

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
51. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z22 in terms of Hybrid parameters can be expressed as ________(a) z22 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \)(b) z22 = – \(\frac{h_{21}}{h_{22}} \)(c) z22 = \(\frac{h_{12}}{h_{22}} \)(d) z22 = \(\frac{1}{h_{22}} \)This question was posed to me in final exam.My query is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in chapter Two-Port Networks of Network Theory |
Answer» Right CHOICE is (d) z22 = \(\frac{1}{h_{22}} \) |
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52. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z12 in terms of Hybrid parameters can be expressed as ________(a) z12 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \)(b) z12 = – \(\frac{h_{21}}{h_{22}} \)(c) z12 = \(\frac{h_{12}}{h_{22}} \)(d) z12 = \(\frac{1}{h_{22}} \)The question was asked in my homework.Query is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in chapter Two-Port Networks of Network Theory |
Answer» Correct choice is (c) z12 = \(\frac{h_{12}}{h_{22}} \) |
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53. |
Permeability is analogous to _____________(a) Conductivity(b) Resistivity(c) Retentivity(d) CoercivityThis question was addressed to me during an interview.The doubt is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in section Two-Port Networks of Network Theory |
Answer» The correct option is (a) CONDUCTIVITY |
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54. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z11 in terms of Hybrid parameters can be expressed as ________(a) z11 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \)(b) z11 = – \(\frac{h_{21}}{h_{22}} \)(c) z11 = \(\frac{h_{12}}{h_{22}} \)(d) z11 = \(\frac{1}{h_{22}} \)The question was asked in exam.I want to ask this question from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in portion Two-Port Networks of Network Theory |
Answer» Right option is (a) z11 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \) |
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55. |
A constant k high pass p section has a characteristic impedance of 300 Ω at f = ∞. At f = fc, the characteristic impedance will be?(a) 0(b) ∞(c) 300 Ω(d) More than 300 ΩThis question was posed to me in an international level competition.Origin of the question is Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in section Two-Port Networks of Network Theory |
Answer» Right option is (b) ∞ |
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56. |
For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z21 in terms of Hybrid parameters can be expressed as ________(a) z21 = \(\left(h_{11} – \frac{h_{21} h_{12}}{h_{22}}\right) \)(b) z21 = – \(\frac{h_{21}}{h_{22}} \)(c) z21 = \(\frac{h_{12}}{h_{22}} \)(d) z21 = \(\frac{1}{h_{22}} \)This question was posed to me in examination.My doubt is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in portion Two-Port Networks of Network Theory |
Answer» Correct answer is (b) z21 = – \(\frac{h_{21}}{h_{22}} \) |
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57. |
For a T-network if the Short circuit admittance parameters are given as y11, y21, y12, y22, then y21 in terms of Hybrid parameters can be expressed as ________(a) y21 = \(\left(- \frac{h_{21} h_{12}}{h_{11}} + h_{22}\right)\)(b) y21 = \(\frac{h_{21}}{h_{11}} \)(c) y21 = –\(\frac{h_{12}}{h_{11}} \)(d) y21 = \(\frac{1}{h_{11}} \)I had been asked this question in quiz.My question is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in section Two-Port Networks of Network Theory |
Answer» The correct answer is (b) Y21 = \(\frac{h_{21}}{h_{11}} \) |
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58. |
In the circuit given below, the current through R is 2 sin 8t. The value of R is ___________(a) (0.18 + j0.72)(b) (0.46 + j1.90)(c) – (0.18 + j1.90)(d) (0.23 – 0.35 j)The question was posed to me during a job interview.Question is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in portion Two-Port Networks of Network Theory |
Answer» Correct choice is (d) (0.23 – 0.35 j) |
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59. |
