is clearer when looking at things further away.

6612.

(Hypermetropia)

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6613.

what is meant by hypermetropia

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6614.

What is Hypermetropia, write the Remedy: for it.

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Hypermetropia, sometimes called hyperopia, is the term used to define being longsighted.

If you are hypermetropic, the image of a nearby object is formed behind the retina. This means that light is focused too far back in the eye, causing things which are close up to appear blurred.

How is it treated?

Both myopia and hypermetropia can be easily corrected by the Optometrist at your local Vision Express, using prescription glasses or contact lenses specifically designed to counteract their effects.

Shortsightedness is corrected using a concave (curved inwards) lens which is placed in front of a myopic eye, moving the image back to the retina and making it clearer.

Longsightedness is corrected using a convex (outward facing) lens. This is placed in front of a hypermetropic eye, moving the image forward and focusing it correctly on the retina.

6615.

1.What is hypermetropia ? How can it be corrected?

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A person withhypermetropia/hyperopia or long sight can see clearly objects far away from them, but not close to them.

This iscausedby the shape of the eye - the eyeball is slightly too short.

It iscorrectedby spectacles or contact lenses with lenses which are 'plus' or convex in shape

what is hypermetropia?

6616.

10. A large number of identical point masses m areplaced along x-axis, at x 0, 1, 2, 4,magnitude of gravitational force on mass at origi(x-0), will be.. Thex=0 x = 1 x=2x=4 and so on4(2) G23(1) Gm22(3) Gm2(4)Grif4

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The magnitude of gravitational force on mass at origin is given by,

F=G×m×m/1^1+G×m×m/2^2+G×m×m/4^2+G×m×m/8^2+......

[Using,F=GMM'/r^2

Given,M=M'=m]

So,F=Gm×m[1+1/4+1/16+...]=Gm^2[1/4/1−1/4⎤⎦=Gm^2×1/3=Gm^2/3

but its given 4/3 Gm^2

6617.

913. What is weight of brain in man and women

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The average brain weight in adult males is1,345 grams; in adult females,1,222 grams.

thanks

6618.

164.The space between the lens and retins is calle

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I was thinking answer is ciliary muscles .

6619.

What are the defects of an eye ? Explain Hypermetropia.

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There are three common defects of an eye. They are:

1) Myopia (Short-sightedness or Near-sightedness)

2) Hypermetropia (Long-sightedness or Far-sightedness)

3) Presbyopia

Hypermetropia (long-sightedness) is a common eye condition where nearby objects appear blurred, but your vision is clearer when looking at things further away. If you feel your eyes are often tired and you have problems focusing on objects close to your eyes, you may have hypermetropia.

6620.

Why does a compass needle get deflected when brought mea bar magnet?

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6621.

BSCand rule.0.23. if A-2i+j-k& Bi-23-3k find 1) 2A+B 2) 3A-B 3)A-B

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6622.

Why does a compass needle get deflected when brought neara bar magnet?

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6623.

Wihs does a compass needle get defleceted when brought neara bar magnet?s

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a compass needle gets deflected when brought near to magnet because a compass in a magnetic field exert a magnetic force either the attraction or repulsion.

6624.

C.僦扴のマ弁研Myopia can be corrected by usingA. Concave lensC. Bi-focal lensB. Convex lensD. of these

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For myopia concave lens is used.

So, Option A is correct.

6625.

State and explain the defects of vision . How can these defects be rectified?

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Myopia:(nearsightedness) This is a defect of vision in which far objects appear blurred but near objects are seen clearly. The image is focused in front of the retina rather than on it usually because the eyeball is too long or the refractive power of the eye’s lens too strong. Myopia can be corrected by wearing glasses/contacts with concave lenses these help to focus the image on the retina.

Hyperopia:(farsightedness) This is a defect of vision in which there is difficulty with near vision but far objects can be seen easily. The image is focused behind the retina rather than upon it. This occurs when the eyeball is too short or the refractive power of the lens is too weak. Hyperopia can be corrected by wearing glasses/contacts that contain convex lenses.

Astigmatism:This defect is when the light rays do not all come to a single focal point on the retina, instead some focus on the retina and some focus in front of or behind it. This is usually caused by a non-uniform curvature of the cornea. A typical symptom of astigmatism is if you are looking at a pattern of lines placed at various angles and the lines running in one direction appear sharp whilst those in other directions appear blurred. Astigmatism can usually be corrected by using a special spherical cylindrical lens; this is placed in the out-of-focus axis.

6626.

6. What are the advantages of connecting electrical devices in paraliel instead of series? (3)0.17 Derive an

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6627.

24. When the speed of a particle is doubled, the ratioof its kinetic energy to its momentum(a) remains the same(b) gets doubled(c) becomes half(d) of the above

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it's mometum remain same

yes it gets doubled when two are collision means kenitic energy

Kinetic energy = 1/2 mv^2

Kinetic energy is proportional to square of velocity(or speed)

So when speed is doubled, Kinetic energy becomes 4 times.

yes it gets doubled because speed is directly proportional to K. E

option B is the correct answer

yes it gets doubled in an kinetic energu

6628.

(1) 1.2 litresA gas at the temperature 250then the percentage increase in its pressure will be(1) 0.4%2) . iltresK is contained in a closed vessel. If the gas is heated through 1K,(2)0.2%(3)0.1%(4) 0.8%har of molecules

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6629.

