A periodic voltage v (t) = 1 + 4 sin ωt + 2 cos ωt is applied across a 1Ω resistance. The power dissipated is ____________(a) 1 W(b) 11 W(c) 21 W(d) 24.5 WThe question was posed to me in a job interview.The question is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in section Two-Port Networks of Network Theory

A periodic voltage v (t) = 1 + 4 sin ωt + 2 cos ωt is applied across

1.	A periodic voltage v (t) = 1 + 4 sin ωt + 2 cos ωt is applied across a 1Ω resistance. The power dissipated is ____________(a) 1 W(b) 11 W(c) 21 W(d) 24.5 WThe question was posed to me in a job interview.The question is from Relation between Hybrid Parameters with Short Circuit Admittance and Open Circuit Impedance Parameters in section Two-Port Networks of Network Theory
Answer» RIGHT option is (b) 11 W For EXPLANATION I would say: Given that, v (t) = 1 + 4 sin ωt + 2 cos ωt So, Power is given by, Power, P = \(\frac{1^2}{1} + \frac{\frac{4^2}{\sqrt{2}}}{1} +\frac{\frac{2^2}{\sqrt{2}}}{1}\) = 11 W.

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