For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z22 in terms of Transmission parameters can be expressed as ____________(a) z22 = \(\frac{D’}{C’}\)(b) z22 = \(\frac{1}{C’}\)(c) z22 = \(\left(\frac{A’ D’}{C’}– B’\right)\)(d) z22 = \(\frac{A’}{C’}\)I had been asked this question during an online exam.Enquiry is from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in division Two-Port Networks of Network Theory |
Answer» RIGHT ANSWER is (d) z22 = \(\frac{A’}{C’}\) Easy explanation: We know that, V1 = z11 I1 + z12 I2 …………. (1) V2 = z21 I1 + z22 I2 ……………. (2) AndV2 = A’V1 – B’I1 ……… (3) I2 = C’V1 – D’I1 …………… (4) Rewriting (3) and (4), we GET, V2 = A’ \(\left(\frac{D’}{C’} I_1 + \frac{1}{C’} I_2\right) – B’I_1 = \left(\frac{A’ D’}{C’}– B’\right) I_1 + \frac{A’}{C’} I_2\) ………… (5) And V1 = \(\frac{D’}{C’} I_1 + \frac{1}{C’} I_2\) ………….. (6) Comparing (1), (2) and (5), (6), we get, z11 =\(\frac{D’}{C’}\) z12 = \(\frac{1}{C’}\) z21 = \(\left(\frac{A’ D’}{C’}– B’\right)\) z22 =\(\frac{A’}{C’}\). |
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60. |
For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z12 in terms of Transmission parameters can be expressed as ____________(a) z12 = \(\frac{D’}{C’}\)(b) z12 = \(\frac{1}{C’}\)(c) z12 = \(\left(\frac{A’ D’}{C’}– B’\right)\)(d) z12 = \(\frac{A’}{C’}\)The question was asked in class test.Question is taken from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in section Two-Port Networks of Network Theory |
Answer» Right option is (b) z12 = \(\frac{1}{C’}\) |
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61. |
A periodic voltage v (t) = 1 + 4 sin ωt + 2 cos ωt is applied across a 1Ω resistance. The power dissipated is ____________(a) 1 W(b) 11 W(c) 21 W(d) 24.5 WThe question was posed to me in a job interview.The question is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in section Two-Port Networks of Network Theory |
Answer» RIGHT option is (b) 11 W For EXPLANATION I would say: Given that, v (t) = 1 + 4 sin ωt + 2 cos ωt So, Power is given by, Power, P = \(\frac{1^2}{1} + \frac{\frac{4^2}{\sqrt{2}}}{1} +\frac{\frac{2^2}{\sqrt{2}}}{1}\) = 11 W. |
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62. |
For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z11 in terms of Transmission parameters can be expressed as ____________(a) z11 = \(\frac{D’}{C’}\)(b) z11 = \(\frac{1}{C’}\)(c) z11 = \(\left(\frac{A’ D’}{C’}– B’\right)\)(d) z11 = \(\frac{A’}{C’}\)This question was posed to me by my college professor while I was bunking the class.Question is taken from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in portion Two-Port Networks of Network Theory |
Answer» The correct OPTION is (a) z11 = \(\frac{D’}{C’}\) |
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63. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y22 in terms of Inverse Transmission parameters can be expressed as ________(a) y22 = \(\frac{A’}{B’}\)(b) y22 = – \(\frac{1}{B’}\)(c) y22 = \(\left(C’ – \frac{D’ A’}{B’}\right)\)(d) y22 = \(\frac{D’}{B’}\)I had been asked this question by my college professor while I was bunking the class.My question is based upon Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in chapter Two-Port Networks of Network Theory |
Answer» Correct answer is (d) y22 = \(\frac{D’}{B’}\) |
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64. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y21 in terms of Inverse Transmission parameters can be expressed as ________(a) y21 =\(\frac{A’}{B’}\)(b) y21 = – \(\frac{1}{B’}\)(c) y21 = \(\left(C’ – \frac{D’ A’}{B’}\right)\)(d) y21 = \(\frac{D’}{B’}\)This question was addressed to me during an online interview.The above asked question is from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in section Two-Port Networks of Network Theory |
Answer» Correct OPTION is (c) y21 = \(\left(C’ – \frac{D’ A’}{B’}\right)\) |
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65. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y12 in terms of Inverse Transmission parameters can be expressed as ________(a) y12 =\(\frac{A’}{B’}\)(b) y12 = – \(\frac{1}{B’}\)(c) y12 = \(\left(C’ – \frac{D’ A’}{B’}\right)\)(d) y12 = \(\frac{D’}{B’}\)The question was posed to me in an internship interview.Asked question is from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in portion Two-Port Networks of Network Theory |
