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A resistor of 10 kΩ with the tolerance of 5% is connected in series with 5 kΩ resistors of 10% tolerance. What is the tolerance limit for a series network?(a) 9%(b) 12.04%(c) 8.67%(d) 6.67%I have been asked this question during an online interview.I would like to ask this question from Advanced Problems on Two Port Network topic in division Two-Port Networks of Network Theory

Answer»

The CORRECT OPTION is (d) 6.67%

Easiest explanation: ERROR in 10 kΩ resistance = 10 × \(\FRAC{5}{100}\) = 0.5 kΩ

Error in 5 kΩ resistance = 5 × \(\frac{10}{100}\) = 5 kΩ

Total MEASUREMENT resistance = 10 + 0.5 + 5 + 0.5 = 16 kΩ

Original resistance = 10 + 5 = 15 kΩ

Error = \(\frac{16-15}{15}\) × 100 = \(\frac{1}{15}\) × 100 = 6.67%.



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