1.

For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y22 in terms of Transmission parameters can be expressed as ________(a) y22 =\(\frac{D}{B}\)(b) y22 = \(\frac{C-A}{B}\)(c) y22 = – \(\frac{1}{B}\)(d) y22 = \(\frac{A}{B}\)The question was asked in an online interview.I'd like to ask this question from Relation between Transmission Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters topic in chapter Two-Port Networks of Network Theory

Answer»

Right option is (d) y22 = \(\frac{A}{B}\)

BEST explanation: We know that, V1 = AV2 – BI2 ……… (1)

I1 = CV2 – DI2 …………… (2)

And, I1 = Y11 V1 + y12 V2 ……… (3)

I2 = y21 V1 + y22 V2 ………. (4)

Now, (1) and (2) can be rewritten as, I2 = \(\frac{A}{B}V_2 – \frac{1}{B}V_1\) …………. (5)

And I1 = CV2 – D \(\left(\frac{A}{B}V_2 – \frac{1}{B}V_1\right) = \frac{D}{B}V_1 + \left(C-\frac{A}{B}\right) V_2\) …………… (6)

Comparing equations (3), (4) and (5), (6), we GET,

y11 =\(\frac{D}{B}\)

y12 = \(\frac{C-A}{B}\)

y21 = – \(\frac{1}{B}\)

y22 = \(\frac{A}{B}\).


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