Answer» The correct OPTION is (B) y12 = – \(\frac{1}{B’}\) |
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66. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y11 in terms of Inverse Transmission parameters can be expressed as ________(a) y11 =\(\frac{A’}{B’}\)(b) y11 = – \(\frac{1}{B’}\)(c) y11 = \(\left(C’ – \frac{D’ A’}{B’}\right)\)(d) y11 = \(\frac{D’}{B’}\)I had been asked this question during an online exam.This interesting question is from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in division Two-Port Networks of Network Theory |
Answer» The correct choice is (a) y11 =\(\frac{A’}{B’}\) |
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67. |
For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z22 in terms of Transmission parameters can be expressed as ____________(a) z22 = \(\frac{A}{C}\)(b) z22 = \(\frac{AD}{C – B}\)(c) z22 = \(\frac{1}{C}\)(d) z22 = \(\frac{D}{C}\)This question was posed to me by my school teacher while I was bunking the class.My doubt is from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in chapter Two-Port Networks of Network Theory |
Answer» Correct choice is (d) z22 = \(\frac{D}{C}\) |
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68. |
For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z21 in terms of Transmission parameters can be expressed as ____________(a) z21 = \(\frac{A}{C}\)(b) z21 = \(\frac{AD}{C – B}\)(c) z21 = \(\frac{1}{C}\)(d) z21 = \(\frac{D}{C}\)The question was asked in a job interview.My enquiry is from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in section Two-Port Networks of Network Theory |
Answer» The CORRECT option is (C) z21 = \(\frac{1}{C}\) |
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69. |
For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z12 in terms of Transmission parameters can be expressed as ____________(a) z12 = \(\frac{A}{C}\)(b) z12 = \(\frac{AD}{C – B}\)(c) z12 = \(\frac{1}{C}\)(d) z12 = \(\frac{D}{C}\)This question was posed to me during a job interview.My question comes from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in section Two-Port Networks of Network Theory |
Answer» Right CHOICE is (b) z12 = \(\frac{AD}{C – B}\) |
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70. |
For a T-network if the Open circuit Impedance parameters are z11, z12, z21, z22, then z11 in terms of Transmission parameters can be expressed as ____________(a) z11 = \(\frac{A}{C}\)(b) z11 = \(\frac{AD}{C – B}\)(c) z11 = \(\frac{1}{C}\)(d) z11 = \(\frac{D}{C}\)I had been asked this question in exam.My question comes from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in division Two-Port Networks of Network Theory |
Answer» Right choice is (a) z11 = \(\FRAC{A}{C}\) |
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71. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y22 in terms of Transmission parameters can be expressed as ________(a) y22 =\(\frac{D}{B}\)(b) y22 = \(\frac{C-A}{B}\)(c) y22 = – \(\frac{1}{B}\)(d) y22 = \(\frac{A}{B}\)The question was asked in an online interview.I'd like to ask this question from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in chapter Two-Port Networks of Network Theory |
Answer» Right option is (d) y22 = \(\frac{A}{B}\) |
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72. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y21 in terms of Transmission parameters can be expressed as ________(a) Y21 =\(\frac{D}{B}\)(b) Y21 = \(\frac{C-A}{B}\)(c) Y21 = – \(\frac{1}{B}\)(d) Y21 = \(\frac{A}{B}\)I had been asked this question in my homework.My question is based upon Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in chapter Two-Port Networks of Network Theory |
Answer» Correct answer is (c) Y21 = – \(\frac{1}{B}\) |
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73. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y12 in terms of Transmission parameters can be expressed as ________(a) y12 = \(\frac{D}{B}\)(b) y12 = \(\frac{C-A}{B}\)(c) y12 = – \(\frac{1}{B}\)(d) y12 = \(\frac{A}{B}\)I have been asked this question in examination.I'm obligated to ask this question of Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in division Two-Port Networks of Network Theory |
