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Consider a circuit having a charge of 600 C, which is delivered to 100 V source in a 1 minute. The value of Voltage source V is ___________(a) 30 V(b) 60 V(c) 120 V(d) 240 VThis question was addressed to me in an interview for job.The query is from Advanced Problems on Two Port Network topic in division Two-Port Networks of Network Theory

Answer»

Right answer is (d) 240 V

Easiest explanation: In order for 600 C charges to be delivered to 100 V source, the electric current must be in REVERSE clockwise direction.

Now, I = \(\frac{dQ}{DT}\)

= \(\frac{600}{60}\) = 10 A

Applying KVL we get

V1 + 60 – 100 = 10 × 20 ⇒ V1 = 240 V.



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