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A 200 μA ammeter has an internal resistance of 200 Ω. The range is to be extended to 500μA. The shunt required is of resistance __________(a) 20.0 Ω(b) 22.22 Ω(c) 25.0 Ω(d) 50.0 ΩThis question was posed to me in class test.Enquiry is from Advanced Problems on Two Port Network topic in portion Two-Port Networks of Network Theory

Answer»

Right CHOICE is (c) 25.0 Ω

The best explanation: Ish Rsh = IM Rm

Ish = I – Im or, \(\frac{I}{I_m} – 1 = \frac{R_m}{R_{SH}}\)

Now, m = \(\frac{I}{I_m}\)

Or, m – 1 = \(\frac{R_m}{R_{sh}}\)

∴Rsh = 25 Ω.



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