Answer» Right answer is (b) y12 = \(\frac{C-A}{B}\) |
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74. |
For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y11 in terms of Transmission parameters can be expressed as ________(a) y11 =\(\frac{D}{B}\)(b) y11 = \(\frac{C-A}{B}\)(c) y11 = – \(\frac{1}{B}\)(d) y11 = \(\frac{A}{B}\)This question was addressed to me during an interview.Origin of the question is Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in division Two-Port Networks of Network Theory |
Answer» Correct option is (a) y11 =\(\frac{D}{B}\) |
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75. |
In the circuit given below, the maximum power that can be transferred to the resistor RL is _____________(a) 1 W(b) 10 W(c) 0.25 W(d) 0.5 WThis question was addressed to me during an interview for a job.This key question is from Series-Series Connection of Two Port Network topic in chapter Two-Port Networks of Network Theory |
Answer» Correct option is (C) 0.25 W |
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76. |
In the figure given below, the pole-zero plot corresponds to _____________(a) Low-pass filter(b) High-pass filter(c) Band-pass filter(d) Notch filterThe question was asked in homework.Question is taken from Series-Series Connection of Two Port Network topic in division Two-Port Networks of Network Theory |
Answer» CORRECT choice is (d) NOTCH filter Explanation: In POLE zero plot the two transmission zeroes are located on the jω-axis, at the complex conjugate location, and then the magnitude response EXHIBITS a zero transmission at ω – ωC. |
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77. |
In the circuit given below, the equivalent inductance is ____________(a) L1 + L2 – 2M(b) L1 + L2 + 2M(c) L1 + L2 – M(d) L1 + L2The question was posed to me in an interview for internship.Asked question is from Series-Series Connection of Two Port Network topic in section Two-Port Networks of Network Theory |
Answer» The correct OPTION is (a) L1 + L2 – 2M |
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78. |
A moving coil of a meter has 250 turns and a length and depth of 40 mm and 30 mm respectively. It is positioned in a uniform radial flux density of 450 mT. The coil carries a current of 160 mA. The torque on the coil is?(a) 0.0216 N-m(b) 0.0456 N-m(c) 0.1448 N-m(d) 1 N-mI got this question in an online interview.My question is from Series-Series Connection of Two Port Network topic in portion Two-Port Networks of Network Theory |
Answer» Correct CHOICE is (a) 0.0216 N-m |
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79. |
In the circuit given below, the number of node and branches are ______________(a) 4 and 5(b) 4 and 6(c) 5 and 6(d) 6 and 4This question was posed to me in unit test.The origin of the question is Series-Series Connection of Two Port Network in portion Two-Port Networks of Network Theory |
Answer» The correct choice is (B) 4 and 6 |
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80. |
In the circuit given below, the 60 V source absorbs power. Then the value of the current source is ____________(a) 10 A(b) 13 A(c) 15 A(d) 18 AI have been asked this question during an online interview.The doubt is from Series-Series Connection of Two Port Network topic in section Two-Port Networks of Network Theory |
Answer» Correct option is (a) 10 A |
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81. |
In the circuit given below, the equivalent capacitance is ______________(a) \(\frac{C}{4}\)(b) \(\frac{5C}{13}\)(c) \(\frac{5C}{2}\)(d) 3CThis question was addressed to me in unit test.This is a very interesting question from Series-Series Connection of Two Port Network in chapter Two-Port Networks of Network Theory |
Answer» Correct choice is (b) \(\FRAC{5C}{13}\) |
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82. |