A body cool from 80 degree centigrade to 50 degree centigrade in 5 mints calculate the time to cool 60 degree centigrade to 30 degree centigrade the temperature of surrounding is 20 degree centigrade

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6630.

* The unit of radius of gyration is(a) kg-m(c) mb) Nm(d) Jsa its kinetic e

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Its S Iunitof radius of gyration is m

6631.

Provev = utat (by Calculus method)

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we know that,acceleration=change in velocity/timea=v-u/tat=v-uat+u=vso, it is proved that v=u+at

6632.

v=u+at solve by calculus method

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6633.

INTEGRALCALCULUS

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It is a branch of mathematics concerned with the determination, properties, and application of integrals.

explain it briefly please

6634.

3s.Whatishisacceleraliu10km/hpersecond.Takinthe speed of sound as2 An aircraft travelling at 600 km/h accelerates steadily at1100 km/h at the aircraftaltitude, how long will it take to reach the sound barrier ?dut daceleration-of 5 m/show long ill

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6635.

eauties &speed of 6 mu's altex traveling with undionn accelermiunn Sor3 s. What is his acceleration ?32. An aircraft travelling at 600 km/h accelerates steadily at 10 km/h per second. Takingthe speed of sxumd as1100 km/h at the aircraft's altitude, how long will it take to reach the'sound barrier 1

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6636.

isGR BANDHU GYAN KEND33. Given that A + B = Ř and A + 2Bperpendicular to Ä . Then:(a) 2B =R(b) B = 2RKEBER(d) B2 = 2R

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c.is correct answer....

option c is correct answer

option c is correct answer

option c is the correct answer of the given question

6637.

A tower subtends an angle of 30° at a point on thesame level as the foot of tower. At a second pointh m high above the first, the depression of the footof tower is 60°. The horizont stance of the towerfrom the point is21.h cot 60°(2)--3一(1)hcot 60°3(4) h cot 30

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6638.

sodlum carbonatc+ ethanoicacidSuinhighestA particle is thrown vertically up with a velocity of 50 m/s. what will be its velocity apoint of journey? How high would the particle rise? What time it takes to reach the h(Take the value of g-10 m/s2)

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6639.

An aircraft travelling at 600 km/h accelerates steadily at 10 km/h per second. Taking the speed of sound as1100 km/h at the aircraft's altitude, how long will it take to reach the 'sound barrier' ?

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Final velocity, v = 1100 km/h= 1100 × 5/18 = 305.55m/sInitial velocity,u= 600 km/h= 600 × 5/18 = 166.66m/sAcceleration = 10 km/hper second = 10 × 5/18 = 2.77m/s2Time taken by body,v =u + att= (v -u)/at = (305.55 -166.66 )/2.77t = 50.14 sect≃50 sec

6640.

Consider a small pebble of mass 1.0 gram falling from a Cliff of height 1km. If it hits the ground with aspeed of 50 m/s. What is the work done by the unknown resistive force ? 、

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6641.

A bulet of mass 0.04kg moving with a speed of 90m/s enters aheavy wooden block and is stopped after a distance of 60cmWhat is the average resistive force exerted by the block on bulletE.

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v²-u²=2ax0-(90)²=2a0.6thereforea=-1500ms-²now F=mathereforeF=0.04*-1500thereforeF=60N

6642.

What is meant by power of a lens? Write its SI unit. A student uses a lens of focallength 40 cm and another of -20 cm. Write the nature and power of each lens.

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6643.

What is meant by power of a lens ? Write its SI unit. A student uses a lens of foclength 40 cm and another of -20 cm. Write the nature and power of each lens.

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The ability of a lens to converge/diverge a beam of light rays is expressed in terms of its Power(P). P=1/f The SI unit of power of lens is Dioptre.It is denoted by the letter "D" SI unit of length is metre(m) therefore 1D = 1/m or 1D = 1m-1

f1 = 40cm = 0.4m P1 = 1/f1 P1 = 1/0.4 P1 = 2.5 DSince Power is +ve therefore the lens with focal lenght 40cm is convex lens.

f2 = -20cm = -0.2m P2 = 1/f1 P2 = 1/-0.2P2 = -5D Since Power is -ve therefore the lens with focal lenght -20cm is concave lens.

The image formed by the concave lens is virtual, erect and diminished irrespective of the position of the object.

6644.

A force of 50 Newton against the wall with a coefficient of friction 0.5. find the frictional force exerted by the wall

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frictional force exerted by wall=0.5*50=25 N

6645.

3.1workenergy theorem (state and prove).

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6646.

C. Answer the following questions.1. How many different types of motions does the Earth have?of the Farth? What is the effect of rotat

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two types of motion1 rotation2 revolution

6647.

Y1nYTYY2.14 State and explain work energy theorem.

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According to thework-energy theorem, the net work on an object causes a change in the kinetic energy of the object. The formula for net work isnet work = change in kinetic energy = final kinetic energy - initial kinetic energy.

Explanation :

6648.

can prove work - energy theoremState and explain Kepler's Laws of planetary motion

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thanks for the answer

6649.

Develop the notions of work and kinetie energy and show that it leads to work-energy theorem.(Mar-14,15-TS, 17-AP)

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6650.

list changes in the body that takes place at puberty

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Generally speaking, the first physicalchanges during pubertyin girls are breast development andbodygrowth. Otherpuberty changesare:

Timing of Puberty.

Genitalia & Pubic Hair.

Growing.

Possible Breast Development.

Voice Change.

Body Hair.

Acne.