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V=0u=19.6total time=5secg=9.8m/s squaret= u/g= 19.6/9.8=2sec to go uptherefore time to come down =3secheight = u square/2g=(19.6) square/2*9.8=19.6mheight =1/2gt square1/2 (9.8)*(3)square=44.1mheight of the building =44.1-19.6=24.5mv=gt= 9.8*3=29.4m

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We know that Horizontal range R = u^2sin 2theta/g --------------- (1)

We know that Maximum height H = u^2sin^2 theta/2g ------------- (2)

On solving (1) and(2) we get

R/H = 4/tan theta --------------------- (3)

Given, R = 50m, Height = 10, substitute in (3), we get

50/10 = 4/tan theta

tan theta =4/5

theta = 38.6598 degrees.

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option 1 is the answer as it's about aircraft taking off.

T =√(2h/g) = √(2*5)/10 = 1 cm Here we have given that R = 10m At that point The speed is R/t = 10m/sec.

Pls explain please

This case is a projectile fired horizontally from a height of hg=9.8m/s2

a)Time it takes to reach the ground,height=100mt=√2h/gt=√2x100/9.8=√200/9.8=4.51 sec

b)The horizontal distance it travels before reaching the ground:speed=u=20m/sx=ut=20x 4.5 =90m

c)Horizontal velocity remains constant through out the journey.

At "A", vx=20m/svy=u+at=0+9.8 x 4.5=44.1m/s

Final resultant velocity=vr=√(44.1)²+20²=48.42 m/stanβ=vy/vx=44.1/20=2.205β=tan⁻¹(2.205)=66⁰∴The ball strikes the ground with a velocity of 48.42m/s at an angle of 66° with horizontal.

This case is a projectile fired horizontally from a height of hg=9.8m/s2

a)Time it takes to reach the ground,height=100mt=√2h/gt=√2x100/9.8=√200/9.8=4.51 sec

b)The horizontal distance it travels before reaching the ground:speed=u=20m/sx=ut=20x 4.5 =90m

c)Horizontal velocity remains constant through out the journey.

At "A", vx=20m/svy=u+at=0+9.8 x 4.5=44.1m/s

Final resultant velocity=vr=√(44.1)²+20²=48.42 m/stanβ=vy/vx=44.1/20=2.205β=tan⁻¹(2.205)=66⁰

∴The ball strikes the ground with a velocity of 48.42m/s at an angle of 66° with horizontal.

Answer will be 2u^2/g * (tan alpha)/(cos alpha)

wrong answer

a=3t^2+3t+5so v=integration(a) =t^3+3/2t^2+5t+cwhere c is a constantnow initial velocity is 3so c=3so velocity at the end of 2s(2)^3+3/2(2)^2+5*2+3=8+6+10+3=27m/s

thanks

Acceleration = dv/dt= dv/dx* dx/dtThanks

A option is correct

plz give solution not the ans...

The box with force 7N Will move to the respective direction and the force with v and will be opposite the force will 7 and because net force will be applied while we push both the boxes resources 5 and 7 and respectively you may have see that the force 7 and applying to the box will move quite fast

box will move because two of them are pussing it

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but its making an angle of 30°..how the angle became 0

a) Work done is zero when displacement is zero. This happens when a man pushes a wall. There is no displacement of the wall. Thus, there is no work done.

b)It is true that the hammer drives the nail into the wood only when it is lifted and then struck.

Analysis -The iron hammer on its own has no kinetic energy, but it has some potential energy (because of its weight). To drive a nail into the piece of wood (which is work), he has to lift the iron hammer up, (this increases its potential energy because if its high position) and force it to move at great speed downwards (now has kinetic energy) to hit the nail.The sum of the potential and kinetic energy that the hammer acquired to drive in the nail is called the Mechanical energy, which results in the work done.

c) If adogandhorsearerunningwith thesame speed, kinetic energyof horseis more than the kinetic energy of thedogbecause the mass ofa horseis more than thedog.

d)A teacher moving around in class has net displacement, whereas the child has zero displacement.

Questions answer not clear

Heatenergy can betransferredfrom one place to another by three mainprocesses. In CONVECTION,heatenergy is carried by the movement of particles of matter. In CONDUCTION,heatistransferredby particles vibrating. In RADIATION,heatis carried directly by electromagnetic waves.

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Heat can be transferred from one place to another by three methods: conduction in solids, convection of fluids (liquids or gases), and radiation through anything that will allow radiation to pass. The method used to transfer heat is usually the one that is the most efficient

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We are not able to push or pull a big tire along the radius or just on the ground because of a resistance force that makes this work difficult .Tbis resistance force is known as friction force .it ia the force that makes work so difficult as it opposes movement or motion .rectangle or flatt based objects is diffult to push on the grund .the only way to reduce friction is by streamlining tho body

Option B8/6= 4/3first as there is a symmetry so we folded this circuit around ABafter folding the resistance became in parallel then we perform the parallel operation and then we got a result

d is a ans............