For a 2 port network, the transmission parameters are given as 10, 9, 11 and 10 corresponds to A, B, C and D. The correct statement among the following is?(a) Network satisfies both reciprocity and symmetry(b) Network satisfies only reciprocity(c) Network satisfies only symmetry(d) Network satisfies neither reciprocity nor symmetryThe question was posed to me in unit test.My question is taken from Series-Series Connection of Two Port Network topic in chapter Two-Port Networks of Network Theory |
Answer» RIGHT answer is (a) Network SATISFIES both reciprocity and symmetry For EXPLANATION: Here, A = 10, B = 9, C = 11, D = 10 ∴ A = D ∴ Condition for symmetry is satisfied. Also, AD – BC = (10) (10) – (9) (11) = 100 – 99 = 1 Therefore the condition of reciprocity is satisfied. |
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83. |
The relation AD – BC = 1, (where A, B, C and D are the elements of a transmission matrix of a network) is valid for ___________(a) Both active and passive networks(b) Passive but not reciprocal networks(c) Active and reciprocal networks(d) Passive and reciprocal networksThis question was posed to me during an internship interview.This intriguing question originated from Series-Series Connection of Two Port Network topic in section Two-Port Networks of Network Theory |
Answer» CORRECT OPTION is (d) Passive and reciprocal networks For explanation: AD – BC = 1, is the condition for reciprocity for ABCD parameters, which SHOWS that the relation is valid for reciprocal network. The ABCD parameters are obtained for the network which consists of resistance, capacitance and INDUCTANCE, which indicates that it is a passive network. |
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84. |
The condition for a 2port network to be reciprocal is ______________(a) Z11 = Z22(b) BC – AD = -1(c) Y12 = -Y21(d) h12 = h21I have been asked this question by my college professor while I was bunking the class.This interesting question is from Series-Series Connection of Two Port Network topic in chapter Two-Port Networks of Network Theory |
Answer» Right choice is (b) BC – AD = -1 |
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85. |
Two networks are connected in series parallel connection. Then, the forward short-circuit current gain of the network is ____________(a) Product of Z-parameter matrices(b) Sum of h-parameter matrices(c) Sum of Z-parameter matrices(d) Product of h-parameter matricesThe question was posed to me in unit test.This question is from Series-Series Connection of Two Port Network topic in section Two-Port Networks of Network Theory |
Answer» Right choice is (b) Sum of h-parameter matrices |
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86. |
How many incandescent lamps connected in series would consume the same total power as a single 100 W/220 V incandescent lamp. The rating of each lamp is 200 W/220 V?(a) Not possible(b) 4(c) 3(d) 2This question was posed to me in a job interview.My question is taken from Series-Series Connection of Two Port Network topic in section Two-Port Networks of Network Theory |
Answer» Right answer is (d) 2 |
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87. |
In the circuit given below, the current through the 2 kΩ resistance is _____________(a) Zero(b) 1 mA(c) 2 mA(d) 6 mAI had been asked this question at a job interview.Enquiry is from Series-Series Connection of Two Port Network in chapter Two-Port Networks of Network Theory |
Answer» The correct OPTION is (a) Zero |
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88. |
In the circuit given below, the number of chords in the graph is ________________(a) 3(b) 4(c) 5(d) 6I got this question in an online quiz.The doubt is from Series-Series Connection of Two Port Network in portion Two-Port Networks of Network Theory |
Answer» CORRECT CHOICE is (b) 4 To explain I would say: Given that, b = 6, N = 3 Number of Links is given by, b – n + 1 = 6 – 3 + 1 = 4. |
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89. |
In the circuit given below, the value of R is ___________(a) 2.5 Ω(b) 5.0 Ω(c) 7.5 Ω(d) 10.0 ΩThe question was asked during an online interview.This intriguing question comes from Series-Series Connection of Two Port Network topic in section Two-Port Networks of Network Theory |
Answer» Correct option is (c) 7.5 Ω |
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90. |
