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Given that, R1 = 36 Ω and R2 = 75 Ω, each having tolerance of ±5% are connected in series. The value of resultant resistance is ___________(a) 111 ± 0 Ω(b) 111 ± 2.77 Ω(c) 111 ± 5.55 Ω(d) 111 ± 7.23 ΩI got this question in exam.Question is taken from Advanced Problems on Two Port Network in portion Two-Port Networks of Network Theory

Answer»

Correct CHOICE is (c) 111 ± 5.55 Ω

For explanation I would say: R1 = 36 ± 5% = 36 ± 1.8 Ω

R2 = 75 ± 5% = 75 ± 3.75 Ω

∴ R1 + R2 = 111 ± 5.55 Ω.



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