3 is the answer this question

the answer could be option 3

सिलिकॉन और जर्मेनियम अर्धचालक होते हैं। वे पूर्ण शून्य तापमान पर इन्सुलेटर बन जाते हैं। ... चालन उच्च तापमान पर होता है क्योंकि अर्धचालक परमाणुओं के आसपास के इलेक्ट्रॉन अपने सहसंयोजक बंधन से दूर हो सकते हैं और जाली के बारे में स्वतंत्र रूप से आगे बढ़ सकते हैं।

Answer: d) Explanation:Suppose a straight current carrying wire AB, carrying current i, lies in the plane of the paper as shown in the figure, P is a point at a perpendicular distance R from conductor, where magnetic field is to be determined.Magnetic field: u0I/2*pi*r

What is Myopia?

Myopia is the term used to define beingshortsighted.

A myopic person has clear vision when looking at objects close to them, but distant objects will appear blurred. This is because light is focused in front of the retina and, being too far forward in the eye, things in the distance look blurred.

What is hypermetropia?

Hypermetropia, sometimes called hyperopia, is the term used to define beinglongsighted.

If you are hypermetropic, the image of a nearby object is formed behind the retina. This means that light is focused too far back in the eye, causing things which are close up to appear blurred.

How is it treated?

Shortsightedness is corrected using a concave (curved inwards) lens which is placed in front of a myopic eye, moving the image back to the retina and making it clearer.

Longsightedness is corrected using a convex (outward facing) lens. This is placed in front of a hypermetropic eye, moving the image forward and focusing it correctly on the retina.

(c) straight lines parallel to each other.

And this is because of earth's magnetic field as there is no magnetic field due to wire.

the question is asking for the incorrect option..?

Formula , P = IV

let I1 & I2 be the current through the bulbs

so ,100=I1 × 200I1= 1/2

similarly,I2=1/8

total current= 1/2+1/8= 5/8 Ampere

The negatively charged body can be thought to be an electron rich specie. When brought near the uncharged body, it repels the free electrons from the uncharged body towards its farther end. As such, the closer end of the uncharged body now experiences lack of electrons, which is a characteristic of positive charge. Hence, the ends of the two bodies develop opposite charges and mutual attraction occurs

Kirchhoff'scurrentlaw(1stLaw)statesthat current flowing into a node (or a junction) must be equal to current flowing out of it. This is a consequence of charge conservation.Kirchhoff'svoltagelaw(2ndLaw)statesthat the sum of all voltages around any closed loop in a circuit must equal zero.

If two vectors are considered to be the adjacent sides of a parallelogram, then the resultant of two vectors is given by the vector that is a diagonal passing through the point of contact of two vectors.

If two vectors are considered to be the adjacent sides of a parallelogram, then the resultant of two vectors is given by the vector that is a diagonal passing through the point of contact of two vectors.

bro I have problem. please help me

Given:

vi = 0 m/s

vf = 521 m/s

d = 0.840 m

Find:

a = ??vf2 = vi2 + 2*a*d(521 m/s)2 = (0 m/s)2 + 2*(a)*(0.840 m)

271441 m2/s2 = (0 m/s)2 + (1.68 m)*a

(271441 m2/s2)/(1.68 m) = a

a = 1.62*105 m /s2.

Given:

vi = 0 m/s

vf = 521 m/s

d = 0.840 m

Find:

a = ??vf2 = vi2 + 2*a*d(521 m/s)2 = (0 m/s)2 + 2*(a)*(0.840 m)

271441 m2/s2 = (0 m/s)2 + (1.68 m)*a

(271441 m2/s2)/(1.68 m) = a

a = 1.62*105 m /s2

Given:

vi = 367 m/s

vf = 0 m/s

d = 0.0621 m

Find:

a = ??vf2 = vi2 + 2*a*d(0 m/s)2 = (367 m/s)2 + 2*(a)*(0.0621 m)

0 m2/s2 = (134689 m2/s2) + (0.1242 m)*a

-134689 m2/s2 = (0.1242 m)*a

(-134689 m2/s2)/(0.1242 m) = a

a = -1.08*106 m /s2

(The - sign indicates that the bullet slowed down.)

Nitrogenis present asN2or dinitrogen. The two atoms ofnitrogenare attached by a triple bond between them which is very strong. To break such a strong energy bond tremendous energy is needed which is not available ininertconditions. That is whynitrogenisinertinroom temperature.

Given density of aluminum is 2.7 g/cm³ and that of brass is 8.4 g/cm³.

so density of brass > density of aluminum

so , higher the density, higher will be the mass of a certain volume as M = D.V , keeping V constant.. mass will be greater if D is greater

so, option B is correct.

I). Renewable resources:- Renewable resources are the natural resources which can be used against and again or can be reproduced by physical, mechanical and chemical processes. Solar energy, air, water and soil are some of the renewable resources of energy.ii). Non-renewable resources:- Non-renewable resources are the natural resources that cannot be replaced at all or within a reasonable time. Fossil fuels such as oil, gas and coal are examples of non-renewable resources. These resources accumulated over millions of years. They are considered to be non-renewable resources because once they are used up, they are gone forever.

renewable and non renewable resources