Determine the value of Ø in the circuit shown below.(a) 0.25(b) 0.5(c) 0.75(d) 1The question was asked by my school teacher while I was bunking the class.Question is from Image Parameters topic in portion Two-Port Networks of Network Theory |
Answer» The correct answer is (C) 0.75 |
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91. |
The value of Z12 in the circuit shown below is?(a) 1.1(b) 2.2(c) 3.3(d) 4.4This question was posed to me in final exam.My enquiry is from Image Parameters topic in section Two-Port Networks of Network Theory |
Answer» The correct ANSWER is (d) 4.4 |
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92. |
The value of Z11 in the circuit shown below is?(a) 1.8(b) 2.8(c) 3.8(d) 4.8The question was asked in an interview for job.Query is from Image Parameters topic in division Two-Port Networks of Network Theory |
Answer» Right answer is (c) 3.8 |
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93. |
Determine the transmission parameter D in the circuit shown below.(a) 3/5(b) 4/5(c) 7/5(d) 2/5This question was posed to me during an interview.My question comes from Image Parameters topic in portion Two-Port Networks of Network Theory |
Answer» CORRECT ANSWER is (c) 7/5 For explanation I would say: The TRANSMISSION parameter D is -I1/I2 |V2=0. This is obtained by short circuiting the port 2. We get I1 = (7/17)V1 and -I2 = (5/17)V1. On solving, we get -I1/I2 = 7/5. On SUBSTITUTING we get D = 7/5. |
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94. |
Determine the transmission parameter B in the circuit shown below.(a) 17/5(b) 5/17(c) 13/5(d) 5/13This question was addressed to me in examination.My query is from Image Parameters in portion Two-Port Networks of Network Theory |
Answer» The correct ANSWER is (a) 17/5 |
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95. |
Determine the transmission parameter C in the circuit shown below.(a) 2/5(b) 1/5(c) 4/5(d) 3/5This question was addressed to me by my school principal while I was bunking the class.Question is from Image Parameters topic in division Two-Port Networks of Network Theory |
Answer» Right answer is (b) 1/5 |
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96. |
Determine the transmission parameter A in the circuit shown below.(a) 3/4(b) 4/3(c) 5/6(d) 6/5The question was posed to me during a job interview.My question is from Image Parameters topic in chapter Two-Port Networks of Network Theory |
Answer» Correct CHOICE is (d) 6/5 |
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97. |
The relation between Z12 and Z11 and B and C parameters if the network is symmetrical is?(a) Z11 = Z12 = B/C(b) Z11 = Z12 = C/B(c) Z11 = Z12 = √(B/C)(d) Z11 = Z12 = √(C/B)I got this question in exam.The query is from Image Parameters topic in chapter Two-Port Networks of Network Theory |
Answer» Right answer is (C) Z11 = Z12 = √(B/C) |
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98. |
The relation between Z11 and Z12 if the network is symmetrical is?(a) Z11 = 2 Z12(b) Z11 = Z12(c) Z11 = 3 Z12(d) Z11 = 4 Z12I have been asked this question in class test.This interesting question is from Image Parameters topic in division Two-Port Networks of Network Theory |
Answer» CORRECT choice is (B) Z11 = Z12 Explanation: For a network to be symmetrical A=D. So the RELATION between Z11 and Z12 for the network is symmetrical is Z11 = Z12. |
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99. |
A network is said to be symmetrical if the relation between A and D is?(a) A = D(b) A = 2 D(c) A = 3 D(d) A = 4 DI got this question in an international level competition.My enquiry is from Image Parameters topic in portion Two-Port Networks of Network Theory |
Answer» CORRECT option is (a) A = D Best explanation: We KNOW V1=AV2-BI2 and I1=CV2-DI2. If the NETWORK is symmetrical, then the RELATION between A and D is A = D. |
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100. |
The value of the Z-parameter Z22 in the circuit shown below.(a) 6/7(b) 7/12(c) 12/7(d) 7/6This question was posed to me during an interview.This intriguing question originated from Terminated Two-Port Network topic in section Two-Port Networks of Network Theory |
Answer» Correct answer is (c) 12/7 |
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